Answer:
out of 700 full marks dolma obtained 525 marks in an examination express her marks in percent
The length of a rectangle is 27 meters and the width is 4 meters. Find the area. Give your answer without units.
Answer:
[tex]108 m^{2}[/tex]
Step-by-step explanation:
[tex]27\times4=108[/tex]
CIRCLE question is in the picture
Answer:
27π cm² or 84.8 cm²
Explanation:
[tex]\sf Formula \ for \ area \ of \ sector = \dfrac{\theta}{360 } \ x \ \pi (radius)^2[/tex]
Shaded region angle: 360° - 90° = 270°
Given radius: 6 cm
Applying formula:
[tex]\rightarrow \sf \dfrac{270}{360} \ x \ \pi (6)^2[/tex]
[tex]\rightarrow \sf 27\pi[/tex]
[tex]\rightarrow \sf 84.823 \ cm^2[/tex]
[tex]\rightarrow \sf 84.8 \ cm^2 \quad (rounded \ to \ nearest \ tenth)[/tex]
Please help! I will give you lots of points!!!
Directions: construct the bisector of the following figures.
Note: please draw them out each on a piece of paper or laptop. Thank you!
A bisector is a line that divides either a given line or an angle into two equal parts. The answer to the given question is in the attachments to this answer.
The process of bisection implies dividing a given angle or line into two equal parts. Thus a bisector should be constructed.
The construction required is as given below:
For figure 1:
With center S and any radius, draw an arc to intersect S and T.Using the end of the arc on SR and a greater radius, draw two arcs.Using the end of the arc on ST and the same radius, draw another arc to intersect the previous arc.Join S to the point of intersection of the arcs by a straight line. Thus this line is the required bisector of <RST.For figure 2:
With center u and any radius, draw an arc to intersect T and V.Using the end of the arc on uT and a greater radius, draw two arcs.Using the end of the arc on uV and the same radius, draw another arc to intersect the previous arc.Join u to the point of intersection of the arcs by a straight line. Thus this line is the required bisector of <TuV.For figure 3:
With center B and any radius, draw an arc to intersect A and C.Using the end of the arc on AB and a greater radius, draw two arcs.Using the end of the arc on BC and the same radius, draw another arc to intersect the previous arc.Join B to the point of intersection of the arcs by a straight line. Thus this line is the required bisector of <ABC.The required construction is as shown in the attachments to this answer.
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(3√5)(10√3) help me pls
Solve the system using substitution.
y - 3x = 1
2y - X = 12
([?], [ ?])
Answer:
x = 2 , y = 7
Step-by-step explanation:
Since
y-3x = 1
y = 3x+1 - equation 1
2y-x = 12 - equation 2
Since we are using substitution method,
we will substitute equation 1 into equation 2.
[tex]2(3x + 1) - x = 12 \\ 6x + 2 - x = 12 \\ 5x + 2 = 12 \\ 5x = 12 - 2 \\ 5x = 10 \\ x = \frac{10}{5} \\ = 2[/tex]
Now we substitute x into equation 1 to find y.
[tex]y = 3(2) + 1 \\ = 6 + 1 \\ = 7[/tex]
Therefore x = 2, y = 7.
What is the greatest common factor of 6, 42, and 18?
Answer:
Step-by-step explanation:
1) List the factors of each number.
Factors of 6 : 1, 2, 3, 6
Factors of 42 : 1, 2, 3, 6, 7, 14, 21, 42
Factors of 18 : 1, 2, 3, 6, 9, 18
2) Find the largest number that is shared by all rows above. This is the GCF.
GCF = 6
Pls Help! Geometry
Find the area of the shaded region.
Answer: 112.5 square cm
Step-by-step explanation:
The area of the rectangle is [tex](20)(9)=180[/tex] square cm.
The area of the white triangle is [tex]\frac{1}{2}(9)(20-3-2)=67.5[/tex] square cm.
So, the area of the shaded region is [tex]180-67.5=112.5[/tex] square cm.
Miles is starting a tree farm. His plot of land is triangular with one side 36 feet and the other two sides 30 feet each. The height of this triangle-shaped plot is 24 feet. If each tree needs 8 square feet of space to grow, how many trees can Miles plant?
a. 35 b. 42 c. 54 d. 76
Answer:
54
Step-by-step explanation:
the plot of land is an isosceles triangle, meaning two sides and angles are the same in value.
height (h)= 24
base (b)= 36
length (l)= 30
solution
find the area of triangle using area=half the product of the base and height.
A=1/2(36×24)
A= 216 square feet.
each tree needs 8 square feet
therefore using ratio and proportion,
1 tree= 8 square feet
x trees= 216 square feet
cross multiply and it'll be
216/8=x
therefore x= 54 trees
Mrs. evans has 5 spaces in which to display 5 baskets. how many ways can mrs. evans display the baskets?
Factorial of a positive integer is the result of the repeated multiplication of all the integers from 1 to that considered integer. The number of ways Mrs Evans can display the 5 baskets is 120.
What is factorial?Factorial of a positive integer is the result of the repeated multiplication of all the integers from 1 to that considered integer.
Thus, if we want to take the factorial of 'n',(n being a positive integer), then:
[tex]n! = 1 \times 2 \times \cdots \times (n-1) \times n[/tex]
We usually write it in reverse order because, in calculations, its cancellation comes useful. Thus, we have:
[tex]n! = n \times (n-1) \times \cdots \times 2 \times 1[/tex]
Mrs. evans has 5 spaces in which to display 5 baskets. Therefore, the number of ways Mrs Evans can display the 5 baskets are,
Number of ways = 5! = 5×4×3×2×1 = 120
Hence, the number of ways Mrs Evans can display the 5 baskets is 120.
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What method of matrixes would be used for this question? ( Inverse Matrices, Cramer's Rule, Gaussian Elimination, and Gauss-Jordan Elimination)
May’s restaurant ordered 200 flowers for Mother’s Day. They ordered carnations at $1.50/each, roses at $5.75 each, and daisies at $2.60 each. They ordered mostly carnations, and 20 less roses than daisies. The total order came to $589.50. How many of each type of flower was ordered?
Answer:
(d) Gauss-Jordan Elimination
80 carnations; 50 roses; 70 daisies
Step-by-step explanation:
The given relations can be written as equations, which can be expressed as one matrix equation. Any of the methods listed can be used to solve the matrix equation.
EquationsIf we let c, r, d represent numbers of carnations, roses, and daisies ordered, respectively, then the given relations can be written as ...
c + r + d = 200 . . . . . . 200 flowers were ordered
0c -r +d = 20 . . . . . . . . . . . . . 20 more daisies than roses were ordered
1.50c +5.75r +2.60d = 589.50 . . . . . the total value of the order
Matrix EquationWritten as a matrix equation, it will be of the form ...
AX = B
where A is the square matrix of variable coefficients, X is the column vector of variables, and B is the column vector of equation right-side constants. This is the matrix equation:
[tex]\left[\begin{array}{ccc}1&1&1\\0&-1&1\\1.50&5.75&2.60\end{array}\right] \left[\begin{array}{c}c\\r\\d\end{array}\right] =\left[\begin{array}{c}200\\20\\589.50\end{array}\right][/tex]
Solution MethodsThe mathematical operations required to find the equation solution can be briefly described as ...
Inverse Matrices
The coefficient matrix is inverted and multiplied by the constant column vector:
[tex]X=A^{-1}B[/tex]
The inversion operation requires computation of 10 determinants, of which 9 are of 2×2 matrices. That's a total of about 39 multiplications, 9 divisions, and 20 additions.
Cramer's Rule
Using Cramer's rule requires computation of 4 determinants of 3×3 matrices. The total number of operations comes to about 48 multiplications, 3 divisions, and 20 additions.
Gaussian Elimination
To obtain the upper triangular matrix that results from Gaussian Elimination requires about 11 multiplications, 11 additions, and 2 divisions. This finds the value of one variable, but the others must be found by substitution into the remaining two equations, requiring an additional 3 multiplications and 3 additions.
Gauss-Jordan Elimination
This method starts with an augmented matrix that appends column vector B to the square matrix A. The result of this is shown in the attachment. It is a diagonal matrix with the variable values a direct result of the matrix operations. The calculator's RREF( ) function performs matrix row operations to transform the augmented matrix to this Reduced Row-Echelon Form. About 6 multiplications, 6 additions, and 4 divisions are required.
Clearly, Gauss-Jordan Elimination is the method that requires the least computational work, so it would probably be used for this question.
FlowersThe attachment shows the order to be ...
80 carnations50 roses70 daisies__
Additional comment
The estimates of computational load presented by each of the solution methods are not intended to be exact counts. For this specific problem, some of the operations can be avoided due to the fact that some coefficients are already 1. Also, some computations are not needed simply because they are intended to produce an outcome that is already known. The intention is to give an idea of the relative difficulty of using these different methods.
In some cases, computationally less-efficient methods may be preferred because they are simpler to describe.
Help
Note that: The solution must be non zero
Spam/Irrelevant answers will
be reported
Answer:
Step-by-step explanation:
[tex]y'' + \omega^2 y = 0[/tex]
has characteristic equation
[tex]r^2 + \omega^2 = 0[/tex]
with roots at [tex]r = \pm\sqrt{-\omega^2} = \pm|\omega|i[/tex], hence the characteristic solution is
[tex]y = C_1 e^{i|\omega|x} + C_2 e^{-i|\omega|x}[/tex]
or equivalently,
[tex]y = C_1 \cos(|\omega|x) + C_2 \sin(|\omega|x)[/tex]
With the given boundary conditions, we require
[tex]y(0) = 0 \implies C_1 = 0[/tex]
and
[tex]y'(\pi) = 0 \implies -|\omega| C_1 \sin(|\omega|\pi) + |\omega| C_2 \cos(|\omega|\pi) = 0[/tex]
With [tex]C_1=0[/tex], the second condition reduces to
[tex]|\omega| C_2 \cos(|\omega|\pi) = 0[/tex]
Assuming [tex]C_2\neq0[/tex] (because we don't want the trivial solution [tex]y=0[/tex]), it follows that
[tex]\cos(|\omega|\pi) = 0 \implies |\omega|\pi = \pm\dfrac\pi2 + 2n\pi \implies |\omega| = 2n\pm\dfrac12[/tex]
where [tex]n[/tex] is an integer. In order to ensure [tex]|\omega|\ge0[/tex], we must have [tex]n\ge1[/tex] if [tex]|\omega|=2n-\frac12[/tex], or [tex]n\ge0[/tex] if [tex]|\omega|=2n+\frac12[/tex].
A driveway 18 ft wide and 36 ft. long is to be paved with concrete 3 in. thick. How many cubic yards of concrete are required?
Answer:
6 yds^3
Step-by-step explanation:
I find these easiest if you put all of the dimensions into yards and then multiply
18 ft = 6 yds
36 ft = 12 yds
3 in = 3/36 yds = 1/12 yds now multiply them together
6 x 12 x 1/12 = 6 yds^3
You have $1,300 in savings for retirement. If your investments earn 12% annually, how much will you have in your retirement account in 11 years?
Step-by-step explanation:
Answer :- Amount (after 11 years) = $4522.11
Instructions: Solve the quadratic equation and simplify your answer(s).
7x2=−12−5x
x=
-5
+
√
,
-5
−
√
14
14
[tex]7x^2 = -12-5x\\\\7x^2 + 5x+12=0\\\\x=\frac{-5 \pm \sqrt{5^{2}-4(7)(12)}}{2(7)}\\\\\boxed{x=\frac{-5 \pm i \sqrt{311}}{14}}[/tex]
If three times a number added to 2 is divided by the number plus 4 the result is eight thirds. Find the number
Answer:
26
Step-by-step explanation:
(3a+2)/(a+4) = 8/3
(3a+2) = (8/3)(a+4)
(3a+2) = a*8/3 + 4*8/3
(3a+2) = 8a/3 + 32/3
3a - 8a/3 = 32/3 - 2
9a/3 - 8a/3 = 32/3 - 6/3
9a - 8a = 32 - 6
a = 26
Check:
(3*26 + 2) / (26+4) = 8/3
(78+2) / 30 = 8/3
80 / 30 = 8/3
Find the Equation of the Perpendicular Line
Instructions: Find the equation of the line through point (-1, 2) and perpendicular to x + 3y = 3.
y =
Answer:
y = 3x +5
Step-by-step explanation:
The equation of a perpendicular line can be formed by swapping the x- and y-coefficients, and negating one of them. The constant in the equation will be chosen to make the equation true at the given point.
Coefficients swappedThe desired equation in the given standard form will be ...
3x -y = c . . . . . . for some new constant c
Note that we have kept the x-coefficient positive, and have negated the y-coefficient.
Constant valueThe new constant will make the equation true at the point (-1, 2):
3(-1) -(2) = c = -5
So, the standard-form equation is ...
3x -y = -5
Slope-intercept formThe answer form suggests you want to solve this for y. Adding y+5 to both sides will give the form you want:
3x -y +(y+5) = -5 +(y+5)
3x +5 = y
y = 3x +5
Suppose a graphic designer earns $52,000 and is not self-employed. How much will the designer have to pay in FICA taxes?
The amount that the designer will have to pay in FICA taxes is:$3,978.
FICA taxes
FICA taxes comprises of:
Social Security tax= 6.2%
Medicare tax= 1.45%
Hence:
FICA taxes=($52,000×6.2%)+($52,000×1.45%)
FICA taxes=$3,224+$754
FICA Taxes=$3,978
Therefore the amount that the designer will have to pay in FICA taxes is:$3,978.
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Choose the letter of the equation for
the graph.
Answer:
a
Step-by-step explanation:
The midline is at y=2.
Eliminate c, d, eAlso, since there is no horizontal shift amongst the remaining options, we know that since y=2 when x=0, this means it must be a sine curve.
This means the answer is a.
Runner A finished 200 meter race in 5/12 of a minute. Runner B ran it in 21/25 of runner A's time. How much time did it take runner B to finish the race?
The time it will take runner B to finish the race is 7/15 of a minutes
FractionRunner A = 200 meters in 5/12 minutesRunner B = 21/25 of runner A timeTime taken by runner B = 21/25 × 5/12 minutes
= (21 × 5) / (25 × 12)
= 105 / 300
= 7/15 minutes
Therefore, it takes runner B 7/15 of a minutes to run the same race as runner A.
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Volume and surface area
Answer:
The volume of the suitcase will be 199.5 [tex]ft^{3}[/tex]
Step-by-step explanation:
To find the volume of a 3D shape (in question, the suitcase) we use the formula length x width x height. With this in mind, we multiply 19 x 7 = 133. Multiply 133 by 1.5, which equals 199.5. With a final answer of 199.5, the volume of the suitcase will be 199.5 [tex]ft^{3}[/tex].
7/8 divided by 9/10[tex]7/8 divided by 9/10[/tex]
Step-by-step explanation:
a ) Solution,
[tex] = \frac{7}{8} \div \frac{9}{10} \\ [/tex]
[tex] = \frac{7}{8} \times \frac{10}{9} \\ [/tex]
[tex] = \frac{70}{72} \\ [/tex]
Change into lowest term....
[tex] = \frac{35}{36} \\ [/tex]
On Friday, a local hamburger shop sold a combined total of 376 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Friday?
Answer:
94 hamburgers
Step-by-step explanation:
Let's solve this question through the use of equations.
Start by defining the variables used.
Let the number of hamburgers and cheeseburgers sold on Friday be h and c respectively.
Form 2 equations using the given information.
Given that the total sold is 376,
h +c= 376 -----(1)
The number of cheeseburgers sold was thrice the number of hamburgers sold.
c= 3h -----(2)
Solving by substitution:
Substitute (2) into (1):
h +3h= 376
Now that we have an equation expressed only in terms of h, we can find the value of h.
4h= 376
Divide both sides by 4:
h= 376 ÷4
h= 94
Thus, 94 hamburgers were sold on Friday.
14. If m is a positive integer, then which of the
following is equivalent to 4m + 4m + 4m + 4m?
(A) 4m+1
(B) 4^4m
(C) 4^4m + 1
(D) 4m +4
Hello!
Simplifying :
⇒ 4m + 4m + 4m + 4m
⇒ 4(4m)
None of the above
what number could t represent to make the inequality true? 2t+4<-8
2t + 4 < -8
2t < -12
t < -6
For the inequality to be true, t must be a number that is less than -6.
Hope this helps!
Simplify (38)-2(13⋅38)3(13)4.
The value of (38)-2(13⋅38)3(13)4. is -154090
How to simplify the expression?The expression is given as:
(38)-2(13⋅38)3(13)4.
Rewrite properly as:
(38) - 2 * (13 * 38) * 3 * (13) * 4.
Evaluate the products in the bracket
(38) - 2 * (494) * 3 * 52
Further, expand
38 - 154128
Evaluate the difference
-154090
Hence, the value of (38)-2(13⋅38)3(13)4. is -154090
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Solve the following equation for X, if Y = 3 and Z = -1. 3XY- 5XZ^2+Y=19
Someone please help!
Answer: horizontal
Step-by-step explanation: there going across sideways and not up and down
Write the statement as an equation." Three is subtracted from the reciprocal of a number. Let x be equal to the number .
Answer:
1/x - 3
Step-by-step explanation:
The number is x.
The reciprocal of the number is 1/x.
3 is subtracted from the reciprocal of a number.
1/x - 3
We have found that:
(X,₁)=(3,-1)
• m = 3
●
Substituting these values in (y - y₁) = m(x-x1), we'll get the equation of the line as:
[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]
Find the equation of the line, with the info given.
[tex]\Large\maltese\underline{\textsf{This problem has been solved!}}[/tex]
The formula used in this problem is,
[tex]\bf{y-y_1=m(x-x_1)}[/tex]□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□□
[tex]\bf{y-(-1)=3(x-3)[/tex] | simplify
[tex]\bf{y+1=3(x-3)}[/tex]
[tex]\rule{300}{1.7}[/tex]
[tex]\bf{Result:}[/tex]
[tex]\bf{=y+1=3(x-3)}[/tex]
[tex]\boxed{\bf{aesthetic \not101}}[/tex]
A single die is rolled twice. Find the probability of rolling a 1 the first time and a 4 the second time.
Answer:
1/36
Step-by-step explanation:
There is an 1/6 chance of rolling 1 the first time and 1/6 chance of rolling a 4 the second time. 1/6 * 1/6 = 1/36 chance of rolling a 1 then 4.