Which expression is equivalent?

Which Expression Is Equivalent?

Answers

Answer 1

Answer:

this one i can not help you on sorry

Step-by-step explanation:


Related Questions

hellllppppp please ​

Answers

Answer:

1. a

2. b...............

Hii Help me pls :))))

Answers

Answer:

B

Step-by-step explanation:

A: 3+5<=8

C: 9+9<19

D: 5+4<10

PLS GIVE BRAINLIEST

Answer:

Perhaps option B

Step-by-step explanation:

the number of employees for a certain company has been decreasing each year by 5%. if the company has 540 employees and this rate continues, find the number of employees in 13 years.

Answers

Answer:

Step-by-step explanation:

540

1=513

2=487.35

3=462.9825

4=

5=

6=

7=

8=

9=

10=

11=

12=

13=

Suppose a,b,c represent three positive whole numbers. if a+b=13 and b+c=22 and a+c=19 what is the value of c

Answers

Answer: C = 14

Step-by-step explanation: You can assume the A is less than B, and if you just go down in numbers such as A=6 and B=7 (To solve A + B = 13), you will eventually get to A=5 and B=8. If you do B = 8 + C = 14 ( That you get after subtracting 8 by 22 ) You should get 22, and to proof check it, you do A + C which is going to be 5 + 14 and you get 19 thus proving that C = 14.

1. Matthew decided that he would like to spend his summer working and saving his money. He begins the summer with no money in his account, but he is getting paid $160.00 per week to mow lawns. His brother Dillon began the summer with $345.00 and has decided that he will referee soccer games. He will make $45.00 per week. After how many weeks will Matthew and Dillon have the same amount of money?​

Answers

the anwer is no matthew will not have the same amount of money

Answer: 3 weeks.

Step-by-step explanation: Matthew's pay goes up by $160 a week, so that's y=160x.

Dillon's pay is $45 a week, but started out with $345. So, that's y=45x+345.

So, they will have the same amount of money after 3 weeks.

3. A ladder leaning against a wall
makes an angle of 68° with the
ground. If the foot of the ladder is 4
feet from the wall, how high on the
wall is the ladder, to the nearest
tenth of a foot?

Answers

Answer:

tangent 68° = opposite / adjacent

opposite (wall height) = tan (68) * 4 feet

opposite (wall height) = 2.4751 * 4 feet

opposite (wall height) = 9.9004 feet or

9.9 feet (to the nearest tenth of a foot).

Step-by-step explanation:

Nicole is making a cake that uses 3/4 cup of flour and 1 and 1/8 teaspoons if nicole uses 1 cup of flour how much salt would she need

Answers

Answer:

1.5 teaspoons

Step-by-step explanation:

1/(3/4)

=4/3

9/8*4/3

=1.5 teaspoons

PLS GIVE BRAINLIEST

What role do animals have in the carbon cycle?

Group of answer choices


use water and release oxygen


use sugar and release carbon


use carbon and release oxygen


use carbon and release nitrogen

Answers

Answer:

use sugar and release carbon

Step-by-step explanation:

Animals they eat and then release carbon through respiration. Nitrogen is only in the nitrogen cycle, and the only living organisms that can release oxygen are plants because humans and animals cannot photosynthesize. LOL!

what is one thousandth less than 0.061

Answers

Answer:

0.06

Step-by-step explanation:

0.061 - 0.001 = 0.060 = 0.06

A certain fraction has the value 3/4. If its numerator is decreased by 7 and its denominator is increase by 4, the resulting fraction has the value 1/2. Find the original fraction​

Answers

27/36 give me brainliest plz

Answer:

n = 16 - 7

n = 9

Step-by-step explanation:

If the numerator of a fraction is increased by 3, the fraction becomes 3/4."

Cross multiply

4(n+3) = 3d

4n + 12 = 3d

"If the denominator is decreased by 7, the fraction becomes 1."

Cross multiply

1n = d - 7

n = (d-7)

In the 1st equation replace n with d-7

4(d-7) + 12 = 3d

4d - 28 + 12 = 3d

4d - 3d - 16 = 0

d = 16 is the denominator

then n = 16 - 7

n = 9

9/16 =  the original equation

Can someone please explain how to do these? I forgot how go

Answers

Use Cosine, Adjacent/hypotenuse.

The cos=0.6

Angle is 53.13°

Turn these numbers into decimals

1. 4/12 2. 89/100 3.7/9 pls i need help

Answers

Answer:

.333   .89   .778

Step-by-step explanation:

1. 4 divided by 12 = .333

2. 89/100= .89

3. 7/9 = .778

Answer:

1. 0.333 repeated

2. 0.89

3. 0.777 repeated

Step-by-step explanation:

You just divide 4 by 12 or 7 by 9

Also, just a tip, if you have a number over 100 like 89/100 0.89 would be the decimal, for example 26/100 would be 0.26

Stealth Bank has deposits of $700 million. It holds reserves of $70 million and has purchased government bonds worth $215 million. The bank's loans have a market value of $490 million. What does Stealth Bank's net worth, or equity capital, equal?

Answers

Answer:

$75 million

Step-by-step explanation:

Given that:

Reserve value = $70 million

Purchased government bond = 215 million

Market value of loan = $490 million

Net worth :

Assets - liability

Assets = (Market value of loan + purchased government bond + reserve value)

(490 million + 215 million + 70 million)

275 million + 70 million

= $775 million

Liability = Deposits = $700 million

Net worth = ($775 - $700) million

Net worth = $75 million

Select the choice that translates the following verbal phrase correctly to algebra: (2 points)
the difference of m and 7 increased by 15
a.) m − (7 + 15)
b.) 7m + 15
c.) (m − 7) + 15
d.) m − 7 ÷ 15

Answers

i think its c. because m-7 is difference and + 15 is increasing

The graph of f(x)= 3/1+x^2 is shown in the figure to the right. Use the second derivative of f to find the intervals on which f is concave upward or concave downward and to find the inflection points of f.

Answers

Answer:

Concave Up Interval: [tex](- \infty,\frac{-\sqrt{3} }{3} )U(\frac{\sqrt{3} }{3} , \infty)[/tex]

Concave Down Interval: [tex](\frac{-\sqrt{3} }{3}, \frac{\sqrt{3} }{3} )[/tex]

General Formulas and Concepts:

Calculus

Derivative of a Constant is 0.

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Quotient Rule: [tex]\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Chain Rule: [tex]\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Second Derivative Test:

Possible Points of Inflection (P.P.I) - Tells us the possible x-values where the graph f(x) may change concavity. Occurs when f"(x) = 0 or undefinedPoints of Inflection (P.I) - Actual x-values when the graph f(x) changes concavityNumber Line Test - Helps us determine whether a P.P.I is a P.I

Step-by-step explanation:

Step 1: Define

[tex]f(x)=\frac{3}{1+x^2}[/tex]

Step 2: Find 2nd Derivative

1st Derivative [Quotient/Chain/Basic]:                           [tex]f'(x)=\frac{0(1+x^2)-2x \cdot 3}{(1+x^2)^2}[/tex]Simplify 1st Derivative:                                                           [tex]f'(x)=\frac{-6x}{(1+x^2)^2}[/tex]2nd Derivative [Quotient/Chain/Basic]:     [tex]f"(x)=\frac{-6(1+x^2)^2-2(1+x^2) \cdot 2x \cdot -6x}{((1+x^2)^2)^2}[/tex]Simplify 2nd Derivative:                                                       [tex]f"(x)=\frac{6(3x^2-1)}{(1+x^2)^3}[/tex]

Step 3: Find P.P.I

Set f"(x) equal to zero:                    [tex]0=\frac{6(3x^2-1)}{(1+x^2)^3}[/tex]

Case 1: f" is 0

Solve Numerator:                           [tex]0=6(3x^2-1)[/tex]Divide 6:                                          [tex]0=3x^2-1[/tex]Add 1:                                              [tex]1=3x^2[/tex]Divide 3:                                         [tex]\frac{1}{3} =x^2[/tex]Square root:                                   [tex]\pm \sqrt{\frac{1}{3}} =x[/tex]Simplify:                                          [tex]\pm \frac{\sqrt{3}}{3} =x[/tex]Rewrite:                                          [tex]x= \pm \frac{\sqrt{3}}{3}[/tex]

Case 2: f" is undefined

Solve Denominator:                    [tex]0=(1+x^2)^3[/tex]Cube root:                                   [tex]0=1+x^2[/tex]Subtract 1:                                    [tex]-1=x^2[/tex]

We don't go into imaginary numbers when dealing with the 2nd Derivative Test, so our P.P.I is [tex]x= \pm \frac{\sqrt{3}}{3}[/tex] (x ≈ ±0.57735).

Step 4: Number Line Test

See Attachment.

We plug in the test points into the 2nd Derivative and see if the P.P.I is a P.I.

x = -1

Substitute:                    [tex]f"(x)=\frac{6(3(-1)^2-1)}{(1+(-1)^2)^3}[/tex]Exponents:                   [tex]f"(x)=\frac{6(3(1)-1)}{(1+1)^3}[/tex]Multiply:                        [tex]f"(x)=\frac{6(3-1)}{(1+1)^3}[/tex]Subtract/Add:              [tex]f"(x)=\frac{6(2)}{(2)^3}[/tex]Exponents:                  [tex]f"(x)=\frac{6(2)}{8}[/tex]Multiply:                       [tex]f"(x)=\frac{12}{8}[/tex]Simplify:                       [tex]f"(x)=\frac{3}{2}[/tex]

This means that the graph f(x) is concave up before [tex]x=\frac{-\sqrt{3}}{3}[/tex].

x = 0

Substitute:                    [tex]f"(x)=\frac{6(3(0)^2-1)}{(1+(0)^2)^3}[/tex]Exponents:                   [tex]f"(x)=\frac{6(3(0)-1)}{(1+0)^3}[/tex]Multiply:                       [tex]f"(x)=\frac{6(0-1)}{(1+0)^3}[/tex]Subtract/Add:              [tex]f"(x)=\frac{6(-1)}{(1)^3}[/tex]Exponents:                  [tex]f"(x)=\frac{6(-1)}{1}[/tex]Multiply:                       [tex]f"(x)=\frac{-6}{1}[/tex]Divide:                         [tex]f"(x)=-6[/tex]

This means that the graph f(x) is concave down between  and .

x = 1

Substitute:                    [tex]f"(x)=\frac{6(3(1)^2-1)}{(1+(1)^2)^3}[/tex]Exponents:                   [tex]f"(x)=\frac{6(3(1)-1)}{(1+1)^3}[/tex]Multiply:                       [tex]f"(x)=\frac{6(3-1)}{(1+1)^3}[/tex]Subtract/Add:              [tex]f"(x)=\frac{6(2)}{(2)^3}[/tex]Exponents:                  [tex]f"(x)=\frac{6(2)}{8}[/tex]Multiply:                       [tex]f"(x)=\frac{12}{8}[/tex]Simplify:                       [tex]f"(x)=\frac{3}{2}[/tex]

This means that the graph f(x) is concave up after [tex]x=\frac{\sqrt{3}}{3}[/tex].

Step 5: Identify

Since f"(x) changes concavity from positive to negative at [tex]x=\frac{-\sqrt{3}}{3}[/tex] and changes from negative to positive at [tex]x=\frac{\sqrt{3}}{3}[/tex], then we know that the P.P.I's [tex]x= \pm \frac{\sqrt{3}}{3}[/tex] are actually P.I's.

Let's find what actual point on f(x) when the concavity changes.

[tex]x=\frac{-\sqrt{3}}{3}[/tex]

Substitute in P.I into f(x):                    [tex]f(\frac{-\sqrt{3}}{3} )=\frac{3}{1+(\frac{-\sqrt{3} }{3} )^2}[/tex]Evaluate Exponents:                          [tex]f(\frac{-\sqrt{3}}{3} )=\frac{3}{1+\frac{1}{3} }[/tex]Add:                                                    [tex]f(\frac{-\sqrt{3}}{3} )=\frac{3}{\frac{4}{3} }[/tex]Divide:                                                [tex]f(\frac{-\sqrt{3}}{3} )=\frac{9}{4}[/tex]

[tex]x=\frac{\sqrt{3}}{3}[/tex]

Substitute in P.I into f(x):                    [tex]f(\frac{\sqrt{3}}{3} )=\frac{3}{1+(\frac{\sqrt{3} }{3} )^2}[/tex]Evaluate Exponents:                          [tex]f(\frac{\sqrt{3}}{3} )=\frac{3}{1+\frac{1}{3} }[/tex]Add:                                                    [tex]f(\frac{\sqrt{3}}{3} )=\frac{3}{\frac{4}{3} }[/tex]Divide:                                                [tex]f(\frac{\sqrt{3}}{3} )=\frac{9}{4}[/tex]

Step 6: Define Intervals

We know that before f(x) reaches [tex]x=\frac{-\sqrt{3}}{3}[/tex], the graph is concave up. We used the 2nd Derivative Test to confirm this.

We know that after f(x) passes [tex]x=\frac{\sqrt{3}}{3}[/tex], the graph is concave up. We used the 2nd Derivative Test to confirm this.

Concave Up Interval: [tex](- \infty,\frac{-\sqrt{3} }{3} )U(\frac{\sqrt{3} }{3} , \infty)[/tex]

We know that after f(x) passes [tex]x=\frac{-\sqrt{3}}{3}[/tex] , the graph is concave up until [tex]x=\frac{\sqrt{3}}{3}[/tex]. We used the 2nd Derivative Test to confirm this.

Concave Down Interval: [tex](\frac{-\sqrt{3} }{3}, \frac{\sqrt{3} }{3} )[/tex]

Pleas help I’m almost appreciate it I’m almost done.

Answers

Answer:

x = 2

RS = 20

ST = 20

RT = 5

Step-by-step explanation:

X=2
RS= 20
ST= 20
RT= 5
Just put RS = RT

Is it possible to improve your grade from a "d" to a "b"?​

Answers

Answer: Of course it is possible if you try your hardest and study

Answer:

Depends

Step-by-step explanation:

Hello! This problem really depends on where you are in the grading period and how many grades are entered in relation to your grade. If you have a D but only have 2 grades then getting a B in the class should be relatively easy. However, if you have a D in a class that you have 15 graded assignments in it will be much harder to raise your grade to a B. Best thing to do is work at this early and try not to let your grade dip throughout the grading semester.

Hope this helps!

-HM

What slope would make the lines
parallel?
y = 5x + 2
y = [?]x + 3

Answers

Answer:

5

General Formulas and Concepts:

Algebra I

Parallel lines have the same slope

Slope-Intercept Form: y = mx + b

m - slope b - y-intercept

Step-by-step explanation:

Parallel lines have the same slope but different y-intercepts.

Our given slope is 5. Therefore, our parallel slope is also 5.

10 1/8 - 3 5/6=.......?

Answers

Answer:

6 7/24

Step-by-step explanation:

6 7/24 Hope this helps!

The process for rationalizing a denominator in a variable expression is the same as in a numeric expression. Here’s a real-world example. The kinetic energy of the car of a rollercoaster is given by the formula k = one-half m v squared where k is kinetic energy, m is the mass of the car, and v is the velocity of the car. Solving this formula for v, we get v = StartRoot StartFraction 2 k Over m EndFraction EndRoot Which formula gives the velocity of the car in simplest form?

Answers

Answer:

It's B

Step-by-step explanation:

Got it right on EDGE2020

The value of velocity of the car will be v = √(2km) / m. Then the correct option is B.

What is kinetic energy?

If the object of mass m is moving with speed v. Then the kinetic energy of the object will be

KE = (1/2) mv²

The process for rationalizing a denominator in a variable expression is the same as in a numeric expression.

Here’s a real-world example.

The kinetic energy of the car of a rollercoaster is given by the formula

k = 1/2 m v²

Where k is kinetic energy, m is the mass of the car, and v is the velocity of the car.

Solving this formula for v, we get

[tex]\rm v = \sqrt{\dfrac{2k}{m}}[/tex]

Simplify the equation, we have

[tex]\rm v = \sqrt{\dfrac{2km}{m^2}}\\\rm v = \dfrac{\sqrt{2km}}{m}[/tex]

Then the correct option is B.

The complete question is attached below.

More about the kinetic energy link is given below.

https://brainly.com/question/12669551

#SPJ2

There are 7 students in a class: 5 boys and 2 girls.
If the teacher picks a group of 3 at random, what is the probability that everyone in the group is a boy?

Answers

3/7 is the answer for this question

Can someone help me simplify this!!!

Answers

Answer:

The answer is in the picture i put, its an equation so 8 can't write it

8) Eugene borrows $250 at a 4% annual interest rate. If he does not
make any payments, how much simple interest will he owe in 18 months?
A) $10
B) $15
C) $18
D) $20

Answers

Answer:

The simplest interest will be $15 ⇒ B

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

P is the initial amountr is the rate in decimalt is the time

∵ Eugene borrows $250 at a 4% annual interest rate

P = 250

r = 4% = 4 ÷ 100 = 0.04

∵ The time is 18 months

→ Change the time to year because the rate is annual

∵ 1 year = 12 months

t = 18 ÷ 12 = 1.5 years

→ Substitute the values of P, r, and t in the rule above to find the interest

∵ I = 250 × 0.04 × 1.5

I = 15

The simplest interest will be $15

I need help on this...

Answers

Answer:

The answer would be C.

Step-by-step explanation:

X is greater than and equal to -2. So it would be a closed circle and it would be going to the right.

Answer:

C

Step-by-step explanation:

when x is greater than AND equal to -2

the numberline will show a closed circle on -2 and a line to the right (because greater than means positive and all numbers to the right increase)

A pair of eyeglasses cost $347.89. The frames of the glasses are $97.86. How much do the lenses of the eyeglasses cost.

Answers

Answer:

$250.03

Step-by-step explanation:

cost of lenses = total cost - cost of frames

cost of lenses = $347.89 -  $97.86

cost of lenses = $250.03

Find the value of the variable, x



Group of answer choices

6

3

15

5

Answers

Answer:

I think you might have a mistake for the numbers you put there.

But the answer is about 15

Step-by-step explanation:

I did the calculation and got 14, but 15 is the closeest answer

a small airplane flies 1 015miles with an average speed of 290 mph. 1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time; what was the average speed of Boeing 747?

Answers

Answer:

The Boeing 747 had an average speed of 580 mph.

Step-by-step explanation:

Constant speed motion

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

[tex]\displaystyle v=\frac{d}{t}[/tex]

Where

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

[tex]\displaystyle t=\frac{d}{v}[/tex]

The small airplane travels 1015 miles at a constant speed of v=290 miles/hour. The time it took to arrive its destiny was:

[tex]\displaystyle t=\frac{1015}{290}[/tex]

t = 3.5 hours

The Boeing 747 left from the same point 1.75 hours after the small plane and traveled the same distance. It needed a time t' = 3.5 - 1.75 = 1.75 hours,  thus its speed must have been:

[tex]\displaystyle v=\frac{1015}{1.75}=580[/tex]

The Boeing 747 had an average speed of 580 mph.

How many arrays are in 42

Answers

Answer:

4 (or eight if you count transposed arrays as being different).

Step-by-step explanation:

On a number​ line, between which two consecutive whole numbers would the square root of 277 be located

Answers

9514 1404 393

Answer:

  16 and 17

Step-by-step explanation:

16² = 256

(√277)² = 277

17² = 289

The root of 277 is between 16 and 17.

Write the following in Scientific Notation. -18,500,000,000,000​

Answers

Answer:

Its 1.85 x 10 to the 13th power

Step-by-step explanation:

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