at sea level water blank at 100 degrees celceius

Answers

Answer 1

Boils

Celsius is based on the freezing and boiling points of water.

Water freezes below 0 degrees Celsius (32 degrees Fahrenheit), and it boils above 100 degrees Celsius (212 degrees Fahrenheit).


Related Questions

Oil from cashew nuts

Answers

Answer:

yes it's a thing, milk too

what are the hydrogen bonding atoms in melatonin?

Answers

The hydrogen bonding atoms in melatonin are phospholipids and cholesterol.

What is Hydrogen bonding?

This is the type of interaction which involves a hydrogen atom being covalently bound to a more electronegative "donor".

Melatonin controls sleep-wake cycle and has phospholipids and cholesterol which have high affinity for hydrogen bonding.

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What volume of a 3.50 M Na3PO4 solution would you use to make 1.50 L of a 2.55 M Na3PO4 solution?

A. 1.09 L
B. 2.06 L
C. 13.4 L
D. 0.917 L

Answers

The answer is A. 1.09 L

In the second equation FePO4 is an ionic compound. What is the charge on the Fe?

Answers

Answer:

+3

Explanation:

The phosphate ion has a charge of -3, so for the compound to have an overall change of 0, Fe needs to have a charge of +3.

A) If Kb for NX3 is 4.5×10^−6, what is the pOH of a 0.175 M aqueous solution of NX3 ?

B) If Kb for NX3 is 4.5×10^−6, what is the percent ionization of a 0.325 M aqueous solution of NX3 ?

Please show your work so I can understand how to solve similar problems on my own! Thank you!

Answers

3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].

0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]

What is pH?

pH is a measure of how acidic/basic water is.

A)

[tex]NX_3 + H_2O[/tex] →[tex]NHX_3^+ + OH^-[/tex]

Kb = 4.5 x[tex]10^-6[/tex]

Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).

concentration of (NH₄⁺) = concentration of (OH⁻) = x.

= Kb x concentration of (NH₃)

= 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)

= 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

=- log ( 8.367 × 10⁻⁴)

= 3.08

B)

Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.

Concentration of (NX₃) = 0.325 M.

Kb = 4.5 x 10⁻⁶.

[NX₃H⁺] = [OH⁻] = x.

[NX₃] = 0.325 M - x.

Kb = [NX₃H⁺] x [OH⁻] ÷  [NX₃].

4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).

x = 0.0007 M.

Per cent of ionization:

α = 0. 0007 M ÷ 0. 325 M x 100%

= 0.215%.

Hence,

3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].

0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]

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PLEASE HELP!!!!!!!!

Calculate the pH for the following weak acid.

A solution of HCOOH has 0.19M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4 . What is the pH of this solution at equilibrium?

Answers

Answer: 2.23

Explanation:

The dissociation of acetic acid is as follows:

HCOOH(aq) ⇋ HCOO− (aq) + H+(aq)

The ICE table for the concentrations of ions is given below. From the table, the concentration of HCOO- and H+ can be found out.

                                                     HCOOH → HCOO−  +   H+
Initial Concentration                     0.019 M         0             0
Equilibrium Concentration          (0.019−x) M    x              x

Where,

x is the concentration of the ions at equilibrium.

At equilibrium, dissociation constant can be calculated as follows.

[tex]K_{\mathrm{a}}=\frac{x^{2}}{(0.19-x) \mathrm{M}}[/tex]

At equilibrium, the concentration of x is negligible as compared to that of HCOOH.

Substitute the value of Ka in the above equation.

[tex]\begin{aligned}K_{\mathrm{a}} &=\frac{x^{2}}{0.19-x} \\x &=\sqrt{1.8 \times 10^{-4} \times 0.19} \\&=0.00584 \mathrm{M}\end{aligned}[/tex]

Here, the concentration of hydrogen ion is obtained. From the hydrogen ion concentration, the pH of the solution is found out as follows:

[tex]\begin{aligned}\mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\&=-\log (0.00584 \mathrm{M}) \\&=2.23\end{aligned}[/tex]

Therefore, the pH of 0.19M HCCOH is 2.23

If we want to study rest-frame visible light emitted by stars in distant galaxies at a high redshift of z 3, what portion of the electromagnetic spectrum do we need to observe? (hint JWST is meant to study distant galaxies)

Answers

The  portion of the electromagnetic spectrum do we need to observe is the red part of the This is further explained below.

What is electromagnetic spectrum?

Generally, Spectrum refers to the range of wavelengths or frequencies that electromagnetic radiation may cover.

In conclusion, We need to keep an eye on the red part of the electromagnetic spectrum since a large positive redshift causes an increase in wavelength and a corresponding fall in frequency and photon energy (such as light).

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calculate the mass in grams of the sample

Answers

Answer:

3666.33 gm

Explanation:

O3  mole mass = 47.997

Each mole has   6.022 x 10^23   molecules

4.6 x 10^25 / 6.022 x 10^23     x    47.997 gm/mole  = 3666.33 gm

A gas expands and does PV work on its surroundings equal to 322 J. At the same time, it absorbs 132 J of heat from the surroundings. Calculate the change in energy of the gas. Note: PV work means work done by a changing volume against constant pressure. Enter your answer in scientific notation.

Answers

From the calculations, the change in energy is - 190 J.

What is the first law of thermodynamics?

From the first law of thermodynamics, the energy is neither created nor destroyed but is transformed from one form to another.

From the law;

U = q + w

U = internal energy

q = heat

w = work

Since work is done on the surroundings and the gas absorbs heat then;

U = 132 J - 322 J

U = - 190 J

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The rate constant, k, for a reaction is 0.0354 sec1 at 40°C. Calculate the rate constant for the
same reaction at 125°C if the activation energy is 26.5 kJ/mol.

Answers

Answer:

The rate constant of the reaction at 125˚ is [tex]0.3115 \ \text{sec}^{-1}[/tex].

Explanation:

The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as

                                                  [tex]k \ = \ Ae^{\displaystyle\frac{-E_{a}}{RT}}[/tex]

                                               [tex]\ln k \ = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT}[/tex]

where [tex]k[/tex] is the rate constant, [tex]E_{a}[/tex] represents the activation energy of the chemical reaction, [tex]R[/tex] is the gas constant, [tex]T[/tex] is the temperature, and [tex]A[/tex] is the frequency factor.

The frequency factor, [tex]A[/tex], is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.

Consider that the rate constant be [tex]k_{1}[/tex] at an initial temperature [tex]T_{1}[/tex] and the rate constant [tex]k_{2}[/tex] at a final temperature [tex]T_{2}[/tex], thus

                         [tex]\ln k_{2} \ - \ \ln k_{1} = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT_{2}} \ - \ \left(\ln A \ - \ \displaystyle\frac{E_{a}}{RT_{1}}\right) \\ \\ \\ \rule{0.62cm}{0cm} \ln \left(\displaystyle\frac{k_{2}}{k_{1}}\right) \ = \ \displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)[/tex]

                                         [tex]\rule{1.62cm}{0cm} \displaystyle\frac{k_{2}}{k_{1}} \ = \ e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)} \\ \\ \\ \rule{1.62cm}{0cm} k_{2} \ = \ k_{1}e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)}[/tex]

Given that [tex]E_{a} \ = \ 26.5 \ \ \text{kJ/mol}[/tex], [tex]R \ = \ 8.3145 \ \ \text{J mol}^{-1} \ \text{K}^{-1}[/tex], [tex]T_{1} \ = \ \left(40 \ + \ 273\right) \ K[/tex], [tex]T_{2} \ = \ \left(125 \ + \ 273\right) \ K[/tex], and [tex]k_{1} \ = \ 0.0354 \ \ \text{sec}^{-1}[/tex], therefore,

           [tex]k_{2} \ = \ \left(0.0354 \ \ \text{sec}^{-1}\right)e^{\displaystyle\frac{26500 \ \text{J mol}^{-1}}{8.3145 \ \text{J mol}^{-1} \ \text{K}^{-1}}\left(\displaystyle\frac{1}{313 \ \text{K}} \ - \ \displaystyle\frac{1}{398 \ \text{K}} \right)} \\ \\ \\ k_{2} \ = \ 0.3115 \ \ \text{sec}^{-1}[/tex]                      

Use the ideas of the Kinetic Theory to explain the following. A sealed container contains nitrogen gas. The pressure of a gas is due to the molecules of the gas hitting the walls of the container. Explain why the pressure inside the container increases when the temperature is increased.​

Answers

Answer:

When the temperature increases, the molecules of the gas gain energy. Therefore, they move faster.

This causes the molecules to hit the walls of the container more frequently and with greater force. Hence the pressure inside the container increases.

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. caco3(s) 2hcl(aq)⟶cacl2(aq) h2o(l) co2(g) how many grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid?

Answers

21.1 grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.

What is a limiting reagent?

The reactant that is consumed first in a chemical reaction is the limiting reagent or limiting reactant because it stops any more reactions from taking place. The limiting reagent controls how much product is produced during the reaction.

CaCO3(s) + 2HCl(aq) ==> CaCl2(aq) + H2O(l) + CO2(g)  

[tex]mols CaCO3 =[/tex] [tex]27 *\frac{1 mol}{100g}[/tex] = 0.27 mol

[tex]mols HCl = 15 gx \frac{1 mol}{36.5 g}[/tex] = 0.38 mol

Limiting reactant = HCl ( it takes 2x the mols of HCl compared to mols CaCO3 as per balanced equation)

mass of CaCl2 = [tex]0.411 mols HCl x\frac{ 1 mol CaCl2}{ 2 mols HCl } x 111.0 g/mol[/tex]

mass of CaCl2 = 21.1 g

Hence, 21.1 g of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.

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Can Ionic bonds form single double or triple bonds?

Answers

Answer:

carbon molecules share their 4 valence electrons through single, double, and triple bonds.

Explanation:

I think you meant ionic bonds not lonic bonds

Which of the following statements is most accurate about how individual atoms produce light?

Group of answer choices

Electrons can spontaneously emit a photon of light without dropping to lower energy levels.

Light is not created by atoms, it just passes through them.

Photons are emitted when an electron jumps to higher energy levels in an atom.

An electron in an excited energy level of an atom will always drop to lower energy levels, emitting very specific wavelengths of light in the process.

Answers

Answer:

An electron in an excited energy level of an atom will always drop to lower energy levels, emitting very specific wavelengths of light in the process.

Sodium tungstate is Na₂WO4. Therefore, the formula for gold(III) tungstate is

Answers

Answer:

AuW₃

Explanation:

I need help with homework

Answers

Answer:

1. H₂SO₄

Explanation:

A balanced equation tells us how each reactant and product is related to each other in terms of moles.

The equation given has already been balanced since the number of atoms of each element is the same on both sides of the arrow. From the equation, we can see that 1 mole of H₂SO₄ reacts with 2 moles of NaOH. Whichever reactant that we do not have enough of to make more products is known as the limiting reagent, since it limits the amount of products formed.

Mole ratio of H₂SO₄: NaOH= 1: 2

The amount of NaOH needed is twice the amount of H₂SO₄ in terms of moles.

Given that there are 0.40 moles of H₂SO₄, let's calculate the amount of NaOH needed.

Amount of NaOH needed

= 2(0.40)

= 0.80 moles

However, there are only 0.75 moles of H₂SO₄. Since 0.75 <0.80, H₂SO₄ is the limiting reactant.

Additional:

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Answer:

See below

Explanation:

From the balanced equation you can see you need twice as many moles of NaOH as H2SO4....

   you have .4 moles of H2SO4   so you need .8 moles of NaOH

              but you only have .75 mole....so NaOH is the limiting factor (because you do not have enough)

A red line is observed at 656.3 nm in the spectrum of atomic hydrogen. determine the values of ???? for the beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line.

Answers

The beginning and ending energy levels of the electron during the emission of energy that leads to spectral line n(i)= 2 and n(f)=2

calculation :-(i) Calculation of energy of photon:-

wavelength(λ) = 656.3 nm = 656.3 x 10^-9

E= hc / λ

E = energy of the photon

h=Planck's constant

c=speed of light

λ= wavelength of the photon

E= (6.626 x 10^-34)(3 x 10^8)/( 656.3 x 10^-9)

E = 3.028 x 10^-37J

(ii) Beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line.

It's a red line which means it falls in a visible region which is known as the Balmer series so;

n (f) = 2

ΔE= RH (1/n(f)^2 - 1/n(i)^2)

3.028 x 10^-37 =-2.18 x 10^-18(1/2^2 - 1/n(i))

n(i)= 2

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For the reaction: C → D + B the graph of ln k vs 1/T(K) gives the equation: y = -2.2x104x + 45.0. Using this information, calculate the activation energy, (J/mol)

Answers

From the equation of the graph, the activation energy of the reaction is -2.2 * 10⁴ J/mol.

What is activation energy?

Activation energy is the minimum required energy that reactant molecules must possess for a reaction to proceed towards formation of products.

The activation energy is determined from the slope of ln k against 1/T(K).

Given the equation, y = -2.2 * 10⁴ x + 45.0.

Comparing with the equation of a straight line, y = mx + c

The gradient, m = -2.2 * 10⁴

Therefore, the activation energy of the reaction is -2.2 * 10⁴ J/mol.

In conclusion, reactant molecules must break the activation energy barrier in order to form products.

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A solution is prepared by dissolving 0.131 g of a substance in 25.4 g of water. The molality of the solution is determined by freezing point
depression to be 0.056 m. What are the moles of the substance?

Answers

The mole of the substance, given the data from the question is 0.0014 mole

What is molality?

This is simply defined as the mole of solute per kilogram of water. Mathematically, it is expressed as

Molality = mole / mass (Kg) of water

How to determine the mole of the substanceMass of water = 25.4 g = 25.4 / 1000 = 0.0254 KgMolality = 0.056 mMole of substance =?

Mole = molality × mass of water

Mole of substance = 0.056 × 0.0254

Mole of substance = 0.0014 mole

Thus, the mole of the substance is 0.0014 mole

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4NH 3+32 to 2 and 2+ 6H20 What is the mole ratio of NH3 to N2

Answers

The mole ratio would be 4:3

What is the mole ratio?

Mole ratio is the ratio of the stoichiometric number of moles of components of reactions.

From the equation: [tex]4NH_3 + 3O_2 --- > 2N_2 + 6H_2O[/tex]

The mole ratio of [tex]NH_3[/tex] to that of [tex]N_2[/tex] is the ratio of their coefficients. The coefficients are 4 and 3 respectively

Thus, the ratio is 4:3.

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Is KI + AgNO3 make potassium nitrate ?

Answers

Answer:

AgNO3 + KI → AgI + KNO3

Explanation:

Yes, it's produced potassium nitrate

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

Answers

1) The theoretical yield of SnS2 will be 4.20 grams

2) The percent yield will be 7.93%

Percent yield

From the equation of the reaction:

[tex]SnBr_4(aq)+2Na_2S(aq)-- > 4NaBr(aq)+SnS_2(s)[/tex]

The mole ratio of the reactant is 1:2.

Mole of 48.1 mL, 0.478 M SnBr4  = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M Na2S = 0.160 x 48.8/1000 = 0.0078 moles

Thus, Na2S is in excess while SnBr4  is limiting.

Mole ratio of SnBr4  and SnS2 = 1:1

Equivalent mole of SnS2 = 0.023 moles

Mass of 0.023 noles SnS2 = 0.023 x 182.81 = 4.20 grams

2) With 0.0333 g of SnS2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

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Here is the complete question:

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

1. A fluid is a substance that (a) always expands until it fills any container; (b) is practically incompressible; (c) cannot be subjected to shear forces; (d) cannot remain at rest under action of any shear force.

Answers

Answer:

cannot remain at rest under the action of any shear force.

What are the social, cultural, and environmental in pacts of water in California

Answers

lower water levels can contribute to higher concentrations of natural and human pollutants. Less water going down the drain means more water available in the lakes, rivers and streams that we use for recreation and wildlife uses to survive.

Sucrose decomposes to fructose and glucose in acid solution. When ln [sucrose] is
plotted vs. time, a straight line with slope of -0.208 hr-1 results. What is the rate law for
the reaction?
A) Rate = 0.208 hr-1 [sucrose]2
B) Rate = 0.208 hr-1 [sucrose]
C) Rate = 0.0433 hr [sucrose]2
D) Rate = 0.0433 hr [sucrose]
E) Rate = 0.208 mol L-1hr-1 [sucrose]0

Answers

The correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].

What is a first order reaction?

A first order reaction is one in which a plot of the logarithm of the concentration against time gives a straight line graph. Now we know that this is a decomposition reaction thus the slope is negative.

Thus, in this case, the correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].

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Identify the following changes as physical or chemical. A loaf of risen but unbaked bread. Photo by Elinor D Bread dough rising: physical chemical

Answers

The answers include:

A loaf of risen but unbaked bread - chemical change.Photo by Elinor D - chemical change.Bread dough rising - chemical change.

What is a Chemical change?

This involves the formation of a new products from substances. In this scenario, a rising bread contains alcohol which evaporates.

Photographs also fall under this category and is therefore an irreversible chemical change.

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2. A sample of gas has a pressure of 1.4 atm and a volume of 500 mL. If the volume is decreased to 250 mL, what is the new pressure?

Answers

Answer: The new pressure is 2.8 atm.

Explanation:

Since our given information only involves pressure and volume, we will use Boyle's Law: [tex]P_{1} V_{1} =P_{2} V_{2}[/tex]. Let's input the data into the formula.

[tex]1.4atm*500mL=P_{2} *250mL[/tex]

We have to rearrange our data a bit now because the volume is supposed to be in liters. To convert from milliliters(mL) to liters(L), you must divide the number by 1000. That is what we will do with both of our given volumes.

[tex]\frac{500mL}{1000} =0.5L[/tex]     [tex]\frac{250mL}{1000} =0.25L[/tex]

Now that our volumes are in liters, we can correctly plug in our data.

[tex]1.4atm*0.5L=P_{2} *0.25L[/tex]

Since we do not know the value [tex]P_{2}[/tex], we must rearrange the formula into a stoichiometric equation to find out the answer.

[tex]P_{2}=\frac{1.4atm*0.5L}{0.25L}[/tex]    [tex]P_{2}=2.8 atm[/tex]

Our final answer is 2.8 atmospheres.

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explain how adding soap to water affects the surface tension of water.

Answers

Answer:

The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.

A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.

There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.

Hope it helps!

Please mark me as brainlist.

Answer:

The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.

A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.

There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.

Explanation:

James was supposed to measure the circumference of three trees as homework for science class. When he got to class the next day, he realized that he measured the trees in inches instead of centimeters.

One tree had a circumference of 41 inches. What is the tree's circumference in centimeters?

Hint: 1 inch equals 2.5 cm
A.
102.5 cm
B.
27 cm
C.
135 cm
D.
16 cm

Answers

Answer:

[tex]\huge\boxed{\sf 102.5\ cm}[/tex]

Explanation:

Given that,

Circumference = C = 41 inches

Also,

1 inch = 2.5 cm

Multiply 41 to both sides

41 inches = 2.5 × 41 cm

41 inches = 102.5 cm

So, The tree has a circumference of 102.5 cm.

[tex]\rule[225]{225}{2}[/tex]

A sample of gas has temperature of 372 K and pressure of 3.8 ATM. If the temperature is increased to 550 K, what is the new pressure?

Answers

Answer: The correct answer is 5.6atm.

Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]. Now that we have the formula, let's plug in our given information!

[tex]\frac{3.8atm}{372K} =\frac{P_{2} }{550K}[/tex]

We must find the value [tex]P_{2}[/tex]. To do this, we will write a stoichiometric equation to solve this.

[tex]P_{2} =\frac{3.8atm*550K}{372K}[/tex]

Let's input the numbers into a scientific calculator to get our answer!

[tex]P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm[/tex]

Given all of this work, the value [tex]P_{2}[/tex] equals 5.6 atm.

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Other Questions
The monthly income of Ram is Rs 40,000. If he paid Rs 8,000 as income tax. Find the rate of income tax. What is the fourth rule of probability The picture below shows a soil texture triangle.Image of a soil texture triangle. Each side is labeled one of the three main soil typessilt, clay, and sandand is divided into percentages, from 0 to 100. Each point in the triangle corresponds to a different soil texture, consisting of a different combination of silty, sandy, and clay soils. For instance, the top part of the triangle contains soils that range from approximately 50 percent clay to 100 percent clay. All these different soils are considered clays. Soils located farther down the triangle contain an increasingly small percentage of clay; for example, silty clay soils are primarily silt, with more clay than sand, and sandy clay soils are primarily sand, with more clay than silt. Soils located in the middle of the triangle contain roughly equal percentages of clay, sand, and silt; these soils are called loam. There are silty loam soils, which contain more silt than clay or sand; clay loam soils, which contain more clay than silt or sand, and sandy loam soils, which contain more sand than silt or clay. There are also silty clay loam soils and sandy clay loam soils.One farmer plans to grow soybean. Soybeans grow best in medium loam soil. Which of these is the most likely soil sample that the farmer would select to grow soybeans? sample containing 30 percent sand, 35 percent clay, and 35 percent silt sample containing 25 percent sand, 15 percent clay, and 60 percent silt sample containing 40 percent sand, 15 percent clay, and 45 percent silt sample containing 55 percent sand, 30 percent clay, and 15 percent silt During the Gilded Age, how did the US Congress act to regulate business practices?Congress did not pass laws that would control the growth of monopolies. Congress was concerned about workers, so they passed laws that guaranteed a minimum wage.Congress passed laws that ensured workplace safety.Congress passed laws that supported laissez-faire policies to help businesses grow. Lins Dairy uses the aging approach to estimate bad debt expense. The ending balance of each account receivable is aged on the basis of three time periods as follows: (1) not yet due, $17,100; (2) up to 120 days past due, $6,300; and (3) more than 120 days past due, $3,300. Experience has shown that for each age group, the average loss rate on the amount of the receivables at year-end due to uncollectibility is (1) 2 percent, (2) 15 percent, and (3) 35 percent, respectively. At the end of the current year, the Allowance for Doubtful Accounts balance is $700 (credit) before the end-of-period adjusting entry is made. Required: What amount should be recorded as Bad Debt Expense for the current year? (Enter your answers as a whole percentage (i.e., 0.12 should be entered as 12).) Which of the following sentences does not use slang or jargon?Multiple ChoiceWhen I got home from work, I was so hangry I decided to nuke a frozen burrito in the microwave.When I got back to my crib, I decided to grab some shuteye.After I arrived home from work, I plopped down on the couch and turned on the television.After putting my nose to the grindstone all day, I decided to go home and catch forty winks. The point-slope form of the equation of the line that passes through (4, 3) and (12, 1) is y 1 = y minus 1 equals 1/4 left-parenthesis x minus 12 right-parenthesis.(x 12). What is the standard form of the equation for this line? The ratio of Jessicas stickers to Rods stickers is 7:4. Jessica has 21 stickers. How manystickers does Rod have? For each of the following, decide whether you agree or disagree and explain your answer: a) In economics, capital refers to wealth, primarily in the form of money of property. b) Since human capital includes the skills and knowledge of workers, it is a form of tangible capital. c) Social capital provides services to the public, so it is a form of intangible capital. Which best describes the organizational structure of The Lure of Shakespeare? 2. For the entire world's population, approximately 14% of all people speak Chinese astheir native language. Suppose four people are randomly selected from the Earth'spopulation, and define x to be the number of these who speak Chinese as their nativelanguage. The probability distribution associated with this random variable is given below.Complete the table to find the answer. Help please! Whats the answer for graphing the piece wise function to get the right answer? Which sentence is capitalized correctly? What is an example of a biological hazard? A. Norovirus B. Chlorine C. Insulation D. Hair evalute the following integral.Help me...step by step Calculate the relative rate of diffusion of 1H2 (molar mass 2.0 g/mol) compared with 2H2 (molar mass 4.0 g/ mol) and the relative rate of diffusion of O2 (molar mass 32 g/mol) compared with O3 (molar mass 48 g/mol). sec(x)- cos(x)=sin(x)tan(x) What is the coefficient of "y" after you multiply the following: ( -3 + 2 y) ( -6 + -4 )answer using two decimal places. pls help with and pls explain George is generally sensory challenged. B. Men have less sensitive olfactory receptors. C. Estrogen enhances olfaction. D. Betty has never smelled tuna. E. None of the above answers are correct.