Which of the following equations has a graph that passes through (3, 3) and has a slope of -2?
A. x + 2y = 9
o B. X- 2y = -3
O
C. 2x + y = 9
o
D. -2x + y = -3

Answer:

V = 36 cm³

Step-by-step explanation:

V = 1/2(3)(4)(6) = 36 cm³

Answer:

c. 60

Step-by-step explanation:

Given

[tex]n = 61[/tex] --- sample

[tex]\bar x = 23[/tex]

Required

Determine the degrees of freedom (df)

This is calculated as:

[tex]df = n - 1[/tex]

[tex]df = 61 - 1[/tex]

[tex]df = 60[/tex]

Answer:

1/2

Step-by-step explanation:

Hope it helps :)

it's recorded that out of 1000 people, 762 wear the corrective lenses.

just divide 762 from 1000 and multiply that result by 100.

762/ 1000 = .762

.762 x 100 = ? %

which is 76.2 %

so, we predict that 76.2% of Americans would wear corrective lenses.

a) the value of the expression is 29.

b) the value of the expression is -3.

d) the value of the expression is 270.

a) To calculate the expression 4x2 + 3 + 6 - 2 + 7 X 2, follow the order of operations (PEMDAS/BODMAS):

4x2 = 8
7 X 2 = 14

Now we can substitute these values into the expression:

8 + 3 + 6 - 2 + 14

Performing the addition and subtraction from left to right:

= 11 + 6 - 2 + 14
= 17 - 2 + 14
= 15 + 14
= 29

Therefore, the value of the expression is 29.

b) To calculate the expression 4+2-6-1 - 7+ 12, again use the order of operations:

4 + 2 = 6
-7 + 12 = 5

Now we can substitute these values into the expression:

6 - 6 - 1 - 7 + 5

Performing the subtraction and addition from left to right:

= 0 - 1 - 7 + 5
= -1 - 7 + 5
= -8 + 5
= -3

Therefore, the value of the expression is -3.

c) To calculate the expression (-48 - 12) = (-3 + 11), perform the subtraction and addition:

-48 - 12 = -60
-3 + 11 = 8

Now we can substitute these values into the equation:

-60 = 8

The equation is not true since -60 is not equal to 8. Therefore, there is no solution to this equation.

d) To calculate the expression (-5)(6)(-9), perform the multiplication:

(-5)(6)(-9) = -30(-9)
= 270

Therefore, the value of the expression is 270.

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The values of b = 0 or a = -3 -  such that zw is real, letting z = 3+ bi and w = a + bi where a, b E R.

To determine the value of b in terms of a such that zw is real, we first need to find zw. Using the distributive property, we have:

zw = (3 + bi)(a + bi)

zw = 3a + 3bi + abi - b^2

To make zw real, the imaginary part must be equal to zero. Therefore, we have:

3b + ab = 0

b(3 + a) = 0

Since b cannot be equal to zero (otherwise z and w would be real), we have:

a = -3

Therefore, b = 0 or a = -3 - this is the value of a such that zw is real.

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Answer:

13 in

Step-by-step explanation:

Let s be the length of a side of the triangle

then one rectangular face of the triangular prism

would be s x 14.

There are 3 rectangular faces in the triangular prism so

Lateral Surface Area  = 3 x (s x 14)

182 = 42s

182/42 = s

There are 3 sides to the triangle so

3 x (182/42) = 13

Answer:

27

Step-by-step explanation:

3 x ((5) + 4)

3 x 9 =27

A.) Similar?  YES  

Why or why not?  It is similar because as your can see in the picture above, it shows a large triangle and a small triangle. On the smaller triangle, the corner "G" has a degree of 67. On the larger triangle, the corner "P" has the same degree as the smaller one, therefore all the other corners have the same degree making the missing degree for "R" 34 degrees, and the missing "C" 79 degrees.  

If so, *similarity statement and scale factor: SF:  1.5  

*I didn't know what they meant by similarity statement

B.) Similar?  NO  

Why or why not?  The triangles are two totally different shapes, with totally different degree angles, making it totally different  

If so, *similarity statement and scale factor: SF:  2  

*I didn't know what they meant by similarity statement

C.) Similar?  NO  

Why or why not?  The triangles are two totally different shapes, with totally different degree angles, making it totally different  

If so, *similarity statement and scale factor: SF:  1.2  

*I didn't know what they meant by similarity statement

D.) Similar?  YES  

Why or why not?  They are the same shape; just with one enlarged and one decreased in size. They both have the same angle degree and everything else similar but the size of the shape.  

If so, *similarity statement and scale factor: SF:  2  

*I didn't know what they meant by similarity statement

**To find the scale factor you would have to divide the big number, to the smaller number... Like for figure D, the base of the BIG triangle is 56, and the small triangle is 28. 56 ÷ 28 = 2 Making 2 the SF (Scale Factor)

Answer:

x =5, y = 4

Step-by-step explanation:

3x + 4y = 31..... (1)

2x - 4y = -6..... (2)

Adding equations (1) & (2)

[tex]3x + \cancel{4y} = 31 \\2x - \cancel{4y} = -6\\ - - - - - - - \\ 5x = 25 \\ x = \frac{25}{5} \\ \bold{ \purple{x = 5}} \\ plug \: x = 5 \: in \: eq \: (1) \\ 3(5) + 4y = 31 \\ 15 + 4y = 31 \\ 4y = 31 - 15 \\ 4y = 16 \\ y = \frac{16}{4} \\ \bold{ \red{y = 4}}[/tex]

Answer:

D. the average difference in height between each player and the mean height

Answer:

S

=

{

(

−

2

,

5

)

}

Step-by-step explanation:

Gauss-Seidel Method:
Iteration 1:
Starting with x(0) = [0, 0], we can substitute the initial values into the system of equations:
3(0) + 1(0) + 3x₂(1) + 6x₂(0) + 2x₂(0) = 0 -> 3x₂ = 0
3(0) + 3x₂(1) + 7x₂(0) = 4 -> 3x₂ = 4

Solving these equations, we find x(1) = [0, 4/3].

Iteration 2:
Using the updated values from the previous iteration, we have:
3x₁(1) + x₂(0) + 3x₂(1) + 6x₂(4/3) + 2x₂(4/3) = 0 -> 3x₁ + 16x₂ = -16/3
3x₁(1) + 3x₂(1) + 7x₂(4/3) = 4 -> 3x₁ + 19x₂ = 16/3

Solving these equations simultaneously, we obtain x(2) ≈ [-16/15, 8/15].

Iteration 3:
Using the updated values from the previous iteration:
3x₁(-16/15) + x₂(8/15) + 3x₂(-16/15) + 6x₂(8/15) + 2x₂(8/15) = 0 -> 3x₁ + 32x₂ = -16/5
3x₁(-16/15) + 3x₂(8/15) + 7x₂(8/15) = 4 -> 3x₁ + 19x₂ = 16/3

Solving these equations, we find x(3) ≈ [-16/35, 16/35].

After three iterations of the Gauss-Seidel method using the given initial value x(0) = [0, 0], we obtain an approximate solution of x(3) ≈ [-16/35, 16/35].

Jacobi's Method:

Iteration 1:
Starting with x(0) = [0, 0], we can update each component separately:
x₁(1) = (0 - (1(0) + 3x₂(0)) / 3 -> x₁ = 0
x₂(1) = (4 - (3x₁(0) + 7x₂(0))) / 3 -> x₂ = 4/3

Hence, x(1) = [0, 4/3].

Iteration 2:
Using the updated values from the previous iteration:
x₁(2) = (0 - (1(0) + 3x₂(4/3)) / 3 -> x₁ ≈ -16/15
x₂(2) = (4 - (3x₁(0) + 7x₂(4/3))) / 3 -> x₂ ≈ 8/15

Therefore, x(2) ≈ [-16/15, 8/15].

Iteration 3:
Using the updated values from the previous iteration:
x₁(3) = (0 - (1(-16/15) + 3x₂(8/15)) / 3 -> x₁ ≈ -16/35
x

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Answer:

6

10

Step-by-step explanation:

30 5 6

70 7 10

Answer: 3x-x+2=4

Step-by-step explanation:

12/X=3/6 CROSS MULTIPLY.

3X=12*6

3X=72 X=72/3 X= 24 FEET TALL.

The given differential equation by undetermined coefficients is y'' - 10y' + 25y = 30x + 3. Its solution is as follows: Let us assume y = yh + yp where yh is the homogeneous solution and yp is the particular solution. To find the homogeneous solution, solve the following differential equation: y'' - 10y' + 25y = 0characteristic equation: r2 - 10r + 25 = 0(r - 5)2 = 0Thus, yh = c1e5x + c2xe5x

Now, let us find the particular solution by assuming the following particular solution: yp = Ax + B Substituting this into the differential equation: y'' - 10y' + 25y = 30x + 3 yields:-10A + 25B = 3, and0x + A = 30Solving for A and B: A = 30 and B = 15Thus, yp = 30x + 15Therefore, the general solution is:y = yh + yp = c1e5x + c2xe5x + 30x + 15, where c1 and c2 are arbitrary constants.

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Answer:

0.85

Step-by-step explanation:

Answer:

312

Step-by-step explanation:

Answer:

I answered it on the second time you asked this question check it out

Answer: No image? Incomplete question? FREE POINTS!

Step-by-step explanation:

BRAINLIEST PLEASE!

Answer:

A≈176.71

Step-by-step explanation:

A=πr^2

We find the radius by slicing the diameter in half. The radius is half of the diameter.

A = A=π 7.5^2

A=π 56.25

A≈176.71

we are 99% confident that the true value of µ lies within the interval (12.5831, 13.9169).

We have a random sample from a normal distribution with mean µ and a true variance of 0.81.

From this sample of 16 values, the sample mean was 13.25.

We want to calculate the 99% confidence interval for µ.

We can use the t-distribution to calculate the confidence interval since the sample size is less than 30.

We need to find the t-value that corresponds to a 99% confidence interval and 15 degrees of freedom (n-1).

We can use a t-distribution table or calculator to find that the t-value is 2.9477.

Using this value, we can calculate the confidence interval as follows: Lower bound = sample mean - (t-value * standard error)Upper bound = sample mean + (t-value * standard error) The standard error is the standard deviation divided by the square root of the sample size.

So, in this case: Standard error = √(0.81/16) = 0.2025 Lower bound = 13.25 - (2.9477 * 0.2025) = 12.5831Upper bound = 13.25 + (2.9477 * 0.2025) = 13.9169Therefore, the 99% confidence interval for µ is (12.5831, 13.9169).

This means that if we repeated the process of taking a sample of 16 values many times and calculating a confidence interval each time, we would expect that 99% of those intervals would contain the true value of µ.

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Given: Sample size, n = 16, Sample mean, x = 13.25, Population variance, σ² = 0.81, Confidence level = 99%. The 99% confidence interval for the population mean, µ, is (12.676, 13.824). It means that if we repeat the process of drawing samples of size 16 from the same population infinite times and calculate the confidence intervals, then 99% of those confidence intervals will contain the true population mean.

Since the sample size is greater than 30 and we have a known population variance, we can use the z-distribution for finding the confidence interval for the population mean.

We can use the following formula to find the confidence interval at a given confidence level.

x - z(α/2) * σ/√n < µ < x + z(α/2) * σ/√n, Where z(α/2) is the z-value at α/2 level of significance.

z(α/2) can be found from the standard normal distribution table.

At 99% confidence level,

α = 1 - 0.99

= 0.01.

α/2 = 0.01/2

= 0.005.

At α/2 = 0.005 level of significance,

z(α/2) = 2.576

σ = √0.81

= 0.9

Substituting the values in the formula,

x - z(α/2) * σ/√n < µ < x + z(α/2) * σ/√n

13.25 - 2.576 * 0.9/√16 < µ < 13.25 + 2.576 * 0.9/√16

13.25 - 0.574 < µ < 13.25 + 0.57412.676 < µ < 13.824

Interpretation of Interval: The 99% confidence interval for the population mean, µ, is (12.676, 13.824).

It means that if we repeat the process of drawing samples of size 16 from the same population infinite times and calculate the confidence intervals, then 99% of those confidence intervals will contain the true population mean.

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Answer:

19/21

Step-by-step explanation:

1×7+4×3/21

19/21

a) Var[M9(X)] = 25/9.

b) P[X > 7] = exp(-7/5).

c) P[Z < 2/5] = 0.3446.

Given information: X1, . . . , Xn is an iid sequence of exponential random variables, each with expected value 5.

(a) We know that the sample mean based on nine trials is M9(X). Now, to calculate the variance of the sample mean based on nine trials, Var[M9(X)], we can use the formula for the variance of a sample mean, which is:

Var[M9(X)] = Var[X]/9  .

Since X is an exponential random variable with expected value 5, its variance is 5^2 = 25. Thus,Var[M9(X)] = 25/9.

(b) To find P[X * 1 > 7], we can use the probability density function of an exponential distribution, which is given by:

f(x) = 1/5 exp(-x/5), x > 0  .

Now, using this probability density function, we have:

P[X > 7] = ∫7∞f(x) dx= ∫7∞ 1/5 exp(-x/5) dx.

Using integration by substitution, with u = x/5 and du = (1/5)dx, we have:

P[X > 7] = ∫7/5∞ exp(-u) du= exp(-7/5).

(c) Since we know that X1, . . . , Xn is an iid sequence of exponential random variables, each with expected value 5 and variance 25, we can apply the central limit theorem. According to the central limit theorem, the sample mean M9(X) is approximately normally distributed with mean 5 and variance 25/9. Thus, we have:

P[M9(X) > 7] = P[Z > (7-5)/(5/3)] where Z is a standard normal random variable. This simplifies to:

P[M9(X) > 7] = P[Z > 2/5] = 1 - P[Z < 2/5]

Using the standard normal distribution table or calculator, we get:

P[Z < 2/5] = 0.6554P[M9(X) > 7] = 1 - P[Z < 2/5] = 1 - 0.6554 = 0.3446.

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Answer:

The answer is x is greater than or equal to -2

Step-by-step explanation:

I just did the math by hand

Answer:  x ≤ -5

Step-by-step explanation:

3x - 11 ≥ 7x + 9

3x ≥ 7x + 20

-4x ≥ 20  when dividing negative numbers, change the sign to the opposite.

x ≤ -5

Two people are trying to decide whether a die is fair. The correct test for analyzing the fairness of the die with the given data is the chi-square [tex]X^2[/tex] test, not the z-test.

The z-test is used for analyzing data when we have known population parameters, such as the mean and standard deviation. However, in this case, we are dealing with categorical data (the frequencies of each face of the die), and we want to determine if the observed frequencies significantly differ from the expected frequencies.

To perform the chi-square test, we first need to calculate the expected frequency for each face of the die. The expected frequency is calculated by multiplying the total number of rolls (100) by the probability of each face (1/6, assuming a fair die). Each face of the die is expected to occur approximately 16.67 times (100/6 = 16.67).

Next, we calculate the degrees of freedom (df) for the chi-square test. For a fair die with 6 faces, the df is (number of categories - 1), which is 5 in this case.

Then, we calculate the chi-square statistic[tex](X^2)[/tex] by summing the squared differences between the observed and expected frequencies, divided by the expected frequencies. The [tex]X^2[/tex] value is used to assess the goodness-of-fit between the observed and expected frequencies.

Finally, we determine the p-value associated with the calculated [tex]X^2[/tex]value using the chi-square distribution and the degrees of freedom. The p-value indicates the likelihood of observing the data if the die is fair.

To provide the specific values for the expected frequency, degrees of freedom, [tex]X^2[/tex], and p-value, the actual calculations based on the given data are required.

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