Which expression represents the quotient of (x^2-4)/(x-7)/(3x+6)/(x^2-6x+7)

Which Expression Represents The Quotient Of (x^2-4)/(x-7)/(3x+6)/(x^2-6x+7)

Answers

Answer 1

Answer:

last option (x-2)(x+1)/3

Step-by-step explanation:

(x^2-4)/(x-7) ÷ (3x+6)/(x^2-6x+7)

(x^2-4)/(x-7) * (x^2-6x+7)/(3x+6)

(x+2)(x-2)/(x-7) * (x-7)(x+1)/3(x+2)

(x-2)/1 * (x+1)/3

(x-2)(x+1)/3

Answer 2
The Expression Waa Suppose To Be

(x^2-4)/(x-7) / (3x+6)/(x^2-6x-7)
Which Expression Represents The Quotient Of (x^2-4)/(x-7)/(3x+6)/(x^2-6x+7)

Related Questions

From 1984 to 1995 the winning scores for a golf tournament were 275,279,279,276,278,277,280,282,284and 270 Find the mean of the data is

Answers

Answer: The mean of the data is 278.

Step-by-step explanation:

To the the mean of the data, we’ll have to add all the numbers up and divide it by the amount of data.

275+279+279+276+278+277+280+282+284+270=2780

2780/10=278

Answer: 278
Explanation: You simply add up all the numbers, then you divide by how many numbers there are.

2780 is the sum of all those numbers.
Divide by 10 because their are 10 numbers listed.

2780/10 = 278.

Which summation formula represents the series below?
1 + 2 + 6 + 24

Answers

Answer:

First one is the answer of the question u asked

Answer:

Option a: ∑⁵(n−1)! is the correct answer.

n=²

Step-by-step explanation:

Option a: ∑n=25(n−1)

By substituting the values of n and expanding the summation, we have,

(2−1)!+(3−1)!+(4−1)!+(5−1)!

Subtracting, we have,

1!+2!+3!+4!

Expanding the factorial,

1+(2∗1)+(3∗2∗1)+(4∗3∗2∗1)

Simplifying, we get,

1+2+6+24

Thus, the summation ∑⁵ (n−1)! represents the

n=2

series 1+2+6+24

Hence, Option a is the correct answer.

GIVING BRAINLIEST!!!!!

Answers

Answer:

7x+2y=18

The first one

Step-by-step explanation:

The equation to be perpendicular switches they numbers before the x and y. Also plugging into a graphing calculator like desmos will show you
that

ANSWER QUICK ILL GIVE BRAINLIEST
A researcher posts a radio advertisement offering $35 in exchange for participation in a short study. The researcher accepts the first eight people who respond to the advertisement. Which of the following statements is true about the sample? It is a valid sample because the first eight people were selected to participate. It is not a valid sample because it is not a random sample of the population. It is a valid sample because money was offered to participants. It is not a valid sample because it is only a short study.

Answers

Answer: Choice B

It is not a valid sample because it is not a random sample of the population.

Explanation:

The researcher should have randomly selected the participants, either by picking names out of a hat, using a random number table, or some kind of computer software to pick the names. Letting the first 8 people form the sample is very likely not representative of the population at large. We have a lot of bias here. Therefore, this is not a valid sample.

Solve for x.
144°
18 degrees
30 degrees
48 degrees
120 degrees

Answers

Answer:

x = 18 °

Step-by-step explanation:

you have a rotation angle of 360 °, take out the known values ​​(360 ° -90 ° -144 ° = 126), 144 ° is part of a flat angle of 180 °, from 180 ° remove 144 and you have 36 °, they are opposite angles therefore the same. therefore 360 ​​- 144 - 90 - 36 - 36 = 54.

54 is 3x, so x = 18 ° (54 : 3 = 18)

7(7-2 × 3) = ?
What is the answer?
A. 24
B. 7
C. 14
D. 26

Answers

Answer:

b) 7 option B 7 is the answer

Step-by-step explanation:

bidmas rule:

7-2×3

2×3= 6

7-6=1

7×1= 7

therefore the answer is 7.

Answer: The answer is [tex]B. 7[/tex]

Step-by-step explanation:

[tex]7(7-2[/tex] × [tex]3)[/tex]

Simplify the expression.

[tex]7-2= 5[/tex]

[tex]7[/tex] × [tex]3[/tex] = [tex]21[/tex]

[tex]21[/tex] ÷ [tex]3=7[/tex]

Match the attributes to each three-dimensional shape that has the cross-section described.

Only consider cross-sections with whole number dimensions parallel to a side of one of the prisms or the base of the pyramid.

Quadrilateral A:
area of
16 square inches
Quadrilateral B:
perimeter of
24 inches
Quadrilateral C:
perimeter of
16 inches

Answers

The attributes to each three-dimensional shape that has the cross-section is 4,16 and 4.

What is a quadrilateral and parallelogram?

Any closed figure made by 4 line segments joined end to end in series is called a quadrilateral.

That quadrilateral in which opposite sides are parallel is called a parallelogram.

Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

Given;

Quadrilateral A: area of 16 square inches

Quadrilateral B: perimeter of 24 inches

Quadrilateral C: perimeter of 16 inches

Now,

Quadrilateral A:

a^2=16

a=4

Quadrilateral B;

4a=24

a=6

Quadrilateral C:

4a=16

a=4

Therefore, the answers of quadrilaterals will be 4,6 and 4.

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Which is a stretch of an exponential decay function? f(x) = one-fifth (one-fifth) superscript x f(x) = one-fifth(5)x f(x) = 5one-fifth f(x) = 5(5)x

Answers

The exponential function that represents a stretch of a decay function is given as follows:

[tex]f(x) = \frac{5}{4}\left(\frac{4}{5}\right)^x[/tex]

What is an exponential function?

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

a is the initial value.b is the rate of change.

It represents a stretch if a > 1, and a decay function if b < 1. Researching the problem on the internet, the correct option is given as follows:

[tex]f(x) = \frac{5}{4}\left(\frac{4}{5}\right)^x[/tex]

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Answer:

the answer is C :)

Step-by-step explanation:

Luke bought 256 ounces of strawberries. he divided them evenly between 8 different pies.

Answers

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

[tex]256[/tex] [tex]ounces=\frac{256}{16}[/tex] [tex]pounds=16[/tex] [tex]pounds[/tex]

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

[tex]Pounds[/tex] [tex]of[/tex] [tex]strawberries[/tex] [tex]on[/tex] [tex]each[/tex] [tex]pie=\frac{16}{8}[/tex]

[tex]Pounds[/tex] [tex]of[/tex] [tex]strawberries[/tex] [tex]on[/tex] [tex]each[/tex] [tex]pie=2[/tex]

Therefore, Luke put 2 pounds strawberries on each pie.

The point S is on the line AB so that lengths AS:SB are in the ration 3:2. If A = (21,3) and B = (6, 33) then find the co ordinate of S

Answers

From the section formula, it was found that the coordinate for the point S is (12,21).

Section Formula

The coordinates of the point S which divides the line AB into two sections can be found from the application of the Section Formula that is presented below:

[tex]S=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})[/tex], where

[tex]ratio=\frac{m}{n}[/tex]

[tex]x_1[/tex] and [tex]y_1[/tex] are coordinates of A

[tex]x_2[/tex] and [tex]y_2[/tex] are coordinates of  B

Find the point S

The question gives  r=[tex]\frac{3}{2}[/tex], A=(21,3) and B=(6,33). From the ratio, you can find m=3 and n=2.

Next step, applying the internal section formula. Then, you have:

[tex]S=(\frac{3*6+2*21}{3+2}, \frac{3*33+2*3}{3+2})\\ \\ S=(\frac{18+42}{5}, \frac{99+6}{5})\\ \\ S=(\frac{60}{5}, \frac{105}{5})\\ \\ S=(12, 21)[/tex]

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PLEASE HELP WILL GIVE BRAINLEST! What is the amplitude of the function graphed below?

Answers

Answer:

The amplitude is the highest point that the curve reached

Which is in your case = 2

Solve the simultanious equations 2x+3y=13 4x-y=-2

Answers

Answer: x = 1/2, y = 4

Step-by-Step Explanation:

Lets solve it using Substitution Method :-

=> 2x + 3y = 13 (Eq. 1)
=> 4x - y = - 2 (Eq. 2)

From Eq. 2 :-

=> 4x - y = - 2
= - y = - 2 - 4x
=> y = 4x + 2 (Eq. 3)

Substitute value of ‘y’ in Eq. 1 :-

=> 2x + 3y = 13
= 2x + 3(4x + 2) = 13
= 2x + 12x + 6 = 13
= 14x = 13 - 6 = 7
=> x = 7/14 = 1/2

Substitute value of ‘x’ in Eq. 3 :-

=> y = 4x + 2
= y = 4(1/2) + 2
= y = 4/2 + 2
=> y = 2 + 2 = 4

Therefore; x = 1/2, y = 4

Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) dx x 25x2 1

Answers

The integral of [tex]\int {x(25x^2 + 1)} \, dx[/tex] is [tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

How to evaluate the integral?

The integral expression is given as:

[tex]\int {x(25x^2 + 1)} \, dx[/tex]

Start by expanding the bracket

[tex]\int {25x^3 + x} \, dx[/tex]

Next, we integrate each term in the expression

[tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

Hence, the integral of [tex]\int {x(25x^2 + 1)} \, dx[/tex] is [tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

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Which THREE statements would produce the truth value F when pis true and q is false?

Answers

The THREE statements that would produce the truth value F when p is true and q is false are (a) p → q (b) ¬ p ∧ ¬ q (d) q ∨ ¬ p

How to determine the statements with a false truth value?

To do this, we simply analyze each option

The given parameters are:

p = true

q = false

(a) p → q

This means that:

If p then q

So, we have:

If true then false

The above statement would return false.

(b) ¬ p ∧ ¬ q

This means that:

If not p and not q

So, we have:

If not true and not false

i.e.

If false and true

The above statement would return false.

(c) p → ¬ q

This means that:

If p then not q

So, we have:

If true then not false

i.e.

If true then true

The above statement would return true.

(d) q ∨ ¬ p

This means that:

If q and not p

So, we have:

If false and not true

i.e.

If false and false

The above statement would return false.

Hence, the THREE statements that would produce the truth value F when p is true and q is false are (a) p → q (b) ¬ p ∧ ¬ q (d) q ∨ ¬ p

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PLEASE HELP ME I WILL MAKE YOU BRAINLIST!!!!

Answers

Answer:

I worked it out and got C as my answer

approximately, how much air would be needed to fill a soccer ball with a radius of 15 centimeters ?

Answers

Answer:

about 2827cm^3

Step-by-step explanation:

you are looking for the area  

4*pi*r^2

4*pi*15^15

pi*4*225

pi*900

2827.43

it would be 2827.43 i did this on platoe

11z-6=16, then z=

First answer get to be brainliest! ​

Answers

                - - -- - - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Given question:-}}}}[/tex]

         11z-6=16, what is z?

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]

We need to make sure that all variables are on the left-hand side and the numbers are on the right-hand side.

Since we have a number on the left-hand side, we need to move it to the right-hand side with the opposite operation:-

11z=16+6

[tex]\it{11z=22}[/tex]

Divide by 11 on both sides:-

[tex]\it{z=2}[/tex]

We can check our solution by replacing z with 2 and seeing whether or not we end up with a true statement:-

[tex]\it{11(2)-6=16}[/tex]

[tex]\it{22-6=16}[/tex]

[tex]\it{16=16}[/tex]

So we conclude that our solution, z=2, is correct.

Good luck with your studies.

          - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

z=2

Step-by-step explanation:

11(2)-6=16

22-6=16

What is the volume of a cone with a height of 10.5 inches and a radius of 8 inches? cone v = 1 3 bh 1. rewrite the formula for the base area: v = 1 3 πr2h 2. substitute the values into the formula: v = 1 3 π(82)(10.5) 3.evaluate the power: v = 1 3 π(64)(10.5) 4.simplify using multiplication: v = 1 3 π(672) the cone has a volume of pi inches cubed.

Answers

The volume of the cone that has a radius of 8 in. and a height of 10.5 in. is: 703.7 in.³

What is the Volume of a Cone?

Volume = 1/3πr²h

Given the parameters:

Height (h) = 10.5 in.Radius (r) = 8 in.

Volume of the cone = 1/3πr²h = 1/3π(8²)(10.5)

Volume of the cone = 1/3π(64)(10.5)

Volume of the cone = 703.7 in.³

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Answer:

224Pi inches cubed

Step-by-step explanation:

A builder is developing a neighborhood of one-bedroom and two-bedroom houses. the builder wants to build 12 houses and can use as many as 88 total
windows. the one-bedroom houses need 6 windows and the two-bedroom houses need 9 windows.
part a
write and solve a system of equations to represent the situation. let 2 represent the number of one-bedroom houses. let y represent the number of two-
bedroom houses. round your answers to the nearest hundredth, if necessary.

Answers

Builder can build 7 one bedroom houses and 5 two bedroom houses.

What is consistent Equation?

A linear or nonlinear system of equations is called consistent if there is at least one set of values for the unknowns that satisfies each equation in the system—that is, when substituted into each of the equations, they make each equation hold true as an identity.

Let x represents the number of one-bedroom houses and y represents the number of two bedroom houses.

According to Question,

Total number of houses is 12 i.e. x + y = 12..........(i)

Total we have 88 windows in which 6 windows can be use in one bedroom house and 9 windows can be used in two bedroom house so,

6x + 9y = 88 ..................(ii)

From Equation (i) and (ii), we get

x = 7 and y = 5

Thus, Builder can build 7 one bedroom houses and 5 two bedroom houses.

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help with practice problem

Answers

Answer:

-5<x<-3

Step-by-step explanation:

Hope this helps! ;-)

factor by grouping
NEED HELP ASAP
# after letters are the exponent
1: 28v+16v2-21v-12
2: 49x3-35x2+56x-40
3: 24r3-64r2-21r+56

Answers

Answer and step-by-step explanation:

[tex]28v^3 +16v^2-21v-12 =[/tex] collecting [tex]4v^2[/tex] in the first two terms and [tex]-3[/tex] in the last two:

[tex]4v^2(7v+4)-3(7v+4) =[/tex] collecting the bracket

[tex](7v+4)(4v^2-3)[/tex]

Bonus stage: if you are factoring over the real numbers and not over the rational, the second brackets is a difference of squares. Else, you stop  here.

[tex](7v+4)(2v+\sqrt3)(2v-\sqrt3)[/tex]

NEXT!

[tex]49x^3-35x^2+56x-40=[/tex]As before, [tex]7x^2[/tex]in the first two, and [tex]8[/tex] in the last two:

[tex]7x^2(7x-5)-8(7x-5)[/tex] collecting the bracket again

[tex](7x-5)(7x^2-8) =[/tex]again, bonus step

[tex](7x-5)(\sqrt7 x +2\sqrt2) (\sqrt7x-2\sqrt2)[/tex]

FINALLY!

[tex]24r^3-64r^2-21r+56 =\\8r^2(3r-8) -7(3r-8)=\\(3r-8)(8r^2-7) =[/tex]Again, bonus step

[tex](3r-8)(2\sqrt2r+\sqrt7)(2\sqrt2r-\sqrt7)[/tex]

Since usually most courses talk about factorization of polynomials BEFORE talking about real numbers, I would stop at the third stage, skipping the fourth.

Solve the following literal equation for y 16=2y-4x

Answers

Answer:

y=2x+8

Step-by-step explanation:

Move 4x to other side and divide everything by 2

Help pls!!!!!!


A family sized box of cereal with dimensions 3x9x12 inches costs $6, while the regular size with dimensions 2x8x9 inches costs $4.50. What is the difference in price per cubic inch?

Answers

Answer:

$0.01

Step-by-step explanation:

Family size rate (per cubic inch)

Volume of box = 3 x 9 x 12 = 324 in³Cost = $6Rate = 6/324 = 1/54 = $0.02 per cubic inch

Regular size rate

Volume of box = 2 x 8 x 9 = 144 in³Cost = $4.50Rate = 4.50/144 = 1/32 = $0.03 per cubic inch

Difference in price

$0.03 - $0.02$0.01

Volume of family sized box

LBH3(9)(12)27(12)324in³

Price per inch

6/324=0.02$/in

Volume of regular size

2(8)(9)144in³

Price per in

4.5/144=0.03$/in

Difference:-

|0.02-0.03|=0.01$

Write the verbal sentence as an algebraic equation.

The product of a three and a number plus five is 20.

Answers

Step-by-step explanation:

product=× three=3 a number is unknown =x plus=+ five=5 is=equals to 20

3×x +5=20

3x+5=20

Subtract 5 from both sides

3x+5-5=20-5

3x=15

3x/3=15/3

x=5

5. in the following figure, GE= r.
where ris the radius of the circle.
a) What is the nature of the triangle GEO? Justify your answer.
b) By calculating SEG in two different ways. using ares of the ​

Answers

Answer + Step-by-step explanation:

a) GE = r = GM

Then GEO is an isosceles triangle

b) since GEO is an isosceles triangle  then :

m∠SEG = m∠GOM = measure of the arc GM (mGM)  (result 1)

On the other hand :

m∠SEG = m∠SEG = (1/2)×(mAS - mGM)  (it’s a formula)   (result 2)

Now ,we equate  (result 1) and  (result 2) :

m∠SEG = mGM  

m∠SEG = (1/2)×(mAS - mGM)

Then

mGM = (1/2)×(mAS - mGM)

c) mGM = (1/2)×(mAS - mGM)

⇔ 2mGM = mAS - mGM

⇔ 3mGM = mAS

⇔ 3m∠SEA = m∠SOA

Remember:

mGM = m∠GOM = m∠SEA

find arc JK

BRAINLIEST,POINTS,THANKS AND RATING GIVEN!!!

Answers

Answer: 164
x = 19

Explanation: The equation you would make is:

250 = 7x + 117.

Or you could also do :

125 = 1/2 ((7x + 31) + (86)) ; they both come out as the same answer.

If someone can answer all these ill give 100 points

Answers

Answer:

1. x = -6

2. x = 2

3. x = 6

4. x = 3

5. x = -5

6. x = -1

7. x = 0

8. x = 9

9. x = -4

10. x = 7

Step-by-step explanation:

1.

[tex]-10x = -8x + 12[/tex] [tex]-10x+8x=-8x+12+8x[/tex] [tex]-2x=12[/tex] [tex]-2x/-2=12/-2[/tex] [tex]x=-6[/tex]

2.

[tex]9-5x+x=1-x+x[/tex] [tex]-4x+9=1[/tex] [tex]-4x+9-9=1-9[/tex] [tex]-4x=-8[/tex] [tex]-4x/-4=-8/-4[/tex] [tex]x=2[/tex]

3.

[tex]-2x+16-x=x-2-x[/tex] [tex]-3x+16=-2[/tex] [tex]-3x+16-16=-2-16[/tex] [tex]-3x=-18[/tex] [tex]-3x/3=-18/-3[/tex] [tex]x = 6[/tex]

4.

[tex](-4)(6x)+(-4)(-2)= -8x-40[/tex] [tex]-24x+8=-8x-40[/tex] [tex]-24x+8+8x=-8x-40[/tex] [tex]-16x+8=-40[/tex] [tex]-16x+8-8=-40-8[/tex] [tex]-16x=-48[/tex] [tex]-16x/-16=-48/-16[/tex] [tex]x=3[/tex]

5.

[tex]37 - 8x = (-7)(x)+(-7)(-6)[/tex] [tex]-8x+37=-7x+42[/tex] [tex]-8x + 37 + 7x = -7x + 42 + 7x[/tex] [tex]-x+37=42[/tex] [tex]-x+37-37=42-37[/tex] [tex]-x=5[/tex] [tex]-x/-1=5/-1[/tex] [tex]x=-5[/tex]

6.

[tex]6x+(-2)(2)+(-2)(8x) = 10 + 4x[/tex] [tex]6x-4-16x = 10 + 4x[/tex] [tex]-10x - 4 = 4x + 10[/tex] [tex]-10x - 4 -4x=4x+10-4x[/tex] [tex]-14x-4=10[/tex] [tex]-14x-4+4=10+4[/tex] [tex]-14x=14[/tex] [tex]-14x/-14=14/-14[/tex] [tex]x=-1[/tex]

7.

[tex](-2)(x) + (-2)(1) = (2)(x) + (2)(-1)[/tex] [tex]-2x-2=2x-2[/tex] [tex]-2x-2-2x = 2x - 2 - 2x[/tex] [tex]-4x - 2 = -2[/tex] [tex]-4x-2+2=-2+2[/tex] [tex]-4x=0[/tex] [tex]-4x/-4=0/-4[/tex] [tex]x=0[/tex]

8.

[tex](-3)(x)+(-3)(3)=(-6)(x)+(-6)(-3)[/tex] [tex]-3x-9=-6x+18[/tex][tex]-3x-9+6x=-6x+18+6x[/tex] [tex]3x-9=18[/tex] [tex]3x-9+9=18+9[/tex] [tex]3x=27[/tex] [tex]3x/3 = 27/3[/tex] [tex]x=9[/tex]

9.

[tex]6x-36=(-4)(-2x)+(-4)(7)[/tex] [tex]6x-36= 8x -28[/tex] [tex]6x-36-8x = 8x - 28 - 8x[/tex] [tex]-2x-36=-28[/tex] [tex]-2x-36+36=-28+36[/tex] [tex]-2x = 8[/tex] [tex]-2x/-2=8/-2[/tex] [tex]x=-4[/tex]

10.

[tex](2)(x)+(2)(1) = -2x + 30[/tex] [tex]2x+2=-2x+30[/tex] [tex]2x+2+2x=-2x+30+2x[/tex] [tex]4x+2=30[/tex] [tex]4x+2-2=30-2[/tex] [tex]4x=28[/tex] [tex]4x/4=28/4[/tex] [tex]x=7[/tex]

6. The three side lengths of a triangle are given. Which triangle is a right triangle?

A. Triangle 1: 13, 6, 7
B. Triangle 2: 7, 8, 13
C. Triangle 3: 10, 11, 12
D. Triangle 4: 10, 9,8

Answers

The answer would be b because

which of the tables represent a function?
(sorry for the bad photo)
15 points!

Answers

Answer:
table B
Step-by-step explanation:

Answer:

Table B

Step-by-step explanation:

A function is present when x-value can only have a single y-value.

In Table A, the x-value 5 corresponds to 2 y-values : 3 and 2, hence it is not a function.In Table B, each x-value corresponds to a single y-value, hence it is a function.

Find the errors and solve the problem correctly!
Thanks

Answers

The sequence converges to 5 as n goes to ∞. We can prove this rigorously:

The claim is that, for [tex]n\in\Bbb N[/tex],

[tex]\displaystyle \lim_{n\to\infty} \frac{5n-1}{n+1} = 5[/tex]

By definition of the limit, this means for any ε > 0, there exists some N such that for any n larger than N, we have

[tex]\left| \dfrac{5n-1}{n+1} - 5 \right| < \varepsilon[/tex]

In order to ensure this inequality, we work backwards to find N in terms of ε :

[tex]\left| \dfrac{5n-1}{n+1} - 5 \right| = \left| \dfrac{5n-1 - 5(n+1)}{n+1} \right| = \dfrac4{|n+1|} < \varepsilon[/tex]

n is a natural number, so n + 1 > 0 and |n + 1| = n + 1. Then

[tex]\dfrac4{n+1} < \varepsilon \implies \dfrac{n+1}4 > \dfrac1\varepsilon \implies n+1 > \dfrac4\varepsilon \implies n > \dfrac4\varepsilon - 1[/tex]

Let N be the smallest natural number greater than or equal to 4/ε - 1, i.e.

[tex]N = \left\lceil \dfrac4\varepsilon - 1 \right\rceil[/tex]

Then the proof follows: suppose

[tex]n \ge N = \left\lceil \dfrac4\varepsilon - 1 \right\rceil[/tex]

Then

[tex]n \ge \left\lceil\dfrac4\varepsilon - 1\right\rceil \implies n > \dfrac4\varepsilon - 1 \\\\ \implies n+1 > \dfrac4\varepsilon \\\\ \implies \dfrac4{n+1} < \varepsilon \\\\\implies \left|\dfrac{5n-1}{n+1}-5\right| < \varepsilon[/tex]

as required.

Or we can avoid the rigor and use some facts we know about limits:

[tex]\displaystyle \lim_{n\to\infty} \frac{5n-1}{n+1} = \lim_{n\to\infty} \frac{5-\frac1n}{1+\frac1n} = 5[/tex]

since 1/n converges to 0 as n goes to ∞.

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