Where is the arctic tundra biome found?

Use this website to answer the question: https://thewildclassroom.com/biomes/artictundra-2/

Question 2 options:

Almost entirely in the Northern Hemisphere, from 60 to 70 degrees latitude North.


In tropical and subtropical latitudes


In high altitudes


Within tropical and subtropical latitudes

Answer:

Explanation:

From the information given:

Mass of BiPO₄ = 0.3451 g

Number of moles of BiPO₄ = [tex]0.3451 \ g \ BiPO_4 \times \dfrac{1 \ mol \ BiPO_4}{303.95 \ g \ BiPO_4}[/tex]

[tex]= 0.001135 \ mol[/tex]

The number of moles of Bi³⁺ in 20.00 mL is:[tex]= 0.001135 \ mol \ BiPO_4 \times \dfrac{1 \ mol \ of \ Bi^{3+}}{1 \ mol \ BiPO_4}[/tex]

=  0.001135 mol of Bi³⁺

The number of moles of Bi³⁺ in 100 mL stock solution

[tex]= 0.001135 \ mol \ Bi^{3+} \times \dfrac{100 \ mL}{20.0 \ mL}[/tex]

[tex]= 0.005675 \ mol[/tex]

Mass of BSS in 4.9993 g tablets

[tex]m = 0.005675 \ mol \ Bi^{3+} \times \dfrac{1 \ mol \ BSS}{1 \ mol \Bi^{3+}} \times \dfrac{362.1 \ g \ BSS}{1 \ mol \ BSS}[/tex]

m = 2.055 g BSS

Mass of BSS in 5.0103 g (5 tables)

[tex]m = 2.055 g \ BSS \times \dfrac{5.0103 \ g}{4.9993 \ g}[/tex]

= 2.06 g

∴

The mass of BSS per tablet is [tex]=\dfrac{2.06 \ g}{5 \ tablet}[/tex]

= 0.412 g BSS/ tablet

Answer: C

Explanation:

he never had evidence in the first place that was nearly enough.

Answer:

I believe the answer is "b". "During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis."

Explanation:

I remember from last year but I'm not totally sure. Good luck!

The experimental setup has been the design that includes the experimental and the control group. during the experiment, only one variable is changed to test the hypothesis. Thus, option b is correct.

The experiment design includes the testing of the hypothesis to solve the problem and reach the solution through the analysis of the observations. It has been the setup that includes the test and the control group that involves the dependent, independent, and controlled variables.

Testing one variable in the experimental designs means changing one of the elements of the experience to prove the reliability of the hypothesis. This variable is the factor that alters and affects the other factors of the experiment and leads to a cause and effect.

The result of the effect of the hypothesis proves the testability of the experiment and provides solutions to the research question. This further leads to the formulation of the law and theory.

Therefore, option A. testing one variable involves proving the hypothesis.

Learn more about experimental design, here:

https://brainly.com/question/17280313

#SPJ6

Answer:

Its Kinetic  energy

Explanation:

You are giving the bow potential energy. "When you let the bow go, it returns to its original shape. The energy is transformed to kinetic energy and transferred to the arrow"

Answer:

potential

Explanation:

the energy is potential lol

Answer: 1. 2.7 moles  of ammonia are formed

2. 12.0 moles  of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

[tex]N_2+3H_2\rightarrow 2NH_3[/tex]

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form =[tex]\frac{2}{3}\times 4.0=2.7moles[/tex] of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by  =[tex]\frac{3}{2}\times 8.0=12.0moles[/tex] of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with =[tex]\frac{1}{3}\times 6.0=2.0moles[/tex] of nitrogen

Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

Now, how do we find the number of moles?

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

How do we work this out?

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

[tex]\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

[tex]\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

[tex]\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}[/tex]

Now, we need to simplify a little bit.

[tex]\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}[/tex]

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

[tex]\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}[/tex]

Are we done yet?

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

[tex]0.379241517 \approx 0.379[/tex]

Therefore, there are approximately 0.379 moles of Ca in the given sample.

Answer: [tex]K_{sp}=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=13.90[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]  

The equation for the ionization of magnesium phosphate is given as:

[tex]Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}[/tex]

 When the solubility of [tex]Mg_3(PO_4)_2[/tex] is S moles/liter, then the solubility of [tex]Mg^{2+}[/tex] will be 3S moles\liter and solubility of [tex]PO_4^{3-}[/tex] will be 2S moles/liter.

Thus S = 0.173 g/L or [tex]\frac{0.173g/L}{262.8g/mol}=0.00065mol/L[/tex]

[tex]K_{sp}=(3S)^3\times (2S)^2[/tex]

[tex]K_{sp}=108S^5[/tex]

[tex]K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90[/tex]

The value of Ksp and pKsp for the given reaction is 1.25 × 10⁻¹⁴ and 13.90 respectively.

Solubility product constant (Ksp) is define as the product of the solubilities of the products, present in any chemical reaction.

Given chemical reaction will be represented as:

Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄³⁻

Solubility of Mg₃(PO₄)₂ = 0.173 g/L or 0.173g/L / 262.8g/mole = 0.00065mol/L
Now for the given reaction let we consider that solubility of Mg₃(PO₄)₂ be x, solubility of Mg²⁺ be 3x and solubility of PO₄³⁻ will be 2x and equation for Ksp will be written as:
Ksp = [Mg²⁺]³[PO₄³⁻]²

Ksp = [3x]³[2x]²

Ksp = 108[x]⁵

Now we pot the solubility value of x as the solubility of Mg₃(PO₄)₂ & we get,

Ksp = 108(0.00065)⁵

Ksp = 1.25 × 10⁻¹⁴

Now we calculate the value of pKsp as:
pKsp = -log(Ksp)

pKsp = -log(1.25 × 10⁻¹⁴)

pKsp = -(-13.90) = 13.90

Hence value of pKsp is 13.90.

To know more about Ksp, visit he below link:
https://brainly.com/question/7185695

Answer:

B. equal numbers of molecules

Explanation:

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll use the molar mass of hydrogen peroxide (H₂O₂), as follows:

There are 8 moles in 272 grams of hydrogen peroxide.

Answer:

B 1650

Explanation:

Answer:

C

Explanation:

thermal energy is the another name for heat

Answer:

The balance reaction is

2Pb(NO3)2 ----》4NO2+2PbO+O2

hence the value of a,b,c,d are 2,4,2,1 respectively!

Answer:

c is correct option

according to the question.

Scientists classify organisms into three domains and six kingdoms. In Fungi kingdom are yeasts classified because they are heterotrophic. Therefore, option C is correct.

An organism is referred to be a heterotroph if it is unable to manufacture food on its own and must obtain it from other sources of organic carbon, primarily plant or animal materials.

All fungi are heterotrophic, which means they draw their energy from other living things.

Since they share some traits with fungi, such as the presence of chitin in their cell walls, extracellular digestion, saprophytic feeding, asexual reproduction by budding, and the ability to store food as glycogen, yeast cells are categorised as fungi.

Thus, option C is correct.

To learn more about the heterotrophic, follow the link;

https://brainly.com/question/11065112

#SPJ6

Answer:

The answer is C if its wrong you can report my answer I'm 100% sure its C

The statement which is  given below describe a homogeneous catalyst.

"It is in the same phase as the reactants"

The catalyst which have similar phase to the reactant of the reaction is called homogeneous catalyst.

Mostly in  homogeneous catalyst, catalyst present in liquid form.

To learn more about homogeneous catalyst here.

https://brainly.com/question/1563647

#SPJ3

Answer:

15.2 g H2

Explanation:

2H2O -> 2H2 + O2

9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2

Answer:

b

Explanation:

i know

Answer:

2

Explanation:

WO2(s) + 2H2(g) -> W(s) + 2H2O(l)

Answer:

calcium has more mass

Explanation:

1 mole calcium mass= 40.078 g

1 mole magnesium mass= 24.305 g

Answer:

Sodium (Na)

Helium

Magnesium (Mg).

Explanation:

From the periodic table, we will understand that the group 1 metals are the alkali metal. However, the period runs from left to right on the periodic table while the group runs from up to down in the periodic table. In period 3, the alkali metal present there with one valence electron in its outermost shell is sodium (Na).

The only noble gas exists in the last group, group zero of the periodic table. However, the only noble gas with two electrons in its outermost shell is called Helium

The ALkaline earth metals are group 2 metals. They are usually shiny metals and the ability to lose 2 electrons in their outermost electron shell. The alkaline earth metal located in period 3 is Magnesium (Mg).

Answer:

Explanation:

pretty sure its gaillieo

Answer:

Galileo

Explanation:

he was the first one to use a telescope

Answer:

False, it becomes colourless in acidic solutions and turns pink in basic solutions

Producers are the foundation of every food web in every ecosystem—they occupy what is called the first tropic level of the food web. The second trophic level consists of primary consumers—the herbivores, or animals that eat plants. At the top level are secondary consumers—the carnivores and omnivores who eat the primary consumers. Ultimately, decomposers break down dead organisms, returning vital nutrients to the soil, and restarting the cycle. Another name for producers is autotrophs, which means “self-nourishers.” There are two kinds of autotrophs. The most common are photoautotrophs—producers that carry out photosynthesis. Trees, grasses, and shrubs are the most important terrestrial photoautotrophs.  In most aquatic ecosystems, including lakes and oceans, algae are the most important photoautotrophs.

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Explanation:

Let's consider the molecular equation for the reaction between Ba(NO₃)₂ and Na₂SO₄. This is a double displacement reaction in which BaSO₄ forms a white precipitate.

Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)

The complete ionic equation includes all the ions and insoluble species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and insoluble species.

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Answer:

533.2 torr.

Explanation:

The following data were obtained from the question:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total pressure = 775 torr

Partial pressure of N₂ =?

Next, we shall determine the mole fraction of N₂. This can be obtained as follow:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total mole = 1.45 + 0.659 = 2.109 moles

Mole fraction of N₂ = Mole of N₂ / total mole

Mole fraction of N₂ = 1.45 / 2.109

Mole fraction of N₂ = 0.688

Gina, we shall determine the partial pressure of N₂. This can be obtained as follow:

Total pressure = 775 torr

Mole fraction of N₂ = 0.688

Partial pressure of N₂ =?

Partial pressure of N₂ = total pressure × mole fraction of N₂

Partial pressure of N₂ = 775 × 0.688

Partial pressure of N₂ = 533.2 torr.

Therefore, the partial pressure of N₂ is 533.2 torr.

Answer:

161.54 g of N₂

Explanation:

The balanced equation for the reaction is given below:

2NaN₃ —> 2Na + 3N₂

Next, we shall determine the mass of NaN₃ that decomposed and the mass of N₂ produced from the balanced equation. This is illustrated below:

Molar mass of NaN₃ = 23 + (3×14)

= 23 + 42 = 65 g/mol

Mass of NaN₃ from the balanced equation = 2 × 65 = 130 g

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass of N₂ from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

130 g of NaN₃ decomposed to produce 84 g of N₂.

Finally, we shall determine the mass of N₂ produced by the decomposition of 250 g of NaN₃. This can be obtained as follow:

From the balanced equation above,

130 g of NaN₃ decomposed to produce 84 g of N₂.

Therefore, 250 g of NaN₃ will decompose to produce

= (250 × 84)/130 = 161.54 g of N₂

Thus, 161.54 g of N₂ were obtained from the reaction.

Answer:

Learn how gifted students think. ...

Created tiered assignments for students. ...

Include a variety of levels in your classroom library. ...

Utilize their talents and interests. ...

Explore real-word application.