Which graph represents the equation x2 = 8y?

Equations are written by equating two expressionsThe value of x - 2y is 8/3

Equations are written by equating two expressions. Given the following equation

3x - 6y = 8

Divide through by 3 to have:

3x/3 - 6y/3 = 8/3

x - 2y = 8/3

Hence the value of x - 2y is 8/3

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The key features of the graph include the fact the graphs are periodic.

It should be noted that a graph is a diagram that represents ban interrelations between variables.

The tan graph is simply the visual representation of the tangent function for a range of angles.

In this case, the graphs have been attached and it can be seen that the tan graph repeats every 180° and is not a continuous curve.

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Answer: it is a ratio of vertical alignment w.r.t horizontal alignment

Step-by-step explanation:

The main difference is that graph of tan(x) is the ratio of sin(x)/cos(x) that is it is a ratio of vertical alignment w.r.t horizontal alignment whereas graph of x^3 is not trigonometric but algebraic in nature as ( x×x×x).

The value of the correlation is -0.0721 and it is a weak negative correlation

The points are given as:

(12, 28), (15, 50), (18, 14), (21, 28), (24, 36)

Enter the above points in a graphing calculator.

From the graphing calculator, we have the following summary:

X Values

Y Values

X and Y Combined

R Calculation

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

This gives

r = -18 / √((90)(692.8)) = -0.0721

So, the correlation coefficient is -0.0721

The above is a negative correlation because it is less than 0 and it is a weak correlation because it is closer to 0 than -1

Hence, the correlation is a weak negative correlation

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Answer:

[tex]25x^2-10x+4[/tex]

Step-by-step explanation:

You can use the quadratic formula to determine if a quadratic equation has real or imaginary solutions. The quadratic formula is: [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]. What really matters in this case is the discriminant, which is the stuff under the radical which is: [tex]b^2-4ac[/tex]. This is because the solutions are only imaginary, if the discriminant is negative, because then you would be taking the square root of a negative number. So let's look through each example:

[tex]25x^2+20x-4[/tex]; a=25, b=20, c-4: [tex]20^2-4(25)(-4) = 800[/tex]. By examining this one example, it's important to note, if you have one negative number as a or c, then it cancels out the negative sign in the -4, and it becomes positive. So let's look at examples where a or c doesn't equal a negative number OR both a and c equal negative, that way they cancel out and over -4ac is still negative.

[tex]25x^2-10x+4[/tex]; a=25, b=-10, c=4. In this case both a and c are positive so -4ac will remain negative. This gives you: [tex](-10)^2-4(25)(4) = 100-400 = -300[/tex]. So this has a negative discriminant meaning it will have no real solution but rather imaginary solutions

By means of recurrence formulas and a given initial value, we find the following three results: f(5) = 19, f(125) = 469, f(3125) = 11719.

Sequences are sets of values defined by at least one condition. In this case, we have three conditions to generate the required values:

f(n) = f(n/5) + 3 · n

f(1) = 4

[tex]n \in \mathbb{N}[/tex]

Now we proceed to find the elements by recurrence:

f(5) = f(1) + 3 · 5

f(5) = 4 + 15

f(5) = 19

f(25) = f(5) + 3 · 25

f(25) = 19 + 75

f(25) = 94

f(125) = f(25) + 3 · 125

f(125) = 94 + 375

f(125) = 469

f(625) = f(125) + 3 · 625

f(625) = 469 + 3 · 625

f(625) = 469 + 1875

f(625) = 2344

f(3125) = f(625) + 3 · 3125

f(3125) = 2344 + 9375

f(3125) = 11719

By means of recurrence formulas and a given initial value, we find the following three results: f(5) = 19, f(125) = 469, f(3125) = 11719.

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Answer: [tex]4i\sqrt{5}[/tex]

Step-by-step explanation:

[tex]\sqrt{-80}\\\\=\sqrt{-1} \sqrt{80}\\\\=\sqrt{-1} \sqrt{16} \sqrt{5}\\\\=4i\sqrt{5}[/tex]

None of the provided options is equivalent to √-80.

We have,

To simplify the expression √-80, we need to determine the square root of -80.

However, since -80 is a negative number, its square root is not a real number.

The square root of a negative number is usually expressed using the imaginary unit "i," where i = √(-1).

In this case, we can rewrite the expression as:

√(-1 * 80) = √(-1) * √(80) = i * √(80).

Therefore,

None of the provided options is equivalent to √-80.

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Answer:26

Step-by-step explanation:

Answer:

102cm^3

Step-by-step explanation:

The end behavior is that as the value of x increases the value of function increases.

A) We want to completely factor; f(x) = 2x² - x - 10

⇒ f(x) = 2x² - 5x + 4x - 10

⇒ 2x(x + 2) - 5(x + 2)

⇒ (2x - 5)(x + 2)

B) The x-intercept occurs at y = 0. Thus;

(2x - 5)(x + 2) = 0

x  =5/2  and x = -2

C) f(x) = 2x² - x - 10

Thus, the end behavior is that as the value of x increases the value of function increases.

D) The graph steps has been attached

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Answer:

[tex]volume=558.9[/tex]

Step-by-step explanation:

find the volume of the cone and the hemisphere and add them together

cone:

[tex]Vcone=\pi r^{2} \frac{h}{3} \\\\V=\pi (5.3)^2(\frac{8.4}{3} )\\V=\pi (28.09)(2.8)\\V=247.09\pi \\V=247.1[/tex]

hemisphere:

[tex]Vhemisphere=\frac{2\pi r^3}{3} \\V=\frac{2\pi (5.3)^3}{3} \\V=\frac{2\pi (148.877)}{3} \\V=\frac{297.754\pi }{3} \\V=\frac{935.421}{3}\\ V=311.8[/tex]

add the volumes together:

[tex]Vol=247.1+311.8\\Vol=558.9[/tex]

Answer:

D

Step-by-step explanation:

Answer:

D. 1/125

Step-by-step explanation:

[tex]f(3)=(\frac{1}{5} )^{3} =\frac{1^{3} }{5^{3} } =\frac{1}{125}[/tex]

Hope this helps

Based on the data given, the length of line segment AC is 2.29

Based on the given data:

The triangle ABC is an isosceles triangle.

The line segment AC is the hypotenuse of the the triangle ACD.

The length of AD = 3/2

[tex]AC = \sqrt{(\sqrt{3)^{2}} + (\frac{3}{2})^{2}}= 2.29[/tex]

In conclusion, the length of  AC is 2.29

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Step-by-step explanation:

it is 8+1 people (8 students and 1 teacher).

a.

how many seating arrangements are possible ?

start with any of the 9 seats. there are 9 possibilities who will sit in that chair.

the next seat has then only 8 possibilities left. the next one 7. the next b one 6. and so on.

so, all possibilities are

9×8×7×6×...×1 = 9! = 362,880

b.

if the teacher is fixed to a specific seat, then this position is constant in all seating arrangements.

that means for the variable part we have only 8 people remaining.

and that gives us now only

8! = 40,320

possibilities

c.

how many combinations are there for the triplets, when they sit together, to arrange their internal sitting sequence ?

3! = 6

and we need to block these 6 combinations for each of the freely selectable seats as starting seat for such a block of 3.

to visualize this, let's give each seat an identifier.

we have the seats s1, s2, s3, ... s8, s9.

for all the combinations of these 9 seats, we need to eliminate the 6 combinations, where the triplets sit on s1, s2, s3.

and then the 6 combinations, where they sit at s2, s3, s4.

and then at s3, s4, s5. then at s4, s5, s6. ... s8, s9, s1. and s9, s1, s2.

it is not clear if b. still applies here (and the teacher has a fixed seat), or if we are back to the general a. scenario.

if we have again all 9 people picking their seats freely, and we only block the triplets from sitting together, then we need to block these 6 combinations for each of the 9 seats (as visualized above) giving us

9! / (9×3!) = 362,880 / 54 = 6,720 remaining possibilities.

if we have again the teacher blocking one fixed seat, then we need to block the 6 triplets combinations theoretically for each of the 8 remaining seats as above.

but : the teacher is now a separator disabling some of these blocks of 3.

e.g. let's say the teacher's seat is s9. then the teacher automatically separates the triplets in otherwise "illegal" blocks of 3.

s7, s8, s1 is now a valid seat combination for the triplets (because there is the fixed s9 in between).

the same for s8, s1, s2.

so, we need to eliminate the 6 combinations not for all 8 starting seats, but only for 6.

and that gives us

8! / (6×3!) = 40,320 / 36 = 1,120 remaining possibilities.

The first four terms in the sequence are 4, 9, 16 and 25.

Given that, the nth term of the sequence is 1 (n + 1)².

We need to find the first four terms in the sequence.

In mathematics, a sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

To find the first four terms of the sequence, replace n=1, 2, 3 and 4.

Now, when n=1

1(1+1)²=1×4=4

When n=2

1(1+2)²=1×9=9

When n=3

1(1+3)²=1×16=16

When n=4

1(1+4)²=1×25=25

Therefore, the first four terms in the sequence are 4, 9, 16 and 25.

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The table that represents a linear function is y=3,7,11,15

For a table to represent a linear function, the table must have a constant rate of change i.e. a common difference

From the list of options, we have:

y=3,7,11,15

The difference between each y value is 4

i.e. 7 - 3 = 11 - 7 = 15 - 11 = 4

Hence, the table that represents a linear function is y=3,7,11,15

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Answer:

67

Step-by-step explanation:

7 + 2 =9

9 + 4 = 13

13 + 16 = 29

29 + 38 = 67

Answer + Step-by-step explanation:

[tex]f(x) = 5|x-6|+2 = \begin{cases}5\left( x-6\right) +2&if\ x\geq 6\\ 5\left( 6-x\right) +2 &if\ x\leq 6\end{cases}[/tex]

[tex]\Longrightarrow f(x) = \begin{cases}5x-30+2&if\ x\geq 6\\ 30-5x +2 &if\ x\leq 6\end{cases}[/tex]

[tex]\Longrightarrow f(x) = \begin{cases}5x-28&if\ x\geq 6\\ -5x +32 &if\ x\leq 6\end{cases}[/tex]

case 1: x ≥ 6 → f(x) = 5x - 28

5(6) - 28 = 30 - 28 = 2

Then

the point A(6 ,2) lie on the graph (line) of f

5(7) - 28 = 35 - 28 = 7

Then

the point B(7 ,7) lie on the graph (line) of f

Graphing :

When x ≥ 6 ,the graph of f is the ray [AB) (just connect the points A and B)

case 2: x ≤ 6 → f(x) = -5x + 32

-5(6) +32 = -30 + 32 = 2

Then

the point A(6 ,2) lie on the graph (line) of f

-5(5) +32 = -25 + 32 = 7

Then

the point C(5 ,7) lie on the graph (line) of f

Graphing :

When x ≤ 6 ,the graph of f is the ray [AC) (just connect the points A and C)

Answer:

[tex] \frac{2}{15} {cm}^{2} [/tex]

Step-by-step explanation:

Area of Rectangle = Length x Breadth

=

[tex] \frac{1}{5} \times \frac{2}{3} \\ = \frac{2}{15} {cm}^{2} [/tex]

Answer:

Negative

Step-by-step explanation:

When you move the decimal place to the right, the exponent in scientific notation is negative. In other words, when you are converting a number smaller than 1 into scientific notation, the exponent will be negative. In this case, because you are moving the decimal place to the right 3 places, the new number would be 4.430 x 10⁻³ cm.

When you move the decimal place to the left, the exponent in scientific notation is positive.

Angles are complementary

Answer:

A and C are complementarty

sinC=cos90-C

Step-by-step explanation:

Just took the exam on a pex

good luck homedawg

Answer:

Step-by-step explanation:

So in this example we'll be using the difference of squares which essentially states that: [tex](a-b)(a+b)=a^2-b^2[/tex] or another way to think of it would be: [tex]a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})[/tex]. So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

[tex]x^8-16 = (x^4-4)(x^4+4)[/tex]

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

[tex]x^4-4 = (x^2-2)(x^2+2)[/tex]

So completely factored form is: [tex](x^2-2)(x^2+4)(x^4+4)[/tex]

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because [tex]x^2+4 = x^2-(-4)[/tex]. and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: [tex]x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i)[/tex] just something that might be useful in some cases.

We can factor this into [tex](x^{4}+4)(x^{4} -4)[/tex].

This is because we use  difference of two squares where [tex]x^{2} -y^{2} = (x+y)(x-y)[/tex]

So we rewrite x^8-16 to x^8-4^2.

This can then be written to the equation I put at the start.

p.s. The reason its [tex]x^{4}[/tex] is because [tex]x^{4} * x^{4} = x^{8}[/tex]
(P.S.S I just found that the other helper did it fully so I stopped here, read his, its correct)

Answer:

a^11

Step-by-step explanation:

1) Simplify the numerator. Use the laws: (x^a)^y = x^ay, x^a × x^b = x^a+b.

= a¹⁵ × a^-6 / a^-2

= a⁹ / a^-2

2) Divide them. Use the law: x^a / x^b = x^a - b.

= a^9 - (-2) / 1

= a^9 + 2 / 1

= a^11

Step-by-step explanation:

so, if I understand this correctly, the original function (shown in the graph) is

f(x) = sqrt(x)

the following transformations were done going from f(x) to h(x) :

x -> x + 4 as variable term moved the whole curve 4 units to the left. because now a specific functional value is calculated for a smaller x (by 4 units) than for the original f(x). e. g. let's call g(x) = sqrt(x + 4). then g(-4) = f(0). as mentioned, everything moved over to the left by 4 units.

sqrt(x) -> 3×sqrt(x) increased the range of the function (the generated y values) by the factor 3. was the functional result for a x value = 1, then it is now 3 for the same x value.

sqrt(x) -> sqrt(x) - 1 moved the whole curve down by 1 unit.

in summary, the whole original curve was moved 4 units to the left, then stretched upwards by the factor 3, and then that result was moved down by 1 unit.

so, e.g.

h(-4) = 3×f(0) - 1 = -1 point (-4, -1) corresponds to old (0, 0)

h(-3) = 3×f(1) - 1 = 2 point (-3, 2) corresponds to old (1, 1)

h(0) = 3×f(4) - 1 = 5 point (0, 5) corresponds to old (4, 2)

Answer:

Additive = -10x^2+70x

Multiplicative = 1/10x(x−7)

Step-by-step explanation:

The multiplicative inverse of a number is the reciprocal of that number. Since 10(x^2−7x)⋅ 1/10x(x−7)=1 , then 1/10x(x−7)  is the multiplicative inverse of  10(x^2−7x) .

Since  10(x^2−7x)−10x^2+70x=0 , then −10x^2+70x

is the additive inverse of 10(x^2−7x).

If a, b and c are integers then the correction option in the above case is that both equation 1 and 2 are correct.

Note that:

Because:

Suppose  one say a|b. Then one can see that   an integer  do exist which is n such that  b = an.

Hence:

bc = (an)c = a(nc), so a|(bc) (the reverse is still the case or still applies)

Therefore, If a, b and c are integers then the correction option in the above case is that both equation 1 and 2 are correct.

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It is a. True that educators should teach children how to properly use yardsticks to measure.

A yardstick is a standard long tool used to measure lengths.  It contains three feet, 36 inches, or 0.9144 meters.

Since it is three times the length of a standard ruler of 12 inches, it is recommended for teaching children.

Thus, truly, educators should teach children how to properly use yardsticks to measure.

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Answer:

Id say A but it's tricky.

Israel is in the Eurasian plate. Go ahead with A for the correct one

Answer:

C. Yes, △ABC~△CBD by the SAS similarity theorem

Step-by-step explanation:

i think

Answer:

C- SAS similarity theorem

Explantion:

Two sides and one 90 degree angle

Answer:

march 9

Step-by-step explanation:

10+3-4

=9

I think that's the answer

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

Determine the slope of a line that is parallel to the equation [tex]\bf{3x+6y=18}[/tex].

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

First we should divide the whole equation by 6,

[tex]\bf{\dfrac{3}{6}x+\dfrac{6}{6}y=\dfrac{18}{6}}[/tex] | simplify

[tex]\bf{\dfrac{1}{2}x+y=3}[/tex] | subtract 1/2 x

[tex]\bf{y=-\dfrac{1}{2}x+3[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{Result:}[/tex]

            [tex]\bf{=Slope-\dfrac{1}{2}[/tex]

[tex]\boxed{\bf{aesthetic\not101}}[/tex]

The coordinates represents a possible collision point of the objects according to equations r = 4cos(θ) and r = –1/ 2cos(θ)  cos(∅) are (-2,2π/3).

Given Equations  r = 4cos(θ) and r = –1 2cos(θ).

We have to find the coordinates of collision.

The first object is moving around the screen r = 4cos(θ).

The second object is moving around the screen r = –1 /2cos(θ).

According to question

Coordinate can be found out by equating both the equations.

4cos(θ) =–1 /2cos(θ)

2cos(θ)=-1

cos(θ)=-1/2

θ=[tex]cos^{-1} (1/2)[/tex]

=120°

θ=-2π/3

Therefore the two equations are equal when

θ=2π/3

we have

r=4 cos(2π/3)=-2

and r=-1+2 cos(2π/3)

r=-2

Hence the coordinates that represent the collision point are (-2,2π/3).

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Answer: Option A on EDGE

Just took test

Step-by-step explanation: