-will give brainliest, thx

When a spring of stiffness K = 120N/m supporting a smooth cylinder of mass 6kg is subjected to a force of 60N, the velocity it moves downward when compressed a distance of 0.2m is 1.79m/s.

Therefore, the answer is 1.79m/s.

The compression of spring, say x₀ at equilibrium position can be determined by

F = Kx₀

mg = Kx₀

6 × 9.81 = 120 × x₀

Therefore x₀ = 0.4905m

When force F = 60N is applied the spring is compressed more and let new compression of spring be x₁. Then when string compresses additional s distance

x₁ = x₀ + s

Then spring force, F₁ = Kx₁

F₁ = 120 × (0.4905 + s)

F₁ = 58.86 + 120s

Let the cylinder accelerates downward at a m/s², then

60N + mg = ma + F₁

60 + 6×9.81 = 6a + 58.86 + 120s

a = (10 - 20s) m/s²

dv/dt = 10 - 20s

We know that ds/dt = v, that is 1/dt = v/ds

Therefore, vdv/ds = 10 - 20s

vdv = (10 - 20s)ds

Integrating both sides

v²/2 = 10s - 10s²

v = √(20s - 20s²)

At s = 0.2m,

v = √(20×0.2 - 20×0.2²)

v = 1.79m/s

--The question is incomplete, answering to the question below--

"The 6kg smooth cylinder is supported by the spring having a stiffness of kAB = 120 N/m. Determine the velocity of the cylinder when it moves downward s = .2m from its equilibrium position, which is caused by the application of the force F = 60 N. (The 60 N force is not present in the equilibrium position.)"

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Answer:

Square, rhombus, parralelogram

Step-by-step explanation:

Bro too much to type trust

Yes, the starting position of these players form a perpendicular line.

The area of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).

Given:

Using Trigonometry

sin [tex]\theta[/tex] = 33.33/100

sin [tex]\theta[/tex] = 0.3333

[tex]\theta[/tex] = [tex]sin^{-1}[/tex] (0.3333)

[tex]\theta[/tex] = 19.469

cos 19.469 = B/ 100

0.9428 = B/ 100

B= 94.28

tan  [tex]\theta[/tex] = P/B

tan  [tex]\theta[/tex] = 94.28/ 33.33

[tex]\theta[/tex] = 70.5

Using Angle Sum property

< 3= 180 - (70.5 + 19.5)

<3 = 180 - 90

<3 = 90

Hence, they form perpendicular line.

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Answer:

0.4 x 10^-1

Step-by-step explanation:

4 x 10^0

=> 4

=> 0.4 x 10^-1

The number of students who like dressmaking and catering only is 7.

The number of students who did not choose any of the 3 vocations is 12.

A Venn diagram is an overlapping circle to describe the logical relationships between two or more sets of items.

We have,

Total students = 40

The Venn diagram is given below.

The number of students who like dressmaking and catering only.

= 7

Total number of students who like at least one vocation.

= 28

The number of students who did not choose any vocation.

= 40 - 28

= 12

Thus,

7 students like dressmaking and catering only.

12 students did not choose any vocation.

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The value of TC = 5.9

According to the given figure of the triangle ABC, (refer to the attached figure)

The length of perpendicular bisector AC is = m

The length of perpendicular bisector BC is = n

The point at which line m and line n are intersecting = T

Given the value of TA = 5.9

According to the corner theorem.

AC = CF

So, ΔTFA ≅ ΔTFC

⇒ TA = TC = 5.9

Therefore, The value of TC = 5.9

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In a dice, there is a six side

Probability of occurring a score = 1/18

                                           = 1*2/18*2

                                               = 2/36

                                        =   preferred outcome/ Total outcome

Only 5 is a number that has occurred twice

The score that has a probability of occurring of 1/18 is 5.

The two dice having different values 30/36 = 5/6 (because the probability of the two dice having equal values is 6/36 = 1/6.)

The probability of the second dice being less than the first dice is the same as the probability of the first dice is less than the second dice: (5/6) / 2 = 5/12.

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Answer: The distance between the two parallel lines is 11/12.

Step-by-step explanation:

The distance between two parallel lines can be found by calculating the difference between the y-intercepts of the two lines. In this case, the y-intercept of the first line is (-1/4,0), and the y-intercept of the second line is (-7/6,0). The difference between these y-intercepts is (-1/4 - (-7/6)) = 11/12. Therefore, the distance between the two parallel lines is 11/12.

The surface area of that part of the plane 10x+7y+z=4 that lies inside the elliptic cylinder [tex]\frac{x^2}{25} +\frac{y^2}{9}[/tex] is 15π√150 and this can be determined by using the given data.

We are given the two equations are:

10x + 7y + z = 4---------(1)

[tex]\frac{x^2}{25} +\frac{y^2}{9} =1-------------(2)[/tex]

equation(1) is written as

z = 4 - 10x - 7y-----------(3)

The surface area is given by the equation:

A(S) = ∫∫√[(∂f/∂x)² + (∂f/∂y)² + 1]dA------------(4)

compare equation(4) with equation(3) we get the values of ∂f/∂x and

∂f/∂y

∂f/∂x = -10

∂f/∂y = -7

substitute these values in equation(4)

A(S) = ∫∫√[(-10)² + (-7)² + 1]dA

A(S) = ∫∫√[100 + 49 + 1]dA

A(S) = ∫∫√[150]dA

A(S) = √150 ∫∫dA

Where ∫∫dA is the elliptical cylinder

From the general form of an area enclosed by an ellipse with the formula;

comparing x²/a² + y²/b² = 1  with x²/25 + y²/9 = 1, from that we get the values of a and b

a = 5 and b = 3

So, the area of the elliptical cylinder = πab

Thus;

A(S) = √150 × π(5 × 3)

A(S) = 15π√150

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The first three taylor polynomials of the function f(x) = e⁻ˣ at x = 0 is 1, 1 - x and 1 - x + x²/ 2.

Taylor polynomial of degree n for a function f(x) which is infinitely differentiable at a is

f(a) + f'(a)×(x - a)/ 1! + f''(a)×(x - a)²/ 2! + ... + (f⁽ⁿ⁾(a)×(x - a)ⁿ/ n! = ∑(i = 1 to n)(f⁽i⁾(a)×(x - a)^{i}/ i!)

where f⁽i⁾(a) denotes the ith derivative of f(x) at a

The first, second and nth derivative of the function f(x) = e⁻ˣ is

f'(x) = -e⁻ˣ

f''(x) = e⁻ˣ

f⁽ⁿ⁾x = (-1)ⁿe⁻ˣ

First Taylor polynomial, n = 1, here f(x) = e⁻ˣ and a = 0.

P₁(x) = f(0) = e⁻⁰ = 1

Similarly

P₂(x) = f(0) + f'(0)(x - 0)/ 1!

P₂(x) = 1 + -1×e⁻⁰×(x - 0)

P₂(x) = 1 - x

P₃(x) = f(0) + f'(0)(x - 0)/ 1! + f''(0)(x - 0)²/ 2!

P₃(x) = 1 - x + e⁻⁰×(x - 0)²/ 2

P₃(x) = 1 - x + x²/ 2

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The length of the wall in her drawing is given as follows:

5.6 inches.

A scaling measurement represents the proportion of a total dimension, as it is the ratio between the length of the drawing with the actual length of the object.

On her drawing a 10-foot wall is 8 inches, hence the scale measurement for this problem is given as follows:

8 inches/10 feet = 0.8 inches per feet.

The scale means that each feet of an actual object is represented by a length of 0.8 inches on the drawing.

Audrey wants to add a 7 foot wall to the drawing, meaning that the length of the drawing is given as follows:

7 x 0.8 = 5.6 inches.

(applying the proportion found from the scale measurement).

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π/16 is the area enclosed by the curve r= sin(4θ)

The given curve is polar curve and hence the area of the polar curve is given by:

Let A be the area of the curve so,

A = [tex]\int\limits^b_a {\frac{1}{2}r^2 } \, d\theta[/tex]

where a and b is the boundary at which r=0

so after equation r=0

sin(4θ) =0

=> sin(4θ) =0

=> 4θ = 0,π

=> θ = 0, π/4

so a=0 , b= π/4

now  

  A =  [tex]\int\limits^b_a {\frac{1}{2}r^2 } \, d\theta[/tex]   ------(i)

so   [tex]r^2[/tex] = (sin(4θ))^2

=>   [tex]sin^2[/tex]( 4θ )

ans we know that

cos(2α) = 1 -  [tex]2sin^2[/tex]2 α

so     [tex]sin^2[/tex]= (1- cos(8θ) )/2

putting the value of r in the equation (i) we get :-

A = [tex]\int\limits^b_a {\frac{1}{4} *(1-cos8\theta) } \, d\theta[/tex]

=> 1/4*  [tex]\int\limits^b_a {(1-cos8\theta) } \, d\theta[/tex]

here a=0 and b=π/4

after putting the value and solving the integral

A = π/16

so A is the area enclosed by r=sin(4θ) is π/16

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i didn't learn it.. so im not sure.. but i thimk 3

Answer:-2,0

Step-by-step explanation:

you have to ether multiply or divide by an easy number

It is about 24% of the students could be expected to score between 70 and 90 on the exam.

To find the percentage of students who score between 70 and 90 on the exam, we need to determine what proportion of the exam scores falls within that range. We can do this by converting the scores to standard units and using a table of the standard normal distribution.

First, we need to convert the scores to standard units. We do this by subtracting the mean of 100 from each score and then dividing by the standard deviation of 60. For a score of 70, the standard units would be (70 - 100)/60 = -1.67. For a score of 90, the standard units would be (90 - 100)/60 = -0.67.

Next, we can use a table of the standard normal distribution to find the proportion of scores that fall within that range. For example, a table of the standard normal distribution might tell us that the proportion of scores between -1.67 and -0.67 standard units is about 0.24

Percentage of scores within range = 8.64/36 * 100% = 24%

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Answer:

x = 1          y = 0

Step-by-step explanation:

-8x + y = -8

6x - y = 6

y have the same coefficient but one is negative and the other is positive therefore we add both the equations

we get:

-2x = -2

divide both sides by -2

x = 1

now as we have the value of x we can input this into any one of the starting equations

-8x + y =-8

-8(1) +y = -8

-8 + y = -8

add 8 to both sides

y = 0

Answer:

(1, 0 )

Step-by-step explanation:

- 8x + y = - 8 → (1)

6x - y = 6 → (2)

adding (1) and (2) term by term will eliminate y

- 2x + 0 = - 2

- 2x = - 2 ( divide both sides by - 2 )

x = 1

substitute x = 1 into either of the 2 equations and solve for y

substituting into (1)

- 8(1) + y = - 8

- 8 + y = - 8 ( add 8 to both sides )

y = 0

solution is (1, 0 )

The fundamental counting principal there will be 2*2*2*4*2 = 64 possible lunches.

What is fundamental counting principal ?

According to this concept, the sum of the outcomes of two or more independent events is equal to the product of the outcomes of each individual event. For instance, a youngster picking from a menu of six ice cream flavors and three types of cones will have a total of 6 x 3 = 18 options.

Here size has two types  say  2

Here cheese has two types say 2

Here type of bun has two types say 2

Here side order has four types say 4

Here fruit drink has two types say 2

So, according to the fundamental counting principal there will be 2*2*2*4*2 = 64 possible lunches.

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Answer: 50%

Step-by-step explanation:

Take 2.62 divided by 5.24, then times 100 = 50%

Then take 100% - 50% = 50%

The percentage discount is 50%

in a regression with 7 predictors and 62 observations,The degrees of freedom for a t-test for each coefficient would use 55 degrees of freedom (df = 62 - 7 = 55).

The degrees of freedom for a t-test for each coefficient is calculated by subtracting the number of predictors (7) from the number of observations (62) in a regression with 7 predictors and 62 observations,. This leaves us with 55 degrees of freedom (df = 62 - 7 = 55). Degrees of freedom measure the number of observations that are free to vary in estimating a parameter. In other words, they are the number of observations that are used to generate the estimate. In this case, there are 55 observations that can be used to estimate each coefficient.

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The equation of the Parabola is (y - 6 )² = 28 (x + 1)  of the given focus and directrix.

Given directrix x = -8

we know that    x = h - a = -8

              h -a =  -8  ...(i)

Given Focus  = ( 6,2)

we know that the Focus of the Parabola

        ( h + a , k ) = (6,2)

  comparing  h + a = 6 ...(ii)

                 k = 2

solving (i) and (ii) and adding

  h - a + h+ a = -8 +6

          2 h = -2

             h = -1

  Put h = 6 in equation (i)

 ⇒     h - a = -8

 ⇒   -1 + 8 = a

 ⇒      a = 7

The equation of the Parabola ( h,k) = (-1 , 7)

( y - k )² = 4 a ( x - h )

(y - 7 )² = 4 (7) (x -(-1))

(y - 6 )² = 28 (x + 1)

Hence, the equation of the Parabola is (y - 6 )² = 28 (x + 1)  of the given focus and directrix.

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Although part of your question is missing, you might be referring to this full question: What are the vertex and range of y = |2x + 6| + 2?

(0, 2); 2 < y < ∞

(0, 2); −∞ ≤ y < ∞

(−3, 2); 2 < y < ∞

(−3, 2); −∞ ≤ y < ∞

The vertex of the function is (–3, 2) and the range of the function is 2 < y < ∞.

The given modulus function:

y = |2x + 6| + 2

Now, we get two equations out of the absolute value function:

y = 2x + 6 + 2

y = 2x + 8

and

y = –2x – 6 + 2

y = –2x – 4

The vertex of the function will be at a point where these two equations are equal. So, we can calculate the vertex as follows:

2x + 8 = –2x – 4

2x + 2x = –4 – 8

4x = –12

x = –3

If x = –3, then y = 2(–3) + 8 = –6 + 8 = 2

Thus, the vertex of the function is (–3, 2).

Now, the values that y can take will range from 2 to infinity as y cannot take values below the vertex.

Thus, the range of the function is 2 < y < ∞.

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Answer:

2.64 square meters.

Step-by-step explanation:

To find the surface area of a cuboid, you need to find the area of each of the six faces and add them together. A wooden cuboid with an open flame base that has a square surface with 1.2 meter sides and a height of 0.25 meters would have a surface area of 1.2 * 1.2 + 4 * (1.2 * 0.25) = 1.44 + 1.2 = 2.64 square meters. This is because the base of the cuboid has an area of 1.2 * 1.2 = 1.44 square meters, and each of the four sides has an area of 1.2 * 0.25 = 0.3 square meters. The total surface area of the cuboid is therefore the sum of these areas: 1.44 + 4 * 0.3 = 2.64 square meters.

Answer:

3.11(0) = 0

Step-by-step explanation:

D. 3.11(0) = 0 is an example of the identity property of 1. The identity property of 1 states that any number multiplied by 1 is equal to itself. In this case, 3.11 is multiplied by 0, which is equal to 0.

Answer:

putting more than question is against app rules but alr

Part A: The value of each of the houses after a fixed number of years can be described by a linear function. This is because the value of each house increases at a constant rate, with the same amount added each year.

Part B: The function for House 1 could be written as f(x) = 294,580 + 8,937.6x, and the function for House 2 could be written as f(x) = 295,000 + 9,000x.

Part C: After 25 years, the value of House 1 will be approximately $750,834.40, and the value of House 2 will be approximately $753,000. The difference in value between the two houses after 25 years will be approximately $2,165.60, which is not a significant difference in the overall value of the houses. Therefore, either house would be a good choice for Belinda to purchase.

Answer:

18

Step-by-step explanation:

this seems to be an equilateral triangle so all sides are equal

5r+8=9r

-5r.   -5r

8=4r

/4 /4

2=r

now fill it in

5(2)+8

10+8

18

hopes this helps

The number of years that the deposit was held for is 3 years.

From the information, Mr. Johnson deposited $2000 in an account that earns simple interest at an annual interest rate of 6%. and he received $360 as interest at the end of the tenure.

It should be noted that simple interest is Illustrated as:

I = PRT

Therefore, T = Interest / Principal × Rate

Time = 360 / (2000 × 6%)

Time = 360 / 120

Time = 3 years

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The given statement is true for tabulation method representing the variable different categories and summarize it in tabulation method makes the calculation simple.

As given in the question,

Therefore, the given statement of representing the variable different categories and summarize it in tabulation method makes the calculation simple is a true statement.

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Answer:

d is the correct answer to your question

Answer:

9.2 units

Step-by-step explanation:

cause the last guy is right...

[tex]-4w+ 2 = 14[/tex]

Subtract 2 from both sides:

[tex]-4w+2-2=14-2[/tex]

[tex]-4w=12[/tex]

Divide both sides by -4:

[tex]\dfrac{-4w}{-4} =\dfrac{12}{-4}[/tex]

[tex]= \fbox{w = -3}[/tex]

Answer:

w = -3

Step-by-step explanation:

-4w + 2 = 14

-4w + 2 - 2 = 14 - 2 (Subtract 2 from both sides)

-4w = 12

-4w/-4 = 12/-4 (Divide -4 from both sides)

w = -3