a large heavy truck and a baby carriage roll down a hill. Neglecting friction, at the bottom of the hill, the baby carriage will likely have A. less momentum, B. about the same momentum, C. more momentum or D. double the momentum of the truck
Answer:
please give me brainlist and follow
Explanation:
At the bottom of the hill, the baby carriage will likely have less momentum Therefore, option D is correct. Solution: ... Therefore, at the bottom of the hill, the heavy truck will have more momentum and baby carriage will have less momentum.
An electromagnetic wave has a frequency of 1.0 x 10^5. What is the wavelength of the wave?
Answer:
The frequency , speed and wavelength of an electromagnetic wave are related by the formula
Speed = frequency x wavelength
frequency = speed / wavelength
substituting the values
frequency = 3 x #10 ^8# m /s / 1 x #10^15# m
= 3 x #10^-7# /s
The wavelength of the wave will be 3000 m. The relationship between the wave's wavelength, time, and speed is used to solve the problem.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The given data in the problem is;
[tex]\lambda[/tex] is the wave's wavelength
c denotes the wave's speed=3×10⁸ m/secv
v is the frequency = 1 ×10⁵ Hz
The relationship between the wave's wavelength, time, and speed is given as
[tex]\rm \lambda = \frac{c}{v} \\\\ \rm \lambda = \frac{3 \times 10^8}{1.0 \times 10^5} \\\\ \lambda=30000 \ m[/tex]
Hence the wavelength of the wave will be 3000 m.
To learn more about the wavelength refer to the link;
brainly.com/question/7143261
PLS HELP, WILL GIVE BRAINLIEST!!!
A piece of clay with a mass of 350 g is dropped to the floor from a height of 1.5 m (A). Calculate the KE and PE of the clay at
a. (A = 1.5 m).
b. (B = 70 cm), and
c. (C = 0 m, just before hitting the ground). d. Make an energy graph at each point
Answer:
b bro it's b bro
pls help giving brainliest!
• Explain how Ohm's Law is like a river.
o What represents Voltage?
o What represents Current?
o What represents Resistance?
Answer:
Pressure of water = Voltage
Flow rate of water = Current
Obstructions present in the river = Resistance
Explanation:
We can describe Ohm's Law by using the river analogy,
The flow of water from a mountain to lower parts can be considered as change from high potential to a lower potential.The flow of water can also be considered as flow of electrons, that is current in a circuitThere are also obstructions in rivers that can be considered as resistance in an electric circuit.Suppose that a particle accelerator is used to move two beams of particles in opposite directions. In a particular region, electrons move to the right at 4910 m/s and protons move to the left at 2583 m/s. The particles are evenly spaced with 0.0758 m between electrons and 0.0577 m between protons. Assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region
Answer:
The answer is "[tex]17.28 \times 10^{-14}\ A[/tex]"
Explanation:
Calculating the number of electrons passing in per second:
[tex]\to n_e = \frac{4910}{0.0758} = 6.4 \times 10^5[/tex]
Calculating the current in electron:
[tex]\to I_e = 6.4 \times 10^5 \times 1.6 \times 10^{-19} = 10.24 \times 10^{-14}\ A[/tex]
Calculating the number of protons passing in per second:
[tex]\to n_p = \frac{2583}{0.0577} = 4.4 \times 10^{4}[/tex]
Calculating the current in proton:
[tex]\to I_p = 4.4 \times 10^{4} \times 1.6 x 10^{-19} = 7.04 \times 10^{-14} \ A[/tex]
Calculating the total current:
[tex]\to I = I_p + I_e = 17.28 \times 10^{-14}\ A[/tex]
19
What is the mass of a ball that is traveling 30 m/s and has 4.5 J of kinetic energy?
ave a GPF of 35512
Answer: The mass of ball is 10 grams.
Explanation:
Given : Kinetic energy = 4.5 J
Velocity = 30 m/s
The formula for Kinetic energy is as follows.
[tex]K.E = \frac{1}{2}mv^{2}[/tex]
where,
K.E = Kinetic energy
m = mass
v = velocity
Substitute the values into above formula as follows.
[tex]K.E = \frac{1}{2}mv^{2}\\4.5 J = \frac{1}{2} \times m \times (30 m/s)^{2}\\m = \frac{4.5 J \times 2}{900 m^2/s^2} (1 Js^{2} = kg m^{2})\\= 0.01 kg (1 kg = 1000 g)\\= 10 g[/tex]
Thus, we can conclude that the mass of ball is 10 grams.
An astronomy class is so excited by the discovery of planets around other stars that they decide to do a library exhibit on the subject so that everyone in the school can learn about it. In this exhibit they want to pay tribute to both the astronomers of today who have done the work AND some of the scientists of the past whose work was essential to making the discoveries possible (and directly related to the techniques involved). Which of the following scientists of the past should definitely be included in the exhibit?
George Herbig Ejnar Hertzsprung Ptolemy
Gerard Kuiper Christian Doppler
Answer:
Christian Doppler
Explanation:
The Scientist with the most significant contribution to the discovery of planets around other stars is Christian Doppler and his work that made this discovery possible is the Principle of DOPPLER EFFECT
Christian Doppler was an Austrian scientist and physicist whose principle Doppler effect explained how observed frequency of light and sound waves are affected by a relative motion of both the source and detector
The elastic force acting on a 0.60 kg object on a spring is 1.2 N. If the distortion of the object is 0.025 m to the right, what is the spring constant?
Answer:
Spring constant = 48 N/m
Explanation:
Given the following data;
Mass = 0.60 kg
Force = 1.2 N
Distortion = 0.025 m
To find the spring constant;
Mathematically, the force exerted on a spring to cause a distortion or an extension is given by the formula;
Force = spring constant * distortion
Substituting into the formula, we have;
1.2 = spring constant * 0.025
Spring constant = 1.2/0.025
Spring constant = 48 N/m
what part of the rocket reaches space
Answer:
7
Explanation:
There is really no explanation needed
Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm.
Required:
What is V(star) , the speed at which the star is moving relative to the earth?
Answer:
The speed will be "18km/s". A further explanation is given below.
Explanation:
According to the question, the values are:
Wavelength,
[tex]\lambda = 656.46 \ nm[/tex]
[tex]\Delta \lambda = 0.04[/tex]
[tex]c=3\times 10^8[/tex]
As we know,
⇒ [tex]\frac{\Delta \lambda}{\lambda} =\frac{v}{c}[/tex]
On substituting the values, we get
⇒ [tex]\frac{656.46}{0.04} =\frac{v}{3\times 10^8}[/tex]
⇒ [tex]v=\frac{656.46}{0.04} (3\times 10^8)[/tex]
⇒ [tex]=16411.5\times 3\times 10^8[/tex]
⇒ [tex]=18280 \ m/s[/tex]
or,
⇒ [tex]=18 \ km/s[/tex]
The speed at which the star is moving relative to the earth is 18 km/s
Calculation of the speed:Since the wavelength is 656.46 nm.
And, Δλ=0.04nm
Here Wavelength should represent the distance between the same points in the cycles of a signal propagated in space or it should be along a wire.
Now the speed should be
[tex]= 0.04 \div 656.46 \times 3 \times 10^8[/tex]
= 1820m/s
= 18 km.s
Therefore, The speed at which the star is moving relative to the earth is 18 km/s
learn more about speed here: https://brainly.com/question/24692367
Sheryl always expects special treatment wherever she goes because, after all, she is better than everyone else. She could care less how others feel and routinely expects people to worship her. These attributes are typical of ______.
Explanation:
it attributes to Being pride of herself
space question 50 points
Explain how sun angle and seasons vary as you move away from the equator.
Seasonal change in the angle of sunlight, caused by the tilt of the Earth's axis, is the basic mechanism that results both in warmth of the weather and in length of the day.
Some fundamental particles such as quarks (and some leptons, such as the electron) have an electric charge and use photons as mediating particles to communicate with other particles with electric charge. Similarly, quarks, identified by their color charge, use a mediating particle to interact with other particles with color charge, that is, other quarks. What is the particle that mediates interactions among quarks
Answer: hello the options to your question is missing below are the missing
options :
the W boson the gluon the Z boson the tau particleanswer : The Gluon ( option 2 )
Explanation:
The particle that mediates the interactions between quarks is known as the Gluon.
Gluon is known as an elementary particle that acts as the exchange particle between quarks. It's function is similar to the activity involving the exchange of photons in the electromagnetic force involving two charged particles
Rudy plans to conduct an experiment using three rosebushes of the same variety and size. His hypothesis is that the plant
receiving the most sunlight at the end of three months will show the most growth. In his plan below, he has listed how much
water, fertilizer, and sunlight each plant will receive. Why is his experiment flawed?
Answer: B) He has too many independent variables.
Explanation: Nothing in the experiment is a constant or being measured.
How does a sound wave's amplitude affect the sound we hear? How does a sound
wave's frequency affect the sound we hear?
Answer:
cause we hear differently
Explanation:
Answer:
As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder. Relative sound intensities are often given in units named decibels (dB)
How does Mountaineering help to improve our lifestyle?
Answer:There are numerous benefits to mountaineering. The most obvious benefits are improving both your physical fitness and cardiovascular fitness levels as well as reducing body fat through aerobic exercise.
Explanation: trust
Answer:
Lower your risk of heart disease. Improve your blood pressure and blood sugar levels. Boost bone density, since walking is a weight-bearing exercise.
Please help 23 also 29 the answer choices are reflection or refraction your fraction absorption
Answer:
23. Option B. Hertz
29. Refraction.
Explanation:
23. Determination of the unit of measurement of frequency.
Frequency is simply defined as the number of oscillation made in one second. Mathematically, frequency can be represented as:
Frequency = 1/period
f = 1/T
Period is measured in seconds.
Thus, the unit of frequency becomes
f = 1/T
f = 1/s = s¯¹ (Hertz)
Therefore, the unit of frequency is Hertz.
29. When a wave enters a new medium, the speed of the wave is uttered. This leads to the bending of the wave. When this occurs, we can say refraction has taken place.
A man kicks the 150-g ball such that it leaves the ground at an angle of 60° and strikes the ground at the same elevation a distance of 12 m away (14 points). Determine: (a). The velocity of the ball instantly after the man kicks the ball; (6 points) (b). Determine the impulse of his foot on the ball at A. (8 points) Neglect the impulse caused by the ball’s weight while it’s being kicked.
Answer:
[tex]313.92\ \text{m/s}[/tex]
[tex]47.088\ \text{kg m/s}[/tex]
Explanation:
m = Mass of ball = 150 g
[tex]\theta[/tex] = Angle of kick = [tex]60^{\circ}[/tex]
[tex]x[/tex] = Displacement of ball in x direction = 12 m
Range of projectile is given by
[tex]x=\dfrac{u\sin^2\theta}{2g}\\\Rightarrow u=\dfrac{2xg}{\sin^2\theta}\\\Rightarrow u=\dfrac{2\times 12\times 9.81}{\sin^260^{\circ}}\\\Rightarrow u=313.92\ \text{m/s}[/tex]
The velocity of the ball instantly after the man kicks the ball is [tex]313.92\ \text{m/s}[/tex]
Impulse is given by
[tex]J=mu\\\Rightarrow J=0.15\times 313.92\\\Rightarrow J=47.088\ \text{kg m/s}[/tex]
The impulse of his foot on the ball is [tex]47.088\ \text{kg m/s}[/tex].
Average speed is the rate at which an object is moving at a given instant. True or False.
Answer:
True
Explanation:
Average speed is the rate at which an object is moving at a given instant in time.
Answer: false.
Explanation: i’m pretty sure that’s instantaneous speed.
Your spaceship lands on a moon of a small planet that orbits a distant star. As you initially circled the moon, you measured its diameter to be 5480 km. After land you observe that a simple pendulum that had a frequency of 3.50 Hz on Earth now has a frequency of 1.82 Hz. What is the mass of the moon
Answer:
[tex]m=3*10^2^3kg[/tex]
Explanation:
From the question we are told that:
Moon diameter [tex]D_m=5480Km \approx 2740000m[/tex]
Earth's frequency [tex]F_e=3.50Hz[/tex]
Planet's frequency [tex]F_p=1.80Hz[/tex]
Generally the equation for Frequency and Gravity relationship is mathematically given by
[tex]\frac{F_p}{F_e}=\sqrt{ \frac{g_p}{g_e} }[/tex]
Therefore gravity of Moon is given as
[tex]g_p= g_e*(\frac{f_p}{f_e} )^2[/tex]
[tex]g_p= 9.8*(\frac{1.82}{3.50} )^2[/tex]
[tex]g_p=2.64992m/s^2[/tex]
Generally the equation for mass of spherical body is mathematically given by
[tex]m=\frac{g_pD_m^2}{G}[/tex]
where G= gravitational constant
[tex]m=\frac{2.64992m/s^2*(2740000m)^2}{6.67*10^{-11}}[/tex]
[tex]m=2.98268956*10^2^3kg[/tex]
[tex]m=3*10^2^3kg[/tex]
Tendons are, essentially, elastic cords stretched between two fixed ends; as such, they can support standing waves. These resonances can be undesirable. The Achilles tendon connects the heel with a muscle in the calf. A woman has a 20-cm long tendon with a cross-section area of 130 mm^2. The density of tendon tissue is 1100 kg/m^3.
Required:
For a reasonable tension of 600 , what will be the fundamental resonant frequency of her Achilles tendon?
Answer:
161.938 Hz
Explanation:
the computation of the fundamental resonant frequency is shown below
p = 1100 kg/m^3
A = 130 mm^2
= 130 ×10^-6 m^2
T = 600 N
L = 20 cm
= 0.2 m
Now the linear density of tendon is
= 1100 kg/m^3 × 130 ×10^-6
= 0.143 kg/m
Now the wave of the string is
= √600 ÷ √0.143
= 64.775 m/s
Now finally the fundamental resonant frequency is
= 64.775 ÷ (2 × 0.2)
=161.938 Hz
a wave raises a buoy twice every second and the crests of the incoming waves are 4m apart
what is the wavelength in meters?
You just said that the crests of the incoming waves are 4m apart.
That's it ! That's the wavelength. The distance between crests. It doesn't matter how often they sail past you.
The question I was expecting here: How fast are the waves traveling ?
That's (frequency)x(wavelength). 8 m/s.
The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7m when leaving the ground at an angle of 45 degrees. with what speed must the animal leave the ground to reach that height?
Answer:
v = 12 m/s
Long, boring, and convoluted explanation:
First, let's lay out our information.
- max height = 3.7 m
- 0 = 45°
- gravitational acceleration constant = 9.8 [tex]\frac{m}{s^2}[/tex]
Since the puma leaves the ground at a 45 ° angle, its motion will follow a curved path as seen in many projectile motion problems, where the object is being influenced solely by the force of gravity. And because the puma leaves the ground at an angle, its initial velocity is broken down into its horizontal and vertical components. We were also told, though indirectly, that the max height is 3.7m because the puma can reach up to that height. Gravity is always given to be 9.8 [tex]\frac{m}{s^2}[/tex]
Because we are dealing with maximum height and gravity, we have to use the vertical component of the velocity, vsin ( θ ) , and not the horizontal component, vcos ( θ ) .
Given its max height, the acceleration due to gravity, and the angle, we can now solve for the speed at which the puma leaves the ground using the following equation: vsin ( θ ) = [tex]\sqrt{2hg}[/tex]
Where vsin ( θ ) is the vertical component of the initial velocity and h and g are max height and gravitational acceleration constant respectively.
Plugin, rearrange and solve
v sin ( θ ) = [tex]\sqrt{2hg}[/tex]
v sin ( 45 ∘ ) = √ 2 × 3.7 × 9.8
v ( 0.71 ) = [tex]\sqrt{72.52}[/tex]
v ( 0.71 ) = 8.52
v = 8.52 /0.71
v = 12 m s
plz help
In a pot of boiling water, what happens to the hot water at the bottom of the pot? What happens to the cold water at the top of the pot?
Explanation:
First, the liquid on the bottom of the pot closest to the heat source starts to get hot; as it does, it rises. The rising hot water is replaced by the cooler, more dense water molecules. The water molecules in your pot continually exchange in this way, thanks to gravity, eventually warming the entire pot of liquid.
On the graph of voltage versus current, how do the resistors compare?
A person is dragging a packing crate of mass 74.9 kg across a rough horizontal floor where the coefficient of kinetic friction is 0.35. He exerts a force F at and angle 43.0 degrees above the horizontal. What is the Force F such that the crate moves at a constant speed
Answer:
351.28 N
Explanation:
Let F be the force on the object and f be the frictional force. The component of the force acting in the horizontal direction causing the object to move is FcosФ where Ф is the angle between F and the horizontal = 43.0°. The frictional force on the packing crate f = μN where μ = coefficient of kinetic friction = 0.35 and N = normal force = W = weight of the packing crate = mg where m = mass of crate = 74.9 kg and g = acceleration due to gravity = 9.8 m/s². So, f = μN = μW = μmg
So, the net force on the packing crate is
FcosФ - f = ma
FcosФ - μmg = ma
Since the crate moves at constant speed, its acceleration a = 0
So, FcosФ - μmg = ma
FcosФ - μmg = m(0)
FcosФ - μmg = 0
FcosФ = μmg
F = μmg/cosФ
Substituting the values of the variables into the equation, we have
F = μmg/cosФ
F = 0.35 × 74.9 kg × 9.8 m/s²/cos43.0°
F = 256.907 kg-m/s²/0.73135
F = 351.28 kg-m/s²
F = 351.28 N
Why would ash from a volcano make the temperature drop?
50POINTS PLEASE HELP SPACE QUESTION
Explain how and why seasons vary in the Northern and Southern Hemispheres.
The seasons in the Northern Hemisphere are the opposite of those in the Southern Hemisphere. Seasons occur because Earth is tilted on its axis relative to the orbital plane, the invisible, flat disc where most objects in the solar system orbit the sun.
Someone please help me! And I will mark you as brainlist!!
1) A ball with a mass of 2.0 kg is thrown upward 1.2m calculate its gravitational potential energy into two significant figures. Gravity = 9.8 N/kg
• 2.4 J
• 1.4 J
• 120 J
• 24 J
2) Translation kinetic energy is defined as the energy of a system due to the motion of the system’s...
• center of mass
• axis of symmetry
• molecules
• rotational movement
PLEASE HELP!!
Answer:
1. G.P.E = 24 J
2. center of mass
Explanation:
Given the following data;
Mass = 2kg
Height, h = 1.2m
Acceleration due to gravity = 9.8 N/kg or m/s².
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
[tex] G.P.E = mgh[/tex]
Where;
G.P.E represents potential energy measured in Joules.m represents the mass of an object. g represents acceleration due to gravity measured in meters per seconds square. h represents the height measured in meters.Substituting into the formula, we have;
[tex] G.P.E = 2*1.2*9.8 [/tex]
G.P.E = 23.52 to 2 S.F = 24 Joules.
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.
A house brick has a volume of 1900 cm³ and a weight in air of 80N.What is its apparent weight in water?The density of water is 1.00 g cm³?
Answer:
61 N
Explanation:
We'll begin by calculating the mass of the brick when placed in water. This can be obtained as follow:
Volume of brick = 1900 cm³
Density of water = 1 g/cm³
Mass of brick in water =…?
Density = mass / volume
1 = mass of brick in water / 1900
Cross multiply
Mass of brick in water = 1 × 1900
Mass of brick in water = 1900 g
Next, we shall convert 1900 g to Kg.
1000 g = 1 Kg
Therefore,
1900 g = 1900 g × 1 Kg / 1000 g
1900 g = 1.9 Kg
Next, we shall determine the weight in water. This can be obtained as follow:
Mass (m) = 1.9 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = m × g
W = 1.9 × 10
W = 19 N
Thus, the weight of the brick in water is 19 N.
Finally, we shall determine the apparent weight of the brick in water. This can be obtained as follow:
Weight in air = 80 N
Weight in water = 19 N
Apparent weight =?
Apparent weight = weight in air – weight in water
Apparent weight = 80 – 19
Apparent weight = 61 N