Determine the launch speed of a horizontally launched projectile that lands 26.3m from the base of a 19.3m high cliff
The launch speed of a horizontally launched projectile is 13.28 m/s.
Time of motion of the projectile
The time of motion is calculated as follows;
t = √(2h / g)
where;
h is height of the cliffg is acceleration due to gravityt = √(2 x 19.3 / 9.8)
t = 1.98 s
Launch speed of the projectileX = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
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Suppose a 65.5 kg gymnast climbs a rope. What is the tension in the rope if she climbs at a constant speed
The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.
Given:
Mass of gymnast, m = 65.5 kg
The speed 'v' of gymnast is constant
Solution:
Consider the free-body diagram of the system as shown below.
Balancing forces along the vertical axis we get:
ΣFy = 0
Thus, we get:
F = ma - (1)
where, m is mass of gymnast
a is acceleration of gymnast (a = 0m/s², as the speed is constant)
Also,
F = T - mg -(2)
where, T is tension in the rope
g is acceleration due to gravity
Equating (1) & (2), we get:
ma = T - mg
Re-arranging the equation, we get:
T = m(a+g)
Applying values in above equation we get:
T = (65.5 kg)(0 m/s²+9.8 m/s²)
T = 641.9 N
Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.
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In creating an accurate scale model of our solar system, Lana placed Earth 1 foot from the Sun. The actual distance from Earth to the Sun is 93,000,000 miles. If the actual distance from Pluto to the Sun is 3,695,950,000 miles, how far from the Sun would Lana need to place Pluto in her model
Pluto would be placed 39.74 feet far from the Sun.
Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.
Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.
The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.
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A constant 20N force is applied to a 7kg box to push it along the ground. How much work is done by this force if the box moves 2m?
Answer:
40 J
Explanation:
W = (f)(d)
W = (20)(2)
W = 40 J
If a constant 20 N force is applied to a 7 kg box to push it along the ground , then the work is done by this force if the box moves 2 meters would be 40 Newton meters.
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance .
As given in the problem if a constant 20 N force is applied to a 7 kg box to push it along the ground, then we have to find out the work is done by this force if the box moves 2 meters ,
The work done by the force to push the box = 20 × 2
=40 Newton meters
Thus, the work is done by this force if the box moves 2 meters would be 40 Newton meters.
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Tommy is awake during a procedure involving his brain his doctor has a test and electrical part of his brain and stimulating it every time she does so tommy start singing showtunes what is the procedure an example of
Repetitive Transcranial Magnetic Stimulation (TMS) is the procedure that is being performed on Tommy, while he is awake.
What is Transcranial Magnetic Stimulation?
Transcranial magnetic stimulation (TMS) is a non-invasive method for mood control. It does not require the patient to be sedated and is usually performed on completely conscious patients.
In this procedure, the nerve cells are stimulated by magnetic pulses by placing electromagnetic coils against the scalp of the patient. The patient is then stimulated repetitively which is why it is known as repetitive TMS.Tommy sings during the procedure because the region of the brain responsible for memory and singing is stimulated by this procedure.
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A 12.5 g clothesline is stretched with a tension of 22.1 n between two poles 7.66 m apart. the frequency of the fundamental and the second harmonic are 7.60 hz and 15.2 hz respectively.
(a) Fundamental frequency of clothesline is 6.98Hz.
(b) Frequency of second harmonic is 13.98Hz.
The wave velocity expression is,
v = √T / √μ
here, T is tension μ is mass per unit length
v = √22.1 / √(12.5×10⁻³/7.66)
v = 116.37 m/s
For the fundamental frequency,
v = fλ
116.37 m/s= 7.6 ×λ
λ = 15.31 m
For the second Harmonic,
λ₂= v/ f₂ = 116.37 / 15.2 = 7.66 m
Now consider mass is increased
μ= 14.8 × 10⁻³ / 7.66
v = √T / √μ
v = √22.1 / √14.80 × 10⁻³/7.66
v = 106.95 m/s
Fundamental harmonic,
f₁ = v/λ₁ = 106.95 / 15.31 = 6.98 Hz
f₂= v/ λ₂ = 106.95 / 7.65 = 13.98 Hz
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[Your question is incomplete, but most probably your full question was-
a) What is the frequency of the fundamental harmonic for a clothesline with a mass of 14.8 g?
(b) What is the frequency of the second harmonic for a clothesline with a mass of 14.8 g?]
Which characteristic is most associated with egalitarian societies?
O Women perform a lot of the domestic labor.
Women have responsibility for child care.
Women have access to education.
O Work is highly segregated by sex.
Answer:
a woman who have responsibility of child care
Explanation:
egalitarian is one who supports equality
The characteristic that is most associated with egalitarian societies is Women have responsibility for child care.
What is society?A society is a bunch of individuals that frequently contact with one another or a significant social group that inhabits the same physical or social area and is typically under the control of the same leadership and prevailing cultural expectations. A given society may be defined as the sum of all of these interactions among its constituent members.
Society is characterized by patterns of interaction (social relations) between people who share a certain culture and institutions. In the social scientists, subgroup dominance or stratification patterns commonly occur in bigger societies. By defining certain behaviors or ideas as acceptable or unacceptable, societies create patterns of behavior. The phrase "societal norms" relates to such behavioral patterns within a particular community. Societies and their standards are continuously and changing slowly.
What is women?Women typically inherit a pair of X - chromosome from their parents, which allows them to get pregnant and give birth from adolescence until menopause. More specifically, the sex determination of the female embryo is controlled by the lack of a present or active on either of the respective s-ex chromosomes. Female anatomy differs from male anatomy due to the female reproductive system, which consists of the ovaries, ut-erus, v-agina, and vulva. A lady is a grown-up female. Before being an adult, a woman is referred to as a girl (a female child or adolescent).
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A box weighing 660 N is sliding across a cement floor and the coefficient of sliding
friction between the box and the floor is 0.15. What is the frictional force?
09g
O 4,400 N
0 99 N
O 99 kg
The Frictional force is 99 N; option C.
What is the frictional force?The frictional force between the floor and the surface is calculated as follows:
Frictional force = coefficient of friction * normal reaction
Frictional force = 660 * 0.15
Frictional force = 99 N
In conclusion, the frictional force is determined from the coefficient of friction and the normal reaction of the box on the floor.
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An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. it flies up to its nest in a tree at a height of 25 m. how much gravitational potential energy did the eagle gain? 221 j 882 j 1103 j 1323 j
882J of gravitational potential energy is gained by the eagle.
Here, we have been provided with data-
mass, m = 4.5 kg
height, h = 25 m
We have to find the gravitational potential energy.
In the question, it is given that the eagle is at a height of 5m and it flies from there 20 m more to reach its nest.
So, gravitational potential energy is given as
P.E = m x g x h
P.E = 4.5 × 9.8 × 20
P.E = 882J
Thus, the correct option is (b).
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Answer:
b
Explanation:
its b
What is the velocity ratio of the inclined plane h 9 L 12 hypothesis 15 bellow? A. 1.25 B. 0.60 C. 1.67 D. 0.80
B is the answer
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do banked curves help car make turns more softly
Answer:
yes
Explanation:
banked curve :
is a road that looks like the top part of a race track
its looks elevated
often seen in bicycle race track (velodrome)
Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.
sfuca
3
its out
n
A mom walks into her child's room and finds clothes all over the floor. 20% of the clothes are
clean. She randomly picks up 5 articles of clothing.
1. We can expect 1
2. The standard deviation is 25
3. Because the distribution has a
r
O
5
, the distribution is close to skewed right (positive)
✔
n-
4. Use the probability formula P(r) =n Crp'q" to create a binomial distribution table.
Probability formula
Round to the tenth, if necessary.
6
✔ CO
Dirty Room
out of 5
articles of clothing to be clean.
x. (Round to the nearest tenth, if necessary.)
probability of success (P(S)) that is
5
✓.2 ✓
0
small (closer to 0)
P(r)
Enter the probability only.
Round to the 4th decimal place, if
necessary.
.6
?
The probability computed shows that we can expect 1 out of 5 clothes to be clean.
How to calculate the probability?From the information given, it was stated that 20% of the clothes are clean. Therefore, the probability of clean clothes will be:
= 20% = 1/5.
Therefore, one out fo five clothes are clean.
The standard deviation will be:
= ✓npq
where,
n = 5
p = 0.20
q = 1 - 0.20 = 0.80
SD = ✓(5 × 0.20 × 0.80)
= ✓0.80
= 0.09
The distribution is close to symmetric.
The binomial distribution table will be:
0 = (0.20)^0 (0.80)^5 = 0.3277
1 = (0.20)¹ (0.80)⁴ = 0.4096
2 = (0.20)² (0.80)³ = 0.2040
3 = (0.20)³ (0.80)² = 0.0512
4 = (0.20)⁴ (0.80)¹ = 0064
5 = (0.20)^5 (0.80)^0 = 0.0003
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Astronomers cannot use parallax to find the distance to most stars. This is because the stars are Choose one: A. too small. B. too close. C. moving too fast. D. too far away.
Answer:
B
Explanation:
Astronomers cannot use parallax to find the distance to most stars. This is because the stars are: B too close.
The density of a block of wood is 2.7 g/cm³ and a mass of 583.3 g. What is its volume?
A lump of butter has a volume of 350 cm³ and a mass of 319 g. What is the density of the butter?
Answer:
1) To find the volume of the wood block, divide the mass by the density:
Volume = 583.3 g / 2.7 g/cm³
Volume = 216.24 cm³
2) To find the density of the butter, divide the mass by the volume:
Density = 319 g / 350 cm³
Density = 0.9114 g/cm³
Explanation:
0. If heavy stone and cotton having same masses are dropped from certain height on the surface of the earth. Explain the results according to the presence and obsence of air resistance. V 0. If heavy stone and cotton having same masses are dropped from certain height on the surface of the earth . Explain the results according to the presence and ab
sence of air resistance .
The cotton will fall slower than the heavy stone of same mass because of the density of the substances, which affects air resistance.
What is air resistance?Air resistance is the action of friction that slows something moving through air.
It is worthy to note the air resistance is not dependent on the mass of an object but on the velocity and density of that object.
According to this question, a heavy stone and a cotton having same masses are dropped from certain height on the surface of the Earth.
Based on difference in densities, the cotton will fall slower than the heavy stone because the density of the stone is greater.
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A 10 N force and a 15 N force are acting from a single point in opposite directions. What additional force must be added to produce equilibrium?
Group of answer choices
A) A 5 N force acting in the same direction as the 10 N force.
B) A 10 N force acting in the same direction as the 15 N force.
C) A 25 N force acting in the direction perpendicular to the 10 N and 15 N forces.
D) A 5 N force acting in the same direction as the 15 N force.
The additional force must be added to produce equilibrium is 5 N force acting in the same direction as the 10 N force (Option A)
Data obtained from the questionForce to the left = 10 NForce to the right = 15 NAdditional force =?How to determine the additional forceTo have equilibrium,
Force to the left = force to the right
But
The force to the right is greater than the force to the left.
Thus,
Force to the left + additional force = force to the right
10 + additional force = 15 N
Collect like terms
Additional force = 15 - 10
Additional force = 5 N
Therefore, an additional force of 5 N acting in the same direction of the 10 N force is needed to obtain the equilibrium of the system (Option A)
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Most interstellar clouds are: Most interstellar clouds are: much bigger than our solar system. similar in size to clouds in Earth's atmosphere. about the size of Earth. about the size of a wavelength of light. much smaller than the clouds in Earth's atmosphere.
Answer:
Most interstellar clouds are much bigger than our solar system.
Explanation:
An interstellar cloud refers:
It is generally an accumulation of gas, plasma, and dust in our and other galaxies. It is basically a denser-than-average region of the interstellar medium (ISM).Interstellar clouds can be large up to 106 solar masses
It is also often said to be the most massive entities in the galaxy.
Hence
we can say about Interstellar clouds,
They are much bigger than our solar system.
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Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Use the drop-down
menus to complete the statements.
The independent variables in Part I, the ones intentionally manipulated, are the
The independent variable in Part II, the one that is intentionally manipulated, is the [
The dependent variable for both Parts I and II, the one that you measure the response in, is the
The complete statements are;
In Part I ---> mass & type of materialIn Part I ----> type of materialIn Part I----> temperatureThis is further explained below.
What is reflection?Generally, reflection is seen when light, heat, or sound that is reflected back by an object or surface rather than absorbed by it.
In conclusion, The full statements are as follows: Part I: Mass and Material Type For the first section, please refer to the following categories of content: To begin, let's talk about the temperature, as discussed in Part I.
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Answer:
The independent variables in Part I, the ones intentionally manipulated, are the
✔ mass and type of material
.
The independent variable in Part II, the one that is intentionally manipulated, is the
✔ type of material
.
The dependent variable for both Parts I and II, the one that you measure the response in, is the
✔ temperature
got right in edge 2022
Some of the lowest pitches attainable on a musical instrument are achieved on the world's largest pipe organs. What is the length of an organ pipe that is open on both ends and has a fundamental frequency of 8.75 Hz when the speed of sound in air is 341 m/s
The length of an organ pipe is 19.48
Given,
An organ pipe that is open on both ends and has a fundamental frequency of n1 = 8.75Hz & the speed of sound in air is v = 341m/s
we have the formula for fundamental frequency in open pipe as
n1 = v /λ1 = v / 2L
so L = v / 2n1
plug in the values for L
n1 = v / λ1 = v / 2L
L = v / 2n1
= 341 / 2 (8.75)
= 19.48
The length of an organ pipe is 19.48
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When sound waves superimpose they can interfere?
Answer:
Explanation:
When two waves of similar frequency arrive at the same point and superimpose, they alternately constructively and destructively interfere. This alternating is known as a beat because it produces an unpleasant pulsing sound
Which of the following statements are true about a mass rotating around a string? Select all that apply.
Group of answer choices
A. If you cut the string as the ball is in motion, the ball will continue to move in uniform circular motion due to the centripetal force.
b. The acceleration and velocity vectors on the mass will always be perpendicular to each other.
c. Since the linear speed of the rotating mass is constant, the kinetic energy of the mass is also constant.
d. The acceleration and centripetal force vectors will always be directed inward, towards the center of the arc.
Answer:
Only (C) and (D) are true
a = (v2 - v1) / t since a and v are vector quantities they have the same direction
Also KE = 1/2 M v^2 describes the linear KE of an object moving with a speed of v
Also KE = F * S where S is the displacement - the radius vector is a constant for an object moving in a circle and the centripetal force provides no change in KE
Danny Diver weighs 500 N and steps off a diving board 10 m above the water. Danny hits the water with kinetic energy of
Answer:
Danny hits the water with kinetic energy of 5000 J.
Explanation:
Given that,
The Weight of Danny Diver,
F = 500 N
m*g= 500 N
He steps off a diving board 10 m above the water.
h=10 m
when Danny diver hits water he generates the kinetic energy.
We need to find the kinetic energy of the water.
Let kinetic energy is K.
K = m*g*h
Where g is acceleration due to gravity.
that g= 9.8 m/s^2
now substituting the values in above equation
K= (500) * 10
K= 5000 J
Hence,
he hits the water with kinetic energy of 5000 J.
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i dont understand pojectile motion can someone help with this
When thrown from the balloon, the sandbag has a constant horizontal/forward velocity. As the text puts it, "the sandbag continues forward as if it had not been dropped." What this means is that the sandbag has no acceleration in the horizontal plane of motion, so it moves in this direction at a constant speed. So for any time [tex]t[/tex], the horizontal velocity is given by
[tex]v_x(t) = 12\dfrac{\rm m}{\rm s}[/tex]
In the vertical plane of motion, the sandbag has no vertical velocity until it's released and allowed to fall. As it's falling, however, the sandbag is being pulled down by gravity and is accelerating with magnitude [tex]g=9.8\frac{\rm m}{\mathrm s^2}[/tex], so its vertical/downward velocity at time [tex]t[/tex] is given by
[tex]v_y(t) = -gt[/tex]
So, after 3 seconds have passed, the sandbag has horizontal velocity [tex]v_x = 12\frac{\rm m}{\rm s}[/tex] and vertical velocity [tex]v_y = -g(3\,\mathrm s) = -29.4\frac{\rm m}{\rm s}[/tex]. If the question is specifically asking about speed you would just ignore the negative signs.
A diagnostic test involving recording the electrical activity within muscle fibers in response to nerve stimulation is known as.
Electromyography (EMG) measures muscle response or electrical activity in response to a nerve's stimulation of the muscle. The test is used to help detect neuromuscular abnormalities.
Electromyography (EMG) :
(EMG) detects the electrical activity that occurs when a muscle is stimulated by a nerve. The test is used to identify aberrant neuromuscular function. One or more tiny needles, commonly known as electrodes, are introduced through the skin and into the muscle during the test. An oscilloscope is then used to display the electrical activity that the electrodes picked up (a monitor that displays electrical activity in the form of waves). In order to hear the activity, an audio amplifier is employed. The electrical activity of muscles during rest, a light contraction, and a strong contraction is measured by EMG. At rest, muscle tissue doesn't typically create any electrical signals. A brief period of activity can be seen on the oscilloscope when an electrode is introduced, but there should be no signal beyond that.
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A dipole with its charges,-q and +q located at the points (0,-b,0) and (0+b,0) is present in uniform electric field E whose equipotential surfaces are planes parallel to the YZ planes.
The direction of the electric field based on the information given about the dipole is along the x axis.
What is a dipole?It should be noted that a dipole simply means a pair of opposite charges that are separated by a distance.
By default, the direction of the dipole is always from the negative charge -q to the positive charge q.
In this case, since the equipotential surfaces are planes parallel to the YZ planes., the direction of the electric field is along the x axis.
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Complete question:
A dipole with its charges,-q and +q located at the points (0,-b,0) and (0+b,0) is present in uniform electric field E whose equipotential surfaces are planes parallel to the YZ planes.
What is the direction of the electric field?
How much water will flow in 30 secs through 200 mm of capillary tube of 1.50 mm in diameter, if the pressure difference across the tube is 6660N/m² and viscosity is 8.01x10 kg/ms
The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as
[tex]Qo=1.6 \times 10^{2} \mathrm{~mL}[/tex]
What is the water outflow in 30 secs through 200 mm of the capillary tube?[tex]\begin{aligned}\Delta P &=6660 \mathrm{~m} / \mathrm{m}^{2} \\\mu &=8.01 \times 10^{-4} \text { Pas } \\t &=30 \mathrm{~s} \\L &=200 \mathrm{~mm}=200 \times 10^{-3} \mathrm{~m} \\D &=1.5 \mathrm{~mm}=1.5 \times 10^{-3} \mathrm{~m} \Rightarrow \gamma=\frac{1.5 \times 10^{-3}}{2} \mathrm{~m}\end{aligned}[/tex]
Generally, the equation for Rate of flow of Liquid is mathematically given as
[tex]\\$$Q=\frac{\pi r^{4} \times \Delta P}{8 \mu L}[/tex]
$$
Where dP is pressure difference r is the radius
[tex]\mu[/tex] is the viscosity of water
L is the length of the pipe
[tex]Q=\frac{\pi \times\left(\frac{1.5 \times 10^{-3}}{2}\right)^{4} \times 6660}{8 \times 8.01 \times 10^{-4} \times 200 \times 10^{-3}}[/tex]
[tex]Q=5.2 \mathrm{~mL} / \mathrm{s}[/tex]
In $30s the quantity that flows out of the tube
[tex]&Qo=5.2 \times 30 \\&Qo=1.6 \times 10^{2} \mathrm{~mL}[/tex]
In conclusion, the quantity that flows out of the tube
[tex]Qo=1.6 \times 10^{2} \mathrm{~mL}[/tex]
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In a certain material there is a current of 18 A flowing through a surface to the right, and there is an equal amount of positive and negative charge passing through the surface producing the current. How much negative charge passes through the surface
The negative charge passes through the surface is 9 A/s
The Intrinsic property of protons and electrons are known as Electric Charge
Protons are known as positive charge
Electrons are known as negative charge
Give that
I =18A
The current is flowing to the right
The equal amount of positive and negative charges.
that is total charge is q= Q+Q=2Q. that is magnitude
Then, the rate of charge that pass though is dq/dt
Give that,
q=it
2Q=it
Let differentiate with respect to t
2dQ/dt=I
Then, dQ/dt=i/2
Since I=18A
Then, dQ/dt=18/2
dQ/dt= 9 A/s. Toward the left
9 A/s negative charge passes through the surface .
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Make a list of nutrients found in packed items and amount of nutrient present in them
EXAMPLE IS SHOWN IN PIC
If any one will answer this correctly I will mark them as brainlist
Nutrients found in packed items include carbohydrates, fats and proteins and the amount of nutrients present in them is found in calories/grams.
What are macronutrients?Macronutrients are nutrients that contain calories that must be consumed in the diet to perform metabolic functions.
These macronutrients are specified in packed foods, and include proteins, carbohydrates and lipids.
Macronutrients provide 4 calories (proteins and carbohydrates) or 9 calories per gram (fats).
In conclusion, nutrients include carbohydrates, fats (lipids) and proteins and their proportions are expressed in grams.
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A soapbox derby race car starts at rest at the top of a track that has a vertical drop of 15 m. The car is to be stopped at the end of the track by colliding with and compressing a spring. In order to avoid injury to the driver, the spring must be compressed to 3.0 m before the car stops. What should be the force constant of this spring
In order to avoid injury to driver, The force constant of this spring should be 73.82 N/m
Calculation of force constant to this spring:
Here
vertical drop is 15 m.
mass of the car, m= 113 kg
gravitational acceleration, g= -9.8 m/s^2
spring compression before car stops, x= 3.0 m
In order to avoid injury to the driver,
we need to use Hooke's law and Newton's second law:
F(net) = F(x)
m*a=-k*x
here a=g
k= -(m*g) / x
here k is force constant of this spring
substituting the values we get,
k = -(113* -9.8) / (15)
k = 73.8266 N/m
Hence, the force constant of this spring should be 73.82 N/m
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Newton’s laws of motion are an inherent part of our everyday life. Starting from the beginning of the day till the end, Newton’s laws find their applications in a number of activities we do.
1st
Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: Law 1. A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.
2nd
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
3rd
His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.
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