a plane passes over Point A with a velocity of 8,000 m/s north. Forty seconds later it passes over Point B with a velocity of 10,000 m/s north. Which is the plane's acceleration from A to B ?

Answer:

a = 5 m/s^2

Explanation:

First, we look at Newton's 2nd Law:

F = ma

We now plug in the values,

10 N = 2 kg * a

10 N/2 kg = a

5 m/s^2 = a

The  charge on the inner surface of the shell is -Q

The  charge on the outer surface of the shell is Q

After this contact, the charge on the tack is  0

The charge on the inner surface of the shell now is  0

The charge on the outer surface of the shell now is Q

The charge on a shell depends on the situation and the conditions of the shell. If the shell is an electrically neutral object, such as a metallic spherical shell, it has no net charge, meaning that the total positive charge is equal to the total negative charge. However, if the shell has an excess or deficit of electrons, it will have a net charge, either positive or negative, depending on whether it has an excess of electrons or a deficit of electrons.

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Answer:

F = 2.40 × [tex]10^{-6}[/tex]  N

Explanation:

given data

charge q1 = 3.95 nC

x= 0.198 m

charge q2 = 4.96 nC

x= -0.297 m

solution

force on a point charge kept in electric field F = E × q       ................1

here E is the magnitude of electric field and q is the magnitude of charge

and

first we will get here electric field at origin

So net field at origin is

E = (Kq2÷r2²) - (kq1÷r1²)           ...............2

put here value

E = 9[(4.96÷0.297²)-(3.95÷0.198²)]

E = 400.72 N/C        ( negative x direction )

so that force will be

F = 6 × [tex]10^{-9}[/tex] × 400.72

F = 2.40 × [tex]10^{-6}[/tex]  N

The net force on the third charge is 2.404 x 10⁻⁶ N.

The given parameters:

The force on the third charge due to first charge is calculated as follows;

[tex]F_{13} = \frac{kq_1 q_3}{r^2} \\\\F_{13} = \frac{9\times 10^9 \times 3.95 \times 10^{-9} \times 6 \times 10^{-9} }{(0.198)^2} (+i)= 5.44 \times 10^{-6} \ N \ (+i)[/tex]

The force on the third charge due to second charge is calculated as follows;

[tex]F_{23} = \frac{kq_2q_3}{r^2} \\\\F_{23} = \frac{9\times 10^9 \times 4.96 \times 10^{-9}\times 6 \times 10^{-9} }{(0.297)^2} (-i)\\\\F_{23} = (3.036 \times 10^{-6} ) \ N \ (-i)[/tex]

The net force on the third charge is calculated as follows;

[tex]F_{net} = 5.44 \times 10^{-6} - 3.036 \times 10^{-6} \\\\F_{net} = 2.404 \times 10^{-6} \ N[/tex]

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Answer:

i honestly think its 21

Explanation:

da memes

10 + 10 =21

Answer:

t = 2x / v    ( time echo),       t = 2.9 10⁻² s

Explanation:

In this case we can use the uniform motion relationships, since the sound wave has a constant speed. Let's start by calculating the time it takes for the click to reach the detector.

          v = d / t

           t = d / v

where d is the distance from the speaker to the detector and v the speed of sound (v = 340 m / s)

Now let's analyze the echo, it is produced by a reflection of the sound from a large obstacle in the direction of the sound, therefore if the distance to the obstacle is x, the echo travels a distance of 2x in this time (to)

            2x = v to

            2x = v (d / v)

            d = 2x

if we substitute in the first equation

            t = 2x / v    ( time echo)

Let's analyze these results, if the distance relationship is fulfilled, the detector (microphone) is not able to distinguish between a click and the echo of the previous click

For a numerical result suppose that the distance from the loudspeaker to the detector is d = 10 m, we obtain that the obstacle must be at a distance from the loudspeaker of

                x = 5 m

                t = 2  5/ 340

                t = 2.9 10⁻² s

            This is the time the echo has to return in this speaker-microphone configuration

Answer:

3.65 x mass

Explanation:

Given parameters:

Time  = 20s

Initial velocity  = 0m/s

Final velocity  = 73m/s

Unknown:

Force the ball experience  = ?

Solution:

To solve this problem, we apply the equation from newton's second law of motion:

    F  =  m [tex]\frac{v - u}{t}[/tex]  

m is the mass

v is the final velocity

u is the initial velocity

 t is the time taken

So;

  F  = m ([tex]\frac{73 - 0}{20}[/tex] )  = 3.65 x mass

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

[tex]v = f\lambda[/tex]

where,

v= speed of wave = ?

f = frequency of wave = [tex]\frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz[/tex]

Therefore,

[tex]v = (0.217\ Hz)(5.5\ m)\\[/tex]

v = 1.2 m/s

Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

[tex] W = F*d [/tex]

Where:

F: is the applied horizontal force = 108.915 N

d: is the distance = 2.38 m  

Hence, the work is:

[tex] W = F*d = 108.915 N*2.38 m = 259.22 J [/tex]

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!                                                

Answer:

The response to this question is as follows:

Explanation:

The whole question and answer can be identified in the file attached, please find it.

The force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.

The given parameters;

The force diagram of all the forces acting on the snowball is calculated as follows;

                                     ↑ N

                                     ⊕  → F

                                      ↓ W

Where;

Thus, the force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.

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Answer:

a) wooden floor  

      a = 3170.6 m / s²,    t = 1.03 10⁻³ s

the child's traumatic injury to the brain

b) the floor is carpeted

      a = 385 m / s²

no injuries are created in the child

Explanation:

To solve this exercise we can use the energy conservation relations, let's start by looking for the speed of the child when he is just reaching the ground

starting point. When you get out of bed

         Em₀ = U = m g h

final point. Just when it hits the floor

          [tex]Em_{f}[/tex] = K = ½ m v²

as there is no friction, energy is conserved

           Em₀ = Em_{f}

           mgh = ½ m v²

           v² = 2 gh

let's calculate

          v² = 2 9.8 0.55

          v² = 10.78

           v = 3.28 m / s

Now let's use the concepts of kinematics to find the deceleration. The case of the wooden floor, where the distance for the deceleration is

x = 1.7 mm = 0.0017 m

      v² = v₀² - 2 a y

as the child stops the final velocity is zero

      0 = v₀² - 2a y

      a = v₀² / 2y

let's calculate

      a = [tex]\frac{10.78}{2 \ 0.0017}[/tex]

      a = 3170.6 m / s²

Let's find the time that braking lasts

        v = v₀ - a t

         0 = v₀ - at

          t = v₀ / a

         t = 3.28 / 3170.6

         t = 1.03 10⁻³ s

hence the child's traumatic injury to the brain

second case the floor is carpeted, in this case the stopping distance is

x = 1.4 cm = 0.014 m

we look for acceleration

         a = v₀² / 2y

         a = [tex]\frac{10.78}{2 \ 0.014}[/tex]

         a = 385 m / s²

therefore no injuries are created in the child

In conclusion we see that with the wooden floor there is silence and with the carpeted floor there is no

Answer:

A system that includes the stone and the earth.

Explanation:

If the system of being dropped from the height of the cliff consists of just the stone alone, then it means that its momentum will certainly undergo changes as it falls freely. However, If the system is now expanded to include not only the stone but also the Earth, then it implies that the momentum of the stone which is in the downward direction will be equal and opposite to the momentum of the Earth in the upwards direction towards the stone. Therefore, the momentum will cancel out and net momentum will be zero.

A system of stone and earth can result to a net zero momentum.

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to the sum of final momentum.

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]

A system that consists a linear system of stone and earth can result to a net zero momentum.

Thus, a system of stone and earth can result to a net zero momentum.

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Answer:

D

Explanation:

right edge 2022

Answer:

1 kg

Explanation:

Assuming that,

Δx(2) = v(2)t, where Δx(2) = d and v(2) = 2m1 / (m1 + m2) v1i

On the other hand again, if we assume that

Δx(1) = v(1)t, where Δx(1) = -2d, and v(1)t = m1 - m2 / m1 + m2 v1i

From the above, we proceed to dividing Δx(2) by Δx(1), so that we have

d/-2d = [2m1 / (m1 + m2) v1i] / [m1 - m2 / m1 + m2 v1i], this is further simplified to

1/-2 = [2m1 / (m1 + m2)] / [m1 - m2 / m1 + m2]

1/-2 = 2m1 / (m1 + m2) * m1 + m2 / m1 - m2

1/-2 = 2m1 / m1 - m2, if we cross multiply, we have

m1 - m2 = -2 * 2m1

m1 - m2 = -4m1

m2 = 5m1

From the question, we're told that m1 = 0.2 kg, if we substitute for that, we have

m2 = 5 * 0.2

m2 = 1 kg

Answer:

A

Explanation:

All the objects are motionless, so kinetic energy of each object is zero after the collision.

The kinetic energy of an object is defined as the energy which is  possesses due to its motion. It is the work required to accelerate a body of a given mass from rest to its stated velocity. This energy is gained during its acceleration, the body maintains the kinetic energy as long as its momentum does not change.

Kinetic Energy can be expressed as

[tex]K.E.=[/tex] [tex]1/2 mv^2[/tex]

Where, m is the mass of the object

v is the velocity.

It is expressed in joules (J).

After the collision all the objects are at rest, therefore, the final kinetic energy is also zero which shows maximum loss of kinetic energy. Such collisions are called perfectly inelastic.

Thus, all the objects are motionless, so kinetic energy of each object is zero after the collision.

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Answer:

To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Explanation:

The general formula of kinetic energy is given as follows:

[tex]K.E = \frac{1}{2}mv^{2}[/tex]

where,

K.E = Kinetic Energy

m = mass of the object

v = speed of the object

So, for the marble and rock to have same kinetic energy, we can write:

[tex]K.E_{marble} = K.E_{rock}\\\\\frac{1}{2}m_{marble}v_{marble}^{2} = \frac{1}{2}m_{rock}v_{rock}^{2}\\\\(0.03\ kg)v_{marble}^{2} = (2.43\ kg)v_{rock}^{2}\\\\taking\ square\ root\ on\ both\ sides:\\v_{marble} = \sqrt{\frac{2.43\ kg}{0.03\ kg}}v_{rock}\\\\v_{marble} = 9\ v_{rock}[/tex]

Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Answer:

Thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Explanation:

From the concept of Escape Velocity, derived from Newton's Law of Gravitation, definition of Work, Work-Energy Theorem and Principle of Energy Conservation, which is the minimum speed such that rocket can overcome gravitational forces exerted by the Earth, and according to the Tsiolkovski's Rocket Equation, which states that thrust done by the rocket is equal to the change in linear momentum of the rocket itself, we conclude that thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Answer:

Barriers to and risks associated with an increasing use of nuclear energy include operational risks and the associated safety concerns, uranium mining risks, financial and regulatory risks, unresolved waste management issues, nuclear weapons proliferation concerns, and adverse public opinion.

Explanation:

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

[tex]C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\[/tex]

where;

V is the potential difference between the plates

The charge on the plates is given as;

[tex]Q = \frac{V\epsilon _0 A}{d}[/tex]

The energy stored in the capacitor is given as;

[tex]E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2[/tex]

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Answer:

33624.32 N

Explanation:

From second law of motion, thrust of engine can be computed as

F= Δp/ Δt

= m1 * Δv + m2 v(o)

F= m1 *[v(o) - v] + m2 *v(o).............eqn(1)

Where

v(o) = initial velocity of the gas when ejected= 487 m/s

v= final velocity=233 m/s

m1= initial rate The engine takes in air at =122 kg/s

m2= rate of burning fuel= 3.36 kg/s.

If we input the given values into eqn (1) we have

F= 122×[ 487-233] + [3.36×487]

F=30988+1636.33

=33624.32 N

Hence, the thrust of the jet engine is 33624.32 N

The time of the day she spent walking is equal to 3.70 hrs.

Power can be explained as the rate of doing work in unit time. The SI unit of measurement of power is J/s or Watt (W). Power can be described as a time based quantity. The mathematical expression for power can be represented as mentioned below.

Power = work/time

P = W/t

Given, the energy spends part of her day walking, Ew = 280 W

The energy is spent by sitting in the class, Es = 100 W

The total energy spends, Et = 1.1 × 10⁷J

[tex]E_w \times t + E_s(24\times 60\times 60-t)= 1.1 \times 10^7J[/tex]

[tex]280 \times t + 100(24\times 60\times 60-t)= 1.1 \times 10^7[/tex]

280 t + 0.86 × 10⁷ - 100 t = 1.1 × 10⁷

180 t = 0.24 × 10⁷

t =  0.24 × 10⁷/180 × 3600

t = 3.70 hr

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Answer:

The second ball must be thrown at 30.01 m/s.

Explanation:

First, we need to find the maximum height (H) reached by the ball 1:

[tex] v_{f_{1}}^{2} = v_{0_{1}}^{2} - 2gH [/tex]  

Where:

[tex]v_{f_{1}}[/tex]: is the final speed of ball 1 = 0 (at the maximum height)

[tex]v_{0_{1}}[/tex]: is the initial speed of ball 1        

g: is the gravity = 9.81 m/s²    

We need to find the initial speed, by using the following equation:

[tex] v_{f_{1}} = v_{0_{1}} - gt [/tex]

Where t is the time = 1.71 s (when it reaches the maximum height)

[tex] v_{0_{1}} = gt = 9.81 m/s^{2}*1.71 s = 16.78 m/s [/tex]

So, the maximum height is:                  

[tex] H = \frac{v_{0_{1}}^{2}}{2g} = \frac{(16.78 m/s)^{2}}{2*9.81 m/s^{2}} = 14.35 m [/tex]  

Finally, the speed at which ball 2 must be thrown is:

[tex]v_{f_{2y}}^{2} = (v_{0_{2y}}sin(\theta)})^{2} - 2gH[/tex]      

[tex]v_{0_{2y}}= \frac{\sqrt{2gH}}{sin(\theta)} = \frac{\sqrt{2*9.81 m/s^{2}*14.35 m}}{sin(34)} = 30.01 m/s[/tex]                    

Therefore, the second ball must be thrown at 30.01 m/s.

I hope it helps you!                                                                                    

Answer:

The correct answer is - Characteristics.

Explanation:

On Earth, there are many organisms that shared similar characteristics with other organisms in various ways. These similarities of the characteristics could result from similar habitat, common ancestor, similar function, genetics, and many other reasons.

The example of such shared characteristics are different kinds of birds that have wings and lay eggs, while mammals give birth to babies and many other traits and characteristics. On the basis of the traits and characteristics organisms shared they are grouped and classified.

Answer:

15.68 m/s

Explanation:

Given that,

She catches the ball 3.2 s later at the same height from which it was thrown.

When it reaches the maximum height, its height is equal to 0.

It will move under the action of gravity.

[tex]t=\dfrac{2u}{g}[/tex]

2 here comes for the time of ascent and descent.

So,

[tex]u=\dfrac{tg}{2}\\\\u=\dfrac{3.2\times 9.8}{2}\\\\u=15.68\ m/s[/tex]

So, the initial upward speed of the ball is 15.68 m/s.

Answer:

An example would be

Explanation:

You have a ball with a mass of 10 kg swinging from a rope arond in a cirlce if we were to change the mass of the ball to 20 kg the kinetic energy would increase because we know the ball has more mass and more mass means ner force increases which is connected to kinetic energy. hope this answer helps!