The angle of elevation for two parasailing boats traveling at the same speed is equal because they have the same length of tow line.
What is parasailing?Parasailing is also referred to as parascending and it can be defined as a recreational activity which involves a person wearing an open parachute (canopy wing) and gliding through the air, while being towed by a boat.
By critically observing the image shown below, we can infer and logically deduce that the reason why the angle of elevation for two parasailing boats traveling at the same speed is equal, is simply because they have the same length of tow line.
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Complete Question:
Why is the angle of elevation for two parasailing boats traveling at the same speed equal?
What is the sequence equation 8, 17, 35, 71, 143
Answer:
Step-by-step explanation:
What you do is multiply the previous number and add 1 to get the next answer.
Equation An = 2(An-1)+1
n = The Term
Simplify 8 over the quantity of 2 plus 2i
Answer:
2-2i
Step-by-step explanation:
So you have the equation:
[tex]\frac{8}{2+2i}[/tex]
and when you have these equations, you want to get rid of the i, and to do that the simplest way is to square it right? If you simply multiply by 2+2i, you're going to get some i in the middle, so to make sure it's eliminated, you use the difference of squares identity: [tex](a+b)(a-b)=a^2-b^2[/tex]. So you multiply by the conjugate, since it's 2+2i, you multiply by 2-2i, that way it evaluates to 2^2-(2i)^2
Multiply both sides by the conjugate of 2+2i
[tex]\frac{8(2-2i)}{(2+2i)(2-2i)}[/tex]
Simplify:
[tex]\frac{16-16i}{2^2-(2i)^2}[/tex]
Distribute square the values below
[tex]\frac{16-16i}{4-4i^2}[/tex]
Rewrite the i^2 as -1, since sqrt(-1) = i
[tex]\frac{16-16i}{4-4(-1)}[/tex]
Cancel out the negatives
[tex]\frac{16-16i}{8}[/tex]
Distribute the division
[tex]2-2i[/tex]
How many hours would it take Natalie if she worked alone?
Multiply and reduce to lowest terms
5/13 X 3 3/8
Answer:
1 31/104Step-by-step explanation:
First, let's turn them both into improper fractions.
3 3/8 = 27/8
Now we can multiply
It is 5*27 / 13 * 8
This equals: 135 / 104
Simplified even further is:
1 31/104
A swimming pool is shaped like the figure below. Each end is a semicircle, and the length and
width of the rectangle are 40 feet and 20 feet, respectively. If there were a -foot-wide cement
border around the pool, what would be the area of the border?
The area of the border around the pool is determined as 145.97 ft².
Area of the pool
Diameter of the circle = 20 ft
Radius of the circle = 10 ft
Area of circular portion:Area = π(10²) = 314.16 ft²
Area of rectangular portionA = 40 ft x 20 ft = 800 ft²
Pool area = 314.16 ft² + 800 ft² = 1,114.16 ft²
Overall area which include 1 foot borderDiameter of the circle = 20 ft + 1ft + 1 ft = 22 ft
Radius of the circle = 11 ft
Area of circular portion:A = π(11²) = 380.13 ft²
Area of rectangular portion:A = 22 ft x 40 ft = 880 ft²
Total area = 880 ft² + 380.13 ft² = 1,260.13 ft²
Area of the borderArea of border = Total area - pool area
Area of border = 1,260.13 ft² - 1,114.16 ft²
Area of border = 145.97 ft²
Thus, the area of the border around the pool is determined as 145.97 ft².
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In a class of 95 students, 48 play basketball, 35 play football and 32 play neither basketball or football. What percentage of the class plays only football?
Need answers ASAP thank you so much
The number of people who plays only footfall will be 15. The percentage of the class plays only football will be 15.79%.
What is the percentage?The quantity of anything is stated as though it were a fraction of a hundred.
In a class of 95 students, 48 play basketball, 35 play football and 32 play neither basketball nor football.
Let x be the number of student who plays basketball as well as football.
48 – x + x + 35 – x + 32 = 95
115 – x = 95
x = 20
The number of people who plays only footfall will be
⇒ 35 – 20
⇒ 15
Then the percentage of the class plays only football will be 15.79%.
⇒ 15/95 × 100
⇒ 15.79%
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Tony made 14 \text{ L}14 L14, start text, space, L, end text of lemonade for a party. His guests drank 9{,}500 \text{ mL}9,500 mL9, comma, 500, start text, space, m, L, end text of the lemonade.
How many milliliters of lemonade did Tony have left over?
Unit conversion is a way of converting some common units into another without changing their real value. The lemonade left with Tony is 4500ml.
What is unit conversion?Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimetre is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.
One litre is equal to 1000 millilitres. Tony made 14 Liter of lemonade, therefore, Tony made 14,000 millilitres of lemonade. His guest drank 9500 millilitres. Therefore, the lemonade left with Tony is,
Lemonade left = 14,000 - 9,500 = 4,500 ml
Hence, the lemonade left with Tony is 4500ml.
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hs and Equations: Practice
Question 2 of 5
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Determine the equation for the quadratic relationship graphed below.
у
-2
6
2
4
-6
✓
Submit
X+
X
Reset
Answer:
Retype your question. That question made me nauseous
Same directions as question #1
Sn = ( -1 )n + 1
The sum of the sequence based on the function Sn = ( -1 )n + 1 will be -6.
How to depict the information?The formula for finding the nth term in an arithmetic sequence given as:
= a + (n - 1)d
Here, Sn is given as ( -1 )n + 1. This is used to illustrate the sum in the sequence. Based on the function given, let's assume that n = 5. Therefore, the 5th term will be:
= (-1)n + 1
= (-1)5 + 1
= (-1)6
= -6
Here is the complete question:
Find the 5th term of a sequence given the function Sn = ( -1 )n + 1.
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If A = (10, 4) and B = (2, 19) what is the length of AB
Hello,
Answer:
The length of AB is 17
Step-by-step explanation:
[tex]AB = \sqrt{(x_{B} -x_{A} ) {}^{2} + (y_{B} -y_{A} ) {}^{2} } [/tex]
[tex]AB = \sqrt{(2 - 10) { }^{2} + (19 - 4) {}^{2} } [/tex]
[tex]AB = \sqrt{( - 8) {}^{2} + (15) {}^{2} } [/tex]
[tex]AB = \sqrt{64 + 225} [/tex]
[tex]AB = \sqrt{289} [/tex]
[tex]\boxed{AB = 17}[/tex]
Two equations are given below:
m + 5n = 20
m = n − 4
What is the solution to the set of equations in the form (m, n)?
(3, 7)
(0, 4)
(5, 1)
(2, 6)
Answer:
(0,4)
Step-by-step explanation:
Because the problem gives you the value of what m would equal in terms of n you would substitute n - 4 for m in the equation above, resulting in:
n - 4 + 5n = 20
6n - 4 = 20
6n = 24
n = 4
Now that you know n = 4, you already can see that the answer would be (0,4), however to check you can substitute 4 for n into the second equation.
m = 4 - 4
m = 0
Because this results in m = 0, that tells you that (0,4) is the right answer.
Answer:
(0, 4)
Step-by-step explanation:
So you can solve the equation by substitution. The solution of a systems of equations, is when they both intersect, or when the (x, y) values are exactly equal, which is why I can substitute the m of the second equation into the first equation, because I'm looking for when they're equal, and that is when m is going to be equal in both equations, as well as the n value.
original equation:
m + 5n = 20
substitute n-4 as m in the equation
(n-4) + 5n = 20
simplify:
6n-4 = 20
add 4 to both equations
6n = 24
divide both sides by 6
n = 4
Now to find m, simply substitute 4 as n in either equation:
Original equation:
m = n - 4
substitute 4 as n
m = 4-4
m=0
so m=0, and n=4, so the solution in the form (m, n) = (0, 4)
if two men dig a well in 12 days how many days will it take 8 men to dig the same well if they work at the same rate
Answer:
3 days
Step-by-step explanation:
Time taken by 2 men to dig the well = 12 days
Therefore, Time taken by 1 man to dig the well = 2 * 12 = 24 days
So, Time taken by 8 men to dig the well = 2 * 12/8 days = 3 days
Answer:3 days
Step-by-step explanation: 2 people dig well=12 days right
1 person equal 2x12=24 days
8 people 2x12/8=3
25 yr old gets a 1 yr life insurance for $10000 at $100. Probability of death at age 25 is 0.0023 What is the company's expected gain
The expected gain of this company by the policy that they have here is given as $77.
How to solve the expected gain of the companyThe stated probability about a person dying is given as 0.0023
This tells us that out of this 10000, the number of people that would die would be 10000*0.0023 = 23 persons
Out of these 23, each of the number that would get the $10000 form the company.
23 * 10000 = $230000
Amount of policy sold at unit price is $100 for 10000
= 100 * 10000
= $1000000
The net earning = 1000000 - 230000
= 770000
The total earning = 770000/10000
= $77
Hence the expected gain of this company is going to be $77.
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2. Divide 4.62 10° by 4.2 10³
O 0.42-106
O 1.1 106
.
4.62 × 10⁹ divided by 4.2 × 10³ in standard form is 1.1 × 10⁶
How to divide in standard form?Lets divide 4.62 × 10⁹ by 4.2 × 10³
since, its division we will subtract the powers.
Therefore,
4.62 × 10⁹ ÷ 4.2 × 10³ = 4.62 × 10⁹ / 4.2 × 10³
Hence,
4.62 / 4.2 = 1.1
Therefore,
4.62 × 10⁹ / 4.2 × 10³ = 1.1 × 10⁹⁻³ = 1.1 × 10⁶
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If 10^3=1,000, write the logarithmic form that is equal to 3 below
Answer:
log10(1000)=3
Note: The ten is the base number and should be placed slightly lower and be smaller than shown.
Please help! Suppose....
Answer:
24
Step-by-step explanation:
We are given the logarithmic expression:
[tex]\displaystyle{\log_a \left(\dfrac{x^3y}{z^4}\right)}[/tex]
We are also given by the problem that:
[tex]\displaystyle{\log_a x = 3, \ \log_a y = 7, \ \log_a z = -2}[/tex]
From the expression, we will simplify it using two properties:
[tex]\displaystyle{\log_a MN = \log_a M + \log_a N}\\\\\displaystyle{\log_a \dfrac{M}{N} = \log_a M - \log_a N}[/tex]
Therefore, apply the properties to simplify:
[tex]\displaystyle{\log_a x^3y - \log_a z^4}\\\\\displaystyle{\log_a x^3 + \log_a y - \log_a z^4}[/tex]
Next, we will use another property to take an exponent as a coefficient:
[tex]\displaystyle{\log_a x^n = n\log_a x}[/tex]
Hence:
[tex]\displaystyle{3\log_a x + \log_a y - 4\log_a z}[/tex]
Substitute what are given in the problem and the answer will be:
[tex]\displaystyle{3(3)+7-4(-2)}\\\\\displaystyle{9+7+8 = 24}[/tex]
Hence, the answer is 24.
Simplify the following expression.
‐3 + 7(a – 3b – 1) – 4(10 – a + 2b)
Answer:
11a − 29b − 50
Step-by-step explanation:
Subtract 7 from − 3
7a − 21b − 10 − 40 + 4a − 8b
Add 7a and 4a
11a - 21b - 10 - 40 - 8b
Subtract 8b from -21b
11a - 29b - 10 - 40
Subtract 40 from -10
11a - 29b - 50
Answer:
11a - 29b - 50
Explanation:
⇒ ‐3 + 7(a – 3b – 1) – 4(10 – a + 2b)
distribute inside parenthesis
⇒ -3 + 7a - 21b - 7 - 40 + 4a - 8b
collect like terms
⇒ 7a + 4a - 21b - 8b - 3 - 7 - 40
add or subtract like terms
⇒ 11a - 29b - 50
What is the solution to this equation?
-1/5(x+1 1/4)=-2 1/2
[tex]\large\displaystyle\text{$\begin{gathered}\sf -\frac{1}{5}\left(x+1\frac{3}{4}\right)=-2\frac{1}{2} \end{gathered}$}[/tex]
Multiply both sides of the equation by 20, the lowest common denominator of 5,4,2.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{4+3}{4}\right)=-10(2\times2+1) } \end{gathered}$}[/tex]
Add 4 and 3 to get 7.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{7}{4}\right)=-10(2\times2+1) } \end{gathered}$}[/tex]
Use the distributive property to multiply −4 times x 4/7.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-4\times\left(\frac{7}{4}\right)=-10(2\times2+1) } \end{gathered}$}[/tex]
Multiply −4 by 4/7.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(2\times2+1) \ \ \to \ \ [Multiply \ 2\times2] } \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(4+1) \ \ \to \ \ [Add] } \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10\times5 \ \ \to \ \ [Multiply] } \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=-50 } \end{gathered}$}[/tex]
Add 7 to both sides.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-50+7 \ \ \to \ \ [Add] } \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-43 } \end{gathered}$}[/tex]
Divide both sides by −4.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{-43}{-4} } \end{gathered}$}[/tex]
The fraction [tex]\bf{\frac{-43}{-4}}[/tex] can be simplified to [tex]\bf{\frac{43}{4}}[/tex] by removing the negative sign from the numerator and denominator.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{43}{4} } \end{gathered}$}[/tex]
simplify
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{x=10\frac{3}{4} \ \ \to \ \ \ Answer } \end{gathered}$}[/tex]
{ Pisces04 }Answer:
[tex]\sf c)\ x=10\dfrac{3}{4}[/tex]
Step-by-step explanation:
Given equation:
[tex]\sf -\dfrac{1}{5}\left(x+1\dfrac{3}{4}\right)=-2\dfrac{1}{2}[/tex]
Step 1: Convert the mixed numbers into improper fractions.
[tex]\sf -\dfrac{1}{5}\left(x+\dfrac{4\times1+3}{4}\right)=-\dfrac{2\times2+1}{2}\implies -\dfrac{1}{5}\left(x+\dfrac{7}{4}\right)=-\dfrac{5}{2}[/tex]
Step 2: Distribute -⅕ through the parentheses.
[tex]\sf-\dfrac{1}{5}(x)+-\dfrac{1}{5}\left(\dfrac{7}{4}\right)=-\dfrac{5}{2}\\\\\implies -\dfrac{1}{5}x-\dfrac{7}{20}=-\dfrac{5}{2}[/tex]
Step 3: Rewrite the equation with a common denominator of 20.
[tex]\sf -\dfrac{1\times4}{5\times4}x-\dfrac{7}{20}=-\dfrac{5\times10}{2\times10}\\\\\implies -\dfrac{4}{20}x-\dfrac{7}{20}=-\dfrac{50}{20}[/tex]
Step 4: Multiply both sides by 20.
[tex]\sf 20\left(-\dfrac{4}{20}x\right)-20\left(\dfrac{7}{20}\right)=20\left(-\dfrac{50}{20}\right)\\\\\implies -4x-7=-50[/tex]
Step 5: Add 7 to both sides.
[tex]\sf -4x-7+7=-50+7\\\\\implies -4x=-43[/tex]
Step 6: Divide both sides by -4.
[tex]\sf \dfrac{-4x}{-4}=\dfrac{-43}{-4}\\\\\implies x=\dfrac{43}{4}[/tex]
Step 7: Convert the answer back into a mixed number.
[tex]\sf x=\dfrac{43}{4}\implies x=\dfrac{40+3}{4}\implies x=10\dfrac{3}{4}[/tex]
A ladder is 4 feet and 1 inch tall. How tall is it in inches
Answer:
[tex]\huge\boxed{\sf 49\ inches}[/tex]
Step-by-step explanation:
Length of the ladder = 4 feet 1 inch
We know that,
1 feet = 12 inchesSo,
4 feets = 12 × 4 inches
4 feets = 48 inches
So,
Length of the ladder:= 48 inches + 1 inch
= 49 inches
[tex]\rule[225]{225}{2}[/tex]
[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]
If a ladder is 4 feet and 1 inch tall, how tall is it in inches?
[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]
[tex]\boxed{\begin{minipage}{7cm} \\ The length of this ladder is 4 feet and 1 inch.\\The measure of one foot is 12 inches. \end{minipage}}[/tex]
Thus,
[tex]\fbox{The measure of 4 feet is 12*4=48 inches.}[/tex]
We add 1 inch more.
[tex]\bf{48+1=49\;inches}[/tex]
[tex]\cline{1-2}[/tex]
[tex]\bf{Result:}[/tex]
[tex]\bf{The\;ladder\;is\;49\;inches\;long.}[/tex]
[tex]\LARGE\boxed{\bf{aesthetic\not1\theta\ell}}[/tex]
Which is a solution of the system of equations?
O (1,3)
O (2, 2)
O (3, 1)
O (4,2)
(2 one)
(2,2) is the answer
What is the value of f(x) when x = 4 in the piecewise function f(x) = 2x² when x>4
4x when x < 4
Answer:
16
Step-by-step explanation:
f(x) = 2x² when x>4
We cannot use this expression of f to calculate f(4)
because ,this expression define f for the value of x
that are greater (not equal) than 4.
………………………………………………………
f(x) = 4x when x ≤ 4 , here x is can be equal to 4
(notice the sign ≤ )
Therefore
f(4) = 4 × (4) = 16
For the function f(x) = 2x² - 3x + 1, find the value of f(-2).
Answer:
f(-2)= 15
Step-by-step explanation:
f(-2)= 2(-2)² - 3(-2) + 1=15
Which of these expressions equal 15 when x = and y=3? Circle
all that apply.
4 (2y-4x)-1
(x²+1)+2x+3y
4x²+2y³-10
xy+3+20x
Answer:
Option 1: 4(2y - 4x) -1
Step-by-step explanation:
Hello!
Given:
x = 0.5y = 3Plug in the values for x and y into each equation and see which one outputs 15.
4(2y - 4x) -14(2(3) - 4(0.5)) - 14(6 - 2) - 14(4) - 116-115(x² + 1) + 2x + 3y(0.5² + 1) + 2(0.5) + 3(3)1.25 + 1 + 911.254x²+2y³-104(0.5²) + 2(3³) - 104(0.25) + 2(27) - 101 + 54 - 1055 - 1045xy+3+20x(0.5)(3) + 3 + 20(0.5)1.5 + 3 + 104.5 + 1014.5The only option that works is the first option.
Answer:
[tex]4 (2y-4x)-1[/tex]
Step-by-step explanation:
Given:
[tex]x =\dfrac{1}{2}[/tex][tex]y=3[/tex]To find which expressions equal 15, substitute the given values of x and y into the expressions and evaluate:
[tex]\begin{aligned}4(2y-4x)-1 &= 4 \left(2(3)-4 \left(\dfrac{1}{2}\right)\right)-1\\& = 4 \left(6-2\right)-1\\& = 4 \left(4\right)-1\\& = 16-1\\& = 15\\\end{aligned}[/tex]
[tex]\begin{aligned}(x^2+1)+2x+3y & = \left(\left(\dfrac{1}{2}\right)^2+1\right)+2 \left(\dfrac{1}{2}\right)+3(3)\\& = \left(\left\dfrac{1}{4}+1\right)+1+9\\& = \dfrac{5}{4}+1+1+9\\& = \dfrac{45}{4}\end{aligned}[/tex]
[tex]\begin{aligned}4x^2+2y^3-10 & = 4\left(\dfrac{1}{2}\right)^2+2(3)^3-10\\& = 4\left(\dfrac{1}{4}\right)+2(27)-10\\& = 1+54-10\\& = 45\end{aligned}[/tex]
[tex]\begin{aligned}xy+3+20x & = \left(\dfrac{1}{2}\right)(3)+3+20\left(\dfrac{1}{2}\right)\\& = \dfrac{3}{2}+3+10\\& = \dfrac{29}{2}\end{aligned}[/tex]
Therefore, the only expression that equals 15 is:
[tex]4(2y-4x)-1[/tex]
A bulldozer does 4,500 j of work to push a mound of soil to the top of a ramp that is 15 m high. the ramp is at an angle of 35° to the ground. how much force did the bulldozer apply to the mound of soil? round your answer to two significant figures. 300 n 370 n 520 n
The bulldozer will apply 520n of force to the mound of soil if the top of a ramp is 15 m high and ramp is at an angle of 35° to the ground.
Given Work = 4500 j , Height of top of a ramp is 15m , the ramp is at an angle 35° to the ground.
Work is the . product of the force vector and displacement vector.
[tex]W=F . x[/tex]
It is the multiplication of magnitudes of the vectors and the vectors and the cosine of the angle between them.
W=F * cos ∅
Displacement of the soil is 15 m . The force is parallel to the ramp. So the angle between the vectors is 90°-35°=55°.
Plugging in the values and solving for F:4500 J =F(15 m)( cos55 °)
F=523N
rounded to the significant figures the force is 520 n.
Hence bulldozer needs to apply force of 520 N.
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Answer:
520N
Step-by-step explanation:
Rule 1: Multiply by 2 then add 1 starting from 1.
Rule 2: Divide by 2 then add 4 starting from 40.
Sequence 1
Sequence 2
Ordered Pairs
The sequence 1 will be 3(n – 1) + 1. And the sequence 2 will be 9(n – 1) / 2 + 40.
What are sequence and series?A sequence is a list of elements that have been ordered sequentially, such that members come either before or after.
Let n = natural number.
The sequence 1 will be multiplied by 2 then add 1 starting from 1. Then we have
⇒ 2(n – 1) + 1(n – 1) + 1
⇒ 3(n – 1) + 1
The sequence 1 will be divided by 2 then add 4 starting from 40. Then we have
⇒ (n – 1 / 2) + 4(n – 1) + 40
⇒ 9(n – 1) / 2 + 40
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5. Art has three times as much money as Flora. Together they have
$180. How much money does each person have?
Choices for Flora's amount: 45, 60, 75
A motor vehicle is____________.
A motor vechicle is motor cycle
Find n in this equations: 9P(n,5)=P(n,3).P(9,3)
[tex]\begin{aligned}&9P(n,5)=P(n,3)\cdot P(9,3)\\&9\cdot\dfrac{n!}{(n-5)!}=\dfrac{n!}{(n-3)!}\cdot\dfrac{9!}{6!}\\&\dfrac{n!}{(n-5)!}=\dfrac{n!}{(n-3)!}\cdot7\cdot8\\&\dfrac{1}{(n-5)!}=\dfrac{56}{(n-3)!}\\&(n-4)(n-3)=56\\&n^2-3n-4n+12-56=0\\&n^2-7n-44=0\\&n^2-11n+4n-44=0\\&n(n-11)+4(n-11)=0\\&(n+4)(n-11)=0\\&n=-4 \vee n=11\end[/tex]
[tex]n[/tex] can't be negative, therefore [tex]n=11[/tex]
Answer:
Step-by-step explanation:
9P(n,5)=P(n,3).P(9,3)
9n(n-1)(n-2)(n-3)(n-4)=n(n-1)(n-2)×9×8×7
(n-3)(n-4)=8×7
(n²-4n-3n+12)=56
(n²-7n+12)=56
n²-7n+12-56=0
n²-7n-44=0
n²-11n+4n-44=0
n(n-11)+4(n-11)=0
(n-11)(n+4)=0
n=11,-4
n=-4(rejected as n is a natural number.)
Hence n=11
60 units and 14 Units per case. How many cases and how many units needed
There are 4.29 cases in the units
How to determine the number of cases?The given parameters are:
Units = 60
Rate = 14 units per case
The number of cases is then calculated as:
Case = Unit/Rate
This gives
Case = 60/14
Evaluate
Case = 4.29
Hence, there are 4.29 cases in the units
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Rewrite in simplest terms: -7(5v-10)-7v
Answer: -42v + 70
Step-by-step explanation: You’d multiply -7 with the figures in the brackets, then you’d group like terms then subtract -7v from -35v.
1. -35v + 70 - 7v
Negative multiplied by negative is a positive
2. -35v - 7v + 70
Group like terms
3. -42v +70
Subtract
Hope this was helpful
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation:}[/tex]
[tex]\mathbf{-7(5v - 10) -7v}[/tex]
[tex]\huge\textbf{Solving for your equation:}[/tex]
[tex]\mathbf{-7(5v - 10) -7v}[/tex]
[tex]\huge\textbf{Distribute -7 within the parentheses:}[/tex]
[tex]\mathbf{= -7(5x) -7(-10) - 7v}[/tex]
[tex]\mathbf{= -35v + 70 - 7v}[/tex]
[tex]\huge\textbf{Combine the like terms:}[/tex]
[tex]\mathbf{= (-35v - 7v) + (70)}[/tex]
[tex]\mathbf{= -35v - 7v + 70}[/tex]
[tex]\mathbf{= -42v + 70}[/tex]
[tex]\huge\textbf{Answer:}[/tex]
[tex]\huge\boxed{\mathsf{-42v + 7}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]