Which describes why liquid moves through a straw?

A. The straw allows a method of escape for the liquid in the glass.
B. The liquid inside the straw has a higher pressure than the air outside, so it draws the air in.
C. The air pressure creates a vacuum in the straw that pulls the air into the liquid.
D. The atmosphere pushes down on the liquid in the glass causing it to rise in the straw.

Answer:

if he drops them some where there is no air they will both land at the same time as they have no air resistance and gravity pulls every item equally but if they just do it of a building in the middle of the street then the baseball would hit first as it has a larger mass  

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eat this

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should be earthquake

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P1V1=P2V2

65 mmHg × 600 mL = 385 mmHg × V2

V2 = 101.30 mL

Explanation:

We can use Boyle's law

Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion

The sum of the coefficients for all reactants and products is: 12.

Here, we first need to balance the equation of the reaction between Fe2S3(s) and H+.

The sum of the coefficients for all reactants and products is therefore;

Sum = 1 + 6 + 3 + 2.

Sum of coefficients = 12

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Answer:

424 grams of sodium are contained in 4moles of na2co3

i hope this calculation will help you  

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The rice will move

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the sound vibration and waves will cause the rice to move

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The rice will begin to move.

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W I think good luck I think

Answer: w

Explanation: potential energy is greater when higher from the ground. i took the test

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It takes the shape of a container.

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i

b because it says it in the question

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fafsafwafsxDlmfao

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your welcome :)

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strawberry blueberry raspberry walang compound at element

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19.3 g/cm3

A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper? 19.3 g/cm3

Answer:

Someone Said Telophase II. Ill update if its right or wrong when I finish.

Update : He is.... Wong. False.

Explanation:

The answer is Prophase I. It is not Telophase II.

Billions of time smaller

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hydrogen cloride

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C(s) + O2(g) --> CO2(g)

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True

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Solid carbon and oxygen gas when mixed together reacts, and forms carbon dioxide gas.

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Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.

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hiiiii

hope u Likes it

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The answer has to be A, greater force of attraction than the gas, only

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I really hope this helps! Have a good day and good luck!

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Radiation therapy

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I hope this helps

Answer:

850

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It's between 840 and 860

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yes

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it's easy

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Approximately [tex]81.84\%[/tex].

Explanation:

Balanced equation for this reaction:

[tex]{\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)[/tex].

Look up the relative atomic mass of elements in the limiting reactant, [tex]\rm CaCl_{2}[/tex], as well as those in the product of interest, [tex]\rm CaCO_{3}[/tex]:

Calculate the formula mass for both the limiting reactant and the product of interest:

[tex]\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

[tex]\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the quantity of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) available to this reaction:

[tex]\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}[/tex].

Refer to the balanced equation for this reaction. The coefficients of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) and the product ([tex]{\rm CaCO_{3}}[/tex]) are both [tex]1[/tex]. Thus:

[tex]\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1[/tex].

In other words, for every [tex]1\; \rm mol[/tex] of [tex]\rm CaCl_{2}[/tex] formula units that are consumed, [tex]1\; \rm mol\![/tex] of [tex]\rm CaCO_{3}[/tex] formula units would (in theory) be produced. Thus, calculate the theoretical yield of [tex]\rm CaCO_{3}\![/tex] in this experiment:

[tex]\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}[/tex].

Calculate the theoretical yield of this experiment in terms of the mass of [tex]\rm CaCO_{3}[/tex] expected to be produced:

[tex]\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}[/tex].

Given that the actual yield in this question (in terms of the mass of [tex]\rm CaCO_{3}[/tex]) is [tex]13.19\; \rm g[/tex], calculate the percentage yield of this experiment:

[tex]\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}[/tex].

Answer:

Technology

hope this helps

125 milliliters of a 6.00 M sulfuric acid solution are required if 0.750 moles of H2SO4 are needed for a reaction.

HOW TO CALCULATE VOLUME:

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