You measure 47 watermelons' weights, and find they have a mean weight of 33 ounces. Assume the population standard deviation is 7.7 ounces. Based on this, construct a 90% confidence interval for the true population mean watermelon weight. Give your answer as m (round to 2 decimal places) + ounces You measure 21 turtles' weights, and find they have a mean weight of 56 ounces. Assume the population standard deviation is 2.9 ounces. Based on this, construct a 99% confidence interval for the true population mean turtle weight. Enter your answer as #Im.Give your answers as decimals, to two places + ounces You measure 34 textbooks' weights, and find they have a mean weight of 62 ounces. Assume the population standard deviation is 9.4 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places Out of 200 people sampled, 104 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Enter your answer as p m Give your answers as decimals, to three places. + Out of 300 people sampled, 189 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places

Answers

Answer 1

a. The 90% confidence interval for the true population mean watermelon weight is 30.41 to 35.59 ounces.

b. The 99% confidence interval for the true population mean turtle weight is 54.56 to 57.44 ounces.

c. The 99% confidence interval for the true population mean textbook weight is 56.884 to 67.116 ounces.

d. The 99% confidence interval for the true population proportion of people with kids is 0.464 to 0.576.

e. The 99% confidence interval for the true population proportion of people with kids is 0.585 to 0.675.

a. For the watermelon weights:

Sample mean (m) = 33 ounces

Population standard deviation (σ) = 7.7 ounces

Sample size (n) = 47

Confidence level = 90%

To construct the confidence interval, we can use the formula:

Confidence Interval = m ± Z * (σ/√n)

Where Z is the z-score corresponding to the desired confidence level. For a 90% confidence level, Z = 1.645 (obtained from the standard normal distribution table).

Confidence Interval = 33 ± 1.645 * (7.7/√47)

Confidence Interval ≈ 33 ± 2.586

Confidence Interval ≈ (30.41, 35.59) ounces

The 90% confidence interval for the true population mean watermelon weight is 30.41 to 35.59 ounces.

b. For the turtle weights:

Sample mean (m) = 56 ounces

Population standard deviation (σ) = 2.9 ounces

Sample size (n) = 21

Confidence level = 99%

Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.

Confidence Interval = 56 ± 2.576 * (2.9/√21)

Confidence Interval ≈ 56 ± 1.438

Confidence Interval ≈ (54.56, 57.44) ounces

The 99% confidence interval for the true population mean turtle weight is 54.56 to 57.44 ounces.

c. For the textbook weights:

Sample mean (m) = 62 ounces

Population standard deviation (σ) = 9.4 ounces

Sample size (n) = 34

Confidence level = 99%

Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.

Confidence Interval = 62 ± 2.576 * (9.4/√34)

Confidence Interval ≈ 62 ± 5.116

Confidence Interval ≈ (56.884, 67.116) ounces

The 99% confidence interval for the true population mean textbook weight is 56.884 to 67.116 ounces.

d. For the proportion of people with kids:

Number of people with kids (p) = 104

Sample size (n) = 200

Confidence level = 99%

To construct the confidence interval for a proportion, we can use the formula:

Confidence Interval = p ± Z * √[(p(1-p))/n]

Using the z-score corresponding to a 99% confidence level (Z = 2.576), we can calculate the confidence interval.

Confidence Interval = 104/200 ± 2.576 * √[(104/200)(1 - 104/200)/200]

Confidence Interval ≈ 0.52 ± 0.056

Confidence Interval ≈ (0.464, 0.576)

The 99% confidence interval for the true population proportion of people with kids is 0.464 to 0.576.

e. For the proportion of people with kids:

Number of people with kids (p) = 189

Sample size (n) = 300

Confidence level = 99%

Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.

Confidence Interval = 189/300 ± 2.576 * √[(189/300)(1 - 189/300)/300]

Confidence Interval ≈ 0.63 ± 0.045

Confidence Interval ≈ (0.585, 0.675)

The 99% confidence interval for the true population proportion of people with kids is 0.585 to 0.675.

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Related Questions

what is the area of a 3.3in circle​

Answers

Answer:

3.3/2 = 1.65² x 3.14 = 8.54865

Can someone help me you’re correct me it only let me type one number plz

Answers

Answer:

9

Step-by-step explanation:

Hello There!

The circumference is equal to the diameter times π

The diameter given is 9m

NOTE: it says "leave answer in terms of π" meaning that we do not apply π to the diameter

So the answer would be just 9π

Answer:

9

Step by step:

C= 2 x pi x r

c = 2 x pi x 4.5

c=  9 x pi

A rectangle has a length of 16.2 in. The width is half length. What is the area, in square inches, of the rectangle (please hurry)

Answers

The area is 131.22 squared in

When rolling a die why is the probability of rolling a 2 or 3

Answers

Answer:

1/3

Step-by-step explanation:

If you're talking about a 6-sided die, then there are 6 sides.  Rolling a 2 or a 3 would be a 2/6 chance.  To simplify if from there, you can also say that there is a 1/3 chance.

Please help me, GodBless.

Answers

Answer:

-6

Step-by-step explanation:

To find the slope, you do y₂ - y₁ / x₂ - x₁

y₂ - y₁ / x₂ - x₁

= -35 - 11 / 5 - 1

= -24 / 4

= -6

The slope is -6

Answer:

-6

Step-by-step explanation:

Hi,

To find the slope when given a table, just pick two points, subtract the y values, and then divide them by the x values after you subtract them as well. Here's what I mean...

Let's use 1, -11 and 5, -35

So...

-35 - (-11)

This is the change in y. -35 - (-11) is the same thing as -35 + 11 (subtracting  negative switches to adding it)

You get -24

Now, the change in x.

5 - 1 = 4

So, -24/4 and you get the slope of : -6

I hope this helps :)


Evaluate the function at the given value.
G(x)= 10.2^x
what is g(-4)?

Answers

Answer:

5/8

Step-by-step explanation:

10 * 2^-4 = 10 * 1/16 = 10/16 = 5/8

Read and Complete the Scenario Together (45m) If a person living in the state of Utah, USA gets Covid 19, what is the probability that he or she was vaccinated? There are many variables relating to age, health risks, and behaviors that contribute to getting Covid. However, with those limitations in mind let's see what we can find out. As of May 2021, 41.8% of Utahns had been vaccinated. Utah had a 13.9% rate of Covid before (without) the vaccine. Studies have shown that the Pfizer vaccine is 95% effective in preventing being infected. Using this information, as well as the methods and videos you covered in the pre-group assignment, work with your group to respond the following prompts: C = Got Covid NV = not vaccinated with Pfizer V = Vaccinated with Pfizer 1. If a person is randomly selected from the population of Utah, what is the probability of that person getting Covid? P C)= 2. If a Utah resident gets Covid, what is the probability that he or she was vaccinated with Pfizer? P(VIC) = 3. If a Utah resident gets Covid, what is the probability that he or she was NOT vaccinated with Pfizer? P(NVC) 4. Discuss with your group and then write a paragraph using statistics to support someone choosing to get vaccinated. You may also use other facts but you must reference where you get them. 5. Discuss with your group and then write a second paragraph using statistics to support someone choosing NOT to get vaccinated. You may also use other facts but you must reference where you get them.

Answers

The correct probabilities are 0.1017 and 0.2053.

Given:

P(c\NV)=0.139, P(C|V)= 1- 0.95 = 0.05

P(V) = 0.418

P(NV) = 1- 0.418 = 0.582.

(1). The probability of that person getting Covid? P CP(C) = P(C|NV)        P(NV)+P(C|V) P(V)

0.139*0.582+0.05*0.418

= 0.1017.

(2).  The probability that he or she was vaccinated with P fizer P(V|C).

   [tex]P(V|C) = \frac{P(V|C)P(V)}{P(C|NV)P(NV)+P(CV)P(V)}[/tex]

                        [tex]\frac{0.05\times0.418}{0.139\times0.582+0.05\times0.418} = 0.2053[/tex]

3). P(NV|C) = 1 - P(V|C) = 0.7946.

(4). The chances of Covid is decreased.

(5). A second paragraph using statistics to support someone choosing 0.1017 = 10% got Covid and 0.139 = 13% not vaccinate.

Therefore, the probability of that person getting Covid is 0.1017 and the probability that he or she was vaccinated with Pfizer is 0.2053.

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Help with this ( math)

Answers

The answer is 61 or 22 u choose between these To

The equation r = a describes a right circular cylinder of radius a in the cylindrical (r, t, z)-coordinate system. Consider the points P : (r = a, t = 0, z = 0), Q: (r = a, t = tmax, z = h) on the cylinder, and let C be a curve on the cylinder that goes from P to Q. Suppose C is parametrized as a(t) = (a cost, a sin(t), p(t)), 0 ≤ t ≤ tmax, where p(0) = 0 and p(tmax) = h. • (4 pts) Express the length L(p) of C in terms of p. (Hint: You need to look up the formula for the length of a curve in cylindrical coordinates in your calculus textbook.) • (4 pts) Apply the Euler-Lagrange equation of the calculus of varia- tions to find a differential equation for the ☀ that minimizes L(p). • (4 pts) Solve that differential equation and conclude that the mini- mizing curve is a helix.

Answers

Minimizing curve C is a helix, described by the equation :

C(t) = (a cos(t), a sin(t), C exp(-cot(t)) + h)

To express the length L(p) of curve C in terms of p, we can use the formula for the length of a curve in cylindrical coordinates. In cylindrical coordinates, the arc length element ds can be given by:

ds² = dr² + r² dt² + dz²

Since dr = 0 (as r = a is constant along the curve C), and dt = -a sin(t) dt (from the parametrization), we have:

ds² = a² sin²(t) dt² + dz²

Integrating ds over the curve C from t = 0 to t = tmax, we get:

L(p) = ∫[0,tmax] √(a² sin²(t) + p'(t)²) dt

where p'(t) denotes the derivative of p(t) with respect to t.

To find the differential equation for the function p(t) that minimizes L(p), we can apply the Euler-Lagrange equation of the calculus of variations. The Euler-Lagrange equation is given by:

d/dt (dL/dp') - dL/dp = 0

Differentiating L(p) with respect to p' and p, we have:

dL/dp' = 0 (since p does not appear explicitly in L(p))

dL/dp = d/dt (dL/dp') = d/dt (a² sin²(t) p'(t) / √(a² sin²(t) + p'(t)²))

Using the chain rule, we can simplify the expression:

dL/dp = (a² sin²(t) p''(t) - a² sin(t) cos(t) p'(t)²) / (a² sin²(t) + p'(t)²)^(3/2)

Setting the Euler-Lagrange equation equal to zero, we get:

(a² sin²(t) p''(t) - a² sin(t) cos(t) p'(t)²) / (a² sin²(t) + p'(t)²)^(3/2) = 0

Simplifying further, we have:

p''(t) - (sin(t) cos(t) / sin²(t)) p'(t)² = 0

This is the differential equation that the function p(t) must satisfy to minimize L(p).

To solve this differential equation, we can make the substitution u = p'(t). Then the equation becomes:

du/dt - (sin(t) cos(t) / sin²(t)) u² = 0

This is a separable first-order ordinary differential equation. By solving it, we can obtain the solution for u = p'(t). Integrating both sides and solving for p(t), we get:

p(t) = C exp(-cot(t)) + h

where C is a constant determined by the initial condition p(0) = 0, and h is the value of p at t = tmax.

Therefore, the minimizing curve C is a helix, described by the equation :

C(t) = (a cos(t), a sin(t), C exp(-cot(t)) + h)

where C is a constant determined by the initial condition, and h is the value of p at t = tmax.

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The diameter of a circle is 8 inches. What is the area?

d=8 in

Give the exact answer in simplest form.

Answers

Step-by-step explanation:

Radius = Half of Diameter

r = 8/2

= 4 in.

Area of Circle =

[tex]\pi {r}^{2} \\ = \pi( {4}^{2} ) \\ = 16\pi \: {in}^{2} [/tex]

The linearized form for the above non-linear model is. . a = AB A B c.log x -log A+ ** log B log= log 4 + xlog B los d. tos 3) = log 4+ Blog of 3) = log 4 + Blog x log = x e log

Answers

Using the corrected linearized form a = c * A * B * log(x) - A * B * log(A) + A * B * log(B), solve for unknowns A, B, c, and x.

To solve the equation a = c * A * B * log(x) - A * B * log(A) + A * B * log(B) for unknowns A, B, c, and x, we need additional information or constraints.

Without specific values or relationships among the variables, it is not possible to provide a numerical solution. However, if you have specific values for any of the variables or if there are constraints or relationships among them, we can apply appropriate mathematical techniques, such as substitution or optimization methods, to find the values of A, B, c, and x that satisfy the equation.

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HURRY!!! ANSWER QUICK!!!

Choose all the equations that have x = 5 as a possible solution.
A. 20 - x = 5
B. x + 2 = 7
C. 3x = 15
D. 5x = 15
E. x- 5 = 0

Answers

Answer:

b,c,e

Step-by-step explanation:

B. - 5+2=7
C. 3x5=15
E. 5-5=0

A circle has a radius of 13 cm what is the diameter of the circle? What is the circumference of the circle? What is the area of the circle? Step-by-step answer please

Answers

Answer:

Diameter: 26cm

Circumference: 26π / 81.68cm

Area: 169π / 531cm²

Step-by-step explanation:

Diameter is radius x 2, so 13 x 2 = 26

Circumference is diameter x π, so 26 x π = 26π / 81.68cm

Area is π x r², so π x 13² = 169π / 531cm²

Tyler and his friends wanted to watch a movie on opening night. They bought tickets online for $9 each. They paid an additional $5 handling fee for the order. The costs was more than $150. How many tickets could they have purchased?

Answers

Answer:

caca

Step-by-step explanation:

The expenses E and income I for making and selling T-shirts with a
school logo are given by the equations E = 535 +4.50n and I = 12n,
where n is the number of T-shirts.

Expenses: Slope=
Y-Intercept =


income: Slope=
Y-Intercept

Answers

Answer: n = 71.333

Step-by-step explanation: E (n) = 535 + 4.50
I (n) = 12n
E = I
535 + 4.5n = 12n
7.5 n = 535
n = 71.333

Approximate the stationary matrix S for the transition matrix P by computing powers of the transition matrix P. P= [ 0.37 0.63] [ 0.19 0.81] S= (Type an integer or decimal for each matrix element Round to four decimal places as needed.)

Answers

To approximate the stationary matrix S for the transition matrix P, we need to compute powers of the transition matrix P until it reaches a stable matrix.

Starting with P = [0.37 0.63; 0.19 0.81], we can compute powers of P as follows:

P^2 = P * P

= [0.37 0.63; 0.19 0.81] * [0.37 0.63; 0.19 0.81]

= [0.2746 0.7254; 0.1538 0.8462]

P^3 = P * P^2

= [0.37 0.63; 0.19 0.81] * [0.2746 0.7254; 0.1538 0.8462]

= [0.2421 0.7579; 0.1873 0.8127]

P^4 = P * P^3

= [0.37 0.63; 0.19 0.81] * [0.2421 0.7579; 0.1873 0.8127]

= [0.2222 0.7778; 0.1941 0.8059]

Continuing this process, we find:

P^5 = [0.2149 0.7851; 0.1957 0.8043]

P^6 = [0.2124 0.7876; 0.1961 0.8039]

P^7 = [0.2117 0.7883; 0.1961 0.8039]

As we can see, the matrix P^7 is very close to the stationary matrix S. Therefore, we can approximate the stationary matrix S as:

S ≈ [0.2117 0.7883; 0.1961 0.8039]

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What is the theoretical probability of flipping a heads?

Answers

A coin only has two side so you have a 1 out of 2 chance of getting heads. The probability could change depending on how many times you flip.

answer:

50/50

step-by-step explanation:

hi there!

flip a coin a couple of times, most likely get the same number of heads then you will of tails, since a coin has 2 sides and only two equal sides the probability to flip that very coin and it landing on heads is 50 percent same as landing it on tails, we know its 50 percent because 100 percent is the full amount ( no matter how much the coin is worth ) and dividing that by 2 does indeed equal 50 or 50 percent.

i believe that is one of the reasons why before a lot of sport games start off with a coin toss to chose which team plays first because it is a 50/50 chance for each team, making it fair toss

i hope this helps you! i hope you have a good rest of your day! :)

Cody weighed 110 pounds when he started 6th grade but now weighs 150 pounds
as a 7th grader. What is the percent of increase in his weight?

Answers

answer: he increased 40 pound

Step-by-step explanation: if it gives negative option please select that

Reading Improvement Program To help students improve their reading, a school district decides to implement a reading program. It is to be administered to the bottom 14% of the students in the district, based on the scores on a reading achievement exam. If the average score for the students in the district is 124.5, find the cutoff score that will make a student eligible for the program. The standard deviation is 15. Assume the variable is normally distributed. Round 2-value calculations to 2 decimal places and the final answer to the nearest whole number.

Answers

Rounding the cutoff score to the nearest whole number, the cutoff score that will make a student eligible for the reading program is approximately 108.

To find the cutoff score that will make a student eligible for the reading program, we need to determine the score below which the bottom 14% of students fall.

Since the variable is normally distributed and we know the average score and standard deviation, we can use the Z-score formula to find the cutoff score.

The Z-score formula is:

[tex]\[Z = \frac{X - \mu}{\sigma}\][/tex]

Where:

Z is the Z-score,

X is the raw score,

[tex]\mu[/tex] (mu) is the mean, and

[tex]\sigma[/tex] (Sigma) is the standard deviation.

We want to find the Z-score that corresponds to the bottom 14% of students, which means the area to the left of the Z-score is 0.14.

Using a standard normal distribution table or calculator, we can find the Z-score that corresponds to an area of 0.14, which is approximately -1.08.

Now we can rearrange the Z-score formula to solve for X, the cutoff score:

[tex]\[X = Z \cdot \sigma + \mu\][/tex]

Substituting the values we have:

[tex]\[X = -1.08 \cdot 15 + 124.5\][/tex]

Calculating the expression:

[tex]\[X = -16.2 + 124.5\]\\X = 108.3[/tex]

Rounding the cutoff score to the nearest whole number, the cutoff score that will make a student eligible for the reading program is approximately 108.

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Let W = {(0, x, y, z): x - 6y + 9z = 0} be a subspace of R4 Then a basis for W is: a O None of the mentioned O {(0,-6,1,0), (0,9,0,1); O {(0,3,1,0), (0,-9,0,1)} O {(0,6,1,0), (0,-9,0,1)} Let w = {(:a+2c = 0 and b – d = 0} be a subspace of M2,2. 2 W d } Then dimension of W is equal to: 4. O 3 1 O 2 O None of the mentioned

Answers

The dimension of w is 1.

To find a basis for the subspace W = {(0, x, y, z) : x - 6y + 9z = 0} of R4, we can first find a set of vectors that span W, and then apply the Gram-Schmidt process to obtain an orthonormal basis.

Let's find a set of vectors that span W. Since the first component is always zero, we can ignore it and focus on the last three components. We need to find vectors (x, y, z) that satisfy the equation x - 6y + 9z = 0. One way to do this is to set y = s and z = t, and then solve for x in terms of s and t:

x = 6s - 9t

So any vector in W can be written as (6s - 9t, s, t, 0) = s(6,1,0,0) + t(-9,0,1,0). Therefore, {(0,6,1,0), (0,-9,0,1)} is a set of two vectors that span W.

To obtain an orthonormal basis, we can apply the Gram-Schmidt process. Let u1 = (0,6,1,0) and u2 = (0,-9,0,1). We can normalize u1 to obtain:

v1 = u1/||u1|| = (0,6,1,0)/[tex]\sqrt{37}[/tex]

Next, we can project u2 onto v1 and subtract the projection from u2 to obtain a vector orthogonal to v1:

proj_v1(u2) = (u2.v1/||v1||^2) v1 = (-6/[tex]\sqrt{37}[/tex]), -1/[tex]\sqrt{37}[/tex], 0, 0)

w2 = u2 - proj_v1(u2) = (0,-9,0,1) - (-6/[tex]\sqrt{37}[/tex]), -1/[tex]\sqrt{37}[/tex], 0, 0) = (6/[tex]\sqrt{37}[/tex]), -9/[tex]\sqrt{37}[/tex], 0, 1)

Finally, we can normalize w2 to obtain:

v2 = w2/||w2|| = (6/[tex]\sqrt{37}[/tex], -9/[tex]\sqrt{37}[/tex], 0, 1)/[tex]\sqrt{118}[/tex]

Therefore, a basis for W is {(0,6,1,0)/[tex]\sqrt{37}[/tex], (6/[tex]\sqrt{37}[/tex]), -9/[tex]\sqrt{37}[/tex], 0, 1)/[tex]\sqrt{118}[/tex]}.

For the subspace w = {(:a+2c = 0 and b – d = 0} of [tex]M_{2*2}[/tex], we can think of the matrices as column vectors in R4, and apply the same approach as before. Each matrix in w has the form:

| a b |

| c d |

We can write this as a column vector in R4 as (a, c, b, d). The condition a+2c = 0 and b-d = 0 can be written as the linear system:

| 1 0 2 0 | | a | | 0 |

| 0 0 0 1 | | c | = | 0 |

| 0 1 0 0 | | b | | 0 |

| 0 0 0 1 | | d | | 0 |

The augmented matrix of this system is:

| 1 0 2 0 0 |

| 0 1 0 0 0 |

| 0 0 0 1 0 |

The rank of this matrix is 3, which means the dimension of the solution space is 4 - 3 = 1. Therefore, the dimension of w is 1.

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2. Write the equation of a circle that has a diameter of 12 units if its center is at (4,7).
O (x – 4)2 + (y – 7)2 = 144
O (x +4)2 + (y + 7)2 = 144
O (x – 4)2 + (y-7)2 = 36
O (x+4)2 + (y + 7)2 = 36

Answers

Answer:

The Answer is B

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here diameter = 12, thus radius = 12 ÷ 2 = 6 and (h, k) = (2.5, - 3.5), thus

(x - 2.5)² + (y - (- 3.5))² = 6², that is

(x - 2.5)² + (y + 3.5)² = 36 ← equation of circle

jemimah went to the market and bought 500g of meat 850g of fish and 900g of eggs. What is the total weight of the items she bought in a kilograms.​

Answers

Answer:

2.25kg

Step-by-step explanation:

500g+850g+900g=2250

2250/1000=2.25kg

Let A and B be two events in a specific sample space. Suppose P(A) = 0,4; P(B) = x and P(A or B) = 0,7 For which values of x are A and B mutually exclusive? For which values of x are A and B independent?

Answers

For A and B to be mutually exclusive, the value of x must be 0. For A and B to be independent, the value of x can be any value between 0 and 0.3, inclusive.

Two events A and B are said to be mutually exclusive if they cannot occur at the same time, meaning that the intersection of A and B is an empty set. In probability terms, if A and B are mutually exclusive, then P(A and B) = 0.

Given that P(A) = 0.4 and P(A or B) = 0.7, we can use the formula for the probability of the union of two events: P(A or B) = P(A) + P(B) - P(A and B). Since we want to find the values of x for which A and B are mutually exclusive, we set P(A and B) = 0:

0.7 = 0.4 + x - 0

0.7 = 0.4 + x

x = 0.3

Therefore, for A and B to be mutually exclusive, the value of x must be 0. For any other value of x, A and B will have a non-empty intersection and therefore will not be mutually exclusive.

On the other hand, two events A and B are considered independent if the occurrence of one event does not affect the probability of the other event. In probability terms, if A and B are independent, then P(A and B) = P(A) * P(B).

Since P(A) = 0.4 and P(B) = x, we can set up the equation:

P(A) * P(B) = 0.4 * x

For A and B to be independent, this equation must hold for any value of x. Therefore, A and B are independent for any value of x between 0 and 0.3, inclusive.

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Please help will mark brainliest!!

Find the surface area of each figure. Round to the nearest tenth if necessary.

Answers

Answer:

9 - 166.42m²

10 - 308.8cm²

Step-by-step explanation:

The first figure shown is a triangular prism

We can find the surface area using this formula

[tex]SA=bh+L(S_1+S_2+h)[/tex]

where

B = base length

H = height

L = length

S1 = base length

S2 = slant height ( base's hypotenuse )

The triangular prism has the following dimensions

Base Length = 4m

Height = 5.7m

Length = 8.6m

S1 = 4m

S2 = 7m

Having found the needed dimensions we plug them into the formula

SA = ( 4 * 5.7 ) + 8.6 ( 4 + 7 + 5.7 )

4 * 5.7 = 22.8

4 + 7 + 5.7 = 16.7

8.6 * 16.7 = 143.62

22.8 + 143.62 = 166.42

Hence the surface area of the triangular prism is 166.42m²

The second figure shown is a pyramid

The surface area of a pyramid can be found using this formula

[tex]SA = A+\frac{1}{2} ps[/tex]

Where

A = Area of base

p = perimeter of base

s = slant height

The base of the pyramid is a square so we can easily find the area of the base by multiplying the base length by itself

So A = 8 * 8

8 * 8 = 64

So the area of the base (A) is equal to 64 cm^2

The perimeter of the base can easily be found by multiplying the base length by 4

So p = 4 * 8

4 * 8 = 32 so p = 32

The slant height is already given (15.3 cm)

Now that we have found everything needed we plug in the values into the formula

SA = 64 + 1/2 32 * 15.3

1/2 * 32 = 16

16 * 15.3 = 244.8

244.8 + 64 = 308.8

Hence the surface area of the pyramid is 308.8cm²

If I work for $7.25 an hour and work for 35 day how much money do I make

Answers

Answer:

1776.25

Step-by-step explanation:

35x7=245. 245x7.25=1776.25

Answer:

35 x 24 = 840, 840 hours

840 x 7.25 = $6090 for 35 days

Step-by-step explanation:

what is the mistake below? solve the system equations by substitution: {4x − y = 20−2x − 2y = 10

Answers

The solution to the system of equations by substitution is x = 3 and y = -8.

To solve the system of equations by substitution:

Solve one equation for one variable in terms of the other variable. Let's solve the first equation for x:

4x - y = 20

4x = y + 20

x = (y + 20)/4

Substitute this expression for x into the second equation:

-2x - 2y = 10

-2((y + 20)/4) - 2y = 10

(y + 20)/2 - 2y = 10

(y + 20) - 4y = 20

-y - 20 - 4y = 20

-5y = 40

y = -8

Substitute the value of y back into the first equation to find x:

4x - (-8) = 20

4x + 8 = 20

4x = 20 - 8

4x = 12

x = 12/4

x = 3

Therefore, the solution to the system of equations is x = 3 and y = -8.

To learn more about “substitution” refer to the https://brainly.com/question/22340165

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Help pleaseeeeeeeeeee

Answers

Answer:

d

Step-by-step explanation:

Which graphs have a line of symmetry? Check all of the boxes that apply.

Answers

Answer:

The last one is symmetrical.

The first one and the last one are correct.

OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPORT CARD RESULTS AND I DONT WANNA FAIL PLS HELP-

Answers

Answer:

it would be $1800

Step-by-step explanation:

if each hoop costs $600, and they buy 3, 600 x 3 = 1800

Answer:

1800

Step-by-step explanation:

600 * 3 = 1800

How did Clay and Webster fight against Jackson’s dislike for the bank?

Answers

Answer:

Jackson's opponents planned to use the bank to defeat him in the 1832 presidential campaign. Senators Henry Clay and Daniel Webster were friends of Biddle. ... They thought that if Jackson tried to veto, or reject, the renewal of the charter, he would lose support.

Step-by-step explanation:

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