When is the kinetic energy of the ball being transformed into gravitational potential energy?

Answer:

Perpendicular to the polarization

Explanation:

In this question, we are interested in selecting the option that best complete the question.

The direction of propagation of light is perpendicular to the polarization. Polarized and unpolarized light behave in different manners.

In unpolarized light, the oscillation of the magnetic and electric occurs in all directions to the propagated light.

However, in the case of polarized light, there is a restriction of the electric field oscillation. And thus, it only oscillates in a direction which is perpendicular to the propagation light

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

F = 1.6 N

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Answer: a. Stall AOA increases, CL max increases.

Explanation:

Deploying slats or slots on an airfoil affect CL max and Stall AOA by increasing Stall AOA and also increasing CL max.

It should be noted that the coefficient of lift CL would rise through the use of slots due to increase in boundary later energy. The slots also leads to delay of stall by through increase in AOA.

Answer:

is there an equasion it gives you?

Explanation:

need a little more info.

Answer:

2 seconds

Explanation:

The time taken for the movement is 2.81 seconds.

To find the time, the given values are,

Distance = 45 meters

speed = 16 m/s.

Formula of distance,

              Distance = Speed × Time.

As we have to find the time, Formula can be rearranged as,

              Time = Distance / Speed

Substituting the given datas in the formula,

Time = 45 / 16

        = 2.81 seconds.

So, the time taken for the movement is 2.81 seconds.

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Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation:

Answer:

A

Explanation:

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s

Answer:

The work to be done is 638,761.12 J

Explanation:

Given;

mass of the car, m = 1150 kg

velocity of the car, v = 120 km/h = 33.33 m/s

Apply work energy theorem;

W = K.E

where;

W is the work done

K.E is the kinetic energy

W = ¹/₂mv²

W =  ¹/₂ (1150)(33.33)²

W = 638,761.12 J

Therefore, the work to be done is 638,761.12 J

Answer:

Open and globular

Explanation:

Answer:

3.0 x 10 and the exponent on ten is 5.

Explanation:

You are moving the decimal point over to the left 5 times, making the exponent a positive 5 and then you would put a decimal after 3. Making it 3.0 x 10, and the exponent 5.

The speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

The given parameters;

speed of the x-ray, v = 300,000 m/s

The standard form of the given number represents the scientific notation of the number.

In scientific notation the speed of the x-ray can be expressed as follows;

300,000 m/s = 3.0 x 10⁶ m/s

Thus, the speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

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Answer:

16.7m/s

Explanation:

Using v= u+ at

V = final velocity. U = initial velocity

So since the two movements are the same they will return with the same speed they went up

Then final velocity v= 0

So

0:= u +-9.8 x 1.7

U= 16.7m/s

Answer:

C- An explanation for why matter cannot be created or destroyed

Explanation:

Answer: A. A statement that matter cannot be created or destroyed.

Explanation:

Apex

Answer:

Resultant = 13km

Direction = 67.38° East of North

Explanation:

Given the following :

5km North ; 12km East

Resultant Displacement (r) :

r² = 5² + 12²

r² = 25 + 144

r² = 169

r = √169

r = 13

Direction:

Tangent = opposite / Adjacent

Tanθ = opposite / Adjacent

Opposite = 12 ; adjacent = 5

Tanθ = (12/5)

Tanθ = 2.4

θ = tan^-1(2.4)

θ = 67.38° east of north

Answer:

It will take about 1.32 seconds to travel to his location.

Explanation:

Considering the sound travels at 340 m/s, then if a person is at a distance of 450 m m from the bell, we can use the velocity formula to find the answer;

[tex]velocity=\frac{distance}{time} \\340\,\frac{m}{s} =\frac{450\,\,m}{t} \\t=\frac{450}{340} \,s\\t\approx 1.32\,\,s[/tex]

Answer:

b

Explanation:

Answer:

18.3 C

Explanation:

Answer: 55/3 °C

Explanation:

Formula:

C=5/9(F-32)

Given:

F=65

Solve:

C=5/9(F-32)

C=5/9(65-32)

C=5/9(33)

C=55/3

Answer:

charge

Explanation:

7r0I and its etc. ,"!×_/;

Answer:

[tex]V_1=2mL[/tex]

Explanation:

Hello,

In this case, considering this as a dilution problem, the first step here is to consider that the moles of tetrodotoxin remains the same and just the volumes and concentrations are modified from the initial stock (1) and the required dilution (2):

[tex]V_1M_1=V_2M_2[/tex]

Whereas V is referred to volume and M to molar concentration, in this case in mM. In such a way, solving the V1 as the volume of the 3-mM solution we obtain:

[tex]V_1=\frac{V_2M_2}{M_1} \\\\V_1=\frac{6mL*1mM}{3mM} \\\\V_1=2mL[/tex]

It means you need 2 mL of the 3-mM solution.

Best regards.

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

Given:-

To Find: Speed of it.

We know,

v = s/t

where,

Putting the values,

v = (20 m)/(4 s)

→ v = 5 m/s (Ans.)

The speed of an object will be "5 m/s".

The given values are:

Distance,

Time,

As we know, the formula:

→ [tex]Distance (d)= Speed (v)\times Time (t)[/tex]

or,

→ [tex]Speed (v) = \frac{Distance (d)}{Time (t)}[/tex]

By putting the values, we get

→                [tex]= \frac{20}{4}[/tex]

→                [tex]= 5 \ m/s[/tex]

Thus the above answer is correct.

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Answer:

240 meters

Explanation:

He is walking 2 meters per second, and there are 60 seconds per minute. There are 120 seconds in two minutes. So, 120 x 2 = 240. That's your answer!

Answer:

water displacement.

the bigger the item means more water displacement meaning bouyance

Answer:

C

Explanation:

The 15N object has more mass than the 10N object.

A 15 N object has more mass than the 10 N object due to their weight differences.

Weight is defined as the force exerted by the earth on an object on the surface of earth. The direction of this force is directed towards the center of earth. Mathematically -

W = mg

Where -

m is the mass of body

g is the acceleration due to gravity

Weight can also be written as -

W = ρVg     [ρ is density and V is volume]

Given is a person who dropped two objects from the same height. One object weighs 15 N and the other weighs 10 N.

We can write -

Weight of Object 1 [W1] = 15 N

Weight of Object 2 [W2] = 10N

We know that -

W = m x g

We can write it as -

m = W/g

Therefore -

Mass of Object 1 [M1] = 15/9.8 = 1.53 Kg

Mass of Object 2 [M2] = 10/9.8 = 1.02 Kg

Clearly -

M1 > M2

So, the 15 N object has more mass than the 10 N object.

Therefore, a 15 N object has more mass than the 10 N object due to their weight differences.

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Answer:

The wavelength of the wave is 1 m

Explanation:

Given;

mass of the string, m = 20 g = 0.02 kg

length of the string, L = 3.2 m

tension on the string, T = 2.5 N

the frequency of the wave, f = 20 Hz

The velocity of the wave is given by;

[tex]v = \sqrt\frac{T}{\mu} {}[/tex]

where;

μ is mass per unit length = 0.02 kg / 3.2 m

μ = 6.25 x 10⁻³ kg/m

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{2.5}{6.25*10^{-3}} } \\\\v = 20 \ m/s[/tex]

The wavelength of the wave is given by;

λ = v / f

λ = (20 m/s )/ (20 Hz)

λ = 1 m

Therefore, the wavelength of the wave is 1 m