A linear function is shown below. Choose the two points that are on the graph of the inverse of this function.

A- (-1, 4)
B (2 , -6)
C ( 2, -2)
D ( 1, 0)
E ( 0 , -1 )
F ( -4 , 3)

Answer:

b

Step-by-step explanation:

hj

Answer:Its B,dude

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

x(x + 8) = 48

x² + 8x = 48

x² + 8x - 48 = 0

times into -48

add into 8

(x - 4)(x + 12) = 0

x - 4 = 0

x = 4

or

x + 12 = 0

x = -12

A length cannot be a negative number therefore x = 4

Answer:

C.  -18

Step-by-step explanation:

Scalar Product (Dot Product) of two vectors

[tex]\displaystyle \vec{a} \cdot \vec{b}=\sum_{i=1}^na_ib_i[/tex]

[tex]\textsf{If }\: \vec{a}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \quad \textsf{and } \quad \vec{b}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k}[/tex]

[tex]\textsf{then }\quad \vec{a} \cdot \vec{b}=a_1b_1+a_2b_2+a_3b_3[/tex]

Given:

⇒ v₁ · v₂ = (3 · 2) + (-4 · 6)

⇒ v₁ · v₂ = 6 + (-24)

⇒ v₁ · v₂ = 6 - 24

⇒ v₁ · v₂ = -18

Answer:

110

50+50=100

5+5=10

100+10=110

(thats how i do mental math)

Answer:

-3/4

Step-by-step explanation:

ΔY / ΔX, or change in y divided by change in x
(-4,3) and (0, 0)
x increases by 4
y decreases by 3
-3/4

Answer:

It is -3/4

Step-by-step explanation:

HOPE IT HELP (≧▽≦)(≧▽≦)(≧▽≦)

Answer:

Step-by-step explanation:

the answer is wrong its  34.3

324

Step-by-step explanation:

roughly about that much

Answer:

Step-by-step explanation:

The problem statement gives expressions and relations for revenue, cost, and profit. Substitute and simplify or solve, as appropriate.

__

Given: r(x) = 20x; c(x) = 3600+4x; p(x) = r(x) -c(x)

The formula for p(x) is ...

  p(x) = (20x) -(3600 +4x) . . . . substitute for r(x) and c(x)

  p(x) = 16x -3600 . . . . . . . . simplify

__

  r(x) = 2·c(x) . . . . given relation for revenue and cost

  20x = 2(3600 +4x) . . . . substitute for each

  12x = 7200 . . . . . . . simplify and subtract 8x

  x = 600 . . . . . . . divide by 12

Revenue is twice the cost when x = 600 units.

__

  p(x) = 292 +1/3r(x) . . . . given relation for profit and revenue

  16x -3600 = 292 +1/3(20x) . . . . . substitute for each

  28/3x = 3892 . . . . . . . . add 3600 -20/3x

  x = 417 . . . . . . . . multiply by 3/28

Profit is $292 more than 1/3 the revenue earned for 417 units.

Answer:

the difference in their ages is 31/2

Step-by-step explanation:

151/2=2x15+1/2=31/2

Answer:

Step-by-step explanation:

A: Not a Rhombus. Adjacent sides are unequal

B: True. Opposite sides are parallel

C: True. Adjacent sides are unequal in length but it has two sets of parallel lines and at least 1 right angle.

D: Not a square. Not all 4 sides are of equal length

E: It is a quadrilateral. A quadrilateral only requires 4 sides.

F: Not true. It does not have the properties of a trapezoid.

Answer:

x=1/2 or x=-1/3

Step-by-step explanation:

6x^2-x-1=0

6x^2+2x-3x-1=0

(6x^2+2x)+(-3x-1)=0

2x(3x+1)-1(3x+1)=0

2x(3x+1)-1(3x+1)=0

(2x-1)(3x+1)=0

(2x-1)(3x+1)=0

2x-1=0

or

3x+1=0

x=-1/3

x=1/2

Answer:

Its 1/3 and -1/2

Step-by-step explanation:

I hope this will help you a lot

The probability of winning the game on your next turn is; 14%

The sample size of the two number cubes, when rolled is:

n = 36

The number of outcomes that give a sum of 2 or 5 is 5,

And the outcomes are (1, 1) (2, 3) (3, 2) (1, 4) (4, 1)

The probability is the quotient of the number of outcomes of the sum of 2 or 5 and the total outcomes.

Thus,

Probability = 5/36 * 100% = 13.89% ≈ 14%

Read more about Probability of winning at; https://brainly.com/question/24756209

#SPJ1

opposite sides and diagonals of a parallelogram are equal

+ diagonals of a parallelogram meet eachother in the middle so:

10x+14=x+77

10x-x=77-14

9x=63

x=63÷9

x= 7

y+8=4y-19

y-4y=-19-8

-3y=-27

y=-27÷-3

y=9

2z+3=37

2z=37-3

2z=34

z=34÷2

z=17

Answer:  C) add 12 to both sides

Reason:

We add 12 to the left side to undo the -12, which will get y by itself.

We must do the same thing to both sides to keep things balanced.

Check the picture below.

the ratio of the sides will be the same ratio of their perimeters

[tex]\stackrel{\textit{\LARGE ratio of their}}{\stackrel{perimeters}{\cfrac{6}{15}\implies \cfrac{2}{5}}\hspace{5em}\stackrel{areas}{\cfrac{2^2}{5^2}\implies \cfrac{4}{25}}}[/tex]

Answer:

115 and 1/2

Step-by-step explanation:

B•W•H

Hope this helps! ;-)

Thanks for correcting my mistake!!!

Answer:  The answer is 115 1/2

Explanation: Just multiply all the dimensions

Answer:

21, 29, 30, 35

Step-by-step explanation:

anything greater than 20 would break even and then give a position balance

Answer:

2 15/28

Step-by-step explanation:

First we will convert both mixed fractions into improper fractions.

5 1/4 becomes 21/4

2 5/7 becomes 19/7

21/4 - 19/7 does not work, so we must make the denominator the same

147/28 - 76/28 = 71/28

Now we convert back to a mixed number:

2 15/28

Answer: [tex]-11\frac{15}{28}[/tex]

Step-by-step explanation:

Convert to Improper fractions

[tex]5\frac{1}{4} = \frac{21}{4} \\2\frac{5}{7} = \frac{19}{7} \\[/tex]

Find a lowest common multiple

lcm(4,7) = 28 (7 * 4)

since they are just multiplying each other, we can cross multiply

[tex]\frac{(21*7) - (19*4)}{4*7} = \frac{147-76}{28} \\= \frac{71}{28} \\=2\frac{15}{28}[/tex]

Answer:

8x^2 2y^3

Step-by-step explanation:

Answer:

[tex]D)~(x+3)^2 = 16[/tex]

Step-by-step explanation:

[tex]~~~~~~x^2 +6x -7 = 0\\\\\implies x^2+6x = 7\\\\\implies x^2 +2 \cdot 3 \cdot x +3^2 -3^2 = 7\\\\\implies x^2 +2 \cdot 3 \cdot x+3^2 = 7+3^2\\\\\implies (x+3)^2 = 7+9\\\\\implies (x+3)^2 = 16[/tex]

Multiply the moduli and add the arguments:

√2/6 cis(3π/5) × √6/4 cis(2π/3)

= (√2/6 × √6/4) cis(3π/5 + 2π/3)

= √3/12 cis(19π/15) … [A]

Step-by-step explanation:

because its formula is 4L

Answer:

A. Red/Line C

Step-by-step explanation:

The equations are

Lets solve them through matrix

Let

[tex]\\ \rm\Rrightarrow A=\left[\begin{array}{ccc}\rm 5&\rm 3&\rm 4\\ \rm 2&\rm 5&\rm 5\\ \rm 6&\rm 3&\rm3\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow B=\left[\begin{array}{c}\rm 67 \\ \rm 56\\ \rm 72\end{array}\right][/tex]

Let solve

Determinant of A

[tex]\\ \rm\Rrightarrow |A|[/tex]

[tex]\\ \rm\Rrightarrow 5\left|\begin{array}{cc}\rm 5&\rm 5\\ \rm 3&\rm 3\end{array}\right|-3\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|+4\left|\begin{array}{cc}\rm 2&\rm 5\\ \rm 6&\rm 3\end{array}\right|[/tex]

[tex]\\ \rm\Rrightarrow 5(15-15)-3(6-30)+4(6-30)[/tex]

[tex]\\ \rm\Rrightarrow 72-96[/tex]

[tex]\\ \rm\Rrightarrow -24[/tex]

[tex]\\ \rm\Rrightarrow A_{11}=0[/tex]

[tex]\\ \rm\Rrightarrow A_{12}=24[/tex]

[tex]\\ \rm\Rrightarrow A_{13}=-24[/tex]

[tex]\\ \rm\Rrightarrow A_{21}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{22}=-9[/tex]

[tex]\\ \rm\Rrightarrow A_{23}=3[/tex]

[tex]\\ \rm\Rrightarrow A_{31}=-5[/tex]

[tex]\\ \rm\Rrightarrow A_{32}=-17[/tex]

[tex]\\ \rm\Rrightarrow A_{33}=19[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 24&\rm -24\\ \rm 3&\rm -9&\rm 3\\ \rm -5&\rm -17&\rm 19\end{array}\right]^T[/tex]

[tex]\\ \rm\Rrightarrow \left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{|A|}\times Adj.A[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right][/tex]

Now

[tex]\\ \rm\Rrightarrow AX=B[/tex]

[tex]\\ \rm\Rrightarrow X=A^{-1}B[/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{ccc}\rm 0&\rm 3&\rm -5\\ \rm 24&\rm -9&\rm -17\\ \rm -24&\rm 3&\rm 19\end{array}\right]\left[\begin{array}{c}\rm 67\\ \rm 56\\ \rm 72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\dfrac{1}{-24}\left[\begin{array}{c}\rm -192\\ \rm -120\\ \rm -72\end{array}\right][/tex]

[tex]\\ \rm\Rrightarrow X=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

So

[tex]\\ \rm\Rrightarrow \left[\begin{array}{c}\rm x\\ \rm y\\ \rm z\end{array}\right]=\left[\begin{array}{c}\rm 8\\ \rm 5\\ \rm 3\end{array}\right][/tex]

We get

Answer:

One, since the lines are not parallel (you can tell by either the graph, or the coefficient of the x term, called "slope", and it's (3;4)

Answer:

84cm

Step-by-step explanation:

Given that;

1cm = 7m

12cm = x

Cross Multiply

x = 12×7

x = 84m