A bag contains 2 red,5 blue,6 yellow, and 3 green crayons. What is the probability of selecting a red crayon, then without replacing it selecting an odd number that is (red, then green)
A.0
B.0.25
C.01
D.0.025

Answer: D.0.025

Step-by-step explanation:

Given: A bag contains 2 red,5 blue,6 yellow, and 3 green crayons.

Total crayons: 2+5+6+3=16

Probability of getting red crayon= [tex]\dfrac{\text{Number of red crayons}}{\text{Total}}[/tex]

[tex]=\dfrac{2}{16}=\dfrac18[/tex]

Without replacement, the probability of getting green crayon = [tex]\dfrac{\text{Number of green crayons}}{\text{Total}-1}[/tex]

[tex]=\dfrac{3}{15}=\dfrac15[/tex]

Required probability P(red then green)= [tex]\dfrac18\times\dfrac15=\dfrac1{40}=0.025[/tex]

Hence, correct option is D.0.025

A histogram titled Number of texts has time on the x-axis and texts on the y-axis. From 6 a m to 8 a m there were 15 texts, 8 to10 a m: 5, 10 a m to 12 p m: 0, 12 p m to 2 p m: 0, 2 p m to 4 p m: 0, 4 to 6 p m: 29, 6 to 8 p m: 19, 8 to 9 p m, 14, 10 p m to 12 a m: 5.
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The peak from 4 p.m.–6 p.m. means that the highest number of texts was sent during this interval.

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