a car travels 500 miles at an average speed of 60 MPH on the return trip the same route that it travels 50 miles per hour how long would it take?

Answers

Answer 1

Step-by-step explanation:

it is not clear - is 500 miles the whole round trip, or is it only the trip in one direction ?

and do we need the time for the whole round trip, or only for the return trip ?

in any case, always remember,

speed = distance/time

therefore, to get time, we need to divide distance by speed :

distance / distance/time = time×distance/distance = time

so, let's calculate all these different scenarios :

1. 500 miles is only one direction, and we measure only the time going back with 60 mph :

500 / 60 = 50/6 = 25/3 = 8 1/3 = 8 hours 20 minutes.

as 1/3 of 1 hour = 1/3 of 60 minutes = 60/3 = 20 minutes.

2. 500 miles is only one direction (going 1000 miles altogether), and we measure the time going to with 50 mph and going back with 60 mph :

500 / 50 = 10 hours

500 / 60 = 8 hours 20 minutes

the whole round trip takes 18 hours 20 minutes.

3. 500 miles is the whole round trip. so, 250 miles is one direction. and we measure only the time going back with 60 mph :

250 / 60 = 25/6 = 4 1/6 = 4 hours 10 minutes.

as 1/6 of 1 hour = 1/6 of 60 minutes = 60/6 = 10 minutes.

4. 500 miles is the whole round trip. so, 250 miles is one direction. and we measure the time going to with 50 mph and back with 60 mph :

250 / 50 = 5 hours

250 / 60 = 4 hours 10 minutes

the whole round trip takes 9 hours 10 minutes.

did you notice ?

when going only half the distance, also the time it takes to travel that distance is only half (or vice versa - double). because the ratio distance/time is always the same.


Related Questions

find the volume, show solution pls

Answers

The volume of the square prism shown is 1568 cubic meters

Volume of square prism

The formula for calculating the volume of square prism is expressed as;

V = Base area * height/3

Determine the base are

B = 14 * 14

B = 196 square meters

Determine the height

h = √25² - 7²

h = √625 - 49
h = 24m

Substitute

Volume = 196. * 24/3

Volume = 196 * 8

Volume = 1568 cubic meters

Hence the volume of the square prism shown is 1568 cubic meters

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Mr. Chan’s lawn grows 2 1/8 inches every 2 week. He mows his lawn every 2 weeks and cuts off the top 1 3/4 inches of lawn. If Mr. Chan’s lawn was 4 inches tall at the beginning of the season, how many inches tall, in decimal form, is Mr. Chan’s lawn after 8 weeks.

Answers

Answer:

5.5 in

Step-by-step explanation:

First we will calculate the total lawn grown after 8 weeks.

Grow Rate = [tex]2\frac{1}{8} in/2 weeks[/tex]

Total lawn grown after 8 weeks = [tex]2\frac{1}{8} *4\\=8.5 in[/tex]

Next we will calculate the total lawn mown after 8 weeks.

Mowing Rate = [tex]1\frac{3}{4} in/2weeks[/tex]

Total lawn mown after 8 weeks = [tex]1\frac{3}{4} *4\\=7 in[/tex]

Lawn Height after 8 weeks = Initial Lawn Height + Total lawn grown - Total lawn mown

= 4 in + 8.5 in - 7 in

= 5.5 in

Solve for x 3x – 2(3x – 2) = 2(4 – x) + 3

Answers

Answer:

x = -7

Step-by-step explanation:

First, lets open up the parentheses.

3x - 6x + 4 = 8 - 2x + 3

Combine like terms.

-3x + 4 = 11 - 2x

Add 2x to both sides

-x + 4 = 11

Subtract 4 from both sides

-x + 4 -4 = 11 -4

Simplify

-x = 7

Divide both sides by -1

x = -7

Hope this helps! (:

Answer:

x = -7

Step-by-step explanation:

3x – 2(3x – 2) = 2(4 – x) + 3

The first step is to distribute when solving for x

3x – 6x +4 = 8 – 2x + 3

Then combine like terms

-3x+4=-2x+11

Add 3x to each side

-3x+3x+4=-2x+3x+11

4 = x+11

Subtract 11 from each side

4-11 = x+11-11

-7 = x

In the figure, two poles are 25 m and 30 m high. A cable 16 m long joins the tops of the poles. Find the distance between the poles. HELP PLEASE.

Answers

Answer:

The distance between the poles is approximately 15.2 m.

Step-by-step explanation:

Given

Two poles of 25 m and 30 m height,Distance between tops of the poles is 16 m.

To find

The distance between the poles

Solution

The distance between the poles is the segment d which connects the top of the shorter pole with the point at 5 m from the top of the longer pole, which is the difference of lengths of poles.

The three points form a right triangle, with hypotenuse of 16 m, and legs 5 m and d.

Use Pythagorean to find the value of d:

[tex]d=\sqrt{16^2-5^2} =\sqrt{256-25} =\sqrt{231} =15.2[/tex] m (rounded)

what should be added to 4x²-3x²+1 to make it a perfect square​

Answers

[tex]im \: guessing \: its \: 4x {}^{2} - 3x + 1 \\ (correct \: me \: if \: im \: wrong)[/tex]

[tex](a - b) {}^{2} = a {}^{2} - 2ab + {b}^{2} [/tex]

[tex]4x {}^{2} = a {}^{2} \: \: \: \: \: \: \: \: \: \: \: b {}^{2} = 1 \\ a = 2x \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = 1[/tex]

[tex](2x - 1) {}^{2} = 4x {}^{2} -4x + 1[/tex]

[tex]we \: need \: to \: add \: a \: - x \\ \: to \: the \: original \: equation[/tex]

Note that this problem can be approached in many ways. For instance, we can add to the b² term instead of changing the middle term...
You could solve this by using completing the square and simplifying


The slope of the line graphed below is undefined. True or false

Answers

Answer:

False

Step-by-step explanation:

The slope is 0.

Really confused don’t understand please help me

Answers

Answer:

62cm²

Step-by-step explanation:

Surface Area Formula

SA = 2lw + 2lh + 2hw

2 * 2 * 5 + 2 * 2 * 3 + 2 * 3 * 5 =

62cm²

(-a, 0)
(0, b)
(0,0)
(0,-b)
What is the perimeter of the polygon in the diagram?
(a,0)

Answers

The answer to this diagram is (0,-b)

Can a function ever have 2 y-
intercepts?

Answers

Answer:

yes I think I'm new to this but I think that's a yes

Hay 20% mas duendes que magos en el club de magia. Hay 120 duendes en el club de magia.
¿Cuántos magos hay en el club de magia?

Answers

Answer:

Hay 600 en el club de magia.

Use the ray tool to graph the function. f(x)=−|x+2|+1

Answers

The graph of the function. f(x)=−|x+2|+1 is illustrated.

How to illustrate the function?

The given function is f(x)=−|x+2|+1.

We will have to draw the graph of the function.

When x = 1, f(1) will be -2. When x = 2, f(2,) will be -3

The points are illustrated based on the information given and the appropriate graph is illustrated and attached.

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1) (b + a) = 4; use a = 1 and b = 3

2) c(b + b); use b = 1 and c = 5

3) 4+ pm; use m = 4 and p =3

4) 5+ pm; use m = 4 and p = 2

5) m(p + 2); use m = 5 and p = 2

6) h+j²; use h = 1 and j = 4

7) y-(x - 5); use x = 5 and y = 6

8) 4xy; use x = 5 and y = 2

9) n(p + 3); use n = 2 and p = 2

10) y +x+x; use x = 3 and y=5

11) 6+ a-b; use a = 4 and b = 4

Answers

The equations will be solved by putting the values of the variables in the bracket.

How to calculate the values?

1. (b + a) = 4; use a = 1 and b = 3

( 1 + 3) = 4

2) c(b + b); use b = 1 and c = 5

5(1 + 1)

= 5 × 2 = 10

3) 4+ pm; use m = 4 and p =3

= 4 + (4 × 3)

= 4 + 12

= 16

4) 5+ pm; use m = 4 and p = 2

= 5 + (2 × 4)

= 5 + 8

= 13

5) m(p + 2); use m = 5 and p = 2

= 5(2 + 2)

= 5 × 4

= 20

6) h+j²; use h = 1 and j = 4

= 1 + 4²

= 17

7) y-(x - 5); use x = 5 and y = 6

= 6 - (5 - 5)

= 6 - 0

= 6

8) 4xy; use x = 5 and y = 2

= 4 × 5 × 2

= 40

9) n(p + 3); use n = 2 and p = 2

= 2(2 + 3)

= 10

10) y +x+x; use x = 3 and y=5

= 5 + 3 + 3

= 11

11) 6+ a-b; use a = 4 and b = 4

= 6 + 4 - 4

= 6

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a) 11 pounds, 8 pounds
O Like terms
11 pounds - 8 pounds =
O Not like terms

Answers

Answer:

Like terms

Step-by-step explanation:

Both terms have the same unit, which is pounds.

At the end of January 2003, the population of my town was 11,212. The population of my town increases by 322 every month. In what month does the population of my town first exceed 15,000?

Answers

In 11.76 months, the value of the population will be 15000.

We have given that,

At the end of January 2003, the population of my town was 11,212.

the population is increased by 322 every month

So at the end of the second-month population will be 11534.

suppose x represents the year and  y represent the population

The population increased by 322 every month

Therefore the value of m =322

[tex](x_1,y_1)=(0,11212)[/tex]

We have m=332

[tex](x_2,y_2)=(x_2,15000)[/tex]

We have to determine the value of the x_2

What is the slope point form of the line?

[tex](y_2-y_1)=m(x_2-x_1)[/tex]

[tex]322\left(x_2-0\right)=15000-11212[/tex]

[tex]322\left(x_2-0\right)=3788[/tex]

[tex]\frac{322\left(x_2-0\right)}{322}=\frac{3788}{322}[/tex]

[tex]x_2=\frac{1894}{161}[/tex]

[tex]x_2=11.76[/tex]

Therefore in 11.76 months, the value of the population will be 15000.

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Solve 2w2 + 12w + 10 = 0 by completing the square

A)

w = –15, w = 5

B)

w = –5, w = –1

C)

w = –5, w = 1

D)

w = 5, w = 1

Answers

The value of w is -1 and -5.

The correct option is (B)

What is equation?

A mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.

Given:

2w² + 12w + 10 = 0

First, divide through by 2

2w²/2 + 12w /2 + 10/2 =0/2

w² + 6w + 5 = 0

now, Take half of the w term and add - subtract the square of it

w² + 6w + 5 + 3² - 3² = 0

w² + 2*3w + 3² + 5 - 9 = 0

(w+3)² = 4

w+3 = ±2

w = +2 - 3, -2-2

w= -1 and -5.

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The question is down below

also I home school and have permission to post this question

Answers

Answer:

960

Step-by-step explanation:

(if i made any typos, sorry it is kind of hard to type on computer over writing on paper.)

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=(a+b+c)/2

Solving forA

A=ah+bh+ch+1/2 sqrt(﹣a^4+2(ab)^2+2(ac)^2﹣b4+2(bc)^2﹣c^4)=10·12+24·12+26·12+1

2·﹣104+2·(10·24)2+2·(10·26)2﹣244+2·(24·26)2﹣264=960

Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n

Answers

The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

[tex]a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\[/tex]

[tex]When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\[/tex]

The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003

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0.3(8-2x) - 1.2(2-3x) < -21

Answers

Answer:

x=-7

Step-by-step explanation:

0.3(8-2x) - 1.2(2-3x) < -21

2.4 - 0.6x - 2.4 + 3.6x < -21

3x < -21

x < -7

Daniel wrote the following two-column proof for the given information.

Answers

The information given about the proof does that Daniel made an error on line 2.

How to illustrate the information?

Given:

1. AB = 3x +2;  BC = 4x + 8;  AC = 38

2. AB + BC = AC      incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38         correct

4. 7x + 10 = 38                    correct

5. 7x = 28                           correct

6. x = 4

Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

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A desk is on sale for $123.20, which is 72% less than the regular price.
What is the regular price?

Answers

Answer:

170.833

Step-by-step explanation:

we have to find real value which has to be find.

let take it as x,

in the question they said reduction percentage is equal to $123

then x*72/100=$123

x=$123*100/72

x=12300/72

x=170.8333

Answer:

I believe it's 211.90$.

Write the equation of a sine or cosine function to describe the graph.

Answers

y = A sin(Bx) and y = A cos(Bx). The number, A, in front of sine or cosine changes the height of the graph. The value A (in front of sin or cos) affects the amplitude (height). The amplitude (half the distance between the maximum and minimum values of the function) will be |A|, since distance is always positive.

Wxyz is a dilation image of wxyz. Wich is the correct description of the dilation?

Answers

It’s either bigger or smaller



In the diagram below of AACT, BE | AT.
C
F
If CB = 3, CA = 10, and CE = 6, what is the length
of ET?
1)
5
2)
14
3)
20
4)
26

Answers

Answer:

14

Step-by-step explanation:

CB/AB = CE/ET

3/7 = 6/ET

ET = 14

12:00,10:00,6:00,4:00. What is the missing time? ​

Answers

I would say 8:00 between 6:00 and 10:00 cause it seems to be progressing in increments of 2 hours

Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:

Answers

The  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation        $10,500.

Journal entries

Bailand Company

1. Dec 31  

Debit Depreciation expense         $10,500

Credit Accumulated depreciation                     $10,500

(Being the depreciation expense recorded)

Book value=$148,000-($148,000-$8,000/10×4)]

Book value=$148,000-$56,000

Book value=$92,000

Depreciation=$92,000-$8,000/8

Depreciation=$10,500

2. Dec 31  

Debit Depreciation expense $24,000.00

Credit Accumulated depreciation a/c               $24,000.00

[($92,000-$8,000)×6/21]

(Being the depreciation expense recorded)

3. Dec 31    

Debit Accumulated depreciation $3,200.00

[($8,000×4)/10]

Credit  Retained earnings              $3,200.00

(Being prior year adjustment for depreciation expense)

Dec 31  

Debit  Depreciation expense         $10,000.00

Credit Accumulated depreciation             $10,000.00

[($148,000-$8,000)/10]

(Being the depreciation expense recorded)

Therefore the  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation   $10,500.


The complete question is:

Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:

1. Bailand estimates that the asset has 8 years’ life remaining (for a total of 12 years).

2. Bailand changes to the sum-of-the-years’-digits method.

3. Bailand discovers that the estimated residual value has been ignored in the computation of depreciation expense.

Required: For each of the independent situations, prepare all the journal entries relating to the building for the fifth year. Ignore income taxes.

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will give brainliest

Answers

Answer:

f(x) = x^(1/2) + 3

Step-by-step explanation:

Translating to the right 3 units would change these:

0^(1/2) = 0 /// 3 units to the right would be (0,3)

1^(1/2) = 1 //// 3 units to the right would be (1,4)

4^(1/2) = 2 //// 3 units to the right would be (4,5) etc

Part E
Christopher Columbus set sail from Spain in 1492. In what year did the Civil War end?
I know he died 1865 but you explain the answer

Answers

The year he died was the year 1846

Calculate the area of this triangle.
[tex] [/tex]

Answers

Answer: 30

Step-by-step explanation: Formula for Area of a triangle = 1/2 Base * Height. 12*5 = 60; 60/2 = 30.

Answer:

30 cm squared

Step-by-step explanation:

This is a right angle triangle. That means that the base and height will just be the perpendicular sides of the triangle.

Our base in this case is 12 and our height is 5.

Area of a Triangle = 1/2(base)(height)

=1/2(12)(5)

=1/2(60)

=30

So, the area of this triangle is 30 cm squared.

HELP ASAP
What is the perimeter of rectangle MNOP, rounded to the nearest tenth of a meter?
M
60°
N
O
O
28 m
79.2 m
67.6 m
88.1 m
76.5 m
30°

Answers

Answer: 76.5 meters

Step-by-step explanation:

To find the side lengths you use trig ratios for 30,60,90 triangles. The ratio is n (attached to the opposite side of the 30-degree angle, or the smallest leg), n[tex]\sqrt{3}[/tex] (attached to the opposite side of the 60-degree angle, or the longest leg), 2n (attached to the hypotenuse). Using the inner triangle you can use 2n=28 to find the side opposite the 30-degree angle, 14. Then you plug 14 into every n and add the sides. the full answer is 76.4974226 but this problem said to round making your final answer 76.5 meters. always remember to give proper units.  

Solve for ×:
X/5+3y=-7

Answers

The answer I believe is
X= -1/15
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