Answer:
5.71428571429
Step-by-step explanation:
yolanda drove 638 miles in 11 hours at the same rate how many miles would she drive in 13 hours
Answer: 754
Step-by-step explanation:
Divide 683/11 to get the unit rate of 58. That means she is driving 58mph.
Multiply that by how many hours you have, 13, and you get 754.
Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1 z=-0.92 z=1.23
The area of the shaded region for a z-score of -0.92 is 0.1788, which means the area that will be shadeded in the normal distribution graph is 17.88% of the total.
What is Normal Distribution?The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data distant from the mean. The normal distribution will show as a bell curve on a graph.
1.) The area of the shaded region for a z-score of -0.92 is 0.1788, which means the area that will be shadeded in the normal distribution graph is 17.88% of the total.
2.) The area of the shaded region for a z-score of 1.23 is 0.8907, which means the area that will be shadeded in the normal distribution graph is 89.07% of the total.
Now, the area of the shaded region will be,
Area = 0.8907 - 0.1788
= 0.7119
= 71.19%
Hence, the area of the shaded region is 71.19%.
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need help with this
The graph of R intersects with the horizontal or oblique asymptote at (-3, 0)
The horizontal asymptoteThe function is given as:
[tex]R(x)=\frac{x+3}{x\left(x+8\right)}[/tex]
Set the numerator to 0
[tex]R(x)=\frac{0}{x\left(x+8\right)}[/tex]
Evaluate
R(x) = 0
This means that the horizontal asymptote of R(x) is y = 0
The oblique asymptoteThe function is given as:
[tex]R(x)=\frac{x+3}{x\left(x+8\right)}[/tex]
The numerator has a degree of 1, while the denominator has a degree of 2
When the degree of the numerator is less than the degree of denominator, then the function has no oblique asymptote
Hence, the function has no oblique asymptote.
Intersection of the function and the horizontal asymptote
In (a), we have:
R(x) = 0
Substitute R(x) = 0 in [tex]R(x)=\frac{x+3}{x\left(x+8\right)}[/tex]
[tex]\frac{x+3}{x\left(x+8\right)} = 0[/tex]
Cross multiply
x + 3 = 0
Solve for x
x = -3
So, we have:
(x, y) = (-3, 0)
Hence, the graph of R intersects with the horizontal or oblique asymptote at (-3, 0)
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Find the probability of rolling a sum of 7 or 11. (sum of 7 or 11) = _______________
b. Find the probability of not rolling a sum of 7 nor 11. (not sum of 7 nor 11) = ______________
c. Find the odds against rolling a sum of 7 or 11.
d. In gambling the “odds against” (or “odds on”) usually expresses how much you can gain with a win for each
dollar you bet. If you make a $10 bet that you will roll a sum of 7 or 11, and the dice land on a sum of 7 or 11,
how much money will you win? Include your winnings plus your initial bet.
a. The probability of rolling a sum of 7 or 11. (sum of 7 or 11) is 2/9. b. the probability of not rolling a sum of 7 nor 11. (not sum of 7 nor 11) is 7/9.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events.
The probability of all the events occurring need to be 1.
The probability of getting a total of 7 = 6/36
The probability of getting total of 11 = 2/36
a. The probability of rolling a sum of 7 or 11. (sum of 7 or 11)
= 6/36 + 2/36
= 2/9
b. Find the probability of not rolling a sum of 7 nor 11. (not sum of 7 nor 11)
= 1- 2/ 9
= 7/9
c. Find the odds against rolling a sum of 7 or 11.
= 2/9
d. The money you will win, If you make a $10 bet that you will roll a sum of 7 or 11, and the dice land on a sum of 7 or 11.
10 x 2/9 = 20/9
10 x 7/9 = 70/9
Thus, The money you will win $10.
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witch hazel is listed at 12 per galon, less 34.5%. what is the net cost of the amount needed in filling the prescription
The net cost of the amount needed in filling the prescription is 7.86 per gallon
Net costCost of witch hazel = 12 per gallonDiscount = 34.5%Net cost = 12 - (34.5% of 12)
= 12 - (0.345 × 12)
= 12 - 4.14
= 7.86 per gallon
Therefore the net cost of the amount needed in filling the prescription is 7.86 per gallon
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Set up an algebraic equation and then solve.
The width of a rectangle is 14 units less than the length. If the area is 120 square
units, then find the dimensions of the rectangle.
Length:
Width:
Answer:
Width: 6
Length: 20
Step-by-step explanation:
So the area of a rectangle can be defined as: [tex]A=wl[/tex] where w=width and l=length.
In this case we don't know what the length is, so let's just say the length is the variable l, and since the width is 14 units less than the length, we can express it as (l-14). this gives us the equation: [tex]A=l(l-14)=l^2-14l[/tex]. We can solve for l, since we're given the area which is 120. So let's set the equation equal to that:
Original Equation:
[tex]A=l^2-14l[/tex]
Substitute 120 as A (given)
[tex]120=l^2-14l[/tex]
There is many ways to solve this equation: factoring, quadratic equation, completing the square etc... but in this case I'll just complete the square
Add (b/2)^2 to both sides to complete the square
[tex]120+(\frac{-14}{2})^2=l^2-14l+(\frac{-14}{2})^2[/tex]
Simplify
[tex]169=l^2-14l+49[/tex]
Rewrite right side a square binomial
[tex]169=(l-7)^2[/tex]
Take the square root of both sides
[tex]13=l-7\\[/tex]
Add 7 to both sides
[tex]20=l[/tex]
to solve for width simply subtract 14 from the length which is 20, so the width is 6
Width: 6
L: 20
Which is the graph of the line with equation y−6=4(x−3)+2?
Number graph ranging from negative four to three on the x axis and negative five to two on the y axis. A line is drawn on the graph that passes through the points (zero, negative four) and (one, zero).
Number graph ranging from negative three to three on the x axis and negative seven to one on the y axis. A line is drawn on the graph that passes through the points (zero, negative six) and (three, zero).
Number graph ranging from negative three to three on the x axis and negative two to five on the y axis. A line is drawn on the graph that passes through the points (negative one, zero) and (zero, four).
Number graph ranging from negative three to three on the x axis and negative two to five on the y axis. A line is drawn on the graph that passes through the points (negative three, zero) and (zero, four).
The linear equation passes through (0, -4) and (1, 0), so we conclude that the correct option is the first one.
Which is the graph of the given linear equation?
Here we have the linear equation:
y - 6 = 4*(x - 3) + 2
if we rewrite the line in slope-intercept form, we get:
y = 4x - 12 + 2 + 6
y = 4x - 4
Then the y-intercept of the line is (0, -4). And when x = 1, we have:
y = 4*1 - 4 = 0
So the line also passes through (1, 0).
Then the correct option is the first one:
"Number graph ranging from negative four to three on the x-axis and negative five to two on the y-axis. A line is drawn on the graph that passes through the points (zero, negative four) and (one, zero)."
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At a party, 75% of the people are adults and 25% are children. What is the simplest ratio of adults to children?
0.3:0.1
Step-by-step explanation:
first convert the % to decimals.
75%=0.75
25%=0.25
then look for a common factor and divide be that, in this case its 5.
0.75/5=0.15
0.25/5=0.5
now since these arent in the simplified form, you gotta divide again by 5.
0.15/5=0.3
0.5/5=0.1
The ratio to adults to children is 3:1
What is Ratio?A ratio is a comparison between two amounts that is calculated by dividing one amount by the other. The quotient a/b is referred to as the ratio between a and b if a and b are two values of the same kind and with the same units, such that b is not equal to 0. Ratios are represented by the colon symbol (:). As a result, the ratio a/b has no units and is represented by the notation a: b.
Given:
75% of the people are adults and 25% are children.
So, the ratio of adult to children
= (75%) / (25%)
= 0.75 / 0.25
= 75/25
= 3/1
Hence, the ratio to adults to children is 3:1
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What is the total finance charge for a $4,250 loan at 13.25% interest compounded monthly for 24 months? a. $25.47 b. $202.55 c. $611.20 d. $4,861.20 please select the best answer from the choices provided a b c d
The total finance charge is $611.20 (Option c) for this compound interest.
Data Given
Principal, P = $4250
Rate of Compound Interest, R = 13.25%
Time, t = 24 months, i.e., 2 years
Since it is compounded monthly, n = 12
Calculating the Total Finance Charge
We know that the formula for total amount of finance charge in a Compound Interest is,
[tex]A=P\frac{r(1+r)^{n} }{(1+r)^{n} - 1}[/tex]
Substituting the values of P, R and n, we get,
[tex]A=4250\frac{13.25(1+13.25)^{24} }{(1+13.25)^{24} - 1}[/tex]
[tex]A = 611.20[/tex]
Thus, the total finance charge is $611.20
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Please help me....trying to get my HS diploma, i did not graduate :(
A ball is thrown in air and it's height, h(t) in feet, at any time, t in seconds, is represented by the equation h(t)=−t2+7t. When is the ball higher than 10 feet off the ground?
A. 2
B. −5≤t≤−2
C. 2≤t≤5
D. −5
When t is between 2 and 5, the ball will be above 10 feet.so answer is:
C. 2 ≤ t ≤ 5
Given, height h(t) = ₋t² ₊ 7t
At what values of time t is the ball 10 feet above the ground = ?
To find out the time we need to set up an inequality.
Inequality expression is given as = ₋t² ₊ 7t ≥ 10
= ₋t² ₊ 7t ₋ 10 ≥ 0
= ₋(t² ₋ 7t ₊ 10) ≥ 0
= t² ₋ 7t ₊10 ≥ 0
Now, factorize the expression and get the factors.
= t² ₋ 2t ₋ 5t ₊ 10 ≥ 0
=t(t ₋ 2) ₋ 5(t ₋ 2) ≥ 0
=(t ₋ 2) (t ₋ 5) ≥ 0
Hence t value ranges from t = 2 and 5.
As a result, when t is between 2 and 5 seconds, the ball will be farther than 10 feet, 2 ≤ t ≤ 5
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Find an equation of the line passing through the given points. Use function notation to write the equation,
(-4,9) and (2,-3)
graph F(x) = |x - 1|
Draw the graph:
f(x) = |x-1|
f(x) = -(x-1) when x-1 is negative
f(x) = (x-1) when x-1 is positive
when x = -2, f(x) = 3
when x = -1, f(x) = 2
when x = 0, f(x) = 1
when x = 1, f(x) = 0
when x = 2, f(x) = 1
Using this values, draw the graph of f(x) = |x-1|
Hence, the required modulus of x-1 graph.
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Jim weighs 30 pounds less than Tom, and together they weigh 210 pounds. Let n = Tom's weight in pounds.
(n - 30) + n = 210
(n + 30) + n = 180
(n + 30) + n = 210
(n - 30) + n = 180
The equation that represents the given problem would be (n-30) + n = 210. The correct option is the option A; (n-30) + n = 210
What is a linear equation?A linear equation is an equation that has the variable of the highest power of 1.
The standard form of a linear equation is of the form Ax + B = 0.
From the given information,
n = Tom's weight in pounds
If Jim weighs 30 pounds less than Tom
Jim weighs will be (n - 30)
Thus,
The sum of their weight
(n-30) + n
∴ (n-30) + n = 210
Hence, the equation that represents the given problem would be (n-30) + n = 210. The correct option is the option A; (n-30) + n = 210
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The product of two number is 8 . If one of the numbers is 3 1/3 find the other number.
Hello!
Let the missing number be x.
⇒ 3 1/3 × x = 8
⇒ 10/3 × x = 8
⇒ x = 24/10
⇒ x = 12/5
The other number is [tex]\boxed {\frac{12}{5}}[/tex]
Answer:
The other number ia:
12/5
Step-by-step explanation:
3 1/3 = 3 + 1/3 = 9/3 + 1/3 = 10/3
a * 10/3 = 8
a = 8*3/10
a = 24/10
a = 12/5
a = 2.4
Check:
(12/5) * (10/3) = 8
(12*10) / (5*3) = 8
120 / 15 = 8
Find the equation of the plane passing through the points A=(1,1,1), B=(1,4,5), C=(−3,-2,0).
Find the area of the triangle the 3 points from the first equation.
Find the angle between the 2 vectors; (1) from A to B and (2) from C to B.
Take any two pairs of the given points and make vectors out of them. For example, the vector from A to B is
[tex]\vec v_1 = \langle 1,4,5\rangle - \langle 1,1,1\rangle = \langle0,3,4\rangle[/tex]
and the vector from A to C is
[tex]\vec v_2 = \langle -3,-2,0\rangle - \langle1,1,1\rangle = \langle-4,-3,-1\rangle[/tex]
These vectors lie in the same plane (the one we want). We can get a third vector that is normal to the plane by taking their cross product (details omitted).
[tex]\vec n = \vec v_1 \times \vec v_2 = \langle 9,-16,12 \rangle[/tex]
If [tex]\vec u = \langle x,y,z\rangle[/tex] is an arbitrary vector, then the vector from any of the points A, B, or C to [tex]\vec u[/tex] will lie in our plane. That is, if we start from A,
[tex](\vec u - \langle1,1,1\rangle) \cdot \vec n = 0[/tex]
and this reduces to the equation of the plane,
[tex]\langle x - 1, y - 1, z - 1 \rangle \cdot \langle 9, -16, 12 \rangle = 0[/tex]
[tex]9 (x - 1) - 16 (y - 1) + 12 (z - 1) = 0[/tex]
[tex]\boxed{9x - 16y + 12z = 5}[/tex]
Area of triangle ABCThis follows immediately from the cross product identity
[tex]\|\vec x \times \vec y\| = \|\vec x\| \|\vec y\| \sin(\theta)[/tex]
where [tex]\theta[/tex] is the angle between [tex]\vec x[/tex] and [tex]\vec y[/tex]. The left side corresponds to the area of the parallelogram spanned by [tex]\vec x[/tex] and [tex]\vec y[/tex]; half of this area would be that of a triangle. (see attached)
In our case, we have
[tex]\|\vec n\| = \|\vec v_1 \times \vec v_2\| = \sqrt{481}[/tex]
so the area of ABC is [tex]\boxed{\dfrac{\sqrt{481}}2}[/tex].
Angle between A to B and between C to BWe already know the first vector, [tex]v_1[/tex].
The vector from C to B is
[tex]\vec v_3 = \langle 1,4,5 \rangle - \langle -3,-2,0 \rangle = \langle 4, 6, 5 \rangle[/tex]
Recall the dot product identity,
[tex]\vec x \cdot \vec y = \|\vec x\| \|\vec y\| \cos(\theta)[/tex]
Then
[tex]\vec v_1 \cdot \vec v_3 = \|\vec v_1\| \|\vec v_3\| \cos(\theta) \implies \cos(\theta) = \dfrac{38}{5\sqrt{77}} \implies \theta \approx \boxed{29.9914^\circ}[/tex]
100POINTS WHY NOT
sally took money from her bank account to go out of town for an audition.she spot 54$ for a round trip ticket and 1/2 of the remaining money on her hotel bill.she spent $7.90 for food and arrived home with $15.10.How much money did Sally take from her bank account??
Answer:
$100
Step-by-step explanation:
Given information:
$54 = cost of ticketCost of hotel = 1/2 remaining money after purchase of ticket$7.90 = cost of food$15.10 = remaining moneyLet x = money taken from bank account
If Sally paid $54 for her ticket, then the money remaining at that point can be defined as: [tex]x-54[/tex]
If the cost of the hotel was half of the remaining money, then:
[tex]\textsf{Cost of hotel}=\dfrac{1}{2}(x-54)}[/tex]
To find how much money Sally took from her bank account, create an equation with the given information and solve for x.
[tex]\implies \textsf{Money in bank} - \textsf{ticket} - \textsf{hotel} - \textsf{ food} =\textsf{remaining money}[/tex]
[tex]\implies x - 54 - \dfrac{1}{2}(x - 54)-7.90=15.10[/tex]
[tex]\implies x - 54 - \dfrac{1}{2}x+27-7.90=15.10[/tex]
[tex]\implies \dfrac{1}{2}x-34.90=15.10[/tex]
[tex]\implies \dfrac{1}{2}x=50[/tex]
[tex]\implies x=100[/tex]
Therefore, Sally took $100 from her bank account.
Radical Equations: How do I solve this?
Answer:
(B). roots
Step-by-step explanation:
(a ± b)² = a² ± 2ab + b²
~~~~~~~~
( [tex]\sqrt{4x+5}[/tex] - [tex]\sqrt{x-1}[/tex] )² = ( [tex]\sqrt{x+4}[/tex] )²
( [tex]\sqrt{4x+5}[/tex] )² - 2[tex]\sqrt{(4x+5)(x-1)}[/tex] + ( [tex]\sqrt{x-1}[/tex] )² = ( [tex]\sqrt{x+4}[/tex] )²
4x + 5 - 2[tex]\sqrt{(4x+5)(x-1)}[/tex] + x - 1 = x + 4
2[tex]\sqrt{(4x+5)(x-1)}[/tex] = 4x + 5 + x - 1 - x - 4
[tex]\sqrt{(4x+5)(x-1)}[/tex] = 2x
( [tex]\sqrt{(4x+5)(x-1)}[/tex] )² = ( 2x )²
( 4x + 5 )( x - 1 ) = 4x²
4x² + x - 5 = 4x² ⇒ x = 5
what is the equation of the line that is paralle to y=3x-8 and passes thur the point (4,-5)
⊰_________________________________________________________⊱
Answer:
The equation is-: y=3xStep-by-step explanation:
[tex]\large\displaystyle\text{$\begin{gathered} \sf{Substitute \ the \ values \ into \ the \ formula \ y-y_1=m(x-x_1)} \\ \sf {parallel \ lines \ have \ same \ slopes, \ thus} \\ \sf{slope \ of \ the \ 2nd \ line = 3}\\ \sf{now \ substitute \ the \ values} \\ \sf {y-(-5)=3(x-4)}\\ \sf{y+5=3(x-4) (It's \ Point-Slope\;Form, \ see \ below \ for \ slope-intercept)}\\ \sf {y+5=3x-12} \\ \sf{y=3x-12-5} \\ \sf{y-3x-17} \end{gathered}$}}[/tex]
[tex]\pmb{\tt{done \ !!}}[/tex]
⊱_________________________________________________________⊰
ram takes 20 minutes to inspect a car, while robert takes only 18 minutes.if both start inspecting car at 8.00 hours what is the first time at which both will have finished inspecting a car at the same point time
Answer:
11:00
Step-by-step explanation:
here we have to calculate the LCM of 20 and 18
20 = 2² × 5
18 = 2 × 3²
Then
LCM(20 , 18) = 2² × 5 × 3² = 20 × 9 = 180
The
After 180 minutes (3 hours) they will have finished inspecting a car at the same point time.
Then
At 8:00 + 3 = 11:00 Ram and Robert will have finished inspecting a car at the same point time.
Adi used algebra tiles to represent the product (negative 2 x minus 1)(2 x minus 1).
The true statement is (b) use of incorrect header
How to determine the true statement?The product expression is given as:
(-2x - 1)(2x - 1)
Expand the expression
(-x - x - 1)(x + x - 1)
This means that the header of the algebra tiles would be:
-x, -x, 1 and x, x and -1
From the figure, we can see that this is incorrectly represented
Hence, the true statement is (b)
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A well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece. What is the probability of getting a cookie with no more than 3 chips? Round your answer to four decimal places.
The probability of getting a cookie with no more than 3 chips is 0.714.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece.
Using poison ratio:
[tex]\rm P (X = k) = \dfrac{\lambda^k e^{-\lambda}}{k!}[/tex]
λ is the mean number of chocolate chips in a piece
[tex]\rm P (X = 6) = \dfrac{6^k e^{-6}}{k!}[/tex]
P(X ≥ 5) = 1 - P(X < 5)
P(X ≥ 5) = 1 - P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
[tex]\rm P(X \geq 5) = 1-[\dfrac{6^0 e^{-6}}{0!}+\dfrac{6^1 e^{-6}}{1!}+\dfrac{6^2 e^{-6}}{2!}+\dfrac{6^3 e^{-6}}{3!}+\dfrac{6^4 e^{-6}}{4!}][/tex]
After solving;
P(X ≥ 5) = 0.714
Thus, the probability of getting a cookie with no more than 3 chips is 0.714.
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Translate the following from words to an algebraic expression or equation,
denoting the unknown by n.
52a. The express train travels 5 mph faster than the local train.
52b. The length of a rectangle is 7 inches more than its width.
52c. The area of a triangle, if the altitude is twice the base
52d. The sum of 3 consecutive even numbers
52e. 15% of the amount by which a number exceeds 10,000
Answer:
a. n+5
b. n+ 7
c. 1\2(n×2n)
d. n +n+1 n+2
One half of 8 5/9 is
Answer:
Step-by-step explanation:
Answer:
4 5/18 ≈ 4.278
Step-by-step explanation:
1/2 of 8 5/9
8 5/9 = 77/9
1/2 x 77/9
= 77 over 18
= 77/18
= 4 and 5/18
≈ 4.278
Hope this helps!
Help, please
A rectangular room is 1.2 times as long as it is wide, and its perimeter is
30 meters. Find the dimension of the room.
length___
Width is____
The width of the rectangle is 6.82 meters, while the length of the rectangle is 8.184 meters.
What is a rectangle?A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.
Let the width of the rectangle be x.
Given that a rectangular room is 1.2 times as long as it is wide. Therefore, the length is 1.2x.
Perimeter = 2(x + 1.2x)
30 meters = 2(2.2x)
30 = 4.4x
x = 6.82
Hence, the width of the rectangle is 6.82 meters, while the length of the rectangle is 8.184 meters.
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Q. Unscramble the following term related to algebra:- ROTPORAE.
Answer:
operator
Step-by-step explanation:
Operator is represented as any symbol that indicates an operation to be performed.
Examples:
- Square root of√x, which indicates the square root is to be taken
- d/dx, which indicates differentiation with respect to x is to be performed
Answer:
OPERATION
OF ALGEBRA IN MATH
A suitcase measures 18 inches long and 12 inches high. What is the diagonal length of the suitcase?
Answer:
21.6 in
Step-by-step explanation:
Imagine the suitcase as a rectangle, with length of 18 in and width of 12 in. In order to find the diagonal length, simply use the Pythagorean Formula, a^2 + b^2 = c^2, and solve for c!
In this case, a = 18 and b = 12.
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solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x < 360°?
Answer:
Step-by-step explanation:
cos (x/2)=cos x+1
cos (x/2)=2cos ²(x/2)
2 cos²(x/2)-cos (x/2)=0
cos (x/2)[2 cos (x/2)-1]=0
cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)
x/2=2nπ+π/2,2nπ+3π/2
x=4nπ+π,4nπ+3π
n=0,1,2,...
x=π,3π
or x=180°,540°,...
180°∈[0,360]
so x=180°
or
2cos(x/2)-1=0
cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)
x/2=360n+60,360n+300
x=720n+120,720n+300
n=0,1,2,...
x=120,300,840,1020,...
only 120° and 300° ∈[0,360°]
Hence x=120°,180°,300°
1. How many variables are involved in the chi-square test?
2. Which type of chi-square test is this?
A.goodness of fit B.test of independence
3. How many degrees of freedom are involved?
4. Using the chi-square critical values table is the result of this rest statistically significant?
A. Yes B.No
The result of the respective questions are:
This chi-square test only takes into consideration one variable.The type of chi-square test this is is a Goodness of Fitdf= 3NOHow many variables are involved in the chi-square test?a)
This chi-square test only takes into consideration one variable.
b)
The type of chi-square test this is, is a Goodness of Fit
To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.
The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.
c)
Parameter
n = 4
Therefore
Degrees of freedom
df= n - 1
df= 4 - 1
df= 3
d)
In conclusion
Parameters
[tex]\alpha = 0.05[/tex]
df = 3
Hence
Critical value = 7.814728
Test statistic = 6.6
Test statistic < Critical value, .
NO, the result of this test is not statistically significant.
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x/4 + 10 = 1
Please include steps
Answer:
x = -36
Step-by-step explanation:
x/4 + 10 = 1
To solve this two step equation, first subtract 10 from each side.
x/4 + 10 -10 = 1-10
x/4 = -9
Then multiply each side by 4 to isolate x
x/4 * 4 = -9*4
x = -36
Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future; however, its value depreciates monthly. The expression shows the depreciated sales value of the gadget: 2,020 − 22m
What does the coefficient of the expression represent? The number of months Megan will wait to sell the gadget The monthly depreciation value of the gadget The amount of money Megan will get when she sells the gadget The original value of the gadget
The coefficient (m) of the expression represents: C. the monthly depreciation value of the gadget.
What is depreciation?Depreciation can be defined as a process in which the monetary value of a physical asset decreases or falls over a period of time, especially due to wear and tear.
In this scenario, we can infer and logically deduce that the coefficient (m) of the given expression represents the monthly depreciation value of Megan's gadget.
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Answer:
it is C
Step-by-step explanation:
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