Answer:
a) 50 meters
b) 2354 meters
c) 12 seconds
d) 24.13 seconds
Step-by-step explanation:
Hello!
a) How far is Lincoln above the ground when he shoots the gun?We need to really understand what the variables represent in this question. Given that t is time, and h is height, the time at which he shoots the bullet will be 0, as the bullet hasn't started traveling yet. This means that we can solve for the original height of the bullet by plugging in 0 for time in the equation.
Equation: [tex]h = -16t^2 + 384t + 50[/tex]
Plug in 0 for t:
[tex]h = -16t^2 + 384t + 50[/tex][tex]h = -16(0)^2 + 384(0) + 50[/tex][tex]h = 50[/tex]The height at which Lincoln shot the bullet is 50 meters.
We can also look at this graphically. The height of origin will simply be when the x-value (in this case t-value) is 0. That means it is the point at which the graph intersects the y-axis, known as the y-intercept.
Standard form of a Parabola: [tex]y = ax^2 + bx + c[/tex]
The y-intercept is the "c" value.
Given our equation: [tex]h = -16t^2 + 384t + 50[/tex]
The c-value is 50. This proves that the y-intercept is 50.
b)How high does the bullet travel vertically relative to the ground?We want to find the highest point of the graph. To do that, we can find the vertex.
We can utilize the Axis of Symmetry (AOS) to find the Vertex.
First, find the AOS using the formula: [tex]AOS = -\frac{b}{2a}[/tex]
a = -16b = 384Plug it into the formula:
[tex]AOS = -\frac{b}{2a}[/tex][tex]AOS = -\frac{384}{2(-16)}[/tex][tex]AOS = \frac{384}{32}[/tex][tex]AOS = 12[/tex]Plug in 12 for t in the equation:
[tex]h = -16t^2 + 384t + 50[/tex][tex]h = -16(12)^2 + 384(12) + 50[/tex][tex]h = -2304 + 4608 + 50[/tex][tex]h = 2304+50[/tex][tex]h = 2354[/tex]Therefore, the highest point of the bullet is 2354 meters.
c)How long does it take the bullet to reach its greatest height?We answered this in the last question. The t-value when h is at its highest is 12.
d)After how many seconds (round to nearest 100th) does the bullet hit the ground?We have to solve for the values of t when h is 0 (when it touches the ground).
Set the equation to 0, and solve using the quadratic formula.
Quadratic formula: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex][tex]x = \frac{-384\pm\sqrt{384^2 - 4(-16)(50)}}{2(-16)}[/tex][tex]x = \frac{-384\pm\sqrt{147456 +3200}}{-32}[/tex][tex]x = \frac{-384\pm\sqrt{150656}}{-32}[/tex][tex]x = \frac{-384\pm388.14}{-32}[/tex][tex]x = -\frac{4.14}{32}, x = \frac{772.14}{32}[/tex]We are only going to take the positive solution, as we can't have a negative time. The solution that doesn't work is called an extraneous solution.
[tex]x = \frac{772.14}{32}[/tex][tex]x = 24.13[/tex]It takes approximately 24.13 seconds for the bullet to hit the ground.
30 mi / h = ____ ft / min
a.
2640
c.
880
b.
264
d.
2112
Answer:
its a 2640 trust me
Step-by-step explanation:
look at the image.......
Answer: 70.9 miles per hour
Step-by-step explanation:
The total distance traveled is 1188 miles (66313- 65125).
Since this was over 16.75, you'll want to divide 1188 by 16.75.
1188/16.75 = 70.9253731
And then round that off to 70.9
what is the slope of y=5/4x-7/4?
Answer:
5/4 or 1.25
Step-by-step explanation:
y=mx+b is the form of all linear equations
m is the slope
here m = 5/4 so the slope is 5/4 or 1.25
Triangle ABC has side lengths:
AB = 3.5 cm, BC = 2.4 cm, and AC = 4.2 cm
ΔABC ≅ ΔHJK
What is the length of side HJ?
The length of HJ is 3.5 cm
What is Congruency?Two geometric figures are said to be congruent, or to be in the relation of congruence, if it is possible to superpose one of them on the other so that they coincide throughout.
Given:
AB = 3.5 cm, BC = 2.4 cm, and AC = 4.2 cm
As, ΔABC ≅ ΔHJK
So,
AB = HJ
BC = JK
AC = HK
Thus, HJ= AB = 3.5 cm
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Help pls asap
If sine < 0 and tans > 0 then:
OA. 180° << 270°
OB. 0° <9< 90°
C. 270° << 360°
OD. 90° << 180°
Answer:
The answer is C. 270° < ∅ < 360°
Step-by-step explanation:
Given information:
sine < 0 and tans > 0.
Quadrant where sine < 0 is either III or IV.
Quadrant where tans > 0 is either I or III.
It is Quadrant III that has both sines < 0 and tans > 0.
Translation: (x,y)→(x+7,y+5) Coordinates: Y(−5,−4), X(−5,−1), W(−2,0), V(−2,−5)
Answer:
Y - (2,1)
X - (2,4)
W - 5,5)
V - (5,0)
Step-by-step explanation:
Translation: (x,y) → (x+7,y+5)
Coordinates:
Y(−5,−4) => (-5 + 7, -4 + 5) => (2,1)
X(−5,−1) => (-5 + 7, -1 + 5) = > (2,4)
W(−2,0) => (-2 + 7, 0 + 5) => (5,5)
V(−2,−5) => (-2 + 7, -5 + 5) => (5,0)
What is the value of cos(Tan^-1 1)?
a. 2
b.square root 2
c. 2 square root 2
d. square root 2 over 2
Answer:
D
Step-by-step explanation:
So you have the equation: [tex]cos(tan^-1(1))[/tex]. So let's work in order and focus on the [tex]tan^-1(1)[/tex] part first. The inverse of tan is essentially taking in the value of [tex]tan(\theta)[/tex] and returning [tex]\theta[/tex]. And the value of [tex]tan(\theta)[/tex] can be defined as [tex]\frac{sin(\theta)}{cos(\theta)}[/tex]. So if you look at the unit circle, you'll need to look for two values that are exactly the same. You'll notice when the angle is 45 degrees, the value of sine, and cosine are the exact same. They're both [tex]\frac{\sqrt2}{2}[/tex]. So the inverse of tan(1 degree) = 45 degrees. Now we can literally refer to the same point, because when finding the cosine of 45 degrees, we can just use the x-value. This gives a solution of [tex]\frac{\sqrt2}{2}[/tex]
A quantity with an initial value of 130 decays exponentially at a rate such that the
quantity cuts in half every 9 weeks. What is the value of the quantity after 21 days
A quantity with an initial value of 130 decays exponentially at a rate such that the quantity cuts in half every 9 weeks. 103.18 is the value of the quantity after 21 days.
What is exponential decay?A process known as exponential decay is when a quantity diminishes over time at a pace that reduces proportionately as the amount shrinks.
The term "exponential decay" refers to a population's or group's rate of decline when it is proportionate to the size of the population. The overall value falls in exponential decay, yet the percentage that departs stays constant over time.
Let, y = 130. aˣ
here, x = number of days
Given that,
A quantity with an initial value of 130 decays exponentially.
the quantity cuts in half every 9 weeks
the value of the quantity after 21 days = ?
So, 130 × [tex]a^{(7\times9) }[/tex] = 130 × (1/2)
or, a⁶³ = 1/2
or, a [tex](1/2)^{(1/63)}[/tex]
Thus, y = 130 × [tex](1/2)^{(x/63)}[/tex]
when x = 21
thus, y = 130 ×[tex](1/2)^{(21/63)}[/tex]
y = 130 × [tex](1/2)^{(1/3)}[/tex]
y ≈ 103.18
Hence, 103.18 is the value of the quantity after 21 days.
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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defective. What is the probability that the first two electric toothbrushes sold are defective
The probability that the first two electric toothbrushes sold are defective is 0.016.
The probability of an event, say E occurring is:
[tex]P(E)=\frac{n(E)}{N}[/tex]
Here,
n (E) = favorable outcomes
N = total number of outcomes
Let X = the number of defective electric toothbrushes sold.
The number of electric toothbrushes that were delivered to a store is n = 20.
The number of defective electric toothbrushes is x = 3.
The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:
[tex](\left {{20} \atop {2}} \right. )[/tex][tex]=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190[/tex]
The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:
[tex](\left {{3} \atop {2}} \right. )[/tex][tex]=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3[/tex]
Compute the probability that the first two electric toothbrushes sold are defective as follows:
P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes
[tex]\frac{3}{190}\\ =0.01579\\=0.016[/tex]
Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.
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What is the slope of the line represented by the equation y = y equals StartFraction 4 Over 5
x minus 3.x – 3?
The slope of the line represented by the given equation is 0.8
Slope of a lineFrom the question, we are to determine the slope of the line represented by the given equation
The given equation is
[tex]y = \frac{4}{5} x-3[/tex]
The slope-intercept form of the equation of a line is given as
y = mx + c
Where m is the slope or gradient
and c is the y-intercept
By comparing with the given equation,
m = 4/5
m = 0.8
Hence, the slope of the line represented by the given equation is 0.8
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The Box-and-Whisker Plot shown displays the number of text messages sent during the previous week. What is the fewest reported number of text messages sent?
A. 82
B. 62
C. 74
D. 90
The fewest reported number of text messages sent, given the data is 62 (Option B)
Data obtained from the questionData = 62, 74, 82, 90, 99Fewest number = ?How to determine the fewest numberThe fewest number in a given data is simply defined as the smallest number in the data.
Considering the data given from the question, we can see that the smallest number in the data is 62
Thus, 62 is the fewest number in the data.
Therefore, the correct answer to the question is 62 (Option B)
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Complete question
The Box-and-Whisker Plot shown displays the number of text messages sent during the previous week. What is the fewest reported number of text messages sent? 62, 74, 82, 90, 99
A. 82
B. 62
C. 74
D. 90
You plan to conduct a survey to estimate the percentage of adults who have had chickenpox. Find the number of people who must be surveyed if you want to be 90% confident that the sample percentage is within two percentage points of the true percentage for the population of all adults.
The number of people who must be surveyed if you want to be 90% confident that the sample percentage is within two percentage points of the true percentage for the population of all adults is 1691.
The true proportion of the population is not given, so we assume it to be 0.5, that is, p = 0.5.
Hence, q = 1 - p = 1 - 0.5 = 0.5.
Confidence level given = 90%.
Z-Score corresponding to 90% confidence interval (Z) = 1.645.
We are asked to find the sample size (n) when we want to be 90% confident that the sample percentage is within two percentage points of the true percentage for the population of all adults, that is, standard error (E) = 2% = 0.02.
By the formula of standard error, we know:
E = Z√[{p(1 - p)}/n].
Substituting the values, we get
0.02 = 1.645√[{0.5*0.5}/n]
or, 0.0004 = 2.706025*0.25/n
or, n = 2.706025*0.25/0.0004 = 1691.265625 ≈ 1691 {Since the sample size has to be a whole number}.
Thus, the number of people who must be surveyed if you want to be 90% confident that the sample percentage is within two percentage points of the true percentage for the population of all adults is 1691.
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x^3 - y^3 = 218 where x and y are positive integers. Find x+y
The value of x + y is 12
How to solve for x + y?The equation is given as:
x^3 - y^3 = 218
Make x^3 the subject
x^3 = 218 + y^3
The next cubic expression greater than 218 is 343.
So, we assume
x^3 = 343
This gives
x = 7
Substitute x^3 = 343 in x^3 = 218 + y^3
343 = 218 + y^3
Evaluate the like terms
y^3 = 125
This gives
y = 5
So, we have:
x + y = 7 + 5
Evaluate
x + y = 12
Hence, the value of x + y is 12
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You enter a room. 2 dogs, 4 horses, one giraffe, and a duck are laying on a bed. 3 chicken are flying over a chair. How many legs are on the ground?.
Answer:
4 legs from the bed and 4 from the chair im guessing since not all have 4
Step-by-step explanation:
.
Answer:
36 legs
Step-by-step explanation:
What are two angles next to each other called?
Two angles which are next to each other is referred to as adjacent angle in this case.
What is an Adjacent angle?These are angles which have a common vertex and side and do not overlap with one another.
This angle lie next to each other when plotted hence the reason why they share a common vertex.
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Prove that
cos^4∆ - sin^4∆ = 2cos^2∆ - 1
[tex]\cos^{4} x-\sin^{4} x\\\\=(\cos^{2} x+\sin^{2} x)(\cos^{2} x-\sin^{2} x)\\\\=\cos^{2} x-\sin^{2} x\\\\=\cos^{2} x-(1-\cos^{2} x)\\\\=2\cos^{2} x-1[/tex]
What are the solutions to the quadratic equation 2x + x = 3? - 1,2/-/- 1,3/- 1, -/-/- -1, - -/-/- (A) (B) (C) (D)
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Assuming equation:}[/tex]
[tex]\mathbf{2x + x = 3}[/tex]
[tex]\huge\textbf{Solving for the equation:}[/tex]
[tex]\mathbf{2x + x = 3}[/tex]
[tex]\mathbf{2x + 1x = 3}[/tex]
[tex]\huge\textbf{Combine the like terms:}[/tex]
[tex]\mathbf{(2x + 1x) = 3}[/tex]
[tex]\mathbf{(2x + x) = 3}[/tex]
[tex]\mathbf{2x + x = 3}[/tex]
[tex]\mathbf{3x = 3}[/tex]
[tex]\huge\textbf{Divide 3 to both sides:}[/tex]
[tex]\mathbf{\dfrac{3x}{3} = \dfrac{3}{3}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\mathbf{x = \dfrac{3}{3}}[/tex]
[tex]\mathbf{x = 3\div3}[/tex]
[tex]\mathbf{x = 1}[/tex]
[tex]\huge\textbf{Answer:}[/tex]
[tex]\huge\boxed{\mathsf{x = 1}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]How do you Calculate the mean,median and mode in grouped data.
Answer:
The mean:
data: 3,6,9,10
You first add all of the numbers together.
3+6+9+10= 28
There 4 numbers in the data set, so you divide 4 by the sum of all of the numbers.
28/4= 7
So the mean is 7.
The median:
data: 3,6,9,10
first put all of the numbers in numerical order.
3,6,9,10
Then you find the middle number in the data set.
3,6,(the middle number here),9,10
to find the middle number, do the mean of 6 and 9
The mean of 6 and 9 is 7.5
So, 7.5 is the median
another example: 3,4,7,9,13
The middle number is 7
so 7 is the median
The mode:
data: 3,6,9,10
The mode is the number that is repeated the most
in this data, there is no mode.
but in this data: 4,4,6,9,11
4 is the mode because it was repeated the most
What is the solution set for
O s-4 and x-16
O s--4 and s-4
Os--8 and s-8
Ox--16 and x-16
||-8₂
Answer:
4th option
Step-by-step explanation:
the absolute value function always gives a positive result, however, the expression inside can be positive or negative, that is
[tex]\frac{x}{2}[/tex] = 8 or - [tex]\frac{x}{2}[/tex] = 8
solving each equation
[tex]\frac{x}{2}[/tex] = 8 ( multiply both sides by 2 to clear the fraction )
x = 2 × 8 = 16
or
- [tex]\frac{x}{2}[/tex] = 8 ( multiply both sides by 2 )
- x = 16 ( multiply both sides by - 1 )
x = - 16
then x = - 16 , x = 16
I am not able to solve this question
Answer:
C
Step-by-step explanation:
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(ChildofHermes)
please mark brainliest
im only streaming for 15 more hours
Answer:
Choice C
Step-by-step explanation:
2654^0 and 5^0
Which is greater?
There's a law of exponents for solving this type of question.
The law states that,
x^0 = 1Same case here.
2654^01And,
5^0 1Hence, they are same.
2654⁰ = 5⁰
Can you divide 2 by 9? Explain your response.
Answer:
0.22222222222
Step-by-step explanation:
To divide two by nine, you need to use your long division skills. Unfortunately, this interface doesn't lend itself well to showing you the actual long division problem, so try to follow the steps with me.
draw a division symbol (should look like half a rectangle). Put the 9 in front of the rectangle and a 2 inside it. Make the top of the rectangle long.
Note that the result of the division 2÷9 is not an exact value and is equivalent to recurring decimal 0.22... (which has 2 as the period).
Use the law of cosines to find the value of cos0. Round your answer to two decimal places.
A.0.22
B.0.84
C.0.35
D.-1.04
Using the law of cosines on the given triangle, we see that; cosθ = 0.22
How to use the law of cosines?The law of cosines is expressed as;
c² = a² + b² - 2ab cos C
Now, in this case the angle is θ and employing this law of cosines gives us;
10.2² = 5.7² + 9.8² - 2(5.7 * 9.8)*cosθ
104.04 = 32.49 + 96.04 - 111.72 * cosθ
104.04 = 128.53 - 111.72 * cosθ
(128.53 - 104.04)/111.72 = cosθ
cosθ = 0.22
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graph the inequality y > |x - 4| + 3
Answer: As graphed below.
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Which equation represents a line that passes through the two points in the
table?
Can you help me with these two because I don't understand
Answer: 1: 34 units 2: 24.5
Step-by-step explanation:
For figure 1, just split the area into squares and triangles and find the area of each. If you split figure 1 into 1 square and 3 triangles you get...
4x4= 16
(4x3)/2= 6
(4x4)/2= 8
(4x2)/2= 3
16+6+8+3 = 34
You do the same for figure 2, but use 4 triangles and 1 tiny square
1x1= 1
(4x3)/2= 6
(3x3)/2= 4.5
(4x4)/2= 8
(5x5)/2= 5
1+6+4.5+8+5= 24.5
You shouldn't need to worry about negative numbers because you are looking at the area
Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the distance from point P to point R.
4.9
4.7
2.5
2.3
Answer:
4.7
Explanation:
A point is positioned at minus two, seven. At one, zero, you'll find point R. Determine the value of Y. Regarding point Q. That is 2/3 of the distance between points P. So, negative two becomes positive seven. So, we have minus twenty-seven and 1 common zero. So, if we place a line between these, we must calculate the distance. First, you should be aware that you may achieve this using the distance formula. I prefer to conceive of it as the Pythagorean Theorem. So, the distance is 3^2 and 7^2, which is D^2. So, 9+49=58. And, we'll take the square root of it. As a result, the square root of 58=D. And, you want to be 2/3 the distance between points P and B. So, divide this by 2/3. So, this is close to 5.1. But, you want to get the Y value; found the distance, 2/3 of the way. When the distance is 5.1 instead of round 7.6, we've arrived at point P. We want to be 5. 1 yard away on this line. This is point P and we want to be at point Q. Since it'll have the same slope. As a result, the slope will be 7/3. So, it'll be proportionate 7. Since the square root of fifty-eight is too large. Route 58/3 is the destination. The square root of 258 is canceled. Such that 7=3y/2. 7x2=14/3=4.7. It's by locating comparable figures.
The diagram shows the intersections of several straight roads. The avenues run parallel to each other.
First Avenue and Second Avenue are parallel. Oak goes through both streets at point A and B. Main goes diagonally down through both streets and intersects with Oak Street. The distance from First to Second on Main is 280 feet. The distance from Second to the intersection of Oak is 140 feet. The distance from Point B to the intersection of Main is 113 feet.
Amana walks along Oak from point A to B. To the nearest foot, how far does she walk?
75 ft
226 ft
307 ft
347 ft
By applying the property of similar triangles, the distance Amana from point A to B walked is: B. 226 ft.
How to determine the distance?By critically observing the diagram (see attachment), we can deduce that two (2) similar triangles were formed by the First Ave. and Second Ave.
By applying the property of similar triangles, the distance Amana walked is given by:
(AB + 113)/113 = (280 + 140)/140
(AB + 113)/113 = 420/140
(AB + 113)/113 = 3
AB + 113 = 3 × 113
AB + 113 = 339
AB = 339 - 113
AB = 226 ft.
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Answer: B. 226 ft.
Step-by-step explanation: Trust Me! I got it correct on Edge.
The formula for the perimeter of a rectangle is P = 2 (1+w).
The equation of L is L = 0.5P - W
How to solve for L?The formula is given as:
P = 2(L + W)
Divide through by 2
0.5P = L + W
Subtract W from both sides
L = 0.5P - W
Hence, the equation of L is L = 0.5P - W
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Complete question
The formula for the perimeter of a rectangle is P=2(l+w). Solve for l.
Solve the Percent Discount Application.
The local grocery store has just marked down a patio set by 20%. If the patio set costs $79.90, what is the discounted price?
$63.92
$94.80
$15.80
$70.00
Write a compound inequality that represents the given graph:
OA.x < -2 and x ≥ 4
OB.x < -2 or x ≥4
OC.-2
OD.-2≥x>4
Answer: the correct answer is choice A
Step-by-step explanation:
This is because the inequality symbols are pointed the correct way. The symbols are also showing the correct answers with the greater than or equal to sign is on the correct point value. You find the place for the equal to or greater/less than symbol by the open or closed circle point. An open circle means the number is not included in the answer while a closed circle is included in the answer.