Q methane = Q water
Q = mcΔt
mass water = V x ρ = 1 L x 1 kg/L = 1 kg
298 K to 373K = 25 °C to 100 °C
c water = 75.2 J/mol K = 4.2 J / g °C = 4200 J/kg °C
Q water = 1 x 4200 x (100 - 25)
Q water = 315000 J
Q methane = Q water = 315000 J = 315 KJ
n (mol) methane = ΔH/Q = 890.4 / 315 = 2.83
PV = nRT
V = nRT/P
V = 2.83 x 0.082 x 298/1
V = 69.15 L
Which three words best describe the composition of the inner planets?solid, smooth, giantrocky, solid, densegiant, dense, gaseousgaseous, smooth, small
The three words which best describe the composition of the inner planets are rocky, solid, and dense.
What is an inner planet?A planet classified as an inner planet is one that is rocky, solid, and dense by nature, such as Mercury, Venus, Earth, and Mars. Inner planets are those that are nearest to the Sun.
There are two types of planets:
Based on astronomical information and records, there are two main types of planets :
Outer planetInner planetThe moons of the inner planets are either absent or limited to one (Earth) or two (Mars). The inner planets don't have any rings. The inner planets have shorter orbits around the Sun than the outer planets, but they all rotate more slowly.
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Answer:rocky soild and dense
Explanation:
How many molecules are in 84.7 grams?
The number of molecules will depend on the molar mass of the compound.
Number of moleculesAccording to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex].
To find the number of moles in a substance:
Mole = mass/molar mass.
In this case, we do not know the compound but we know the mass. Hence, we cannot know the molar mass.
Assuming the molar mass is X.
Mole = 84.7/X
Number of molecules in 84.7 grams of the compound =
84.7/X x 6.022 x [tex]10^{23}[/tex] molecules.
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Calculate the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L.
The molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
How to calculate molecular mass?The molecular mass can be calculated by first calculating the number of moles using the following formula:
PV = nRT
Where;
P = pressureV = volumen = no of molesR = gas law constantT = temperature1.112 × 0.7 = n × 0.0821 × 300
0.7784 = 24.63n
n = 0.032mol
molecular mass = 2.66g ÷ 0.032mol
molecular mass = 84.16g/mol
Therefore, the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
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which of the three minerals contain calcium carbonate?
A. salt
B. chalk
C. talcum
Answer:
Answer choices A, B, and C all contain a certain level (or amount, if you will) of Calcium Carbonate, but B. chalk contains the most amount out of all three.
Explanation:
I hope that this was helpful! (✿◠‿◠)
Thank you!
The compound HBr can be decomposed to form H2 and Br2. This can be represented at the atomic level by a chemical equation:
2HBr H2 + Br2
According to the law of conservation of mass, if 29.5 grams of HBr decomposes and 0.4 grams of H2 is formed, how many grams of Br2 must simultaneously be formed?
The law of conservation of mass say that, in a chemical reaction, the mass of the reagents will always be equal to the mass of the products.
If we have 29.5 g of HBr, we must have 100 g of H2 and Br2 together, so:
29.5 = 0.4 + Br2Br2 = 29.1 gHow many grams of Al are needed to react with 63.0 g of FeO
The amount of Al required will be 15.77 grams
Stoichiometric problemFirst, the equation of the reaction:
[tex]2Al +3 FeO -- > Al_2O_3 + 3Fe[/tex]
The mole ratio is 2:3.
Mole of 63.0 g of FeO = 63/71.84 = 0.8769 moles
Equivalent moles of Al = 0.8769 x 2/3 = 0.5846 moles
Mass of 0.5846 moles Al = 0.5846 x 26.98 = 15.77 grams
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Taking into account the reaction stoichiometry, 13.28 grams of Al is required to react with 63 grams of FeO.
Reaction stoichiometryIn first place, the balanced reaction is:
2 Al + 3 FeO → 3 Fe + Al₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Al: 2 molesFeO: 3 molesFe: 3 molesAl₂O₃ : 1 moleThe molar mass of the compounds is:
Al: 27 g/moleFeO: 71.85 g/moleFe: 55.85 g/moleAl₂O₃ : 102 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Al: 2 moles ×27 g/mole= 54 gramsFeO: 3 moles ×71.85 g/mole= 215.55 gramsFe: 3 moles ×55.85 g/mole= 167.55 gramsAl₂O₃ : 1 mole ×102 g/mole= 102 gramsMass of Al requiredThe following rule of three can be applied: If by reaction stoichiometry 215.55 grams of FeO react with 54 grams of Al, 53 grams of FeO react with how much mass of Al?
[tex]mass of Al= \frac{53 grams of FeOx54 grams of Al}{215.55 grams of FeO}[/tex]
mass of Al= 13.28 grams
Finally, 13.28 grams of Al is required to react with 63 grams of FeO.
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The rate law for the reaction 3A --> 2B is rate = k[A] with a rate constant of 0.0447 hr-1.
What is the half-life of the reaction?
A) 0.0224 hr
B) 0.0645 hr
C) 15.5 hr
D) 22.4 hr
E) 44.7 hr
The half-life of the reaction is determined as 22.4 hr.
Half life of the reaction
The half life of the reaction is calculated as follows
rate of reaction, k = Δ[A]/3t = Δ[B]/2t
t = Δ[A]/3k = Δ[B]/2k
where;
k is rate constant = 0.0447/hrt = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr
Thus, the half-life of the reaction is determined as 22.4 hr.
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What volume in milliliters of 0.0150 M Ba(OH)2 is required to neutralize 50.0 mL of 0.0500 M HBr?
The volume of [tex]Ba(OH)_2[/tex] required will be 83.33 mL
Stoichiometric reactionsThe equation of the reaction is as follows:
[tex]Ba(OH)_2 + 2HBr --- > 2H_2O + BaBr_2[/tex]
Mole ratio of reactants = 1:2
Mole of 50 mL, 0.05 M HBr = 0.05 x 0.05 = 0.0025 moles
Equivalent mole of [tex]Ba(OH)_2[/tex] = 0.0025/2 = 0.00125 moles
Volume of 0.015 M, 0.00125 moles [tex]Ba(OH)_2[/tex] = 0.00125/0.015 = 0.0833 L
0.0833 L = 83.33 mL
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Which group on the periodic table has the most reactive metals?
A.
group 1
B.
group 3
C.
group 18
D.
group 17
Answer:
A group 1
Explanation:
Group 1
reactivity decreases as you go from L to R or downward on the periodic table
It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was required
to melt the iceberg if 1 m³ of ice has a mass of 917 kg?
The amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?The heat required to melt a unit mass of ice is known as the latent heat of fusion.
The latent heat of fusion of ice of 1 kg= 334 kJ of heat
Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg
Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.
Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
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which of these is/are conserved during a chemical reaction ?
a)Mass only
b) Charge only
c)both mass and charge
d)neither
Answer:
C- both!
Explanation:
In a chemical reaction, the total mass and total charge has to be balanced on both sides of the "equation", therefore both are conserved
kinetic energy is proportional to what
Answer:
mass and the square of the magnitude of velocity.
Explanation:
The sugar fructose contains 40.0% C, 6.7% H, and 53.3% O by mass. A solution of 11.7 g of fructose in 325 g of ethanol has a boiling point of 78.59 °C. The boiling point of ethanol is 78.35 °C, and Kb for ethanol is 1.20 °C/m. Assuming ideal solution behavior, what is the molecular formula of fructose?
The molecular formula of fructose is C₆H₁₂O₆.
What is the molecular formula of fructose?The molecular formula is derived in the following steps:
Step 1. the molality of the solution is determined first
Molality = Change in boiling point/Kb
Molality = (78.59 - 78.35)/1.2 = 0.2 molal
Step 2. Moles of solute is determined.
Moles of solute = molality * mass of solvent (kg)
moles = 0.2 * 0.325 = 0.065
Step 3. Molar mass of fructose = mass/moles
Molar mass of fructose = 11.7/0.065 = 180 g/mol
Step 4: Mole ratio of constituent elements
Carbon = 40% * 180/12 = 6
Hydrogen = 6.7% * 180/1 = 12
Oxygen = 53.3% * 180/16 = 6
Therefore, the molecular formula of fructose is C₆H₁₂O₆.
In conclusion, the molecular formula of fructose is derived from the molality of the solution.
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What is the half-life in minutes of a compound if 75.0 percent of a given sample decomposes in 40.0 minutes? Assume first-order kinetics.
Answer:
See below
Explanation:
.75 = 1/2^(40/h)
log .75 / ( log 1/2) = 40 / h
h = half life = 96.37683 min
To solve this type of question we must know the concept of rate law. The half-life of a compound is 23 years for 75% of a given sample of the compound decomposes in 40 minutes.
What is the expression for rate law for first order kinetics?There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law
The rate law for first order kinetics is
[tex]k=\frac{2.303}{t}log\frac{a}{a-x}[/tex]
Where
k - rate constant
t - time passed by the sample
a - initial amount of the reactant
a-x - amount left after the decay process
The expression for the half-life of the compound is
[tex]t_{1/2} = \frac{0.693}{K}[/tex]
Where k is the rate constant
t = 40 minutes
a = 100 g
a-x = 100 g - 75g = 25 g
(Since it is given that 75% of the given compound decomposes)
Then,
[tex]k=\frac{2.303}{40}log\frac{100}{25}[/tex]
=0.03years⁻¹
[tex]t_{1/2} = \frac{0.693}{0.03}[/tex]
=23 years
Therefore, the half-life of the given compound is 23years.
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What temperature would constitute a fever for a child? What effects on dental treatment would a fever pose?
Answer:
38
Explanation:
that I believe is correct
Show all work:
A saturated solution of the Ca(OH)2 is prepared and allowed to equilibrate at 25°C. A 32.40ml
sample of the solution is titrated with 0.050M HCL solution. 14.90mL of the HCI solution are
required to fully react with the sample.
Write the balanced equation for the reaction of the salt with HCl
The equation of the reaction is;
Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)
What is neutralization?The term neutralization has to do with the process in which an acid reacts with a base to form salt and water only. A neutralization reaction is known by the fact that water is obtained by the reaction of hydrogen and hydroxide ions.
The equation of the reaction is;
Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)
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How much heat would need to be removed to
cool 215.1 g of water from 25.6°C to -10.7°C?
Answer:
100 KJ
Explanation:
yep yep cool is that correct
For this same exercise, if 2.5 liters of this solution (2,500 ml) are administered in a 24-hour interval, what amount in grams of glucose did the patient receive in one day? the glucose to dissolve is 50 grams
Answer:
j
Explanation:
becaisdbyhe wrl is so not goood
You have prepared an aqueous solution of a monoprotic acid (formula mass = 153.483g/mol) by dissolving 26.816g of the acid in sufficient water to make 500.0mL of solution. The pH of the resulting solution is 4.274. What is Ka for this acid?
The Ka of the solution is 8.1 * 10^-9.
What is the pH?The pH of a solution is the concentration of hydrogen ions in the solution.
Number of moles of the acid = 26.816g/153.483g/mol = 0.175 moles
Concentration of the acid = 0.175 moles/0.5 L = 0.35 M
Now we know that the acid reacts with water as follows;
HA(aq) + H2O(l) ------> H3O^+(aq) + A^-(aq)
[H3O^+] = Antilog (-4.274)
[H3O^+] = 5.32 * 10^-5 M
Since;
[H3O^+] = [A^-] = x
Ka = x^2/[HA]
Ka = (5.32 * 10^-5)^2/( 0.35)
Ka = 8.1 * 10^-9
Hence, the Ka of the solution is 8.1 * 10^-9.
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If you know that lithium reacts strongly with oxygen in a 2:1 ratio, which of
the following properties would you predict about cesium
Answer:
Same as lithium
Explanation:
Lithium and Ceaseum both are group one elements i.e alkali metals
So they have same chemical properties almost
Hence Ceaseum would react with oxygen in 2:1 ratio
the roof of a building is 0.2km^2. during a rainstorm, 5.5 cm of rain was measured to be sitting on the roof. what is the mass in kg of the water on the roof after the rainstorm? (density of rainwater = 1g/ml)
The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
What is the mass in kg of the water on the roof after the rainstorm?Generally, the equation for the Area of the roof is mathematically given as
[tex]A=0.20 \times 10^{10} \mathrm{~cm}^{2}[/tex]
height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density
[tex]&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}[/tex]
In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
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The table describes how some substances were formed.
Substance
Description
P
Formed by boiling pure water
Q
Formed by combining three hydrogen atoms to every nitrogen atom
R
Formed by adding 5 g of sugar to 1 L of water
S
Formed by compressing carbon under high pressure
Based on the given descriptions, which substance is most likely a mixture?
P
Q
R
S
R is the mixture formed by adding 5 g of sugar to 1 L of water.
Which is a mixture?A mixture is an impure substance made up of two or more substances which are miscible or immiscible in each other.
Dissolving the sugar in the water makes a homogenous mixture and once dissolved a solution is made by the combination of a solute (sugar) and solvent (water).
Hence, R is the mixture formed by adding 5 g of sugar to 1 L of water.
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57.A cofactor is a(an)
a. catalyst for chemical reactions in a living system.
b. protein molecule whose primary function is transport of insoluble molecules in the
bloodstream.
C.
d.
e.
molecule that is acted on by a catalyst.
biological molecule used for storage of energy.
organic or inorganic molecule or ion necessary for proper functioning of some
biological catalysts.
A cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts (option E).
What is a cofactor?A cofactor in biochemistry is a molecule that binds to and regulates the activity of a protein.
A cofactor is a metal or coenzyme responsible for the functioning of an enzyme and must be present.
Therefore, a cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts.
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If a sample of Cl2 gas in a 1000 mL container is exerting a pressure of 14.2 atm, how many grams of chlorine are present? The temperature of the container is 256 K.
Taking into account the ideal gas law, the mass of chlorine present is 47.9284 grams.
Ideal gas lawAn ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Mass of chlorine presentIn this case, you know:
P= 14.2 atmV= 1000 mL= 1 LT= 256 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?Replacing in the ideal gas law:
14.2 atm× 1 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K
Solving:
(14.2 atm× 1 L)÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K)= n
0.676 moles= n
Being the molar mass of chlorine Cl₂ 70.9 g/mole, the mass of the compound can be calculated as:
0.676 moles× 70.9 g/mole= 47.9284 grams.
Finally, the mass of chlorine present is 47.9284 grams.
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How does increasing the temperature of a liquid below the boiling point affect
the motion of the particles in the liquid?
OA. The particles move faster.
B. The motion of the particles overcomes the forces holding the
particles together.
OC. The motion of the particles strengthens the forces between the
particles.
D. The particles move slower.
Answer: A. The particles move faster
Explanation:
Increasing the temperature increases the kinetic energy of the particles, causing them to move faster.
A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.00 atm.
Considering the combined law, the volume of the sample is 81.639 L at 423 K and 1.00 atm.
Charles's lawCharles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law states:
[tex]\frac{V}{T}=k[/tex]
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law is expressed as:
P×V= k
Gay-Lussac's lawGay-Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant. This law says that the pressure of a gas is directly proportional to its temperature: if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.
Mathematically, Gay-Lussac's law states:
[tex]\frac{P}{T}=k[/tex]
Combined law equationCombined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{VxP}{T}=k[/tex]
Considering an initial state 1 and a final state 2, it is fulfilled:
[tex]\frac{V1xP1}{T1}=\frac{V2xP2}{T2}[/tex]
Volume of the sampleIn this case, you know:
V1= 57.9 LP1= 1 atmT1= 300 KV2= ?P2= 1 atmT2= 423 KReplacing in combined law equation:
[tex]\frac{57.9 Lx1 atm}{300 K}=\frac{V2x1 atm}{423 K}[/tex]
Solving:
[tex]V2= \frac{423 K}{1 atm} \frac{57.9 Lx1 atm}{300 K}[/tex]
V2= 81.639 L
Finally, the volume of the sample is 81.639 L at 423 K and 1.00 atm.
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What do you see when the Moon is waning?
Answer:
The bright side of the moon will become less and less and will eventually be covered in complete darkness :)
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What's electrolysis
Answer:
electrolysis is the process by which electric current is passed through a substance to effect a chemical change
The _______ effect means water can "climb" up thin tubes and water plants. This is due to the ______ nature of water.
The Capillary effect means water can "climb" up thin tubes and water plants. This is due to the surface tension nature of water.
Hope this helps:)
The capillary effect means water can "climb" up thin tubes and water plants. This is due to the adhesive nature of water.
The capillary effect is a phenomenon where liquids, like water, can rise against gravity in narrow tubes or spaces, such as the stems of plants. This effect is possible due to the adhesive nature of water, which allows it to stick to the walls of the tube or surface it comes into contact with.
The cohesive forces between water molecules create a sort of "pull" that allows the water to climb up the tube, defying gravity. This property is essential for plants, as it helps them transport water and nutrients from their roots to their leaves and other parts of the plant, supporting their growth and survival.
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When aqueous solutions of calcium bromide and potassium carbonate are combined, solid calcium carbonate and a solution of potassium bromide are formed. The net ionic equation for this reaction is:
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)
(screen shot is attached ) please help
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
What is an ionic equation?An ionic equation is a synthetic equation where electrolytes are composed as separated particles.
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.
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