Help please!
What’s the answer for graphing the piece wise function to get the right answer?

[tex]\sqrt{2^{2}+6^{2}}=\sqrt{4+36}=\sqrt{40}=\boxed{2\sqrt{10}}[/tex]

Answer:

Sprinter #1

Step-by-step explanation:

Sprinter #1 is running at 96/12 feet per second: 8 feet per second

Sprinter  #2 is running at 475/60 feet per second: approximately 7.9 feet per second

Sprinter #1 covers more distance per second.

Answer:

Since the radius is 3.5, to figure out the length on the diameter/side of the triangle, we have to multiply it by 2:

3.5 x 2 = 7

Now we can use the Pythagorean theorem to figure out the length of the other side of the triangle.

a^2 + b^2 = c^2

7^2 + b^2 = 25^2

49 + b^2 = 625

b^2 = 576

b = 24cm

Now that we have all the lengths of the triangle, using the radius, we can calculate the arc of the semi circle using the following formula:

(π + 2)r

(π + 2)3.5

3.5π + 7 = 18cm

Now we can add all of the lengths excluding the diameter of the circle since we want to calculate the perimeter:

25 + 24 + 18 = 67cm

Therefore, the correct answer would be C.

Answer:

thanks for the imformation

The cost to paint the walls and the ceiling is $855

First, we need to find the area that will be painted.

The area of two of the walls is:

A = 20ft*12ft = 240ft²

The area of the other two walls:

A' = 30ft*12ft = 360ft²

The area of the ceiling is:

A'' = 20ft*30ft = 600ft²

We also need to subtract the areas of the two doors and the 4 windows.

Each door is 7ft by 3ft, so the area of each door is:

a = 7ft*3ft = 21ft²

Each window is 4ft by 3ft:

a' = 4ft*3ft = 12ft²

Then the total area that will be painted is:

area = 2A + 2A' + A - 2a - 4a'

area = 2*( 240ft²) + 2*(360ft²) + 600ft² - 2*(21ft²) - 4*(12ft²)

area = 1,710 ft²

We know that we need two coats of paint to cover that area, and the cost per square foot of paint is $0.25, then the total cost is:

C = $0.25*2*(1,710) = $855

The cost to paint the walls and the ceiling is $855

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Hello !

We replace x by 3.

[tex]f(3) = {2}^{3} = 8[/tex]

Have a nice day ;)

[tex]\frak{Hi!}[/tex]

[tex]\orange\hspace{300pt}\above2[/tex]

                              We have the expression -:

                             [tex]\boldsymbol{\sf{f(x)=2^x}}[/tex], and we're asked to find

                             [tex]\boldsymbol{\sf{f(3)}}[/tex].

                             To do that we put in the value for x (3)-:

                             [tex]\boldsymbol{\sf{f(3)=2^3}}[/tex].

                             Evaluate-:

                             [tex]\boldsymbol{\sf{f(3)=2\times2\times2=8}}[/tex]

[tex]\orange\hspace{300pt}\above3[/tex]

The equivalent expression of [tex]\frac{2^4}{\sqrt[3]{xy}}[/tex] is [tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

The expression is given as:

[tex]\frac{2^4}{\sqrt[3]{xy}}[/tex]

Multiply 4 by 1

[tex]\frac{2^{4 * 1}}{\sqrt[3]{xy}}[/tex]

Express 1 as 3/3

[tex]\frac{2^{4 * 3/3}}{\sqrt[3]{xy}}[/tex]

Evaluate the product

[tex]\frac{2^{12 * 1/3}}{\sqrt[3]{xy}}[/tex]

Apply the following law of indices

[tex]a^\frac 1n = \sqrt[n]{a}[/tex]

So, we have:

[tex]\frac{\sqrt[3]{2}^{12}}{\sqrt[3]{xy}}[/tex]

The numerator and the denominator have the same root

So, we have:

[tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

Hence, the equivalent expression of [tex]\frac{2^4}{\sqrt[3]{xy}}[/tex] is [tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

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Answer:

for x = 0 ; we have f(x) = 0,5

We can eliminate the first and the last proposal because

f(x) = 0,2(0,5ˣ) ⇒ f(0) = 0,2(0,5⁰) = 0,2 × 1 = 0,2 ≠ 0,5

f(x) = 0,2(0,2ˣ) ⇒ f(0) = 0,2(0,2⁰) = 0,2 × 1 = 0,2 ≠ 0,5

Try for x = 1, we have f(x) = 0,1

f(x) = 0,5(5ˣ) ⇒ f(1) = 0,5 × 5 = 2,5 ≠ 0,1

f(x) = 0,2(0,5ˣ) ⇒ f(1) = 0,2(0,5) = 0,1 ⇒ ok

So the answer is f(x) = 0,2(0,5ˣ)

Answer:

The dependent variables in most cases is output variable. That is a value that depends on some other input value and changes based on that input value.

Step-by-step explanation:

The radius and height, in two decimal places are mathematically given as

r=10.60

Generally, the equation for the volume is mathematically given as

[tex]V=\pi r^{2} h+\frac{2}{3} \pi r^{3}[/tex]

Therefore

[tex]5000 &=\pi 0^{2} h+\frac{2}{3} \pi r^{3}[/tex]

[tex]V(r, h) &=\pi r^{2} h+\frac{2}{3} \pi r^{3}-5000 \\\nabla V &=\left\langle 2 \pi r h+2 \pi r^{2}, \pi r^{2}\right\rangle \\[/tex]

[tex]\cos t &=100\left(2 \pi r^{2}\right)+75(2 \pi r h) \\\\\cos t &=200 \pi r^{2}+150 \pi r h \\\\\nabla C(r, h) &=\langle 400 \pi r+150 \pi h, 150 \pi r\rangle[/tex]

Using Lagrange method

[tex]$\langle 400 \pi \gamma+150 \pi \gamma h, 150 \pi \gamma\rangle=\lambda\left\langle 2 \pi \gamma h+2 \pi \gamma^{2}, \pi r^{2}\right\rangle$[/tex]

[tex]$400 \pi r+150 \pi r=\left(2 \pi r h+2 \pi r^{2}\right) \lambda$[/tex]

[tex]$400 \pi \gamma+150 \pi h=300 \pi h+300 \pi r \\\\[/tex]

[tex]$400 \pi r-300 \pi r=150 \pi h$[/tex]

[tex]$160 \pi r=150 \pi h \quad \\\\\\[/tex]

with

[tex]h=\frac{2}{3} r $[/tex]

[tex]$\pi r^{2} h+\frac{2}{3} \pi r^{3}=5000$[/tex]

[tex]\pi r}\left(\frac{2}{3} r \right)+\frac{2}{3} \pi^{3}=5000$[/tex]

[tex]$\frac{4 \pi \gamma^{3}}{3}=5000 \quad[/tex]

[tex]r^{3}=\left(\frac{5000 \times 3}{4 \pi}\right)$[/tex]

r=10.60

In conclusion, the radius and height, in two decimal places is

r=10.60

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Answer:

Yes, Maureen is correct. If a system of linear equations has three equations, then there could be exactly two solutions to the system. This is because, in general, a system of linear equations with three variables will have three equations. However, if two of the equations are the same, then there will only be two equations. In this case, there will be two solutions to the system.

Step-by-step explanation:

Answer:

Step-by-step explanation:

AAS and SAS

The congruence theorems or postulates could be given as reasons why ABC= ADEF are SAS, AAS the correct options are A and F.

Suppose it is given that two triangles ΔABC ≅ ΔDEF

Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.

The order in which the congruency is written matters.

For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.

Thus, we get:

[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]

(|AB| denotes length of line segment AB, and so on for others).

We are given that;

The diagram

Now,

Based on the information given in the diagram, we can use the following congruence theorems or postulates as reasons why ABC= ADEF:

SAS (Side-Angle-Side): If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent.

We can use SAS to show that ABC and ADEF are congruent, since AB = AD, BC = DE, and the included angle BAC = the included angle EDF.

AAS (Angle-Angle-Side): If two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the triangles are congruent.

We can use AAS to show that ABC and ADEF are congruent, since the included angles BAC and EDF are congruent, angle ABC is congruent to angle ADE (since they are vertical angles), and side BC is congruent to side EF.

Therefore, by congruent triangles the answer will be SAS, AAS.

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When the multiplicity of a real root is even, the graph of the function neither crosses nor is tangent to the x-axis. The correct answer is (c) the graph is tangent to the y-axis.

When a real root has an even multiplicity, it means that the corresponding factor appears multiple times in the factored form of the polynomial. In terms of the graph of the function, this means that the graph touches the x-axis at that root but does not cross it.

Since the graph touches the x-axis without crossing it, it remains on one side of the axis. This behavior indicates that the graph is tangent to the x-axis at the root with even multiplicity.

However, the graph can still intersect or cross the y-axis at a different point depending on other factors or terms in the polynomial. Therefore, option (a) "the graph crosses the y-axis" may or may not be true depending on the overall behavior of the function. The statement in option (b) "the graph crosses the x-axis" is incorrect for an even multiplicity root. Option (d) "the graph is tangent to the x-axis" is also incorrect for an even multiplicity root. Hence, option (c) "the graph is tangent to the y-axis" is the correct choice.

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Answer:

c.) [tex]x^{3} -16x^{2} +75x-108[/tex]

Step-by-step explanation:

Check the attachment.

Answer: D. Cannot be determined

Step-by-step explanation: There are 3 postulates we can use for determining similar triangles.

There is Side Side Side (SSS) Postulate, which requires you have 2 sides of each triangle that are the same proportion as the other triangle. For example, in a triangle ABC, if 2 sides are 5 and 7, and in a triangle DEF, if 2 sides are 10 and 14, then the proportions 5/10 ( 1/2) and 7/14 (1/2) are equal. Thus these are similar triangles and the scale is 1/2.

There is Angle Angle (AA) postulate. If 2 angles are the same to another 2 angles in another triangle, then the two triangles are automatically similar.

The last is Side Angle Side (SAS), which requires you to have an angle that is congruent to another angle in a different triangle, and the angle is in between 2 sides that are proportionally equal to another triangle that also has the same angle in 2 sides. For example, if triangles ABC have angles A, B and C, and angle A is the same equal degrees to another angle in a triangle D, and both A and D are in between 2 sides (i.e DE and AB) that are proportionate (e.g DE and AB are proportionate.) The triangles are then similar.

None of these postulates can be applied to our given problem. Let's see why.

For Angle-Angle, we don't have 2 congruent angles. We have 2 right angles, but that's only 1 angle.

For Side Side Side, we don't have 2 sides given on each triangle, let alone proportionate ones.

For Side Angle Side, we don't even have 2 sides for each triangle given, so this cannot be used either.

Answer:

about 52 feet

Step-by-step explanation:

The figure is omitted--you may draw it to confirm my answer.

sin (38°) = 32/x

x sin (38°) = 32

x = 32 / sin (38°) = about 52 feet

Answer: 2

Step-by-step explanation:

A function composed with its inverse outputs the original input.

Answer:

-3/2

Step-by-step explanation:

gradient= y2-y1 over x2-x1

2-5 over 6-4

which equals to -3 over 2

Answer:

 -3/2.

Step-by-step explanation:

Slope of a line joining the points (x1, y1) and (x2, y2) is:

(y2 - y1) / (x2 - x1)  so here we have

Slope = (2 - 5)/(6 - 4)

          =  -3/2

Answer:

$80,000

Step-by-step explanation:

Define the variables:

Let x =  "fish-flavored" chicken company investment (in dollars)

Let y = spray-on vitamins company investment (in dollars)

If Allen invested a total of $100,000:

⇒ x + y = 100000

Given:

⇒ 0.03x + 0.01y = 2600

Rewrite the first equation to make y the subject:

⇒ y = 100000 - x

Substitute into the second equation and solve for x:

⇒ 0.03x + 0.01(100000 - x) = 2600

⇒ 0.03x + 1000 - 0.01x = 2600

⇒ 0.02x + 1000 = 2600

⇒ 0.02x = 1600

⇒ x = 80000

Therefore, Allen invested $80,000 in the "fish-flavored" chicken company.

The surface area of the triangular pyramid shown is 94.6 in²

An equation is an expression that shows the relationship between two or more variables and numbers.

The surface area of the regular pyramid is given as:

Surface area = 3(0.5 * 4.3 * 13) + (0.5 * 4.3 * 5) = 94.6 in²

The surface area of the triangular pyramid shown is 94.6 in²

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Answer:

y + 2 = -5(x - 4)

Step-by-step explanation:

Point-slope form is the following: [tex]y-y_{1}=m(x-x_{1})[/tex], where m is the slope of the line and [tex](x_{1}, y_{1} )[/tex] is a point on the line. We are already given all of the information we need, so all we have to do is write it out. We are told that the slope (m) is -5, and the point the question wants us to use is (4, -2), though either of the points given would work. If we plug in the quantities, we get that y - (-2) = -5(x - 4), or y + 2 = -5(x - 4)

Answer:

if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2

Step-by-step explanation:

join my stream and tell me how to label the triangle

(ChildOfHermes)

Answer:

this gvfyftvyccg c

Step-by-step explanation:

New information obtained through research or experimentation that enables an updating or revision of the state-of-nature probabilities is known as SAMPLE INFORMATION.

Hence, 2nd option is the best choice.

A statistical concept called joint probability determines the chance that two events will occur simultaneously and at the same time.

A sample is a collection of people, things, or things used in the study that is taken for analysis from a wider population. To enable us to extrapolate the study sample's findings to the entire population, the sample must be representative of the population. Sample information is the collection of the information of the sample.

The possibility of an event or outcome happening contingent on the occurrence of a prior event or outcome is known as conditional probability. The probability of the prior event is multiplied by the current likelihood of the subsequent, or conditional, occurrence to determine the conditional probability.

The expected utility of a course of action is a weighted average of the utilities of each of its potential outcomes, where the utility of a potential result indicates how much it is preferred to the alternatives.

In the question, we are asked what will be the new information obtained through research or experimentation that enables an updating or revision of the state-of-nature probabilities called.

As we are to name the information, it will be called sample information, from the above-discussed points.

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Answer:

Step-by-step explanation:

To answer this, you also need to click the transversal pic above.

Question 5

1) Given

2) Definition of congruent segments

3) Reflexive property of equality

4) Addition property of equality

5) Substitution

6) Commutative property of addition

7) Segment addition postulate

8) Substitution

9) Segments with equal measure are congruent

Question 6

1) Given

3) Segment addition postulate

4) Substitution

5) Subtraction property of equality

7) SSS

Answer:

Equation of a line passing through two point (a, 0) and (c, d) is given by [tex]$y=\frac{d}{c-a} x-\frac{a d}{c-a}$[/tex].

Step-by-step explanation:

In the question, it is given that a line passes through (a, 0) and (c, d).

It is asked to write the equation of line.

To do so, first find the values which are given in the question and put it in the formula of the equation of line passing through two points.

Step 1 of 2

Passing point of the line is (a, 0).

Hence, [tex]$x_{1}=a$[/tex] and

[tex]$$y_{1}=0 \text {. }$$[/tex]

Also, Passing point of the line is (c, d).

Hence, [tex]$x_{2}=c$[/tex] and

[tex]$$y_{2}=d \text {. }$$[/tex]

Step 2 of 2

Substitute the above values in the formula of equation of line passing through two point given by [tex]$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)$[/tex].

[tex]y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)$$\\ $y-0=\frac{d-0}{c-a}(x-a)$\begin{aligned}&y=\frac{d}{c-a}(x-a) \\&y=\frac{d}{c-a} x-\frac{d a}{c-a}\end{aligned}$$[/tex]

Hence, [tex]$y=\frac{d}{c-a} x-\frac{d a}{c-a}$[/tex].

Based on Diego's normal usage of his phone, if the battery is at 75%, the phone will not last the whole trip.

First find out how long each percentage of battery life lasts:

= 15 / 100

= 0.15 hours

If Diego is going on a 12 hour trip with 75%, the length of time it would last is:

= 0.15 x 75

= 11.25 hours

This is less than the 12 hours required so the phone will not last the whole trip.

Rest of question:

At 100%, the battery can go for 15 hours.

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Answer:

a,b,d

Step-by-step explanation: