73 m is equal to how many dm?

Answer:

The rate constant of the reaction at 125˚ is [tex]0.3115 \ \text{sec}^{-1}[/tex].

Explanation:

The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as

                                                  [tex]k \ = \ Ae^{\displaystyle\frac{-E_{a}}{RT}}[/tex]

                                               [tex]\ln k \ = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT}[/tex]

where [tex]k[/tex] is the rate constant, [tex]E_{a}[/tex] represents the activation energy of the chemical reaction, [tex]R[/tex] is the gas constant, [tex]T[/tex] is the temperature, and [tex]A[/tex] is the frequency factor.

The frequency factor, [tex]A[/tex], is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.

Consider that the rate constant be [tex]k_{1}[/tex] at an initial temperature [tex]T_{1}[/tex] and the rate constant [tex]k_{2}[/tex] at a final temperature [tex]T_{2}[/tex], thus

                         [tex]\ln k_{2} \ - \ \ln k_{1} = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT_{2}} \ - \ \left(\ln A \ - \ \displaystyle\frac{E_{a}}{RT_{1}}\right) \\ \\ \\ \rule{0.62cm}{0cm} \ln \left(\displaystyle\frac{k_{2}}{k_{1}}\right) \ = \ \displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)[/tex]

                                         [tex]\rule{1.62cm}{0cm} \displaystyle\frac{k_{2}}{k_{1}} \ = \ e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)} \\ \\ \\ \rule{1.62cm}{0cm} k_{2} \ = \ k_{1}e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)}[/tex]

Given that [tex]E_{a} \ = \ 26.5 \ \ \text{kJ/mol}[/tex], [tex]R \ = \ 8.3145 \ \ \text{J mol}^{-1} \ \text{K}^{-1}[/tex], [tex]T_{1} \ = \ \left(40 \ + \ 273\right) \ K[/tex], [tex]T_{2} \ = \ \left(125 \ + \ 273\right) \ K[/tex], and [tex]k_{1} \ = \ 0.0354 \ \ \text{sec}^{-1}[/tex], therefore,

           [tex]k_{2} \ = \ \left(0.0354 \ \ \text{sec}^{-1}\right)e^{\displaystyle\frac{26500 \ \text{J mol}^{-1}}{8.3145 \ \text{J mol}^{-1} \ \text{K}^{-1}}\left(\displaystyle\frac{1}{313 \ \text{K}} \ - \ \displaystyle\frac{1}{398 \ \text{K}} \right)} \\ \\ \\ k_{2} \ = \ 0.3115 \ \ \text{sec}^{-1}[/tex]                      

Answer:

The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.

A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.

There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.

Hope it helps!

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Answer:

The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.

A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.

There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.

Explanation:

Answer: 2.23

Explanation:

The dissociation of acetic acid is as follows:

HCOOH(aq) ⇋ HCOO− (aq) + H+(aq)

The ICE table for the concentrations of ions is given below. From the table, the concentration of HCOO- and H+ can be found out.

                                                     HCOOH → HCOO−  +   H+
Initial Concentration                     0.019 M         0             0
Equilibrium Concentration          (0.019−x) M    x              x

Where,

At equilibrium, dissociation constant can be calculated as follows.

[tex]K_{\mathrm{a}}=\frac{x^{2}}{(0.19-x) \mathrm{M}}[/tex]

At equilibrium, the concentration of x is negligible as compared to that of HCOOH.

Substitute the value of Ka in the above equation.

[tex]\begin{aligned}K_{\mathrm{a}} &=\frac{x^{2}}{0.19-x} \\x &=\sqrt{1.8 \times 10^{-4} \times 0.19} \\&=0.00584 \mathrm{M}\end{aligned}[/tex]

Here, the concentration of hydrogen ion is obtained. From the hydrogen ion concentration, the pH of the solution is found out as follows:

[tex]\begin{aligned}\mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\&=-\log (0.00584 \mathrm{M}) \\&=2.23\end{aligned}[/tex]

Therefore, the pH of 0.19M HCCOH is 2.23

Answer: The correct answer is 5.6atm.

Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]. Now that we have the formula, let's plug in our given information!

[tex]\frac{3.8atm}{372K} =\frac{P_{2} }{550K}[/tex]

We must find the value [tex]P_{2}[/tex]. To do this, we will write a stoichiometric equation to solve this.

[tex]P_{2} =\frac{3.8atm*550K}{372K}[/tex]

Let's input the numbers into a scientific calculator to get our answer!

[tex]P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm[/tex]

Given all of this work, the value [tex]P_{2}[/tex] equals 5.6 atm.

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Answer: 6 valence electrons

Explanation: the atomic number for oxygen is 8. the first shell takes 2, the second 8. so, the outer shell is the last shell, which takes 6 from oxygen because oxygen has only 8.  6 is the number for outer or valence electron for oxygen

The beginning and ending energy levels of the electron during the emission of energy that leads to spectral line n(i)= 2 and n(f)=2

wavelength(λ) = 656.3 nm = 656.3 x 10^-9

E= hc / λ

E = energy of the photon

h=Planck's constant

c=speed of light

λ= wavelength of the photon

E= (6.626 x 10^-34)(3 x 10^8)/( 656.3 x 10^-9)

E = 3.028 x 10^-37J

It's a red line which means it falls in a visible region which is known as the Balmer series so;

n (f) = 2

ΔE= RH (1/n(f)^2 - 1/n(i)^2)

3.028 x 10^-37 =-2.18 x 10^-18(1/2^2 - 1/n(i))

n(i)= 2

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Answer:

yes it's a thing, milk too

The answers include:

This involves the formation of a new products from substances. In this scenario, a rising bread contains alcohol which evaporates.

Photographs also fall under this category and is therefore an irreversible chemical change.

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From the calculations, the change in energy is - 190 J.

From the first law of thermodynamics, the energy is neither created nor destroyed but is transformed from one form to another.

From the law;

U = q + w

U = internal energy

q = heat

w = work

Since work is done on the surroundings and the gas absorbs heat then;

U = 132 J - 322 J

U = - 190 J

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From the equation of the graph, the activation energy of the reaction is -2.2 * 10⁴ J/mol.

Activation energy is the minimum required energy that reactant molecules must possess for a reaction to proceed towards formation of products.

The activation energy is determined from the slope of ln k against 1/T(K).

Given the equation, y = -2.2 * 10⁴ x + 45.0.

Comparing with the equation of a straight line, y = mx + c

The gradient, m = -2.2 * 10⁴

Therefore, the activation energy of the reaction is -2.2 * 10⁴ J/mol.

In conclusion, reactant molecules must break the activation energy barrier in order to form products.

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Answer:

Entropy is a measurement of how much the atoms in a substance are free to spread out, move around, and arrange themselves in random ways

Answer:

[tex]\huge\boxed{\sf 102.5\ cm}[/tex]

Explanation:

Given that,

Circumference = C = 41 inches

Also,

Multiply 41 to both sides

41 inches = 2.5 × 41 cm

41 inches = 102.5 cm

So, The tree has a circumference of 102.5 cm.

[tex]\rule[225]{225}{2}[/tex]

[tex]density = \frac{mass}{volume} [/tex]

[tex]d = \frac{25.7}{22.6} = 1.13717 \: g/ml[/tex]

[tex]pay \: attention \: to \: the \: unit \: used \: to \\ express \: the \: density \\ since \: the \: mass \: is \: given \: in \: grams \\ and \: volume \: in \: milliliter \: then \\ the \: density \: is \: expressed \: in \\ grams \: per \: \: milliliter[/tex]

Answer:

+3

Explanation:

The phosphate ion has a charge of -3, so for the compound to have an overall change of 0, Fe needs to have a charge of +3.

The molar ratio of (6 moles of NaBr)/(1 mole of Fe₂S₃) is correct based on the balanced chemical equation.

The balanced chemical reaction is given as;

2FeBr₃ + 3Na₂S   →  Fe₂S₃   +  6NaBr

From the balanced chemical reaction above, 6 moles of NaBr will also correspond to 1 mole of  Fe₂S₃.

Thus, the molar ratio of (6 moles of NaBr)/(1 mole of Fe₂S₃) is correct based on the balanced chemical equation.

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Answer: The new pressure is 2.8 atm.

Explanation:

Since our given information only involves pressure and volume, we will use Boyle's Law: [tex]P_{1} V_{1} =P_{2} V_{2}[/tex]. Let's input the data into the formula.

[tex]1.4atm*500mL=P_{2} *250mL[/tex]

We have to rearrange our data a bit now because the volume is supposed to be in liters. To convert from milliliters(mL) to liters(L), you must divide the number by 1000. That is what we will do with both of our given volumes.

[tex]\frac{500mL}{1000} =0.5L[/tex]     [tex]\frac{250mL}{1000} =0.25L[/tex]

Now that our volumes are in liters, we can correctly plug in our data.

[tex]1.4atm*0.5L=P_{2} *0.25L[/tex]

Since we do not know the value [tex]P_{2}[/tex], we must rearrange the formula into a stoichiometric equation to find out the answer.

[tex]P_{2}=\frac{1.4atm*0.5L}{0.25L}[/tex]    [tex]P_{2}=2.8 atm[/tex]

Our final answer is 2.8 atmospheres.

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The  portion of the electromagnetic spectrum do we need to observe is the red part of the This is further explained below.

Generally, Spectrum refers to the range of wavelengths or frequencies that electromagnetic radiation may cover.

In conclusion, We need to keep an eye on the red part of the electromagnetic spectrum since a large positive redshift causes an increase in wavelength and a corresponding fall in frequency and photon energy (such as light).

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3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].

0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]

pH is a measure of how acidic/basic water is.

A)

[tex]NX_3 + H_2O[/tex] →[tex]NHX_3^+ + OH^-[/tex]

Kb = 4.5 x[tex]10^-6[/tex]

Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).

concentration of (NH₄⁺) = concentration of (OH⁻) = x.

x² = Kb x concentration of (NH₃)

x² = 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)

= 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

=- log ( 8.367 × 10⁻⁴)

= 3.08

B)

Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.

Concentration of (NX₃) = 0.325 M.

Kb = 4.5 x 10⁻⁶.

[NX₃H⁺] = [OH⁻] = x.

[NX₃] = 0.325 M - x.

Kb = [NX₃H⁺] x [OH⁻] ÷  [NX₃].

4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).

x = 0.0007 M.

Per cent of ionization:

α = 0. 0007 M ÷ 0. 325 M x 100%

= 0.215%.

Hence,

3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].

0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]

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When 400g each of water, oil, and sand are taken and heated from room temperature to 700⁰C on identical Bunsen burners. In this case, Substances that take more time to get heated will take more time to cool Hence, Option (A) is correct.

Heat transfer is a form of energy transfer and can occur by conduction, convection, and/or radiation.

Heat transfer occurs any time there is a temperature difference between two objects and occurs in the direction of decreasing temperature, meaning from a hot object to a cold object.

Tests show that the transferred heat relies upon three factors—the adjustment of temperature, the mass of the framework, and the substance and period of the substance.

One of the significant impacts of heat transfer is temperature change: warming builds the temperature while cooling diminishes it.

We expect no stage change and no work is done on or by the framework.

In this case, Substances that take more time to get heated will take more time to cool Hence, Option (A) is correct.

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The mole of the substance, given the data from the question is 0.0014 mole

This is simply defined as the mole of solute per kilogram of water. Mathematically, it is expressed as

Molality = mole / mass (Kg) of water

Mole = molality × mass of water

Mole of substance = 0.056 × 0.0254

Mole of substance = 0.0014 mole

Thus, the mole of the substance is 0.0014 mole

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1) The theoretical yield of SnS2 will be 4.20 grams

2) The percent yield will be 7.93%

From the equation of the reaction:

[tex]SnBr_4(aq)+2Na_2S(aq)-- > 4NaBr(aq)+SnS_2(s)[/tex]

The mole ratio of the reactant is 1:2.

Mole of 48.1 mL, 0.478 M SnBr4  = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M Na2S = 0.160 x 48.8/1000 = 0.0078 moles

Thus, Na2S is in excess while SnBr4  is limiting.

Mole ratio of SnBr4  and SnS2 = 1:1

Equivalent mole of SnS2 = 0.023 moles

Mass of 0.023 noles SnS2 = 0.023 x 182.81 = 4.20 grams

2) With 0.0333 g of SnS2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

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Here is the complete question:

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

The maximum amount of CaCO3 we can expect is 0.0180 mole x 100 g/mole = 1.80 g.

Given that:

There would be a precipitate of calcium carbonate from the reaction between sodium carbonate and calcium chloride.

The reaction is:

Na2CO3 (aq) + CaCl2(aq) → CaCO3 (s) + 2 NaCl (aq)

2.00 g CaCl2 x 1 mole/ 111 g CaCl2

= 0.0180 mole CaCl2

Mix it with 2.00 g Na2CO3 x 1 mole/ 106 g

= 0.0189 mole Na2CO3

The maximum amount of CaCO3 we can expect is 0.0180-mole x 100 g/mole = 1.80 g

Therefore, the 1.80 g is the theoretical (calculated) yield of CaCO3 in this example.

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Answer:

An electron in an excited energy level of an atom will always drop to lower energy levels, emitting very specific wavelengths of light in the process.

Answer:

Neutron does not contain any charge because the charge of the quarks that made up the neutron balances each other out.

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The weaker bond is the bond between the two hydrogen atoms since it has a lower bond energy.

The term bond energy has to do with the energy that is required to break a bond. It is also the energy that must be supplied when a bond is formed.

The lower the bond energy of  bond, the weaker the bond. Hence, it follows that the weaker bond here is the bond between the two hydrogen atoms since it has a lower bond energy.

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The correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].

A first order reaction is one in which a plot of the logarithm of the concentration against time gives a straight line graph. Now we know that this is a decomposition reaction thus the slope is negative.

Thus, in this case, the correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].

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Answer:

2 g/mL

Explanation:

Density can be calculated using the ratio:

Density = mass (g) / volume (mL)

Since you have been given both the mass and volume of the liquid, you can calculate the density.

Mass = 6 grams (g)

Volume = 3 milliliters (mL)

Density = mass / volume

Density = 6 g / 3 mL

Density = 2 g/mL

It will take less 1.8 seconds for the mass of a sample of magnesium-20 to decay from 65.6 micrograms to 8.20 micrograms.

The half-life of a radioactive element is the time for half the amount of a sample of the substance to decay.

After 0.6 seconds 31.25 remains

After 1.2 seconds, 15.625 remains

After 1.8 seconds, 7.9 micrograms remains.

In conclusion, it will take less 1.8 seconds for the sample to decay to 8.20 micrograms.

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The time taken for the radioactive sample to decay is 1.8 s.

The half life is the time taken for only half of the number of the radioactive isotopes to remain. Now we have;

No = 65.6 micrograms

N = 8.20 micrograms

t1/2 = 0.600 seconds

t = ?

Hence;

N/No = (1/2)^t/t1/2

8.20/ 65.6  = (1/2)^t/0.600

0.125 =  (1/2)^t/0.600

1/8 =  (1/2)^t/0.600

(1/2)^3 =  (1/2)^t/0.600

3 = t/0.600

t = 3 * 0.600

t = 1.8 s

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Answer:

When the temperature increases, the molecules of the gas gain energy. Therefore, they move faster.

This causes the molecules to hit the walls of the container more frequently and with greater force. Hence the pressure inside the container increases.