Why open flames near to ethanol can lead to serious fires?​

The equilibrium concentration of ethyl acetate will be 5.39 M.

Initially, 8.59 M acetic acid react with 8.59 M ethanol.

acetic acid  +  ethanol  ===>  ethyl acetate  +  water

     (8.59)           (8.59)                      (0)

after some time, some change will happen.

acetic acid  +  ethanol  ===>  ethyl acetate  +  water

  (8.59-x)         (8.59-x)                   (x)

At equilibrium condition,

acetic acid  +  ethanol  ===>  ethyl acetate  +  water

     (3.20)           (3.20)                      (x)

At equilibrium, for acetic acid and ethanol to go from 8.59 to 3.20, the value of x must be 5.39.

Therefore, the equilibrium concentration of ethyl acetate will be 5.39 M.

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Answer:

26.5 L

Explanation:

To find the volume of the gas, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this formula

-----> P = pressure (torr)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (62.36 L*torr/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you need to convert Celsius (°C) to Kelvin (K). Then, you can solve for volume through simplification.

P = 760 torr                    R = 62.36 L*torr/mol*K

V = ? L                            T = 21 °C + 273.15 = 294.15 K

n = 1.1 moles

PV = nRT

(760 torr)V = (1.1 moles)(62.36 L*torr/mol*K)(294.15 K)

(760 torr)V = 20177.5134

V = 26.5 L

The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.

Some ores of iron include:

Molar mass of hematite, Fe₂O₃ = 160 g/mol

Molar mass iron = 56 g/mol

Percent mass of iron in hematite = 56/160 = 35%

The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.

Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

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Taking into account the reaction stoichiometry, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

In first place, the balanced reaction is:

2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 319.4 grams of Fe₂O₃ form 132 grams of CO₂, 0.500 grams of Fe₂O₃ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{0.500 grams of Fe_{2}O_{3}x132 grams of CO_{2} }{319.4 grams of Fe_{2}O_{3}}[/tex]

mass of CO₂= 0.2066 grams

Then, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

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Answer:

Suggest a structural reason why carbonic anhydrase synthesized with Ni2+, Fe2+, or Mn2+ in place of Zn2+ gives an enzyme with less catalytic efficiency.

Answer:

5 moles

Explanation:

From the coefficients of the equation, we know that for every 8 moles of nitric acid consumed, 4 moles of water are produced.

So, the answer is 9(4/8), which is 5 moles to 1 sf.

Empirical formula = mol ratio

mol H = 9.42 x 10²⁴ : 6.02 x 10²³ = 15.648

mol N = 3/9 x 15.648 = 5.216

mass N = 5.216 x 14 g/mol =73.024 g

7) From the coefficients of the equation, the answer is 4:5.

8) From the coefficients of the equation, for every 6 moles of carbon dioxide consumed, 1 moleof glucose is consumed. This means that 1.66 moles of glucose is produced. Glucose has a formula mass of 180.16 g/.mol, so the answer is (1.66)(180.16), which is about 300 grams.

9) From the coefficients of the equation, we know that for every 6 moles of water consumed, 1 mole of glucose is consumed. Since we want 150 grams of glucose, and glucose has a formula mass of 180.16 g/mol, we want 150/180.16 = 0.83 mol of glucose. Thus, we need 0.83(6) moles of water, which is 5 moles to 1 sf.

10) From the coefficients of the equation, we know that for every 6 moles of carbon dioxide produced, 6 molds of oxygen are produced. Since carbon dioxide has a formula mass of 44.009 g/mol, 55 grams is about 1.25 moles. Thus, since oxygen has a formula mass of about 32 g/mol, the answer is 32(1.25), which is about 55 grams.

Answer:

b. milk spoiling and c. firecrackers exploding

Explanation:

These are both chemical changes, the composition of them change when this happens and it cannot be reversed

Answer:

= 1.553 x 10²³ ions

Explanation:

One mole of a compound or a substance consists of 6.02 x 10²³ ions. 6.02 x 10²³ is also referred to as Avogadro's number/constant.

From the above question, we have been asked to determine the number of ions in 16g of H₂CO3.

The relative formula mass (RFM) of H₂CO3 is 62.026 u:

Derived as;

H₂CO3 = (2 x 1.008) + (12.01 x 1) + (3 x 16.00) u

= 62.026 u.

Number of moles = Mass/RFM

[tex]moles \: = \frac{16}{62.026} \\ = 0.2579563 \\ = 0.2580 \: moles[/tex]

1 mole = 6.02 x 10²³ ions

0.2580 moles = ?

=

[tex] = \frac{0.2580 \times 6.02 \times 10 ^{23} }{1} \\ = 1.553 \times {10}^{23} \: ions[/tex]

Hence the number of ions in 16g H2CO3 = 1.553 x 10²³

The balanced net ionic equation for the reaction, that occurs when aqueous solutions of Na₂CO₃ and CaCl₂ are mixed is Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq).

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The balanced equation for Na₂CO₃ and CaCl₂ is as follows

Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq)

When two aqueous solutions are mixed then a white insoluble solid  CaCO₃ will precipitate out of solution. The above reaction is double displacement reaction.

Thus from the above conclusion we can say that The balanced net ionic equation for the reaction, that occurs when aqueous solutions of Na₂CO₃ and CaCl₂ are mixed is Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq).

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Answer:

Velcro was an accident.

Explanation:

hope it helps

sry if im wrong

Answer:

it was a accident

Explanation:

The empirical formula of compounds formed from the given ions are as follows:

The empirical formula of a compound is the simplest formula of the compound showing the simplest ratios in which elements in the compound combine.

The empirical formula of compounds formed from the given ions are as follows:

In conclusion, the empirical formula is the simplest formula of a compound.

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Correct option:

The statement "America is the world’s number one producer of natural gas derived from shale oil" is True.

Shale gas:

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Internal combustion energy for TNT(Trinitro toluene) is found to be  -170 kJ.

Internal energy= (- heat evolved by the system) + Work done by the system

ΔU = -Q+W

W = - PΔV

P= pressure

ΔV =difference in volume

Given,

V1 = 10 L

V2 = 90 L

∴ΔV = V2-V1 = 90-10 = 80 L

P = 1 atm

∴W = - ( 1× 80)

      = -80 kJ

Heat evolved by the system = 90 kJ

∴Δ U= - 90 kJ - 80 kJ

       = - 170 kJ

Thus, Internal combustion energy for TNT(Trinitro toluene) is found to be -170 kJ.

NOTE : here work done by the system is considered negative and also heat evolved by the system is taken -Ve.

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Answer:

1.673*10^-23 grams

Explanation:

This is a bit of an odd question, and can be done a few different ways.

In a "typical" NH3 molecule, N has 7 protons, and 7 neutrons, while H has 1 proton and 0 neutrons. In total in a NH3 molecule, there are 7+3*1 = 10 protons. We know how much a proton weighs, so we can directly multiple 10 by 1.673*10^-24 grams, getting 1.673*10^-23 grams

A more complicated way, in the case that a proton's mass isn't already given

If we don't know the mass of a proton, we can still do this problem. Most of the mass of a molecule resides in the protons and neutrons. a mole of ammonia that is made of N-14 and H-1 (numbers signifying atomic mass) weighs 14+3*1 = 17 grams. there are 6.022*10^23 molecules in a mol of any molecule, 17 grams of the specific ammonia that we have equals to 6.022*10^23 molecules.

6.022*10^23 molecules / mol = 17 grams / mol

6.022*10^23 molecules = 17 grams  

1 molecule = 2.823*10^-23 grams

There are 10 protons and 7 neutrons in one molecule NH3, so if we subtract the mass of the neutrons in one molecule of NH3, we get the mass of the protons in one molecule of NH3
(mass of 10 protons + mass of 7 neutrons) - (mass of 7 neutrons) = mass of 10 protons
(mass of one NH3) - (mass of 7 neutrons) = mass of 10 protons
7 neutrons weigh 1.1725*10^-23 grams and 1 molecule of NH3 is 2.823*10^-23 grams so substitute everything

2.823*10^-23  -   1.1725*10^-23 = 1.6505e-23 grams, which is a fairly close value to what we got using the first method.

The total mass of the protons in a typical ammonia (NH₃) molecule is 1.673 x 10⁻²³ g. The correct option is 4.

Protons are charged particles that are present in the atom. Protons are positively charged, and they are present inside the nucleus of the atom.  

Ammonia is a gas that is made up of nitrogen and hydrogen. Nitrogen = 7 protons and Hydrogen has only 1 proton.

In a "typical" NH₃ molecule, N has 7 protons, and 7 neutrons, while H has 1 proton and 0 neutrons. In total, in an NH₃ molecule, there are 7+ 3 x 1 = 10 protons.

1.673 x 10⁻²³ grams

Most of the mass of a molecule resides in the protons and neutrons.

A mole of ammonia that is made of N-14 and H-1 (numbers signifying atomic mass) weighs 14 + 3 x 1 = 17 grams.

Thus, the correct option is  4. 1.673 x 10⁻²³ g.

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The question is incomplete. Your most probably complete question is given below:

1. None of these

2. 1.675 x 1023 g

3. 1.1711 x 1023 g

4.1.673 x 10-23 g

5. 9.109 x 10-27 g

6. 1.172 x 102 g

7. 6.3763 x 10-27 g

[OH⁻]= 1 x 10⁻¹⁴ : 4.8 x 10⁻⁴ = 2.083 x 10⁻¹¹

Possible products in this reaction are the products 2 and 3.

The Friedel Crafts reaction is one in which the electrophile is created by a Lewis acid reaction between the AlCl3 and the alkylhalide reactant .

Now we know that there is the possibility of two products in this reaction due to a resonance shift as such possible products in this reaction are the products 2 and 3.

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The formula of water is H2O

Explanation:

The water molecule consists of two hydrogen atoms and one oxygen atom. So the chemical molecula formula of water is H2O where H is the symbol of hydrogen and O is the symbol of oxygen and 2 indicates that there are two atoms of hydrogen.

Hope this helps you!

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

In this case, you know:

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

1,148,344.444 mL= 1148.34 L=  V2

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

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From the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains (option D).

The absorption spectra shows us the energy that is taken in by a gas. We know that when a gas is heated, it absorbs energy which shows up in its absorption spectra.

Thus, from the absorption spectra of a gas, we can see the  amount of thermal energy the gas contains.

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Explanation:

in this question, we're asked how to determine whether we have a metallic or nonmetallic substance.So what you want to do is one to remember that metals are malleable and Nonmetal are brittle. So if we were to hammer the metal, it would be very malleable, but the nonmetal would fall apart. And never we could just hammer the sample and see whether it was malleable. And therefore it would be a medal or a brittle and therefore being nonmetal. 

The atmosphere protects life on earth by shielding it from incoming ultraviolet (UV) radiation, keeping the planet warm through insulation, and preventing extremes between day and night temperatures.

An atmosphere is the layers of gases surrounding a planet or other celestial body.

The three important functions of the atmosphere are:

1. The atmosphere protects life on earth by preventing it from incoming ultraviolet (UV) radiation.

2. The atmosphere keeps the planet warm through the insulation effect.

3. The atmosphere maintains extremes between day and night temperatures.

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Taking into account the ideal gas law,  the density of methanol vapor is 1.1219 [tex]\frac{g}{L}[/tex].

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P×V = n×R×T

where

Now, taking into account this law, you get:

[tex]\frac{n}{V} =\frac{P}{RXT}[/tex]

The units are moles/L. So, in order to calculate the density, it is necessary to take into account the molar mass, in order to calculate the density as follows:

[tex]density =\frac{P}{RXT}xmolar mass[/tex]

Then, in this case, you know:

Replacing in the previous expression:

[tex]density =\frac{1.15 atm}{0.082\frac{atmL}{molK} X400 K}x32 \frac{g}{mol}[/tex]

Solving:

density= 1.1219 [tex]\frac{g}{L}[/tex]

Finally, the density of methanol vapor is 1.1219 [tex]\frac{g}{L}[/tex].

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The mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.

The mass of a substance that underwent release of energy can be calculated using the following formula:

Q = mc∆T

Where;

543 = m × 0.227 × 5

543 = 1.135m

m = 543/1.135

m = 478.4g

Therefore, the mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.

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The value of Ka of the weak acid is 4.47 x 10^-3.

The acids that do not dissociate completely in the aqueous solution and remains in equilibrium are called weak acids. The acid dissociation constant of the weak acid is represented as Ka.

Consider a weak acid HA. Its dissociation reaction will be:

      HA        ----->      H+         +          A-

I    0.072                    0                       0

C     -x                       +x                      +x

E  0.072-x                  x                        x

Calculations:

pH = -log[H+]

1.80 = -log[H+]

[H+] = 0.01585 M

Hence, x = 0.01585 M

The value of Ka is calculated as:

Ka = x^2/0.072-x

= (0.01585)^2/(0.072 - 0.01585)

= 4.47 x 10^-3

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The molarity of the unknown solution prior to dilution is calculated to be 1.31M.

The molarity of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

10.5 × C1 = 80 × 0.172

10.5C1 = 13.76

C1 = 13.76/10.5

C1 = 1.31M

Therefore, the molarity of the unknown solution prior to dilution is calculated to be 1.31M.

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2 Na3PO4 (aq) + 3 Pb(NO3)2 (aq) --> 2 Pb3(PO4)2 (s) + 6 NaNO3 (aq)

The total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation 6 Na+ (aq) + 2 PO43-(aq) + 3 Pb2+ (aq) + 6 NO3- (aq) --> 2 Pb3(PO4)2 (s) + 6 Na+ (aq) + 6 NO3- (aq)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

3 Pb2+ (aq) + 2 PO43- (aq) -> 2 Pb3(PO4)2 (s)

Answer:

2+ 3 3 Pb (aq) + 2 PO4 (aq) -> 2 Pb3(PO4)2 (5)

Lead(II) nitrate,

Pb

(

NO

3

)

2

, and sodium bromide,

NaBr

, are soluble in an aqueous solution, which means that they dissociate completely to form cations and anions when dissolved in water.

Please check the attached file for brief answer.

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Answer:

Add Copper(II) oxide, CuO, to an aqueous solution of hydrochloric acid, HCl, to produce the salt copper chloride, CuCl2. To obtain a pure, dry sample of the salt, remove excess, undissolved CuO through filtration. Then heat the system to evaporate water, leaving behind pure Copper(II) Oxide.