The molality of the solution is obtained as 0.63 m.
What is the freezing point?The freezing point is the temperature at which the liquid is converted into solid.
We know that;
ΔT = 3.5° C
K = 1.86° C/m
i = 3
m = ?
Thus;
ΔT = K m i
m = ΔT/K i
m = 3.5° C/ 1.86° C/m * 3
m = 0.63 m
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What temperature would constitute a fever for a child? What effects on dental treatment would a fever pose?
Answer:
38
Explanation:
that I believe is correct
What do you see when the Moon is waning?
Answer:
The bright side of the moon will become less and less and will eventually be covered in complete darkness :)
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Alpha Decay
1. If an atom of Uranium-238 decays via alpha emission, what would be its daughter product? (You will need a periodic table.)
2. If an atom of Thorium -228 decayed via beta emission, what would be the daughter isotope?
Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
What are the products of Uranium-238 and Thorium -228?If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.
So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
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What's electrolysis
Answer:
electrolysis is the process by which electric current is passed through a substance to effect a chemical change
How does increasing the temperature of a liquid below the boiling point affect
the motion of the particles in the liquid?
OA. The particles move faster.
B. The motion of the particles overcomes the forces holding the
particles together.
OC. The motion of the particles strengthens the forces between the
particles.
D. The particles move slower.
Answer: A. The particles move faster
Explanation:
Increasing the temperature increases the kinetic energy of the particles, causing them to move faster.
The sugar fructose contains 40.0% C, 6.7% H, and 53.3% O by mass. A solution of 11.7 g of fructose in 325 g of ethanol has a boiling point of 78.59 °C. The boiling point of ethanol is 78.35 °C, and Kb for ethanol is 1.20 °C/m. Assuming ideal solution behavior, what is the molecular formula of fructose?
The molecular formula of fructose is C₆H₁₂O₆.
What is the molecular formula of fructose?The molecular formula is derived in the following steps:
Step 1. the molality of the solution is determined first
Molality = Change in boiling point/Kb
Molality = (78.59 - 78.35)/1.2 = 0.2 molal
Step 2. Moles of solute is determined.
Moles of solute = molality * mass of solvent (kg)
moles = 0.2 * 0.325 = 0.065
Step 3. Molar mass of fructose = mass/moles
Molar mass of fructose = 11.7/0.065 = 180 g/mol
Step 4: Mole ratio of constituent elements
Carbon = 40% * 180/12 = 6
Hydrogen = 6.7% * 180/1 = 12
Oxygen = 53.3% * 180/16 = 6
Therefore, the molecular formula of fructose is C₆H₁₂O₆.
In conclusion, the molecular formula of fructose is derived from the molality of the solution.
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determine the number of moles of H in each sample
C. The number of moles of H in 0.109 mole of N₂H₄ is 0.436 mole
D. The number of moles of H in 34 moles of C₁₀H₂₂ is 748 moles
C. How to determine the number of mole of H in 0.109 mole of N₂H₄1 mole of N₂H₄ contains 4 moles of H
Therefore,
0.109 mole of N₂H₄ will contain = 0.109 × 4 = 0.436 mole of H
D. How to determine the number of mole of H in 34 mole of C₁₀H₂₂1 mole of C₁₀H₂₂ contains 22 moles of H
Therefore,
34 mole of C₁₀H₂₂ will contain = 34 × 22 = 748 mole of H
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How many grams of N2o are formed if 0.46 mole of NH4No3 is used in the reaction
20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Balanced equation:
[tex]NH_4NO_3[/tex] → [tex]N_2O + 2H_2O[/tex].
1 mole [tex]NH_4NO_3[/tex] gives 1 mole of [tex]N_2O.[/tex]
0.46 mole of [tex]NH_4NO_3[/tex] gives [tex]\frac{ 1 mole}{ 1 mole}[/tex] x 0.46 mole [tex]N_2O[/tex].
0.46 mole [tex]N_2O[/tex] =[tex]\frac{mass}{44.013 g/mol}[/tex]
Mass= 0.46 x 44.013
Mass=20.24gram.
Hence, 20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
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How much heat would need to be removed to
cool 215.1 g of water from 25.6°C to -10.7°C?
Answer:
100 KJ
Explanation:
yep yep cool is that correct
Calculate the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L.
The molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
How to calculate molecular mass?The molecular mass can be calculated by first calculating the number of moles using the following formula:
PV = nRT
Where;
P = pressureV = volumen = no of molesR = gas law constantT = temperature1.112 × 0.7 = n × 0.0821 × 300
0.7784 = 24.63n
n = 0.032mol
molecular mass = 2.66g ÷ 0.032mol
molecular mass = 84.16g/mol
Therefore, the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
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Behavior can best be defined as
A.
the response of an organism to its environment.
B.
the physical characteristics of a species.
C.
a sudden change in an organism's habitat.
D.
the geographic range of a species.
Help pls !!!
From first step to eighth, options are on the right !
Wastewater can be treated using series of eight steps which would be clarified below.
What are the steps of wastewater treatment?Wastewater is the type of water that is used for four different purposes in homes,offices, industries and factories.
These wastewater contain human waste, food scraps, oils, soaps and chemicals which can be treated and reused through the following means:
First Step: headworks, remove big objects.Second step: separate tiny solid particles and oil out of the water by settling (primary treatment).Third step: Pump up the water to secondary treatment level.Fourth step: Let solids settle and oil float again and let bacteria do de-nitrification without blowing any air (secondary treatment).Fifth step: Blow pure oxygen through the water and let bacteria eat the waste. Also let the bacteria perform de-nitrification (secondary de-nitrification).Sixth step: Filtration, disinfection, reverse osmosis filtration (tertiary treatment).Seventh step: send 6% of the water away from the tertiary treatment.Eight step: drop most of the water through a 5 mile pipe 200 feet deep into the ocean.Learn more about water treatment here:
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Calculate the mass of water produced by metabolism 84.0 g of glucose
The amount of water that will be produced is 50.36 grams
Stoichiometric problemsThe metabolism of glucose is represented by the following equation:
[tex]C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)[/tex]
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
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Based on the electron configuration of the two
atoms, predict the ratio of metal cationic (+) atom
to nonmetal anionic (-) atom in the compound.
1s²2s²2p63s²
1s²2s²2p63s²3p4
A. 1:1-
C. 2:1
Magnesium
Sulfur
B. 1:2
D. 3:1
Based on the electron configuration of the two atoms predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound hence the ratio is 1:1.
What does the octet rule say?The Octet Rule states that the atoms of the elements bond to each other in an attempt to complete their valence shell (the last shell of the electrosphere).
Basically, they obey the octet rule which states that the capacity of atoms (e.g. here Magnesium and Sulfur) to prefer to have 8 (eight) electrons (e-) in their respective valence shells. In this case, Magnesium is Mg (+2) and Sulfur is (-2) hence the ratio is 1:1.
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When aqueous solutions of calcium bromide and potassium carbonate are combined, solid calcium carbonate and a solution of potassium bromide are formed. The net ionic equation for this reaction is:
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)
(screen shot is attached ) please help
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
What is an ionic equation?An ionic equation is a synthetic equation where electrolytes are composed as separated particles.
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.
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Calculate the relative rate of diffusion of 1H2 (molar mass 2.0 g/mol) compared with 2H2 (molar mass 4.0 g/ mol) and the relative rate of diffusion of O2 (molar mass 32 g/mol) compared with O3 (molar mass 48 g/mol).
The ratio of diffusion rates of ¹H₂ to ²H₂ is 1.4 while the ratio of diffusion rates of O₂ to O₃ is 1.2.
What is Graham's law?Graham’s law states can be described as the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight of the gas.
According to this Law, molecules with lower molecular mass will diffuse faster than those with higher molecular mass molecules at constant pressure and temperature.
The mathematical formula is utilized to compare the rates of diffusion of two different gases at pressures and temperatures.
[tex]{\displaystyle \frac{R_1}{R_2} =\sqrt{\frac{M_2}{M_1} }[/tex]
Where M₁ and M₂ represent the molar mass of gas 1 and gas 2.
Given, the molar mass of ¹H₂ = 2.0 g/mol
The molar mass of to ²H₂ = 4.0 g/mol
The ratio of the rate of diffusion of ¹H₂ to ²H₂:
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{M_{^2H_2}}{M_{^1H_2}} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{4}{2} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =1.4[/tex]
Given, the molar mass of O₂ = 32.0 g/mol
The molar mass of to O₃ = 48.0 g/mol
The ratio of the rate of diffusion of O₂ to O₃:
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{M_{O_3}}{M_{O_2}} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{48}{32} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =1.2[/tex]
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How many grams of Al are needed to react with 63.0 g of FeO
The amount of Al required will be 15.77 grams
Stoichiometric problemFirst, the equation of the reaction:
[tex]2Al +3 FeO -- > Al_2O_3 + 3Fe[/tex]
The mole ratio is 2:3.
Mole of 63.0 g of FeO = 63/71.84 = 0.8769 moles
Equivalent moles of Al = 0.8769 x 2/3 = 0.5846 moles
Mass of 0.5846 moles Al = 0.5846 x 26.98 = 15.77 grams
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Taking into account the reaction stoichiometry, 13.28 grams of Al is required to react with 63 grams of FeO.
Reaction stoichiometryIn first place, the balanced reaction is:
2 Al + 3 FeO → 3 Fe + Al₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Al: 2 molesFeO: 3 molesFe: 3 molesAl₂O₃ : 1 moleThe molar mass of the compounds is:
Al: 27 g/moleFeO: 71.85 g/moleFe: 55.85 g/moleAl₂O₃ : 102 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Al: 2 moles ×27 g/mole= 54 gramsFeO: 3 moles ×71.85 g/mole= 215.55 gramsFe: 3 moles ×55.85 g/mole= 167.55 gramsAl₂O₃ : 1 mole ×102 g/mole= 102 gramsMass of Al requiredThe following rule of three can be applied: If by reaction stoichiometry 215.55 grams of FeO react with 54 grams of Al, 53 grams of FeO react with how much mass of Al?
[tex]mass of Al= \frac{53 grams of FeOx54 grams of Al}{215.55 grams of FeO}[/tex]
mass of Al= 13.28 grams
Finally, 13.28 grams of Al is required to react with 63 grams of FeO.
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57.A cofactor is a(an)
a. catalyst for chemical reactions in a living system.
b. protein molecule whose primary function is transport of insoluble molecules in the
bloodstream.
C.
d.
e.
molecule that is acted on by a catalyst.
biological molecule used for storage of energy.
organic or inorganic molecule or ion necessary for proper functioning of some
biological catalysts.
A cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts (option E).
What is a cofactor?A cofactor in biochemistry is a molecule that binds to and regulates the activity of a protein.
A cofactor is a metal or coenzyme responsible for the functioning of an enzyme and must be present.
Therefore, a cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts.
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A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.00 atm.
Considering the combined law, the volume of the sample is 81.639 L at 423 K and 1.00 atm.
Charles's lawCharles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law states:
[tex]\frac{V}{T}=k[/tex]
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law is expressed as:
P×V= k
Gay-Lussac's lawGay-Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant. This law says that the pressure of a gas is directly proportional to its temperature: if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.
Mathematically, Gay-Lussac's law states:
[tex]\frac{P}{T}=k[/tex]
Combined law equationCombined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{VxP}{T}=k[/tex]
Considering an initial state 1 and a final state 2, it is fulfilled:
[tex]\frac{V1xP1}{T1}=\frac{V2xP2}{T2}[/tex]
Volume of the sampleIn this case, you know:
V1= 57.9 LP1= 1 atmT1= 300 KV2= ?P2= 1 atmT2= 423 KReplacing in combined law equation:
[tex]\frac{57.9 Lx1 atm}{300 K}=\frac{V2x1 atm}{423 K}[/tex]
Solving:
[tex]V2= \frac{423 K}{1 atm} \frac{57.9 Lx1 atm}{300 K}[/tex]
V2= 81.639 L
Finally, the volume of the sample is 81.639 L at 423 K and 1.00 atm.
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Find the pH of 0.0025M sodium benzoate
the roof of a building is 0.2km^2. during a rainstorm, 5.5 cm of rain was measured to be sitting on the roof. what is the mass in kg of the water on the roof after the rainstorm? (density of rainwater = 1g/ml)
The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
What is the mass in kg of the water on the roof after the rainstorm?Generally, the equation for the Area of the roof is mathematically given as
[tex]A=0.20 \times 10^{10} \mathrm{~cm}^{2}[/tex]
height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density
[tex]&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}[/tex]
In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
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which of the three minerals contain calcium carbonate?
A. salt
B. chalk
C. talcum
Answer:
Answer choices A, B, and C all contain a certain level (or amount, if you will) of Calcium Carbonate, but B. chalk contains the most amount out of all three.
Explanation:
I hope that this was helpful! (✿◠‿◠)
Thank you!
Place the stages of a high-mass star's life cycle in the correct order, from a star's birth to its death.
supergiant
neutron star
protostar
nebula
supernova
Whether a living or non-living object, everyone has a particular life cycle. It starts right from the birth and ends upon the death of that object. Just like others, stars also have their own life cycle and that has different stages.
Nebula ⇒ Protostar ⇒ Supergiant ⇒ Supernova ⇒ Neutron Star
What is the life cycle of a high-mass star?In the initial stage, a star is in the form of a nebula. At this stage, it is a huge cloud of gas and dust. The changes occur in the star and the final size totally depends upon the size of that star.
In a massive star, the fuel is used very quickly because of its life span of a few hundred thousand years. The second stage is the Protostar.
The next stage is the Supergiant. At this stage, the nuclear reactions that occur because of the hydrogen will gradually run out and the star will enter the final phase of its life span. The bigger star will have more massiveness.
Following this, the star will enter the next stage, i.e., supernova, and after that, neutron star. In a supernova, the star will have a very energetic and violent end. In the last stage, when the dust particles clear, a neutron star will be visible.
For better understanding, an image is attached at the end.
Thus, the life cycle of a high-mass star is arranged from its birth to its death.
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The stages of a high-mass star's life cycle in the correct order, from a star's birth to its death are-
Nebula
Protostar
Supergiant
Supernova
Neutron star
The life cycle of a high-mass star begins with a nebula, a cloud of gas and dust in space. As gravity pulls the nebula together, it forms a protostar—a young, hot, and dense object. The protostar continues to gather mass and becomes a main-sequence star, burning hydrogen in its core.
Once the hydrogen is exhausted, the star expands into a supergiant and starts fusing helium into heavier elements. Eventually, it undergoes a supernova explosion, releasing an enormous amount of energy and leaving behind a dense core known as a neutron star. This process showcases the incredible transformations that high-mass stars undergo throughout their life cycle.
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What is technology ?
Answer:
Technology is the application of scientific knowledge for practical purposes especially in industry.
which of these is/are conserved during a chemical reaction ?
a)Mass only
b) Charge only
c)both mass and charge
d)neither
Answer:
C- both!
Explanation:
In a chemical reaction, the total mass and total charge has to be balanced on both sides of the "equation", therefore both are conserved
differenciate between adsorption and absorption.
[tex] \\ [/tex]
ty! ~
Answer:
Adsorption is the adhesion of atoms, ions or molecules from a gas, liquid or dissolved solid to a surface. This process creates a film of the adsorbate on the surface of the adsorbent. This process differs from absorption, in which a fluid is dissolved by or permeates a liquid or solid.
while ,
Absorption is a physical or chemical phenomenon or a process in which atoms, molecules or ions enter some bulk phase – liquid or solid material. This is a different process from adsorption, since molecules undergoing absorption are taken up by the volume, not by the surface
[tex] \\ [/tex]
-,-
How many molecules are in 84.7 grams?
The number of molecules will depend on the molar mass of the compound.
Number of moleculesAccording to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex].
To find the number of moles in a substance:
Mole = mass/molar mass.
In this case, we do not know the compound but we know the mass. Hence, we cannot know the molar mass.
Assuming the molar mass is X.
Mole = 84.7/X
Number of molecules in 84.7 grams of the compound =
84.7/X x 6.022 x [tex]10^{23}[/tex] molecules.
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What volume in milliliters of 0.0150 M Ba(OH)2 is required to neutralize 50.0 mL of 0.0500 M HBr?
The volume of [tex]Ba(OH)_2[/tex] required will be 83.33 mL
Stoichiometric reactionsThe equation of the reaction is as follows:
[tex]Ba(OH)_2 + 2HBr --- > 2H_2O + BaBr_2[/tex]
Mole ratio of reactants = 1:2
Mole of 50 mL, 0.05 M HBr = 0.05 x 0.05 = 0.0025 moles
Equivalent mole of [tex]Ba(OH)_2[/tex] = 0.0025/2 = 0.00125 moles
Volume of 0.015 M, 0.00125 moles [tex]Ba(OH)_2[/tex] = 0.00125/0.015 = 0.0833 L
0.0833 L = 83.33 mL
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The compound HBr can be decomposed to form H2 and Br2. This can be represented at the atomic level by a chemical equation:
2HBr H2 + Br2
According to the law of conservation of mass, if 29.5 grams of HBr decomposes and 0.4 grams of H2 is formed, how many grams of Br2 must simultaneously be formed?
The law of conservation of mass say that, in a chemical reaction, the mass of the reagents will always be equal to the mass of the products.
If we have 29.5 g of HBr, we must have 100 g of H2 and Br2 together, so:
29.5 = 0.4 + Br2Br2 = 29.1 gHi, Can someone help me with this question, please! It's due tonight!
Given the balanced equation:
3 CO + 7 H2 C3H8 + 3 H2O,
how much C3H8 will be produced if 45.8 g CO reacts with 87.3 g H2?
Answer:
24.0 g C₃H₈
Explanation:
To find the mass of C₃H₈, you need to (1) convert grams CO/H₂ to moles CO/H₂ (via molar mass), then (2) convert moles CO/H₂ to moles C₃H₈ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C₃H₈ to grams C₃H₈ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs in the given values.
Molar Mass (CO): 12.011 g/mol + 15.998 g/mol
Molar Mass (CO): 28.009 g/mol
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (C₃H₈): 3(12.011 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.097 g/mol
3 CO + 7 H₂ ----> 1 C₃H₈ + 3 H₂O
^ ^ ^
45.8 g CO 1 mole 1 mole C₃H₈ 44.097 g
----------------- x ------------------ x -------------------- x ------------------ =
28.009 g 3 moles CO 1 mole
= 24.0 g C₃H₈
87.3 g H₂ 1 mole 1 mole C₃H₈ 44.097 g
---------------- x --------------- x --------------------- x ----------------- =
2.016 g 7 moles H₂ 1 mole
= 273 g C₃H₈
It was necessary to find the mass of the products from both of the reactants because you did not know which one was the limiting reagent. The limiting reagent is the reactant which is completely used up first. Because CO produced the smaller amount of product, it must be the limiting reagent. Therefore, the actual amount of C₃H₈ produced is 24.0 grams.