Which congruence criteria cab be used directly from the information about triangles jhk ghl to prove hk and ghl

Answers

Answer 1

Triangle JHK and GHL are congruent based on the angle-angle-angle congruency theorem.

What are congruent triangles?

Two triangles are said to be congruent if they have the same shape and angles. The ratio of their corresponding sides are also to be proportional.

Given triangle JHK and GHL are congruent based on the angle-angle-angle congruency theorem.

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Related Questions

Draw the image of the figure under the given rotation. Triangle PQR; 90 degrees about the the origin. Number 2 :)

Answers

The attached figure represents the image of the triangle under the rotation

How to draw the image of the triangle?

The coordinates of the triangle are given as:

P = (2, 1)

Q = (4, 1)

R = (4, -3)

The rule of 90 degrees rotation about the origin is:

(x, y) = (y, -x).

So, we have:

P' = (1, -2)

Q' = (1, -4)

R' = (-3, -4)

See attachment for the figure under the rotation

Answers

According to multiplication you can use repeated addition to get the same product of the given equation.

Ex: 5x2= 2+2+2+2+2 ( 5 groups of 2)

Both will give you same answer (10).

Hence 2 x 3/4 = 3/4 + 3/4

Answer:

2 x 3/4 = 3/4 + 3/4

Step-by-step explanation:

(LOOK AT IMAGE)
EG is a tangent to the circle below at point F.
Calculate the size of angle x.
Give reasons for your answer.

Answers

[tex]\angle FHD=74^{\circ}[/tex] (alternate segment theorem)

[tex]x=77^{\circ}[/tex] (angles in a triangle add to 180 degrees)

if t is 25% of u, then what percent of 4t is 2u?

Answers

Howdy,

Step-by-step explanation:

t = .25u (given)

4 t = 4 (.25u) = u

then u = 50% of 2 u

T = 0.25u
4t = 4(0.25u) =
u
Then u is 50 percent of 2u.
Hope this helps, please mark brainliest if possible :)

suppose it costs $45 to attend a concert where the band plays for 1.5 hours.

a. what was the cost to attend the concert per hour?
b. what was the cost to attend to the concert per minute
make sure to show your work

Answers

Answer

$30 minutes per hour

$0.5 per minute

Step-by-step explanation:

45/1.5=30

45/90=0.5

Geometry question Need help with #10

Answers

Answer:

x = 6

Step-by-step explanation:

Line segment SU is a bisector of angle <TSV which means it divided the angle into two equal parts:

The measure of <TSV = 62 in this case the measure of <VSU = 62/2 = 31

we can write the following equation to find the value of x

5x + 1 = 31 subtract 1 from both sides

5x = 30 divide both sides by 5

x = 6

Suppose Z has a standard normal distribution with a mean of 0 and a standard deviation of 1. 27% of the possible Z values are smaller than __________.

Answers

Suppose Z has a standard normal distribution with a mean of 0 and a standard deviation of 1. 27% of the possible Z values are smaller than 0.613.

The standard normal distribution, also known as the z-distribution, is a special normal distribution with a mean of 0 and a standard deviation of 1. The normal distribution can be standardized by converting its value to a z-score. The Z-score indicates how many standard deviations each value has from the mean.

The standard normal distribution (z distribution) is a normal distribution with a mean of 0 and a standard deviation of 1. Each point (x) of the normal distribution can be converted to the standard normal distribution (z) using the equation z = (x-mean) / standard deviation.

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what is the area of the shaded region?

Answers

Area of Composite Shapes

To find the area of composite shapes, we can break the bigger shape down into small, simpler shapes, and find the sum of their areas.

For this triangle, we will need to know the formula to find the area of a triangle:

[tex]A=\dfrac{1}{2}bh[/tex]

Solving the Question

The given shape can be seen as one large triangle with a little triangle cut out of it. To find the shaded region, we can:

Find the area of the large triangleFind the area of the little triangleSubtract the area of the little triangle from the large triangle

Area of the Large Triangle

[tex]A=\dfrac{1}{2}bh[/tex]

⇒ Plug in the values given for the base and height:

[tex]A=\dfrac{1}{2}(5)(2+4+6)\\\\A=\dfrac{1}{2}(5)(12)\\\\A=(5)(6)\\\\A=30 mm^2[/tex]

Area of the Small Triangle

[tex]A=\dfrac{1}{2}bh[/tex]

⇒ Plug in the values given for the base and height:

[tex]A=\dfrac{1}{2}(3)(4)\\\\A=(3)(2)\\\\A=6mm^2[/tex]

Subtract the Area of the Small Triangle from the Area of the Large Triangle

[tex]30 mm^2-6mm^2\\=24mm^2[/tex]

Answer

The area of the shaded region is [tex]24mm^2[/tex].

find the product (2y - 2nb) (y+4nb)

Answers

Answer: 2y^2+6bny-8n^2b^2

Step-by-step explanation: I hope this helps!

You should be able to find this
without a calculator.
cos(cos-¹ 0.3) = [?]

Answers

Hello:

Let's consider this problem in steps:

Let's gather some information:

cosine and arccosine cancel each other out in this case

Now let's apply our knowledge to solve the problem:

[tex]\rm \hookrightarrow cos(cos^{-1}0.3) = 0.3[/tex]

Answer: 0.3

Hopefully that helps!

[tex]\frak{Hi!}[/tex]

[tex]\large\text{Related Concept-:}[/tex]

[tex]\boxed{\begin{minipage}{10cm} \sf{If\;you\;take\;the\;inverse\;cosine}\\ \;of\;a\;number,\;and\;then\;take\; its\;cosine,\;don't\;you\;get\;the\;number \\ you started with? \end{minipage}}[/tex]

Clarification

The inverse cosine and the cosine are operations that undo each other.

This being said, let's solve our problem.

[tex]\bf{cos(cos^{-1}\;0.3)=0.3[/tex], based on what I said above

[tex]\cal{CALLIGRAPHY}[/tex]

In the following exercises, multiply the binomials. Use any method.
258. (5x − y)(x − 4)

Answers

Answer:

Hence the expression [tex]$$(5x-y)(x-4)=5x^2-xy-20x+4y$$[/tex]

Step-by-step explanation:

Explanation

The given expression is (5 x-y)(x-4).We have to multiply the given expression.Multiply the (5 x-y) by -4, multiply the (5 x-y) by x then add like terms.

[tex]$$\begin{matrix}{} & {} & {} & {} & 5x & - & y \\ \times & {} & {} & {} & x & - & 4 \\ \end{matrix}$$[/tex]

_________________

[tex]$$\begin{matrix}{} & {} & {} & - & 20x & + & 4y \\ 5{{x}^2} & - & xy & {} & {} & {} & {} \\ \end{matrix}$$[/tex]

_________________

[tex]$$\begin{matrix}5{{x}^2} & - & xy & - & 20x & + & 4y \\ \end{matrix}$$[/tex]

Mrs. Ibarra wants to create a right triangle for a geometry test. She plans to use 15, 36, and 41 as side lengths.

Select the four true statements regarding the side lengths Mrs. Ibarra chose.
15 + 36 greater-than 41, so the side lengths will form a triangle.
15 + 36 not-equals 41, so those lengths will not form a triangle.
15 squared + 36 squared = 1,521
41 squared = 1,681
Since a squared + b squared not-equals c squared, it will not be a right triangle.
15 squared + 36 squared = 297
41 squared = 82

Answers

Answer:

See below.

Step-by-step explanation:

Sides: 15, 36, 41

True: 15 + 36 greater-than 41, so the side lengths will form a triangle.

True: 15 squared + 36 squared = 1,521

True: 41 squared = 1,681

True: Since a squared + b squared not-equals c squared, it will not be a right triangle.

Answer:

A) 15 + 36 greater-than 41, so the side lengths will form a triangle.

C) 15 squared + 36 squared = 1,521

D) 41 squared = 1,681

E) Since a squared + b squared not-equals c squared, it will not be a right triangle.

Proof:

Using a phone to drive people to Web-based survey instruments is known as a(n) online focus group. online theater system. hybrid survey. cybertracking tactic.

Answers

Answer:

Using a phone to drive people to web-based survey instruments is known as a hybrid survey.

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then what is the probability of observing at least one car during any 5-minute time interval

Answers

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

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is x/3 = 5/6, then x =

Answers

⅓X=5/6
X=(5/6)/⅓
=5/2

you divide the denominator so it would be 5/2

on the first day the apple iphone 5 was released, the local store had 200 in stock. by 8:00 pm, the store had sold 3/5 of their stock. how many phone were left in the store’s stock?

Answers

Answer:

120 Phones

Step-by-step explanation:

3/5 of 200

Step 1: Divide 200 by 5

200 ÷ 5 = 40

Step 2: Multiply 40 by 3

40 · 3 = 120

Answer: 3/5 of 200 = 120

Tip: When finding a fraction of a whole, divided the whole by the denominator, then multiply the quotient you got by dividing the whole by the denominator by the numerator

Example: 1/2 of 80

80 ÷ 2 = 40

40 · 1 =40

1/2 of 80 = 40

Help please!
A vocational school admits 4 out of every
10 people who apply for admission. One
year, 640 students were admitted. How
many people applied for admission?

Answers

Answer:

319

Step-by-step explanation:

i am really not sure but i believe so i hope it is the right answer

Answer:

1600 people

Step-by-step explanation:

This is a ratio problem. We can set up the proportion by letting x be the number of people who applied for admission:

[tex]\frac{4}{10}=\frac{640}{x}[/tex]

Since we know that 4 people get in for every 10 people that apply, we can set up an equation like the one above and solve for x by cross multiplying:

[tex]6400=4x\\x=1600[/tex]

This means that 1600 people applied for admission to the vocational school.

help me please please please!!!

What formula should be used to calculate an unknown side of a right angled triangle
when the hypotenuse (c) and one other side (b) are known?

a) Oa^2 = b^2-c^2

b) Oa^2 = c^2 + b^2

c) Oa^2 = c^2-b^2

d) Oc^2 = a^2 - b^2

e) Oc^2 = b^2- a^2

Answers

C is the correct answer

because it would be the hypotenuse c squared minus the side b squared

The sum of a squared plus b squared equals c squared

Answer:

c) Oa^2 = c^2-b^2

Step-by-step explanation:

the formula of finding hypotenuse (c) is

c^2 = a^2 + b^2

that means c^2 - b^2 = a^2

a^2 = c^2 - b^2.

Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses.

f(x)=
x+a
b

g(x)=cx−d

Part 2. Show your work to prove that the inverse of f(x) is g(x).

Part 3. Show your work to evaluate g(f(x)).

Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include five values for each function. Graph the line y = x on the same graph.

Task 2
Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model:

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

Answers

See below for the solution to the inverse function and the rational equation

The function and the inverse

Create functions f(x) and g(x)

The functions are given as:

f(x) = x + a/b

g(x) = cx − d

Let a = 4 and b = 2.

So, we have:

f(x) = x + 4/2

Rewrite as:

y = x + 2

Swap x and y

x = y + 2

Make y the subject

y = x - 2

So, we have:

g(x) = x - 2

So, the functions are:

f(x) = x + a/b ⇒ f(x) = x + 4/2

g(x) = cx − d ⇒ g(x) = x - 2

Show that the functions are inverse functions

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

If the functions are inverse functions, then:

f(g(x)) = x

We have:

f(x) = x + 4/2

This gives

f(g(x)) = g(x) + 4/2

This gives

f(g(x)) = x - 2 + 4/2

Evaluate

f(g(x)) = x

Evaluate g(f(x))

In (a), we have:

f(x) = x + 4/2

g(x)= x - 2

We have:

g(x)= x - 2

This gives

g(f(x)) = f(x) - 2

This gives

g(f(x)) = x + 4/2 - 2

Evaluate

g(f(x)) = x

Graph the functions

See attachment for the graph

The table of values is:

x f(x) g(x)

0 2 -2

1 3 -1

2 4 0

3 5 1

4 6 2

Radical equations

Create the equations

The form of the equations is given as:

[tex]a\sqrt{x + b} + c= d[/tex]

So, we have:

[tex]\sqrt{4x + 5} + 1 = 0[/tex] --- has extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex] --- has no extraneous solution

The equation solution

Equation 1 with extraneous solution

[tex]\sqrt{4x + 5} + 1 = 0[/tex]

Subtract 1 from both sides

[tex]\sqrt{4x + 5} = -1[/tex]

Square both sides

4x + 5 = 1

Evaluate the like terms

4x = -4

Divide by 4

x = -1

Substitute x = -1 in [tex]\sqrt{4x + 5} + 1 = 0[/tex] to check

[tex]\sqrt{4(-1) + 5} + 1 = 0[/tex]

[tex]\sqrt{-4 + 5} + 1 = 0[/tex]

[tex]\sqrt{1} + 1 = 0[/tex]

Evaluate the root

[tex]1 + 1 = 0[/tex]

[tex]2= 0[/tex] --- false

Equation 2 without extraneous solution

[tex]2\sqrt{3x - 1} + 2 = 8[/tex]

Subtract 2 from both sides

[tex]2\sqrt{3x - 1} = 6[/tex]

Divide by 2

[tex]\sqrt{3x - 1} = 3[/tex]

Square both sides

3x - 1 = 9

Evaluate the like terms

3x = 10

Divide by 3

x = 10/3

Substitute x = x = 10/3 in [tex]2\sqrt{3x - 1} + 2 = 8[/tex] to check

[tex]2\sqrt{3 * \frac{10}{3} - 1} + 2 = 8[/tex]

[tex]2\sqrt{10 - 1} + 2 = 8[/tex]

[tex]2\sqrt{9} + 2 = 8[/tex]

Evaluate the root

[tex]2*3 + 2 = 8[/tex]

[tex]8 = 8[/tex] --- true

Why the equations have (or do not have) an extraneous solution

The first equation has an extraneous solution because the solution is false for the original equation and the second does not have an extraneous solution because the solution is true for the original equation

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In triangle QRS, QR = 8 and RS = 5. Which expresses all possible lengths of side QS?
QS = 13
5 < QS < 8
QS > 13
3 < QS < 13

Answers

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side. The length of QS can lie between 3 < QS < 13.

What is the triangle inequality theorem?

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.

Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,

(a+b) > c(b+c) > a(c+a) > b

As per the given law of triangle inequality, the sum of the two sides of the triangle is greater than the third side.

x + 8 > 5

x > -3

x + 5 > 8

x > 3

8 + 5 > x

13 > x

Hence, the length of QS can lie between 3 < QS < 13.

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The figure shown is a regular octagon. The measure of
What is the measure of

Answers

Answer:

135°

Step-by-step explanation:

X is also 135° as is S , T U , V, W and Y

Answer:

b)135°

Step-by-step explanation:

The value of an interior angle of 135° is appreciated

In a regular polygon all interior angles are equal

Angle x = 135°

Hope this helps

What is b and c in this expression?
[tex]\sqrt[4]{15^7} }[/tex]

Answers

The value of b and c is 4 and 7.

What is algebra?

Algebra is the part of mathematics in which letters and other general symbols are used to represent numbers and quantities in formulae and equations.

Algebra is divided into different sub-branches such as elementary algebra, advanced algebra, abstract algebra, linear algebra, and commutative algebra.

Elementary algebra: elementary algebra, branch of mathematics that deals with the general properties of numbers and the relations between them. Algebra is fundamental not only to all further mathematics and statistics but to the natural sciences, computer science, economics, and business.

From the given question,

[tex]\sqrt[4]{15^7}[/tex] This expression can also be written in the form of [tex]a^\frac{b}{c}[/tex]

We will convert [tex]\sqrt[4]{15^7}[/tex] to the required form:

[tex](15^\frac{7c}{4b} )\left \{ {{a=15^\frac{7c}{4b} } \atop {b=b} , c = c} \right.[/tex]

Hence,

From the above equation we get the value of b and c is 4 and 7.

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Help me help me help me help me help me please

Answers

Answer:

x = 1, 4

Step-by-step explanation:

We assume the graph is of the relation y = f(x). The desired values of x are those that correspond to points where the y-value is -2.

Reading the graph

We are only interested in the x-coordinates of points that lie on the horizontal line where y = -2. Those points are (1, -2) and (4, -2).

The values of x such that f(x) = -2 are x=1 and x=4.

Kara wants to make a histogram of the number of students who wear blue shirts in her class throughout the week. She gathered the following information:

Day 1 4 students

Day 2 9 students

Day 3 5 students

Day 4 7 students

Day 5 6 students

What data would be on the horizontal axis?
names of the students wearing the blue shirts
the exact color of the blue shirt
school day
number of students wearing blue shirts

Answers

Answer:

school day

Step-by-step explanation:

When drawing a chart or a graph:

x-axis: Independent variabley-axis: Dependent variable

The two given variables are:

number of students who wear blue shirtsdays of the week

Therefore, in this scenario the independent variable is the school day and the dependent variable is the number of students since the former effects the latter.

So the data on the horizontal axis (x-axis) is: school day

On a coordinate plane, a quadrilateral has points E (negative 2, 0), D (0, 4), G (4, 2), and F (0, 0).
Which are true if figure DEFG is reflected across the x-axis? Check all that apply.

D(0, 4) → D'(0, –4)
E(–2, 0) → E'(–2, 0)
The perpendicular distance from G' to the x-axis will equal 2 units.
The perpendicular distance from D' to the x-axis will equal 8 units.
The orientation will be preserved.

Answers

By applying the reflection rule across the x-axis to quadrilateral DEFG, we obtain the following true statements:

D(0, 4) → D'(0, -4)E(-2, 0) → E'(-2, 0)The perpendicular distance from G' to the x-axis will be equal to 2 units.

The reflection of a quadrilateral.

In Geometry, the x-axis would remain the same if a quadrilateral is reflected across the x-axis and the sign on the y-axis would change either from positive to negative and vice-versa.

By applying the reflection rule across the x-axis (x, y) → (x, -y), we obtain the following true statements:

D(0, 4) → D'(0, -4)E(-2, 0) → E'(-2, 0)The perpendicular distance from G' to the x-axis will be equal to 2 units.

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Answer:

Are the right answer

Step-by-step explanation:

Which conditional and its converse form a true biconditional?
If x = 19, then 2x – 3 = 35.

If x = 3, then x2 = 9.

If x2 = 4, then x = 2.

If x > 0, then > 0.

Answers

The conditional and its converse that form a true biconditional is; Option A; If x = 19, then 2x – 3 = 35.

How to Interpret Biconditional Statements?

A) If x = 19, then 2x – 3 = 35.

Thus, 2(19) - 3 = 35. Thus, this is a true biconditional.

B) If x = 3, then x²= 9.

This is not a true biconditional because x could also be -3.

C) If x² = 4, then x = 2

This is not a true biconditional because x could also be -2.

D) If x > 0, then |x| > 0.

This is not a true biconditional because x could also be negative which less than zero.

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I WILL MARK BRAINLIEST A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, can the company build 20 child bikes and 6 adult bikes in a week.

Answers

Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable c: number of child bikes.Variable a: number of adult bikes.

Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:

4c + 4a = 100.

c + a = 25.

With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:

c + a = 26

20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

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1. One group (A) contains 180 people.
One-fourth of the people in group A will be
selected to win free tickets to a concert.
There is another group (B) in a nearby town
that will receive the same number of tickets,
but there are 292 people in that group.
What will be the ratio of non-winners in
2
group A to non-winners in group B after the
selections are made?

Answers

Answer:

135:147

Step-by-step explanation:

180/4=45

180-45=135

292-45=247

135:247

A construction company prepares an
estimate to install a new pool for a home-
owner. The estimate includes h hours of
labor, where h>80. The company's goal
is for the estimate to be within 8 hours
of the actual number of hours of labor. If
the company meets the goal and it takes
a hours of actual labor, which inequality
represents the relationship between the
estimated number of hours of labor and
the actual number of hours of labor?
A) a+h≤8
B) a2h+8
C) ash-8
D) -8≤a-h≤8

Answers

The equation that represents the relationship between the estimated number of hours of labor and the actual number of hours of labor is D. -8≤a-h≤8.

How to illustrate the equation?

From the information given, the estimate includes h hours of labor, where h>80 and the company's goal is for the estimate to be within 8 hours of the actual number of hours of labor.

Here, the equation that represents the relationship between the estimated number of hours of labor and the actual number of hours of labor is -8≤a-h≤8.

In conclusion, the correct option is D.

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Question
(01.02 MC)
For which of the following distributions is the mean most likely to be less than the median?

Answers

The distribution where the mean is most likely to be less than the median is the third histogram.

How to illustrate the information?

It should be noted that when the histogram shows the day is left skewed, it means the mean is less than the median.

If it right skewed, the mean is greater than the median.

When they're equal, the data is symmetric.

In this case, based on the information, the distribution where the mean is most likely to be less than the median is the third histogram.

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