-x² + 2x + x - 3x = -9 + 2 + 6

For a hypothesis testing by considering two samples related to rate of people who exercise and who do not exercise, the observed t-value < standard so, null hypothesis does not rejected and there is no evidence to support the claim.

We have a researcher who was interested in making a comparison of resting pulse rate of people who exercise regularly and who do not exercise regularly. There is two independent samples. In 1ˢᵗ sample, sample size, n₁= 16

Sample mean, [tex]\bar X_1[/tex] = 72.3

Standard deviations, s₁ = 10.3

In case of second sample, sample size, n₂ = 12

Sample mean, [tex] \bar X_2[/tex] = 69.0

Standard deviations, s₂ = 8.9

Level of significance = 2.5% = 0.25

Consider the null and alternative hypothesis for the test hypothesis are defined as [tex]H_0 : μ_1 =μ_2[/tex]

[tex]H_a : μ_1 >μ_2[/tex]

The test statistic : using t-test formula

[tex]t = \frac{ \bar X_1 - \bar X_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2}}}[/tex]

[tex]= \frac{72.3- 69}{ \sqrt{ \frac {10.3^2}{16} + \frac{8.9^2}{12}}}[/tex]

= 0.91

Degree of freedom, df = n1 + n2 - 2

= 16 + 12 -2 = 26

Using the t-distribution table, the critical value for t(0.025, df = 26) is equals to the 2.06. Now, the observed t-value = 0.91 is less than 2.06 ( standard t value), so, we do not reject H₀ . Hence, no evidence to support the researcher claim.

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a) A 2*2 area model would not work to multiply (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) because this expression has 5 terms, and a 2*2 area model can only accommodate 4 smaller areas (b) The area model for (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) with the correct lengths and widths labeled has been attached below. (c) The final total area is 2x² - 10x - 15.

An area model is a way to visualize multiplication by breaking up the larger rectangle into smaller rectangles whose areas represent the products of the terms being multiplied. To determine the correct rows and columns for the area model, we count the number of terms in each factor and use that as a guide. For example, if one factor has 3 terms and the other has 4 terms, we would use a 3x⁴ area model, with 3 rows and 4 columns.

a) A 2*2 area model would not work to multiply (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) because this expression has 5 terms, and a 2*2 area model can only accommodate 4 smaller areas.

b) The area model for (x + 3)(2x⁴ − 3x³ − 2x² − 4x − 1) with the correct lengths and widths labeled has been attached below.

   2x⁴ − 3x³ − 2x² − 4x − 1

 +---------------------------------------

x  |   2x⁵    -3x⁴    -2x³    -4x²   -x

 |

3  |   6x⁴    -9x³    -6x²    -12x    -3

 +---------------------------------------

c) To find the total area of a rectangle with length (x + 8) and width (x − 5), we can use an area model with 2 rows and 2 columns. The length (x + 8) corresponds to one dimension of the rectangle, while the width (x − 5) corresponds to the other dimension. The area of each smaller rectangle in the model represents the product of one term from each factor.

    x + 8      x - 5

 +--------------------

x  |  x² + 8x   x² - 5x

 |

-5 | -5x + -40   -5x + 25

 +--------------------

The final total area can be found by adding up the areas of the smaller rectangles:

Total area = x² + 8x + x² - 5x - 5x - 40 + 25

= 2x² - 10x - 15

= 2x² - 10x - 15.

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Ann drinks 125 milliliters of water each hour to stay on track and finish her 1-liter water bottle by the end of the school day.

To solve this problem, we first need to convert the given volume of water from liters to milliliters since milliliters are a more appropriate unit of measurement for the amount of water that Ann drinks each hour.

1 liter = 1000 milliliters

Therefore, Ann drinks 1000 milliliters of water in total for the day.

To find out how many milliliters of water Ann drinks each hour, we can divide the total amount of water by the number of hours she drinks it for.

1000 milliliters / 8 hours = 125 milliliters per hour

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Answer: 560 metres.

Step-by-step explanation:  Here’s a step-by-step explanation of how to convert 0.56 kilometres into metres:

1. Start with the value in kilometres: 0.56 km

2. Know that there are 1000 metres in a kilometre.

3. Multiply the value in kilometres by the conversion factor (1000 m/km): 0.56 km x 1000 m/km = 560 m

4. The result is the value in metres: 560 m

So, 0.56 kilometres is equal to 560 metres.

The like radicals are 3x√x²y and x√yx², and the answer is:

3x√x²y, -2x√xy³², x√yx²,  2√xy

An expression is a combination of numbers, variables, and mathematical operations, such as addition, subtraction, multiplication, and division. It does not have an equal sign and can be simplified or evaluated by applying the appropriate rules of arithmetic.

According to the given information:

The like radicals have the same radicand (expression under the radical sign) and the same index (the number outside the radical sign). Checking each expression:

Therefore, the like radicals are 3x√x²y and x√yx², and the answer is:

3x√x²y, -2x√xy³², x√yx²,  2√xy

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The answer of the given question based on the rectangle is , The MNOP congruence is shown by  Side-Angle-Side (SAS) and the steps are given below.

In geometry, a diagonal is a straight line that connects two non-adjacent vertices of a polygon or a polyhedron. In other words, a diagonal is a line segment that joins two corners or vertices of a shape that are not next to each other. For example, in a rectangle, the diagonals are the line segments that connect opposite corners of the rectangle.

To show that the diagonals of a rectangle bisect each other and are congruent, we can use the following steps:

Therefore, we have shown that the diagonals of a rectangle bisect each other and are congruent.

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We have shown that the boundary of a generalized rectangle is the union of finitely many closed generalized rectangles with volume zero.

The internal angles of a rectangle, which has four sides, are all exactly 90 degrees. At each corner or vertex, the two sides come together at a straight angle. The rectangle differs from a square because its two opposite sides are of equal length.

Let A and B be two sets in a generalized rectangle R, i.e., R = A x B. The boundary of R, denoted by bd(R), is defined as the closure of the set of points that are not in the interior of R. In other words, bd(R) = cl(R) \ int(R), where cl(R) is the closure of R and int(R) is the interior of R.

To show that bd(R) is the union of finitely many closed generalized rectangles with volume zero, we first note that the closure of R can be expressed as the union of R and its boundary, i.e., cl(R) = R ∪ bd(R). Therefore, it suffices to show that R can be expressed as the union of finitely many closed generalized rectangles with volume zero and that bd(R) can also be expressed as the union of finitely many closed generalized rectangles with volume zero.

Let (a,b) be a point in R. Then there exists an open ball B((a,b), r) around (a,b) that is contained in R, where r > 0. Without loss of generality, we can assume that r is small enough so that B((a,b), r) is a generalized rectangle. Since B((a,b), r) is open, it follows that int(R) is the union of all such generalized rectangles. Therefore, R can be expressed as the union of finitely many closed generalized rectangles with volume zero, namely the closures of all such generalized rectangles.

Next, we show that bd(R) can be expressed as the union of finitely many closed generalized rectangles with volume zero. Let (a,b) be a point in bd(R). Then every open ball B((a,b), r) around (a,b) contains points both in R and in the complement of R. By definition of bd(R), the closure of B((a,b), r) intersects both R and the complement of R. Therefore, B((a,b), r) can be expressed as the union of two closed generalized rectangles, one contained in R and one contained in the complement of R. It follows that bd(R) can be expressed as the union of finitely many closed generalized rectangles with volume zero, namely the closures of all such balls B((a,b), r) and their decompositions into closed generalized rectangles.

Therefore, we have shown that the boundary of a generalized rectangle is the union of finitely many closed generalized rectangles with volume zero.

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The team that has the largest overall size hat for their players is the Falcons; they have a larger mean value of about 22 inches

In order to determine the average hat size per team, it is necessary to sum up each player's measurements and divide by the total number of players.

For the Pelicans: The combined sum equals 344.5, which results from adding up values such as 21.5, 25, 22, 24, and so on. With a team membership of 15 people, their mean measures out to approximately 22.97 inches.

The Falcon's equivalent calculation yields a total of 330 attained from summing head sizes, including those measuring 20, 23.5, 21, etc., with an equal number of members, coming close to an average measure of 22 inches thick.

As a result, comparisons between both teams reveal that the Falcons possess the larger collective hat size averages at roughly 22 inches in thickness.

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using trignometric ratio of sine thee measure of the angle x to the nearest degree is 28 degrees

Trigonometric ratios are ratios of the sides of a right triangle, such as sine, cosine, and tangent, that are used to find missing side lengths or angles.

An angle is a geometric figure formed by two rays or line segments that share a common endpoint, known as the vertex. It is typically measured in degrees or radians.

According the given information:

We can use the trigonometric ratio of sine to find the measure of the angle x.

sin(x) = opposite/hypotenuse

In this case, the opposite side is the height of the triangle, which is 13, and the hypotenuse is the length of the diagonal line connecting the base and the top of the triangle. We can use the Pythagorean theorem to find the length of the hypotenuse.

hypotenuse² = base² + height²

hypotenuse² = 22² + 13²

hypotenuse² = 769

hypotenuse ≈ 27.73

Now we can substitute the values into the sine ratio:

sin(x) = 13/27.73

x ≈ 28 degrees

Therefore, the measure of the angle x to the nearest degree is 28 degrees.

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Answer:

1. is (18,4)

2. is (8,10)

3. (-9,-8)

4. (9,-8)

Step-by-step explanation:

i promise its right please give brainliest

Answer:

B

Step-by-step explanation:

the equation y=3/2x-3 has a slope of 3/2 and a y intercept of -3

So, first find the graph(s) that have the y intercept of -3.  The only options would be B and C.

Next, from the y-intercept of -3, go UP 3, and to the RIGHT 2 to find your next point.  This eliminates option C for the slope.  The slope of option C is 2/3, not 3/2.

So, option B is correct.  Hope this helps ;)

Answer:

B

Step-by-step explanation:

y = mx + b

y = mx (slope) + b (y-intercept)

The y-intercept of y = 3/2x - 3 is -3, so the graph needs to have a point at (0, -3). The slope is 3/2, if you go up 3 times and to the right twice from the point (0, -3), it will point (2, 0).

The measure of angle ABP from the given circle is 90°.

From the given figure,

11) Measure of angle ABP is 90°.

12) Measure of angle BAK is 180°-(90°+25°)

= 180°-115°

= 65°

13) Measure of angle AQP is 90°.

14) Measure of angle QAK is 180°-(90°+25°) (Because ∠BPA=∠QPA=25°)

15) Measure of Arc BK = Measure of angle BAK = 65°

16) Measure of Arc BQ = Measure of angle BAQ = 65°×2

= 130°

17) m∠CAD=m∠BAK=65°

Therefore, the measure of angle ABP from the given circle is 90°.

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Answer:

7x + 13

Step-by-step explanation:

because the correct answer is 7x+13

The answers are:

1) The area of a triangle is given by the formula A = (1/2)bh, where b is the base and h is the height. For the given triangles:

Triangle 1: A = (1/2)(2ft)(4ft) = 4 sq ft (for one tablecloth), so for two tablecloths, the total area is 8 sq ft.

Triangle 2: A = (1/2)(6ft)(10ft) = 30 sq ft, so for two tablecloths, the total area is 60 sq ft.

Triangle 3: A = (1/2)(12m)(15m) = 90 sq m, so for two tablecloths, the total area is 180 sq m.

2) The area of a parallelogram is given by the formula A = Bh, where B is the base and h is the height. Rearranging this formula, we get h = A/B. For the given parallelogram:

A = 78 mm2 and B = 13 mm, so h = 78/13 = 6 mm.

3) The area of a rectangle is given by the formula A = LW, where L is the length and W is the width. For Charles' den:

The total wall space to be painted is (2 x 9 x 15) + (2 x 8 x 10) = 342 sq ft. One gallon of paint covers 440 sq ft, so Charles needs (342/440) = 0.7778 gallons of paint. Therefore, he does not have enough paint.

4) To calculate the total area of the walls to be painted, we can calculate the area of each wall and add them together.

The area of the two walls that are 9 ft high and 15 ft long is (9 x 15) = 135 sq ft each, for a total of 270 sq ft. The area of the other two walls that are 8 ft high and 10 ft long is (8 x 10) = 80 sq ft each, for a total of 160 sq ft. Adding them together, we get a total of 430 sq ft.

Since one gallon of paint covers 440 sq ft of wall space, Charles has enough paint to cover the den walls.

5) The area of a trapezoid is given by the formula A = (1/2)(b1 + b2)h, where b1 and b2 are the bases and h is the height. Rearranging this formula, we get h = 2A/(b1 + b2). For the given trapezoids:

A = (1/2)(6ft + 7ft)(10ft) = 65 sq ft and h = 2(65)/(6ft + 7ft) = 5 ft.

A = (1/2)(5yds + 8yds)(4yds) = 26 sq yds and h = 2(26)/(5yds + 8yds) = 2 sq yds.

A = (1/2)(9in + 11in)(13in) = 143.5 sq in and h = 2(143.5)/(9in + 11in) = 13.05 in.

For the application in part (d), we are given A = 32 km2 and (b1 + b2) = 16 km.

Rearranging the formula for A, we get h = 2A/(b1 + b2). Substituting the given values, we get h = 4

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Answer:

(d + 1) (2d + 9)

Step-by-step explanation:

2d² + 11d + 9

First, we rewrite 11d as 2d + 9d, we have the equation:

2d² + 2d + 9d + 9

We group them, so the equation will be

(2d² + 2d) + (9d + 9)

Factor out the GCF of each group

2d (d + 1) + 9 (d + 1)

Factor the polynomial by factoring out the greatest common factor, d+1

(d + 1) (2d + 9)

So, the answer is (d + 1) (2d + 9)

The two fractions with denominators of 2 and 6 that add up to 19/3 are 3/6 and 29/3, respectively.

First, let's break down what that mixed number means in terms of fractions. 6 1/3 is the same as 19/3.

Now, we need to find two fractions with different denominators that add up to 19/3. One way to do this is to use a common denominator. To find a common denominator, we need to find the least common multiple (LCM) of the two denominators.

Let's say we want to find two fractions that add up to 19/3, with denominators of 2 and 6. The LCM of 2 and 6 is 6. So, we can rewrite the fractions with a denominator of 6:

1/2 = 3/6

x/6

Now we need to find the value of x that makes the sum of the fractions equal to 19/3:

3/6 + x/6 = 19/3

To solve for x, we can multiply both sides by 6:

3 + x = 38/3

Then, we can subtract 3 from both sides:

x = 29/3

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The difference between the high and low prices on October 20 is $3.33  

On October 27, the actual volume of discovery group shares posted is 2360000

The price that Discovery group clothes on October 19 is $36.94

The difference in the prices as a percent increase is 0.76%

The number change from October 20 to October 21 as a percent rounded to the nearest tenth of a percentage is -16.9%

The net change from October 27 to October 28 as a percent, rounded to the nearest tenth of a percent is 14.8%

The reason why 52 week high and 52 week low numbers are the same in both charts is that there was no price higher than $76.19 or lower than $22.78 for those weeks.

The closing price one year earlier is $54.60

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Answer:

Mrs. Ades is not being fair. The probability of Elias and Maha getting chosen should be equal, but Elias has a 6/10 chance of being chosen, while Maha only has a 4/10 chance of being chosen. This is because Elias has 6 tiles assigned to him, while Maha only has 4 tiles assigned to her.

Explanation:

To make it fair, Mrs. Ades should assign each person an equal number of tiles, or draw from a bag with the tiles numbered 1 through 5 twice, assigning one to Elias and one to Maha each time, and then draw from a bag with tiles numbered 6 through 10 twice, assigning one to Elias and one to Maha each time.

On average, the number of cars on the busy road increases by 25 cars per hour from midnight to 12:00pm

The average rate of change of a function from x=a to x=b is given by the formula:

average rate of change = (f(b) - f(a)) / (b - a)

Using this formula, we can calculate the average rate of change of the function f(x) from x=0 to x=12 as follows:

average rate of change = (f(12) - f(0)) / (12 - 0)

Where

f(0) = 0 and f(12) = 300 -- from the graph

So, we have

Rate = (300 - 0) / 12

Rate = 25

Therefore, the approximate average rate of change of the function from x=0 to x=12 is 25 cars per hour.

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Answer:

either or

2,4 or 4,2

4,8 or 8,4

6,12 or 12,6

8,16 or 16,8

Step-by-step explanation:

if u tell me which one is x and would help even more good luck

In probability theory, an event is any collection of outcomes or results from a probability experiment. option a) is correct event

It represents a particular occurrence or set of occurrences that we are interested in studying or analyzing. A sample space (option b) is the set of all possible outcomes in a probability experiment. An outcome (option c) is a particular result of a single trial of a probability experiment. An experiment (option d) refers to the process of conducting a trial or series of trials to observe the outcomes and collect data for analysis in probability theory. Therefore, the correct answer is option a) event.

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Complete Question

A(n) _______ is any collection of outcomes from a probability experiment.

a) event

b) sample space

c) outcome

d) experiment

To summarize, an outcome is a result of an experiment, a sample space is a collection of all possible outcomes, an event is a set of outcomes chosen from the sample space, and a collection is a group of events with a common property.

An experiment in probability refers to a process of observing or measuring some phenomenon, where the outcomes are uncertain. The collection of all possible outcomes from this experiment is known as the sample space. An outcome is a particular result that occurs as a result of the experiment.

Now, a set of outcomes chosen from the sample space is known as an event. An event can be as simple as a single outcome or as complex as a combination of outcomes. For example, flipping a coin and getting heads is a simple event, while flipping a coin and getting heads or rolling a dice and getting an even number is a compound event.

Finally, a collection of events is simply a group of events that share a common characteristic or property. In probability, we use collections of events to determine the likelihood of certain outcomes occurring. This allows us to make predictions about the experiment based on the available data.

So, to summarize, an outcome is a result of an experiment, a sample space is a collection of all possible outcomes, an event is a set of outcomes chosen from the sample space, and a collection is a group of events with a common property.

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Nathan needs 24 cups of water to make his lemonade recipe.

Let's call the amount of lemon juice Nathan uses "x".

We know that Nathan uses 3 cups of lemon juice, so we can substitute x = 3 into the problem.

According to the recipe, the amount of sugar Nathan needs is twice the amount of lemon juice, so he needs 2x cups of sugar.

Substituting x = 3, we get that Nathan needs 2(3) = 6 cups of sugar.

The amount of water Nathan needs is four times the amount of sugar he needs, so he needs 4 times 6 cups of water, which is equal to 24 cups of water.

Therefore, Nathan needs 24 cups of water to make his lemonade recipe.

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55% of the claims are within one standard deviation of the mean claim size.

To find the percentage of claims that are within one standard deviation of the mean claim size, we first need to calculate the mean and standard deviation of the distribution.

The mean claim size is:

u = (20 × 0.10) + (30 × 0.10) + (40 × 0.10) + (50 × 0.20) + (60 × 0.15) + (70 × 0.10) + (80 × 0.25) = 54

The variance can be calculated as follows:

s^2 = [[tex](20-54)^{2}[/tex] × 0.10] + [[tex](30-54)^{2}[/tex] × 0.10] + [[tex](40-54)^{2}[/tex] × 0.10] + [[tex](50-54)^{2}[/tex] × 0.20] + [[tex](60-54)^{2}[/tex] × 0.15] + [[tex](70-54)^{2}[/tex] × 0.10] + [[tex](80-54)^{2}[/tex] × 0.25] = 340

The standard deviation is the square root of the variance:

s = √340 ≈ 18.44

To find the percentage of claims that are within one standard deviation of the mean claim size, we need to find the range of claim sizes that fall within the interval (u - s, u + s).

(u - s) = 54 - 18.44 = 35.56

(u + s) = 54 + 18.44 = 72.44

We can see from the table that the claim sizes 40, 50, 60, and 70 fall within this range, and their probabilities add up to:

0.10 + 0.20 + 0.15 + 0.10 = 0.55

Therefore, 55 percentage of the claims are within one standard deviation of the mean claim size.

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If a group of friends wanted to rent a cabin for the fourth of July. The number of  friends that were originally in the group is 8.

Let x represent the number of friends in the group

Cost per person =960/x

After   the 4 friends dropped out the remaining number of friends was = x - 4

New cost per person =960/x + 120

New total cost of the cabin rental = (x - 4) * (960/x + 120)

Set the two expressions equal to each other

960 = (x - 4) * (960/x + 120)

960 = 960 - (3840/x) + 120(x - 4)

Simplifying

3840/x = 120x - 480

Multiplying both sides by x

3840 = 120x^2 - 480x

Rearranging

120x^2 - 480x - 3840 = 0

Dividing both sides by 120

x^2 - 4x - 32 = 0

Quadratic equation

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where:

a = 1, b = -4, and c = -32.

Plugin the formula

x = (4 ± √(16 + 128)) / 2

x = (4 ± √(144)) / 2

x = (4 ± 12) / 2

x = 8 or x = -4

Therefore the number of friends  is 8.

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The median nerve and Klumpke's palsy are both related to nerve injuries in the arm, but they involve different nerve pathways and result in different symptoms.

The median nerve runs from the brachial plexus in the neck through the arm to the hand, and controls movement and sensation in the thumb, index, middle, and part of the ring fingers. Damage to the median nerve can result in symptoms such as weakness, numbness, and tingling in these fingers, as well as muscle wasting in the thumb.

Klumpke's palsy, on the other hand, involves damage to the lower brachial plexus nerves, specifically the C7, C8, and T1 nerve roots. This can result in weakness or paralysis in the hand and wrist, with symptoms such as a claw-like deformity, decreased grip strength, and loss of sensation in the affected areas.

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On average, you can expect to get about 4.24 points per game if you play many times.

To find the average number of points you can get by playing the game many times, you can use the expected value as a guide.

The expected value of the game is calculated as follows:

(20 points x probability of getting 20) + (10 points x probability of getting 10) + (2 points x probability of getting 2) = 5.6

Let's use the variables p20, p10, and p2 to represent the probabilities of getting 20 points, 10 points, and 2 points, respectively. Then we can set up the equation:

(20p20) + (10p10) + (2p2) = 5.6

We also know that the sum of the probabilities must equal 1:

p20 + p10 + p2 = 1

Now we have two equations and three variables. We need one more equation to solve for the variables. One way to do this is to assume that the probabilities of getting 20 points, 10 points, and 2 points are proportional to the point values themselves.

In other words, let's assume that:

p20 : p10 : p2 = 20 : 10 : 2

We can then use this proportion to write p20 and p2 in terms of p10:

p20 = 2p10

p2 = 4p10

Now we can substitute these expressions into the two equations we have:

(20p20) + (10p10) + (2p2) = 5.6

p20 + p10 + p2 = 1

Substituting the first equation gives:

(20(2p10)) + (10p10) + (2(4p10)) = 5.6

Simplifying:

80p10 + 10p10 = 5.6

90p10 = 5.6

p10 = 5.6/90

p10 = 0.062

Now we can use the proportions to find p20 and p2:

p20 = 2p10 = 2(0.062) = 0.124

p2 = 4p10 = 4(0.062) = 0.248

Finally, we can calculate the average number of points:

(20 points x 0.124) + (10 points x 0.062) + (2 points x 0.248) = 3.12 + 0.62 + 0.496 = 4.236

So, on average, you can expect to get about 4.24 points per game if you play many times.

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The surface area of the rectangular pyramid is 75 m².

Surface area is the sum of all the surfaces on each side of a three-dimensional shape.

To calculate the surface area of the rectangular pyramid, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equaation 1

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