Answer:
B. light
Step-by-step explanation:
When specific frequencies of light are absorbed by a material, it forms an absorption spectrum.
Write a sequence of dilations and translations that maps circle D onto circle C and that shows the two circles you created are similar.
Answer: Circle d
Step-by-step explanation:
A square has a perimeter of 40 feet. Find the length of the
diagonal of the square.
Answer:
14.14
Step-by-step explanation:
Answer:
The length of the diagonal of the square is about 14.142 feet
Step-by-step explanation:
Step 1: Determine the length
[tex]P = 4(l)[/tex]
[tex]40\ ft = 4(l)[/tex]
[tex]\frac{40\ ft}{4}=\frac{4(l)}{4}[/tex]
[tex]10\ ft = l[/tex]
Step 2: Determine the diagonal length
Pythagorean theorem → [tex]a^2 + b^2 = c^2[/tex]
a and b are going to be the sides of the square which are both 10 ft so we just plug those in and solve for c
[tex](10)^2 +(10)^2 =c^2[/tex]
[tex]100+100=c^2[/tex]
[tex]\sqrt{200}=\sqrt{c^2}[/tex]
[tex]14.142=c[/tex]
Answer: The length of the diagonal of the square is about 14.142 feet
What is the probability that a person with an iron deficiency is 20 years or older?
A.
0.23
B.
0.34
C.
0.60
D.
0.78
The answer to this is:
0.34
The probability that a person with an iron deficiency is 20 years or older will be 0.34. Then the correct option is B.
What is probability?Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.
The table is given below.
Then the probability that a person with an iron deficiency is 20 years or older will be
P = 102 / 300
P = 0.34
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HELPPPPPPPPP!!!!!!!!!!!!!!!!
Which of the following functions matches this graph?
The equation that match the graph is
b. y = 3x^2
What is vertical stretch?In mathematics, a vertical stretch is a transformation of a function that changes the distance between the function's graph and the x-axis without changing its shape.
A vertical stretch multiplies all the y-coordinates of a function's graph by a constant factor greater than 1. This causes the graph to be stretched vertically and move further away from the x-axis.
For example, if we have a function f(x) = x^2, a vertical stretch by a factor of 3 would result in the function g(x) = 3x^2.
The graph of g(x) would be the same as that of f(x), but stretched vertically by a factor of 3.
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Help me with the 2 problems
Answer:
9) Vincent will not get the correct answer because the + 484 is unneccesary, as he already subtracted it.
10a) 310,000 + x = 465,000; so x = 155,000
10b) 930,000/310,000 = 3 times more
Step-by-step explanation:
find the domain and range with a vertex of (1,-2)
Answer:
see explanation
Step-by-step explanation:
the domain ( values of x ) that a quadratic can have is all real numbers
domain : - ∞ < x < ∞
the range ( values of y ) are from the vertex upwards , that is
range : y ≥ - 2
Work out 3 1/2 x 1 3/7, giving your answer in its simplest form?
let's firstly convert the mixed fractions to improper fractions and then get their product.
[tex]\stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}} ~\hfill \stackrel{mixed}{1\frac{3}{7}}\implies \cfrac{1\cdot 7+3}{7}\implies \stackrel{improper}{\cfrac{10}{7}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{2}\cdot \cfrac{10}{7}\implies \cfrac{7}{7}\cdot \cfrac{10}{2}\implies 1\cdot 5\implies 5[/tex]
Solve the equation with rational exponents
(x-1)3/2=27
[tex]~~~~~~(x-1)^{\tfrac 32} =27\\\\\implies \left[(x-1)^{\tfrac 12} \right]^3 = 3^3\\\\\implies (x-1)^{\tfrac 12} = 3~~~~~~~~~;[\text{Cube root on both sides}]\\\\\implies x -1 = 9~~~~~~~~~~~~;[\text{Square both sides}]\\\\\implies x = 10[/tex]
Simplify (3^-2)^4
O A. 1 /3^2
O B. 3^2
O c. 3^8
OD.1/3^8
[tex](3^{-2})^4 = 3^{-2 \times 4} = 3^{-8} = \dfrac 1{3^8}\\\\\text{Hence the answer is D.}[/tex]
Answer:
1/3^8
Step-by-step explanation:
[tex]\hookrightarrow (3^{-2} )^{4} \\[/tex]
As,
x⁻²=1/x²
Then,
[tex]\hookrightarrow (\frac{1}{3^{2} } )^{4} \\\\\hookrightarrow (\frac{1}{9} )^{4} \\\\\hookrightarrow ((\frac{1}{3} )^{2})^{4} \\\\\hookrightarrow (\frac{1}{3})^{8}[/tex]
Which is a statistical question that you can ask to learn about your classmates' pets?
How many students in my class have a dog for a pet?
How many pets are in each student's household?
O How many classmates have a reptile for a pet?
How many pets does Mrs. Bruckner have?
Answer:
Answer "A" is correct
Step-by-step explanation:
I got it right on edge test
if the area of a triangle is 64 and the height is 10 what is the base
Give the degree of the polynomial. 10yx^5w^4-w^3v^5-5x^11-6
10yx⁵w⁴ - w³v⁵ - 5x¹¹ - 6
Degree = biggest exponent = 11
The perimeter of a rectangular painting is 304 centimeters. If the width of the painting is 61 centimeters, what is its length?
Answer:
The width of the rectangle is 91 cm
Step-by-step explanation:
61 × 2 = 122
304 - 122 = 182
182 ÷ 2 = 91
Answer:
91 cm
Step-by-step explanation:
61 x 2 (because there are 2 sides with length 61) = 122
304 - 122 = 182
182 / 2 = 91
For which values of m is the equation always true.
Answer:
m∈(-∞;-2]∪[6;+∞).
Step-by-step explanation:
1) Δ=b²-4ac, then
m²-4(m+3)≥0; ⇔m²-4m-12≥0; ⇔ (m-6)(m+2)≥0;
2) m∈(-∝;-2]∪[6;+∝).
Based on the data in the two-way table, what is the probability that a person consumes 1,500 to 2,000 calories in a day? A. 0.22 B. 0.28 C. 0.35 D. 0.50
Using it's concept, it is found that the probability that a person consumes 1,500 to 2,000 calories in a day is given by:
D. 0.50
What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.
Researching the problem on the internet, it is found that out of 500 people, 250 consume 1,500 to 2,000 calories in a day, hence the probability is given by:
p = 250/500 = 0.5.
Which means that option D is correct.
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HELP!!! The box plots compare the speeds of cars traveling on a highway
Answer:
See below ~
Step-by-step explanation:
The statements which are true :
The interquartile range for the cars going South is 9The maximum speed for the cars going North is higher than the maximum speed for the cars going SouthThe interquartile range for the cars going North is higher than the interquartile range for the cars going Southfind the value of x. Cos(67°) = x/1
Answer:
The value of cos 67° is equal to the x- cordinate ( 0.3907 ). therefore, cos 67° = 0.3907
One number is ten more than twice another. Their sum is one. Find the numbers.
answer:
x = 4
y = -3
steps :
x = 10 + 2y
x + y = 1
2y = x - 10 -> y = 1/2x - 5
x + y = 1 -> y = 1 - x
since theyre both equal to y they are equal to each other
1/2x - 5 = 1 - x
3/2x = 6
x = 4
plug 4 back where x is
y = 1 - 4
y = -3
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Calculus, factor the given polynomial.
Answer:
x² + 10x + 21 = (x + 3)(x + 7)Step-by-step explanation:
x² + 10x + 21 = x² + (3x + 7x) + 21
= (x² + 3x) + (7x + 21)
= x(x + 3) + 7(x + 3)
= (x + 3)(x + 7)
A frame around a rectangular family portrait has a perimeter of 96 inches. The length of the frame is 6 inches less than
twice the width. Find the length and width of the frame.
Width of the frame is
inches
Length of the frame is
inches
The length is 30 inches.
How to get the length of the frame?
For a frame of length L and width W, the perimeter is:
P = 2*(L + W).
Here we know that:
P = 96 in
L = 2*W - 6in
Replacing that we get:
96in = 2*( (2*W - 6 in) + W)
Now we can solve that equation for W:
96in = 2*(3W - 6in)
96in/2 + 6in = 3W = 54in
W = (54in)/3 = 18in
The width is 18 inches, then:
L = 2*W - 6in = 2*(18 in) - 6in = 30in
The length is 30 inches.
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hi can anyone solve my math problem
Answer:
The solutions to this equation are x = -8/9 and x = -16/3.
Step-by-step explanation:
We have this equation here:
[tex]\displaystyle \frac{1}{3}|x-4|=\frac{2}{3} x+2|x+\frac{6}{3} |[/tex]First, let's simplify the right sight of the equation by simplifying 6/3 to 2.
[tex]\displaystyle \frac{1}{3}|x-4|=\frac{2}{3} x+2|x+2 |[/tex]Multiply both sides of the equation by 3 in order to get rid of the fractions.
[tex]|x-4|=2x+6|x+2|[/tex]Move the terms on either side of the equation to set them equal to 0.
[tex]|x-4|-2x-6|x+2|=0[/tex]Now, we can split this equation up into 4 possible cases. In each case, we make the absolute values negative or positive.
Case #1 (first absolute value: positive; second absolute value: positive)[tex](x-4)-2x-6(x+2)=0[/tex]Simplify this equation by distributing -6 inside the parentheses.
[tex]x-4-2x-6x-12=0[/tex]Combine like terms.
[tex]-7x-16=0[/tex]Add 16 to both sides of the equation and divide by -7.
[tex]\displaystyle \boxed{x=-\frac{16}{7}}[/tex]Case #2 (first absolute value: negative; second absolute value: positive)[tex]-(x-4)-2x-6(x+2)=0[/tex]Distribute the negative sign and -6 inside of their respective parentheses.
[tex]-x+4-2x-6x-12=0[/tex]Combine like terms.
[tex]-9x-8=0[/tex]Add 8 to both sides of the equation and divide by -9.
[tex]\displaystyle \boxed{x=-\frac{8}{9}}[/tex]Case #3 (first absolute value: positive; second absolute value: negative)[tex](x-4)-2x-6[-(x+2)]=0[/tex]Distribute the negative sign inside the parentheses first.
[tex]x-4-2x-6(-x-2)=0[/tex]Now, distribute -6 inside the parentheses.
[tex]x-4-2x+6x+12=0[/tex]Combine like terms.
[tex]5x+8=0[/tex]Subtract 8 from both sides of the equation and divide by 5.
[tex]\displaystyle \boxed{ x=-\frac{8}{5}}[/tex]Case #4 (first absolute value: negative; second absolute value: negative)[tex]-(x-4)-2x-6[-(x+2)]=0[/tex]Distribute the negative signs inside the parentheses first.
[tex]-x+4-2x-6(-x-2)=0[/tex]Distribute -6 inside the parentheses.
[tex]-x+4-2x+6x+12=0[/tex]Combine like terms.
[tex]3x+16=0[/tex]Subtract 16 from both sides of the equation and divide by 3.
[tex]\displaystyle \boxed{x=-\frac{16}{3}}[/tex]Extraneous SolutionsWhenever we solve problems with absolute values, we will always need to check for extraneous solutions.
Definition: These are solutions that may come up while solving but do not actually fit in the domain of the original problem.
Checking for these is tedious, but it will help eliminate wrong answers, so let's plug every "solution" for x that we found back into the original equation.
1) x = -16/7Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{16}{7}) -4|=\frac{2}{3} (-\frac{16}{7}) +2|(-\frac{16}{7}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{44}{21} =-\frac{20}{21}[/tex]Since this equation is NOT true, this means that x = -16/7 is NOT A SOLUTION.
2) x = -8/9Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{8}{9}) -4|=\frac{2}{3} (-\frac{8}{9}) +2|(-\frac{8}{9}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{44}{27} =\frac{44}{27}[/tex]Since this equation IS true, this means that x = -8/9 IS A SOLUTION.
3) x = -8/5Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{8}{5}) -4|=\frac{2}{3} (-\frac{8}{5}) +2|(-\frac{8}{5}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{28}{15} =-\frac{4}{15}[/tex]Since this equation is NOT true, this means that x = -8/5 is NOT A SOLUTION.
4) x = -16/3Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{16}{3}) -4|=\frac{2}{3} (-\frac{16}{3}) +2|(-\frac{16}{3}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{28}{9} =\frac{28}{9}[/tex]Since this equation IS true, this means that x = -16/3 IS A SOLUTION.
Final AnswerThe two true solutions of the double absolute value equation, shown above, are:
[tex]\displaystyle \boxed{-\frac{8}{9} } \ \ \& \ \ \boxed{-\frac{16}{3}}[/tex]Answer:
x = -16/3 or -8/9
Step-by-step explanation:
The equation can be rewritten as a piecewise linear function with two breakpoints, or three domain regions. Each breakpoint is at the value of x where the argument of the absolute value function is zero: at x=4 and x=-2.
For each absolute value, we have ...
|q| = -q for q < 0
|q| = q for q ≥ 0
Then the three parts of the domain are ...
x < -2 . . . . . . . . where |x +2| has its vertex-2 ≤ x < 4 . . . . . between the vertices4 ≤ x . . . . . . . . . where |x -4| has its vertex__
Subtracting the right side, the equation becomes ...
1/3|x -4| -2/3x -2|x +2| = 0
Then the three piecewise functions are ...
x < -2Both absolute value arguments are negated.
1/3(-(x -4)) -2/3x -2(-(x +2)) = 0
x(-1/3 -2/3 +2) +4/3 +4 = 0 . . . . . collect terms
x +5 1/3 = 0 . . . . . . . simplify
x = -5 1/3 . . . . . . . . . subtract 5 1/3. This result is in the domain
__
-2 ≤ x < 4Only the argument of |x -4| is negated.
1/3(-(x -4)) -2/3x -2(x +2) = 0
x(-1/3 -2/3 -2) +4/3 -4 = 0 . . . . collect terms
-3x -8/3 = 0 . . . . . . . simplify
-3x = 8/3 . . . . . . . add 8/3
x = -8/9 . . . . . divide by -3. This result is in the domain
__
4 ≤ xNeither absolute value function argument is negated.
1/3(x -4) -2/3x -2(x +2) = 0
x(1/3 -2/3 -2) -4/3 -4 = 0 . . . . . collect terms
-7/3x -8/3 = 0 . . . . . . . . . simplify
-7/3x = 8/3 . . . . . . . . add 8/3
x = -8/7 . . . . . . . . . divide by -7/3. This result is not in the domain.
There is no solution in this region.
__
The solutions are ...
x = -5 1/3x = -8/9Tony orders 3 copies of a book online. He pays $2 for
shipping.
Which expression represents his total cost?
Answer:
A. 3b + 2
Step-by-step explanation:
We know that Tony ordered 3 copies and the shipping costs $2, what we don't know is b.
What don't we know? The cost of the 3 copies.
So 3b (3 multiplied by the cost(?)) + (because shipping is more money so we use addition.) and we know that the shipping is $2. Therefore our expression is
3b + 2
Select the statement that describes this expression: fraction 1 over 2 x (734 − 246).
Half the sum of 734 and 246
fraction 1 over 2 the difference between 734 and 246
fraction 1 over 2 the quotient of 734 and 246
2 times the difference between 734 and 246
The graphs below have the same shape. What is the equation of the graph of g(x)?
A. g(x)=x²-2
B. g(x) = (x + 2)²
C. g(x)=(x-2)^2
D. g(x)=x^2+2
Answer:
B. g(x) = (x + 2)²
Step-by-step explanation:
We got the graph of g by translating the graph of the parent function
f(x) = x² two units to the left
Therefore the equation of the graph of g is (x + 2)²
find the greatest common factor of 21 35 70
Answer:
7
Step-by-step explanation:
21 = 3 x 7
35 = 7 x 5
70 = 2 x 5 x 7
The greatest common factor of 21, 35 and 70 is 7.
Note : -
The greatest common factor ( GCF ) of a set of numbers is the largest factor that all the numbers share.
If ( x - y ) = 2 and xy = 3 find the value of...
[tex] {x}^{3} + {y}^{3} [/tex]........
Answer: 4:7
Step-by-step explanation:
Answer:
28
Step-by-step explanation:
Given :
x - y = 2xy = 3Solving :
2 values which satisfy the given conditions are x = 3 and y = 1Evaluating the expression :
x³ + y³(3)³ + (1)³27 + 128What is the slope of the line through (-4,2) and (−4,2)
Answer:
Step-by-step explanation:
there is no slope. they have the same coordinates
i need this answer fast and as soon as possible
Find the volume of the podium in the shape of a prism.
Answer:
8640
Step-by-step explanation:
1) Volume of the lower prism:
V1 = 27*20*12 = 6480
2) Volume of the higher prism:
V2 = 9*20*12 = 2160
3) Volume of the podium: V1 + V2 = 8640
What is the area of the pizza? Explain how you know and the formulas that you used.
Answer:
90.24 in²
Step-by-step explanation:
Area of the pizza :
⇒ Area (rectangle) + Area (semicircle)
⇒ length × width + π × (radius)²
⇒ 8 x 5 + 3.14 x 4²
⇒ 40 + 3.14 × 16
⇒ 40 + 50.24
⇒ 90.24 in²
The area of a 2D form is the amount of space within its perimeter. The area of the pizza is 65.1327 in².
What is an area?The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm², m², and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
The area of the pizza = Area of semi-circle + Area of Rectangle
= (π/2)r² + (d×h)
= [(π/2)×4²] + (8×5)
= 25.1327 in² + 40 in²
= 65.1327 in²
Hence, the area of the pizza is 65.1327 in².
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