Which of the following is the equivalent expression for (x + 2)(x - 2)? LIKE PLS HELP

Answers

Answer 1
The answer is x^2-2^2
X^2-4

Related Questions

given that £1=1.55 CHF how much cheaper is £

Answers

The £1 as a foreign exchange rate is cheaper than 1 CHF by 35%.

What is a foreign exchange rate?

The foreign exchange rate refers to the unit of conversion of one currency to another.

Data and Calculations:

Exchange rate = £1=1.55 CHF

Ratio of 1.55 CHF to £1 = 1 : 0.65

Cheapness of £1 = 0.35 (1 - 0.65)

Thus, £1 as a foreign exchange rate is cheaper than 1 CHF by 35%.

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In circle M. Diameters JL and HK each measure 16 centimeters.

Answers

The length of the arc in the image given is approximately: A. 3.5 cm

What is the Length of Arc?

Length of arc = ∅/360 × 2πr

The missing parts of the question is shown in the image below, where we are asked to find arc length of JH.

Thus, we would have the following:

∅ = 25°

Radius (r) = 16/2 = 8 cm

Substitute the values into the formula:

Arc length JH = 25/360 × 2π(8)

Arc length JH ≈ 3.5 cm

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If 10^3=1,000, write the logarithmic form that is equal to 3 below

Answers

Answer:

log10(1000)=3

Note: The ten is the base number and should be placed slightly lower and be smaller than shown.

what are the solutions to z^3+8i=0

Answers

Z^3+8i=0
Z^3=-8i
Z^3= raíz cúbica de -8i
Polar form

Rule 1: Multiply by 2 then add 1 starting from 1.
Rule 2: Divide by 2 then add 4 starting from 40.
Sequence 1
Sequence 2
Ordered Pairs

Answers

The sequence 1 will be 3(n – 1) + 1. And the sequence 2 will be 9(n – 1) / 2 + 40.

What are sequence and series?

A sequence is a list of elements that have been ordered sequentially, such that members come either before or after.

Let n = natural number.

The sequence 1 will be multiplied by 2 then add 1 starting from 1. Then we have

⇒ 2(n – 1) + 1(n – 1) + 1

⇒ 3(n – 1) + 1

The sequence 1 will be divided by 2 then add 4 starting from 40. Then we have

⇒ (n – 1 / 2) + 4(n – 1) + 40

⇒ 9(n – 1) / 2 + 40

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parallelogram has 2 pairs of congruent sides and the opposite angles are equal.

Answers

Answer:

True.

Step-by-step explanation:

In order for a quadrilateral to be a parallelogram, the top and bottom sides must be congruent, and the left and right must be congruent.

Opposite angles on either side are equal.

Multiply and reduce to lowest terms
5/13 X 3 3/8

Answers

Answer:

1 31/104

Step-by-step explanation:

First, let's turn them both into improper fractions.

3 3/8 = 27/8

Now we can multiply

It is 5*27 / 13 * 8

This equals: 135 / 104

Simplified even further is:

1 31/104

Please help! Suppose....

Answers

Answer:

24

Step-by-step explanation:

We are given the logarithmic expression:

[tex]\displaystyle{\log_a \left(\dfrac{x^3y}{z^4}\right)}[/tex]

We are also given by the problem that:

[tex]\displaystyle{\log_a x = 3, \ \log_a y = 7, \ \log_a z = -2}[/tex]

From the expression, we will simplify it using two properties:

[tex]\displaystyle{\log_a MN = \log_a M + \log_a N}\\\\\displaystyle{\log_a \dfrac{M}{N} = \log_a M - \log_a N}[/tex]

Therefore, apply the properties to simplify:

[tex]\displaystyle{\log_a x^3y - \log_a z^4}\\\\\displaystyle{\log_a x^3 + \log_a y - \log_a z^4}[/tex]

Next, we will use another property to take an exponent as a coefficient:

[tex]\displaystyle{\log_a x^n = n\log_a x}[/tex]

Hence:

[tex]\displaystyle{3\log_a x + \log_a y - 4\log_a z}[/tex]

Substitute what are given in the problem and the answer will be:

[tex]\displaystyle{3(3)+7-4(-2)}\\\\\displaystyle{9+7+8 = 24}[/tex]

Hence, the answer is 24.

5. Art has three times as much money as Flora. Together they have
$180. How much money does each person have?
Choices for Flora's amount: 45, 60, 75

Answers

The amount flora has is 45.

60 units and 14 Units per case. How many cases and how many units needed

Answers

There are 4.29 cases in the units

How to determine the number of cases?

The given parameters are:

Units = 60

Rate = 14 units per case

The number of cases is then calculated as:

Case = Unit/Rate

This gives

Case = 60/14

Evaluate

Case = 4.29

Hence, there are 4.29 cases in the units

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Lydia has half of her investments in stock paying an 11% dividend and the other half in a stock paying 14% interest. If her total annual interest is $440, how much does she have invested?

Answer

Answers

The amount that Lydia has earned on her investment is $198 on the stock paying the 11% dividend and $252 on the stock paying 14% interest for a total earned of $450 on her $3600 investment.

Calculations and Parameters

Let x represent half of her total investment.

The total annual interest earned is $450.

This is represented by the following equation:

0.11x + 0.14x= 450

Collect the like terms together

0.25x = 450

x= 1800

Therefore, half of her total investment is $1800 so her total investment is $3600.

Check the solution:

0.11∗1800 + 0.14 ∗ 1800 = 450

198 + 252 = 450

Therefore, she earned $198 on the stock paying the 11% dividend, and $252 on the stock paying 14% interest for a total earned of $450 on her $3600 investment.

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Based on the data in the two-way table, the probability of being 25-35 years and having a hemoglobin level above 11 is __ a.29 b.34 c.54
The probability of having a hemoglobin level above 11 is __ a.25 b.3 c.36
Being 25-35 years and having a hemoglobin level above 11 __ dependent on each other. a.are b.are not

Answers

The probability of being 25-35 years and having a haemoglobin level above 11 is 34%.

The probability of having a haemoglobin level above 11 is 36%.

Being 25-35 years and having a hemoglobin level above 11 are not dependent on each other.

What are the probabilities?

Probability determines the odds that a random event would occur. The odds of the event happening lie between 0 and 1.

The probability of being 25-35 years and having a haemoglobin level above 11 = number of people between 25 - 35 that have a level above 11 / total number of people between 25 - 35

44 / 128 = 34%

The probability of having a haemoglobin level above 11  = number of people with a level above 11 / total number of respondents

153 / 429 = 36%

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25 yr old gets a 1 yr life insurance for $10000 at $100. Probability of death at age 25 is 0.0023 What is the company's expected gain

Answers

The expected gain of this company by the policy that they have here is given as $77.

How to solve the expected gain of the company

The stated probability about a person dying is given as 0.0023

This tells us that out of this 10000, the number of people that would die would be 10000*0.0023 = 23 persons

Out of these 23, each of the number that would get the $10000 form the company.

23 * 10000 = $230000

Amount of policy sold at unit price is $100 for 10000

= 100 * 10000

= $1000000

The net earning = 1000000 - 230000

= 770000

The total earning = 770000/10000

= $77

Hence the expected gain of this company is going to be $77.

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Need help with this diagram

Answers

The width of the square garden is 4 feet

How to determine the width of the garden?

The area of the garden is given as:

x^2 + 20x + 75 = 171

Subtract 171 from both sides

x^2 + 20x - 96 = 0

Expand

x^2 + 24x - 4x - 96 = 0

Factorize

x(x + 24) - 4(x + 24) = 0

Factor out x + 24

(x - 4)(x + 24) = 0

Solve for x

x = 4 or x =-24

The width of the garden cannot be negative.

So, we have:

x = 4

Hence, the width of the garden is 4 feet

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A bag of mixed nuts contains cashews, pistachios, and almonds. There are 1,000 total nuts in the bag, and there are 100 less almonds than pistachios. The cashews weigh 3 g, pistachios weigh 4 g, and almonds weigh 5 g. If the bag weighs 3.7 kg, fi d out how many of each type of nut is in the bag.

Answers

Answer:

Below in bold.

Step-by-step explanation:

Let the number of pistachios be x then the number of almonds = x-100.

The number of cashews = 1000 - x - (x - 100) = 1100-2x.

From the info given

3(1100-2x) + 4x + 5(x - 100) = 3700

3300 - 6x + 4x + 5x - 500 = 3700

3x = 3700 - 3300 + 500

3x = 900

x = 300

So there are 300 pistachios, 200 almonds and 500 cashews in the bag.

There are 300 pistachios, 200 almonds, and 500 cashews in the bag of mixed nuts.

To find the number of each type of nut in the bag, we can set up a system of equations based on the given information.

Let's assume there are x pistachios in the bag. According to the problem, there are 100 fewer almonds than pistachios, so the number of almonds will be (x - 100).

Now, the total number of nuts is 1,000:

x (pistachios) + (x - 100) (almonds) + cashews = 1000

The total weight of the nuts in the bag can be calculated as follows:

3g (cashews) * number of cashews + 4g (pistachios) * x + 5g (almonds) * (x - 100) = Total weight in grams.

Since we know that the bag weighs 3.7 kg, we need to convert the total weight to grams and set it equal to 3.7 kg * 1000g/kg = 3700g.

Now we have two equations:

x + (x - 100) + cashews = 1000

3g * cashews + 4g * x + 5g * (x - 100) = 3700

Let's simplify equation 1:

2x - 100 + cashews = 1000

2x + cashews = 1100

cashews = 1100 - 2x

Now, let's substitute the expression for cashews in equation 2:

3g * (1100 - 2x) + 4g * x + 5g * (x - 100) = 3700

Now, distribute the weights:

3300g - 6g * x + 4g * x + 5g * x - 500g = 3700

Combine like terms:

-6g * x + 4g * x + 5g * x = 3700 - 3300 + 500

3g * x = 900

x = 900 / 3

x = 300

Now that we have the value of x (number of pistachios), let's find the number of almonds:

almonds = x - 100

almonds = 300 - 100

almonds = 200

Now, let's find the number of cashews using the total nut count:

cashews = 1000 - (pistachios + almonds)

cashews = 1000 - (300 + 200)

cashews = 1000 - 500

cashews = 500

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Please help I want clear answers for example
AB: X = ___ Y =___

Answers

Answer:

AB: y=2x+2

CB: y=-2x+6

CD: y=1/2x-1.5

DA: y=-3x+2

Step-by-step explanation:

Answer:

AB: [tex]y=2x+2[/tex]

CB: [tex]y=-2x+6[/tex]

CD: [tex]y=\frac{1}{2}x -1.5[/tex]

DA: [tex]y=-3x+2[/tex]

Step-by-step explanation:

So when it's saying y = __ x + __ it's asking for the slope-intercept form. This is given as y=mx+b where m is the slope and b is the y-intercept. m is the slope because as x increases by 1, the y-value will increase by m, which is by definition what the slope is [tex]\frac{rise}{run}[/tex] how much the function "rises" as x "runs".

AB: See how it "rises" by 2 and only "runs by 1", thus the slope is 2/1 or 2. the last part is the y-intercept, which is the value of y when the line crosses the y-axis. If you look at the graph when it "crosses" the y-axis it's y-value is 2. So you have the equation: [tex]y=2x+2[/tex]

CB: See how it "goes down" by 4 and "runs" by 2, thus the slope is -4/2 or -2. The y-intercept isn't shown on the graph but you can calculate that by substituting known values into the slope-intercept form. So we know so far y=-2x+b since the slope was calculated, and we can take any point on the line to calculate b, for this example I'll take the point C which is (3, 0) which is (x, y) and I'll plug that in

Plug values in:

0 = -2(3) + b

0 = -6 + b

6 = b

This gives you the complete equation: [tex]y=-2x+6[/tex]

CD: see how it only "rises" by 1 but "runs" by 2, thus the slope is 1/2. The y-intercept isn't shown on the graph but you can calculate it by substituting a point into the equation For this example I'll use point C (3, 0)

0 = 3(1/2) + b

0 = 1.5 + b

-1.5 = b

This gives you the complete equation: [tex]y=\frac{1}{2}x - 1.5[/tex]

DA: see how it "decreases" by 3 but "runs" by 1, thus the slope is -3/1 or -3. The y-intercept is known and is at (0, 2) so now we plug these values in to get the equation: [tex]y=-3x+2[/tex]

Tony made 14 \text{ L}14 L14, start text, space, L, end text of lemonade for a party. His guests drank 9{,}500 \text{ mL}9,500 mL9, comma, 500, start text, space, m, L, end text of the lemonade.

How many milliliters of lemonade did Tony have left over?

Answers

Unit conversion is a way of converting some common units into another without changing their real value. The lemonade left with Tony is 4500ml.

What is unit conversion?

Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimetre is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.

One litre is equal to 1000 millilitres. Tony made 14 Liter of lemonade, therefore, Tony made 14,000 millilitres of lemonade. His guest drank 9500 millilitres. Therefore, the lemonade left with Tony is,

Lemonade left = 14,000 - 9,500 = 4,500 ml

Hence, the lemonade left with Tony is 4500ml.

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Simplify 8 over the quantity of 2 plus 2i

Answers

Answer:

2-2i

Step-by-step explanation:

So you have the equation:

[tex]\frac{8}{2+2i}[/tex]

and when you have these equations, you want to get rid of the i, and to do that the simplest way is to square it right? If you simply multiply by 2+2i, you're going to get some i in the middle, so to make sure it's eliminated, you use the difference of squares identity: [tex](a+b)(a-b)=a^2-b^2[/tex]. So you multiply by the conjugate, since it's 2+2i, you multiply by 2-2i, that way it evaluates to 2^2-(2i)^2

Multiply both sides by the conjugate of 2+2i

[tex]\frac{8(2-2i)}{(2+2i)(2-2i)}[/tex]

Simplify:

[tex]\frac{16-16i}{2^2-(2i)^2}[/tex]

Distribute square the values below

[tex]\frac{16-16i}{4-4i^2}[/tex]

Rewrite the i^2 as -1, since sqrt(-1) = i

[tex]\frac{16-16i}{4-4(-1)}[/tex]

Cancel out the negatives

[tex]\frac{16-16i}{8}[/tex]

Distribute the division

[tex]2-2i[/tex]

Which of the following equations have complex roots?

Answers

Answer:

D

Step-by-step explanation:

Subtracting 2 from both sides and then dividing both sides by 3 gives that x² = -2/3, which indicates the roots are complex.

What is the value of the underlined digit?


5,682, 450,003

/////^

that is the underlined digit


A. eighty thousand

B. eighty million

C. eighty-two million

D. eighty billion

Answers

The value of the underlined digit (8) in the number given is; Choice B; Eighty million.

What is the value of the underlined digit?

The underlined digit in the task content is 8. On this note, it follows that the since, the number can be pronounced as; Five billion, Six hundred and Eighty-two million, Four hundred and fifty thousand, and three.

It is evident, that the place value occupied by the underlined number is; Eighty million.

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Given a pair of complex numbers, z1 = 5 and z2 = –6i, let z3 = 3i z1 and z4 = z2 – 2. in which quadrant is z3 – z4 located?

Answers

Assuming [tex]z_1=5[/tex] and [tex]z_2=-6i[/tex], as well as [tex]z_3=3i z_1[/tex] and [tex]z_4 = z_2-2[/tex], we have

[tex]z_3 - z_4 = 3iz_1 - (z_2-2) = 3i\times5 - (-6i-2) = 15i + 6i + 2 = 2 + 21i[/tex]

Since both the real and imaginary parts are positive, [tex]z_3-z_4[/tex] belongs to the first quadrant.

Problem
(a) Let [tex]a_1, a_2, a_3,...[/tex] be an arithmetic progression of non-zero numbers with common difference [tex]d[/tex].
(i) Show that [tex]\frac{1}{a_na_{n+1}}=\frac{1}{da_n}-\frac{1}{da_{n+1}}[/tex] for any [tex]n\geq1[/tex].
(ii) Hence show that [tex]\frac{1}{a_1a_2}+\frac{1}{a_2a_3}+\frac{1}{a_3a_4}+...+\frac{1}{a_{99}a_{100}}=\frac{99}{a_1a_{100}}[/tex].
(b) For what value of [tex]k[/tex] does [tex]\frac{1}{3\times7}+\frac{1}{7\times11}+\frac{1}{11\times15}+...+\frac{1}{k(k+4)}+\frac{2}{25}[/tex]?

Answers

(a.i) If [tex]a_1,a_2,a_3,\ldots[/tex] are in arithmetic progression, then there is a constant [tex]d[/tex] such that

[tex]a_{n+1} - a_n = d[/tex]

for all [tex]n\ge1[/tex]. In other words, the difference [tex]d[/tex] between any two consecutive terms in the sequence is always the same.

[tex]a_2-a_1 = a_3-a_2 = a_4-a_3 = \cdots = d[/tex]

Now, we can expand the target expression into partial fractions.

[tex]\dfrac1{a_na_{n+1}} = \dfrac{\alpha}{a_n} + \dfrac{\beta}{a_{n+1}}[/tex]

Combining the fractions on the right and using the recursive equation above, we have

[tex]\dfrac1{a_na_{n+1}} = \dfrac{\alpha (a_n + d) + \beta a_n}{a_n(a_n+d)} = \dfrac{(\alpha+\beta) a_n + \alpha d}{a_n a_{n+d}} \\\\ \implies \begin{cases}\alpha + \beta = 0 \\ \alpha d = 1 \end{cases} \implies \alpha = \dfrac1d, \beta = -\dfrac1d[/tex]

and hence

[tex]\dfrac1{a_n a_{n+1}} = \dfrac1{da_n} - \dfrac1{da_{n+1}}[/tex]

as required.

(a.ii) Using the previous result, the [tex]n[/tex]-th term [tex](n\ge1)[/tex] in the sum on the left is

[tex]\dfrac1{a_n a_{n+1}} = \dfrac1d \left(\dfrac1{a_n} - \dfrac1{a_{n+1}}\right)[/tex]

Expand each term in this way to reveal a telescoping sum:

[tex]\dfrac1{a_1a_2} + \dfrac1{a_2a_3} + \dfrac1{a_3a_4} + \cdots + \dfrac1{a_{99}a_{100}} \\\\ ~~~~~~~~ = \dfrac1d \left(\left(\dfrac1{a_1} - \dfrac1{a_2}\right) + \left(\dfrac1{a_2} - \dfrac1{a_3}\right) + \left(\dfrac1{a_3} - \dfrac1{a_4}\right) + \cdots + \left(\dfrac1{a_{99}} - \dfrac1{a_{100}}\right)\right) \\\\ ~~~~~~~~ = \dfrac1d \left(\dfrac1{a_1} - \dfrac1{a_{100}}\right) = \dfrac{a_{100} - a_1}{d a_1 a_{100}}[/tex]

By substitution, we can show

[tex]a_n = a_{n-1} + d = a_{n-2} + 2d = \cdots = a_1 + (n-1)d \\\\ \implies a_{100} = a_1 + 99d[/tex]

so that the last expression reduces to

[tex]\dfrac{(a_1 + 99d) - a_1}{d a_1 a_{100}} = \dfrac{99d}{d a_1 a_{100}} = \dfrac{99}{a_1 a_{100}}[/tex]

as required. More generally, it's easy to see that

[tex]\dfrac1{a_1a_2} + \dfrac1{a_2a_3} + \dfrac1{a_3a_4} + \cdots + \dfrac1{a_na_{n+1}} = \dfrac{n}{a_1a_{n+1}}[/tex]

(b) I assume you mean the equation

[tex]\dfrac1{3\times7} + \dfrac1{7\times11} + \dfrac1{11\times15} + \cdots + \dfrac1{k(k+4)} = \dfrac2{25}[/tex]

Note that the distinct factors of each denominator on the left form an arithmetic sequence.

[tex]a_1 = 3[/tex]

[tex]a_2 = 3 + 4 = 7[/tex]

[tex]a_3 = 7 + 4 = 11[/tex]

and so on, with [tex]n[/tex]-th term

[tex]a_n = 3 + (n-1)\times4 = 4n - 1[/tex]

Let [tex]a_n=k[/tex]. Using the previous general result, the left side reduces to

[tex]\dfrac1{3\times7} + \dfrac1{7\times11} + \dfrac1{11\times15} + \cdots + \dfrac1{a_na_{n+1}} = \dfrac n{3a_{n+1}} \\\\ \implies \dfrac{\frac{k+1}4}{3(k+4)} = \dfrac2{25}[/tex]

Solve for [tex]k[/tex].

[tex]\dfrac{k+1}{12k+48} = \dfrac2{25} \implies 25(k+1) = 2(12k+48) \\\\ \implies 25k + 25 = 24k + 96 \implies \boxed{k=71}[/tex]

If f(x) = x2 - 1, and
g(x) = x + 2, then
f(g(x)) = [? ]x2+[?]x+[?]

Answers

Step-by-step explanation:

f.g(x) = f(x+2)

         =(x+2)2 -1

         =(x2+2*x*2+4)-1

         =x2+4x+4-1

         =x2+4x+3

Write an equivalent expression for 3(4x+2y)+5​

Answers

Answer:

12x+6y+5

Step-by-step explanation:

expand this: 3(4x+2y)=12x+6y

then add 5

12x+6y+5

Answer:

Hello! The answer is 12x + 6y + 5

Step-by-step explanation:

3(4x + 2y) + 5

Distribute:

3(4x + 2y) + 5

= 12x + 6y + 5

All like terms are combined/non-existent so the equivalent expression is: 12x + 6y + 5

For the function f(x) = 2x² - 3x + 1, find the value of f(-2).

Answers

Answer:

f(-2)= 15

Step-by-step explanation:

f(-2)= 2(-2)² - 3(-2) + 1=15

An insurance policy sells for $600. Based on past data, an average of 1 in 50 policy holders
will file a $5,000 claim, an average of 1 in 100 policyholders will file a $10,000 claim, and an average
of 1 in 200 policyholders will file a $30,000 claim.
(a) Find the expected value (to the company) per policy sold.
(b) If the company sells 10,000 policies, what is the expected profit or loss

Answers

Using a discrete distribution, we have that:

a) The expected value is of $250 per policy sold.

b) The expected profit for 10,000 policies is of $2,500,000.

What is the mean of a discrete distribution?

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Considering that an insurance profit sells for $600, the distribution of the company's earnings is given as follows:

P(X = -4400) = 0.02.P(X = -9400) = 0.01.P(X = -29400) = 0.005.P(X = 600) = 0.965.

Hence the expected value for a policy sold is given by:

E(X) = 600(0.965) - 4400(0.02) -9400(0.01) - 29400(0.005) = 250.

For 10,000 policies, the expected profit is given by:

E = 10000 x 250 = 2,500,000.

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A motor vehicle is____________.

Answers

A motor vechicle is motor cycle

Which is a solution of the system of equations?
O (1,3)
O (2, 2)
O (3, 1)
O (4,2)

Answers

(2 one)

(2,2) is the answer

Answer two questions about Systems A and B:
A
​4x+16y=12
x+2y=−9

B
​4x+16y=12
x+4y=3

1) How can we get System B from System A?
Choose 1 answer:

(Choice A, Checked, Correct)
CORRECT (SELECTED)
Replace one equation with a multiple of the other equation

Answers

For the given systems the answers are:

1) "Replace one equation with a multiple of the other equation".

2) The systems are not equivalent.

How can we get System B from System A?

Here we have the systems of equations:

A:

4x + 16y = 12

x +2y = -9

B:

4x + 16y = 12

x + 4y = 3

Notice that the first equation is the same in both systems, but the second is different.

In A we have:

x + 2y = -9

In B we have:

x + 4y = 3

So we need to add 2y on the left side of A, and 12 on the right side of A to get the equation in B.

Or we can just take the other equation in A, divide it by 4, and replace it.

So we need to replace the second equation in A for other equation, then the correct option is:

"Replace one equation with a multiple of the other equation".

Because we are replacing an equation in A by other to get system B, we conclude that systems are not equivalent.

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Answer:

khan

Step-by-step explanation:

Aisha wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 76 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 8.9 and a standard deviation of 2.3. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Assume the data is from a normally distributed population. Round answers to 3 decimal places where possible.

Answers

Using the t-distribution, the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies is (8.374, 9.426).

What is a t-distribution confidence interval?

The confidence interval is:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which:

[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 76 - 1 = 75 df, is t = 1.9921.

The other parameters are given as follows:

[tex]\overline{x} = 8.9, s = 2.3, n = 76[/tex].

Hence the bounds of the interval are:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 8.9 - 1.9921\frac{2.3}{\sqrt{76}} = 8.374[/tex]

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 8.9 + 1.9921\frac{2.3}{\sqrt{76}} = 9.426[/tex]

More can be learned about the t-distribution at https://brainly.com/question/16162795

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