Answer:
it's
answer
is
chlorinesodium gives sodium a different texture
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What is the importance of the shape of a conical flask?
The shape allows the flask to be sealed with a bung for heating purposes, while also allowing a researcher the freedom to shake or stir the flask without spilling liquid.
Explanation:
Hope it helps you!!Find concentration of solution of 45g of glucose is dissolved in water to prepare 500g solution?
Answer:
9% solution by mass
Explanation:
If there is 500 gm of solution and 45 g of it is glucose then:
45/500 * 100% = 9 % solution
How many moles of hydrogen atoms are there in one mole of (NH4)PMo12O40?
Answers
4
3
1
12
7
Answer:
I don't think (NH4)PMo12O40 is written properly, but if it is, there are 4 moles of hydrogen atoms for every 1 mole of (NH4)PMo12O40
Explanation:
1 mole of (NH4)PMo12O40 has 6.02x10^23 molecules of (NH4)PMo12O40. Each molecule of (NH4)PMo12O40 has 4 hydrogen atoms. If the molecule is decomposed to just it's elements, there would be 4 moles of hydrogen atoms for every one mole of (NH4)PMo12O40.
The number of moles of hydrogen atoms in one mole of (NH₄)PMo₁₂O₄₀ is 4. Hence, option A is correct.
What are moles?Moles can be given as the mass of the compound to the molar mass.
Moles = Mass/Molar mass
The subscript to the H in the formula describes the number of hydrogen atom in a molecule.
Thus, 1 molecule of (NH₄)PMo₁₂O₄₀ contains 4 atoms of hydrogen.
1 mole = 6.023*10²³ molecules
1 molecule (NH₄)PMo₁₂O₄₀ = 4 hydrogen atoms
1 mole (NH₄)PMo₁₂O₄₀ = 6.023*10²³ * 4 hydrogen atoms
1 mole (NH₄)PMo₁₂O₄₀ = 4 moles of hydrogen atoms
Thus, the moles of hydrogen atoms present in 1 mole of (NH₄)PMo₁₂O₄₀ is 4. Hence option A is correct.
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Set up the math. But don’t do any of it. Just leave your answer as a math expression. Also be should you’re answering includes all the correct unit symbols.
Answer:
See below
Explanation:
9 m * 2.16 kg/ m = ___________ kg ( see how the 'm' cancels out?)
How can one tell if a reaction is a redox reaction?
a. spectator ions are present.
b. elements change phases.
c. a precipitate is formed.
d. electrons are gained and lost.
submit
Answer:
D.) electrons are gained and lost.
Explanation:
Redox reactions involve the change in oxidation states of the reactants. Oxidized molecules lose electrons whereas reduced molecules gain electrons. In redox reactions, the oxidation number of oxidized molecules decreases and increases in reduced molecules.
Pls help asap i will mark u brainlist
Answer:
not sure
Explanation:
Goo gle can help for sure lol that's what I do anyway good luck hope you get it right.
The chemical equation for a reaction is shown below.
2 NO2(g) → N2O4(g)
What is the standard free energy change (ΔGo) in this reaction at 298 K? (NOTE: At 298 K, ΔGfo for NO2 is 51.84 kJ/mol, and for N2O4 is 98.28 kJ/mol.)
The standard free energy change (∆Gº') is the energy released when the products are created from the reactants. The (∆Gº') at 298 K is -5.40kJ.
What is standard free energy change?The standard free energy change is given by the sum of the standard free energies of the products subtracted from the sum of the standard free energies of the reactants, given as,
ΔG = ∑nΔG°products − ∑mΔG°reactants
Given,
ΔG°(NO₂) = 51.84 kJ/mol
ΔG°(N₂O₄) = 98.28 kJ/mol
Substituting values:
ΔG = ∑nΔG°products − ∑mΔG°reactants
= ΔG°(N₂O₄) − 2ΔG°(NO₂)
= 98.28 − 2(51.84)
= - 5.4
Therefore, -5.40 kJ is the standard free energy.
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Lawrencium-262 has a half-life of 4 hr. How much of a 40 mg sample remains after 12 hours?
Answer:
5 mg
Explanation:
If one half life is 4 hours, then 3 half lives is 12 hours.
This means that the sample will decay to 1/8 of its original amount.
So, the answer is 40(1/8) = 5 mg.
Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively, ________.
Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively mannoses and xyloses.
What are cyclic hemiacetals?Cyclic hemiacetals are those molecules that contain both alcohol and a carbonyl group and can undergo an intramolecular reaction to form a cyclic hemiacetal.
Example of Cyclic hemiacetals are :
Mannoses: These are they type of Cyclic hemiacetals that contains Six-membered cyclic hemiacetals.Xyloses: These are they type of Cyclic hemiacetals that contains five-membered cyclic hemiacetals.Learn more about xyloses here:
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Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively, pyranoses and furanoses.
What are hemiacetals?Hemiacetals are chemical compounds containing hydrogen or organic substituents in their molecules and formed by aldehydes or ketones.
The chemical formula of these hemiacetals compounds may be depicted as RHC(OH)OR'.
In conclusion, six-membered and five cyclic hemiacetals are pyranoses and furanoses.
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An enzyme _____. An enzyme _____. can bind to nearly any molecule is an organic catalyst increases the the activation energy of a reaction is a inorganic catalyst is a source of energy for endergonic reactions
An enzyme is an organic catalyst that can bind to nearly any molecule is an organic catalyst increases the activation energy of a reaction is an inorganic catalyst is a source of energy for endergonic reactions
Enzymes are substances that act as catalysts for living organisms and regulate the rate at which chemical reactions take place without a change in the process. The biological processes that occur in all living organisms are chemical reactions, most of which are controlled by enzymes.
Enzyme functions as an organic catalyst. A catalyst is a chemical that participates in a chemical reaction but is not modified by it. Many enzymes work by lowering the activation energy of the reaction.
Enzymes are called biocatalysts because they speed up the biochemical reactions of living organisms. Enzymes are called biocatalysts because they promote chemical reactions without changing the equilibrium state.
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A barium hydroxide solution is prepared by dissolving 2.81 g of Ba(OH)2 in water to make 25.6 mL of solution. What is the concentration of the solution in units of molarity
The concentration of the solution in units of molarity is 0.64 M and the concentration of the solution in terms of g/mL is 0.10976 g/mL.
What is the concentration of the solution?The measure of the amount of the solute dissolved in the given amount of the solvent or solution is said to be the concentration of the solution.
It is given by the expression,
Concentration of the solution = mass of the solute/total volume of the solution
Units: g/mL
What is the concentration of the solution in units of molarity?The concentration of the solution in units of molarity is given by the expression,
Molarity = (no. of moles of the solute)/(Volume in L)
Units: moles/L
Calculation:It is given that the solute is barium hydroxide - Ba(OH)₂
The mass of Ba(OH)₂ = 2.81 g
When in dissolved in water, the total volume of the solution = 25.6 mL
The molar mass of Ba(OH)₂ = 171.34 g/mol
Then,
No. of moles = (mass of Ba(OH)₂)/(molar mass of Ba(OH)₂)
i.e.,
No. of moles = [tex]\frac{2.81}{171.34}[/tex] = 0.0164 mole
Concentration = mass of the solute/total volume
I.e., C = [tex]\frac{2.81}{25.6}[/tex] = 0.10976 g/mL
Then the concentration of the solution in units of molarity is,
Molarity = (no. of moles)/(Volume of the solution in L)
⇒ Molarity = [tex]\frac{0.0164}{25.6/1000}[/tex] = 0.64 M
Therefore, the concentration of the solution in units of molarity is 0.64 M.
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As atomic radius decreases, electronegativity __________. This is mostly because a smaller atomic radius represents a ________ hold on the valence ________.
As atomic radius decreases, electronegativity increases. This is mostly because a smaller atomic radius represents a stronger hold on the valence electrons.
During strenuous exercise, the NADH formed in the glyceraldehyde 3-phosphate dehydrogenase reaction in skeletal muscle must be reoxidized to NAD if glycolysis is to continue. The most important reaction involved in the reoxidation of NADH is:
The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate
Two ATP were generated as a net result of glycolysis, two NAD+ were converted to two NADH + H+, and two glucose molecules were divided into two pyruvate molecules.
Pyruvate will go through a process called fermentation when oxygen is absent.
The NADH + H+ from glycolysis will be recycled back to NAD+ during fermentation, allowing glycolysis to proceed.
NAD+ is converted during the glycolysis process into NADH + H+.
Glycolysis cannot proceed without the presence of NAD+.
The NADH produced during glycolysis will be oxidised to create new NAD+ during aerobic respiration, when it will be used once more in glycolysis.
Pyruvate will undergo oxidation in the absence of oxygen or if an organism is unable to engage in aerobic respiration.
Hence The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate
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A sample of gold weighing 38.6 g was added to a graduated cylinder containing 23.00 mL of water. The volume of the water plus the gold was 25.00 mL. What is the density of gold
Answer:
2.00 g mL -1
Explanation:
2.00 g mL -1
Answer:
19.3 g / ml
Explanation:
The volume of gold is the increase in the cylinder volume
volume = 2 ml
mass = 38.6 g
density = mass / volume = 38.6 / 2 = 19.3 g / cm^3
When a suitable alkyl halide is treated with a nucleophile, a substitution reaction can occur in which the leaving group is replaced by a(n) ____________. In an elimination reaction, a(n) ___________ is removed and a leaving group is expelled, giving an alkene.
When a suitable alkyl halide is treated with a nucleophile, a substitution reaction can occur in which the leaving group is replaced by a nucleophile.
In an elimination reaction , hydrogen halide is removed and a leaving group is expelled, giving an alkene.
In nucleophilic substitution reactions ,nucleophile attacks on the electrophilic group and replaces this group. In an elimination reaction, certain atoms in pair are removed from the compound.A Nucleophile is a electron rich reactant which provides electron in the reaction to form a bond. An Electrophile is a electron deficient group which accepts the electrons from a electron rich group.Learn more about nucleophiles here..
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What types of functional groups react to form the imine intermediate in the Strecker synthesis of amino acids
Strecker synthesis of amino acids:
Aldehyde and ketone are the functional groups that react to form the imine intermediate in the Strecker synthesis of amino acids.
Method of Strecker synthesis:
A method for synthesizing amino acids by the reaction of an aldehyde with ammonia in the presence of potassium cyanide is known as the Strecker amino acid synthesis. α-aminonitrile is produced by the condensation reaction, and this α-aminonitrile is then hydrolyzed to produce the required amino acid. The technique is applied commercially to make racemic methionine from methional.
Although primary and secondary amines also produce substituted amino acids, using ammonium salts only produces unsubstituted amino acids. Similar to this, using ketones in place of aldehydes results in amino acids that are α,α-disubstituted.
Reaction mechanism:
An aldehyde's carbonyl oxygen is protonated in the first phase of the reaction, which is followed by an ammonia nucleophilic attack on the carbonyl carbon. Water is separated from the intermediate iminium ion after a second proton exchange. The iminium carbon is then attacked by a cyanide ion, resulting in an aminonitrile.
The aminonitrile's nitrile nitrogen is protonated in the second step of the Strecker Synthesis, and a water molecule attacks the nitrile carbon. Proton exchange and a nucleophilic attack of water on the former nitrile carbon are followed by the formation of a 1,2-diamino-diol. The protonation of the amino group is then followed by the elimination of ammonia, and eventually, the deprotonation of a hydroxyl group results in the production of amino acids.
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If 65.39 g of zinc are mixed with some unknown mass of hydrochloride acid, 136.29 g of zncl2 are formed along with 2.00 g of hydrogen gas. what mass of hydrochloric acid was used?
How much hydrogen chloride acid was used?
72.916 g of hydrochloric acid was used.
Given:
Mass of Zn = 65.39 g
Mass of [tex]ZnCl_{2}[/tex] =136.29 g
Mass of [tex]H_{2}[/tex] = 2 g
Equation:
The chemical equation for the reaction of zinc with hydrochloric acid:
Zn + 2HCl → Zn [tex]Cl_{2}[/tex] + [tex]H_{2}[/tex]
Hydrogen gas is created when zinc combines with hydrochloric acid, which causes the process to bubble ferociously. Another sign that a chemical reaction is taking place is the generation of a gas.
Calculation:
A number of equivalents equate:
Number of equivalents = [tex]\frac{given mass}{Molecular Mass}[/tex] x 1000 x equivalent factor
[tex]\frac{x}{36.458}[/tex] x 1000 x 1 = [tex]\frac{136.29}{136.286}[/tex] x 1000 x 2
[tex]x[/tex] = 36.458 x 2
[tex]x[/tex] = 72.916
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What is an ethical vacuum?
A. When technology has created something for which we do not have an ethical framework yet.
B. A philosophy that ethics cannot exist in a vacuum, but need specific examples to be valid.
C. The situation of being without ethics.
D. A scientific idea that lacks ethics.
Answer:
A
Explanation:
when technology has created something for which we don't have an ethical framework is called ethical vacuum .
Answer: A
Explanation: A is the correct answer because when technology has created something in which we do not have an ethical framework yet its a called a vacuum.
What is hyperconjugation
Hyperconjugation is the interaction between bonds in organic compounds.
What is hyperconjugation?Hyperconjugation is the relationship or interaction that exist between multiple bonds molecules and single bond molecules in organic compounds.
Therefore, Hyperconjugation is the interaction between bonds in organic compounds.
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The boiling temperature of the condensed gas is:
600°C
O-273°C
O-160°C
50°C
other
Well, the answer is the 4rth one "
50°C"
How many grams of ethylene glycol (C2H6O7) must be added to 1.00 kg of water to produce a solution that freezes at -5.00C
0.03 g of ethylene glycol (C2H6O7) must be added to 1.00 kg of water to produce a solution that freezes at -5.00C.
How to calculate the amount of solution with freezing point ?[tex]\Delta T_{f} = K_{f} m[/tex]
where,
ΔTf = Change in freezing point
Kf = molal freezing point depression constant of the solvent
m = moles of solute per kilogram of solvent.
Now,
[tex]\Delta T_{f} = K_{f} m[/tex]
[tex]\Delta T_{f} = K_{f} \times \frac{W_2}{M_2} \times \frac{1000}{W_1}[/tex] [-5.00°C = 273 + (-5.00) = 268 K] [tex]268 = 1.86 \times \frac{W_2}{62} \times \frac{1000}{0.001}[/tex] [1.00 kg = 0.001 g]
[tex]W_{2} = \frac{268 \times 62 \times 0.001}{1000 \times 1.86}[/tex]
= 0.03 g
Thus from the above conclusion we can say that 0.03 g of ethylene glycol (C2H6O7) must be added to 1.00 kg of water to produce a solution that freezes at -5.00C.
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The ___________ of a chemical reaction shows how much product was actually made compared with the amount of product that was expected. A. percent yield B. atom economy C. actual yield D. exponential yield
The Actual yield of a chemical reaction shows the amount of product actually made
What is actual yield ?Actual yield in a chemical reaction is the exact amount of products that is produced in a chemical reaction other than the expected amount of products ( theoretical yield ) from the chemical reaction.
Hence we can conclude that the actual yield of a chemical reaction shows the amount of product actually made.
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Answer:
B.) Atom economy
Explanation:
Got it right on founders edtell
5. A drinking water sample was analyzed for fecal contamination. There are 65 colonies from a 10-2 dilution and plated 0.1mL. What is the number of CFU's per milliliter of water
65 * 10^3 CFU's per milliliter of water.
CFU stands for a colony-forming unit. which means that cfu/g is a colony-forming unit in line with gram and CFU/ml is a colony-forming unit in step with milliliter. A colony-forming unit is where a colony of microbes grows on a petri dish, from one unmarried microbe.
Colony Forming devices are a time period from Microbiology. CFU offers an indication of the quantity of residing microorganisms in a liquid. This quantity, determined with the aid of counting the individual colonies, describes the number of cells of organisms within the water, which can be capable of multiplying.
Whilst you do plate be counted of micro organism you are making serial suspension dilution in saline buffer or any other diluent, and then you plate a sure quantity (one hundred microliters on a 9cm Petri plate) you unfold and incubate and then you definitely depend on the range of colonies shaped.
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The principal quantum number (n): specifies the maximum number of electrons. specifies the 3-D shape of the orbital. none of the above specifies the subshell of the orbital. specifies the principal shell of the orbital.
The principal quantum number (n): specifies the principal shell of the orbital.
The answer is option D.
The important quantum number (n) describes the dimensions of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, as an example. Because they have got opposite electric costs, electrons are interested in the nucleus of the atom.
The numerals, called essential quantum numbers, imply strength degrees as well as the relative distance from the nucleus. A 1s electron occupies the energy stage nearest the nucleus.
A 2s electron, less strongly certain, spends most of its time farther far from the nucleus.
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What volume of a 0.167 M potassium hydroxide solution is required to neutralize 16.6 mL of a 0.366 M nitric acid solution
36.38 ml of a 0.167 M potassium hydroxide solution is required to neutralize 16.6 mL of a 0.366 M nitric acid solution.
Given that 16.6 mL of a 0.366 M nitric acid solution is neutralized by 0.167 M potassium hydroxide solution.
The balanced equation for the reaction is:
HNO₃ + KOH → KNO₃ + H₂O
From the equation given above,
Mole ratio of the acid, HNO₃ (nA) = 1
Mole ratio of the base, KOH (nB) = 1
From the question:
Molarity of the acid, HNO₃ (Ma) = 0.366 M
Volume of the base, KOH (Vb) =
Molarity of the base, KOH (Mb) = 0.167 M
Volume of the acid, HNO₃ (Va) = 16.6 ml
Now,
MaVa/ MbVb = nA/nB
0.366 × 16.6 / 0.167 × Vb = 1/1
6.0756 = 0.167 × Vb
Vb = 36.38 ml
Therefore, 36.38 ml of potassium hydroxide solution is required for the reaction.
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175 ml of a 1.6 m solution of kcl is diluted to a new volume of 1.0 l. what is the new concentration of the solution? (3 points)
0.13 m kcl
0.28 m kcl
0.85 m kcl
1.1 m kcl
175 ml of a 1.6 m solution of KCl is diluted to a new volume of 1.0 L. The new concentration of the solution is 0.28 m KCl.
Hence, Option (B) is correct answer.
What is Concentration ?Concentration is defined as the measure of how much substance there is mixed with another substance.
How to find the concentration ?To find the concentration use the dilution formula
C₁V₁ = C₂V₂
where,
C₁ = Concentration of starting solution
C₂ = Concentration of final solution
V₁ = Volume of the starting solution
V₂ = Volume of the final solution
Now put the values in above formula we get
C₁V₁ = C₂V₂
1.6 × 0.175 = C₂ × 1.0
0.28 = C₂ × 1.0
C₂ = 0.28
Thus from the above conclusion we can say that 175 ml of a 1.6 m solution of KCl is diluted to a new volume of 1.0 L. The new concentration of the solution is 0.28 m KCl.
Hence, Option (B) is correct answer.
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The remnants of an ancient fire in a cave in Peru showed a decay rate of 8.0 counts per minute per gram of carbon. Assuming that the decay rate in freshly cut wood is 12.7 counts per minute per gram of carbon, calculate the age of the remnants. The half life of 614C is 5730 years.
The age of the remnants is calculated as 3807 years.
What is the half life?The half life is the time taken for only half of the number of the radioactive atoms to remain.
Half life of carbon - 14 = 5730 years.
Initial count rate = 8.0 counts per minute per gram
Count rate at time t = 12.7 counts per minute per gram of carbon
Since;
0.693/t1/2 =2.303/t log (N/No)
0.693/5730 = 2.303/t log (12.7/8)
1.21 * 10^-4 = 2.303/t * 0.2
t = 2.303 * 0.2/1.21 * 10^-4
t = 0.4606/1.21 * 10^-4
t = 3807 years
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Analysis of an unknown compound shows that it contains 1.04 grams K, 0.70 grams Cr, and 0.86 grams
O. Find the empirical formula of the compound.
A. K₂CrO4
B. KCrO2
C. KCRO
D. K₂CrO2
Answer:
1
Explanation:
1.04/MM = 1.04/39.09 = 0.0266 potassium moles
0.7/MM = 0.7/52 = 0.0133 chromium moles
0.86/MM =0.86/16 = 0.05375 oxygen moles
divide all the moles number by the lowest
0.0266/0.0133=2
0.0133/0.0133=1
0.05375/0.133=4
so the empirical formula is K2CrO4
which of the following measurements are listed in the proper mathematical relationship?(Select all that apply)
A. PV = K
B. V/T = K
C. PV/T = K
D. P/V = K
The measurements which are listed in the proper mathematical relationship include:
PV=kV/T=kPV/T = kWhat is a Constant?This is used in mathematical expressions and has a constant value which doesn't change in expression.
Options A,B and C have the appropriate constants as pressure is usually multiplied by volume.
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Identify the steps that are followed in taking a stratified random sample. i. Take a sample of size n/k from each strata, where n is sample size and k is the number of strata. ii. Determine what portion of the sample should come from each strata. iii. Measure the size of the strata as a proportion of the population. iv. Take a systematic sample from the population as a whole. Take random samples from each strata.
steps that are followed in taking a stratified random sample are
i. Take a sample of size n/k from each strata, where n is the sample size and k is the number of strata
iv. Take a systematic sample from the population as a whole. Take random samples from each strata.
Stratified random sampling is a sampling method that divides the population into smaller groups called layers. Groups or hierarchies are organized based on the common characteristics or attributes of the members in the group. The process of dividing the population into groups is called hierarchization.
Stratified Random Sample Example:
Suppose a research team wants to determine a GPA for a college student in the United States. The research team is having a hard time collecting data from all 21 million college students. We decided to use 4,000 students to extract a random sample of the population.
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