Ade think of a number.he double it and then subtract five.the results cannot less than 100 . find the range of value of x

Because there are 36 total possibilities, the probability P (sum of 12 OR 5) is 7/36.

It is defined as the ratio of favorable outcomes to total outcomes; in other words, the probability is the number that indicates the likelihood of an event occurring.

Given data;

Total outcomes rolling a pair of dice =6×6=36

Probability obtaining the total of 12 is;

P(A) = 1/36

P(A) = 1/36

P(A) = 1/36

Probability of obtaining the total is less than 5:

P(B)=6/36

the probability of rolling the sum of 12 OR less than 5 is calculated as;

P(sum of 12 OR 5) = 1/36 + 6/36

P= 7/36

Hence,the probability P (sum of 12 OR 5) is 7/36.

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It's a combine function (Alike signum function)

Which is given by

[tex]\\ \rm\Rrightarrow f(x)=\begin{cases}\sf 3x,x<3\\ \sf 2x,x>3\end{cases}[/tex]

Find some points

Graph attached

Red line is 2x and blue one is 3x

Answer:

Median: 11

Range: 12

25th Percentile: 9

75th Percentile: 14

Interquartile Range: 5

Step-by-step explanation:

The median is the line in the 'middle' of the box. The range is the largest number minus the smallest number. 25th Percentile is the first line of the box, 75th is 3rd line. IQR is the 75th Percentile - 25th Percentile.

Hope this helps! :)

8 × 6 = 8 × (5 + 1)

… = (8 × 5) + (8 × 1)

… = 40 + 8

… = 48

-5(y+2)=25

y+2=25 ÷(-5)

y+2= -5

y= -5-2

y=7

Answer:

the stripe chip design has

the greatest probability of selection

Step-by-step explanation:

p(draw a dot chip) = 1/10

p(draw a star chip) = 2/10

p(draw a heart chip) = 3/10

p(draw a stripe chip) = 4/10

4/10 > 3/10 > 2/10 > 1/10

Therefore , the stripe chip design has

the greatest probability of selection.

Factors of 130: 1, 2, 5, 10, 13, 26, 65, 130

GCF of 52 and 130 is 26

I found a similar question here so that's what I can only tell you. I hope it will help you.

Answer:

Step-by-step explanation:

Based on the height the yard dart is thrown from, the inital velocity, and the elevation angle, the length of time the dart is in the air is 1.6 seconds.

This can be solved using a projectile motion calculator which can show you the velocity of the dart and the time it spent in the air.

Plugging in the given values above, we find that the yard dart spent a total of:

= 1.6 seconds in the air

In conclusion, option D is correct.

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[tex]\\~~~~~3x^2 +4x +7 = -1\\\\\implies 3x^2 +4x +7 +1 = 0\\\\\implies 3x^2 +4x +8 = 0\\\\\text{It is now in the standard form of quadratic equation}~( ax^2 +bx +c = 0)\\[/tex]

Answer:

a

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

u know that the left triangle is not a right angles triangle so u cannot do Pythagoras and 27 is the other bottom side meaning that the length of the left triangle base is 20.25

Answer:

18.43 units

Step-by-step explanation:

132/360 cause 360 degrees in circle

π4^r=area of totoal

16π= area

16π*132/360=18.4306769011

Answer:

l=5.1in

r=2.4in

Step-by-step explanation:

size increase of 50% so just add (+50%) to both existing values

Answer:

91

Step-by-step explanation:

9x8-7+4x10-2x7

72-7 + 40- 2x7

72 - 7 + 40 - 14

65 + 40 - 14

105 - 14

= 91

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Since, the Area of smaller rectangle is 35,

Let's calculate it's length ~

[tex]\qquad \sf  \dashrightarrow \:a = l \cdot w[/tex]

[tex]\qquad \sf  \dashrightarrow \:35 = l \cdot5[/tex]

[tex]\qquad \sf  \dashrightarrow \:l = 35 \div 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:l = 7 \: ft[/tex]

And the two rectangles are similar ~ so the ratio of their sides are equal as well ~

Assume length of greater rectangle be x

[tex]\qquad \sf  \dashrightarrow \: \dfrac{25}{5} = \dfrac{x}{7} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 5 \times 7[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 35[/tex]

Now, since the length and width of the greater rectangle is known, let's find it's Area ~

[tex]\qquad \sf  \dashrightarrow \:a = l \cdot w[/tex]

[tex]\qquad \sf  \dashrightarrow \:a = 35 \sdot25[/tex]

[tex]\qquad \sf  \dashrightarrow \:a = 875 \: \: ft {}^{2} [/tex]

So, Area of the greater rectangle is 875 ft²

A parallelogram is a type of quadrilateral(four sides polygon) that has both the pair of opposite sides parallel and equal.

Area of a parallelogram = height× base

from the question,

height= 6cm

base= 5cm

area= 6×5= 30cm^2

====================================

[tex]\large \sf \underline{Problem:}[/tex]

The weight of the rectangle is 80 grams.

The weight of the triangle is double the weight of the

circle.

Determine the weight of the circle.

====================================

[tex]\large \sf \underline{Answer:}[/tex]

Rectangle has four sides. The total weight of the circle is 20 grams.

====================================

[tex]\large \sf \underline{Explanation:}[/tex]

What is a rectangle?

A rectangle is a 2D shape that has four sides, and the pair of opposite sides are equal and parallel to each other.

As it is given that the weight of the rectangle is 80 grams, and a rectangle is made up of two triangles. Therefore, the weight of each triangle can be written as,

[tex]Weight \: of \: the \: reactangle \: = \frac{80}{2} = 40 grams[/tex]

It is given that the total weight of the triangle is double the weight of the circle. therefore, the relationship can be written as,

[tex]Weight \: of \: the \: triangle = 2x \\ Weight \: of \: the \: circle \: \\ 40 = 2 \times Weight \: of \: the \: circle

[/tex]

[tex]Weight \: of \: the \: circle = 20 grams[/tex]

Hence, the total weight of the circle is 20 grams.

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====================================

Hence the weight of the circle is 20 grams.

Answer:

Solution Given:

Weight of rectangle =80grams

we know that

twice the weight of triangle =weight of rectangle

2*weight of triangle =80 grams

weight of the triangle = 80/2=40 grams

again

The weight of the triangle is double the weight of the

circle.

weight of the circle=½*weight of triangle

=½*40=20grams

Answer:

It has a minimum of -3 and a unkown maximum

Step-by-step explanation:

The chords ac and db are intersecting chords, and the length of line segment db is 16 units

The given parameters are:

ah = 20 - x

hb = 12 - x

dh = x + 4

hc = x

Start by calculating the value of x using the following intersection chord equation

ah * hc = dh * hb

So, we have:

(20 - x) * x = (x + 4) * (12 - x)

Solve for x

x = 4

The length of segment db is calculated using:

db = dh + hb

So, we have:

db = x + 4 + 12 - x

Substitute 4 for x

db = 4 + 4 + 12 - 4

Evaluate

db = 16

Hence, the length of line segment db is 16 units

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Answer:

c

Step-by-step explanation:

Answer:

Kale, 1 carrots, 4 sweet potatoes, 3, beets, 2

Step-by-step explanation:

um just round

P.S. Iready sucks

Answer:

Kale ; 1(oz)

Carrots; 4(oz)

Sweet Potatoes; 4(oz)

Beets; 2(oz)

Step-by-step explanation:

       Kale              \          1.35                ⇒    1(oz)

    Carrots            \         3.50                ⇒   4(oz)

Sweet potatoes   \         3.81                ⇒   4(oz)

      Beets              \        2.29                ⇒   2(oz)

Answer:

tan65=?/7

7*tan65=?

=15.0115

change (x,y) -> (-y,-x)

Hi Student!

Looking at the question we can see that we are given a number which is 120 days.  The question is asking for us to convert the amount of days it took to break the code into hours.  We can do this by multiplying the amount of days that we have by 24 because there are 24 hours in a day.  The days would cancel and that would result us with just hours left.

[tex]120\ days*\frac{24\ hours}{1\ day}[/tex]

[tex]\frac{120\ days\ *\ 24\ hours}{1\ day}[/tex]

[tex]\frac{2880\ hours}{1}[/tex]

[tex]2880\ hours[/tex]

Therefore, our final answer is that it took the computer 2880 hours to break the code after we converted the days to hours.

Check the picture below.

now, we're making an assumption that, the two blue shaded region are equal in shape, and thus if that's so, that area above the 14 is 6 and below it is also 6, 14 + 6 + 6 = 26.

so hmm if we simply get the area of the trapezoid and subtract the area of the yellow triangle and the area of the cyan triangle, what's leftover is what we didn't subtract, namely the shaded region.

[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=14\\ b=26 \end{cases}\implies A=\cfrac{15(14+26)}{2}\implies A=300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\stackrel{trapezoid}{300}~~ - ~~\stackrel{yellow~triangle}{\cfrac{1}{2}(26)(9)}~~ - ~~\stackrel{cyan~triangle}{\cfrac{1}{2}(15)(6)}} \\\\\\ 300~~ - ~~117~~ - ~~45\implies 138\qquad \textit{blue shaded area}[/tex]

Answer:

x=11

y=9

Step-by-step explanation:

place both and solve for x and y.

If Rob receives $4,585.75 in annual dividends, the number of shares of Agram Imports that Rob owns is D. 441 shares.

A dividend is the distribution of cash or stock that a company makes to its stockholders periodically.

Dividends are usually based on a dividend payout ratio, determined by the Board of Directors of the company.

                                       Dowc Beverage Co.     Agram Imports

Dividend per share                 $6.52                               $5.15

Number of shares                    x                                     x+ 86

Number of shares                 355 (441 - 86)                  441 (355 + 86)

Total dividend received      $2,314.60 ($4,585.75 - $2,271.15))  $2,271.15

which is equivalent to $2,314.60 ($355 x $6.52)

Assuming total shares from Agram Imports to be 441, the total dividends will be $2,271.15 ($5.15 x 441), and, the dividend from Dowc Beverage Co. will be $2,314.60 and the number of shares will be 355 ($2,314.60/$6.52), which is 86 less than the shares in Agram Imports.

Thus, if Rob receives $4,585.75 in annual dividends, the number of shares of Agram Imports that Rob owns is D. 441 shares.

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