What’s the volume of this? pls do step by step cus it’s for my homework and I have to show work

The median, mode and range for both dot plots are:

The median

This is the middle value

From the dot plots, we have the middle values to be

Group A = (7 + 8)/2 = 7.5

Group B = 5

So, we have

Median Group A = 7.5

Median Group B = 5

The mode

This is the number of books with the highest dots

From the dot plots, we have the modal values to be

Mode Group A = 7 and 8

Mode Group B = 4 and 5

The range

This is the difference between the smallest and highest number of books with the highest dots

From the dot plots, we have the range to be

Group A = 9 - 6 = 3

Group B = 10 - 3 = 7

So, we have

Range Group A = 3

Range Group B = 7

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Answer:

4 cannot be written as a logarithm with a base of 4. A logarithm is an exponent that tells us how many times we need to multiply a base by itself to get a certain number. For example, log2(8) = 3 because 2^3 = 8. We can write this as an equation: logb(x) = y means b^y = x.

-4 cannot be written as a logarithm with a base of 4 because there is no exponent that can make 4 equal to -4. In other words, there is no y such that 4^y = -4. This is because any positive number raised to any power will always be positive. Therefore, log4(-4) is undefined or does not exist.

Therefore, -4 cannot be written as a logarithm with a base of 4.

Step-by-step explanation:

Answer:

a) The scale factor is [tex]\frac{4}{5}[/tex]

b) [tex]t=5\frac{3}{5}[/tex]

Step-by-step explanation:

The scale factor from shape A to shape B is the value that is multiplied by the side measures of shape A to arrive at the side measures of shape B.

In other words, 5 times a certain value is 4, 15 times a certain value is 12. and 7 times a certain value is t.

Let's start by calling our "certain value" k.

[tex]5k=4=\\k=\frac{4}{5}[/tex]

Let's check 15 to make sure k is 4/5, like so:

[tex]15(\frac{4}{5})=\\\frac{60}{5} =\\12[/tex]

Since 15 times 4/5 is twelve, our initial answer was correct.

So, the scale factor, or k, is 4/5.

Following this logic, we know that 7 multiplied by the scale factor is equal to t.

Let's set up an equation and solve for t:

[tex]7(\frac{4}{5} )=t=\\\frac{28}{5} =t=\\5\frac{3}{5} =t[/tex]

So, [tex]t=5\frac{3}{5}[/tex]

The distance from the center are equal,

x = 6

The value of x is solved using the relationship existing between chords and the bisectors.

It will be noted that the line from the center

In the figure, since the chords are equal and the line from the center are perpendicular bisectors then the line from the center are equal.

we can therefore say that x = 6

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Answer:

dependent

Step-by-step explanation:

its dependent because the names getting pulled depends on the names pulled first

The surface area of the cylinder is approximately 3015.93square inches when rounded to the nearest hundredth.

To find the surface area of a cylinder, we need to add the areas of the top and bottom circles, and the area of the lateral surface, which is the curved part of the cylinder.

The formula for the surface area of a cylinder is:

S.A. = 2πr² + 2πrh

where r is the radius of the cylinder, h is the height, and π is approximately equal to 3.14.

Given that the diameter is 32 inches, we can find the radius by dividing by 2:

r = d/2 = 32/2 = 16 inches

Now we can substitute the values into the formula and simplify:

S.A. = 2πr² + 2πrh

S.A. = 2π(16)² + 2π(16)(14)

S.A. = 2π(256) + 2π(224)

S.A. = 512π + 448π

S.A. = 960π

To approximate the answer to the nearest hundredth, we can use the value of π rounded to two decimal places (3.14):

S.A. ≈ 960(3.14)

S.A. ≈ 3015.93 square inches

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The surface area of the cylinder figure is derived to be equal to 3014.40 square inches rounded to the nearest hundredth.

The surface area of a cylinder can be calculated using the formula:

Surface Area = 2πr² + 2πrh

Where r is the radius of the base of the cylinder, h is the height of the cylinder, and π (pi) is a mathematical constant approximately equal to 3.14159.

From the figure we have that:

r = 16 in

h = 14 in

surface area = 2 × 3.14 × 16 in × 16 in + 2 × 3.14 × 16 in × 14 in

surface area = 1607.68 in² + 1406.72 in²

surface area = 3014.40 in²

Therefore, the surface area of the cylinder figure is derived to be equal to 3014.40 square inches rounded to the nearest hundredth.

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Given:

[tex]\vec F_{1} =27 \ N[/tex]

[tex]\vec F_{2} =24 \ N[/tex]

[tex]\vec a_{1} = 9 \ m/s^2[/tex]

Find:

[tex]\vec a_{2} = ?? \ m/s^2[/tex]

We know that [tex]\vec F= m \vec a[/tex]. Use [tex]\vec F_{1}[/tex] and [tex]\vec a_{1}[/tex] to find mass, m.

[tex]\Longrightarrow \vec F_{1} = m \vec a_{1} \Longrightarrow 27= m(9) \Longrightarrow m= \frac{27}{9} \Longrightarrow m= \boxed{ 3 \ kg }[/tex]

We now know the mass of the moving object we can now find [tex]\vec a_{2}[/tex].

[tex]\Longrightarrow \vec F_{2} = m \vec a_{2} \Longrightarrow 24= (3) \vec a_{2} \Longrightarrow \vec a_{2}= \frac{24}{3} \Longrightarrow \vec a_{2}= \boxed{ 8 \ m/s^2 } \ \therefore \ Sol.[/tex]

A function's codomain is a subset of its range. Although it is not a true subset, it is conceivable for the range to be equal to the codomain, in which case it is also a subset of the codomain.

A set that includes all or a portion of another set's elements is known as a subset. For instance, because every even integer is also an integer, the set of even integers is a subset of the set of integers. A subset that contains some, but not all, of the members of another set is said to be a proper subset. Because it contains some, but not all, of the positive integers, the set of positive integers less than 10 is a valid subset of the set of positive integers.

A function's codomain is a subset of its range. Although it is not a true subset, it is conceivable for the range to be equal to the codomain, in which case it is also a subset of the codomain.

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Answer: 2

Step-by-step explanation:

Answer:

2 lines of symmetry.

The horizontal component of the force is approximately 80.34 N, and the vertical component of the force is approximately 74.62 N.

The force can be broken down into its horizontal and vertical components using trigonometry.

Horizontal component:

cos(42) = adjacent/hypotenuse

adjacent = cos(42) * 110 N

adjacent ≈ 80.34 N

Vertical component:

sin(42) = opposite/hypotenuse

opposite = sin(42) * 110 N

opposite ≈ 74.62 N

Therefore, the horizontal component of the force is approximately 80.34 N, and the vertical component of the force is approximately 74.62 N.

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Because it gives exactly one output value for each input value, a(x) is a function, hence the answer is yes. Since several input values might result in the same output value, it is not a one-to-one function.

A mathematical item called a function accepts an input and creates an output. It looks like an apparatus with an input and an output. A formula or a graph can both be used to express a function. For instance, the function f(x) = x² returns the square of an input x as output.

Because it gives exactly one output value for each input value, a(x) is a function, hence the answer is yes. Since several input values might result in the same output value, it is not a one-to-one function. A(x) is not one-to-one, for instance, because a(1) and a(3) are both equal to 1.

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Answer:

13

Step-by-step explanation:

By counting the amount of dots there is on the graph you would end up with 13 trees.

The measure of arc angle QT is determined as 142 ⁰.

The measure of m∠STR is determined as 23⁰.

The measure of angle subtended by the arc QT is calculated by applying the following formula.

Based on the angle of intersecting chord theorem, we will have the following equation.

m∠QST = ¹/₂( arc QT )

arc QT = 2 (m∠QST)

arc QT = 2 x 71⁰

arc QT = 142⁰

m∠STR = ¹/₂( arc SR )

m∠STR = ¹/₂ x 46⁰

m∠STR = 23⁰

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How many construction sites has each of the current Mohawk Skywalkers worked on in their lifetime? is a statistical question about the Mohawk Skywalkers. Option A.

A statistical question is a question that can be answered by collecting and analyzing data. It involves variability and asks about the distribution of a population, rather than just a single value or specific instance.

Option A is a statistical question because it asks about the variability of the number of construction sites each of the current Mohawk Skywalkers worked on in their lifetime.

Option B is also a statistical question as it asks about the distribution of New York City skyscrapers built with the help of Mohawk Skywalkers.

Option C is not a statistical question because it asks for a specific value, the number of generations of the Martin family who have worked as Mohawk Skywalkers, which does not involve variability or a population.

Option D is not a statistical question as it asks for a specific value, the number of Mohawk Skywalkers who helped build the Empire State Building, which does not involve variability or a population.

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The journal entry to record the sale of the equipment would be:Cash $105,800,Loss on Sale of Equipment $35,650,Equipment $212,000

Accumulated Depreciation $66,000

How to solve the question?

a. To calculate the book value of the equipment at December 31 of the fifth year, we need to determine the accumulated depreciation for the first five years. The annual depreciation expense is calculated as follows:

Depreciation Expense = (Cost - Residual Value) / Useful Life

Depreciation Expense = ($212,000 - $14,000) / 15

Depreciation Expense = $13,200 per year

The accumulated depreciation for five years is therefore:

Accumulated Depreciation = Depreciation Expense x Number of Years

Accumulated Depreciation = $13,200 x 5

Accumulated Depreciation = $66,000

The book value of the equipment at December 31 of the fifth year is calculated as follows:

Book Value = Cost - Accumulated Depreciation

Book Value = $212,000 - $66,000

Book Value = $146,000

b.

To record depreciation for the three months until the sale date, we need to calculate the depreciation expense for the sixth year. The annual depreciation expense remains the same at $13,200, but since the equipment was sold on April 1, we need to prorate the depreciation for the first three months of the year.

Depreciation Expense for the Sixth Year = Depreciation Expense x (Months Remaining / 12)

Depreciation Expense for the Sixth Year = $13,200 x (9 / 12)

Depreciation Expense for the Sixth Year = $9,900

The journal entry to record depreciation for the three months until the sale date would be:

Depreciation Expense $9,900

Accumulated Depreciation $9,900

To record the sale of the equipment, we need to compare the sale price to the book value of the equipment at the time of the sale.

The book value of the equipment at the time of the sale is calculated as follows:

Book Value = Cost - Accumulated Depreciation

Book Value = $212,000 - ($13,200 x 5.25)

Book Value = $141,450

Since the sale price of $105,800 is less than the book value of $141,450, we need to record a loss on the sale of the equipment. The journal entry to record the sale of the equipment would be:

Cash $105,800

Loss on Sale of Equipment $35,650

Equipment $212,000

Accumulated Depreciation $66,000

The cash received from the sale is debited, and the difference between the sale price and the book value is recorded as a loss on the sale of the equipment. The equipment and its accumulated depreciation are removed from the books.

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The calculated value of sec^-1(1.4) is 44.41 degrees

The inverse secant function, denoted as sec^-1(x), returns the angle whose secant is x.

In other words, if secθ = x, then sec^-1(x) = θ.

To find the value of sec^-1(1.4), we need to find the angle whose secant is 1.4.

However, we know that the range of the secant function is [-∞, -1] ∪ [1, ∞], which means that sec^-1(x) is only defined for values of x that fall within this range.

Uisng a graphint tool, we have

sec^-1(1.4) = 44.41

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The confidence interval can be expressed as a trilinear inequality: 82.9% < p < 95.7%.

The confidence interval in interval form is (0.1864, 0.3026).

The given confidence interval, 89.3% ± 6.4%, means that we are 89.3% confident that the true value of the population parameter lies within a range of 6.4% above and below the sample estimate.

To express this in the form of a trilinear inequality, first find the upper and lower bounds of the interval.

Upper bound = 89.3% + 6.4% = 95.7%

Lower bound = 89.3% - 6.4% = 82.9%

Therefore, the confidence interval 89.3% ± 6.4% can be expressed in the form of a trilinear inequality as:

82.9% < p < 95.7%

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As a result, a = 7 + (n - 1) * 15 is the formula for the nth term of the series with first term 7 and common difference.

An ordered set of number with a pattern or rule regulating their values is referred to as a sequence in mathematics. A word is used to characterize each number in a sequence. There are many various kinds of sequences, but a few of the most popular ones are as follows: A common differential, or constant number, is added to the respective period to produce an arithmetic series, each term of which is obtained. One arithmetic series with a following differences of three is 1, 4, 7, 10, 13, etc.

given

Given an arithmetic series with a first term (a1) and a common difference (d), the formula for the nth term (an) is as follows:

[tex]a = a1 + (n - 1) * d[/tex]

In this instance, the common difference (d) is 15, and the first term (a1) is 7. When these values are added to the formula, we obtain:

[tex]a = 7 + (n - 1) * 15[/tex]

As a result, a = 7 + (n - 1) * 15 is the formula for the nth term of the series with first term 7 and common difference.

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Answer:

4. b/c

Step-by-step explanation:

In a right-angled triangle with sides of lengths a, b, and c, where c is the hypotenuse (the side opposite the right angle), the sine of the angle opposite side b (angle B) is given by:

Sin theta : Opposite/hypotenuse

sin(B) = b/c

Therefore, the answer is 4. b/c

The correct statement is option a) The height of the terrain can measure between 2 meters and 10 meters.

Let the base of the triangular piece of land be x meters. Then, the height of the triangular plot is (x+2) meters.

The area of a triangle is given by the formula: A = (1/2)bh, where b is the base and h is the height.

Substituting the given values:

A = (1/2)x(x+2)

Simplifying:

A = (1/2)(x² + 2x)

Since the area is less than 40 m², write:

(1/2)(x² + 2x) < 40

Multiplying both sides by 2:

x² + 2x < 80

Rearranging and factorizing:

x² + 2x - 80 < 0

(x+10)(x-8) < 0

The roots of the quadratic equation are -10 and 8. Since the coefficient of x² is positive, the parabola opens upwards and is negative in between the roots. Therefore, the inequality is true when -10 < x < 8.

However, x cannot be negative, so the base of the triangular terrain is between 0 and 8 meters.

Substituting the values in the expression for the height, the height is between 2 and 10 meters.

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The eight letters in the word DECEIVED may be arranged in 4200 distinct ways, with two Ds grouped together and three Es not all together.

The following approach may be used to determine how many different ways there are for the eight letters in the word DECEIVED to be arranged such that two Ds are together and three Es are not altogether:

7! - 6! - 5! = 5040 - 720 - 120 = 4200

Therefore, there are 4200 different arrangements of the 8 letters in the word DECEIVED, in which two Ds are together and the three Es are not all together.

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As per the question of trigonometry the another equation that describes the given graph is

y = -cos5x. And after verifying the equation given in the question as well as the new equation we conclude that both equations are equal.

The sine and cosine function graphs' main characteristics are:  

a. We can use trigonometric identities to simplify the given equation in order to describe the graph using a different equation.

b. We can simplify the following equation and compare it with  [tex]y = -cos(5x)[/tex]to see if the two equations are equivalent.

We obtain this by applying the same trigonometric identity as before.

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Answer:

C.

Step-by-step explanation:

because x value cannot be repeated in an ordered pair

The number of subsets that the set has are 128 subsets.

First, let's remove the duplicates from the set A. The distinct elements in set A are:

A = {a, r, i, t, m, e, c}

Now, we can find the number of subsets. For each element in the set, we have two choices: either it is included in the subset, or it is not. Therefore, there are 2^n subsets for a set with n distinct elements.

In our case, n = 7, so there are 2^7 = 128 subsets for the given set A.

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The field's length is therefore three times its breadth, or 3(50), or 150 yards, and its width is 50 yards.

A this double shape's perimeter is the space encircling its outside edge. It is the length of the object's sides. As an illustration, the perimeter of a rectangle is equivalent to the total of its four sides' lengths.

given

Assume that the rectangular field has a width of "x" yards.

The problem states that the field's length is three times its breadth, or three times yards.

The lengths of all the sides make up the rectangle's perimeter, therefore we can write:

[tex]Perimeter = 2 (length + width).[/tex]

In place of the values we hold:

[tex]400 = 2(3x + x)\\400 = 2(4x) (4x)\\400 = 8x\\x = 50[/tex]

The field's length is therefore three times its breadth, or 3(50), or 150 yards, and its width is 50 yards.

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The correct equation to use is "s - 2.3 = 6.8", where s represents the distance Sam ran.

Distance is a measurement of how far apart two objects or points are from each other. It is usually measured in units such as meters, kilometers, miles, or feet. Distance can refer to physical space between two points, or it can be used to describe the extent of an abstract concept, such as a difference in opinion or a cultural divide.

The Situation column should have two entries: "finding part of a total" and "difference".

The Operation column should have only one entry: "minus".

The right formula is "s - 2.3 = 6.8", where s stands for the distance Sam ran.

To solve for s, we can add 2.3 to both sides of the equation:

s - 2.3 + 2.3 = 6.8 + 2.3

s = 9.1

Therefore, Sam ran 9.1 kilometers.

So, the Situation entries are: "difference" and "finding part of a total".

The Operation entry is: "minus".

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The distance traveled by the wheel when it turns 20 times is 150.7964 feet.

What is circumference?

The circumference of a wheel can be calculated as:

Circumference = 2 x π x radius

where π (pi) is a mathematical constant approximately equal to 3.14159.

The distance traveled by a wheel when it turns is equal to the circumference of the wheel multiplied by the number of times it turns.

Given that the radius of the wheel is 1.2 feet, the circumference of the wheel is:

Circumference = 2 x π x radius

Circumference = 2 x 3.14159 x 1.2

Circumference = 7.53982 feet (rounded to 5 decimal places)

Therefore, each time the wheel turns, it travels a distance of 7.53982 feet. To find the distance traveled when the wheel turns 20 times, we can multiply the distance traveled each time by the number of times the wheel turns:

Distance traveled = Circumference x Number of turns

Distance traveled = 7.53982 feet x 20

Distance traveled = 150.7964 feet (rounded to 4 decimal places)

Therefore, the distance traveled by the wheel when it turns 20 times is 150.7964 feet.

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A quadratic equation with opposite solutions can be found by multiplying a variable by its negative value. Specifically, if we start with a quadratic equation of the form:

ax^2 + bx + c = 0

We can find an equation with opposite solutions by multiplying either a or c by -1. For example, if we multiply c by -1, we get:

ax^2 + bx - c = 0

This equation will have opposite solutions if the discriminant, b^2 - 4ac, is negative. This is because the solutions of a quadratic equation are given by the formula:

x = (-b ± sqrt(b^2 - 4ac)) / (2a)

Thus, if the discriminant is negative, then the square root term will be imaginary, which means that the solutions will be complex conjugates of each other.

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By using the properties of logarithms, The logarithm "log₅(98)" can be written as log₅(2) + log₅(7) + log₅(7).

We use the "product' and "quotient" logarithmic identities to write log₅(98) in terms of log₅(2) and log₅(7):

⇒ logₐ(b × c) = logₐ(b) + logₐ(c)      ....(product rule)

⇒ logₐ(b/c) = logₐ(b) - logₐ(c)           ...(quotient rule)

First, we write the number "98" as the product of 2 and 7, which is :

⇒ log₅(98) = log₅(2 × 7 × 7),

Using the product rule, we can split this into three logarithms;

⇒ log₅(2 × 7 × 7) = log₅(2) + log₅(7) + log₅(7),

So, we have,

⇒ log₅(98) = log₅(2) + log₅(7) + log₅(7),

Therefore, log₅(98) is equal to log₅(2) + log₅(7) + log₅(7).

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The given question is incomplete, the complete question is

Use the properties of logarithms to write the logarithm in terms of log₅(2) and log₅(7).

The logarithm is log₅(98).

The ice rink is 14.42 units away from the origin and other solutions are added below

First, we have the library at (7,8), which is 7 units to the right of the origin and 8 units up from the origin.

Next, we have the market at (3,6), which is 4 units to the left of the library (7-4=3) and 2 units down from the library (8-2=6).

Then, we have the bank at (3,8), which has the same x-coordinate as the market (3) and a y-coordinate of 8.

We have the school at (10,8), which has the same y-coordinate as the bank (8) and an x-coordinate of 10.

The pool is located at (7,3), which is 5 units down from the school (8-5=3) and 3 units to the left from the school (10-3=7).

Finally, the park is located at (7,1), which has the same x-coordinate as the pool (7) and a y-coordinate of 1.

The completed table is:

Point Ordered Pair (x, y)

Library (7,8)

Market (3,6)

Bank (3,8)

School (10,8)

Pool (7,3)

Park (7,1)

Bao's new location can be found by moving 5 blocks down from his current location of (3,13) and then 2 blocks right.

This gives us the new coordinates of (5,8) for Boo.

The new location is 5 units right and 8 units up of the origin

To get to the baseball diamond, he traveled 3 blocks to the right from his starting point (3 - 3 = 0) and 8 blocks down (15 - 8 = 7), which gives us the new coordinates of (3, 15) for the baseball diamond.

Bao's starting point was (0, 7).

Bao's starting point can be found by moving 5 blocks to the left from his current location of (14, 13) and then 10 blocks down.

This gives us the new coordinates of (9,3) for Bao's starting point.

The distance between the ice rink and the origin can be found using the distance formula:

d = √((x2 - x1)^2 + (y2 - y1)^2)

In this case, we have:

d = √((12 - 0)^2 + (8 - 0)^2) = √(144 + 64) = √(208) ≈ 14.42

So the ice rink is approximately 14.42 units away from the origin.

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