Which of the following is equivalent to (8 – 5) ÷ 23 ?
A 3/8
B 19/8
C 27/8
D 1/125

Answers

Answer 1

Answer:

none

Step-by-step explanation:

(8-5)=3

8-5÷23

=179/23


Related Questions

A, B, and C are midpoints of ∆XYZ. What is the length of yz

Answers

Answer:

Step-by-step explanation:

Comment

When you join 2 consecutive midpoints with a line between them, the length of that line is 1/2 the length of the side opposite the line you just drew.

In other words 24 is 1/2 the length of yz.

Solution

1/2 yz = AB

AB = 24

1/2 yz = 24                 Multiply both sides by 2

2(1/2 yz) = 2*24

yz = 48

Answer

yz = 48

. The number or expression that remains when an expression divides another expression.​

Answers

Answer:

thanks for the imformation

Sprinter #1 is running at a speed of 96 inches/second. Sprinter #2 is running at a speed of 475
feet/minute. Who will win the race? Give reason for your answer.

Answers

Answer:

Sprinter #1

Step-by-step explanation:

Sprinter #1 is running at 96/12 feet per second: 8 feet per second

Sprinter  #2 is running at 475/60 feet per second: approximately 7.9 feet per second

Sprinter #1 covers more distance per second.

III- Hallar el módulo del vector
a (2,6)

Answers

[tex]\sqrt{2^{2}+6^{2}}=\sqrt{4+36}=\sqrt{40}=\boxed{2\sqrt{10}}[/tex]

the function f(x) is shown below

Answers

Answer: 2

Step-by-step explanation:

A function composed with its inverse outputs the original input.

Find the slope of the line that passes through the pair of points listed below.
(4,5) , (6,2)

Answers

Answer:

-3/2

Step-by-step explanation:

gradient= y2-y1 over x2-x1

2-5 over 6-4

which equals to -3 over 2

Answer:

 -3/2.

Step-by-step explanation:

Slope of a line joining the points (x1, y1) and (x2, y2) is:

(y2 - y1) / (x2 - x1)  so here we have

Slope = (2 - 5)/(6 - 4)

          =  -3/2

What is the variable of f(3) in the function below? f(x) =2^x

Answers

Hello !

We replace x by 3.

[tex]f(3) = {2}^{3} = 8[/tex]

Have a nice day ;)

[tex]\frak{Hi!}[/tex]

[tex]\orange\hspace{300pt}\above2[/tex]

                              We have the expression -:

                             [tex]\boldsymbol{\sf{f(x)=2^x}}[/tex], and we're asked to find

                             [tex]\boldsymbol{\sf{f(3)}}[/tex].

                             To do that we put in the value for x (3)-:

                             [tex]\boldsymbol{\sf{f(3)=2^3}}[/tex].

                             Evaluate-:

                             [tex]\boldsymbol{\sf{f(3)=2\times2\times2=8}}[/tex]

[tex]\orange\hspace{300pt}\above3[/tex]

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression:

Answers

Answer:

c.) [tex]x^{3} -16x^{2} +75x-108[/tex]

Step-by-step explanation:

Check the attachment.

A silo is to be built by attaching a hemisphere roof onto a circular cylinder. The hemisphere part of the silo is constructed by a material costing $100 per square foot, and the sides are constructed with a different material costing $75 per square foot. The volume of the silo must be held to 5000 cubic feet. What radius and height, to two decimal places, will minimize the cost of the construction

Answers

The radius and height, in two decimal places are mathematically given as

r=10.60

What is the radius and height, in two decimal places?

Generally, the equation for the volume is mathematically given as

[tex]V=\pi r^{2} h+\frac{2}{3} \pi r^{3}[/tex]

Therefore

[tex]5000 &=\pi 0^{2} h+\frac{2}{3} \pi r^{3}[/tex]

[tex]V(r, h) &=\pi r^{2} h+\frac{2}{3} \pi r^{3}-5000 \\\nabla V &=\left\langle 2 \pi r h+2 \pi r^{2}, \pi r^{2}\right\rangle \\[/tex]

[tex]\cos t &=100\left(2 \pi r^{2}\right)+75(2 \pi r h) \\\\\cos t &=200 \pi r^{2}+150 \pi r h \\\\\nabla C(r, h) &=\langle 400 \pi r+150 \pi h, 150 \pi r\rangle[/tex]

Using Lagrange method

[tex]$\langle 400 \pi \gamma+150 \pi \gamma h, 150 \pi \gamma\rangle=\lambda\left\langle 2 \pi \gamma h+2 \pi \gamma^{2}, \pi r^{2}\right\rangle$[/tex]

[tex]$400 \pi r+150 \pi r=\left(2 \pi r h+2 \pi r^{2}\right) \lambda$[/tex]

[tex]$400 \pi \gamma+150 \pi h=300 \pi h+300 \pi r \\\\[/tex]

[tex]$400 \pi r-300 \pi r=150 \pi h$[/tex]

[tex]$160 \pi r=150 \pi h \quad \\\\\\[/tex]

with

[tex]h=\frac{2}{3} r $[/tex]

[tex]$\pi r^{2} h+\frac{2}{3} \pi r^{3}=5000$[/tex]

[tex]\pi r}\left(\frac{2}{3} r \right)+\frac{2}{3} \pi^{3}=5000$[/tex]

[tex]$\frac{4 \pi \gamma^{3}}{3}=5000 \quad[/tex]

[tex]r^{3}=\left(\frac{5000 \times 3}{4 \pi}\right)$[/tex]

r=10.60

In conclusion, the radius and height, in two decimal places is

r=10.60

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A carnival tent is set up using a 32-foot pole as the center. The Support wires each have an angle of elevation of 38 degrees from the ground to the top of the pole. Approximately how many feet of wire is needed for one support for the tent?

Answers

Answer:

about 52 feet

Step-by-step explanation:

The figure is omitted--you may draw it to confirm my answer.

sin (38°) = 32/x

x sin (38°) = 32

x = 32 / sin (38°) = about 52 feet

A llhe intersects the points
(4, -2) and (3, 3).
m = -5
Write an equation in point-slope form
using the point (4, -2).
y- [?] =[?]
(x-[?])

Answers

Answer:

y + 2 = -5(x - 4)

Step-by-step explanation:

Point-slope form is the following: [tex]y-y_{1}=m(x-x_{1})[/tex], where m is the slope of the line and [tex](x_{1}, y_{1} )[/tex] is a point on the line. We are already given all of the information we need, so all we have to do is write it out. We are told that the slope (m) is -5, and the point the question wants us to use is (4, -2), though either of the points given would work. If we plug in the quantities, we get that y - (-2) = -5(x - 4), or y + 2 = -5(x - 4)

67. Extensions
Find the equation of the line that passes through the following points: (a, 0) and (c, d)

Answers

Answer:

Equation of a line passing through two point (a, 0) and (c, d) is given by [tex]$y=\frac{d}{c-a} x-\frac{a d}{c-a}$[/tex].

Step-by-step explanation:

In the question, it is given that a line passes through (a, 0) and (c, d).

It is asked to write the equation of line.

To do so, first find the values which are given in the question and put it in the formula of the equation of line passing through two points.

Step 1 of 2

Passing point of the line is (a, 0).

Hence, [tex]$x_{1}=a$[/tex] and

[tex]$$y_{1}=0 \text {. }$$[/tex]

Also, Passing point of the line is (c, d).

Hence, [tex]$x_{2}=c$[/tex] and

[tex]$$y_{2}=d \text {. }$$[/tex]

Step 2 of 2

Substitute the above values in the formula of equation of line passing through two point given by [tex]$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)$[/tex].

[tex]y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)$$\\ $y-0=\frac{d-0}{c-a}(x-a)$\begin{aligned}&y=\frac{d}{c-a}(x-a) \\&y=\frac{d}{c-a} x-\frac{d a}{c-a}\end{aligned}$$[/tex]

Hence, [tex]$y=\frac{d}{c-a} x-\frac{d a}{c-a}$[/tex].

what happens when the multiplicity of a real root is even

a. the graph crosses the y-axis
b. the graph crosses the x-axis
c. the graph is tangent to the y-axis
d. the graph is tangent to the x-axis

Answers

When the multiplicity of a real root is even, the graph of the function neither crosses nor is tangent to the x-axis. The correct answer is (c) the graph is tangent to the y-axis.

When a real root has an even multiplicity, it means that the corresponding factor appears multiple times in the factored form of the polynomial. In terms of the graph of the function, this means that the graph touches the x-axis at that root but does not cross it.

Since the graph touches the x-axis without crossing it, it remains on one side of the axis. This behavior indicates that the graph is tangent to the x-axis at the root with even multiplicity.

However, the graph can still intersect or cross the y-axis at a different point depending on other factors or terms in the polynomial. Therefore, option (a) "the graph crosses the y-axis" may or may not be true depending on the overall behavior of the function. The statement in option (b) "the graph crosses the x-axis" is incorrect for an even multiplicity root. Option (d) "the graph is tangent to the x-axis" is also incorrect for an even multiplicity root. Hence, option (c) "the graph is tangent to the y-axis" is the correct choice.

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NEED HELP RN LIKE ASAPP PLEASE!!

Answers

Answer:

Step-by-step explanation:

To answer this, you also need to click the transversal pic above.

An equilateral triangle with side lengths of 8.7 centimeters is shown. An apothem has a length of a and the radius has a length of 5 centimeters. The apothem and radius form a triangle with a base length of b.
Which statements about finding the area of the equilateral triangle are true? Select three options.

The apothem can be found using the Pythagorean theorem.
The apothem can be found using the tangent ratio.
The perimeter of the equilateral triangle is 15 cm.
The length of the apothem is approximately 2.5 cm.
The area of the equilateral triangle is approximately 65 cm2.

Answers

Answer:

a,b,d

Step-by-step explanation:

Allen is horrible at managing his money. For example, he
recently invested $100,000-part of it in a company that
makes "fish-flavored" chicken and the rest in a company
that makes spray-on vitamins. Somehow he managed to earn
a 3% profit on the fish-flavored chicken investment and 1%
profit on the spray-on vitamin deal. If Allen made a profit
of $2,600 from both investments, how much did he invest in
the fish-flavored chicken company?

Answers

Answer:

$80,000

Step-by-step explanation:

Define the variables:

Let x =  "fish-flavored" chicken company investment (in dollars)

Let y = spray-on vitamins company investment (in dollars)

If Allen invested a total of $100,000:

⇒ x + y = 100000

Given:

3% profit on "fish-flavored" chicken investment 1% profit on pray-on vitamins investmentTotal profit = $2,600

⇒ 0.03x + 0.01y = 2600

Rewrite the first equation to make y the subject:

⇒ y = 100000 - x

Substitute into the second equation and solve for x:

⇒ 0.03x + 0.01(100000 - x) = 2600

⇒ 0.03x + 1000 - 0.01x = 2600

⇒ 0.02x + 1000 = 2600

⇒ 0.02x = 1600

⇒ x = 80000

Therefore, Allen invested $80,000 in the "fish-flavored" chicken company.

Based only on the information given in the diagram, which congruence
theorems or postulates could be given as reasons why ABC= ADEF?
Check all that apply.
AA
A. SAS
B. LL
C. LA
O. D. HA
E. HL
F. AAS

Answers

Answer:

Step-by-step explanation:

AAS and SAS

The congruence theorems or postulates could be given as reasons why ABC= ADEF are SAS, AAS the correct options are A and F.

What are congruent triangles?

Suppose it is given that two triangles ΔABC ≅ ΔDEF

Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.

The order in which the congruency is written matters.

For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.

Thus, we get:

[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]

(|AB| denotes length of line segment AB, and so on for others).

We are given that;

The diagram

Now,

Based on the information given in the diagram, we can use the following congruence theorems or postulates as reasons why ABC= ADEF:

SAS (Side-Angle-Side): If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent.

We can use SAS to show that ABC and ADEF are congruent, since AB = AD, BC = DE, and the included angle BAC = the included angle EDF.

AAS (Angle-Angle-Side): If two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the triangles are congruent.

We can use AAS to show that ABC and ADEF are congruent, since the included angles BAC and EDF are congruent, angle ABC is congruent to angle ADE (since they are vertical angles), and side BC is congruent to side EF.

Therefore, by congruent triangles the answer will be SAS, AAS.

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The following diagram shows a semicircle ABC with centre O and a right-angled triangle ACD.

Given the radius is 3.5 cm, calculate the perimeter, in cm, of the whole diagram.
A 36 B 60 C 67 D 72​

Answers

Answer:

Since the radius is 3.5, to figure out the length on the diameter/side of the triangle, we have to multiply it by 2:

3.5 x 2 = 7

Now we can use the Pythagorean theorem to figure out the length of the other side of the triangle.

a^2 + b^2 = c^2

7^2 + b^2 = 25^2

49 + b^2 = 625

b^2 = 576

b = 24cm

Now that we have all the lengths of the triangle, using the radius, we can calculate the arc of the semi circle using the following formula:

(π + 2)r

(π + 2)3.5

3.5π + 7 = 18cm

Now we can add all of the lengths excluding the diameter of the circle since we want to calculate the perimeter:

25 + 24 + 18 = 67cm

Therefore, the correct answer would be C.

Find the surface area of the regular pyramid.

Answers

The surface area of the triangular pyramid shown is 94.6 in²

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

The surface area of the regular pyramid is given as:

Surface area = 3(0.5 * 4.3 * 13) + (0.5 * 4.3 * 5) = 94.6 in²

The surface area of the triangular pyramid shown is 94.6 in²

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PLS HELP
re writing expressions

Answers

The equivalent expression of [tex]\frac{2^4}{\sqrt[3]{xy}}[/tex] is [tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

How to rewrite the expression?

The expression is given as:

[tex]\frac{2^4}{\sqrt[3]{xy}}[/tex]

Multiply 4 by 1

[tex]\frac{2^{4 * 1}}{\sqrt[3]{xy}}[/tex]

Express 1 as 3/3

[tex]\frac{2^{4 * 3/3}}{\sqrt[3]{xy}}[/tex]

Evaluate the product

[tex]\frac{2^{12 * 1/3}}{\sqrt[3]{xy}}[/tex]

Apply the following law of indices

[tex]a^\frac 1n = \sqrt[n]{a}[/tex]

So, we have:

[tex]\frac{\sqrt[3]{2}^{12}}{\sqrt[3]{xy}}[/tex]

The numerator and the denominator have the same root

So, we have:

[tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

Hence, the equivalent expression of [tex]\frac{2^4}{\sqrt[3]{xy}}[/tex] is [tex]\frac{\sqrt[3]{\frac{2^{12}}{xy}}}[/tex]

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Can someone pls help me out on these geometry questions? Just fill in the blanks, ASAP pls

Answers

Question 5

1) Given

2) Definition of congruent segments

3) Reflexive property of equality

4) Addition property of equality

5) Substitution

6) Commutative property of addition

7) Segment addition postulate

8) Substitution

9) Segments with equal measure are congruent

Question 6

1) Given

3) Segment addition postulate

4) Substitution

5) Subtraction property of equality

7) SSS

Work out the rule for the nth term then work out the 100 term
th

a) 3, 5, 7, 9, 11, 13....

b) 12, 20, 28, 36, 44....

c) 19, 29, 39, 49, 59....

d) 7, 10, 13, 16, 19....

e) 14, 20, 26, 32, 38....

f) 55, 60, 65, 70, 75...

g) 8, 17, 26, 35, 44....

Answers

1234567891011121314151617181920

Triangles P and Q are similar.
Find the lengths of the sides:
Triangle P—> CA=9cm AB=4cm BC=?
Triangle Q—> XY=16cm YZ=48cm ZX=?


Answers

Answer:

if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2

Step-by-step explanation:

join my stream and tell me how to label the triangle

(ChildOfHermes)

Diego inicia un viaje por carretera de 12 horas con la batería de su teléfono al 75%. Dado su uso normal, ¿su teléfono durará todo el viaje?

Answers

Based on Diego's normal usage of his phone, if the battery is at 75%, the phone will not last the whole trip.

How long will the phone battery last?

First find out how long each percentage of battery life lasts:

= 15 / 100

= 0.15 hours

If Diego is going on a 12 hour trip with 75%, the length of time it would last is:

= 0.15 x 75

= 11.25 hours

This is less than the 12 hours required so the phone will not last the whole trip.

Rest of question:

At 100%, the battery can go for 15 hours.

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VERBAL
2. Explain how to find the output variable in a word problem that uses a linear function.

Answers

Answer:

The dependent variables in most cases is output variable. That is a value that depends on some other input value and changes based on that input value.

Step-by-step explanation:

In the question, it is given that a problem uses an output variable.It is required to explain how to find the output variable in a word problem that uses a linear function.In order to find the output variable in a world problem, for the dependent variable. That is a value that depends on some other input value and changes based on that input value.It cannot change independently. In these types of functions, this value is mostly marked as y or f(x).

Express in exponential form.
log(10)0.001 = -3

Answers

Answer:

this gvfyftvyccg c

Step-by-step explanation:

Maureen says that if a system of linear equations has three equations, then there could be exactly two solutions to the system. Is
Maureen correct? Justify your reasoning.

Answers

Answer:

Yes, Maureen is correct. If a system of linear equations has three equations, then there could be exactly two solutions to the system. This is because, in general, a system of linear equations with three variables will have three equations. However, if two of the equations are the same, then there will only be two equations. In this case, there will be two solutions to the system.

Step-by-step explanation:

New information obtained through research or experimentation that enables an updating or revision of the state-of-nature probabilities is known as _____. Group of answer choices joint probability sample information conditional probability expected utility

Answers

New information obtained through research or experimentation that enables an updating or revision of the state-of-nature probabilities is known as SAMPLE INFORMATION.

Hence, 2nd option is the best choice.

A statistical concept called joint probability determines the chance that two events will occur simultaneously and at the same time.

A sample is a collection of people, things, or things used in the study that is taken for analysis from a wider population. To enable us to extrapolate the study sample's findings to the entire population, the sample must be representative of the population. Sample information is the collection of the information of the sample.

The possibility of an event or outcome happening contingent on the occurrence of a prior event or outcome is known as conditional probability. The probability of the prior event is multiplied by the current likelihood of the subsequent, or conditional, occurrence to determine the conditional probability.

The expected utility of a course of action is a weighted average of the utilities of each of its potential outcomes, where the utility of a potential result indicates how much it is preferred to the alternatives.

In the question, we are asked what will be the new information obtained through research or experimentation that enables an updating or revision of the state-of-nature probabilities called.

As we are to name the information, it will be called sample information, from the above-discussed points.

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Which exponential function is represented by the table

Answers

Answer:

for x = 0 ; we have f(x) = 0,5

We can eliminate the first and the last proposal because

f(x) = 0,2(0,5ˣ) ⇒ f(0) = 0,2(0,5⁰) = 0,2 × 1 = 0,2 ≠ 0,5

f(x) = 0,2(0,2ˣ) ⇒ f(0) = 0,2(0,2⁰) = 0,2 × 1 = 0,2 ≠ 0,5

Try for x = 1, we have f(x) = 0,1

f(x) = 0,5(5ˣ) ⇒ f(1) = 0,5 × 5 = 2,5 ≠ 0,1

f(x) = 0,2(0,5ˣ) ⇒ f(1) = 0,2(0,5) = 0,1 ⇒ ok

So the answer is f(x) = 0,2(0,5ˣ)

CAN SOMEONE HELP ME PLEASE:)<3

Answers

Answer: D. Cannot be determined

Step-by-step explanation: There are 3 postulates we can use for determining similar triangles.

There is Side Side Side (SSS) Postulate, which requires you have 2 sides of each triangle that are the same proportion as the other triangle. For example, in a triangle ABC, if 2 sides are 5 and 7, and in a triangle DEF, if 2 sides are 10 and 14, then the proportions 5/10 ( 1/2) and 7/14 (1/2) are equal. Thus these are similar triangles and the scale is 1/2.

There is Angle Angle (AA) postulate. If 2 angles are the same to another 2 angles in another triangle, then the two triangles are automatically similar.

The last is Side Angle Side (SAS), which requires you to have an angle that is congruent to another angle in a different triangle, and the angle is in between 2 sides that are proportionally equal to another triangle that also has the same angle in 2 sides. For example, if triangles ABC have angles A, B and C, and angle A is the same equal degrees to another angle in a triangle D, and both A and D are in between 2 sides (i.e DE and AB) that are proportionate (e.g DE and AB are proportionate.) The triangles are then similar.

None of these postulates can be applied to our given problem. Let's see why.

For Angle-Angle, we don't have 2 congruent angles. We have 2 right angles, but that's only 1 angle.

For Side Side Side, we don't have 2 sides given on each triangle, let alone proportionate ones.

For Side Angle Side, we don't even have 2 sides for each triangle given, so this cannot be used either.

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