A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure. The mass of the treasure chest is 75.6 kg.
If the tension in rope A is 7.42x10^2 N and the tension rope B carries is 7.52x10^2 N, what is the tension in rope C?

The model of the Air as in ideal fluid estimating the speed of air stream flowing through he leak is given as; V  = 347m/s. See the calculation below.

A model is a mathematical equation that is used to represent a real life problem.

P₁ + (1/2) pv₁² + pgh₁ = p₂ + (1/2) pv₂² + pgh₂

Hence,

1 + 0 + 0 = 0.287 + (1/2) (1.2) v²

Therefore,

V  = 347m/s

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The final position of Gilligan in kilometers and degrees south of east relative to the island is  9.07 km, 61.4° south of east.

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

The term also denotes the mathematical or geometrical representation of such a quantity.

According to the question,

Suppose, the direction east as i, direction west as -i, direction north as j and direction south as j.

Therefore,

1. : 2.5 km 45° north of west

[tex]= 2.5 cos45 (-i) + 2.5 cos45 (j)\\ = -1.77(i) + 1.77(j)[/tex]

2. : 4.7 km 60° south of east

[tex]= 4.7 cos60 (i) + 4.7 sin60 (-j) \\= 2.35(i) - 4.07(j)[/tex]

3. : 5.1 km straight east

[tex]=5.1(i)[/tex]

4 : 7.2 km 55° south of west

[tex]= 7.2 cos55 (-i) + 7.2 sin55 (-j)\\ = -4.13(i) - 5.9(j)[/tex]

5: 2.8 km 5° north of east

[tex]= 2.8 cos5 (i) + 2.8 sin5 (j)\\= 2.79(i) + 0.24(j)[/tex]

The sum of all the above yields,

[tex]R = 4.34(i) + 7.96(-j)[/tex]

The magnitude of the resultant is:

[tex]|R| =\sqrt{4.34^{2} + (-7.96)^{2} }= 9.07[/tex]

The angle that the resultant makes is  as follows.

θ= [tex]tan^-^1(\frac{7.96}{4.34} )\\[/tex]

θ = 61.4°

Hence,

Final position relative to the island is 9.07 km, 61.4° south of east.

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The relative pressure at this state is determined as 0.455.

The pressure of the ideal gas given rise to the relative pressure is calculated as follows;

R.P = P2/P1

P2 = P1(R.P)

P2 = 200 kPa x (3.482)

P2 = 696.4 kPa

R.P = (P3)/(P2)

R.P = (320)/(696.4)

R.P = 0.455

Thus, the relative pressure at this state is determined as 0.455.

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The center of the mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3) is 37.62(cm)

λ Fe =8g/cm,λ Al =2.7g/cm

There is a metal rod 1 meter long, with the first 50cm being iron and the other 50cm aluminum. the problem is solved in a one-dimensional case meaning it's a thin rod.

Next, we would solve by definition of the center of mass

We would also note that the masses of iron and aluminum are just the product of their length and linear density.

[tex]X_C_M[/tex]= [tex]\frac{8(g/cm). \frac{2500(cm^2)}{2} + 2.7 (g/cm). \frac{7500(cm^2)}{2} }{8(g/cm).50(cm) + 2.7(g/cm). 50 (cm)}[/tex]

= 37.62(cm)

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If the current in a wire increases from 5A to 10A, the magnetic field generated will also be doubled.

Hi ! I will help you to discuss about "magnetic field around a conducting wire". A conducting wire that carried electric current can generate amount of magnetic fields. In a standard winding condition, the increase number of electric current will be proportional to the increase number of the generated magnetic field. In other condition, the increase in distance (between center of field with a point) will be inversly proportional to the increase in the generated magnetic field. So, the magnetic field that generated around a current-carrying wire can be expressed in the following equation.

[tex] \boxed{\sf{\bold{B = \frac{\mu_0 \cdot I}{2\pi \cdot d}}}}[/tex]

With the following condition:

We can assume that:

We know that :

What was asked ?

Step by step :

[tex] \sf{B_1 : B_2} [/tex]

[tex] \sf{\frac{\cancel{\mu_0} \cdot I_1}{\cancel{2\pi} \cdot d_1} : \frac{\cancel{\mu_0} \cdot I_2}{\cancel{2\pi} \cdot d_2}} [/tex]

[tex] \sf{\frac{I_1}{d_1} : \frac{I_2}{d_2}} [/tex]

[tex] \sf{\frac{I_1}{\cancel d} : \frac{I_2}{\cancel d}} [/tex]

[tex] \sf{I_1 : I_2} [/tex]

[tex] \boxed{\sf{\bold{1 : 2}}} [/tex]

From the above comparison, we can see that the ratio of the magnetic field at a point will be the same as the ratio of the current flowing through the conducting wire is 1 : 2. So, The magnetic field generated will also be doubled.

Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation. This force can move the body in the circular direction.

So we can conclude that Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

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The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

The centrifugal force is the force that force that tends to throw an object out of the circular path. It is the opposite of the centripetal force which tends to keep the object in the circular path.

Hence. the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

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Answer:

The atomic number is the number of protons in an element

Inertia is directly proportional to mass.

What is Walter Lewin famous for?

Walter Hendrik Gustav Lewin (born January 29, 1936) is a Dutch astrophysicist and former professor of physics at the Massachusetts Institute of Technology.

Lewin earned his doctorate in nuclear physics in 1965 at the Delft University of Technology and was a member of MIT's physics faculty for 43 years beginning in 1966 until his retirement in 2009.

According to Walter Levin,

The concept of moment of inertia is demonstrated by rolling a series of cylinders down an inclined plane.

Inertia is the resistance of any physical object to a change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed when no forces act upon them.

By rolling a series of cylinders down on an inclined plane , he demonstrated that a cylinder have a smooth friction.

He compares the rolling cylinder by using hollow cylinder and a heavy cylinder , and finalize the result that a hollow cylinder moves slowly but the heavy cylinder move faster.

Hence , By doing this experiment he explained about the inertia that Inertia depend on the mass of the object. As the heavy the object it will take more time to travel or move.

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The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.

The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.

According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.

The molar mass of ammonium sulphate is as follows:

[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)

= 36.02 + 32.07 + 64

= 132.09

Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.

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Answer:

.714 m

Explanation:

The VERTICAL component is all we are interested in for this Q

Vertical velocity = 6.32  m/s   sin 36.3° = 3.742 m/s

Vertical displacement  =   vo t  - 1/2 at^2

                                     = -1/2 at^2 + vo t  

        max occurs at - b/2a = -3.742/ (2(-1/2(9.81)) = .3814 sec

                then vot-1/2 at^2 =

                          3.742 (.3814) - 1/2 ( 9.81)(.3814^2) = .714 m

Answer:

.714

Explanation:

The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

Q=45 degrees

Generally, the equation for Force is  mathematically given as

[tex]\frac{mg}{sin \theta}[/tex]

Therefore

[tex]F=\frac{17.1*10^{-3}*9.8}{sin45}[/tex]

F=0.237N

Considering horizontal axis or plane

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

[tex]tan\theta= 30/30\\\\tan\theta=1\\\\\theta=45[/tex]

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Answer:

did you ever the answer?

Explanation:

The time for the javelin in the air will be 3.977 second

The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.

Given data;

Θ is the angle of throw = 43.2°

u is the thrown velocity =  28.5 m/s

t is the  time for the javelin in the air

The time period is found as;

[tex]\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.[/tex]

Hence the time for the javelin in the air will be 3.977 second

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The value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive

In order words, ΔEk in the above question is positive

Kinetic energy can be defined as the energy a body possess when the body is in motion or due its motion

In conclusion, the value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive

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The average speed of the round trip is 1.25 m/s.

The average speed of the round trip journey is obtained by taking the average of the forward and return speed of the journey.

Average speed = 1.0 + 1.5/2 = 1.25 m/s

In conclusion, the average speed of the round trip is the average of the initial and final speeds.

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1. The magnitude of the gravitational force between the Earth and an m is  54.1 N.

2. The magnitude of the gravitational force between the Moon and an m is  1.91 x 10⁻⁴ N.

3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.

The gravitational force between Earth and mass, m is calculated as follows;

F(Earth) = Gm₁m₂/R²

F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²

F(Earth) = 54.1 N

F(moon) = Gm₁m₂/R²

F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²

F(moon) = 1.91 x 10⁻⁴ N

F(sun) = Gm₁m₂/R²

F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²

F(sun) = 0.0324 N

= 0.0324/1.91 x 10⁻⁴

= 169.6

Thus, the magnitude of the gravitational force between the Earth and an m is  54.1 N.

The magnitude of the gravitational force between the Moon and an m is  1.91 x 10⁻⁴ N.

The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.

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a)The distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.

b)Both the routes have the same distance.

Displacement is defined as the shortest distance between the two points.

Distance is the horizontal length covered by the body, while displacement is the shortest distance between the two points. Displacement is a vector quantity.

Given data;

Distance,d = 7.5 km

Angle,θ=10° E of N

From the triangle ABD and ABC it is obtained that;

AC = AB sinθ

AC=7.5 sin(10°)

AC=1.302 km

CB = 7.5 cos 10°

CB = 7.386 km

AC is the distance in the east direction = 1.302 km

CB is the distance in the north direction = 7.386 km

Both the routes have the same distance. Hence you still arrive at the same point if the East and North legs are reversed in order.

Hence the distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.

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Due a decrease in the velocity of the cart, the change in kinetic energy is negative

Kinetic energy is the energy of a body due to its motion.

Since the cart is slowed down, its velocity decreases and the change in kinetic energy is negative.

In conclusion, the change in kinetic energy of a body is affected by the mass and velocity of the body.

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Decrease.

Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.

Note that your body itself does not change.

Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.

In short, a trip to the equator is not a viable long-term weight-loss program.

Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.

We experience as "something pulling you down" is actually the total of all the forces and not just gravity.

The four dominant large-scale, long-term forces are:

The earth's gravity

The sun's gravity

The moon's gravity

The earth's centrifugal force

Hence, the weight of a body at the equator will be less than at the Poles.

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The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

The given parameters are:

The pressure altitude is calculated as:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Subtract 700 from both sides

750 = (29.92 - Altimeter reading) * 1000

Divide through by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

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The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.

The mechanical energy of the bat is in the form of potential energy.

At a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *

Potential energy = 39.7 N

In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.

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The current made by the circuit produce this effect by generating a magnetic field that attracts the car magnetically to the crane lift and is denoted as option C.

This is a machine which is used to lift and lower objects which are most times heavy.

It employs the use of magnetic force as it is generated when the button is switched on in this scenario.

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Answer:

animals and wildlife (c)

Explanation:

Ecotourism is essentially tourism of nature--which highly incorporates animals/wildlife

> it usually has a goal of conservation of nature

poaching is illegally hunting wild animals, which is focused on an aspect of nature protection (which is why it is ecotourism)

the only option listed here that is about ecotourism is animals and wildlife (c), meaning that this is the correct fill-in

hope this helps! have a lovely day :)

The work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.

The work done by the man is the product of his applied force and the displacement of the bag.

The man gets tired because his internal energy has be used to do work on the bag.

Thus, the work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.

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The magnitude of the vector C is 96.32m

Ax = AcosθA

= 40 cOS 20

= 37.59

Ay = AsinθA

-40sin20

= -13.68

Bx = B cos θ B

= 75Cos50

= 48.21

By = BsinθB

= 75sin50

= 57.45

Cx = AX + Bx

= 37.59 + 48.21

= 85.8

Cy = Ay + By

= -13.65 + 57.45

= 43.77

The magnitude is solved by

|c| = [tex]\sqrt{Cx^{2}+Cy^{2} }[/tex]

= √85.8² + 43.77²

= 96.32m

The magnitude of the vector c is 96.32m

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The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.

Clockwise moment = Anticlockwise moment

Ft * 1.58 m = F * 0.67 m

where

m * a * 1.58 = m * 9.81 * 0.67

a = 4.15 m/s²

The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

In conclusion, the acceleration of the truck is found by taking moments about the tipping point.

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APA not implemented early on for research on humans and these ethics of research in place because there was no stable and widely accepted system of research.

This is referred to a writing style used by American Psychological Association in reasearches etc.

There was no stable method of writing which was the reason why it wasn't used early for researches.

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Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
[tex]KE = \frac{1}{2}mv^2 \\\\PE = mgh[/tex]

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

[tex]E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)[/tex]

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

[tex]E_f = \frac{1}{2}mv_f^2[/tex]

And:
[tex]W_A = E_i - E_f[/tex]

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
[tex]W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2[/tex]

Solving for the work done by air resistance:
[tex]W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)[/tex]

[tex]W_A = \boxed{42.552 J}[/tex]

Answer:

2

Explanation:

8-0/4

Final velocity-initial velocity/time taken

After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

[tex]RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2[/tex]

where;

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

[tex]RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g[/tex]

Thus, after plugging all the data into the equation, the result is measured in terms of g.

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