Answer:
Talc powder suspended in air
All forms of energy can exist as either ________ or ________ energy.
Answer:
potentiol or kenetic
Explanation:
Determine how much sulfuric acid (in metric tons) is produced by the combustion of 1.2 metric ton of this coal. (A metric ton is 1000 kg.)
2. Which of the following best represents the nucleus in a model of an atom?
a positively charged nucleus consisting of protons and neutrons
O a positively charged nucleus consisting of electrons and neutrons
a neutral nucleus consisting of protons and neutrons
a neutral nucleus consisting of electrons and neutrons
Answer:
A positively charged nucleus consisting of protons and neutrons
Explanation:
The atomic nucleus is a positively charged region located at the core of an atom that consists of positively charged protons and neutral neutrons while the negatively charged electrons make up the outer cloud (electrons are therefore not contained in the nucleus).
Calculate the amount of heat required to completely sublime 55.0 g of solid dry ice CO2 at its sublimation temperature. The heat of sublimation for carbon dioxide is 32.3 kj mol
Answer:
40.4 kJ
Explanation:
Step 1: Given data
Mass of CO₂ (m): 55.0 gHeat of sublimation of CO₂ (ΔH°sub): 32.3 kJ/molStep 2: Calculate the moles corresponding to 55.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
n = 55.0 g × 1 mol/44.01 g = 1.25 mol
Step 3: Calculate the heat (Q) required to sublimate 1.25 moles of CO₂
We will use the following expression.
Q = n × ΔH°sub
Q = 1.25 mol × 32.3 kJ/mol = 40.4 kJ
What is the concentration of a solution that is made by diluting 50.0 mL of a 0.40 M NaCl solution to a final volume of 1000.0 mL?
Answer:
The correct answer is 0.020 M.
Explanation:
To solve this problem, we can use the equation M1V1 = M2V2, where M represents the molarity of the solution and V represents the volume of solution. Since we are given that the original solution is 50 mL and 0.40 M, these values are V1 and M1, respectively. The solution after dilution has a volume of 1000 mL, so this value is V2. We are solving for the molarity after dilution, which represents M2.
If we plug in the values specified above, we get the following:
M1V1 = M2V2
(0.40 M)(50.0 mL) = (M2)(1000.0 mL)
Solving for M2, we get:
M2 = 0.020 M
Notice that our answer has 2 significant figures because 0.40 has 2 significant figures, the least of any values given in the problem.
Therefore, the answer is 0.020 M.
Hope this helps!
How much energy is produced when 13.1 g of tin reacts with 2.715 g of N2 ?
I.
3 Sn + 2 N2-----------Sn3N4 + 632 KJ
Hint change grams to moles first.
1 mole Sn= 119g
1 mole N2= 28 g
Answer:
23.2 kJ of energy are released by the reaction.
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary for us to calculate the moles of both tin and nitrogen and the produced moles of Sn3N4 product by each reactant as shown below:
[tex]13.1gSn*\frac{1molSn}{119gSn} *\frac{1molSn_3N_4}{3molSn} =0.0367molSn_3N_4\\\\2.715gN_2*\frac{1molN_2}{28gN_2} *\frac{1molSn_3N_4}{2molN_2} =0.0485molSn_3N_4[/tex]
Thus, since 13.1 grams of tin produce the fewest moles of Sn3N4 product, we infer tin is the limiting reactant, and the correct produced energy, due to this reaction is:
[tex]E=632\frac{kJ}{mol\ rxn}*\frac{1mol\ rxn}{1molSn_3N_4}*0.0367mol Sn_3N_4\\\\E=23.2kJ[/tex]
Regards!
A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required 28.18 mL of permanganate solution. The unbalanced chemical equation for the reaction in acidic solution is Determine the concentration of the permanganate solution in molarity. g
The question is incomplete, the complete question is:
A solution of permanganate is standardized by titration with oxalic acid. To react completely with 0.0018 mol of oxalic acid required 28.18 mL of permanganate solution. The unbalanced chemical equation for the reaction in acidic solution is:
[tex]\mathrm{MnO}_{4}^{-}(aq)+\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}(aq)\stackrel{\mathrm{Acidic}}{\longrightarrow}\mathrm{Mn}^{2+}(aq)+\mathrm{CO}_{2}(\mathrm{g})[/tex]
Determine the concentration of the permanganate solution in molarity.
Answer: The molarity of permanganate solution is 0.026 M
Explanation:
The balanced chemical equation follows:
[tex]2MnO_4^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow 2Mn^{2+}+8H_2O(l)+10CO_2(g)[/tex]
Given values:
Moles of oxalic acid = 0.0018 moles
By the stoichiometry of the reaction:
If 5 moles of oxalic acid reacts with 2 moles of permanganate solution
So, 0.0018 moles of oxalic acid will react with = [tex]\frac{2}{5}\times 0.0018mol=0.00072mol[/tex] of permanganate solution
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Moles of permanganate solution = 0.00072 moles
Volume of solution = 28.18 mL
Putting values in equation 1, we get:
[tex]\text{Molarity of permanganate solution}=\frac{0.00072\times 1000}{28.18}\\\\\text{Molarity of permanganate solution}=0.026M[/tex]
Hence, the molarity of permanganate solution is 0.026 M
A small container is filled with liquid water. What can happen if the container of water is an open system that couldn't happen if it were a closed or isolated system?
Evaporation can decrease the amount of water. Dust from the surroundings can enter the water. The water can freeze if the surrounding temperature decreases sufficiently.
only some particles split up into smaller particles
Answer:
Everything around you can be broken down into smaller particles called atoms. The particles of one substance are all the same and different substances are made up of different particles.
Explanation:
a polluted lake is 0.300 μg (micrograms) per liter of water, what is the total mass of mercury in the lake, in kilograms, if the lake has a surface area of 15.0 square miles and an average depth of 27.0 feet?
Answer:
95.9 kg
Explanation:
First we convert 15.0 mi² to m²:
15.0 mi² * ([tex]\frac{1609.34 m}{1mi}[/tex])² = 3.88x10⁷ m²Then we convert 27.0 ft to m:
27.0 ft * [tex]\frac{0.3048m}{1ft}[/tex] = 8.23 mNow we calculate the total volume of the lake:
3.88x10⁷ m² * 8.23 m = 3.20x10⁸ m³Converting 3.20x10⁸ m³ to L:
3.20x10⁸ m³ * [tex]\frac{1000L}{1m^3}[/tex] = 3.20x10¹¹ LNow we calculate the total mass of mercury in the lake, using the given concentration:
0.300 μg / L * 3.20x10¹¹ L = 9.59x10¹⁰ μgFinally we convert μg to kg:
9.59x10¹⁰ μg * [tex]\frac{1kg}{1x10^9ug}[/tex] = 95.9 kgH2S + CuSO4--->
Complete the equation?
The sloth is able to camouflage by moving really slowly and
A. changing colors
B. hanging upside down
D. having fur that is a similar color to tree barks with algae growing on it
Answer:
D. having fur that is a similar color to tree barks with algae growing on it
Explanation:
Choice A doesnt make sense because sloths do not change colors, and hanging upside down would not protect you from prey or blend in. D matches the description of a sloth.
Answer:
Having fur that is a similar color to tree barks with algae growing on it.
Explanation:
Examine the differences between the expanded structure, the condensed structure, and bond-line representation.
Answer:
One structure shows all the bonds whereas the other shows some of the bonds.
Explanation:
Expanded structure shows all of the bonds connecting all of the atoms in the compound while on the hand, condensed structural shows all atoms, but exclude some or all of the vertical and horizontal bonds. condensed structure makes it easier to write the formula in a line as compared to expanded structure. A bond-line representation is a kind of representation of molecular structure of compounds on a line. In this representation, covalent bonds are represented with one line for each level of bond order.
Lemon juice has a pH of 2. What is the hydrogen ion concentration of lemon juice?
Which compound is insoluble in water?
Answer:
The answer is C... I am almost positive.
Balance the equation by ion electron method
Answer:i believe you are to decompose the formula (i think)
We have a 3.7 L container filled with 82 g of CO gas. This container is maintained at a temperature of 298 K
a) How many moles of CO gas are in this container?
b) What is the pressure inside the container?
Answer:
a) 2.9 mol
b) 19 atm
Explanation:
Step 1: Given data
Volume of the container (V): 3.7 LMass of CO gas (m): 82 gTemperature (T): 298 KStep 2: Calculate the number of moles (n) corresponding to 82 g of CO
The molar mass of CO is 28.01 g/mol.
82 g × 1 mol/28.01 g = 2.9 mol
Step 3: Calculate the pressure (P) inside the container
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 2.9 mol × (0.0821 atm.L/mol.K) × 298 K / 3.7 L = 19 atm
How does the Big Bang theory explain why there is a lot of hydrogen and helium in the universe?
Answer:
when the explosion happened the matter fussed into elements as the electrons portions Nd notrons were compresed into the elements beacuase hydrogen has 1 nutron proton and electron surronding its core
which substances would have exhibit a giant covalent structure explain
Answer:
Silicon
Explanation:
Silicon is in group IV with strong Si-Si ( Silicon to Silicon ) bonds. Since it is a molecule, these bonds exert a strong molecular force hence adopting a giant covalent structure.
how many atoms of carbon are in 6CO2 + 6H2O --> C6H12O6 + 6O2
Answer:
6 atoms of carbon are in the reactant side
Explanation:
Are on the reactant side in:
6CO2 + 6H2O → C6H12O6 + 6O2
In the reaction, there are 6 molecules of CO2 that are reacting with 6 molecules of H2O. As you can see, CO2 has only 1 atom of carbon per molecule whereas H2O hasn't.
That means the atoms of carbon are:
6 molecules CO2 * (1atom C / 1molecule CO2) =
6 atoms of carbon are in the reactant sideiodide (KI). Identify the correct products of this
reaction. (Note that NO3? is the nitrate ion, a
polyatomic ion.)
AgNO3 + KI – ?
AgK + INO3
✓
Agl + KNO3
Ag + K + I + NO3
COMPLETE
What type of reaction is this?
Answer:
AgNO3 + KI → Agl + KNO3. Double-replacement reaction
Explanation:
Based on solubility rules, Silver, Ag produce an insoluble salt in presence of halides (Fluorides F-, Chlorides Cl-, Iodides, I-, and bromides Br-). That means the mixture of AgNO3 (Ag⁺ ions) with KI (I- ions) produce AgI as insoluble salt.
The reaction is:
AgNO3 + KI → Agl + KNO3And this is a double-replacement reaction where the cations exchange of anion to produce 2 new compounds.
Answer:
AgI + KNO3
Explanation:
double replacement
A worker gets paid 11.33 $/hour. The worker works on average 39.7 hours/week for 48 weeks per year. How much does the worker make in 1.7 years?
Answer:
36704 $
Explanation:
First we calculate how much the worker gets paid in one week:
11.33 $/hour * 39.7 hour/week = 449.80 $/weekThen we calculate how many weeks does the worker work in 1.7 years:
48 week/year * 1.7 years = 81.6 weeksFinally we calculate how much does the worker make in 1.7 years:
449.80 $/week * 81.6 weeks = 36704 $Calculate the density of CO2 at a pressure of 685.0 torr and 41.0°C .
R=0.0821 (L*atm)/(mol *K)
T=41+273=314 k
M=(12)+(16×2)=44g/mol
d=PM/RT
d=685×44/0.0821×314
d=1169.15 g/L
A mixture of gases at 2.99 atm can You have two gases, and , at the same temperature. Determine the ratio of effusion rates of and .ists of 13.2 moles of hydrogen gas and 19.1 moles of helium gas. Determine the partial pressure of the helium gas.
Answer:
Given total pressure of the gas mixture(hydrogen and helium) is 2.99 atm
Number of moles of hydrogen is ---- 13.2 mol
Number of moles of helium is ---- 19.1 mol
Determine the partial pressure of the helium gas.
Ratio of effusion rates of the two gases.
Explanation:
According to Dalton's law of partial pressures,
partial pressure of a component gas in a mixture is:
partial pressure of a gas = total pressure x mole fraction
mole fraction of helium gas is:
[tex]mole fraction of helium gas = \frac{number of moles of helium gas}{total number of mioles} \\=>mole fraction of He= \frac{19.1mol}{(19.1+13.2)mol} \\=>mole fraction of He = 0.591\\[/tex]
Partial pressure of He gas is:
[tex]Partial pressure of He =mole fraction of He * total pressure\\ =0.591 x 2.99atm\\ =1.77atm[/tex]
Effusion rate of a gas is inversely proportional to its square root of its molecular mass.
[tex]\frac{rate of effusion of H2 gas}{rate of effusion of He gas} =\sqrt{\frac{molar mass of He gas}{molar mass of H2 gas} } \\=> \frac{rate of effusion of H2 gas}{rate of effusion of He gas}=\sqrt{\frac{4g.}{2g} } \\=>\frac{rate of effusion of H2 gas}{rate of effusion of He gas}=1.414:1[/tex]
Hence, rates of effusion of H2:He is 1.414:1.
HELP PLS THIS IS SO HARD AHHHHHHH
What is the balanced form of the chemical equation shown below?
Zn(NO3)2(aq) + Na S(aq) → ZnS(s) + NaNO3(aq)
PLEASE TELL ME THE AWNSERS ITS A DOC FILE SO OPEN IT I WILL GIVE BRAINLIEST PLS HURRY
Guys i need a long inforation about....
"Formation of colloids"
Please and thank you
Answer:
Colloids
There are two basic methods of forming a colloid: reduction of larger particles to colloidal size, and condensation of smaller particles (e.g., molecules) into colloidal particles. Some substances (e.g., gelatin or glue) are easily dispersed (in the proper solvent) to form a colloid; this spontaneous dispersion is called peptization. A metal can be dispersed by evaporating it in an electric arc; if the electrodes are immersed in water, colloidal particles of the metal form as the metal vapor cools. A solid (e.g., paint pigment) can be reduced to colloidal particles in a colloid mill, a mechanical device that uses a shearing force to break apart the larger particles. An emulsion is often prepared by homogenization, usually with the addition of an emulsifying agent. The above methods involve breaking down a larger substance into colloidal particles. Condensation of smaller particles to form a colloid usually involves chemical reactions—typically displacement, hydrolysis, or oxidation and reduction.
Which metal does not form cations of differing charges?
Transition metals
Most transition metals differ from the metals of Groups 1, 2, and 13 in that they are capable of forming more than one cation with different ionic charges. As an example, iron commonly forms two different ions
Calculate the mass percent composition of O in each compound.
a. calcium nitrate
b. Iron(II) sulfate
c. Carbon dioxide
Answer:
A. Mass percent composition of oxygen = 58.5%
B. Mass percentage composition of oxygen = 42.1%
C. Mass percentage composition of oxygen = 72.7 %
Explanation:
Percentage mass composition of an element in a compound is given by the formula below:
Percentage mass composition = mass of element/ molar mass of compound × 100%
Percentage mass of oxygen in the given compounds are then calculated.
a. Calcium nitrate, Ca(NO₃)₂: molar mass of compound is obtained first.
Molar mass of Ca(NO₃)₂ = 40 + 14 × 2 + 16 × 2 × 3 = 164 g
Mass of oxygen = 16 × 6 = 96 g
Mass percent composition of oxygen = 96/164 × 100% = 58.5%
b. Iron (ii) sulfate, FeSO₄: molar mass of compound is obtained first.
Molar mass of FeSO₄ = 56 + 32 + 16 × 4 = 152 g
Mass of oxygen = 16 × 4 = 64 g
Mass percentage composition of oxygen = 64/152 × 100% = 42.1%
c. Carbon dioxide, CO₂: molar mass of compound is obtained first.
Molar mass of CO₂ = 12 + 16 × 2 = 44 g
Mass of oxygen = 16 × 2 = 32 g
Mass percentage composition of oxygen = 32/44 × 100% = 72.7 %