Which type of circuit would be best to use for lights used for decorations?

Answer:

The density of the substance is

[tex]0.85\: \: g \: \: \: {cm}^{ - 3}[/tex]

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Answer:

300 Newtons

Explanation:

Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.

The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have

Force = 12 × 25 = 300 Newtons or 300 N for short.

Answer:

F = G M m / R^2 gravitational force on planet of mass m.

None of these quantities change in the given hypothesis so

there will be no change in the orbit of mass m

Answer:

[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.

Explanation:

The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].

If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.

The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].

The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:

[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].

(The new velocity of the log is negative because the log would be moving away from the beaver.)

The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].

Answer:

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. What is most likely the phase of the substance?

gas. NO. Gases have expansibility, that is, they occupy all the space available, so they wouldn't occupy just one half of the container.

liquid. YES. The description fits the liquid phase.

solid and gas. NO. Solids occupy fixed positions and their atoms can't slide past each other.

liquid and solid. NO. Solids can't be present due to their lack of movement.

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.

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Explanation:

Answer:

it is B

Explanation:

Answer:

CO and H20

Explanation:

The minimum  speed that the second swimmer must have in order to catch up with the first swimmer by the end of the  pool is; 4.04 m/s

We are given the following facts;

Formula for time taken is;

time = distance/speed

Time taken by swimmer 1 for one leg;

t₁ = 50/3.9

t₁ = 12.82 s

Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;

t₂ = 12.82 -0.45

t₂ = 12.37 s

Thus, speed of swimmer 2;

v = 50/12.37

v = 4.04 m/s

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Explanation:

hope it's useful for you knows

Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

Additional comment

The mass is irrelevant in the equations we typically use for this purpose.

Answer:

0.2 m/s^2

Explanation:

a = fm

a = 2 x .1

a = 0.2 m/s^2

Answer:

Explanation:

Centrifugal force Fc = m x v2 / r

Weight  = mg

As required by the question

Fc = W

v2 /r = g

given radius r = 22 m

v2 /22 = 9.8

Solve for v

required speed v = √(22 * 9.8)

= 14.35 m/s

v=15 m/s

this may help you

The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.

The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.

The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:

[tex]{\displaystyle F=m\omega ^{2}r}[/tex]

Given, the radius of the curve, r = 22m

The acceleration, a = v²/r

The weight of the box, W = mg

We know that, F = ma

mg = m(v²/r)

v = √gr

[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]

v = 14.68 m/s

Therefore, you should drive at a speed of 14.68 m/s

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Answer:Passengers instinctively use the car as a frame of reference, while a physicist uses Earth. ... In such a frame of reference, Newton's laws of motion take the form given in Dynamics: Newton's Laws of Motion The car is a non-inertial frame of reference because it is accelerated to the side.

Explanation: Example of inertial and Noninertial Frame of Reference

Answer:

Approximately [tex]1.3\times 10^{8}\; \rm m\cdot s^{-1}[/tex].

Explanation:

Look up the speed of light in vacuum: [tex]c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}[/tex]. Denote the speed as [tex]c[/tex].

If the speed of light in a medium is [tex]v[/tex], the refractive index of that medium would be:

[tex]\displaystyle n = \frac{c}{v}[/tex].

Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.

Rearrange this equation to find the speed of light [tex]v[/tex] in this medium:

[tex]\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}[/tex].

Answer:

capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.

Explanation:

Hope it's help

please brainless me :)

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Doubt clarification - use comment section.

Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.

A physical cause that can change the state of motion or rest of a body is called force. It is the product of mass and acceleration  off the body.

Here,

Net force acting on the car, F = 4000 N

Acceleration of the car, a = 2..5 m/s²

We know that,

F = ma

So, m = F/a

 m = 4000/2.5

 m = 1600 kg

Hence,

Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.

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Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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Answer:

C

Explanation:

because the concave mirror is always inverted

d )  when object is between focus and mirror , image formed is always virtual and erect

A concave mirror has a reflective surface that is curved inward and away from the light source .

a) Incorrect because image can be equal to , smaller then , and bigger then the object

b) and c)  Incorrect when object is between focus and mirror , image formed is virtual and erect

d ) Correct option  when object is between focus and mirror , image formed is always virtual and erect

e) Incorrect except one case in all other cases nature is real and inverted

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The synonym of a word( observe, infer, repetition, replication and data) means another word that is nearest in meaning to the given word.

The synonym of the words given from the question is given below:

Therefore, synonym of a word means another word that is nearest in meaning to the given word.

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Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

Answer:

M2=0.52kg

Explanation:

thats rightt

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

Answer:

papi sus

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 4 \ Newtons}}}[/tex]

Explanation:

Work is energy transferred when an object is moved. It is the product of force and distance.

[tex]W= F*d[/tex]

John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.

Substitute the values into the formula.

[tex]3.2 \ N *m = F * 0.8 \ m[/tex]

We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.

[tex]\frac {3.2 \ N*m}{0.8 \ m}= \frac{ F* 0.8 \ m}{0.8 \ m}[/tex]

The units of meters cancel.

[tex]\frac {3.2 \ N}{0.8 }=F[/tex]

[tex]4 \ N = F[/tex]

John must exert 4 Newtons of force.

Answer:

the orbital in which the electron is located relative to the atom's nucleus.

Explanation:

Answer:

the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.

Here are all the steps.

When you are pulling a sled with constant velocity with a rope then the ground exerts a surface force on the sled will be equal to 573.56 N.

The pulling force delivered axially by a cable, string, chain, or by either end of a rod, truss member, or another such 3-D object is known as tension in physics. Tension can be described as the action-reaction pair of forces acting at each end while tension is a polar opposite of compression.

A restoring force causes tension when atoms or molecules are torn apart at the atomic level and build up potential energy.

When you are trying to move upward and push in a positive way,

F = - 112 i + 57.4 (9.8) j

F = -112 i + 562.52 j

[tex]F = \sqrt{(-112)^2+ (562.52)^2}[/tex]

[tex]F =\sqrt{12544 + 316428.7}[/tex]

F = 573.56 N

Therefore, the surface force the ground exerts on the sled is 572.52 N.

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Hi there!

a.

The equation for centripetal acceleration is as follows:

[tex]\large\boxed{a_c = \frac{v^2}{r}}}[/tex]

Plug in the given values to solve:

[tex]\large\boxed{a_c = \frac{(65)^2}{75} = 56.33 m/s^2}[/tex]

b.

According to Newton's Second Law:

[tex]\large\boxed{\Sigma F = ma}}[/tex]

The acceleration is v²/r, so the net force is:

[tex]\large\boxed{\Sigma F = m(\frac{v^2}{r})}}[/tex]

Multiply by the given mass:

[tex]\large\boxed{\Sigma F = 700(56.33) = 39433.33 N}}[/tex]

c.

There is NO net force in the vertical direction since the object is NOT accelerating in the vertical direction (normal force and weight cancel).

Thus, the ONLY net force experienced by the object is in the horizontal direction and is EQUAL to the centripetal force.

To solve the problem it is necessary to apply the concepts of Torque and equilibrium.

The Torque is defined as:

Where

F= Force

d = Distance

In this particular case, the force is caused by the weight of both children.

In turn, when there is equilibrium, the two torques must be equal therefore

Replacing with our values

Re-arrange to find  

Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.

Answer:

Net force = 0

Explanation:

Whenever there is an unbalanced force, it shows that the net force doesn’t = 0 because if net force = 0, then everything force is balanced by another force. If there is an unbalanced force, acceleration will occur in the direction the net force is towards.