What speed must a 600 kg car have in order to have the same momentum as a 1200 kg truck traveling at a velocity of 10 m/s to the west? 5 m/s west B 20 mls west 5 m/s east 20 m/s east

A) 5m/s west
B) 20m/s west
C) 5m/s east
D) 20m/s east

Answers

Answer 1

Answer:

20 m/s

Explanation:


Related Questions

Please help me !!!!!!!

Answers

Answer:  I believe that it is 35 Joules.

Explanation:

100 - 65 = 35

:)

Please help. It’s probably easy

Answers

I believe it’s 60km/h

I divided the total distance (120 km) by the time it took to get there (2h) to get this.

What is a energy transformation when using a microwave to make popcorn?

Answers

Answer:

Radiation

Explanation:

Radiant energy

Explanation:

Radiant energy is transformed into thermal energy as the popcorn kernels absorb the microwaves. This causes the kernels to become hot and pop. Electric energy is transferred from the electrical outlet to the microwave.

The total charge a battery can supply is rated in mA⋅hmA⋅h, the product of the current (in mA) and the time (in h) that the battery can provide this current. A battery rated at 1000mA⋅h can supply a current of 1000 mA for 1.0 h, 500 mA current for 2.0 h, and so on. A typical AA rechargeable battery has a voltage of 1.2 V and a rating of 1800mA⋅h. For how long could this battery drive current through a long, thin wire of resistance22Ω?

Answers

Answer:

118800 seconds

Explanation:

Given :

Voltage, V = 1.2 V

Resistance, R = 22 Ω

Applying Ohm's law, we get

Voltage, V = IR

Current [tex]$I=\frac{V}{R}$[/tex]

           [tex]$I=\frac{1.2}{22}$[/tex]

          I = 0.0545 A

Rate = 1800 mAh

Time taken, [tex]$t=\frac{1800 \times 10^{-3}}{0.0545}$[/tex]

                       = 33 hr

                      = 118800 s

Which planet is least like earth? Mars,Venus, or Jupiter

Answers

Answer:

mars, reason why is because they both are diff from the size

Explanation:

Jupiter is least like Earth. Planets like Venus, and Mars are mostly rocky and are more or less similar in interbal composition. Jupiter is large, gaseous, and hydrogen-rich.

a potted plant falls from a window sill and is gaining speed. which one of the following statements is true of the plant?

a) its kinetic energy is constant
b) its kinetic energy is increasing
c) its kinetic energy is decreasing​

Answers

It’s kinetic energy is increasing

Lava from a volcano becomes solid as a result of
A. cooling
B. heating.
C. evaporating.
D. condensing.
E. melting.

Answers

Answer:

B. heating.

Explanation:

Answer:

A. Cooling

Explanation:

Because when Lava cools down, it hardens and becomes a solid, and is less hotter.

I need help plissss..............

Answers

Answer: A.
Have a good day!!!!

Consider the path of a comet orbiting a star, the system of the comet plus the star. Which of the following statements are correct? Select all that are True. 1) As the comet slows down, the kinetic energy of the system decreases. 2) As the comet's kinetic energy increases, the gravitational potential energy of the system also increases. 3) External work must be done on the system to speed up the comet. 4) As the kinetic energy of the system increases, the gravitational potential energy of the system decreases. 5) As the comet slows down, energy is lost from the system.

Answers

Answer:

True  1, 4

False 2, 3, 5

Explanation:

The system is formed by the Sun that is fixed at a point (focus of movement) and the comet that rotates around in styptic orbits. The only force involved is the force of attraction between the two bodies, if we write the energy of the system

         Em = K + U

         Em = ½ m v2 + G m Ms / r2

where m is the mass of the comet, Ms the mass of the Sun and r the distance between them.

This system is isolated so the energy is conserved throughout the movement, it only transforms from kinetic to gravitational potential.

Let's review the different claims;

1) True. The speed of the comet determines its kinetic energy, so when decreasing the speed decreases the kinetic energy, there is also a decrease due to the lost mass

2) False. The total energy is constant, so if the kinetic energy increases, the power energy must decrease

3) False. The comet's speed changes are due to changes in gravitational energy, so no external work is needed to change the speed.

4) True. Correct because the sum of the two must be constant

5) False. When the comet loses speed, the energy increases, the power would gravitate, so there is no loss of energy, we are ignoring the loss of mass of the comet.

How can parents help children to gain friends?

Answers

Answer:

You could try finding a familiar peer to join the activity with your child. Or ask your child who their friends are at school, or what they look for in a friend at school.

Answer:

Let the parents their Children to play outside

Explanation:

I HOPE I HELP YOU

There are two main types of collisions that you will study: elastic and perfectly inelastic. In an elastic collision, kinetic energy is conserved. In a perfectly inelastic collision, the particles stick together and thus retain the same velocity after the collision.

a. True
b. False

Answers

Answer:

The first part is right (KE is conserved in an elastic collision).

The second part of the  statement is false,.

Since momentum is conserved, let moving mass m strike stationary mass M:

m v = (m + M) V   where m v is the momentum in

Obviously, v does not equal V.

What is energy transfer in a car crash

Answers

Force energy- kinetic energy

Answer:

Kinetic and thermal

Explanation:

Kinetic because a moving car is transferring movement energy into the other one. Thermal because, in a car crash, the touching surfaces of both cars friction and that produces heat.

how is a trench and a tsunami related? 6-8 sentences

Answers

Answer: A tsunami is a very long-wavelength wave of water that is generated by sudden displacement of the seafloor or disruption of any body of standing water.  Tsunami are sometimes called "seismic sea waves", although they can be generated by mechanisms other than earthquakes.  Tsunami have also been called "tidal waves", but this term should not be used because they are not in any way related to the tides of the Earth.  Because tsunami occur suddenly, often without warning, they are extremely dangerous to coastal communities. Ocean trenches are steep depressions in the deepest parts of the ocean [where old ocean crust from one tectonic plate is pushed beneath another plate, raising mountains, causing earthquakes, and forming volcanoes on the seafloor and on land.  

Explanation:

a solid disk rotates in the horizontal plane at an angular velocity of 4.9 x 10 rad/s with respect to an axis perpendicular to the disk at its center the moment of inertia of the disk is 0.14 kg from above sand is dropped straight down onto this rotating disk so that a thin unifrom ring of sand is formed at distance of 0.4 m from the axis the sand in the ring has mass of 0.5 kg after all the sand is in place what is the angular velocity of the disk

Answers

Answer:

ωf = 3.1*10 rad/sec

Explanation:

Assuming no external torques acting while the sand is being dropped, total angular momentum must keep constant.So we can write the following equality:

       [tex]L_{o} = L_{f} (1)[/tex]

For a rigid body rotating with respect to an axis, the angular momentum can be written as follows:

      [tex]L = I* \omega (2)[/tex]

where I = moment of inertiaω = angular velocityReplacing (2) on both sides of (1) we get:

       [tex]I_{o}* \omega_{o} = I_{f}* \omega_{f} (3)[/tex]

In (3) we know the values of I₀ and ω₀ (since they are givens), but we need to find the value of If first.The final moment of inertia, will be equal to the sum of the initial one, plus the one due to the ring of sand, that also rotates with respect to an axis perpendicular to the disk, as follows:[tex]I_{f} = I_{o} + I_ {ring} (4)[/tex]The moment of inertia of a circular ring is as follows:

        [tex]I_{ring} = m_{ring} *r^{2} (5)[/tex]

Replacing by the givens in (5) we get:

        [tex]I_{ring} = m_{ring} *r^{2} = 0.5 kg * (0.4m)^{2} = 0.08 kg*m2 (6)[/tex]

Replacing (6) in (4):[tex]I_{f} = I_{o} + I_ {ring} = 0.14kg*m2 + 0.08 kg*m2 = 0.22 kg*m2 (7)[/tex]Replacing I₀, ω₀ and If in (3), we can solve for ωf, as follows:[tex]\omega_{f} =\frac{I_{o} *\omega_{o} }{I_{f} } = \frac{0.14kg*m2*4.9*10rad/sec}{0.22kg*m2} = 3.1*10 rad/sec (8)[/tex]

A car is travelling at 15 m/s on a horizontal road and stopped after 4 s. The coefficient of kinetic friction between the tires and road is:​

Answers

Answer:

Fr,= umg

umg= ma

a= v/t

umg= mv/t

u= v/gt= 0.38

An amateur blacksmith wants to cool off a 42kg glowing piece of iron, specific heat 470and decides to toss it into a 5.0 kg iron bucket with 10.0 kg of room temperature(23 C) water in it. To his surprise the water completely evaporates away (meaning once it vaporizes it is no longer part of the system) and after some time he goes to pick up the bucket but finds that the bucket is at 150 C.

Required:
What was the initial temperature of the glowing piece of iron?

Answers

Answer:

The right approach is "1479°C".

Explanation:

The given values are:

Mass of iron piece,

[tex]m_p=42 \ kg[/tex]

Mass of iron bucket,

[tex]m_I=5 \ kg[/tex]

Mass of water,

[tex]m_w=10 \ kg[/tex]

Iron's specific heat,

[tex]C_I=470 \ J/Kg^{\circ}C[/tex]

Water's specific heat,

[tex]C_w=4186 \ J/Kg^{\circ}C[/tex]

Initial temperature,

[tex]t_I=23^{\circ}C[/tex]

Final equilibrium temperature,

[tex]T=150^{\circ}C[/tex]

Latent heat,

[tex]L_v=2260\times 10^3 \ J/Kg[/tex]

As we know,

The heat lost by the glowing piece of iron will be equal to the heat gain by the iron bucket as well as water, then

⇒ [tex]m_IC_I \Delta T=m_wC_w(100-23)+m_wL_v+m_bC_I(150-23)[/tex]

On substituting the given values, we get

⇒ [tex]42\times 420\times \Delta T=10\times 4186(100-23)+10(2260\times 10^3)+5\times 420(150-23)[/tex]

⇒ [tex]17640 \Delta T=3.22\times 10^6+2.26\times 10^7+2.667\times 10^5[/tex]

⇒          [tex]\Delta T=\frac{2.60867\times 10^7}{17640}[/tex]

⇒          [tex]\Delta T=1479^{\circ}C[/tex]

Compare and contrast the solar eclipse seen in this video to a lunar eclipse.

Answers

Answer: sadly, I can’t see the video. However, a lunar eclipse happens when the moon is hidden by the earth’s shadow. A solar eclipse occurs when the moon casts a shadow on the earth.

Explanation: I’m not completely sure if this is what you were looking for, but I hope it helps anyway.


a man pushed on the side ..

Answers

Answer:

B.will increase the maximum static friction between the box and the floor

Explanation:

Because static friction is the force that keeps an object at rest

A vibrating mass of 300 kg mounted on a massless support by a spring of stiffness 40,000 N>m and a damper of unknown damping coefficient is observed to vibrate with a 10-mm amplitude while the support vibration has a maximum amplitude of only 2.5 mm (at resonance). Calculate the damping constant and the amplitude of the force on the base.

Answers

Answer:

400 N

Explanation:

[tex]\text { Given: } m=300 \mathrm{~kg}, k=40,000 \mathrm{~N} / \mathrm{m}, \omega_{b}=\omega_{n}(r=1), X=10 \mathrm{~mm}, Y=2.5 \mathrm{~mm}[/tex] .

Find damping constant

[tex] \frac{X}{Y}=\left[\frac{1+(2 \zeta r)^{2}}{\left[\left(1-r^{2}\right)^{2}+(2 \zeta r)^{2}\right.}\right]^{1 / 2} \\ \left.\frac{10}{2.5}=\frac{\left\lceil 1+4\zeta^{2}\right]^{1 / 2}}{4 \zeta^{2}}\right] \\ 16=\frac{1+4 \zeta^{-2}}{4 \zeta^{2}} \\ \zeta^{2}=\frac{1}{60}=\frac{c^{2}}{4 k m} \\ c=\sqrt{\frac{4(40,000)(300)}{60}} \\ c=894.4 \mathrm{~kg} / \mathrm{s}[/tex]

Amplitude of force on base:

[tex]F_{T}=k Y r^{2}\left[\frac{1+(2 \zeta r)^{2}}{\left(1-r^{2}\right)^{2}+(2 \zeta r)^{2}}\right]^{1 / 2}[/tex]

substituting the values in above formula we get

F_T = 400 N

Riders in an amusement park ride shaped like a Viking ship hung from a large pivot are rotated back and forth like a rigid pendulum. At each end of the swing the ship hangs motionless for a moment before the ship swings down under the influence of gravity. Assume that this motionless point occurs when the bar connecting the pivot point and the ship is horizontal.

Required:
a. Assuming negligible friction, find the speed of the riders at the bottom of its arc, given the system's center of mass travels in an arc having a radius of 14.0 m and the riders are near the center of mass.
b. What is the centripetal acceleration at the bottom of the arc?
c. Draw a free body diagram of the forces acting on a rider at the bottom of the arc.
d. Find the force exerted by the ride on a 60.0 kg rider and compare it to her weight.
e. Discuss whether the answer seems reasonable.

Answers

Answer:

a)  v = 16.57 m / s, b)  a = 19.6 m / s², d)    N = 1.76 10³ N,     N / W = 3

Explanation:

This exercise looks interesting, but I think you have some problem with the writing, the questions seem a bit disconnected from the initial text.

Let's answer the questions.

a) For this part we can use energy considerations.

Starting point. The upper part of the trajectory indicates that the arm is horizontally

          Em₀ = U = m g h

in this case h = r

Final point. For lower of the trajectory

          Em_f = K = ½ m v²

as they indicate that there is no friction

         Em₀ = em_f

         mgh = ½ m v²

         v = [tex]\sqrt{2gh}[/tex]

let's calculate

        v = [tex]\sqrt{2 \ 9.8 \ 14.0}[/tex]

         v = 16.57 m / s

b) the centripetal acceleration has the formula

           a = v² / r

           a = 16.57² / 14.0

           a = 19.6 m / s²

c) see attached where the diagram is

where N is the normal and w the weight

d) let's use Newton's second law

               N-W = m a

               N - mg = m ar

               N = m (g + a)

let's calculate

               N = 60.0 (9.8 + 19.6)

               N = 1.76 10³ N

the relationship with weight is

              N / W = 1.76 10³/( 60 9.8)

              N / W = 3

normal is three times greater than body weight

e) the answer is reasonable since by Newton's first law the body must continue in a straight line, therefore to change its trajectory a force must be applied to deflect it

Which of the following represents a concave lens?
A. -di
B. +di
C. -f
D. +f

Answers

Answer:

The answer is option D. +f

Option D represents a concave lens. There are two types of lenses, one is a concave lens while the other is the convex lens.

What is the definition of a concave lens?

A concave lens deviates a direct beam from the source into a reduced form.  At minimum, one interior face of concave lenses is curved.

Because it is curved round inwards at the center and bulges outwards through the edges, causing the light to diverge, a concave lens is also known as a diverging lens.

It forms an upright , virtual picture both real and virtual pictures are formed from the concave lens.

The image formed from the positive side of the focus of the lens.+f shows the positive side of the focus of the lens.f is the focal length.

Hence, option D represents a concave lens

To learn more about the concave lens, refer to the link;

https://brainly.com/question/2919483

#SPJ2

The modern model of the atom describes electrons in a little less specific detail than earlier models did. Why is it that being less sure about the placement of electrons in an atom is actually an improvement over earlier models?
The plum pudding model of the atom states that

Answers

Answer:

It is because one cannot know exactly the position of the electron within the atom.

One formulation of Heisenberg's Uncertainty Principle tells us that one cannot know simultaneously  the position and momentum of the electron, so one cannot specify exactly either coordinate because the other would be infinite.

Bohr specified the most probable position of the electron at its lowest energy level in hydrogen and the product of the two would be about the Heisenberg value.  

D
If you increase the
frequency of a
wave, what
happens to the
speed?
G
A. It decreases.
B. It stays the same.
C. It increases.
D. It can increase or decrease.

Answers

Answer:

D

Explanation:

I think you got it right

The answer Is D!! Hope this helps

Please help !!!!!!!!!!!!

Answers

Answer:

152 Volts

Explanation:

First, the Resistors are in series. So, the net resistance, R = 3 + 4 +3 + 4 +5

= 19 ohms

Using, V = IR;

V (the needed P.D) = 8 x 19 = 152 Volts

will be needed to successfully transport 8 amps of current round the circuit

Answer:

4q

Explanation:

wait nvm i dont know

Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .
A force acts on a 1.5 kg , mass, giving it an acceleration of 3.0 m/s2 .
1. If the same force acts on a 3.0 kg mass, what acceleration would be produced?
2. What is the magnitude of the force?

Answers

Answer:

1) 1.5 m/s^2

2) 4.5 N

Explanation:

From Newton's Second Law of motion, we know

[tex]F=m*a[/tex]

Which states that to calculate the force acting on an object, you multiply its mass and acceleration.

So, we know an object of mass 1.5 kg has an acceleration of 3 m/s^2, then

[tex]F=m*a=1.5*3=4.5[/tex]

A force of 4.5 N is acting on the object.

If a force of 4.5 N acts on a mass of 3kg we have

[tex]a=\frac{F}{m}=\frac{4.5}{3}=1.5[/tex]

So, it would give it an acceleration of 1.5 m/s^2.

Roger drives his car at a constant speed of 80 km/hr. How far can he travel in 2 hrs. and 30 minutes?

Answers

Answer:

200 km/hr

Explanation:

Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.

80 x 2.5 = 200 km/hr.

Can I please have help

Answers

Answer:

it will usually increase

Explanation:

potato

18. Write conversion factors (as ratios) for the number of:
(a) yards in 1 meter
(b) liters in 1 liquid quart
(c) pounds in 1 kilogram

Answers

Answer:

Conversion tables show:

1 m = 1.09361 yds

1 Lit = .26418 gal = 1.05672 qt     or 1 qt = .944632 Lit

1 lb = .45359 kg = 2.2046 Lbs / Kg

So X yds = X  m * 1.09361 yds / m = 1.09361 * X yds

Likewise X Lit  = X  qt  / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632  X Lit

So X  Lbs =  X kg * 2.2046 Lbs / Kg = 2.2046 Lbs

Which of the following is an example of predation?

Answers

A. Owl is looking and attacking

Answer:

an owl hunts, catches, and consumes a field mouse for energy

Explanation:

Cartesian coordinate system is used for?​

Answers

Answer:

sorry not sure but i can try help with telling you this...

Explanation:

alls you havs to do is ask the internet and it will tell you

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