how much work does the electric field do in moving a proton from a point with a potential of 160 v to a point where it is -60 v ? express your answer in joules.
In general, a proton's charge is q=1.61019 C q = 1.6 10 19 C. As a result, the finished work is 2881019 J 288 10 19 J. The work done as a result is 180 electron volts.
What exactly is Proton?A proton is a subatomic particle that has the symbol p, H+, or 1H+ and an elementary charge of +1 e. Its mass is slightly less than that of a neutron and 1836 times that of an electron.
In the early 1900s, Ernest Rutherford discovered the proton. During this time, his research yielded a nuclear reaction that resulted in the first atom'splitting,' from which he discovered protons. His discovery was named "protons" after the Greek word for "first," protos.A proton is the nucleus of a hydrogen atom, also known as an H+ ion. Each hydrogen atom, regardless of isotope, contains one proton; each helium atom contains two protons; each lithium atom contains three protons, and so on.Two up quarks and one down quark make up protons. Neutrons are composed of one up and two down quarks. One of the four fundamental forces, the "strong nuclear force," holds the nucleus together (gravity and electromagnetism are two others).Hence, the general charge of a proton is q=1.61019 C q = 1.6 10 19 C. The work done as a result is 180 electron volts.
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a pendulum with a length of 1 m, is taken to a planet, where its period is 2 s. the acceleration due to gravity on the other planet is most nearly –use the formula where the period is squared and solve for g. g
The acceleration due to gravity on the other planet is most nearly 0.25 m/s².
Equation :As it is given the length of the pendulum is 1 m
So, the time period is 2s
Now the given are putting in the formula of acceleration
a = Δv / Δt
a = d/t / Δt
So,
a = 1/2 / 2
a = 0.25 m/s²
Hence, the acceleration due to gravity on the other planet is most nearly 0.25 m/s².
Gravity :The force that pulls objects toward the center of a planet or other body is called gravity. All of the planets are kept in orbit around the sun by gravity. The amount of mass between you and the Earth's center determines how much gravity there is because the material that makes up the Earth's interior is not uniform.
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suppose a uniform slender rod has length l and mass m . the moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by icm
The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3
To calculate inertia, according to the parallel axis theorem:
[tex]I=I_{cm}+Md^{2}[/tex]
Where,
I is the inertia from an axis that is at distance d from the center of mass and Icm is the inertia when the axis passes through the center of mass.
The distance d = l/2
Now to calculate inertia
[tex]I=I_{cm}+Md^{2}[/tex]
[tex]I=\frac{Ml^{2}}{12} + M\frac{1}{2}\\I=\frac{Ml^{2}}{12}+\frac{Ml^{2}}{4}\\I=\frac{Ml^{2}+3Ml^{2}}{12}\\I=\frac{Ml^{2}}{3}[/tex]
The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3.
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romeo (75.0 kg) entertains juliet (57.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m away from juliet, who is in the front of the boat. after the serenade, juliet carefully moves to the rear of the boat (away from shore) to plant a kiss on romeo's cheek. what if? if the lovers both walk toward each other and meet at the center of the boat, how far (in m) and in what direction does the boat now move?
If the lovers both walk toward each other and meet at the center of the boat, at 0.725m and since romeo has greatest mass of the boat moves towards him away from the shore.
Calculating the system's center of mass should come first
X_{CM}=\sum_{n=1}^{n}\frac{X_n*M_n}{M_n}
Romeo, Juliet, and the boat's masses are multiplied by each coordinate's x value, and the result is then divided by the sum of all the masses.referring to Juliet's position as an example.
X_{CM}=\frac{57Kg\times0m+75Kg\times 2.7m+75kg\times1.35m}{57kg+75kg+75kg}
X_{CM}=\frac{307.395kg.m}{207kg}=1.485m
When internal forces are in play, the center of mass remains constant.
After the maneuver, the center of mass shifts in relation to the back of the boat, but it stays at the same distance from the shore.
X_{CM}=\frac{75\times1.35m+(75kg+57kg)\times2.70m}{207kg}=
X_{CM}=\frac{457.65}{207kg}=2.210m
The boat moves toward the shore with this displacement.
0.725m
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A student walked straight for 6 meters, turned, then walked straight for another 4 meters.
Without knowing how much he turned, what is the largest possible magnitude of his displacement?
Since displacement is a vector quantity, the largest possible magnitude of the student displacement will be 2 m
What is Displacement ?Displacement is the distance travel in a specific direction. It is a vector quantity. It is measured in meter.
Given that a student walked straight for 6 meters, turned, then walked straight for another 4 meters. Without knowing how much he turned, the largest possible magnitude of his displacement D will be
D = 6 - 4
D = 2 m
Therefore, the largest possible magnitude of his displacement will be 2 m
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Two point charges are separated by some distance. The first charge is positive. The second charge is negative, with a charge magnitude twice as large as that of the positive charge. Is it possible to find a place to bring a third charge in from infinity without changing the total potential energy of the system?.
No, it is not possible to bring a third charge in from infinity without changing the total potential energy of the system.
Potential energy for the first two charger is,
[tex]U=\frac{1}{4\pi E_{0} } \frac{q_{1}q_{2} }{r_{12} }[/tex]
This will change for adding a third charge no matter I it's sign, given as,
[tex]U=\frac{1}{4\pi E_{0} } [\frac{q_{1}q_{2} }{r_{12} } +\frac{q_{1}q_{3} }{r_{13} }+\frac{q_{2}q_{3} }{r_{23} }][/tex]
Hence not possible to find a place to bring a third charge in from infinity without changing the total potential energy of the system
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A student writes an expression for the momentum (P) of of mass (m), with total energy (E) and considering the body duration of time (t) as P = √2 mE/t Check it's correctness on dimensional analysis.
Answer:
The expression written for the momenum of a body is dimensionally incorrect.
Explanation:
P = momentum, m = mass, E = Energy & t = time Now, we know: Dimensional formula of momentum (p) = [MLT-1] Dimensional formula of mass (m) = [M] Dimensional formula of Energy (E) = [ML2T-2] Dimensional formula of time (t) = [T] Here, Dimensional formula of LHS = [MLT-1] And, Dimensional formula of RHS = 2/M212T-21 [T] -=√2 M²LT 3]=[MLT/2] [2 is constant] 2[M] [MLT-21 [T] Since the dimensional formula of LHS # dimensional formula of RHS. [MILT-1] [MLT-3/2] hence the given relation is dimensionly incorrect
4 – Microwave Miracle Patrick believes that fish that eat food exposed to microwaves will become smarter and would be able to swim through a maze faster. He decides to perform an experiment by placing fish food in a microwave for 20 seconds. He has the fish swim through a maze and records the time it takes for each one to make it to the end. He feeds the special food to 10 fish and gives regular food to 10 others. After 1 week, he has the fish swim through the maze again and records the times for each. 1.What was Patrick’s hypothesis?
2.Which fish are in the control group?
3.What is the independent variable?
4.What is the dependent variable?
5. Look at the results in the charts. What should Patrick’s conclusion be?
The term experiment has to do with the kind of study in which the effect of a dependent variable on an independent variable is undertaken and looked into in dept.
We know that in an experiment there must be an independent variable which is being monitored and changes from time to time and there is the dependent variable which changes as the independent variable changes.
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interpret the graph of the red slope.
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
____________________________________
[tex] \large \tt Explanation \: : [/tex]
Displacement - Time graph is shown in the given figure, and we have to interpret the graph with red slope.
First of all, Slope of a Displacement time graph represents velocity. so we can say that :
Graph has positive (increasing) Slope from 3rd to 6th seconds that represents positive constant velocity.
From 6th to 8th second graph has Slope = 0, that means there is no Displacement taken in the mean time, that means velocity in this interval of time is 0.
From 8th second the graph has negative (Decreasing) Slope that means, the object is retracing its own path with a constant velocity.
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now assume that a strong, uniform magnetic field of size 0.55 tt pointing straight down is applied. what is the size of the magnetic force on the wire due to this applied magnetic field? ignore the effect of the earth's magnetic field.
If the wire were light in weight, this force would be noticeable. The magnetic force is perpendicular to both the direction of current flow and the direction of the magnetic field. Here's a "right-hand rule" to help you determine the magnetic force's direction.
What exactly is a magnetic field?A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its velocity and the magnetic field.
Atoms make up everything, and each atom has a nucleus made up of neutrons and protons, with electrons orbiting around it.
Each atom generates a small magnetic field because the orbiting electrons are tiny moving charges.
Magnetic force can be found in a compass, a motor, the magnets that hold things on the refrigerator, train tracks, and new roller coasters. All moving charges create a magnetic field, and the charges that move through its regions experience a force.
Hence, if the wire were light in weight, this force would be noticeable. The magnetic force is perpendicular to both the direction of current flow and the direction of the magnetic field. Here's a "right-hand rule" to help you determine the magnetic force's direction.
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the horse on a carousel is 4.3 m from the central axis. part a if the carousel rotates at 0.12 rev/s , how long does it take the horse to go around twice? express your answer in seconds.
The horse takes 16.67 seconds long to go around the carousel twice.
Equation :To find the time first thing to note is that, if a line is drawn from the horse to the center of the carousel, all points above the line will take the same amount of time to complete one, two, or as many rounds as they choose.
So, we are going to use the formula,
θ = ωt
Then,
We must see it is similar to a clock in that every point in the minute arrow hits 12 simultaneously as it travels around the clock.
We note that the problem is independent of the distance from the central axis.
The horse's angle is equal to its angular velocity multiplied by the passage of time, so all we need to know is its angular velocity.
Now, applying the formula
θ = ωt
we have,
θ = 2 rev
ω = 0.12rev/s
So,
t = θ / ω
t = 2 / 0.12
t = 16.67 s
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particle 1 carrying -4.0 μc of charge is fixed at the origin of an xy coordinate system, particle 2 carrying 8.0 μc of charge is located on the x axis at x
The phenomenona of vectors proved.
What is vector?vector is a quantity that has two independent properties magnitude and direction.
The electric force is given by coulumb's law
F = k q₁q₂ / r²
Let's apply newtons second law in particle 3
F = F₃₁ - F₃₂
F₃₁ = k q₃q₁ / r₃₁²
F₃₂ = k q₃q₂ / r₃₂²
Let's write the values they give us
q₁ = -4.0 10⁻⁶ C
x₁ = 0
q₂ = q₃ = + 8.0 10⁻⁶ C
x₂ = 4.0 m
x₃ = -4.0 m
We look for the distances
r₃₁ = x₃ -x₁
r₃₁ = -4.0 - 0 = -4.0 m
r₃₂ = -4.0 - 4.0 = -8.0 m
Let's write the force equation
F = k q₃ (q₁ / r₃₁² + q₂ / r₃₂²)
so let's calculate
F = 8.99 10⁹ 8 10⁻⁶ (4 10-6/4 2 - 8 10-6 / 8 2)
F = 71.92 10³ (1/2 - 1/8 )10⁻⁶
F = 26.97 10-3 N
None of the charge are on the axis and therefore there are no forces on this axis.
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A pot plant falls off the balcony of an apartment. The balcony is 20 m above the ground and the pot plant has a mass of 2 kg. After falling a distance of 2 m from the balcony, the pot plant has a velocity of 6,26 m·s-1 . Ignore the effect of air resistance. 5.1
Calculate the gravitational potential energy of the pot plant before it begins to fall. 5.2 Calculate the total mechanical energy of the pot plant after it has fallen two meters. 5.3 Is this a closed system?
Explain your answer. 5.4 Calculate the speed with which the pot plant hits the ground.
The gravitational potential energy of the pot plant before it begins to fall is 392 J.
The total mechanical energy of the pot plant after it has fallen two meters is 78.39 J.
The speed with which the pot plant hits the ground is 19.8 m/s.
What is the gravitational potential energy?
The gravitational potential energy of the pot plant before it begins to fall is calculated as follows;
P.E = mgh
where;
m is mass of the potg is acceleration due to gravityh is height of the initial height of the potP.E = (2 kg) (9.8 m/s²) (20)
P.E = 392 J
The total mechanical energy of the pot plant after it has fallen two meters is calculated as follows.
M.E = K.E + P.E
where;
K.E is kinetic energyP.E is potential energyM.E = ¹/₂mv² + mgh
M.E = ¹/₂(2 kg)(6.26 m/s)² + (2 kg)(9.8 m/s²)(2 m)
M.E = 78.39 J
The speed with which the pot plant hits the ground is calculated by applying the principle of conservation of energy as follows;
K.E(bottom) = P.E(up)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is the initial height of the potv = √(2 x 9.8 x 20)
v = 19.8 m/s
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In the free-body diagram, the magnitude of the normal force is 35 N, the friction force is 15 N, and the net force is 70 N. What is the magnitude of the applied force? Explain how you came to your answer in one to two sentences.
The applied force on the object is 85 N. This answer was obtained by considering forces acting in horizontal direction.
Also the concept of net force by Newton's second law of motion was used to obtain the applied force (85 N).
What is applied force?The applied force on an object is the external force applied or exerted on an object.
The applied force on the object is determined by calculating the net force on the using Newton's second law of motion.
F(net) = F(app) - F(fric)
where;
F(net) is the net forceF(app) is the applied forceF(fric) is the frictional force70 N = F(app) - 15 N
F(app) = 70 N + 15 N
F(app) = 85 N
Thus, we can conclude that the applied force must be obtained from the forces acting on horizontal direction since force of friction exits only when an object is in horizontal motion.
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magnetic effects involving jupiter's moon io results in an effective voltage of about 550 kv that drives a current of about 4.5 ma between io and jupiter.
Effective voltage for the Gi system
V = 550 KV = 550 * 10 3 * v
Current I = 4.5MA = 4.5 * 10 6 *
A The strength of the Lo to Jupiter current
P= VI\s= (550 * 10 ^ 3)(4.5 * 10 ^ 6)
K = Kilo = 10 3 M = Mega = 106
P = 24.75* 10 ^ 7 W
What is magnetic effects?
Moving electric charges and magnetic dipoles combine to form a magnetic field, which acts as a force field on other adjacent moving charges and magnetic dipoles. Given that it has both a magnitude and a direction, the magnetic field is a vector quantity.
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We need to find the launch velocity of our new marble launcher. we know that it will launch a 25g marble to a distance of 73 cm, causing an impact noise of 44 decibels. the marble will then roll up to 6.2 meters befor stopping. with a launch height of 20 cm and a classroom temperature of 15.8 degrees celsius, we can calculate the launch velocity of the marble launcher to be
The launch velocity of the marble launcher is 34.65 m/s
Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).
The time for landing can be calculated by the second equation of motion formula:
h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
Let u = 0
0.2 = 0×t + [tex]\frac{1}{2}[/tex] × 9.8 × [tex]t^{2}[/tex]
[tex]t^{2}[/tex] = [tex]\frac{0.2}{4.9}[/tex]
[tex]t^{2}[/tex] = 0.04
t = 0.2s
Now, the launch velocity of the marble launcher can be calculated by:
Speed = Distance / Time
Speed = [tex]\frac{0.73 + 6.3}{0.2}[/tex]
Speed = [tex]\frac{6.93}{0.2}[/tex]
Speed = 34.65 m/s
Therefore, the launch velocity of the marble launcher is 34.65 m/s
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A 7. 50g-bullet has a speed of 555 m/s as it leaves the muzzle of a rifle. If the barrel of the rifle is 0. 950 m, what is the average force exerted on the bullet by the ammunition?.
The average force exerted on the bullet by the ammunition is 1215.88N
From the question above, It is given that,
Mass of the bullet, m = 7.50 g
Initial speed of the bullet, u = 0
Final speed of the bullet, v = 555 m/s
We need to find the force exerted on the bullet while it was traveling down the 0.950m length of the barrel of the rifle. Let:
a is the acceleration of the bullet. So,
v² - u² = 2ad
v² = 2ad
a = v²/2d
a = 555²/2*0.950
a = 162118.42m/s²
Let F be the force exerted. It is given by:
F = Ma
F = 7.5 * 10⁻³ * 162118.42
F = 1215.88N
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F = 1590.87 N
So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.
The law of superposition states that in an undeformed sequence of sedimentary rocks the oldest rocks will be at the bottom while the youngest will be on top. Notice the word undeformed in the last sentence: that means the naturally occurring rock layers are somehow altered, causing confusion or gaps in the geologic record. Changes to the rock strata can occur due to a variety of geologic events. Which geologic event is INCORRECTLY identified?
A) D. Intrusion of magma at Earth's surface.
B) B. Folding of layers due to compression.
C) C. Unconformity showing erosion and deposition.
D) A. Faulting due to stress and fracture.
The geologic event that is incorrectly identified is option A) D. Intrusion of magma at Earth's surface.
What is the law of superposition about?According to the Law of Superposition, the oldest rocks will be at the bottom and the youngest at the top of a sequence of sedimentary strata that has not undergone any deformation.
If you were to imagine a river dumping sand into an ocean, the sand would eventually pour out onto the ocean floor and settle on top of the seafloor. After the seafloor's sand had already been laid down, this sand was added.
Note that the events are as follows:
Subsidence and deposit layer Folding of layers as a result of compression.Unconformity showing erosion as well as deposition.Faulting as a result of stress and fracture.Therefore, option A is incorrectly labeled because it is one that is supposed to be labeled as subsidence and deposit layer of geologic event.
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a baseball is thrown straight upwards from the ground and undergoes a free fall motion as it rises towards its highest point. What changes , if any ,would be observed of the velocity and the acceleration of the baseball as it rises towards its highest point?
The baseball thrown upwards will experience change in its velocity while its acceleration will be constant.
What is upward motion?Upward motion is a type of motion in which an object moves upwards against force of gravity.
During the upward motion of an object, its vertical velocity decreases as the object moves upwards due to opposing force of gravity. The velocity of the object eventually becomes zero when the object reaches maximum height.
As the object begins to move downwards, the velocity begins the increase and eventually become maximum before the object hits the ground.
The acceleration of the object during the upward motion is always point downwards and does not change.
Thus, we can conclude that if an object moving upwards, its velocity will change while the acceleration will not change.
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Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
Hence, the gravitational force between them will change by a factor 1/9.
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a large fan requires a torque of 260 ft-lbs to operate at 1740 rpm. what is the minimum horsepower rating of the motor to drive the fan? if the motor is 90% efficient what is minimum input power required by the motor in kw?
Large fan torque requires of 260 ft- lbs operate at 1740 RPM.
1740 RPM = 260 1b-ft N of torque
Torque 1 b. ft = Power in HP X 5252 / Speed in RPM
Power in np =260 X 1740/5252 =86.1386 HP
n= 90% =0.9
Power input = Power in np x 0.746 /n
For input power = (86.1386*0.746)/0.9
=71.4 kw.
What is torque?
The rotating equivalent of force is torque. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect. It illustrates how a force can cause a change in the body's rotational motion. Archimedes' studies on the use of levers are where the idea first emerged.
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must have an opening of sufficient size to allow free movement of water at the bottom of the tank and movement of air at the top during rapid filling or unloading
During dump site operations, the tank baffles must have an opening of sufficient size to allow free movement of water at the bottom of the tank and movement of air at the top during rapid filling or unloading.
What is a land filling?Land filling can be defined as a biological method that is typically adopted for the effective and efficient treatment of waste products (garbage).
The types of land filling.Generally speaking, there are different types of land filling and these include the following:
Green waste landfills.Municipal solid waste landfills.Hazardous waste landfills. Industrial waste landfills. Dumping waste landfills.In conclusion, the dumping waste landfill involves the dumping of solid waste products (garbage) into the landfill site through the use of trucks.
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Complete Question:
During dump site operations, the _____ must have an opening of sufficient size to allow free movement of water at the bottom of the tank and movement of air at the top during rapid filling or unloading.
An airplane, moving at 375 ms relative to the ground, fires a missile forward at a speed of 790 m/s relative to the planewhat the speed of the relative the ground?
Answer:
1165 m/s relative to ground
Explanation:
(375 + 790 ) = 1165 m/s
What shape is the moon's orbit around Earth?
Answer:
Elliptical Orbit
Explanation:
The Moon revolves around Earth in an elliptical orbit with a mean eccentricity of 0.0549. Thus, the Moon's center-to-center distance from Earth varies with mean values of 363,396 km at perigee to 405,504 km at apogee.
When a junked car is crushed into a compact cube, does its mass change? Its volume? Its weight?
Only it's volume changes. Volume is defined as the space an object takes up. The amount of substance, which is the mass stays the exact same. The amount of force that Earth is pulling the car down (the weight) stays the same.
A car moves 4 km in an easterly direction and
then turns to move 3 km in a northerly direction.
By means of a graphical approach, find the
resultant displacement of the car.
According to the given statement the resultant displacement of the car is 5 m.
What exactly is displacement mean?Displacement is the act of removing something from its customary location or position and replacing it with something else in that location or position.
What does velocity displacement mean?A vector called displacement points from an object's initial position to its ultimate position. Meters are the accepted units of displacement. A vector called velocity depicts the direction and speed of motion. Meters per second are the accepted units for measuring velocity.
Briefing:East and north are perpendicular to one another.
Displacement is the distance between a car's starting position and its ending position.
Displacement is √(3² + 4²) = √(25) = 5m
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During Piaget's sensorimotor stage, children acquire a
1) theory of mind.
2) concept of conservation.
3)sense of object permanence.
4) capacity for abstract reasoning
3) sense of object permanence is the condition that the children acquire during the Piaget's sensorimotor stage and is identified during the conscious interaction.
What is the sensorimotor development theory proposed by Piaget?The sensorimotor stage, according to Piaget’s theory of cognitive development, lasts during the first two years of a child’s existence. Your youngster will learn: to repeat enjoyable behaviors throughout this stage.
To consciously interact with objects and investigate their surroundings. To plan actions in order to accomplish a given objective.
What is Piaget’s conservation concept?The Swiss psychologist Jean Piaget was the first to examine conservation as a logical reasoning skill in young children.
To put it simply, being able to preserve means understanding that a quantity remains unchanged when changed (by being stretched, cut, elongated, spread out, shrunk, poured, etc.)
Stage of SensorimotorAccording to Piaget, infants are only conscious of what is directly in front of them during the early stages.
They concentrate on what they are doing, what they observe, and their bodily interactions with the surroundings. They are continually conducting experiments because they are unsure of how things during sensorimotor stage will react.
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A baseball is thrown horizontally off a cliff with a velocity of 15.9 m/s. It lands 35.9 meters away. Assuming that gravity is 9.8 m/s2, how high (dy) is the cliff?
The height of the cliff, given that the baseball landed 35.9 m away is 25.03 m
How to determine the timeFirst, we shall determine the time taken for the baseball to land. This can be obtained as follow:
Horizontal velocity (u) = 15.9 m/sHorizontal distance (s) = 35.9 mTime (t) =?s = ut
35.9 = 15.9 × t
Divide both sides by 15.9
t = 35.9 / 15.9
t = 2.26 s
How to determine the height of the cliffWe can obtain the height of the cliff as follow:
Acceleration due to gravity (g) = 9.8 m/s²Time (t) = 2.26 sHeight (h) =?h = ½gt²
h = ½ × 9.8 × 2.26²
h = ½ × 9.8 × 5.1076
h = 25.03 m
Thus, we can conclude that the cliff is 25.03 m high
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A car moves 4 km in an easterly direction and
then turns to move 3 km in a northerly direction.
By means of a graphical approach, find the
resultant displacement of the car.
When the car moves 4km east and then turns 3km north then the resultant displacement of car will be :
5km
Explanation:Here initially the car moves 4km east , that is a straight line towards east direction with a value of 4kms (let the point be A).
then, from the point A it turns 3km towards north direction. here
North and east are perpendicular to one another.
ie, it forms 90° that means it is a right angle.
The displacement of a car is the distance between its initial and final positions.
The displacement is
S = [tex]\sqrt{3^{2} + 4^{2} }[/tex]
S = [tex]\sqrt{25}[/tex]
= 5
so the resultant displcement is 5km
the resultant graph is attached below:
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an electric dipole is formed from two charges, ±q, spaced 0.700 cm apart. the dipole is at the origin, oriented along the y-axis. the electric field strength at the point (x,y)
In the given electric dipole, the charge q = 0.2 C and the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C is E = 138.37 10⁹ N/C.
What is electric dipole?
Any electromagnetic system has an electric dipole separating the positive and negative charges. A simple illustration of this system is a pair of opposite-sign, equal-sized electric charges that are separated from one another by a relatively short distance. (A permanent electric dipole is known as an electret.)
a) Let's calculate the field for each of the both charge at the point y = 10 cm, x=0 or in the dipole line, for that we calculate the field that creates each charge and add them vectorially
For the Charge 1
y₁ = (0.1 - 0.035) = 0.065 m
(Electric field) E1 = k q / y₁²
E1 = 8.99 10 9 q / 0.065²
E1 = 2127.8 q
For the Charge 2
y₂ = (0.1 - (-0.035) = 0.135 m
(Electric field) E2 = k (-q) / y₂²
E2 = 8.99 109 q / 0.135²
E2 = - 493.3 q
In an electric dipole the value of the two charges is of equal magnitude, but otherwise, suppose the positive charge is the highest
Et = E1 -E2
Et = 2127.8q -493.3q
330 = q (2127.8 -493.3)
q = 330 / 1634.5
q = 0.2 C
Now let the negative charge is higher
Et = (-2127.8 +493.3) q
330 = -1634.5 q
q = -0.2 C
b) calculate the field for the point x = 0.1 m y = 0 m
This is a point perpendicular to the midpoint of the dipole, so that we can use the dipole equation
E = k 2qa / √(x² + a²)³
E = 8.99 10⁹ 2 0.2 0.07 / √(0.1² + 0.07²)³
E = 0.2517 10⁹ / (0.001819)
E = 138.37 10⁹ N/C
Therefore, the charge q is 0.2 C and electric field E is 138.37 10⁹ N/C.
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Complete Question
An electric dipole is formed from two charges, ±q, spaced 0.700 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x,y)=(0cm,10cm) is 330 N/C . What is the charge q? Give your answer in nC what is the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C = ?