Which one of the following vector pairs is equal in magnitude and opposite in direction?Vectors
explained image
a)one short and one long arrow going towards each other
b)one short and one long arrow going right in the same direction
c)two of the same size arrows going right in the same direction
d)two of the same size arrows going in towards eachother

Select one:
a. A
b. B
c. C
d. D

Answer:

t= 10 seconds

Explanation:

Using the equation of motion with constant acceleration v=u+at

where t is time

a is acceleration of gravity

u is initial speed and f is final speed.

take the downward direction as negative

[tex]u = 0 \\ v = - 100 \frac{m}{s} \\ a = - 10 \frac{m}{{s}^{2} } [/tex]

then

[tex] - 100 = 0 - 10t \\ - 100 = - 10t \\ t = 10s[/tex]

The angle of banking does not affect  the maximum speed at which a car can safely negotiate a frictionless banked curve.

We know that when a car is trying to negotiate a curve, the car is undergoing a circular motion at the bend. The car is tending to move around the bend and then emerge at the other side. Sometimes the bend is made a bit or somewhat steeper at a give angle and this can help the cars to negotiate the ben successfully without skidding off the road.

We know that we can obtain the maximum velocity of the motion of the car as it negotiates the bend using thee formula;

v = √mgr/h

v = velocity

m = mass

g = acceleration due to gravity

r = radius

h = height

It the follows that the maximum speed at which a car can safely negotiate a frictionless banked curve depends on all of the following except  the angle of banking.

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Missing parts;

Complete the following statement: The maximum speed at which a car can safely negotiate a frictionless banked curve depends on all of the following except

A. the diameter of the curve.

B. the acceleration due to gravity.

C. the angle of banking.

D. the mass of the car.

E. the radius of the curve.

The acceleration of the ball just before it reaches its highest point is 9.8m/s2.

At the highest point the velocity turns out to become zero.

Then acceleration = acceleration due to gravity = 9.8 m/s2

The meter per second square (m/s2) is unit of acceleration.

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We can see that the images show that the waves are moving towards each other hence they interfere constructively as shown in the first image or option A.

The term  wave has to do with a disturbance along a medium which transfers energy. We know that the wave could be transverse or longitudinal. A longitudinal wave is one in which the direction of the propagation is the same as that of the disturbance that is producing the wave.

The image that have been shown is that of the interference of waves. Recall that waves could interfere constructively  or destructively. The waves that interfere constructively tend to increase the magnitude of the disturbance while the waves that interfere destructively tends to cancel out each other.

Here, it is obvious that the interference of the waves is quite a constructive one as the disturbance increases clearly from the images shown.

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The resultant vector of 1. 130N and 2.  155 N respectively.

A resultant vector is described as a single vector that produces the identical effect as is produced through a number of vectors collectively.

1. 100 N, 37° east of north + 100 N 60°North -west

Let Force₁ = 100 N sin37°

                  = 100 N × 4/5

                  = 80 N North

      Force₂ = 100 N cos 60°

                  = 100 N × 1/2

                  = 50 N

Now, the angle between F₁ and F₂ is 0

Resultant force = [tex]\sqrt {F₁^{2} +\sqrt F₂^{2} + 2abcos°}[/tex]

                         = [tex]\sqrt{(80)^{2} +(50)^{2}+2*80*50}[/tex]

                        = [tex]\sqrt{6400+2500+8000}[/tex]

                        = [tex]\sqrt{16900}[/tex]

                         = 130N

2.  100N, 37° west of north + 50N,53° east of north

   Force₁ = 100N, 37° west of north

                =100N cos 37°

               = 100N × 5/4

               = 125 N north

  Force₂ =  50N,53° east of north

               = 50N cos 53°

                = 50N × 3/5

                = 30N

The angle between F₁ and F₂ is 0°

Resultant force = [tex]\sqrt {F₁^{2} +\sqrt F₂^{2} + 2abcos°}[/tex]

                           = [tex]\sqrt{(125)^{2} +(30)^{2}+2*125*30}[/tex]

                         = [tex]\sqrt{15625+900+7500}[/tex]

                        = [tex]\sqrt{24025}[/tex]

                         = 155 N

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Answer:

Proteins are organic compounds containing nitrogen that are made of long, linked chains of amino acids and are a part of all living organisms.

If the air resistance is negligible, it will take 2 seconds to reach the ground.

What is air resistance?

Air resistance is the force that opposes an object's relative motion as it moves through the atmosphere. By working against the incoming flow's speed, these drag forces make the object travel more slowly. In contrast to other resistance forces, drag has a direct relationship with velocity because it is the portion of the net aerodynamic force that operates in the opposite direction from the direction of the movement.

As given in the question,

(initial vertical velocity) u = 0,

Air resistance is neglected,

g = 9.8 m/s².

The time (t), required for the pen to reach a vertical velocity of 19.62 m/s is given by:

19.62 m/s = 0 + (9.8 m/s²)*(t s)

t = 19.62/9.8 = 2.00 s

Answer:  2.0 s

Therefore, it will take 2 seconds for pan to reach the speed of 19.61 m/s.

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Complete Question

Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem. Assuming air resistance is negligible, how many seconds does it take the pen to reach a speed of 19.62 m/s?

The electron current driven through a 2.4 mm diameter iron wire by a 0.070 v/m electric field is 24.34 * [tex]10^{18}[/tex] electrons / s

I = n A e [tex]v_{d}[/tex]

[tex]v_{d}[/tex] = т e E / m

I = Current

n = Free electron density

A = Area

e = Charge

[tex]v_{d}[/tex] = Drift velocity

т = Mean time

E = Electric field

m = Mass of charge

т = 5.2 * [tex]10^{-15}[/tex] s

d = 2.4 mm

r = 1.2 mm = 1.2 * [tex]10^{-3}[/tex] m

E = 0.07 V / m = 0.07 N / C

e = 1.6 * [tex]10^{-19}[/tex] C

m = 9.1 * [tex]10^{-31}[/tex] kg

A = π r²

A = 3.14 * ( 1.2 * [tex]10^{-3}[/tex] )²

A = 4.52 * [tex]10^{-6}[/tex] m²

[tex]v_{d}[/tex] = ( 5.2 * [tex]10^{-15}[/tex] * 1.6 * [tex]10^{-19}[/tex] * 0.07 ) / ( 9.1 * [tex]10^{-31}[/tex] )

[tex]v_{d}[/tex] = ( 0.58 * [tex]10^{-34}[/tex] ) / ( 9.1 * [tex]10^{-31}[/tex] )

[tex]v_{d}[/tex] = 63.7 * [tex]10^{-6}[/tex] m / s

n = ( Avogadro's number * Density ) / Atomic mass

Avogadro's number = 6.023 * [tex]10^{23}[/tex] atoms / mole

Density of copper = 8.92 * 10³ kg / m³

Atomic mass = 63.5 * [tex]10^{-3}[/tex] kg / mole

n = 8.46 * [tex]10^{28}[/tex] / m³

I = n A e [tex]v_{d}[/tex]

I = 8.46 * [tex]10^{28}[/tex] * 4.52 * [tex]10^{-6}[/tex] * 1.6 * [tex]10^{-19}[/tex] * 63.7 * [tex]10^{-6}[/tex]

I = 3897.34 * [tex]10^{-3}[/tex]

I = 3.9 A

I = 3.9 * 6.242 * [tex]10^{18}[/tex] electrons / s

I = 24.34 * [tex]10^{18}[/tex] electrons / s

Therefore, the electron current driven through the iron wire is 24.34 * [tex]10^{18}[/tex] electrons / s

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It is to be noted that the required flight visibility and distance from clouds, if you are operating in class e airspace at 9,500 feet MSL with a VFR-on-top clearance during daylight hours, is given as "3 statute miles 1,000 above 500 Below and 2,000 horizontal"

Flight visibility is the average forward horizontal distance from the cockpit of a flying aircraft at which conspicuous unlighted objects can be seen and identified during the day and significant lighted objects can be seen and identified during the night.

Visibility requirements are the minimal visibility for flying.

According to Aviation Rules,

(a) No individual may fly an aircraft under VFR in restricted airspace when the ceiling is less than 1,000 feet unless flight vision is at least 2 miles, according to aviation rules.

(b) No person shall operate a helicopter under VFR at or below 1,200 feet above the ground or within the lateral boundaries of a designated Class B, C, D, or E airspace surface area of ​​an aerodrome unless there is clear visibility. is at least -

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The tension in the string gets doubled when we double the mass of the cart as well as of the mass that hangs from the string.

We know, Newton's Second law states that the force applied to a body is directly proportional to the mass and the acceleration of the body, i.e.,

F = ma

where F is the force applied to the body or the tension in the cart, m is the mass of the body and a is the acceleration of the body.

Since, the mass of the cart is doubled, the tension on the string becomes:

[tex]F_{2}[/tex] = (2m)a

[tex]F_{2}[/tex] = 2ma

[tex]F_{2}[/tex] = 2F

Therefore, the tension in the string also gets doubled.

Complete Question: students work together during an experiment about newton’s laws. the students use a setup that consists of a cart of known mass connected to one end of a string that is looped over a pulley of negligible friction, with its other end connected to a hanging mass. the cart is initially at rest on a horizontal surface and rolls without slipping when released. the inertia of the cart's wheels is negligible. students have access to common laboratory equipment to make measurements of components of the system. The students double the mass that hangs from the string. They also replace the original cart with a new cart that has double the mass. By doubling both masses, how will the tension in the string and the acceleration of the cart change?

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From the description, the  type of telescope was she most likely using is the radio telescope.

The telescope is the kind of device that could be used to find the and see the objects that are in the outer space. There are several kinds of telescopes such as;

The radio telescope is the kind of telescope that is able to convert the radio signals into a format that could be used study the parameters that concern the universe. The clarity of the telescope is most times dependent on the location of the person using the telescope.

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Missing parts;

Sarah just bought a telescope and is telling you all about what she saw last night, but she keeps mentioning that every object she pointed it towards seemed to have a fuzzy

glow. What type of telescope was she MOST likely using?

A. radio telescope

B. refracting telescope

C. compound telescope

D. reflecting telescope

Answer:

She is most likely using a refracting telescope.

Explanation:

These telescopes are easily accessible to the general public and are popular for new astronomers but may produce a fuzzy glow around objects they magnify.

The characteristics of sound waves include wavelength, amplitude, frequency, and velocity which can cause of bridge collapse.

When the prevalence of a wave matches the Natural frequency of the bridge the swing of the bridge can be made up in amplitude up to the point of causing its destruction. This phenomenon is called Resonance. No matter whether you are talking about vibrations or waves, all of them can be characterized by the following four characteristics: amplitude, wavelength, frequency, and speed. The most similar causes of bridge failure are the lack of structure and design, corrosion, construction, and supervision error, accidental overload, impact, scour, and lack of maintenance or inspection.

so we can conclude that Wave characteristics include frequency, period, wavelength, and amplitude that can collapse a bridge.

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Potential energy plus kinetic energy are combined to form mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it.

E mechanical = U + K

E mechanical = mechanical energy

U = potential energy

K = kinetic energy

Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location.

Renewable energy is also fueled by mechanical energy. In order to efficiently produce electricity or convert energy, many sources of renewable energy depend on mechanical energy.

Applying,

Mechanical Energy (M.E.) = ((1/2)mv²) + (m × g × h)

                                          = ((1/2)*100*45²)+(100*9.8*12)

                                          = 101250+ 11760

                                          = 113010 J

m is the object's mass, v is its speed, g is its gravitational acceleration, and h is its height above the ground.

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The heat generated due to the friction in the given process is 367.83 J.

Frictional heat generates when two surfaces slide against each other. The heat generated due to the friction in the given process is 6.92.7 J.

Frictional heat:

This heat is generated when two surfaces slide against each other.

Potential energy :-

U= m g h;

Put the values

U=  18.0-kg* 9.8 m/s^2 *2.20 m

U=388.08 J

The Kinetic energy in the bottom:

K = 1/2 * m * v^2

=  1/2 * 18.0* 1.50^2

K= 20.25 J

So the friction heat,

Hf = U - K

Hf = 388.08 J -20.25 J

Therefore, the heat generated due to the friction in the given process is 367.83 J.

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Gravity causes an object to fall toward the ground more quickly the longer it is in free fall. In reality, an object's velocity increases by 9.8 m/s, and by the time it starts to fall, it has already reached 9.8 m/s.

All matter is impacted by a force called gravity in the universe. Any two non-zero mass objects or particles will gravitationally gravitate toward one another. Gravity has an impact on objects of all sizes, from subatomic particles to galaxy clusters.

Speed after 2 seconds = 40m/s

Since falling causes velocity to increase by 9.8m/s,

Speed 5 seconds after the jump = 40 + (3 * 9.8)

                                                      = 69.4 m/s

When an object is moving, its velocity serves as a measure of how quickly its location is changing as it is perceived from a given point of view and as time is measured using a specific unit of measurement.

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Although part of your question is missing, the complete question is "Find the final velocity of the particle if it is initially moving along the x-axis with a velocity of −1.85 m/s. The force shown in the force-time graph acts on a 2.4kg object."

The final velocity of the particle is 1.43 m/s.

The impulse of force is the product of the resultant force and duration of time under the impulse-momentum theorem.

Δρ = ΔF + Δ t = area under F-t curve.

area = area of rectangle + area of triangle( 1/2 base ×height )

∴ area = (2× 3) + 1/2 (2×2) = 8 N

To find the final velocity, Δρ = mass × Δvelocity

let the final velocity be v'

∴  8 = 2.4 × ( v' - (-1.85))

2.4v' = 8- 4.44

v' = 1.43 m/s.

Hence the final velocity of the particle is 1.43 m/s.

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The maximum amount of weight that can hang from the end of the rod is 8.66 N.

The maximum amount of weight that can hang from the end of the rod is calculated as follows.

Apply the formula for tension using Newton's second law of motion. Newton's second law of motion states that the force experienced by an object is directly proportional to the product of the mass and acceleration of the object.

T sinθ = W

Where;

.

10 sin(60) = W

8.66 N = W

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The data table supports that: Option B, "the force of gravity depends on the masses of the objects interacting." is the correct answer.

What is gravity?

Gravity, also sometimes called as gravitation, is the non-changing force of attraction that binds everything together in mechanics. Being the weakest known force in nature, it has little effect on determining the intrinsic properties of common objects.

In the given data table, the distance is same in all five cases, but we can see that the force of gravity is increasing with increase in mass of any one of the object or both of them. We can also understand it as the force of gravity is increasing with the increase in combined mass of both objects.

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The maximum force I can exert horizontally on the crate without moving it is 588.6 Newtons.

What is force?

A force is a push or pull that an object feels as a result of interacting with another thing. Each time two things come into contact, a force is applied to each one of them. When the interaction is finished, the force is no longer sensed by the two objects. Forces are only real when there is interaction.

The max force I can exert horizontally on the crate without moving it is equal:

[tex]F_{smax} = {\mu_s} \times M \times g[/tex]

where,

μs is the static friction, g is the gravitational force by substituted and M is the mass:

Fsmax = 0.5 * 120Kg * 9.81 m/s2

Fsmax = 588.6 N

when, F= Fsmax

Therefore,

The answer is the force F = 588.6 N

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The gravitational force between Earth and the moon  would decrease if them distance between them increased.

The gravitational force is focused at the system's barycenter rather than at the centers of either object when two objects are gravitationally linked together. It has a similar concept to a see-saw.

We are aware that the gravitational force's equation is F=GMm/r2.

Where M is the force of one object, m is the force of another object, r is the distance between them, and G is the gravitational constant.

As we can see, since F is inversely correlated to r, the gravitational force will grow as their separation widens.

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Answer:Mars is about half the size of Earth by diameter and has a much thinner atmosphere, with an atmospheric volume less than 1% of Earth's. The atmospheric composition is also significantly different: primarily carbon dioxide-based, while Earth's is rich in nitrogen and oxygen.

Explanation:

Answer:The atmosphere of Mars is much thinner than Earth's. The average surface pressure is only about 610 pascals (0.088 psi) which is less than 1% of the Earth's value. The currently thin Martian atmosphere prohibits the existence of liquid water at the surface of Mars, but many studies suggest that the Martian atmosphere was much thicker in the past.

Explanation:

Answer:

magnitude of the force acting on the object

F = ma. The higher the Force, higher the acceleration

Explanation:

Acceleration is directly proportional to the magnitude of the force

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From the question, we can see that the momentum is a vector thus the change in the momentum with respect to the ground observer ought to be zero.

The term momentum has to do with the  product of the mass and the velocity of a body. Let us recall that the momentum of a body is a vector quantity thus we have to consider the magnitude as well as the direction of the vector.

With this said, we are going to consider the question more critically. We are told that; a  ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest.

Looking at the fact that the momentum of the body is a vector and we have seen told that the ball bounces off the wall and returns with the same magnitude of momentum the  it follows that the change in the momentum is zero.

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Missing parts;

A ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest. What expression shows the change in momentum as observed by the ground observer?

a. 0

b 0.5p

c 2p

d 1.5p

In designing a rocket to select an engine based on how much force it produces, the engine need to produce 144 N force.

Force applied on launching model rockets is calculated by the formula,

F = m*a

where,

F is the force of engine

m is the mass

a is the acceleration

The given data are :

m = 5 Kg

a = 28.8 m/s²

F = ?

Now, putting the values in the formula we get,

F = 5 Kg x 28.8 m/s²

F = 144 N

So,  In designing a rocket to select an engine based on how much force it produces, the engine need to produce 144 N force.

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Factors that are needed to determine the amount of heat absorbed by an aluminum cube are the initial and final temperatures of aluminum cube.

Heat absorbed by aluminum is the amount of heat taken during the heating process.

To calculate the heat absorbed durring heating process, we use the formula:

Q = mc(T1 - T2)

Where:

T1 = initial temperature

T2 =  final temperature .

c = specific heat capacity of the aluminum.

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Answer:

The correct options are A, B, C, and E!

Explanation:

I just got it right on edge.

Hope this helps - brainliest would be appreciated!

Have a great day everyone!

Answer:

It will be 1/9 of its previous value

Explanation:

Weight = mass x gravity

Gravity = GM / r²     (G is the constant)

Since the new radius is three times r, we plug in 3r:

New gravity = [tex]\frac{GM}{(3r)^{2} }[/tex]

Since the new gravity is 1/9th of the original gravity, the new weight is 1/9th the original weight.

This tell them the speed of the train.

Because it has no specified direction and just magnitude, speed is a scalar number. The amount and direction of velocity are both vector variables.

Speed, as a scalar number, is the pace at which an item travels. The average speed is defined as the distance (a scalar number) divided by the time ratio. Speed is oblivious to direction. Velocity, on the other hand, is a vector quantity that is conscious of its direction.

Speed is described as the rate at which distance changes over time. It has a distance by time dimension. Thus, the SI unit of speed is defined as a combination of the fundamental units of distance and time.

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The frequency of the sound heard by the driver of the Porsche is 689.39 Hz and 614.8 Hz.

In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

(a) as when a person is in front of the car:

f' = (350 - 0/350 - 20) x f = 350/330 x 650 = 689.39 Hz

(b) when a person is behind the car (source is moving away):

f'' = (350 - 0/350 + 20) x f° = 350/370 x 650 = 614.8 Hz

V(source) = 72 km/h = 20 m/s

V(sound) = 350 m/s

f° = 650 Hz

Hence, the frequency of the sound heard by the driver of the Porsche is 689.39 Hz and 614.8 Hz.

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When an item sinks under force, its volume can be calculated. For this reason, the item is fastened to another readily sinkable object. Since the floating object will sink in the water, its volume may be determined.

One method to determine the volume of a floating object is to weigh it down using a heavy object. It's crucial to figure out the water's depth both with the heavy object submerged and with it pulling the floating object down into the water.

An object floats when the water's upward push balances the weight force acting on it. Untainted by water depth, the amount of the object immersed increases the water is probably upward push.

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