Which statement is correct in the process of balancing the equation?

The  balanced chemical equation for the formation of sodium fluoride, NaF is given below:

2 Na (s) + F₂ (g) ----> 2 NaF (s)

The formation of sodium fluoride, NaF is an example of a synthesis reaction.

In a synthesis reaction, two or more elements or compounds react together to form a single compound.

The formation of sodium fluoride is given in the chemical equation below:

2 Na (s) + F₂ (g) ----> 2 NaF (s)

The reaction is a highly exothermic reaction. The compound formed, NaF is an ionic compound.

During the reaction, two moles of sodium atoms lose an electron each to fluorine gas atom which readily accepts the electrons to fluoride ions.

electrostatic forces of attraction between the oppositely-charges ions keep the compound in a crystal lattice form.

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As ′y′ is the energy of molecular orbitals, then for bonding molecular orbital, it is [tex]\frac{y}{2} - x[/tex] and for antibonding molecular orbital, it is [tex]\frac{y}{2} + x[/tex] according to the molecular orbital theory.

Different electron affinities cause the phenomena of different molecular orbital distributions in bonds. Atoms with a high electron affinity tend to control the filled molecular orbitals because they have a strong inclination to attract electrons inward and toward their centers. The vacant molecular orbitals are often dominated by those with weak electron affinities.

According to the molecular orbital theory, a bonding and antibonding molecular orbital pair's differing energies are accompanied by the fact that the energy by which a bond is reduced is less than the energy by which a bond is increased, i.e., the stabilizing energy of each bonding interaction is smaller than the destabilizing energy of antibonding.

Therefore, if ‘y’ is the molecular orbital energy, the antibonding molecular orbital has [tex]\frac{y}{2} + x[/tex] and the bonding molecular orbital has [tex]\frac{y}{2} - x[/tex].

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1.29 milliliters of 3.00 m [tex]H_{2}[/tex] [tex]SO_{4}[/tex] (Sulfuric acid) are required to react with 4.35 g of a solid mixture containing 23.2 % (w/w) [tex]Ba(NO_{3)2[/tex]

Equation of the reaction:

[tex]H_2[/tex]S[tex]O_{4}[/tex](aq) + Ba(N[tex]O_{3}[/tex][tex])_{2}[/tex](aq) --> BaS[tex]O_{4}[/tex] + 2HN[tex]O_{3}[/tex](aq)

Mass of [tex]Ba(NO_{3)3[/tex] = wt% * mass of the solid

= 23.2 x 4.35 / 100

= 1.01 g

Number of moles of [tex]Ba(NO_{3)2[/tex] = Mass / Molar Mass

Molar mass of [tex]Ba(NO_{3})2[/tex] = 137 + (14 + (16 * 3))*2

= 261 g/mol

= 1.01 / 261

= 0.00387

Since the chemical reaction occurs between one mole of Ba(NO3)2 and one mole of [tex]H_{2[/tex] [tex]SO_{4}[/tex]. Therefore, number of moles of [tex]H_{2}[/tex] [tex]SO_{4}[/tex] = 0.00387 moles. The formula is

Volume = number of moles/molar concentration

= 0.00387/3

= 0.00129 L

V2 = 1.29 mL

Hence, 1.29 milliliters of 3.00 m [tex]H_{2}[/tex] [tex]SO_{4}[/tex] (Sulfuric acid) are required to react with 4.35 g of a solid mixture containing 23.2 % (w/w) Ba(NO3)2.

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The complete question is:

How many milliliters of 3.00 m H2SO4 are required to react with 4.35 g of a solid mixture containing 23.2 % (w:w) Ba(NO3)2? (i.e. in the original sample, there are 23.2 g of barium nitrate per 100 g of total sample).

The initial volume of the gas is obtained as 11.02 L.

The work done can be obtained from the use of the formula;

W = PΔV

W = work done on the gas

P = pressure of the gas

ΔV = Change in volume

Now we can see that;

Internal energy = 127.5 J or 1.26 Latm

Heat lost = 34.7 J or 0.34 Latm

We now have;

-1.26 = 0.34 -  0.900(12.80 - V1)

-1.26 = 0.34 - 11.52 + 0.9V1

-1.26 + 11.18 = 0.9V1

V1 = -1.26 + 11.18 / 0.9

V1 = 11.02 L

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Answer:

So, total number of atoms = 6 + 12 + 6 = 24.

Explanation:

A polar covalent bond will exist in HBr if the electronegativity of hydrogen is 2. 20 and the electronegativity of bromine is 2.96

In HBr, a covalent bond is present which is formed as a result of a small electronegativity difference between the two atoms.

It is also formed when two atoms share electrons mutually to form a bond.

For example, in the HBr case, both Bromine and hydrogen share their pair of electrons and form a covalent bond.

In general, a covalent bond forms between atoms when the forces of attraction and repulsion are balanced and in a stable condition.

In covalent bonding, shared pair of electrons is called bonding pair.

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The compound would have higher ionic character if the difference in electronegativity between the atoms is higher.

Electronegativity is a property that explains the tendency of an atom to attract more electrons from other compounds to itself which would result in bond formation. If the attraction or electronegativity is higher, it results in ionic bond between the atoms. This is called ionic character.

We can also say that the ionic character would be high if the covalent character is less in a compound.

Thus, higher electronegativity between shared electrons between atoms and less covalent character in a compound would help us identify the compounds with higher ionic character.

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If a  circuit is arranged so that the current may take two or more different paths then it is a parallel circuit .

What is circuit.

circuit is a completely circular path where electricity flow.

A circuit consists a current source , conductor and a load.

It is a close path or a line forming boundary.

A parallel circuit comprises branches so that the current divided .

The rule of parallel circuit is all components share the same voltage .

It is simple safe and reliable it's allowed for additional components .

The application of parallel circuit is the electrical wiring to the power point in every household is in the form of parallel circuit.

That's why it's called parallel circuit.

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Answer:

Parallel circuit

Explanation:

Penn Foster

Answer:

The density is 33.4

Explanation:

mark as brianlest

The total volume of gas present at the end of the experiment in cm³ was 600. Option C.

In this chemical reaction, 2 molecules of ammonia NH3 are decomposed or decomposed into 1 molecule of nitrogen N2 and 3 molecules of hydrogen H2. Laboratory glass tubing is used in many laboratories and industrial workplaces to connect other glassware and equipment and to transport or dispense chemicals, solvents, liquids, gases, and other products.

Laboratory glass tubes are typically manufactured from borosilicate glass for the most demanding applications. Ammonia gas which has a lower molecular weight than hydrogen chloride diffuses faster and travels a longer distance in the tube. As a result, a white ring of ammonium chloride forms much closer to the hydrochloric acid end of the tube.

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Percent recovery in the first crop is 70%

Total percent recovery is 80%

Percent recovery is defined as amount recovered divided by the total possible amount recovered

First part:

Amount recovered=7g

Total amount recoverable=10g

Percent recovery=7/10=.7=70%

Percent recovery in the first crop is 70%

Second part:

Amount recovered=(7+1)g=8g

Total amount Recoverable=10g

Percent recovery=8/10=.8=80%

Total percent recovery is 80%

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Avogadro's Number:

Avogadro's number, which is equal to 6.02214076 x [tex]10^{23}[/tex] , is the quantity of units in one mole of any material. Hence, 1 mole of calcium phosphate,[tex]Ca_{3} (PO_{4}) _{2}[/tex]   will contain 6.02214076 x [tex]10^{23}[/tex]   atoms.

The molar mass of calcium phosphate is 310.18 g/mol,

Then, number of moles in 24.83g of calcium phosphate = [tex]\frac{mass}{molar mass}[/tex]

                                                                                              = [tex]\frac{24.83}{310.18}[/tex]

                                                                                               = 0.08 mole

Then, 0.08 mole of [tex]Ca_{3} (PO_{4}) _{2}[/tex]   will contain,

= 0.08 moles x 6.02214076 x [tex]10^{23}[/tex]   atoms

=  0.4818 x [tex]10^{23}[/tex]   atoms = 4.818 x  [tex]10^{22}[/tex] atoms.

Hence, 0.08 mole of calcium phosphate will contain 4.818 x  [tex]10^{22}[/tex] atoms.

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Using the balanced reaction equation, we can calculate that 0.399 moles of iodine reacted.

To solve this, we need to write the balanced reaction equation first:

H₂ + I₂ → 2HI

Now we can use the actual yield and the percent yield to calculate the theoretical yield:

0.590 mol / 0.740 = 0.797 mol of HI

From the reaction equation, we can see that 1 mole of iodine produces two moles HI. Using that information, we can set up the following proportion:

1 mol of I₂ : 2 mol of HI = X : 0.797 mol of HI

X = 1 mol of I₂ * 0.797 mol of HI / 2 mol of HI

X = 0.399 mol of I₂  

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Answer:

5.12x10+5 lbs

2.32E+9 g

Explanation:

Density = 732.22 kg/m^3

Volume = 12 gal

Conversion Factor:  0.00378541 gal/m^3 or 264.1721769 m^3/gal

Convert 12 gallons to m^3:  (12 gal)*(264.2 m^3/gal) = 3170 m^3 in 12 gal

Determine total mass from volume:  (3170 m^3/12 gal)(732.2 kg/m^3) = 2321186 kg in 12 gal.

Conversion Factor:  1000 g/kg

Mass of gasoline:  (2321186 kg)*(1000g/kg) = 2.32E+9 g

Conversion Factor:  0.453592 kg/lb or 2.20462442 lb/kg

Yotal wieght = 231186 kg)*(2.205 lb/kg = 511734 lbs (5.12E+5 lbs)

Therefore, the independent variable was cause and the dependent

variable was effect.

An independent variable is a variable that you manipulate or change in an experimental study to study its effects. It is called "independent" because it is not influenced by  other variables in the study.

Independent variables are also called:

These terms are especially used in statistics, where you can assess the extent to which a change in the independent variable  can explain or predict changes in the dependent variable.

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Answer:

the whole answer for everything is

temperature

solubility

temperature

solubility

clearly supported

Explanation:

hop this helped ong

Ammonia (NH[tex]_{3}[/tex]) is the gas that will diffuse faster as it has lower molecular weight than CO[tex]_{2}[/tex].

The rate of diffusion or effusion is explained by Graham's law. According to this law, lighter atoms and molecules will diffuse through the air more quickly than heavier atoms and molecules while a gas's temperature and pressure are kept constant.

The rate of effusion of a gas is the process by which material particles from the confined region gradually start to escape. Think about how a balloon would deflate from the inside out if we made a hole in it, allowing the gas inside to start escaping into the atmosphere. This is referred to as the effusion of gas into the atmosphere.

As ammonia has lower molecular weight than CO[tex]_{2}[/tex], it will diffuse faster.

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The optical activity of the given enantiomer pairs is inactive, active, inactive, active, active, and inactive respectively.

Enantiomers have similar physical and chemical characteristics, making it difficult to identify and separate them. A chiral compound's right- and left-handed enantiomers cause different perturbations in plane-polarized light. It has been called optical activity and is specific to chiral compounds.

Optically active substances rotate the plane of polarized light. A stereoisomeric pair has two identical but sign-opposite enantiomers, each of which is optically active. Because they are scientifically established constants that describe and distinguish pure enantiomers, specific rotations are helpful.

a) 50% r enantiomer and 50% s enantiomer – Optically inactive because the plane-polarized light is moved in an equal but opposing direction by both the r and s enantiomers.

b) A pair of diastereomers – Optically active because these compounds have the same molecular formula but also have non-superimposable non-mirror images.

c) A meso compound – Optically inactive as they do not have enantiomers, because the mirror image of a meso compound is itself.

d) 40% r enantiomer and 60% s enantiomer – Optically active since the s enantiomer is in excess (60 – 40 = 20%).

e) Just the r enantiomer – Optically active because of the light's plane of polarization rotating.

f) A racemic mixture – Optically inactive because each component's rotatory impact completely balances out the other.

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Minimum qualifications of Astronomer 4 year degree to get a postgraduate qualification like a master of physics.

2 or 3 A levels, or similar, in math and physics; 5 GCSEs at grades 9 to 4 (A* to C), or equivalent; and a degree in a field that is useful for postgraduate study.

Math and physics expertise, analytical thinking abilities, science knowledge, great verbal communication skills, the capacity to take initiative, and the capacity to think coherently utilizing logic and reasoning are all desirable. To be extremely knowledgeable about computer applications and systems.

A scientist who concentrates their research on a particular issue or area outside the purview of Earth is called an astronomer in the science of astronomy. In either observational or theoretical astronomy, they observe celestial bodies like stars, planets, moons, comets, and galaxies.

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Answer:

The element was discovered on Earth in 1817 by Johan August Arfvedson (1792-1841) in Stockholm when he investigated petalite, one of the first lithium minerals to be discovered. (It was observed to give an intense crimson flame when sprinkled on to a fire.)

The volume of oxygen required to react with 4.03g Mg at STP is found to be 1860mL by using the ideal gas equation.

An ideal gas is a theoretical gas comprised of numerous randomly moving particles that do not interact with one another. A true gas is the polar opposite; it takes up space (volume) and its molecules interact. As a result, PV is always equal to nRT.

The ideal gas law is a single equation that links an ideal gas's pressure, volume, temperature, and number of moles. The combined gas law describes the relationship between a gas's pressure, volume, and temperature.

Reaction:

[tex]2Mg (s) + O_2 (g) \rightarrow 2MgO (s)[/tex]

Given:

Mass of Mg = 4.03g

STP

To find:

Volume of Oxygen = ?

Formula:

PV = nRT

Calculations:

No. of moles of Mg = 4.03/24 = 0.168 mol

2 moles of MgO are obtained from 2 moles of Mg

1 mole of [tex]O_2[/tex] gives 2 moles of MgO

Therefore,

No. of moles of Oxygen = 0.168 / 2 = 0.084 mol

Volume of Oxygen = nRT/P

Volume of Oxygen = 0.084 x 0.082 x 273 / 1

Volume of Oxygen = 1.860L

Volume of Oxygen = 1860mL

Result:

1860mL of oxygen is required to react with 4.03g Mg at STP.

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A separation method known as chemical extraction depends on the difference between an element's solubility in an organic solvent and an aqueous solution.

Organic solvents are chemicals with a carbon structure that can dissolve or disperse one or more other compounds. Organic solvents have the potential to be neurotoxins, genital poisons, and carcinogens. The organic solvents benzene, carbon tetrachloride, and trichloroethylene are carcinogenic. The boiling point of organic solvents is low – Organic solvents are known to have very low boiling points.

Vegetable oil is analysed and weighed for use as an organic solvent for wastewater treatment in liquid membrane systems.e vegetable oil as a more sustainable organic solvent is highlighted.

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The ratio of the constants for the two reactions is found to be 7.10 by using the Arrhenius equation.

The Arrhenius equation is [tex]k = A e^\frac{-Ea}{RT}[/tex], where A is the frequency or pre-exponential factor and [tex]e^\frac{-Ea}{RT}[/tex] is the proportion of collisions at temperature T that have enough energy to overcome the activation barrier (i.e., have energy higher than or equal to the activation energy Ea).

The exponential part in the Arrhenius equation means that when the activation energy diminishes, the rate constant of a reaction grows exponentially. Because the rate of a reaction is exactly proportional to its rate constant, the rate also grows exponentially. Because a reaction with a low activation energy requires less energy to reach the transition state, it should occur more quickly than a reaction with a higher activation energy.

Given:

T = 25℃ = 25 + 273 = 298K

[tex]Ea^B - Ea^A[/tex] = 28kJ/mol = 28000J/mol

R = 8.314J

To find:

kA / kB = ?

Formula:

[tex]k = A e^\frac{-Ea}{RT}[/tex]

Calculations:

From Arrhenius equation,

kA = [tex]A e^\frac{-Ea^A}{RT}[/tex]

kB = [tex]A e^\frac{-Ea^B}{RT}[/tex]

kA / kB = [tex]e^\frac{Ea^B - Ea^A}{RT}[/tex]

kA / kB = [tex]e^\frac{28000}{8.314 * 298}[/tex]

kA / kB = 7.10

Result:

The ratio of the constants is found to be 7.10

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Electrons subatomic particles surrounding the nucleus of tungsten are responsible for the continuous spectrum observed.

These particles are commonly referred to as subatomic particles since they are the building blocks of atoms. There are protons, neutrons, and electrons, three types of subatomic particles. Protons and electrons, two of the subatomic particles, each have an electrical charge of one or the other.

Two crucial functions for subatomic particles in the construction of matter. They serve as both the universe's fundamental building blocks and the glue that connects them. Although the atoms that play these various jobs belong to two separate categories, they do have some things in common, most notably size.

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Using the law of the conservation of mass, we can see that the aluminum metal would precipitate out of the solution as aluminum oxide.

Let us recall that the law of the conservation of mass states that mass can not be created nor destroyed but the mass can be converted from one form to another. In this case, we can see that the mass of the system would remain a constant. The mass of the system does not change this is in accordance with the law of the conservation of mass.

Hence, When performing the last step in the reaction, aluminum metal is added in excess to the solution. It reacts and dissolves, there would be a recovery of the aluminum as the oxide of the aluminum and by  doing the mass of the system would remain the same but before and after the reaction.

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Answer:

They share an outer electron.

Explanation:

For complementary reasons, sodium and chlorine are both highly reactive. Sodium has a single electron in its outermost, third shell, and chlorine has one electron less than eight in its outermost, fourth shell. They form a strongly bound molecule by sharing that outer electron.

From the balanced equation, 8 moles of ammonia are formed when 4 moles of nitrogen react.

                           N₂ + 3H₂ ⇒ 2NH₃

That's the balanced equation in the question. A mole in a chemical equation is usually denoted by the coefficient of each substance. From the equation, one mole of Nitrogen reacted with three moles of hydrogen to produce 2 moles of ammonia. Using this information, we can produce a mole ratio. A mole ratio is the ratio of the number of moles of one reactant required to completely react with another reactant or the ratio of the number of moles of one product produced to another product.

The mole ratio in the above equation is

                                        1 : 3 : 2

To easily find how many moles of ammonia are formed when 4 moles of nitrogen react:

                 1 mole of Nitrogen = 2 moles of ammonia

                 4 moles of nitrogen = x moles of ammonia

Therefore, x = 4 x 2/1 = 8 moles of ammonia.

     Thus, 8 moles of ammonia are formed when 4 moles of nitrogen react.

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The equilibrium constant is equal to 7.09 * 10⁻³ atm³.

The expression for the equilibrium constant (Kp) for this reaction will look like this:

Kp = (pNH₃)²pCO₂

pNH₃ - partial pressure of NH₃

pCO₂ - partial pressure of CO₂

Because ammonium carbamate is solid, its concentration and pressure cannot change (they are constant), so there is no need to include it in the expression. We know that all the gas present in the mixture is formed by the decomposition of ammonium carbamate. We also know that for every two moles of ammonia formed, 1 mole of carbon dioxide is also formed.

Because partial pressure is proportional to the molar ratio, we can establish  that:

pNH₃ = 2 * pCO₂

pNH₃ + pCO₂ = 0.363 atm

2 * pCO₂ + pCO₂ = 0.363 atm

3 * pCO₂ = 0.363 atm

pCO₂ = 0.363 atm / 3

pCO₂ = 0.121 atm

pNH₃ = 2 * 0.121 atm

pNH₃ = 0.242 atm

We can now plug these values into the expression for the equilibrium constant:

Kp = (0.242 atm)² * 0.121 atm = 7.09 * 10⁻³ atm³

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