What’s the correct answer answer asap for brainlist

Answer: 1.466 g/mL

Explanation:

[tex]\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}[/tex]

The bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

No of moles of calcium bromide is calculated as follows:

moles = 1.642 ÷ 199.89 = 8.215 × 10-³moles

Molarity = 8.215 × 10-³moles ÷ 469.1mL = 1.75 × 10-⁵M

Therefore, the bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

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0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water (option A).

According to this question, when magnesium chloride (MgCl2) dissolves in water, it dissociates into magnesium ions and chloride ions as follows:

MgCl2(aq) ⟶ Mg2+(aq) + Cl−(aq)

However, if a 42.66-gram sample of magnesium chloride is dissolved in water, this means that 42.66g/molecular mass of MgCl2 will be the number of moles of the ionic products.

molecular mass of MgCl2 = 95.3g/mol

moles = 42.66g ÷ 95.3g/mol = 0.448mol

Therefore, 0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water.

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The one that does not demonstrates the law of conservation of matter would be the third option: [tex]2NO_2 + H_2O -- > HNO_3 + HNO_2[/tex]

It is a law that explains that matters are conserved during the course of chemical reactions. They can neither be destroyed nor created.

Thus, the number of moles of the species in a reaction remains the same before and after the reaction.

Thus, an equation that demonstrates the law of conservation of matter will be balanced in terms of the number of moles of species.

The only equation, in this case, is [tex]2NO_2 + H_2O -- > HNO_3 + HNO_2[/tex]

There are 3 oxygen species on the reactant while 5 are present on the product side.

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Answer:

70.9 g/mol

Explanation:

To find the molar mass, you first need to convert molecules to moles via Avogadro's Number.

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

2.123 x 10²¹ molecules X₂                      1 mole
--------------------------------------  x  ------------------------------------  = 0.00353 moles X₂
                                                   6.022 x 10²³ molecules

Now, you can plug the molar value and mass (given) into the molar mass ratio to find your final answer. Your answer should have 3 sig figs to reflect the given value with the lowest amount of sig figs (0.250 g).

Molar Mass (g/mol) = mass (g) / moles

Molar Mass = 0.250 g / 0.00353 moles

Molar Mass = 70.9 g/mol

The criteria that will allow Amol separate group 1 substances into two groups are mixtures and pure substances (option B).

Mixtures are substances that are made up of two or more substances that can be easily separated.

Pure substances, on the other hand, are elements and compounds that cannot be separated by chemical means.

In group 1 of the above table, the substances can be classified as follows:

Therefore, the criteria that will allow Amol separate group 1 substances into two groups are mixtures and pure substances.

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Answer:

Explanation:

b is the right answer

535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given:

[tex]C(s) + O_2(g)[/tex] ⇒[tex]CO_2(g)[/tex]

1 mole of [tex]CO_2(g)[/tex] is formed from 1 mole of charcoal, that means 1 mole of [tex]CO_2(g)[/tex] is formed from 12 g of charcoal.

1 lbs = 453.592 grams

6.75 lbs = 6.75 x 453.592 =3061.746g

So, [tex]CO_2(g)[/tex] formed from 3061.746g of charcoal is:

=[tex]\frac{1}{12}[/tex] x 3061.746g

=255.14 mol.

Now, at STP, the volume of 1 mol of gas =22.4 L

Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 255.14 x 22.4 L

Volume of 255.14 mol of [tex]CO_2(g)[/tex] = 535.8 L

Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

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Answer:

C

Explanation:

This is a chemical reaction because the materials that were mixed have different solubilities than the materials that were made.

Answer:

C

Explanation:

When a chemical reaction occurs, new materials form. Different materials each have unique physical properties, such as solubility.

When olive oil and sodium hydroxide were mixed together, soap and glycerol were made. The table shows that olive oil and sodium hydroxide have solubilities that are different than soap and glycerol. This means that olive oil and sodium hydroxide are different materials than soap and glycerol. Therefore, this is a chemical reaction because the materials that were mixed have different solubilities than the materials that were made.

An atom's mass is determined by its protons and neutrons.

An atom's charge is determined by its number of protons minus it number of electrons.

Atoms become cations, or positively charged when they lose an electron, and since electrons have a negative charge, they become anions, or negatively charged.

Water is a universal solvent.

Carbohydrates (carbs) are used by the body for energy.

Steroids and triglycerides are lipids.

Proteins that catalyze chemical reactions are called enzymes.

Answer:

I have the explanation.

Explanation:

Answer:

H2(hydrogen gas)

Explanation:

The reaction between magnesium and hydrochloric acid combine to form a salt (magnesium chloride) and release gas (hydrogen).

Answer:

52.6 g C₆H₆O₂

Explanation:

Unfortunately, the problem does not specify which of the reactants is the limiting reagent. This means you must convert both starting amounts into the product to identify the final answer.

To find the mass of hydroquinone (C₆H₆O₂) produced, you need to (1) calculate the molar masses of the reactants and product, then (2) convert grams of the reactants to grams of the product (via the molar masses and the mole-to-mole ratio from equation coefficients), and then (3) determine the limiting reagent and the actual answer.

(Step 1)

Molar Mass (C₆H₅OH): 6(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₆H₅OH): 94.112 g/mol

Molar Mass (H₂O₂): 2(1.008 g/mol) + 2(15.998 g/mol)

Molar Mass (H₂O₂): 34.012 g/mol

Molar Mass (C₆H₆O₂): 6(12.011 g/mol) + 6(1.008 g/mol) + 2(15.998 g/mol)

Molar Mass (C₆H₆O₂): 110.11 g/mol

(Step 2)

It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given values.

45.0 g C₆H₅OH             1 g              1 mole C₆H₆O₂             110.11 g
------------------------  x  --------------  x  -------------------------  x  -----------------  =
                                  94.112 g         1 mole C₆H₅OH            1 mole

=  52.6 g C₆H₆O₂

20.0 g H₂O₂           1 mole             1 mole C₆H₆O₂           110.11 g
-------------------  x  -----------------  x  -------------------------  x  ---------------  =
                              34.012 g              1 mole H₂O₂            1 mole

=  64.7 g H₂O₂

(Step 3)

The limiting reagent of the reaction is C₆H₅OH because it is not able to produce as much product as H₂O₂. As such, product stops being made as C₆H₅OH runs out, making the final amount 52.6 g C₆H₆O₂.

Answer:

See below

Explanation:

Mole weight of C6H5OH  = 94 gm/mole       (approx)

   45 gm / 94 gm/mole = .479 Moles of phenol

Mole wt of H2O2  = 34        (approx)

    20 gm / 34 gm /mole = .588 moles of hydrogen peroxide

From the equation.....it takes equal moles of these to react to produce the same number of moles of hydroquinone.....

  there isn't enough phenol to match the peroxide....so phenol is limiting reactant and you will only get .479 moles of hydroquinone

hydroquinone mole weight = 110 gm / mole       (approx)

    .479 mole * 110 gm/mole = 52.69 gm produced

The molecular weight of the molecular compound is

x= 105.57 g/mol

Generally,a  the equation for Mole of molecular compound is  mathematically given as

Mm= mass / molar mass

Therefore

Mm= 0.333 g / x

the equation for Morality

M = mole of solute / mass of solvent

[tex]M = \frac{(0.333 g / x )}{33.3 g / 1000 }[/tex]

M= 10 / x

the equation for change in temp dt

dt= K* morality

Therefore

[tex]0.485 = \frac{5.12}{ * 10/ x}[/tex]

x = (5.12 *10) / 0.485

x = 105.57 g/mol

In conclusion, molecular mass of molecular compound

x= 105.57 g/mol

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A wavelength's frequency and energy (E) drop as it becomes longer. You may conclude from these equations that the wavelength grows shorter as the frequency rises. The wavelength lengthens as the frequency drops.

Since frequency and wavelength are inversely related to one another, the wavelength of the wave falls as frequency increases.

The solubility (in M) of O2 in the blood of a scuba diver at a depth of 100 feet is 2.32 × 10^-3 mol.

It should be noted that the partial pressure of oxygen will be:

= Mole fraction × Total pressure

= 0.209 × 3

= 0.627

According to Henry's law, the solubility will be:

= 3.7 × 10^-2 × 0.627

= 2.32 × 10^-3 mol

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The correct answers are triple point, Carbonic acid, Antibody production, endocytosis of a virus by a phagocyte lymphocyte. E. T lymphocyte activation and clonal expansion, Corpus luteum and Aorta.

In a phase diagram, triple point is the term used for a substance held at a temperature and pressure where the solid ,liquid and gaseous states of substance exist simultaneously.

Carbonic acid is a substance that is responsible for donating H+ ions to act as a buffer when blood pH rises.

Antibody production, endocytosis of a virus by a phagocyte lymphocyte. E. T lymphocyte activation and clonal expansion are specific immune responses.

Corpus luteum is a mass within the ovary that secrets hormones to maintain the uterine lining during pregnancy.

A myocardial infarction affects Aorta blood vessels of the heart.

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Taking into account the definition of calorimetry, the mass of the sample is 159.85 grams.

In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .).

The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case:

Replacing in the expression to calculate heat exchanges:

3750 J= 1.02 [tex]\frac{J}{gC}[/tex]× m× 23 C

Solving:

m= 3750 J ÷ (1.02 [tex]\frac{J}{gC}[/tex]× 23 C)

m= 159.85 grams

In summary, the mass of the sample is 159.85 grams.

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Net potential

Net current=3A

Apply ohm's law

The change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.

The change in temperature of a substance can be calculated using the following formula:

Q = mc∆T

Where;

500 = 23 × 0.24 × ∆T

500 = 5.52∆T

∆T = 500/5.52

∆T = 90.58°C

Therefore, the change in temperature (∆T) if 500 J of heat are added to a 23 g sample of silver is calculated to be 90.58°C.

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Answer:

A.) Adding more of gas C to the system

Explanation:

A.) is correct because the reaction wants to keep the same amount of reactants and products that sustain equilibrium. If you are increasing the amount of gas C, this will push the reaction to make more of the reactants to restore the balance.

B.) is incorrect because heat is a form of energy. As previously stated, when you add more material to the reactants side, the equilibrium shifts to the product side to restore equilibrium.

C.) is incorrect because when the volume is increased, the equilibrium will shift to the side with the greater amount of moles of gas. There is 1 mole of gas on the reactant side (from A (g)) and 3 moles of gas on the products side (from 3 C (g)). Therefore, the reaction will shift to the product side.

D.) is incorrect because if the material on the product side is decreasing, the equilibrium will want to make up that difference by shifting to the product side.

Remember,

reactants ---> products

The volume of water vapour gas that would be produced will be 2,581.73 L

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 535.55 grams of propane = 535.55/44.1 = 12.12 moles

Mole of 2665.06 grams of oxygen = 2665.06/32 = 83.28 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

12.12 x 4 = 48.48 moles.

Using the ideal gas equation: pv = nRt

v = nRT/p = 48.48 x 0.08206 x 623/0.96 = 2,581.73 L

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If matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because compound would have random composition.

The law of definite proportions states that all pure samples of a compound contains the same element in a fixed mass ratio.

The law of multiple proportions states that if an element combines with another element to form more than one compound, the mass of the element combines with a fixed mass of the other element in whole number multiples ratios.

Assuming matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because, their will be no definite ratio or composition in compounds.

The law definite proportions and law of multiple proportions are required for the atomic theory as they help prove that matter consists of definite unique particles called atoms.

In conclusion, the existence of atoms is proved true by the law definite proportions and law of multiple proportions.

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An ion is an electrically charged atom. Details about ions can be found below.

Ion in chemistry refers to an atom or group of atoms bearing an electrical charge.

An example is the sodium (Na+) and chlorine (Cl-) atoms in a salt solution.

Therefore, it can be said that an ion is an electrically charged atom.

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The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).

The volume of a substance can be calculated using the following formula:

P1V1 = P2V2

Where;

153 × 3 = 304 × V2

459 = 304V2

V2 = 459/304

V2 = 1.51L

Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.

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Answer:

8.81 atm

Explanation:

P1 V1 /T1 = P2 V2 / T2              T   must be in Kelvin

re-rrange to :

P1 V1 / T1  *  T2/V2  = P2

2.81 * 713 / (664)  *  368 /126  = 8.81 atm

The new pressure of the gas given that its volume and temperature change to 126 L and 368 K respectively is 8.81 atm

The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(2.81 × 713) / 664 = (P₂ × 126) / 368

Cross multiply

664 × 126 × P₂ = 2.81 × 713 × 368

Divide both side by 664 × 126

P₂ = (2.81 × 713 × 368) / (664 × 126)

P₂ = 8.81 atm

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The rate of increase of NH3 is 0.22M/s.

The balanced equation of the reaction is given below:

The rate of decrease of N2 is half the rate of increase of NH3.

Rate of decrease of N2 = -0.11 M/s

Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.

In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.

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Empirical formula mass

Find n

Molecular formula

The molecular formula of the compound is C₇H₁₄.

The empirical formula of a compound and the molecular formula is related as follows:

The empirical mass of the compound = 12 + 4 = 14

n = molecular mass/empirical mass

n = 98.1861/14 = 7

molecular formula will be n(CH2) = C₇H₁₄

In conclusion, the molecular formula is determined from the molecular mass and empirical mass.

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