air enters the diffuser of a ramjet engine (fig. 9.27c) at 25 kpa, 220 k, with a velocity of 3080 km/h and decelerates to negligible velocity. on the basis of an air-standard analysis, the heat addition is 900 kj per kg of air passing through the engine. air exits the nozzle at 25 kpa. determine

The distance between the image and the mirror is -4.63 cm.

The mirror equation is given by,

1/u + 1/v = 1/f

where, u is the distance to the object = 17.95 cm

v is the distance to the image

f is the focal length = -6.25 cm

Placing the values in the equation, we have

1/17.95 + 1/v = -1/6.25

1/v = -1/6.25 - 1/17.95

1/v = - 0.16 - 0.056

1/v = - 0.216

v = -4.63 cm ( minus sign indicates that the image is behind the mirror and it is virtual)

Thus, the image distance is -4.63 cm.

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Each star has a mass M of 1.43 × 10³²kg.

The simplest types of orbits in celestial mechanics are circular orbits, in which an orbiting body moves around a gravitational mass while maintaining a constant radius.

masses are m1 = m2 = M.

Each star orbits at a speed of Vs = 240 km/s or 240000 m/s.

T = 12.5 days, often known as 12.5246060, or 1080000sec, is the orbital period.

Fc = Mv²/r

The mathematical formula for the gravitational force exerted on these stars is

Fg = GM²/d²

so Fc = Fg

Mv²/r = Gm₁ₓm₂/d²

v²/r = GM/(2r)²

v²/r = GM/4r²

M = v² × 4r /G

D = V × T

D = 240000 × 1080000

D = 2.592×10¹¹ m

D = 2πr

Therefore

2πr =  2.592×10¹¹ m

r = 2.592×10¹¹ / 2π

r = 4.124 × 10¹⁰ m

So,

M = v² × 4r/ G

M = (240000)² × 4 ×  4.124 × 10¹⁰/ 6.67 × 10 ⁻¹¹

M =  1.43 × 10³²kg.

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Volcanoes that are currently erupting are the source of the ionized gas in the charged particle belt that resembles a donut around Jupiter.

Any particle with an electric charge is referred to as a charged particle in physics. It could be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. Another possibility is that it's an elementary particle like an electron, proton, or another one with the same charge (except antimatter). Atomic nuclei without electrons, like alpha particles, could also be charged particles.

The term "plasma" refers to a mixture of charged particles, atomic nuclei, and separated electrons, but it can also refer to a gas with a considerable amount of charged particles.

Positive (+) and negative (-) charges are randomly assigned to charges (-). Positive charges don't have any intrinsic properties; the only known "types" of charges are the two that are currently known.

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The  (2) and (3), that contact force in case (a) is greater than in case (b).

What is force ?

Everyday activities like walking, setting something down on a surface, tossing something into the air, and even the tides' regular variations all include the application of force. The result of the interaction between two or more things, a force is a push or a pull.

What is acceleration ?

Acceleration is the rate at which velocity changes, as well as how quickly velocity changes over time. instantaneous acceleration is an acceleration at a single moment instantaneous acceleration divided by time deceleration

N1 and N2 are normal forces

T1 and T2 are contact force , (equal in magnitude, but opposite in direction)

i.e |T1| - |T2|

here for both case, acceleration

a = Fo/m1+ m2

a = Fo/M + 3M = Fo/um -(1)

acceleration for both cases remains same, as two blocks move with a single force fo, together

Fo – T2 = Ma or T1 = 3Ma

= T1 = 3M (Fo/4M)

T1 = 3/4  Fo –(2)

Fo – T2 = 3Ma

         T2 = Ma

         T2 = M (Fo/4) – (3)

It is obvious from (2) and (3), that contact force in case (a) is greater than in case (b).

Therefore, (2) and (3), that contact force in case (a) is greater than in case (b).

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The answer is, p(x) = 0.1x + 1          (p(x) is the pressure at a depth x)

Just what is pressure?

The amount of force applied to a certain region is referred to as pressure.

1 atmosphere is the pressure at sea level.

Sydney dove to a depth of 23 meters.

23-meter depth equals 3.3 atmospheres of pressure

23-meter deep pressure equals pressure at sea level plus k.

Sydney dove to a depth of 3.3 meters, where 3.3 = 23 k + 1 is the diving rate constant.

By deducting 1 from either side, we arrive at 3.3 - 1 = 23k + 1 -1.

2.3 = 23k is obtained by eliminating the +1 and -1 from the right side.

After subtracting the 23s from the top and bottom of the left side, we arrive at k = 0.1 by dividing both sides by 23.

When we enter k's value into the equation, we obtain

Pressure at a specific depth is equal to sea level pressure plus k. * Sydney's depth dove

p(x) = 1 + k(x)     [where p(x) is the pressure at a depth x]

=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

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A GFCI measures the amount of current that flows from hot to neutral.

What is circuit ?

A circuit is a closed channel in electronics that permits electricity to flow from one place to another. It may contain a variety of electrical components such as transistors, resistors, and capacitors, but the flow is not hampered by a gap or break in the circuit.

A simple circuit is illustrated using a flashlight. When the switch is turned off, the circuit is not closed, which means that no electrical current flows from the batteries to the flashlight's bulb. When you turn the switch on, a piece of metal in the flashlight physically plugs the circuit gap. Electricity goes from the batteries to the bulb, causing it to light up.

A GFCI measures the amount of current that flows from hot to neutral. If there is an imbalance, the circuit will trip. The GFCI detects mismatches as tiny as 4 or 5 milliamps and can respond in as little as one-thirtieth of a second.

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Normal force that will act on the body moving downward will be  480 newtons.

One of the most significant laws in all of physics is Newton's second law. F = ma, wherein F (force) as well as a (acceleration) both are vector values, can be used to represent an object with mass m is constant. A body accelerates according to the equation if there is a net force that acts on it.

Until and unless an external force occurs on a body, it is in a condition of rest or homogeneous movement in a straight line. According to Newton's first law of motion, a body won't begin to move unless and until an outside force impacts it.

given:

m=20 kg, a= 2.0m/s^2, g=10 m/s^2

   Mg-F(normal)=Ma

  60*10-F(normal)=60*2

 F(normal)=480N

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You want exactly nine gallons of water, but you have seven-gallon bucket and five-gallon bucket. To solve this problem, we use the method of selective combination.

We should fill the seven gallon bucket and then pour it into five gallon bucket, leaving the two gallon behind. Discard five gallons and pour two gallon into five-gallon bucket and refill seven-gallon bucket. You will have a total of nine gallons.

To elaborate, the selective combination is an insight producing process that occurs when one merges two or more components that are seemingly unrelated to produce a working solution.

In this case, two components combined are the five-gallon bucket and the seven gallon bucket.

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Answer:

0.500 m/s south

Explanation:

To find Patrick's average velocity for the trip, you need to find the total distance traveled and the total time taken for the trip.

Patrick walks 70.0 meters south in 150.0 seconds, for a total distance traveled of 70.0 meters. He then walks 20.0 meters north in 30.0 seconds, for a total distance traveled of 20.0 meters. The total distance traveled for the trip is therefore 70.0 + 20.0 = 90.0 meters.

The total time taken for the trip is 150.0 seconds + 30.0 seconds = 180.0 seconds.

The average velocity for the trip is the total distance traveled divided by the total time taken, so the average velocity is 90.0 meters / 180.0 seconds = 0.500 m/s.

Therefore, the correct answer is 0.500 m/s south.

Determine the torque around this point created by each force acting on the wrist and select an axis to compute the torques about.

The forearm is the upper limb component that reaches from the shoulder to the wrist. Its bone structure is made up of the ulna and radius which are positioned laterally (medially).

The term "arm" most commonly refers to the entire upper limb appendage, although in anatomy, the phrase "forearm" is used to distinguish it from that.

As a result, the stress exerted by the bicep is 7.38 times more than the weight supported.

The formula for torque is Γ=r×F=rFsin(θ). Torque is, in additional observations, the cross product of the force vector & the distance vector, where a is the angle between r & F.

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Answer:

8.83 N/kg

Explanation:

To solve this problem we can use the formula:

[tex]g=G\frac{M}{r^{2} }[/tex] which describes the field strength at a certain distance from a body (where g=gravitational field strength, G=Gravitational constant, M=Mass of planet, and r=distance from center of planetary mass).

We are given the information that the radius of Venus is 6.073 x 10^6m and its mass is 4.88x10^24kg.

We are also given the gravitational constant.

Since the radius of a planet is equal to the distance between the center of the planet to its surface we can use this value for 'r'.

Therefore we now have all the information we need and so we can plug these values into the equation to solve for the gravitational field strength:

[tex]g=(6.67*10^{-11})\frac{(4.88*10^{24})}{(6.073*10^{6})^{2}}[/tex]

[tex]g=(6.67*10^{-11})\frac{(4.88*10^{24})}{3.688*10^{13}}[/tex]

[tex]g=(6.67*10^{-11})*(1.323*10^{11})[/tex]

[tex]g=8.83Nkg^{-1}[/tex] (to 2.d.p)

This statement is True because A synchronizer sleeve is moved to the input shaft chain sprocket by the mode fork, which resembles a shift fork in a manual transmission, once four-wheel drive .

When a vehicle has a manual transmission, the driver controls the clutch and selects the appropriate gear. Most drivers believe a manual transmission, or stick gear as it is commonly known, gives them a greater sense of involvement with the car's operation and makes driving more enjoyable.

A manual gearbox is essentially a gear train that allows the driver to select from a variety of gear ratios to operate the vehicle. Higher gear ratios provide less torque but more speed, while lower gear ratios provide more torque but less speed.

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The length of the can above the water level is  0.052195 m  .

In the question ,

it is given that ,

capacity of the soda can = 355 ml = 0.000355 m³

diameter of the soda can = 6.2 cm = 0.062 m

mass of the soda can = 20g = 0.02 Kg

given that the soda can is half filled , so , the water volume in the can is

= 0.000355/2 m³

= 0.0001775 m³

Let the density of the water be  = 1000 kg/m³

So , the mass of the half filled water will be = 1000×0.0001775

Let water density be 1000kg/m³ , the mass of this half-filled water is

= 0.1775

So , The total mass of the water-can system is = 0.1775 + 0.02 = 0.1975 kg

Now , For the system to stay balanced, the total mass should be equal to the mass of water displaced by can submerged

So , The volume of water displaced by submerged can is

= 0.1975/1000 = 0.0001975 m³

So , Volume of the can that is not submerged( above water level) is

= 0.000355 - 0.0001975

= 0.0001575 m³

We know that base area of  can = πr² = π(d/2)² = π×(0.062/2)²

= 0.00301754 m²

So , the length of the can above water is = 0.0001575/0.00301754

= 0.0521948342 m

≈ 0.052195 m

Therefore , the can will be 0.052195 m above the water level .

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The magnetic field is upward diection.

What is magnitude ?

The definition of magnitude is "distance or amount." It displays an object's size or motion in either an absolute or a relative sense. It is a means of describing the magnitude or range of something. In physics, a magnitude frequently describes a length or a size.

What is magnetic field ?

The magnetic field is the region where the force of magnetism works around a magnetic substance or a moving electric charge. a magnetic field illustration that shows how the magnetic force is distributed throughout and around a magnetic substance.

Inside the circulation region at distance r,

El = d∅/dt = s (dB / dt )

Therefore E (2π r ) = (π r2). dB/dt

Therefore E = r dB/2 dt

F = qE = qr dB/ 2 dt

At points a and b, distance from Centre is r

Therefore F = qE = qr dB/2 dt

At point c, distance r = 0

Therefore F = 0

Magnetic field is increasing. Hence, induced current in an imaginary loop passing through a and b should be anti-clockwise. Force on positive charge is in the direction of induced current. Hence force at a is towards left and force at b is upward.

Therefore, the magnetic field is upward direction.

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The change in Mary’s potential energy is - 3412.5 Joule.

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

Given that:

Weight of Marry: W = 525 N.

She walks down a flight of stairs to a level 6.5 m.

Hence, decrease in potential energy of her = Wh

= 525 N × 6.5 m

= 3412.5 Joule.

Hence, the  decrease in potential energy of her is 3412.5 Joule.

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The expression for [tex]v^{2}_t[/tex] is equal to √5 times of [tex]v^{2}_b[/tex] where [tex]v_t[/tex] and [tex]v_b[/tex] are the velocities of ball at top and bottom of the circle respectively.

Consider the centripetal force at any point.

T – mg cosθ = m v² ⁄ r

T = mg cosθ + m v² ⁄ r

From figure, cosθ = (r – h) ⁄ r

Substitute in the equation of T.

T = m g (r – h) ⁄ r + m v² ⁄ r

  = m ⁄ r (g (r – h) + v²)

But v² = u² – 2 g h

T = m ⁄ r (g r – g h + u² – 2 g h)

 = m ⁄ r (u² – 3 g h + g r)

This is an equation for tension in string.

Now, when ball is at the top of circle

We have,  

v = √(u² – 2 g h)

 = √(5 g r – 2 g ×(2 r))

 = √(5 g r – 4 g r)

 = √(g r)

And, when ball is at the bottom of the circle,

T[tex]_H[/tex] > 0

m ⁄ r ×(u² – 5 g r) > 0

u² – 5 g r > 0

u² > 5 g r

u > √(5 g r)

Hence,[tex]v^{2}_t[/tex] is equal to √5 times of [tex]v^{2}_b[/tex]

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The energy of the first two quantum states, given that the black body cabity has frequency of 5.0×10¹⁴ Hz is 3.313×10⁻¹⁹ J

Energy is defined as the capacity to do work. However, energy and frequency are related according to the formula given below:

E = hf

Where

We can obtain the energy of the two quantum states as shown below:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

E = 6.626×10⁻³⁴ × 5.0×10¹⁴

E = 3.313×10⁻¹⁹ J

Thus, we can conclude from the above calculation that the energy is 3.313×10⁻¹⁹ J

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The momentum of the cart of mass 18 kg is 12.6 kgm/s.

Momentum is the product of mass and velocity.

To calculate the momentum of the shopping cart, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the momentum of the cart is 12.6 kgm/s.

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The momentum of the shopping cart will be 12.6Kgm/s.

Momentum is defined as the product of mass of an object and velocity of that object. It is vector quantity and it has both direction and magnitude.

The formula for momentum is written as;

p = m × v

p = momentum

m = mass of the object

v = velocity

p = m × v

where m = 18kg

v = 0.7m/s

p = 18 x 0.7

p = 12.6 Kgm/s

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Based on the provided figures, the dough balls which is experiencing shear stress is option C.

Shear stress refers to force tending to cause deformation of a material by slippage along a plane or planes parallel to the imposed stress. The resultant shear is significant in nature, being intimately related to the downslope movement of earth materials and to earthquakes. Shear stress may also happen in solids or liquids. Shear stress causes foliation. When a rock is acted upon by pressure that is not the same in all directions, or by shear stress, minerals can become elongated in the direction perpendicular to the main stress and the pattern of aligned crystals that results is known as foliation. Foliation is among the features that are helpful in identifying many metamorphic rocks.

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A particle of mass m is travelling with an initial velocity of u I along the x-axis.

It moves with half of its initial kinetic energy after elasto-magnetically colliding with a particle of mass 10 m at rest (see figure). If sin 1 = n sin 2, then n has value. A particle of mass m collides with a particle of mass 2m that is initially at rest while travelling along the x-axis at a speed of v. Following the collisions, as shown in the picture, the second particle has split into two equal-mass pieces that travel at equal angles theta? 0 with the x-axis. The first particle has come to rest. The x-axis is being traveled by a particle. Its speed (v) along with.

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I answered it in general way

Since the field is divided into subplots and a random sample is selected from each subplot, stratified sampling is used.

Sampling is the procedure used by researchers to choose a subset of participants from a larger group, given that it is usually impossible to evaluate the entire population. In the case of stratified sampling, this entails breaking the overall population into smaller groups, known as strata, and then choosing a particular number of people from each strata. This approach ensures that the sample is chosen at random, ensuring the objectivity of the research. The approach used in the example provided was stratified sampling since a 46-acre field's general population was separated into subplots that represent was split up into smaller plots that stand in for the strata. The researcher then chose one random sample following that.

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Answer:

Aluminium is extracted from bauxite. Bauxite is the name for the ore in which around 30 to 54% of the aluminium oxide is contained. Because of the fact that aluminium has a tendency to bind with oxygen, there is very little pure aluminium found naturally.

Explanation:

The magnitude of the force that a concrete support exerts on the bridge (a) at the near end is 2593 N  (b) at the far end is  2002 N    .

In the question ,

it is given that ,

the hiker weighs : [tex]W_{h}[/tex] = 985 N

the bridge's weight ([tex]W_{b}[/tex]) is = 3610 N ,

let the magnitude of the force that concrete support exerts on bridge at near end is = F₁    and

let magnitude of force that concrete support exerts on bridge at far end is = F₂ .

Since the bridge is in equilibrium   , the sum of all the forces in the vertical direction will be = 0 .

So , F₁ + F₂ -  [tex]W_{h}[/tex] - [tex]W_{b}[/tex] = 0

Substituting the value ,

we get ,

F₁ + F₂ -  985 - 3610 = 0

F₁ + F₂ = 4595 N

also given that , the hiker is at 1/5th position of the length of bridge from left support = L/5 m .

Since the bridge is not rotating , the net torque will be 0 .

[tex]T_{net}[/tex] = 0 .

The torque due to weight of hiker, due to weight of bridge and due to right end support about point nearest support is written as :

So ,  [tex]W_{h}[/tex]×(L/5) +  [tex]W_{b}[/tex]×(L/2) - F₂×L = 0

[tex]W_{h}[/tex]×(1/5) +  [tex]W_{b}[/tex]×(1/2) = F₂

985×(1/5) + 3610×(1/2) = F₂

So , F₂ = 2002 N

Substituting the value of force in the equation F₁ + F₂ = 4595 N  ,

we get ,

F₁ + 2002 = 4595

F₁ = 4595 - 2002

F₁ = 2593 N

Therefore , The magnitude of the force at the near end is 2593 N and at the far end is 2002 N .

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The height of the cliff will be equal to 5.37 meters, and the time taken to reach the ground if it is thrown straight down with the same speed will be equal to 0.50 s.

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.

As per the given information in the question,

Use the equation given below to find the vertical height of the cliff.

y = y₀ + ut + 1/2 at²

Here,

y represents final position of the object

y₀ is the initial position of the object and t is the time interval.

So,

y₀ = y -ut -1/2at²

y₀ = 0 - (8.16)(2.17) - 1/2(-9.8)(2.17)²

= -17.70 + 23.07

= 5.37 meters.

(b)

Now again rearrange the equation,

y = y₀ + ut + 1/2at² for y - y₀

Now, find the quadratic equation in time,

t = -u ± √[u² - 4(1/2a)(y₀ - y)]/2(1/2a)

Put the values in the above equation,

= -(-8.16 m/s) ± √[(-8.16)² - (-9.8)(2)(5.37)]

= [8.16 ± √(66.58 + 105.25)]/-9.8

= [8.16 ± 13.1]/-9.8

= -4.94/-9.8 = 0.50 s.

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The constant speed (relative to earth) required for the trip is 0.9959.

Solution:

Then these three equations combine to give a single condition from which γ can be determined (and consequently v ):

44 = 4y = y=11 = β = 2√3/11  = 0.9959

A car moving at a constant speed is an example of constant speed because it travels the same distance in the same amount of time. Aircraft systems use constant-speed drives to transfer power to an onboard generator at a constant output speed regardless of engine input speed.

Even if the speed is constant the speed will change if you are moving in a circular motion. This is because when an object moves in a circle, the direction of movement is always changing. Therefore the speed is not constant. DC motors have a large installed base and provide maximum torque at zero speed.

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The change in the kinetic energy of the cart during the move is equal to 98.04 J

According to work energy theorem, the net work done W on an object is equal to the change in the kinetic energy of the object.

W = Kf -Ki

Here, Kf is the final kinetic energy and Ki is the initial energy

The work done on an object is,

W=Fd

Here, F is the force applied on the object and dis the displacement of the object.

Equate these two equations.

Ki-K = Fd

ΔK=Fd

The force exerted on the cart is the tension Tin the chord itself. So,

F=T

Calculate the displacement of the cart.

d = √x²+h² −√x²+h²

Substitute 5.0 m for x,, 1.0 m for x,, and 1.60 m for h.

d=√(5.0 m)² +(1.60 m)² - √(1.0 m)² +(1.60 m)²

=3.36 m

Calculate the change in kinetic energy of the cart.

ΔK = Fd

Substitute 28.0 N for F and 3.36 m for d.

ΔK = (28.0 N) (3.36 m)

=94.08 J

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Reflection of light is when light waves bounce off a surface.

Reflection occurs when light traveling through one material bounces off a different material. The reflected light continues to travel in a straight line, but in a different direction.

The incident light ray that land on the surface is called the reflected off the surface while the ray that bounces back is called the reflected ray.

For example, if an individual looks at a bird, light has reflected off that bird and traveled in nearly all directions. If some of that light enters the individual's eyes, it hits the retina at the back of the eyes. An electrical signal is passed to the person's brain, and the brain interprets the signals as an image.

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Make use of this FADH,+Q- The reduced reactant is In complex III, iron-containing cytochrome C receives electrons from coenzyme Q. QH; +2 cyt (Fe); Q+2 cyt (Ft); +2H+. Iron's oxidation number is +2, which is shown on the right side of the reaction arrow.

FADH₂ + Q  [tex]\rightarrow[/tex]  QH2+ FAD+

Coenzyme Q is reduced in this situation, and FADH2 is oxidized, hence the correct response is Q.

reduced Complex III oxidizes coenzyme Q, cut chromosome c is reduced, resulting in the reduction of Fe3+ to Fe2+, and the iron on the right side is now in the +2 oxidation state.

so the answer is x=+2

Subatomic particles known as electrons have a -1 magnitude elementary charge. The magnitude of an electron's charge is equivalent to that of a proton (but has an opposite sign).

Because of this, electrically neutral atoms and molecules need to contain an equal number of protons and electrons. The size and mass of an electron are significantly smaller than those of a proton, despite the fact that the magnitude of the charges borne by protons and electrons is the same (the mass of an electron is around 1/1837 that of a proton).

Protons, electrons, and neutrons are the fundamental subatomic particles that were later identified by scientists. At the core of each atom is a large mass known as the nucleus. Both neutrons and protons are found in the nucleus. Take into account the solar system.

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The coefficient of restitution between the ball and the surface is equal 0.70.

The coefficient of restitution can be defined as the ratio of the final to the initial speed between two objects after they collide. It generally ranges from 0 to 1 where 1 will be a perfectly elastic collision.

The velocity of the ball when drooped from height 'h' is given by:

[tex]v = \sqrt{2gh}[/tex]

Before impact, the velocity is given by: [tex]u_1 = \sqrt{2gh}[/tex]

[tex]\displaystyle e =\sqrt{\frac{2gh_1}{2gh}}[/tex]

[tex]\displaystyle e =\sqrt{\frac{h_1}{h}}[/tex]

Given, h = 2 m , h₁ = 0.98 m

[tex]\displaystyle e =\sqrt{\frac{0.98}{2} }[/tex]

e = 0.70

Therefore, the coefficient of restitution between the ball and the ground is 0.70.

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Answer:

243?

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