Answer: See explanation
Explanation:
Digital technologies refers to the electronic tools, or devices that can be used to generate data, store them or process data. e.g. mobile phones, ebooks etc.
Digital learning makes use of technology. Effective use of digital learning tools can help increase the engagement of students. This csn.aksi be used by the teachers to enhance personalized learning and also improve the lesson plans.
Digital technology can enhance collaboration, and communication with the students. The use of videos, robots, virtual classrooms, augmented reality and other technologies can bring about fun and foster inquisitiveness.
thesis: physical science improves nursing through technology, energy, and Matter.
write a 4-page essay explaining how science improves Nursing career and how it revolves around
Technology
Energy
Matter
Answer:
When science educators teach nurses, their primary aim should be to help them to develop understanding of their world of nursing. From a study of registered nurses' conceptions of the physical science underlying their clinical practice, we assert that nurses' understanding of the physical sciences is inadequate in terms of the competencies required of them as nurses.
Explanation: Hopes this helps You A lot :-D
What is the best method of separating the mixture of sand and fine salt?
By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.
Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.
Here's how the filtration process can be carried out:
1. Set up a filter apparatus with a funnel and filter paper or a filter flask.
2. Place the mixture of sand and salt in a beaker or a flask.
3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.
4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.
5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.
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Calculate the volume of 0.10 M sucrose solution that must be diluted to prepare 10.00 ml of a 0.015 M sucrose solution
In a sample of neon, carbon, and oxygen gas, the total pressure is 9 atm.
The partial pressure of neon is 2 atm and the partial pressure of oxygen is 2
atm. What is the partial pressure of carbon?
9 atm
3 atm
5 atm
4 atm
Answer:
5 atm
Explanation:
add boh partial pressures and subtract from total pressure
what do you mean by carrier
Answer:
1 : one that carries : bearer, messenger. 2a : an individual or organization engaged in transporting passengers or goods for hire. b : a transportation line carrying mail between post offices.
You are given three liquids, pentane (C5H12), water (H2O), and tetrachloromethane (CCl4), and are told to make solutions.
a. Predict whether you will be able to make a solution with pentane and tetrachloromethane
b. Predict whether you will be able to make a solution with pentane and water, and give your reasoning.
Answer:
A. predict whether you will be able to make a solution with pentane and tetrachloromethane
Explanation:
Sana nakatulong
Question 6 of 10
How much energy is required to vaporize 2 kg of gold? Use the table below
and this equation: Q = mLvapor
Substance
Latent Heat
Fusion
(melting)
(kJ/kg)
Melting
Point
(°C)
Latent Heat
Vaporization
(boiling) (kJ/kg)
Boiling
Point
(°C)
Aluminum
400
660
1100
2450
Copper
207
1083
4730
2566
Gold
628
1063
1720
2808
Helium
52
-270
21
-269
Lead
24.5
327
871
1751
Mercury
11.4
-39
296
357
Water
335
0
2256
100
Answer: Q = mlvap
Q = (2 kg)(1 kmol/197 kg)(1,000 mol/1 kmol)
Q = 10.15 kJ
2126 joules of energy in form of thermal energy is required to vaporize 2 kg of gold.
What is thermal energy?Thermal energy is defined as a type of energy which is contained within a system which is responsible for temperature rise.Heat is a type of thermal energy.It is concerned with the first law of thermodynamics.
Thermal energy arises from friction and drag.It includes the internal energy or enthalpy of a body of matter and radiation.It is related to internal energy and heat .It arises when a substance whose molecules or atoms are vibrating faster.
These vibrating molecules and atoms collide and as a result of which heat is generated in a substance , more the collision of particles , higher is the thermal energy.
Amount of heat is calculated as, Q=2×1063 =2126 joules as per the given formula.
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The energy of flowing electrons
A. A. LightLightB. B. ChemicalChemicalC. C. ElectricalElectricalD. D. TransformationTransformationE. E. MechanicalMechanical
Answer:
C. ElectricalElectrical
Explanation:
( it might be wrong pls dont report me just let me kno y its wrong )
Reaction of Nitrile with Grignard Grignard reagents react with nitriles to give an intermediate imine anion that is hydrolyzed by the addition of water to yield a ketone. The mechanism is similar to the reduction of a nitrile to an amine except that only one nucleophilic addition occurs instead of two, and the nucleophile is a carbanion rather than a hydride ion.
Required:
Draw curved arrows to show the movement of electrons. in this step of the mechanism. Arrow-pushing Instructions
Answer:
its a.
Explanation:
For a theoretical yield of 23 g and actual
yield of 13 g, calculate the percent yield for a
chemical reaction.
1. 63.6364
2. 76.4706
3. 71.4286
4. 57.1429
5. 56.5217
6. 40
7. 70
8. 60
9. 52.6316
10. 41.6667
Answer in units of %.
Answer:
5. 56.5217
Explanation:
Calculate percent yield by (actual yield / theoretical yield) times 100
(13/23) x 100 = 56.52173913
In a given compound, the mass of sulfur (S) is 40.05 g and the mass of oxygen (O) is 59.95 g. What is
the empirical formula of the compound
Answer:
[tex]SO_3[/tex]
Explanation:
Hello there!
In this case, according to the definition of the empirical formula as the smallest representation of the molecular formula of a chemical compound; for us to determine it, we first need to calculate the moles of sulfur in 40.05 g and those of oxygen in 59.95 g as shown below:
[tex]n_S=\frac{40.05g}{32.07g/mol}= 1.25molS\\\\n_O=\frac{59.95g}{16.00g/mol}=3.75molO[/tex]
Now, we perform the following mole ratios to figure out the subscripts in the empirical formula, by dividing over the fewest number of moles:
[tex]S=\frac{1.25}{1.25}=1 \\\\O=\frac{3.75}{1.25}=3[/tex]
Therefore, the empirical formula turns out:
[tex]SO_3[/tex]
Best regards!
oxidation and reduction occur simultaneusly
When a balloon is blown up then let go air molecules rush out of the balloon and join the air molecules in earths atmosphere what happens to the enthalpy in the balloon?
Answer: It decreases
Answer: It decreases.
Explanation: a p e x :)
1. If I have 5 moles of a gas at a pressure of 7.6 atm and a volume of 12 liters, what is the temperature?
Answer:
221.22K or -51°C
Explanation:
We will be using the Ideal Gas Law to calculate the temperature of the gas. It is a mathematical relationship that describes the behavior of ideal gas ample for any combo of varying pressure, volume, temperature, and # of moles (n). It is derived by combing Boyle's Law, Charles' Law, Gay-Lussac's & Avogadro's Law.
Note: As always, remember that temperature must be in Kelvin not Celsius when using this equation.
Ideal Gas Law: [tex]PV = nRT[/tex], where P = pressure, V = volume (in Liters), n = # of moles, R = the ideal gas constant, and T = temperature (in Kelvin).
Based on the problem, we are given the pressure, volume, and # of moles. We are asked to find the temperature. What about R you ask? Well, R is a constant that is the value of 1 mole of gas at STP. R has various values depending on the pressure units. In this case, our pressure is in atm so the R value = 0.0821.
Onto the math - all that needs to be done now is to plug and chug. Plug in the given values to find the temperature:
Set up: [tex](7.6 atm)(12L) = (5 mol)(0.0821 L*atm/(mol*K))(T)[/tex]
==> [tex]T = \frac{(7.6 atm)(12L)}{(5 mol)(0.0821 L*atm/(mol*K))}[/tex]
==> T = 221.17K
The answer is 221.17K. To convert into Celsius, subtract by 273.15 to get -50.99 or -51°C.
How many moles are there in 4.9x10^23 molecules of CO2?
F. 0.81 moles of CO2
G 8.14X10^45
H. 2.95X10^47
J. 2052.44
Answer:
0.81 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\ [/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{4.9 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{4.9}{6.02} \\ = 0.813953...[/tex]
We have the final answer as
0.81 molesHope this helps you
Lab: Enthalpy.
What were the learning goals of this lab experiment? Check all that apply.
to use mass and temperature data to do computations involving heat
to demonstrate that different reactions have different enthalpies
to compute a reaction’s enthalpy directly using mass measurements and a calorimeter
to compute the enthalpy of a reaction that cannot be measured directly using a simple calorimeter
Hess
’s law allows you to find the net enthalpy of the magnesium combustion by adding the enthalpies of intermediate reactions.
To find the enthalpy of a reaction in the lab, you measured the
mass
of the reactants
and the
temperature
change during the reaction.
In both Reactions 1 and 2, the temperature change was
positive
, meaning that the
reactions
gave off
heat.
Answer:
to use mass and temperature data to do computations involving heat
to compute a reaction’s enthalpy directly using mass measurements and a calorimeter
To find the enthalpy of a reaction in the lab, you measured the mass
of the reactants
and the
temperature
change during the reaction.
Explanation:
Was that good?
Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.
What is Enthalpy?Enthalpy is a property or state function that resembles energy; it has the same dimensions as energy and is therefore measured in joules or ergs. The value of enthalpy is solely dependent on the temperature, pressure, and composition of the system, not on its history.
Enthalpy, denoted by the symbol H, is the sum of the internal energy, denoted by E, and the product of the pressure and volume, denoted by PV.
The change in internal energy is equal to the heat transmitted to, less the work done by, the system, according to the law of energy conservation.
Therefore, Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.
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Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.
Answer:
The total amount of energy required is 25,515.2 J.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When a system absorbs (or gives up) a certain amount of heat, it can happen that:
experience a change in its temperature, which involves sensible heat, undergoes a phase change at constant temperature, or latent heat.To calculate the latent heat the formula is used:
Q = m. L
Where
Q: amount of heat m: mass L: latent heatTo calculate sensible heat the following formula is used:
Q = m. c. ΔT
where:
Q: amount of sensible heat m: body mass c: specific heat of the substance ΔT: temperature rangeIn this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184 [tex]\frac{J}{g*C}[/tex]:
q1 = m*c*(Tfinal-Tinitial)
q1 = 10.0 g *(4.184 [tex]\frac{J}{g*C}[/tex])* (100 - 35.0 C) = 2719.6 J
Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 [tex]\frac{J}{g}[/tex]:
q2 = m*(heat of vaporization)
q2 = 10.0 g*(2259.36 [tex]\frac{J}{g}[/tex]) = 22593.6 J
Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02 [tex]\frac{J}{g*C}[/tex] :
q3 = m*c*(Tfinal-Tinitial)
q3 = 10.0 g*(2.02 [tex]\frac{J}{g*C}[/tex])*(110-100 C) = 202 J
The total amount of energy can be calculated as:
Q= q1 + q2 + q3
Q= 2719.6 J + 22593.6 J + 202 J
Q=25,515.2 J
The total amount of energy required is 25,515.2 J.
PLEASE ASNWR ASAP
If I have a 50 liter container that holds 45 moles of gas at a pressure of 2.66 x 104 mmHg, what is the
temperature inside the container? ** convert pressure to atm**
If a system has 5.00×102 kcal of work done to it, and releases 5.00×102 kJ of heat into its surroundings, what is the change in internal energy (Δ or Δ) of the system?
Answer:
U=q+w
=5.00×10^2 +5.00×10^2
=2.5×10^5 kJ
Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to get to the equivalence point. Assume that your base is about 0.05 M and that your unknown acid has a molar mass around 400 g/mol. (Report your answer using 2 significant figures).
Answer:
"0.60 g" is the appropriate solution.
Explanation:
The given values are:
Volume of base,
= 30 ml
Molarity of base,
= 0.05 m
Molar mass of acid,
= 400 g/mol
As we know,
⇒ [tex]Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}[/tex]
On substituting the values, we get
⇒ [tex]0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}[/tex]
⇒ [tex]Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}[/tex]
⇒ [tex]=1.5\times 10^{-3}[/tex]
hence,
⇒ [tex]Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}[/tex]
On substituting the values, we get
⇒ [tex]1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}[/tex]
⇒ [tex]Mass \ of \ acid=1.5\times 10^{-3}\times 400[/tex]
⇒ [tex]=0.60 \ g[/tex]
Some students have said that a buffer is like a proton (H ) sponge. Evaluate this statement and explain both how a buffer is like a sponge and how it is not like a sponge. For your explanation, include chemical equations, data, and create and explain molecular-level drawings. (Question is taken from Orgill and Sutherland, 2008.) (Saloni)
Answer:
i) Buffer absorbs H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH
ii) absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.
Explanation:
i) Buffer like a proton ( H ) sponge
Buffer absorbs H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH
The pH of a Buffer follows the Henderson-Hasselbach model
pH = pKa + Log ([A-]/[HA])
when base is added
HA + OH^- -------> A- + H2O
when acid is added
A^- + H^+ ---------> HA
ii) Buffer not like a proton ( H ) sponge
absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.
Choose the options below that are true.
A. The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.
B. The rate laws of all chemical reactions can be determined directly from their net chemical equations.
C. The rate laws of bimolecular elementary reactions are second order overall.
D. The rate law for a given reaction can be determined from its reaction mechanism, without the accompanying rates of each elementary step in the mechanism.
Answer:
The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism. and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.
Explanation:
(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.
(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.
(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.
(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.
Therefore , the first and third statement is true.
Consider the following intermediate chemical equations.
P₄(s)+3O₂(g) ---> P₄O₆(s) ΔH₁ = -1640kJ
P₄O₁₀(s) ---> P₄(s)+5O₂(g) ΔH₂ = 2,940.1 kJ
What is the enthalpy of the overall chemical reaction P₄O₆(s)+2O₂(g) ---> P₄O₁₀(s)
A.) -4,580 kJ
B.) -1,300 kJ
C.) 1,300 kJ
D.) 4,580 kJ
Answer:
-1,300 kJ
I don't want to explain it brainly AAAAA
The standard enthalpy of the reaction is the enthalpy change which occurs in a system when a matter is transformed by a chemical reaction under standard conditions. Here the enthalpy of the overall chemical reaction is -1,300 kJ. The correct option is B.
What is enthalpy change?In any general chemical reaction, the reactants undergo chemical changes to form products. The change in enthalpy is represented as ΔrH and is termed as the reaction enthalpy. It can be calculated by subtracting the sum of enthalpies of all the reactants from that of the products.
ΔrH = ∑ aiH products - ∑ bi H reactants
Here we should reverse the first reaction and also multiply its ΔH by (- 1):
P₄O₆(s) → P₄(s) + 3O₂(g), ΔH₁' = 1640.1 kJ.
The second reaction is also reversed and also multiply its ΔH by (- 1):
P₄(s) + 5O₂(g) → P₄O₁₀(s), ΔH₂' = - 2940.1 kJ.
If we add the two reactions after modification, we get:
P₄O₆(s) → P₄O₁₀(s).
Therefore, ΔH = ΔH₁' + ΔH₂' = 1640.1 kJ + (- 2940.1 kJ) = - 1300 kJ.
Thus the correct option is B.
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Several elements must be transmuted to sea the real implications of this event
a.surpassed
b.estimated
c.changed
d.summed
thanks guys :)
Why are some resources, like fossils, found in some places and not in others?
Answer:
Because thats where the animal passed away
Explanation:
what is the major organic product obtained from the reaction of 1-butanol with aqueous hbr at reflux
Answer:
1-bromobutane
Explanation:
The reaction of butane with aqueous HBr at reflux is an SN2 reaction. The reaction passes through a single transition state in which the bond between carbon and the leaving group as well as the bond between carbon and the incoming nucleophile are being broken and formed simultaneously. It is a synchronous reaction.
The nuclephile attacks from the backside while the leaving group departs. This leads to inversion of configuration of the product.
4. What is the molarity of a solution that contains 65g of sodium nitrate in 750? ml of solution?
Answer:
1.02 M
Explanation:
Solution contains 65g of sodium nitrate
Volume of solution = 750 ml
Now, Molar mass of sodium nitrate from online values = 84.9947 g/mol
Thus, it means 84.9947 g/mol of sodium nitrate dissolved in 1000 mL of water will be equal to 1 M molarity.
Thus;
Molarity of solution = (65/750) × (1000) × (1/84.9947) = 1.02 M
For the reaction 2 Cr(s) + 3 Pb²⁺(aq) ⟶ 3 Pb(s) + 2 Cr³⁺(aq), what is the value of n in the Nernst equation?
Answer:
The value of n is 6
Explanation:
The half-reactions of the problem are:
Cr(s) → Cr³⁺ + 3e⁻
Pb²⁺ + 2e⁻→ Pb(s)
To balance the electrons we must multiply the half-reactions as follows:
2 * (Cr(s) → Cr³⁺ + 3e⁻)
3 * (Pb²⁺ + 2e⁻→ Pb(s))
2Cr(s) → 2Cr³⁺ + 6e⁻
3Pb²⁺ + 6e⁻→ 3Pb(s)
In Nernst equation, the value of n are the electrons used to balance the reaction, as in this problem, the electrons are 6:
The value of n is 6A truck accelerates at a rate of 14 m/s2 . The truck weighs 17000 kg. What is the amount of force
necessary for the truck to accelerate at this rate?
Answer:
238000 N
Explanation:
Use F=ma
Mass= 17000 kg
Accel.= 14 m/s²
You have a bag of chips at a constant pressure of 1 Atm with a volume of .5 L and a temperature of 10C. The bag is left under the sun for a couple of hours at a temperature of 35 C, what will its new volume be?
Answer:
0.54 L
Explanation:
Given that,
Initial volume, V₁ = 0.5 L
Initial temperature, T₁ = 10°C = 283 K
Final temperature, T₂ = 35 C = 308 K
We need to find the final volume. The relation between the volume and temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{0.5\times 308 }{283}\\\\V_2=0.54\ L[/tex]
So, the new volume is 0.54 L.