When a neon atom is electrified, electrons jump to higher orbits. One of the electrons falls from an outside orbit to an inside orbit, giving off red light with a wavelength of 6.34 x 10^–7m. Calculate the frequency of the red light given off by the neon atom.
Find the energy of a photon of light if the wavelength of the light wave is 4.65 x 10^–7m.
An automobile has a wavelength that is not measurable by human standards. If the car has a mass of 2000 lbs (905 kg) and travels at 30 miles/hr (26.8 m/s), calculate the wavelength of the car.
A local radio station can be tuned in by dialing your radio to a frequency of 1175 kHz. Calculate the energy of the wave. (Hint: kHz means 1 x 10^3 Hz.)
An element has an electron configuration that ends in 5d^4. Which column is it in?
If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.
What is energy level?The energy level refers to the position where an electron is found in the atom. If the electron moves from a higher to a lower energy level, energy is evolved as light.
Now;
v = λf
f = v/λ
f = 3 * 10^8 m/s/6.34 x 10^–7m
f = 4.7 * 10^14 Hz
From E = hc/λ
E = 6.6 * 10^-34 * 3 * 10^8/4.65 x 10^–7m
E = 4.3 * 10^-19 J
From;
λ = h/mv
λ = 6.6 * 10^-34Js/905 kg * 26.8 m/s
λ = 2.27 * 10^-38 m
Given that;
E = hf
E = 6.6 * 10^-34Js * 1175 x 10^3 Hz
E = 7.8 * 10^-28 J
If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.
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You are asked to make 500 mL of a 1.2% (w/v) agarose solution. How much grams of agarose must you weigh out to make this
The grams of agarose that are weighed out are 6 g.
The concentration of a solution is expressed in a number of ways like molarity, molality, normality. It is also expressed as w/v, w/w, and v/v.
In w/v, the w represents the weight of the solute and v is the volume of the solution.
w/v = Mass of the solute/volume of the solution
Calculations:
It is given that w/v is 1.2%. This means that 1.2 g of agarose is present in 100 mL of the solution or 1.2 g/100 mL.
The weight of agarose present in 500 mL of the solution is calculated as:
Mass of agarose = (1.2 g/100 mL) x 500 mL
= 6 g
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how did scientists respond to Copernicus's discovery
Answer:
Scientists were slow to let go of the current theories.
Explanation:
this is correct
How much heat (in kJ k J ) is evolved in converting 2.00 mol m o l of steam at 135 ∘C ∘ C to ice at -42 ∘C ∘ C ? The heat capacity of steam is 2.01 J/(g⋅∘C) J / ( g ⋅ ∘ C ) , and that one of ice is 2.09 J/(g⋅∘C) J / ( g ⋅ ∘ C ) .
The total quantity of heat evolved in converting the steam to ice is determined as -12,928.68 J.
Heat evolved in converting the steam to ice
The total heat evolved is calculated as follows;
Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)
where;
Q is heat evolvedQ = = mcΔθ
where;
m is mass, (mass of water = 18 g/mol)c is specific heat capacity, Δθ is change in temperatureQ(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)
Q(tot) = -12,928.68 J
Thus, the total quantity of heat evolved in converting the steam to ice is determined as -12,928.68 J.
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CH3CH2OH+3O2 2CO2+3H20 ( ethanol) explain this equation! if u didn't understand the wat I have written could u text in personal will sent u photo of questions
The equation is given is of combustion of ethanol.
Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.
The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.
Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.
The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.
To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.
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A sample of gas occupies a volume of 72.0 mL . As it expands, it does 141.2 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas?
The final volume of the gas is 73.359 mL
Given :
A sample gas has an initial volume of 72.0 mL
The work done = 141.2 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since, the process does 141.2 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm; we have
External Pressure P[tex]ext[/tex]:
[tex]P ext[/tex] = 783 torr × [tex]\frac{1 atm}{760 torr}[/tex]
[tex]Pext[/tex] = 1.03 atm
The work done W = [tex]Pext V[/tex]
The change in volume ΔV= [tex]\frac{W}{Pext}[/tex]
ΔV = [tex]\frac{141.2 J \frac{1 L atm}{101.325 J} }{1.03 atm}[/tex]
ΔV = [tex]\frac{0.0014}{1.03}[/tex]
ΔV = 0.001359 L
ΔV = 1.359 mL
The initial volume = 72.0 mL
The change in volume V is ΔV = V₂ - V₁
- V₂ = - ΔV - V₁
multiply both sides by (-), we have:
V₂ = ΔV + V₁
= 1.359 mL + 72.0 mL
= 73.359 mL
Therefore, the final volume of the gas is 73.359 mL .
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Ethanol is highly toxic if it is consumed in large quantities. Although it is the second least toxic of the five alcohols discussed in this case, the ingestion of large quantities of ethanol is not safe. One serious problem with ethanol consumption is how the quantity is conveyed to the consumer. For example, American malt liquor can be sold in 23.5 fl. oz. (695 mL) cans and is 12% volume per volume (v/v) ethanol. Although these cans are labeled as containing multiple servings, many young people consider one can to be a single serving. Drinking two cans of this beverage can result in an accidental overdose of ethanol. Two cans may not seem like much until you do the math. In the previous question, you determined that the total volume of pure ethanol in a 695 mL can of American malt liquor is 83.4 mL. To better understand its significance, consider how this volume of ethanol compares with other alcoholic beverages. Calculate the total volume of ethanol in a standard 25.4 fl. oz (750 mL) bottle of liquor (e.g., whiskey, vodka, rum, etc.), which is typically 40% (v/v) ethanol. Enter your answer in milliliters. pure ethanol in liquor: mL Now calculate the total volume of ethanol in a typical 12 fl. oz (354.8 mL) can of light beer, which is 4% (v/v) ethanol. Enter your answer in milliliters. pure ethanol in light beer:
A significant MOE exists compared to developmental toxicity effect levels.
Blood alcohol levels from ABHS approximate consumption of non-alcoholic beverages.
No significant risk of developmental toxicity is expected from ABHS use.
Ethanol-based topical antiseptic hand rubs, commonly referred to as alcohol-based hand sanitizers (ABHS), are routinely used as the standard of care to reduce the presence of viable bacteria on the skin and are an important element of infection control procedures in the healthcare industry.
There are no reported indications of safety concerns associated with the use of these products in the workplace. However, the prevalence of such alcohol-based products in healthcare facilities and safety questions raised by the U.S. FDA led us to assess the potential for developmental toxicity under relevant product-use scenarios.
Estimates from a physiologically based pharmacokinetic modeling approach suggest that occupational use of alcohol-based topical antiseptics in the healthcare industry can generate low, detectable concentrations of ethanol in blood.
This unintended systemic dose probably reflects contributions from both dermal absorption and inhalation of the volatilized product.
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Compare the concentration of 1 mol of NaCl and 1 mol of MgSO4 ?
The molarity of the NaCl and [tex]MgSO_4[/tex] will be the same.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
1 mol of NaCl in 1 litre of solution gives 1 M.
1 mol of [tex]MgSO_4[/tex] in 1 litre of solution gives 1 M.
Hence, the molarity of the NaCl and [tex]MgSO_4[/tex] will be the same.
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How many grams of fluorine,
F2, are needed to generate 7.65
moles carbon tetrafluoride, CF4?
581.4g of F2 is needed to generate 7.65 mol of CF4.
The reaction of formation of CF4 is-
C(S) +2F2(g) -> CF4
So according to this equation 2 mol of F2 is needed to form 1 mol of CF4 thus to produce 7.65 mol of CF4 we need 15.3 mol of F2 .
And 1 mol F2= 38g of F2
so 15.3 mol F2 means 581.4 g of F2.
As no of mol = [tex]\frac{given mass}{molar mass}[/tex] . \
What is the formation reaction?
When 1 mol of any substance is produced from its elements in their standard state.
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The molar mass of magnesium (mg) is 24.30 g/mol. there are 6.02 times. 1023 atoms in 1 mol. how many atoms are present in 48.60 g of mg? 3.32 times. 10–24 atoms 1.96 times. 10–21 atoms 1.20 times. 1024 atoms 7.11 times. 1026 atoms
Correct option:
Number of atoms is given by option is C, i.e. [tex]1.20\times10^{24}\,atoms[/tex].
Calculation of number of atoms:
As, mole tells about the amount of substance.
Chemical units known as moles are employed to calculate the mass or molecular mass of a compound, molecule, or atom. For instance, there is one mole in 12 grams of carbon.
[tex]1 mole= 6.022\times10^{22}\,atoms/molecules/ions[/tex]
Molecular mass of Mg= 24.30 g/mol
Given weight of Mg= 48.60 g
Atoms present in 48.60 g= ?
[tex]6.022\times10^{23}= N_A[/tex](Avogadro's number)
[tex]n=\frac{m}{M}=\frac{Given\,number\,of\,atoms}{N_A}\\\\\frac{m}{M}=\frac{N}{N_A}\\\\\frac{48.60}{24.30}=\frac{N}{6.022\times 10^{23}}\\\\ N= 2\times 6.022\times10^{23}\\N= 12.044\times10^{23}\,atoms[/tex]
[tex]N= 1.2\times10^{24}\,atoms\,of\,Mg[/tex]
So, the correct option is C.
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Answer: C
Explanation: 1.20 x 10^24 atoms
The activation energy of a first order reaction is 83.5kj/mol. the rate constant is 3.54x10^-5s^-1 at 45 c. what is the rate constant at 65 c?
Rate constant:
The rate constant at 65°C is [tex]k_{2} = 3.069 x 10^{-6}[/tex]
What is the Arrhenius equation?
Sometimes the Arrhenius equation is written as [tex]k = Ae^{-E/RT}[/tex], where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.
According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.
Calculation:
According to the Arrhenius equation for variable temperature:
[tex]ln(\frac{k2}{k1}) = - \frac{Ea}{R} (\frac{1}{T2} - \frac{1}{T1})[/tex]
The temperatures are given to be computed in kelvins and then both temperature and activation energy will be put in the above equation, we get,
[tex]ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = -\frac{89000J/mol}{8.314J (mol* K)} ( \frac{1}{338.15K} - \frac{1}{318.15K} \\ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = 2.1602\\k_{2} = 3.54 x 10^{-5} *exp(2.1602)\\k_{2} = 3.54 x 10^{-5} *8.67\\ k_{2} = 30.69 x 10^{-5}\\k_{2} = 3.069 x 10^{-6}[/tex]
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Cell Membranes
Write your procedure. List each step so that another student could follow the procedure and repeat your experiment.
The procedure to perform a cell membrane experiment is to:
Use beetroots cells to measure the permeability of the membraneThis is done to check the content of the pigment It is also meant to check the pigment leaks out of the cells.What is a Cell Membrane?This refers to the semi-permeable membrane that is around the cytoplasm of a cell.
Hence, we can see that the main purpose of the cell membrane practical experiment is to test the permeability of a membrane and to see the amount of liquid that a membrane can hold.
Please note that your question is incomplete so I gave you a general overview to get a better understanding of the concept.
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As the atomic radius_______, electron affinity _______. Select the correct answer below: decreases, decreases increases, decreases increases, increases increases, stays the same
Calculate the number of milliliters of 0.444 M required to precipitate all of the ions in 107 mL of 0.699 M solution as . The equation for the reaction is:
333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.
What is Stoichiometry ?Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.
What is Molarity ?Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]
Now put the values in above formula to find the number of moles of Pb(NO₃)₂
Molarity = [tex]\frac{\text{Moles of}\ Pb(NO_{3})_2}{\text{Volume of solution (in L)}}[/tex]
Moles of Pb(NO₃)₂ = Molarity × Volume
= 0.699M × 0.107 L [1ml = 0.001 L]
= 0.074 moles
The given balanced chemical equation is
Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)
The mole ratio of KOH to Pb(NO₃)₂ is 2:1.
The mole of KOH = 0.074 mol × 2
= 0.148 moles
Now put the value in above formula to find the volume of KOH
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]
Volume of KOH = [tex]\frac{\text{Number of mole of KOH}}{\text{Molarity}}[/tex]
Volume of KOH = [tex]\frac{0.148\ mol}{0.444\ M}[/tex]
= 0.333 L
= 333.3 mL [1L = 1000 mL]
Thus from the above conclusion we can say that 333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.
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Question: Calculate the number of milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂. The equation for the reaction is:
Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)
_________ mL KOH.
there are 3.0 x 10^22 molecules of sucrose in a sample. how many grams of sucrose is this? The molar mass of C12H22O11 is about 342 g
The amount of sucrose in the sample would be 17 grams
Number of molecules of substancesThere are 6.022 x [tex]10^{23}[/tex] molecules in 1 mole of every substance.
3.0 x [tex]10^2^2[/tex] molecules will, therefore, be:
1 x 3.0 x [tex]10^2^2[/tex]/6.022 x [tex]10^{23}[/tex] = 0.0498 moles
Mass of 0.0498 moles sucrose = 0.0498 x 342 = 17 grams
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The molecule CH3-CH2-CH2-CH2-CH2-CH2-CH3CH3-CH2-CH2-CH2-CH2-CH2-CH3 is best described as a(n) ________.
The given molecule is best described as an organic compound especially an alkane.
What are organic compounds?The organic compounds are those chemical compounds which has carbon-carbon or carbon-hydrogen bonds.
Some of the organic compounds are Carbohydrates, lipids, proteins, nucleic acids etc.
What are alkanes?Alkanes are organic compounds that has straight chain or linear chain between carbon atoms. That is there will be single bonded carbon atoms in the alkanes. So, these are also called saturated compounds.
The general formula for these compounds is CₙH₂ₙ₊₂.
The general formula for the given molecule is C₇H₁₆.
Therefore, the given molecule is best described as an organic compound or as an alkane.
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(1) (a) In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100KJ and that of the product is 54KJ. The energy content of the activated complex is 210KJ. (i) Draw an energy profile diagram for the reaction. (ii) Determine the: I. activation energy of the reaction. II. enthalpy change A H of the reaction. (iii) Write a balanced equation for the reaction. (iv) State whether the reaction is exothermic or endothermic. (v) Give a reason for the answer given in 1(a)(iv). (b) (i) If sodium reacts with cold water, state ONE observation that would be made as the reaction Proceeds. (ii) Write a balanced chemical equation for the reaction in 1(a)(i) (iii) Calculate the volume of gas produced at s.t.p if 3.0g of sodium reacts with excess water. [Molar volume of gas at s.t.p = 22.4dm³; H = 1.0, O=16.0, Na = 23.0] (c) Name ONE allotrope of oxygen.
Answer:
a is my answer
Explanation:
Put 10 milliliters of distilled water into a second test tube. Label it test tube 2, and place it in the rack. 2. Record the temperature of the water. 3. Measure 2.00 grams of anhydrous copper(II) sulfate (white powder) into a weighing boat. 4. Pour the anhydrous copper(II) sulfate into test tube 2. 5. Measure the final temperature of the solution in test tube 2. Watch the thermometer for a couple minutes, and record the highest temperature it reaches. 6. Calculate the change in temperature. What is the initial temperature in Celsius? What is the final temperature in Celsius?
The reaction is an exothermic reaction and the temperature change is calculated using the formula below:
Change in temperature = final temperature - initial temperatureWhat kind of heat change occurs when anhydrous copper(II) sulfate is dissolved in water?When, anhydrous copper(II) sulfate is dissolved in water, heat is given off to the surroundings and the temperature of the solution formed is higher than the temperature of the water used in dissolving it.
This type of reaction is known as an exothermic reaction.
The temperature increase is calculated using the formula below:
Change in temperature = final temperature - initial temperatureIn conclusion, exothermic reactions result in increase in temperature of their surroundings.
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Answer:my answer
Explanation:
EVALUATE:
Directions: For the following exercise, you will draw particle diagrams. A particle diagram uses
spheres to show atoms and how they are bonded when in elements compounds and mixtures.
A. Monoatomic particle diagrams will contain only one atom.
B. Diatomic particle diagrams contain two of the same atoms.
C. Make legends for each element/compound/mixture for each box.
D. Make at least 3 particle diagrams for each problem
The atoms present in the elements, compounds and mixtures are represented in the diagrams by spheres.
What is are elements, compounds and mixtures?Elements are pure substances consisting of the same atoms entirely.
Compounds are formed from two or more elements chemically combined together.
Mixtures are two or more substances physically combined together.
The atoms present in the elements, compounds and mixtures are shown in the attached image.
In conclusion, atoms of the same kind are present in elements whereas atoms of different kinds are found in compounds and mixtures.
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what is the main ore o
f copper
Answer:
The principal copper ore mineral is chalcopyrite (CuFeS2), which is commonly smelted to yield a matte containing ~50% copper.
Answer:
chalcopyrite
Explanation:
The principal copper ore mineral is chalcopyrite (CuFeS2),
If 185 g of wax c22h44 burns how many litres of oxygen gas were used up .assume conditions in lab are 101kpa and 25 degree celcius
How many liters of oxygen gas were used up?
If 185 g of wax [tex]C_{22}H_{44}[/tex] burns, 13.73 L of oxygen gas is used.
An ideal gas equation is:
The macroscopic characteristics of ideal gases are related to the ideal gas law (PV = nRT). Gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume).
First, determine the gas's moles using the gas law.
PV = nRT, where n is the number of moles and R is the gas constant. Next, divide.
To obtain molar mass, multiply the given mass by the number of moles.
Data provided:
P= 101kpa =0.996792 atm
V= ?
R= 0.082057338 L atm K[tex]^{1} mol^{-1}[/tex]
T=25 +273 =298 K
Moles =?
Moles = mass/molar mass = 185g/308.6
Moles =0.56
Putting value in the given equation:
PV/RT =n
0.56 = [tex]\frac{0.996792 atm XV}{0.082057338 L atm K^{1} mol^{-1} X 298}[/tex]
13.73 L =V
13.73 L of oxygen gas was used up if 185 g of [tex]C_{22}H_{44}[/tex] wax burns.
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A certain first-order reaction a → b is 25% complete in 42 min at 25°c. What is the half-life of the reaction?.
Half life of the reaction is :-101.9 min
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
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If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction
If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.
What is Stoichiometry ?Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
2NaHCO₃ → Na₂CO₃ + CO₂ + H₂O
According to Stoichiometry
= [tex]2.864\ g\ NaHCO_{3} \times \frac{1\ \text{mole}\ Na_2CO_3}{105.9\ g/mol} \times \frac{1\ \text{mole}\ CO_2}{2\ \text{mole}\ NaHCO_3} \times \frac{44\ g \ CO_2}{1\ \text{mole}\ CO_2}[/tex]
= 0.59 g
Thus from the above conclusion we can say that If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.
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Question: If you started with 2.486 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction? Show your work.
NaHCO₃ → Na₂CO₃ + CO₂ + H₂O
Which of the following mixtures could be
separated using distillation? Select all that
apply.
a. A solution of rubbing alcohol and water.
b. A solution of salt and water.
c. A solution of sugar and water.
d. An alloy of copper and gold.
Answer:
c
Explanation:
sugar and water are soluble hence can be separated using distillation
will the shielding effect be more noticeable in metals or nonmetals? explain your answer.
The shielding effect is more noticeable in metals than non-metals.
What is shielding effect?
The shielding effect is known as a decrease in the effective nuclear charge on the electron cloud as a result of a variation in the attraction forces acting on the atom's electrons.
Why shielding effect is strong in metals?
Metals will have a more pronounced shielding effect as compared to nonmetals during the same time span. The amount of p+ atoms in the nucleus grows as you advance across the periodic table, raising the nuclear charge of the atom. Because the valence e- are drawn more firmly towards the nucleus in nonmetals, the inner core's shielding action is less obvious.
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In the reaction C+0₂ → CO₂ which element is reduced in the reaction?
O C
O 0₂
O CO₂
Answer:
O2(oxygen)
Explanation:
Reduced means the valence electrons are gained. From this equation we see in CO2, C is 4+ and for each O there's a 2-, however, originally, C and O2 are all 0, it's obvious that O is reduced from 0 to 2-
2HgO(s) 2Hg(l) + O2(g)
In a certain reaction, 4.37 g of HgO is decomposed, producing 3.21 g of Hg. What is the theoretical yield of Hg?
The theoretical yield of the Hg is 4.02 g.
What s the theoretical yield?The theoretical yield is the yield that is obtained from the stoichiometry of the reaction.
The reaction equation is; 2HgO(s) ------> 2Hg(l) + O2(g)
Number of moles of HgO = 4.37 g/217 g/mol = 0.02 moles
Number of moles of Hg = 3.21 g/201 g/mol = 0.012 moles
Now;
Theoretical yield of Hg = 0.02 moles * 201 g/mol = 4.02 g
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How many grams of carbon are contained in one mole of C3H8? (Report your
answer to two places past the decimal point. Moodle is looking for a number
only, no units.)
Considering the definition of molar mass, the mass of one mole of C₃H₈ is 44 grams.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.
Molar mass of C₃H₈In this case, you know the molar mass of the elements is:
C= 12 g/mole
H= 1 g/mole
So, the molar mass of the compound C₃H₈ is calculated as:
C₃H₈ = 3 ×12 g/mole + 8 ×1 g/mole
Solving:
C₃H₈ = 44 g/mole
Finally, the mass of one mole of C₃H₈ is 44 grams.
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In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as a ________ reaction. Group of answer choices combustion
In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as a single replacement reaction.
What is single replacement reaction?A single replacement reaction, also known as a single displacement reaction, occurs when one element in a molecule is swapped out for another. The starting materials are always pure elements, such as a pure zinc metal or hydrogen gas, plus an aqueous compound.
A + BC → B + AC
When A is more reactive than B or when the product AC is more stable than BC, single replacement reactions happen. A and B could either be two halogens or two metals (with hydrogen included) (C is a cation). C functions as a spectator ion when BC and AC are in aqueous solutions.
For example, 2HCl(aq)+Zn(s)→ZnCl₂(aq)+H₂(g)
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Why open flames near to ethanol can lead to serious fires?
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Ethanol is a polar solvent, a flammable liquid made of gasoline and alcohol that fully and immediately combines with water instead of separating, which is the opposite of what a firefighter attempting to knock down a car fire might expect.
Answer:
Ethanol has a high vapor pressure. Therefore, even though you may not be able to see the particles of ethanol in the air, they are there and will readily fuel a combustion reaction if an open flame is nearby