Therefore, Two slices of bacon had 96 less calories than three slices of roasted turkey.
What does equation mean?a formula that illustrates the connection between two expressions on either side of a sign. It usually only has one variable and an equal sign. like this: 2x – 4 = 2.
Here,
One piece of bacon has 42 calories in it.
There are 60 calories in 1 slice of turkey.
2 slices of bacon are 2 calories each (42)
So 84 calories in 2 slice of bacon
3 slices of roasted turkey have 3 calories each slice (60)
Three slices of roasted turkey have 180 calories each.
180-84 is the difference in the amount of calories.
96 calories are added due to the calorie difference.
Two slices of bacon had 96 less calories than three slices of roasted turkey.
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Which of the following is equivalent to −3(2p − 4q)?
−5p − 7q
−5p + 12q
−6p − 4q
−6p + 12q
Answer:
-6p+12q
Step-by-step explanation:
−3(2p − 4q)
Distribute the -3
-3 * 2p -3 * -4q
-6p+12q
Answer:
[tex] \sf \: d) \: -6p + 12q [/tex]
Step-by-step explanation:
Now we have to,
→ simplify the given expression.
The expression is,
→ -3(2p - 4q)
Let's simplify the expression,
→ -3(2p - 4q)
→ -3(2p) - 3(-4q)
→ (-3 × 2)p - (3 × -4)q
→ -6p - (-12)q
→ -6p + 12q
Hence, answer is -6p + 12q.
a washing machine can hold 3/4 kg of laundry in each load. if randy has . 6 kilograms of laundry, how many loads does he need to do? 5 6 7 d8
Randy needs 8 loads.
To find the answer on the question we have to follow the method of multiplication and division .
A washing machine can hold [tex]\frac{3}{4}[/tex] kg of laundry in each load.
[tex]\frac{3}{4}[/tex] kg of laundry is equal to 1 load.
[tex]\frac{3}{4}[/tex] kg of laundry = 1 load
1 kg of laundry = [tex]\frac{1 * 4}{3}[/tex] load ( following the method of division )
1 kg of laundry = [tex]\frac{4}{3}[/tex] load
Randy has 6kg of laundry.
So, 1kg of laundry i.e [tex]\frac{4}{3}[/tex] load is to be multiplied by 6.
6kg of laundry = [tex]\frac{4 * 6}{3}[/tex] load ( following the method of multiplication)
= 8 loads
Hence, Randy needs 8 loads.
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The length of a rectangle is 2m longer than its width. If the perimeter of the rectangle is , 60 find its length and width.
Answer:
Let the width of the rectangle be w.
Then the length of the rectangle is w+2.
The perimeter of the rectangle is the sum of all its sides, so it is 2(w) + 2(w+2) = 60.
Expanding the parentheses and combining like terms, we get:
2w + 2w + 4 = 60
4w + 4 = 60
4w = 56
w = 14
The width of the rectangle is 14.
The length of the rectangle is 14+2 = 16.
Therefore, the length of the rectangle is 16 and the width is 14.
CORRECT ME IF I'M WRONG
Solve: 6г - 17r = -66
-6
-11
11
Answer:
r = 6
Step-by-step explanation:
6г - 17r = -66
-(17г - 6r) = -66
-11r = -66
-11r/(-1) = -66/(-1)
11r = 66
11r/11 = 66/11
r = 66/11
r = 6
When viewed from the side, the spire on the top of a building forms an isosceles triangle m
Answer: When viewed from the side, the spire forms an isosceles triangle m, the area of the isosceles triangle is equal to 1/4b√4a²-b².
Step-by-step explanation:
What is isosceles triangle?
A triangle with two equal-length sides is said to be isosceles. The triangle's third side is referred to as the base, while the triangle's two equal sides are known as the legs. The triangle's legs are usually shorter than the base, which is usually the triangle's longest side.
To determine if the spire on top of a building forms an isosceles triangle when viewed from the side, we first need to define the three sides of the triangle. Let's call the two sides that are equal in length "s" and the third side "l".
Next, we need to determine if the triangle satisfies the definition of an isosceles triangle. The two sides "s" of the spire must therefore be of equal length for the spire to create an isosceles triangle.
To confirm this, we can measure the length of the sides "s" and compare them to each other. If they are equal in length, then the spire forms an isosceles triangle. If they are not equal in length, then the spire does not form an isosceles triangle.
For example, if the base of the triangle is 10 feet and the length of the two equal sides is 10 feet, then the triangle is isosceles. Therefore, the spire on the top of the building forms an isosceles triangle when viewed from the side.
Therefore, if the two sides "s" of the spire are equal in length, then the spire forms an isosceles triangle when viewed from the side.
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An isosceles triangle is a triangle with two sides of equal length and two equal angles.
What is isosceles triangle?
An isosceles triangle is a type of triangle that has two sides of equal length and two angles of equal measure. The two sides of equal length are the two legs of the triangle, while the third side is called the base. The angles opposite the two equal sides are equal in measure, while the angle opposite the base is the third angle. Isosceles triangles are classified according to the measure of their angles. An equilateral triangle is an isosceles triangle with all angles equal to 60°. An isosceles triangle with two angles equal to 45° is called an isosceles right triangle. An isosceles triangle with two angles equal to less than 45° is referred to as an acute isosceles triangle, while an isosceles triangle with two angles equal to more than 45° is referred to as an obtuse isosceles triangle. Isosceles triangles have many practical uses in engineering and architecture. For example, buildings and bridges often feature isosceles triangles in their roofs and arches in order to provide strength and stability.
When viewed from the side, the spire on the top of a building forms an isosceles triangle because it has two equal sides (the sides running up the spire) and two equal angles (the angles at the base of the spire).
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What x values are not included in the domain of the quotient of two functions? You can choose more than 1 answer.
1. Any x -values that are in the domains of both functions.
2. Any x-values that are not in the domain of both functions.
3. Any x-values that result in the numerator being equal to 0.
4. Any x-values that result in the denominator being equal to 0.
The correct answer is 4. Any x-values that result in the denominator being equal to 0.
When finding the domain of the quotient of two functions, we need to consider the domains of both the numerator and the denominator. The domain of a function is the set of all possible input values for which the function is defined. For the quotient of two functions, this means that the domain is the set of all x-values that are in the domains of both the numerator and denominator.
However, there is one additional restriction on the domain of the quotient of two functions. The denominator of the quotient cannot be equal to 0, because division by 0 is undefined. Therefore, any x-values that result in the denominator being equal to 0 are not included in the domain of the quotient.
In summary, the x-values that are not included in the domain of the quotient of two functions are any x-values that result in the denominator being equal to 0.
match the vector fields f with the plots labeled i-iv. f(x, y) = y, x
The match of vector field f for f(x, y) = y, x is graph II .
We can say that some points for the given function are F(1,2)= (2,1) F(2,1) =(1,2) F(0,1) = (1,0) F(2,3) = (3,2) F(0,2)=(2,0) .
That means arrow heads should start with these points and this is shown accordingly in graph II only.
Therefore ,
option A matches with figure 2
option B matches with figure 1
option C matches with figure 3
option D matches with figure 4
A vector field is a way to visualize them as represented by a number of small arrows each having a magnitude or a direction.
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Algebra 2 Questions that i need help with
The function rule for the functions f(x) and g(x) given by the table are;
f(x) = Log₁₀x
g(x) = 2ˣ
What is the function rule of the table?
1) In the first table of the function f(x), we see the coordinates as;
(10, 1), (100, 2), (1000, 3), (10000, 4), (100000, 5)
Thus, we see that;
Log 10 = 1
Log 100 = Log 10² = 2 Log 10 = 2
Log 1000 = Log 10³ = 3Log 10 = 3
Thus, the function rule is Log₁₀x
2) In the second table of the function g(x), we see the coordinates as;
(1, 2), (2, 4), (3, 8), (4, 16), (5, 32)
Thus, we see that;
2¹ = 2
2² = 4
2³ = 8
Thus, the function rule here is 2ˣ
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The price of a venti vanilla bean Frappuccino from Starbucks is $4.45, but you have only $3 with you. Your friend is working and gets you a discount of 20%. How much does the drink cost with the discount? Do you have enough to buy the drink? How much money are you short?
The cost of the drink after discount is 3.56 dollars.
You don't have enough money to buy the drink.
You are short of 0.89 dollars.
How to find the cost of the drink?The price of a venti vanilla bean Frappuccino from Starbucks is $4.45, but you have only $3 with you. Your friend is working and gets you a discount of 20%.
The cost of the drink with discount can be calculated as follows:
amount discounted = 20% of 4.45
amount discounted = 20 / 100 × 4.45
amount discounted = 89 / 100
amount discounted = 0.89 dollars
Therefore,
cost of the drink after discount = 4.45 - 0.89
cost of the drink after discount = 3.56 dollars
Therefore, you don not have enough money to buy the drink.
You are short of 4.45 - 3.56 = 0.89 dollars.
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Calculate the double integral.
(2x)/(1+xy) dA
R = [0, 2]
The double integral of (2x)/(1+xy)dA over the rectangular region R = [0, 2]×[0, 1] give an approximate value of 2.0044.
Therefore, the answer is 2.0044.
By double Riemann sum,
∫∫(2x)/(1+xy) dA ≈ ∑(i = 1 to m)∑(j = 1 to n)f(xij*⁻, yij*⁻)ΔA
R = [0, 2]×[0, 1], that is a = 0, b = 2, c = 0, d = 1
Dividing R into four squares with m = n = 2 and corners of each square chosen (1, 1), (1, 2), ( 2, 1) and (2, 2). So midpoint of the square is (0.5, 0.5), (0.5, 1.5), ( 1.5, 0.5) and (1.5, 1.5)
Δx = (b - a)/m = 1
Δy = (d - c)/ n = 0.5
ΔA = ΔxΔy = 0.5
∫∫(2x)/(1+xy) dA ≈ ∑(i = 1 to 2)∑(j = 1 to 2)f(xij*⁻, yij*⁻)ΔA
= ΔA × ( f(0.5, 0.5) + f(0.5, 1.5) + f( 1.5, 0.5) + f(1.5, 1.5))
= 0.5 × ( (2×0.5)/(1+0.5×0.5) + (2×0.5)/(1+0.5×1.5) + (2×1.5)/(1+1.5×0.5) + (2×1.5)/(1+1.5×1.5))
≈ 0.5 × 4.0088
= 2.0044
--The question is incomplete, answering to the question below--
"Calculate the double integral.
(2x)/(1+xy) dA
R = [0, 2]×[0, 1]"
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Written as a mixed number, the improper fraction 113⁄8 would appear as
Answer:
[tex]14 \frac{1}{8}[/tex]
Step-by-step explanation:
112 goes into 8 14 times, there is then 1/8 leftover
mr. dawson is making a grocery budget for the month of april. he plans to split the budget equally among 4 shopping trips. to stay under budget, mr. dawson figures he should spend less than $180 each trip.let x represent how much mr. dawson wants to spend on groceries in april. which inequality describes the problem?
The inequality that describes the problem is x < 180 × 4, which means that the total amount of money Mr. Dawson wants to spend on groceries in April should be less than $180 multiplied by 4, or $720.
Mr. Dawson is making a grocery budget for the month of April. He plans to split the budget equally among 4 shopping trips and wants to stay under budget. To figure out the maximum amount of money he should spend on groceries in April, he needs to calculate the total amount of money he should spend for all 4 shopping trips. To do this, he multiplies the maximum amount of money he should spend per trip, $180, by the number of trips, 4. This gives us $180 × 4 = $720. Therefore, Mr. Dawson should spend less than $720 on groceries in April. The inequality that describes the problem is x < 180 × 4, which means that the total amount of money Mr. Dawson wants to spend on groceries in April should be less than $720. This inequality ensures that Mr. Dawson will stay under budget and be able to complete his 4 shopping trips for the month of April.
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determine the horizontal and vertical components of force at pins a and c of the two-member frame.
a and C of the two-member frame=Ax=-300N,Ay=300N, cx=300n, cy=300N.
momentum of all forces about A is
=-600x1.5+Cxx3=0
cx=900/3=300n
cx=300n.
momentum of all forces about c is
-600x1.5-AXx3=0
Ax=-900/3=-300n
Ax=-300n
forces in Ab components is
600x1.5-Ayx3=0
ay=300n
momentum of all forces about b
600x1.5-ayx3-cyx3+cxx3=0
900-900-900+cxx3=0
cxx3=900
cx=300n
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Help I need to turn this in urgent please help me
The lengths of the segments SH is 16, HM is 8, TH is 8, HR is 12,
TD = 12 and ER = 18.
What is a triangle?A triangle is a three-sided closed-plane figure formed by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.
We know a centroid divides a line segment in the ratio of 2 : 1 from vertices
to the other side.
Given, ΔSTR, H is the centroid EH = 6, DH = 4, and SM = 24.
SH = (2/3)×24 = 16.
HM = 8.
As DH = 4 hence TH = 8.
As EH = 6, HR = 12.
TD = (DH + TH) = 12.
ER = 6 + 12 = 18.
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find the value of y
Answer:
y = 10 cm
Step-by-step explanation:
A = 12 · 5 / 2
A = 6 · 5 = 30 cm²
y = 30 · 2 / 6
y = 5 · 2
y = 10 cm
a coin is weighted so that the probability of getting heads is two-thirds. suppose you toss this coin 15 times. let x represent the number of heads. what are the mean and standard deviation of x?
When a coin is weighted, there is a two-thirds chance that it will land on its head. suppose you toss this coin 15 times. let x represent the number of heads. Mean = 10 and Standard deviation = 2.88
The mean of x, which represents the number of heads when the coin is tossed 15 times, is 10. This is because the probability of getting heads is two-thirds, meaning that two out of every three tosses will result in heads.We apply the following formula to determine the standard deviation:
Standard Deviation = √(p*q*n), where p is the probability of getting heads, q is the probability of getting tails, and n is the number of tosses. In this case, p = 2/3, q = 1/3, and n = 15, so the standard deviation of x is 2.88.
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An agricultural land of 2 hectares is planted with cereals. 20% of it is planted with corn, 10% with oats, and the rest with wheat. Find how many dynyms is each surface
First, we need to find the total area of the land that is planted with cereals. To do this, we multiply the total area of the land, which is 2 hectares, by the percentage of the land that is planted with cereals, which is 100% - 20% - 10% = 70%. This gives us a total area of 2 hectares * 70% = 1.4 hectares.
Next, we need to divide the total area of 1.4 hectares into three parts, one for each type of cereal. Since 20% of the land is planted with corn, the area of land planted with corn is 1.4 hectares * 20% = 0.28 hectares. Similarly, since 10% of the land is planted with oats, the area of land planted with oats is 1.4 hectares * 10% = 0.14 hectares. Finally, the area of land planted with wheat is 1.4 hectares - 0.28 hectares - 0.14 hectares = 0.98 hectares.
Since 1 hectare is equal to 10,000 square meters, the area of land planted with corn is 0.28 hectares * 10,000 square meters/hectare = 2,800 square meters. The area of land planted with oats is 0.14 hectares * 10,000 square meters/hectare = 1,400 square meters, and the area of land planted with wheat is 0.98 hectares * 10,000 square meters/hectare = 9,800 square meters. So, each surface of land planted with corn is 2,800 square meters, each surface of land planted with oats is 1,400 square meters, and each surface of land planted with wheat is 9,800 square meters.
some friends are leaving a party in westminster to go home. one group takes a taxi uptown, traveling north at 35 miles per hour. the rest of the friends share another taxi, traveling south at 44 miles per hour. if the two taxis depart at the same time, how much time will pass before they are 3 miles apart?
Approximately it will take 2 minutes to pass before they are 3 miles apart.
The time can be defined as the ratio of distance covered by an object to a unit speed. Time refers to the progression of events.
The Formula of Time of a given body can be expressed as,
Time = Distance÷Speed
one group takes a taxi uptown, traveling north at 35 miles per hour
The rest of the friends share another taxi, traveling south at 44 miles per hour
Suppose X as a time before they are 3 miles apart
so forming the equations:
35x+44x=3
79x=3
x=3/79hours.
To convert into minutes multiply x by 60 because 1 hour=60 min
x=3/79*60
x=0.0379*60
x=2.278
x=2 minutes.
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1. A model car travels horizontally after being released. The car travels a distance d metres in a time of t seconds. d is directly proportional to t. The car travels 20 metres in a time of 2 seconds. a) Calculate the distance the car travels in 3 seconds.
If d is directly proportional to t, then we can say that d = k * t, where k is a constant of proportionality. We can find the value of k by substituting the given values for d and t into this equation:
d = k * t
20 = k * 2
Solving for k, we get k = 10.
Now that we know the value of k, we can calculate the distance the car travels in 3 seconds by substituting 3 for t in the equation d = k * t:
d = 10 * 3
d = 30
Therefore, the car travels 30 meters in a time of 3 seconds.
Given the equation a line y+9=-3(x- 4) Determine the characteristics of the line.
Answer:Isn't this cheating
Step-by-step explanation:
One angle of a triangle meaure 10 degree greater than the mallet angle and the third angle meaure 10° le than twice the mallet angle find the meaure of the three angle
One angle in a triangle is 10 degrees larger than the smallest angle, while the third angle is 10 degrees less than twice the smallest angle. As a result, the three angles are 55°, 45°, and 80°.
Three vertices and three sides make up a triangle. The angles of the triangle are formed by the connection of the three sides end to end at a single point. The sum of the triangle's three angles is 180 degrees.
Let's consider the three angles of the triangle as ∠P, ∠Q, and ∠R. Let's consider Q as the smallest angle. The sum of angles P, Q, and R is given as ∠P+∠Q+∠R=180°
Then, ∠P = ∠Q + 10° and ∠R = 2∠Q - 10°. Substituting these two angle values in the above equation,
[tex]\begin{aligned}\angle Q + 10^{\circ}+\angle Q+2\angle Q - 10^{\circ}&=180^{\circ}\\4\angle Q&=180^{\circ}\\\angle Q&=45^{\circ}\end{aligned}[/tex]
Then,
∠P = ∠Q + 10° = 45°+ 10° = 55°
∠R = 2∠Q - 10° = 2(45°) - 10° = 90° - 10° = 80°
The answers are 55°, 45°, and 80°.
The complete question is -
One angle of a triangle measure 10 degrees greater than the smallest angle and the third angle measure 10 degrees less than twice the smallest angle find the measure of the three angles.
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evaluate the function: f(n)=n^2 + 3n; find f(-2)
Answer:
f(-2) = -2
Step-by-step explanation:
Step 1: Substitute -2 for the variable n.
f(-2) = (-2)^2 + 3(-2)
Step 2: Simplify the expression.
f(-2) = 4 - 6
Step 3: Evaluate the expression.
f(-2) = -2
Move the yellow dots in order to make the segments intersect. Let the intersection be called point V. Make the lines intersect in such a way that angle ∠SVT is an obtuse angle less than 135°. Afterwards, use the protractor to determine the precise measure of all four angles. You should redraw the lines if angle ∠SVT is not the proper size.
All four measures of the angles are mentioned in the figure.
What is an angle?The inclination is the separation seen between planes or vectors that meet. Degrees are another way to indicate the slope. For a full rotation, the angle is 360 °.
If the measure of the angle is more than the right angle that is 90°. Then the angle is known as the obtuse angle.
Move the yellow dabs to make the portions cross. Allow the convergence to be called point V. Cause the lines to cross so that point ∠SVT is a harsh point under 135°.
Let the measure of the angle ∠SVU be 'x' which is greater than 45°. Then the measure of the angle ∠SVT will be '180 - x'.
All four measures of the angles are mentioned in the figure.
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guys i need help tell me what 7 is divided by the sum of a number and 8
Answer:
Below
Step-by-step explanation:
x = a number
7 / (x+8)
solve the given differential equation by undetermined coefficients. 1 4 y'' + y' + y = x2 − 3x
The general solution will be:
[tex]$$y(x)=e^{-x / 28}\left(c_1 \cos \left(\frac{\sqrt{55}}{28} x\right)+c_2 \sin \left(\frac{\sqrt{55}}{28} x\right)\right)+x^2-5 x-23$$[/tex]
[tex]$$14 y^{\prime \prime}+y^{\prime}+y=x^2-3 x$$[/tex]
Consider the homogenous equation [tex]$14 y^{\prime \prime}+y^{\prime}+y=0$[/tex]
The auxiliary equation is [tex]$14 m^2+m+1=0$[/tex]
[tex]m=-\frac{1}{28}+i \frac{1}{28} \sqrt{55}[/tex]
The homogenous solution is
[tex]$$y_c(x)=e^{-x / 28}\left(c_1 \cos \left(\frac{\sqrt{55}}{28} x\right)+c_2 \sin \left(\frac{\sqrt{55}}{28} x\right)\right) \text {. }$$[/tex]
Consider the non-homogenous de [tex]$14 y^{\prime \prime}+y^{\prime}+y=x^2-3 x$[/tex] by using the method of undetermined coefficients
consider [tex]$y_p=A x^2+B x+C \Rightarrow y_p^{\prime}=2 A x+B \Rightarrow y_p^{\prime \prime}=2 A$[/tex]
by plugging the values in [tex]$14 y^{\prime \prime}+y^{\prime}+y=x^2-3 x$[/tex]
[tex]$$\begin{aligned}& 28 A+(2 A x+B)+A x^2+B x+C=x^2-3 x \\& \Rightarrow x^2(A)+x(2 A+B)+28 A+B+C=x^2-3 x\end{aligned}$$[/tex]
On comparing both sides we get
A=1.
2A+B =-3
=>B=-3-2A
=>B=-5
28A+B+C=0
=>C=-28A-B
=>C=-23
by plugging the values [tex]y_p=x^2-5 x-23[/tex].
The general solution will be:
[tex]$$y(x)=e^{-x / 28}\left(c_1 \cos \left(\frac{\sqrt{55}}{28} x\right)+c_2 \sin \left(\frac{\sqrt{55}}{28} x\right)\right)+x^2-5 x-23$$[/tex]
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Gievn f(x)=3x+2, find f (-4)
Answer:
-10
Step-by-step explanation:
f(x)=3x+2
f(-4)=3(-4)+2
f(-4)=-12+2
f(-4)=-10
Find the nth term of this number sequence 7, 10, 13, 16, ...
Answer:
31
Step-by-step explanation:
7, 10, 12, 16, 19, 22, 25, 28, 31
Adding by 3
Hope this works
Help on logic and proof homework geometry
A total of 699 tickets were sold for the school play. They were either adult tickets or student tickets. There were 51 fewer student tickets sold than adult tickets. How many adult tickets were sold?
Answer:
Sold:
adults: 375 tickets
student: 324 tickets
Step-by-step explanation:
a + s = 699 Eq. 1
a = s + 51 Eq. 2
a = adult tickets sold
s = student tickets sold
Replacing Eq. 2 im Eq. 1
(s+51) + s = 699
2s + 51 = 699
2s = 699 - 51
2s = 648
s = 648/2
s = 324
From Eq. 2
a = 324 + 51
a = 375
Check:
From Eq. 1:
a + s = 699
375 + 324 = 699
b)
Given that n is an integer greater than 1, explain why the largest prime factor of
2(7^n) - 2(7^n-1)+7^n+1 is 61.
Answer:
See below.
Step-by-step explanation:
Given expression:
[tex]2(7^n) - 2(7^{n-1})+7^{n+1}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}[/tex]
[tex]\implies 2(7^n) - 2(7^{n-1})+7^{n} \cdot 7^1[/tex]
[tex]\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}[/tex]
[tex]\implies 2(7^n) - 2\left(\dfrac{7^{n}}{7^{1}}\right)+7^{n}\cdot 7^1[/tex]
Simplify:
[tex]\implies 2(7^n) - \dfrac{2}{7} (7^n)+7(7^{n})[/tex]
Factor out the common term 7ⁿ:
[tex]\implies \left(2- \dfrac{2}{7} +7\right)7^{n}[/tex]
Therefore:
[tex]\dfrac{61}{7}(7^n)[/tex]
A prime number is a whole number greater than 1 that cannot be made by multiplying other whole numbers. Therefore, the factors of a prime number are 1 and the number itself.
If n is an integer greater than 1, the number will always have at least 4 factors (1, 7, 61 and itself) and therefore cannot be a prime number by definition.
For example:
[tex]n = 2 \implies \dfrac{61}{7}(7^2)=61 \times 7=427[/tex]
[tex]n = 3\implies \dfrac{61}{7}(7^3)=61 \times 7^2=2989[/tex]
Therefore, the largest prime number is when n = 1:
[tex]n = 1 \implies \dfrac{61}{7}(7^1)=61[/tex]