The length of each side of the base of the pyramid is 14 cm
Volume of a pyramidFrom the question, we are to determine the length of each side of the base of the pyramid
The volume of a square-based pyramid is given by
V = 1/3(b²h)
Where V is the volume
b is the length of the base
and h is the height
From the given information,
V = 392 cm³
h = 6 cm
Putting the parameters into the equation, we get
392 = 1/3(b²× 6)
392 = b² ×2
b² = 392/2
b² = 196
b = √196
b = 14 cm
Hence, the length of each side of the base of the pyramid is 14 cm
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A tour company charges a given price per ticket based on the number, n, of people who take the tour. the maximum number of people who are allowed to take the tour is 35. the price per ticket is $20 unless more than 10 people take the tour. if more than 10 people take the tour, the price per ticket is given by the expression: 20- n-10/2 b. harper goes on a tour where the ticket price is $10.50. how many people went on this tour? solve algebraically.
Harper goes on a tour where the ticket price is $10.50 along with 29 people according to the given expression. Solving the given expression for 'n' results in the required number.
How to solve an algebraic expression?Solving an expression algebraically involves basic operations like addition, subtraction, multiplication, and division.
In the expression, add/subtract the constant terms on both sidesMultiply/divide the coefficient of the variable on both sidesSolve for the variable.Calculation:Given that,
A tour company charges a given price per ticket based on the number 'n' of people who take the tour.
The maximum number of people who are allowed to take the tour is 35. I.e., n ≤ 35.
The price per ticket is $20 for n < 10 people and the price per ticket is given by the expression 20-(n-10)/2 for n > 10 people.
Harper goes on a tour where the ticket price is $10.50.
Since the price is less than $20, so the number of people who went on this tour is known by the expression 20-(n-10)/2 for n > 10 people.
So, solving the given expression:
20-(n-10)/2 = $10.50
-(n-10)/2 = 10.50 - 20
-(n-10)/2 = -9.5
(n-10) = 9.5 × 2
n -10 = 19
∴ n = 19 + 10 = 29
Therefore, 29 people went on this tour for a ticket price of $10.50.
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Which graph represents the function f(x) = |-x - 2|-1?
-6-
Answer:
it is the third one
Step-by-step explanation:
third one
What is the slope of these two equations?
Answer:
8. 0
9. undefined
Step-by-step explanation:
8. 0
> because the y variable is the same for all x-values, this is a horizontal line. Horizontal lines have a slope of 0.
> Thinking of slope as rise over run: we will always rise 0, and run __ from any two points--0 divided by any number is always 0
9. undefined
> because the x variable is always the same, no matter what y variable we graph, we will have the same outcome. So, this would look like a straight line, which have an undefined slope.
> If you think of a slope as rise / run; if you go from any two points, there will be a 0 in the denominator--which is undefined
hope this helps!! have a lovely day :)
A.
B.
10. Multiple choice. Determine the area of one face of a cube with a
side length of 14 cm.
A. 196 cm² B. 196 cm³ C. 14 cm²
D. 2744 cm³
Answer:
196cm²
Step-by-step explanation:
14*14=196
area = length of one side * the length of the other side
A sphere has a surface area of 16pi cm³. Find the volume giving your answer in form. Anyone know how to do this question?
Answer:
Your answer should be around 10.7π cm³
Step-by-step explanation:
The surface area formula for a sphere is SA = 4πr^2. The volume formula for a sphere is V=4/3πr^3. Use the given SA to find the value of V.16π=4πr^2 Divide by 4π on both sides. 4 = r^2. r=2 Plug in 2 for r in the equation V=4/3πr^3. Your answer should be around 10.7π cm³
find the distance between (0,3) and (0,-6)
Answer:
the answer should be 9
Step-by-step explanation:
,look at a graph count from 0,-6 up to 0,3 . the distance between them is 9
Answer: 9
Step-by-step explanation:
let the two points P (0,3) and Q(0,-6)
We need to find distance PQ
PQ=[tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
here
x1=x coordinate of P=0
y1=y coordinate of P=3
x2=x coordinate of Q=0
y2=y coordinate of Q=-6
Putting values
[tex]PQ=\sqrt{(0-0)^2+(-6-3)^2}\\[/tex][tex]PQ=\sqrt{(0)^2+(-9)^2} \\PQ=\sqrt{81} \\PQ=9[/tex]
I also dont know how to solve this one either. Please help! I just want to know how to solve it so i can do it on my own
Answer:
[tex]z=5[/tex]
Step-by-step explanation:
[tex]-\frac{3}{z}+\frac{7}{4z}=\frac{5}{z-25}\\\\\implies-\frac{12}{4z}+\frac{7}{4z}=\frac{5}{z-25}\\\\\implies-\frac{5}{4z}=\frac{5}{z-25}\\\\\implies125-5z=20z\\\\\implies25z=125\\\\\implies z=5[/tex]
Have a nice day, also mark brainliest please!
Problem 2
Given: HJ = 5x - 3, JK = 82-9, and KH = 131
Find: x, HJ, and JK
x =
HJ =
JK =
What is the answer.
Answer:
i got 12.2
Step-by-step explanation: (5x-3) +73 =131 is the equation and from that x = 12.2
Use the quadratic formula to find both solutions to the quadratic equation
given below.
The solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
How to determine the solution?The equation is given as:
3x^2 - 7x- 1 = 0
The quadratic equation is represented as:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
So, we have:
[tex]x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}[/tex]
Evaluate the expression
[tex]x = \frac{7 \pm \sqrt{61}}{6}[/tex]
Expand
[tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
Hence, the solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
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Can someone please help me on this question
Answer: ? = 72
Step-by-step explanation:
We will set up a proportion to solve.
[tex]\displaystyle \frac{?}{56} =\frac{45}{35}[/tex]
Now, we will cross-multiply.
? * 35 = 56 * 45
35? = 2,520
? = 72
Can someone help me out on this problem and show work
Answer: 4230.14
Step-by-step explanation:
The amount that the balance is multiplied by each month is
[tex]\frac{2448}{2040}=1.2[/tex].
So, after t months, the balance is [tex]1700(1.2)^{t-1}[/tex].
Substituting in t=6, we get the balance is
[tex]1700(1.2)^{6-1}=\boxed{4230.14}[/tex], to the nearest hundredth.
Combine the radicals 4√7+3√28.
O 10√7
O
4√7
0 -2√7
10√14
Answer:
10sqrt(7)
Step-by-step explanation:
[tex]4 \sqrt{7} + 3 \sqrt{28} \\ \\ 4 \sqrt{7} + 3(2 \sqrt{7} ) \\ \\ 4 \sqrt{7} + 6 \sqrt{7} = 10 \sqrt{7} [/tex]
Gareth buys two oranges. He pays with a £1 coin and gets 52p change. Work out the cost of one orange.
Answer:
24p
Step-by-step explanation:
£1 - £0.52 = £0.48 ← cost of 2 oranges
cost of 1 orange = £0.48 ÷ 2 = £0.24
A motorbike is priced at $945.50 Johnson has $ 5000.
How many motorbikes could he buy?
The number of motorbikes is 5
How to determine the number of motorbikes?The given parameters are:
Motorbike = $945.50
Johnson = $5000.
The number of motorbikes is calculated as:
n = Johnson/Motorbike
So, we have:
n = 5000/945.5
Evaluate
n = 5.29
Remove the decimal
n = 5
Hence, the number of motorbikes is 5
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-8y=7y-5 direct variation or not
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation: }[/tex]
[tex]\mathbf{-8y = 7y - 5}[/tex]
[tex]\huge\textbf{Solving for the equation:}[/tex]
[tex]\mathbf{-8y = 7y - 5}[/tex]
[tex]\mathbf{7y - 5 = -8y}[/tex]
[tex]\huge\textbf{SUBTRACT 7y to BOTH SIDES}[/tex]
[tex]\mathbf{-8y - 7y = 7y - 5 - 7y}[/tex]
[tex]\huge\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathbf{-15y = -5}[/tex]
[tex]\huge\textbf{DIVIDE -15 to BOTH SIDES}[/tex]
[tex]\mathbf{\dfrac{-15y}{-15} = \dfrac{-5}{-15}}[/tex]
[tex]\huge\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathbf{y = \dfrac{-5}{-15}}[/tex]
[tex]\mathbf{y = \dfrac{-5\div-5}{-15\div-5}}[/tex]
[tex]\mathbf{y = \dfrac{1}{3}}[/tex]
[tex]\huge\textbf{Met your answer:}[/tex]
[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{y = \dfrac{1}{3}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]Simplify by looking for like terms: 3a – a + 4b – 2b.
Answer:
2a+2b
Step-by-step explanation:
3a - a = 2a
4b - 2b = 2b
Answer:
2a+2b
Step-by-step explanation:
3a – a + 4b – 2b
Combine like terms
3a-a =2a
4b-2b =2b
3a – a + 4b – 2b. = 2a+2b
Can someone please explain what an outlier is? it keeps popping up in all of my math questions and it is really confusing me...
Answer:
An outlier is something that is out of place compared to the rest of the group. For example, If you had the numbers 3,4,5,4,3,4, and 19, 19 would be the outlier.
Step-by-step explanation:
An outlier is a number that's far away from the rest of your data.
For example, if we look at the numbers 3, 2, 4, 5, 27, and 1, you can likely consider 27 to be an outlier because it's so far away from the rest of the data.
The specific definition of how far something has to be from the rest of the data to be an outlier depends entirely on the situation, but in general: if a number obviously sticks out from the rest, it's probably an outlier.
Which represents the solution(s) of the graphed system of equations, y=x²+x-2 and y = 2x - 2?
Answer:
Option 2: (0,-2) and (1,0)
Step-by-step explanation:
Solutions to graphed systems of equations are the places where the graphs overlap/intersect.
For this system of equations, the red and blue graphs overlap at two points.
Since all of the answers are given as ordered pairs, it is important to know what an ordered pair means.
Ordered pairsAn ordered pair, (x,y), is a pair of numbers, written in parentheses, with a comma between them, that represent the coordinates of a point when graphed on a coordinate system. Each coordinate measures the distance in a certain direction from the origin. The origin is the special point at the intersection of the axes. The axes are the dark horizontal and vertical lines with numbers next to them, representing the value at that distance along the axis.
The first coordinate of an ordered pair is the x-coordinate, and measures the horizontal distance from the origin. Points to the right of the origin are defined to have a positive x-coordinate, and points to the left of the origin are defined to have a negative x-coordinate.
The second coordinate of an ordered pair is the y-coordinate, and measures the vertical distance from the origin. Points above the origin are defined to have a positive y-coordinate, and below the origin are defined to have a negative x-coordinate.
The intersectionsLooking directly below the origin, the blue curve and the red line intersect. Since they intersect directly below the origin, the ordered pair there must have an x-coordinate of zero because no left/right movement was required to get to this point. Only a vertical movement was necessary. The number on the vertical axis tells us that this point has a height of "-2", so the ordered pair for this point is (0,-2).
Looking directly to the right from the origin, the blue curve and the red line intersect again. Since they intersect directly to the right of the origin, the ordered pair there must have a y-coordinate of zero because no up/down movement was required to get to this point. Only a horizontal movement was necessary. The number on the horizontal axis tells us that this point has a horizontal value of "1", so the ordered pair for this point is (1,0).
Since the two points of intersection are (0,-2) and (1,0), the correct answer would be the second choice.
Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet, 16 feet, and 12 feet long. If the two shortest sides of quadrilateral EFGH are 9 feet long and 18 feet long, how long is the 4th side on quadrilateral ABCD?
A. 6 feet
B. 12 feet
C. 10 feet
D. 8 feet
The length of the 4th side on quadrilateral ABCD will be D. 8cm.
How to calculate the length?From the information given, we are told that the lengths of the three longest sides in quadrilateral ABCD are 24 feet, 16 feet, and 12 feet long.
In this case, the side will be:
24/16 = 12/x
x = (16 × 12)/24
x = 8
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need help ASAPP and show your work ( will rate 5 starts )
The cosine model is y = - 7 + 10 · cos (π · x/30 - π).
The sine model is y = - 7 + 10 · sin (π · x/30 - π/2).
How to find sinusoidal functions from a given graph
Sinusoidal functions are periodic trascendent expressions which involves trigonometric functions. There are two kinds of sinusoidal functions:
[tex]y = A \cdot \cos (B\cdot x + C) + D[/tex] (1)
[tex]y = A\cdot \sin (B\cdot x + C) + D[/tex] (2)
Where:
A - AmplitudeB - Angular frecuencyC - Angular phaseD - MidpointFirst, we find the amplitude and the midpoint:
A = [3 - (- 17)]/2
A = 10
D = [3 + (- 17)]/2
D = - 7
Now we find the angular phase and the angular frequency for each model:
Cosine model (x, y) = (0, - 17), (x, y) = (30, 3)
- 17 = 10 · cos C - 7 (3)
3 = 10 · cos (30 · B + C) - 7 (4)
By (3):
- 10 = 10 · cos C
cos C = - 1
C = acos(- 1)
C = - π
And by (4):
3 = 10 · cos (30 · B - π) - 7
10 = 10 · cos (30 · B - π)
cos (30 · B - π) = 1
30 · B - π = acos 1
30 · B - π = 0
30 · B = π
B = π/30
The cosine model is y = - 7 + 10 · cos (π · x/30 - π).
Sine model
Obtain the sine model by using trigonometric expressions:
cos θ = sin (θ + π/2) (5)
By (5):
y = - 7 + 10 · sin (π · x/30 - π + π/2)
y = - 7 + 10 · sin (π · x/30 - π/2)
The sine model is y = - 7 + 10 · sin (π · x/30 - π/2).
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Fill in the gaps below:
Answer:
anticlockwise; reflection about x = 0; reflection about y = x - 1
Step-by-step explanation:
To get from A to A', we have to rotate anticlockwise. This rotation would take us around the coordinate plane from the first quadrant to the fourth quadrant to the third quadrant to the second quadrant. Clockwise about (0, -1) would not bring us to A'. To get from A' to A'', we to reflect across the line x = 0. As you can see in the image, the two triangles mirror each other across a vertical line in the center of them, and this vertical line would be x = 0 because both triangles are at least 1 unit away from it (they are equidistant from this line)
A single transformation that could map A onto A'' would be a reflection about y = x - 1. Both triangles happen to meet at this point so you might be able to visualize it. However, we can also test some points to see if this works. First, we can test the right-most point of A (which is the top-most point of A''). This point on A is (6, 0). If this point was reflected across y = x - 1, y would become 6 - 1 or 5, and since y = x - 1 is the same as x = y + 1, x would become 0 + 1 or 1. Indeed, the equivalent point on A'' is (1, 5).
does anyone know how to do these??
Answer:
b)
c=140°
a= 40°
b=40°
c)
p= 60°
q= 60°
r= 120°
d)
a= 65 °
b= 65°
c= 65°
d= 115°
e=65°
Step-by-step explanation:
Hope it helps
A cab company calculates cab fares using the expression 1.50d + 3, where d is the distance traveled in miles. If a passenger has to pay a $21 fare for a ride, which number from the set {9, 12, 15, 18} is the value of d?
Answer:
12
Step-by-step explanation:
⇒ 21 - 3 = 18 = 1.5a
⇒ a = 12
Which of the following terminating decimals is equivalent to StartFraction 3 over 8 EndFraction
The 0.375 terminating decimals are equivalent to 3/8 option second is correct.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
The fraction is:
= 3/8
After dividing with 8
= 0.375
Thus, the 0.375 terminating decimals are equivalent to 3/8 option second is correct.
The complete question is:
Which of the following terminating decimals is equivalent to 3/8?
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If you anwser the question i give you brainly
The proportional relationship graph that shows the situation is: Graph C.
What is a Proportional Relationship?A proportional relationship is defined as y = kx, where k is the constant of proportionality between x and y, and k = y/x.
Given the equation, M = 3n,
k = 3.
Thus, the graph that has a constant of proportionality (k) of 3, will correspond to the situation.
In graph C, using a point, (400, 1,200), we have:
k = 1,200/400
k = 3
Therefore, the graph that corresponds to the situation is: C.
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Can someone solve this? please
Answer:
Mode = l + [(f₁ - f₀)/(2f₁ - f₀ - f₂)]h
Where, l is the lower limit of the modal class
f₁ is the frequency of the modal class
f₀ is the frequency preceding the modal class
f₂ is the frequency succeeding the modal class
h is the class size
From the table,
Maximum frequency = 41
This frequency lies in the class 10000 - 15000
l = 10000
h = 5000
f₁ = 41
f₀ = 26
f₂ = 16
Now, f₁ - f₀ = 41 - 26 = 15
2f₁ - f₀ - f₂ = 2(41) - 26 - 16
= 82 - 42
= 40
[(f₁ - f₀)/(2f₁ - f₀ - f₂)] = 15/40
= 3/8
Now, mode = 10000 + (3/8)(5000)
= 10000 + (15000/8)
= 10000 + 1875
= 11875
Therefore, the modal income is 11875.What type of function is shown in the data in the table below?
Answer:
the function is quadratic because it have (2) turning points which is a sign of the ax² in rhe quadratic equation (ax²+bx+c)
List the first four terms of the sequence.
The first four terms of the sequence are -1, 6, -22, 90
What is a sequence?A sequence is an order in which numbers occur in a given group of numbers.
It is also numbers arranged based on a certain rule.
Analysis:
a1 = -1
for n ≥ 2
a2 = -4a1 +2
a2 = -4(-1) + 2 = 4+2 = 6
a3 = -4a2 + 2
a3 = -4(6) + 2 = -24 + 2 = -22
a4 = -4a3 +2
a4 = -4(-22) + 2 = 88 + 2 = 90
In conclusion, the first four terms of the sequence are -1, 6, -22, 90
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What is the length of the longest side of a triangle that has the vertices (-2, 1), (5, 1), and (5, 4)?
OA. 65 units
OB. √58 units
OC. 6√65 units
OD. 5√65 units
Answer:
B
Step-by-step explanation:
To find the length of the longest side of the triangle, first sketch the triangle. A graph paper is not needed here.
In this case we have a right-angled triangle, since the ends of the adjacent side has the same y-coordinate of 1 and the opposite side has the same y-coordinate of 5.
In a right-angled triangle, the hypotenuse side is the longest. The length of the hypotenuse side can be found using 2 methods.
1) Pythagoras' Theorem
a² +b²= c²
(adjacent)² +(opposite)²= (hypotenuse)²
Length of adjacent
= 5 -(-2)
= 7 units
Length of opposite side
= 4 -1
= 3 units
(hypotenuse)²
= 7² +3²
= 58
hypotenuse= [tex] \sqrt{58} [/tex]
2) Distance formula
Since we know that the hypotenuse side is the longest, we can simply find the length of the hypotenuse side instead of calculating the length of each side.
[tex]\boxed{{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2} } }}[/tex]
Length of longest side
= distance between (5, 4) and (-2, 1)
[tex] = \sqrt{(4 - 1) {}^{2} + (5 - ( - 2)) {}^{2} } [/tex]
[tex] = \sqrt{3 {}^{2} + {7}^{2} } [/tex]
[tex] = \sqrt{58} [/tex]
Thus, the length of the longest side is [tex] \sqrt{58} [/tex] units.
2x − 4y = 40,
−x + 2y = −20
Find x and y intercept
Answer:
The x and y intercept are (20,0)
Step-by-step explanation:
2x-4y=40—eqn1
-x+2y=-20—eqn2
Make x the subject of eqn2
-x=-20-2y
x=20+2y
plug this into eqn 1
2(20+2y)+4y=40
40+4y+4y=40
8y=40-40
y=0
plug y=0 into eqn2
-x+2(0)=-20
-x=-20
x=20