Answer:
a. DNA storage
Explanation:
A dolphin maintains a constant speed of 2.0 m/s for 24 s while swimming in a straight line. It then reverses direction and returns to its starting point in 8 s. Its average speed and average velocity for the entire trip are
Answer:
Average speed 3m/sAverage velocity is 4m/s
Explanation:
In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.
Given data
speed v= 2 m/s
time t= 24s
the distance travelled by the dolphin is
speed= distance/time
distance= speed*time
distance= 2*24
distance= 48m
now the dolpine made a reverse and covered this 48m in 8s to return to it initial position
the speed it took is
speed= distance/time
speed= 48/8
speed= 6m/s
It average speed is the total distance divided by the total time taken
average speed= (48+48)/(24+8)= 96/32= 3m/s
average speed= 3 m/s
it average velocity is the sum of the initial and final velocity is divided by 2 to find the average
(2+6)/2= 8/2= 4m/s
average velocity is 4m/s
The x-component is 8 m/s east; the y-component is 14.5 m/s North. (a) What is the value of the resultant vector? (b) What is the angle of the resultant vector?
Explanation:
Given that,
The x-component is 8 m/s east and y-component is 14.5 m/s North.
(a) As both x and y components are perpendicular to each other. Their resultant is given by :
[tex]R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s[/tex]
(b) Let [tex]\theta[/tex] is the resultant vector. So,
[tex]\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}[/tex]
Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.
A box of paper is labeled 24lb paper. This means that 500 sheets (counted number) of paper size 17in x 22in weighs 24 pounds (The paper industry in the US has not switched over to metric.). On earth, 1.0lb, using the standard acceleration of gravity, corresponds to 453.6g. Calculate the mass of a single piece of paper that measures 21.59cm x 27.94cm
Answer:
The mass of a single paper is approximately 0.047 lb/paper which in SI Units is approximately 21.77 g/paper
Explanation:
The given information on the size and the weight of paper are;
The mass of a box of 500 sheets of paper = 24 lb
The number of sheets in the paper = 500 sheets
The dimensions of the paper = 17 in. × 22 in., which is equivalent to 43.18 cm × 55.88 cm
The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)
The mass of a single paper = 24 lb/500 = 0.047 lb/paper
Given that 1 lb = 453.6 g, we have;
0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77 g/paper
The mass of a single paper = 0.047 lb/paper = 21.77 g/paper.
Answer:
5.349g
Explanation:
The other post forgot about the differing answer. They wanted the answer for 21.59cm*27.94cm. when they get that 0.047=43.18cm*55.88cm we can set a ratio;
0.047/43.18*55.88=X/21.59*27.94=0.01179
then we do the same;
0.01179lb(453.6g/1lb)=5.349
(*the number is bigger but we have 4 sig figs*)
In which block of the periodic table is uradium (U) found?
s block
d block
р
block
f block
Answer:
f block on edge 2020
Explanation:
hope this helps:)
why aren't two hydrogen atoms bonded together considered a compound explain.
Answer: Because a compound is formed by at least two elements, and here we have only one.
Explanation:
A compound is defined as:
"A substance that is formed when two or more elements are chemical bonded together"
And in this case, we have two hydrogen atoms bonded together, so we have the bond, but there is only one element, and we need to have at least two elements to have a compound.
Two hydrogen atoms bonded together are not considered a compound.
Compounds:A compound is formed when two are more different elements form a chemical bond with each other and make a substance.
For any substance to be categorized as a compound it is necessary that it contains at least two different elements.
A substance that is formed by the chemical combination or bonding of the atoms of the same element is not considered a compound.
In the given case we have two hydrogen atoms bonded together, which is very clear that the substance contains the atoms of the same element bonded together.
Therefore it can not be considered a compound.
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What year will y'all graduate
Answer:
I'm in college and i'm a senior so i will graduate this year.
Explanation:
what are the factor that affect the efficiency of a pulley
Answer:
Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.
Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)
Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.
Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.
Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.
Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.
Explanation:
Which is an example of heat transfer by convection?
Answer:
Boiling water - The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion. Radiator - Puts warm air out at the top and draws in cooler air at the bottom.
3. A rock has a volume of 6 cm3 and a mass of 24g. What is the density of the rock?
Explanation:
Assume that the rock has a constant density,
then the density = volume/mass = 0.25g/cm^3.
Answer:
4 g/cm^3
Explanation:
Density can be found by dividing the mass by the volume.
d=m/v
We know that the mass of the rock is 24 gram. We also know the volume of the rock is 6 cubic centimeters.
m=24 g
v= 6 cm^3
Substitute the values into the formula and divide.
d= 24 g / 6 cm^3
d= 4 g/cm^3
The density of the rock is 4 grams per cubic centimeter.
The image shows the pH value of some common substances. Which statement is true?
A-Pure water is acidic
B-Pure water is basic
C-Pure water is both acidic and basic
D-Pure water is neither acidic nor basic
Is anyone interested in a pile of bricks, it's free on craigslist?
The interest in a pile of free bricks on Craigslist varies based on the needs and preferences of individuals in the local area, and posting clear details about the quantity, condition, and pickup arrangements can attract potentially interested parties.
Craigslist is an online classified advertising platform where users can post and find a wide range of listings for various goods, services, housing, jobs, and more. It operates on a local level, allowing individuals to connect within their specific geographic regions.
Interest in a pile of bricks on Craigslist would depend on the specific needs and preferences of individuals in the local area. While some people may find value in acquiring free bricks for construction or DIY projects, others may not have any use for them. It is difficult to predict the level of interest without knowing the specific context, location, and local demand for such materials. Posting the offer on Craigslist and providing clear details about the quantity, condition, and pickup arrangements can help attract potentially interested parties.
Therefore, Interest in a free pile of bricks on Craigslist depends on local individuals' needs and preferences, and posting clear details can attract potentially interested parties.
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A brick has a mass of 562 g and a volume of 43 cm3. What is the density?
Answer:
13.069 g/cm^3
Explanation:
to get density, simply divide the mass by the volume. Your equation would look like this; p=562/43
'P' represents density in this equation. Never forget to add your units!
Hope this helps!
The diagram below shows a 1.5 kilogram kitten jumping from the top of a 1.80 meter high refrigerator to a 0.90 meter high
counter.
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.
Answer:
E = 27 J
Explanation:
It is given that,
Mass of a kitten is 1.5 kg
Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.
We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :
[tex]E=mgh[/tex]
g is acceleration due to gravity
[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]
So, the kitten's gravitational potential energy on top of the counter is 27 J.
An object is released from rest near a planet’s surface. A graph of the acceleration as a function of time for the object is shown for the 4 s after the object is released. The positive direction is considered to be upward. What is the displacement of the object after 2 s?
Answer:
the body has descended a height (4a)
Explanation:
This exercise should use the acceleration given in the graph, but unfortunately the graph is not loaded, but we can build it, using the law of universal gravitation and the fact that you indicate that the movement is near the surface of the planet
F = m a
f
orce is gravitational force
G M m / r² = m a
a = G M / r²
where G is the universal constant of gravitation, M the mass planet and r the distance from the center of the planet of radius R to the body, if we measure the height of the body from the surface of the planet (y), we can write
r = R + y
for which
a = G M/R² (1+ y/R)⁻²
if we use y«R we can expand the function in series
a = (G M /R²) (1 -2 y/R - 2 (-2-1) /2! y² / R² +…)
as the height is small we can neglect the quadratic term and in many cases even the linear term, for this exercise we will remain only constant therefore the acceleration is constant
a = G M / R²
from this moment we can use the relations of motion with constant acceleration for the exercise
a) they ask us for the position for t = 2s
y = y₀ + v₀ t - a t²
as the body is released v₀ = 0
y-y₀ = - a t²
y-y₀ = - a 2²
y-y₀ = - a 4
therefore
therefore the body has descended a height (4a) where a is the acceleration of the planet's gravity
HELP PLEASE . SCIENCE
A spaceship is flying through space at a very high velocity .The astronaut shuts the engines off the spaceship will
Answer:
The astronauts will simply have to fire the rocket engines again to keep moving. The spacecraft will keep coasting at the same speed and in the same direction. The spacecraft will slow down until it comes to a complete stop. ... Its speed will be constant except for very slow changes that are part of its orbital motion.
Explanation:
An object traveling at a constant 20m/sec in a circular path is changing its:
My answer to the question is Velocity.
Will somebody plz help
Answer:
very complex
Explanation:
The answer is D very complex
If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s. How long is the ball in free fall?
Answer:
3.06sExplanation:
If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt
v is the final velocity = 30m/s
u is the initial velocity = 0m/s (the object drops from rest)
g is the acceleration due to gravity = 9.81m/s²
time is the time taken
Substituting the given parameters into the formula;
30 = 0 + (9.81)t
30 = 9.81t
t = 30/9.81
t = 3.06secs
Hence it will take the object 3.06secs in free fall
How is a scientific theory different from a scientific law?
your alpaca is walking down the road at 4 m/s. how far does it go in 45 seconds?
Answer:
180
Explanation:
4m/s x 45s=180m
In Einstein's special theory of relativity, mass and energy are equivalent. An expression of this equivalence can be made in terms of electron volts ( units of energy) and kilograms, with one electron volt (eV) being equal to 1.78*10^ -36 kg. Using this ratio, express the mass of the heaviest mammal on earth, the blue whale, which has an average mass of 1.90*10^ 5 kg , in mega electron volts and tera electron volts
Answer:
In MeV: 10.674 × 10^(34) MeV
In TeV: 10.674 × 10^(28) TeV
Explanation:
We are given that;
1.78 × 10^(-36) kg = 1 eV
We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg
Thus, converting this mass of the blue whale to eV, we have;
(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV
Now, converting to mega electron volts;
From conversions;
1 eV = 10^(-6) MeV
Thus,
10.674 × 10^(40) eV will be;
(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV
Also, converting to Tera electron Volts;
From conversion, we know that;
1 eV = 10^(-12) TeV
Thus;
10.674 × 10^(40) eV will give;
(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV
what is base rule of rounding off
"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form. Express your answer as two numbers separated by a comma. Be careful with your signs"
Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is [tex]dT = ( -0.3, 0.8)[/tex]
Explanation:
From the question we are told that
The first displacement is [tex]dN = 0.900 \ due \ North[/tex] i.e positive y-axis
The second displacement is [tex]dW = 0.300 \ miles \ due \ west[/tex] i.e negative x-axis
The final displacement is [tex]dS = 0.100 \ miles \ due \ south[/tex] i.e negative y-axis
Generally dW in component for is
[tex]dW = (-0.3 , 0)[/tex]
Generally the total displacement of the student is mathematically represented as
[tex]dT = ( -0.3, (0.90 - 0.10))[/tex]
[tex]dT = ( -0.3, 0.8)[/tex]
Which statement is supported by the motion map?
The train traveled south and then north.
The train moved at a velocity of 75 mph north.
The train had a greater velocity when it moved away from the origin.
The train stopped for 3 seconds.
Answer:
The train stopped for 3 seconds.
Explanation:
D on edge
Convert the following measurements. Only type numbers and decimals into the answer boxes:
1. 34mm =
cm
2.234cm =
m
3.3km =
m
4.35 m =
mm
Answer:
2m 4m2Explanation:rteji3ujnrej
1. .134
2. 22.34
3. 330
4. 4350
art integration in superconductors
copper wire is the example of superconductor
Beasy is driving in his car to take care of some errands. The first errand has him
driving to a coffee shop 2 km East and 6 km North of his starting location. Once he
completes that errand, he drives to a thrift store which is 4 km East of the first errand.
What is the displacement of the car from the starting point, rounded to the nearest
km?
At this point in the story, Beasy has driven his car (2+6+4) = 12 km.
He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.
As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.
That's √(72 km²) , which works out to 8.485 km . When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".
Displacement is a vector, so to answer the question completely, we also need to state its direction.
The angle from home to the thrift store, relative to East, is arctan(6km/6km).
That's 45 degrees.
The full displacement vector is 8.485 km Northeast.
From the question, Beasy drives 2km East and 6 km North. He then drives 4 km East of the first errand. An illustrative diagram is shown in the attachment below.
From the diagram S is the starting starting point, C is coffee shop and T is the thrift store.
The displacement of the car from the starting point is giving by /TS/ in the diagram. To calculate /TS/, consider the right-angled triangle TSQ, /TS/ is the hypotenuse.
From The Pythagorean theorem, in a right-angled triangle, the square of the longest side (hypotenuse) equals sum of the squares of the other two sides.
That is,
/TS/² = /SQ/² + /TQ/²
But /TQ/ = /CP/ = 6km
and /SQ/ = /SP/ + /PQ/
/SP/ = 2 km, /PQ/ = 4 km
∴ /SQ/ = 2 km + 4 km
/SQ/ = 6 km
Hence,
/TS/² = 6² + 6²
/TS/² = 36 + 36
/TS/² = 72
/TS/ = [tex]\sqrt{72}[/tex]
/TS/ = 8.485 km
/TS/ ≅ 8 km ( to the nearest km)
Hence, the displacement of the car from the starting point rounded to the nearest km is 8 km.
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WIL GIVE BRAINLISEST PLEASE HELP SPEED ACCELERATION GRAPHS LABEL THE GRAPHS PLEASEEeeee
Answer:
Take the numbers and fill them in graph.
Plot time as X and speed as Y and afterward join then like a line graph.
A mass of gas occupies 20 cm3 at 5 degrees Celcius and 760 mm Hg pressure. What is its volume at 30 degrees Celcius and 800 mm Hg pressure?
Answer:
20.7 cm³
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 5 °C
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 30 °C
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
Initial temperature (T1) = 5 °C
Initial temperature (T1) = 5 °C + 273 = 278 K.
Final temperature (T2) = 30 °C
Final temperature (T2) = 30 °C + 273 = 303 K.
Finally, we shall determine the new volume of the gas as follow:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 278 K
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 303 K
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
P1V1/T1 = P2V2/T2
760 × 20 /278 = 800 × V2/303
Cross multiply
278 × 800 × V2 = 760 × 20 × 303
Divide both side by 278 × 800
V2 = (760 × 20 × 303) / (278 × 800)
V2 = 20.7 cm³
Therefore, the new volume of the gas is 20.7 cm³