ANSWER
[tex]\frac{12}{100}[/tex]EXPLANATION
Now, imagine you are to divide something into 100 equal sections;
the 12th section of those sections is the twelve hundredths.
To represent this as a fraction we have 12/100.
Hence, the twelve hundredths as a fraction is 12/100.
Joan attended school for 2 weeks longer than 3/4 of the year. How long did Joan attend school? (Assume 52 weeks in a year.)
The duration Joan attended school is 41 weeks.
How to find how long she attend school?Joan attended school for 2 weeks longer than 3/4 of the year.
The time she attended school can be calculated as follows:
52 weeks = 1 year
3 / 4 of 52 = 156 / 4
3 / 4 of 52 = 39 weeks
Therefore, 3 / 4 of a year is 39 weeks.
She attended school 2 weeks longer than 3 /4 of the year(39 weeks).
Hence,
the duration she attended school = 39 + 2
the duration she attended school = 41 weeks
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I need some help finding slope from an equation-4y = 12+2x
Given the equation:
[tex]-4y=12+2x[/tex]To find the slope of the equation, solve the equation for (y)
It is required to make the equation like the slope-intercept form
[tex]y=mx+b[/tex]So, for the given equation, divide all terms by (-4)
So,
[tex]\begin{gathered} \frac{-4y}{-4}=\frac{12}{-4}+\frac{2x}{-4} \\ \\ y=-3-\frac{1}{2}x \\ \\ y=-\frac{1}{2}x-3 \end{gathered}[/tex]compare the last result with the slope-intercept form
So, the slope = m = -1/2
So, the answer will be:
[tex]\text{slope}=-\frac{1}{2}[/tex]y=tan(x/8) Find the period, x intercepts, and vertical asymptotes
Given:
[tex]y=\tan(\frac{x}{8})[/tex]Find-: Period, x-intercepts, and vertical asymptotes.
Sol:
Graph of function is:
The period of the function is:
[tex]\text{ Period}=8\pi[/tex]The x-intercept of function is:
For the x-intercept value of "y" is zero so,
[tex]\begin{gathered} y=\tan(\frac{x}{8}) \\ \\ \tan(\frac{x}{8})=0 \\ \\ \frac{x}{8}=\tan^{-1}(0) \\ \\ x=8\tan^{-1}(0) \\ \\ x=-8\pi,0,8\pi,16\pi...... \end{gathered}[/tex]Vertical asymptotes are:
For the function can't find vertical asymptotes.
Kurt bought a vacant lot in a development that was 85% completed. When he started
working with the builder to lay out where the house and driveway would lie, it was
determined that he would need an easement because his driveway would spill over onto
the adjacent lot by a few feet. What type of easement is this?
Easement appurtenant
Easement by necessity
Easement by prescription
Easement in gross
This is a case of easement appurtenant
What is easement?
An easement is a nonpossessory right to use and/or enter another's real property without owning it. It is "best shown by a right of way that one landowner, A, may have over the land of another, B." In most countries, an easement is a property right and sort of incorporeal property in and of itself. Real covenants and equitable servitudes are analogous to easements. The Restatement (Third) of Property in the United States attempts to integrate these notions as servitudes. Easements are useful for allowing persons to access other properties or resources by granting access across two [further explanation needed] or more pieces of property.
This is a case of easement appurtenant
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Josh wants to make the lamp purple.
He will use dye to make the plastic purple.
Josh will mix red dye with green dye and blue dye in the ratio 9:3:15 to make
purple dye.
Josh uses 30 litres of green dye.
(b) How many litres of purple dye will Josh make with the 30 litres of green dye?
Show a check of your working.
(5)
Answer:
Step-by-step explanation:
since 30 liters is ten times 3 liters, you must mulitply all of the amounts of dye liters (not green because we know its 30) by 10. this would make a ratio of 90:30:150. Now, add them all up to equal 270 liters of purple dye in total.
the sugar sweet company is going to transport its sugar to market. it will cost $3250 to rent trucks, and it will cost andl additional $125 for each ton of sugar transported.let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. write and equation relating C to S and then graph your equation.
The variables are
C: total cost ($)
S: amount of sugar (tons)
The equation that relates these two variables is;
C = 3250 + 125S
The graph of the equation is:
where C is the dependent variable, and S is the independent variable
8.4m^9n^5 divided by 2.1m^3n^5
Answer: [tex]4m^{6}[/tex]
Step-by-step explanation:
[tex]\frac{8.4m^{9} n^{5} }{2.1m^{3}n^{5}}[/tex]
Dividing exponents is the same as subtracting the exponents, so
[tex]\frac{m^{9}}{m^{3}} =m^{9-3}=m^{6}[/tex]
[tex]\frac{n^{5}}{n^{5}} =n^{5-5}=n^{0}=1[/tex]
So now our equation looks like
[tex]\frac{8.4m^{6}}{2.1}[/tex]
Now we can divide the numbers
8.4/2.1 = 4
So your final answer is [tex]4m^{6}[/tex]
find the number of units of grain that are to be produced to maximize the profit if…
we need to make revenue-cost and then maximize
[tex]\begin{gathered} R(x)-C(x) \\ (97x-2x^2)-(2x^2+49x+6) \end{gathered}[/tex]simplify
[tex]\begin{gathered} =97x-2x^2-\mleft(2x^2+49x+6\mright) \\ =97x-2x^2-2x^2-49x-6 \\ =-2x^2-2x^2+97x-49x-6 \\ =-4x^2+97x-49x-6 \\ =-4x^2+48x-6 \end{gathered}[/tex]now, to maximize, we need to find the derivate and make it equal to 0
[tex]\begin{gathered} \frac{d}{dx}(-4x^2+48x-6)=0 \\ -8x+48=0 \\ -8x=-48 \\ \frac{-8x}{-8}=\frac{-48}{-8} \\ x=6 \end{gathered}[/tex]so, the maximum profit is at x = 6
Based on the density graph below, what is the probability of a value in thesample space being anywhere from 15 to 20?
Given
Density graph
Find
Probability of the value in the sample space being anywhere from 15 to 20
Explanation
from density graph , we cna get the distribution is uniform.
so , the probability of the value in the sample space being anywhere from 15 to 20 will be
[tex]\begin{gathered} p=\frac{20-15}{25-0} \\ \\ p=\frac{5}{25} \\ \\ p=0.2\approx20\% \end{gathered}[/tex]Final Answer
Hence , the correct option is D
Liz bought seven liters of orange juice for a party. About how many quarts of juice did she buy?
Let's make a conversion:
[tex]7l\times\frac{1.05669qt}{1l}=7.39683qt\approx7.40qt[/tex]She bought about 7.39683qt
Liz bought 7.396817 quarts of orange juice for a party.
What are Quarts?The liquid quart in the United States is a measure of fluid volume equal to one-fourth of a gallon, two pints, or four cups. The liquid quart is not to be confused with the dry quart (US) or the imperial quart, which are two distinct units.
Multiply the volume by the conversion ratio to transform a liter measurement into a quart measurement.
Since each liter equals 1.056688 quarts, you may use the following easy formula to convert:
quarts = liters × 1.056688
The volume in quarts is equal to the liters multiplied by 1.056688.
We have been given that Liz bought seven liters of orange juice for a party.
We have to convert 7 liters to quarts using the formula above.
7 L = (7 × 1.056688) = 7.396817 qt
Thus, she bought 7.396817 quarts of orange juice for a party.
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(d) Find the domain of function R. Choose the correct domain below.
Answer:
Answer:
d
Step-by-step explanation:
The number of years must be non-negative.
This eliminates all of the options except for d.
The function f(x)= -200x+1000 represents the altitude (in feet) of a paraglider x minutes from the time the paraglider begins a descent to a landing site located 100 feet above sea level. Identify the slope, domain, and range.
The slope of the Function is -200, the domain of the function is any real value of x and the range of the function is [1000,∞).
The provided function is,
f(x) = -200x+1000
This function is representing the altitude of a paraglider and time from where the paraglider descent. Here, x is representing time in minutes.
The landing site is located at the depth of 1000 feet.
we can write the function as,
y = -200x + 1000
Here, y is the range of the function.
As we observes the function, it is an equation of line,
So, the slope is equal to the coefficient of x.
So the slope is -200.
The domain is any value of x for which the function is defined,
as this it an equation of line,
The domain would be any real value of x.
The range is the output that we get after putting value of x.
Here,
Put x = 0.
y = -200(0)+1000
y = 1000
Now. putting x = -1,
y = -200(-1) + 1000
y = 1200.
Putting any negative value of x will make y positive,
So, the range will be [1000,∞)
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what are three consecutive integers that add to 40
Answer:
12 1/3 + 13 1/3 + 14 1/3 = 40
Step-by-step explanation:
Here we will use algebra to find three consecutive integers whose sum is 40. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 40. Therefore, you can write the equation as follows:
Diego is thinking of two positive numbers. He says, “If we triple the first number and double the second number, the sum is 34.”
Write an equation that represents this clue. Then, find two possible pairs of numbers Diego could be thinking of.
Diego then says, “If we take half of the first number and double the second, the sum is 14.”
Write an equation that could represent this description.
What are Diego’s two numbers? Explain or show how you know. A coordinate plane is given here, in case helpful.
The equation that represent the situation is as follows;
3x + 2y = 34
1 / 2x + 2y = 14
The two number Diego is thinking of are 8 and 5.
How to use equation to represent a problem?He is thinking of two positive numbers.
If we triple the first number and double the second number, the sum is 34.
If we take half of the first number and double the second, the sum is 14.
Therefore, the equation that can be used to solve the situation is as follows:
let
x = first number
y = second number
3x + 2y = 34
1 / 2x + 2y = 14
Therefore,
3x + 2y = 34
1 / 2x + 2y = 14
5 / 2 x = 20
5x = 40
x = 40 / 5
x = 8
3(8) + 2y = 34
2y = 34 - 24
2y = 10
y = 10 / 2
y = 5
Therefore, the two numbers are 8 and 5.
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3.1 x 10^3 in scientific notation
Answer:3100
Step-by-step explanation:
If 3.1 x 10^3 is because you count the first number and then you use what is less in the power like you have 3 and u used 1 for the number 1 so you left with 2 those 2 will be zeros 3100.
I hope this helped pls put it as brainliest
Answer: 3.1 × 103
Step-by-step explanation:
A family has 5 children. Assume that each child is as likely to be a boy as it is to be a girl. Find the probability that the family has 5 girls if it is known that the family's first child is a girl.
The required probability is 1/31 that the family has 5 girls if it is known that the family's first child is a girl.
What is probability?Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.
Let us express every possible set of 5 children as a 5-letter word made up of the letters G or B. (G for a girl and B for a boy).
In all, 2⁵ = 32 such words are outcomes, with two options for each of the five slots.
The constraint "if it is known that the family contains at least one female" suggests that we would evaluate the reduced space of all such words, except the word (BBBBB).
This reduced event space is made up of 32-1 = 31 elements.
There is just one such term in the favorable collection of events (GGGGG).
As a result, the probability for the question is P = 1/31.
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Alyssa's algebra test score was 8 points lower than Jennifer's. The total of their two tests was 180. What did each girl receive?
Based on the equation, each girl received the following Algebra test scores:
Alyssa's = 86 pointsJennifer's = 94 points.What is an equation?An equation is a mathematical expression that claims that two values are equivalent.
Equations use the equation symbol (=) to illustrate the equality of two or more expressions.
Algebraically, let Alyssa's algebra test score = x
Let Jennifer's test score = x + 8
The total of their two tests = 180
x + x + 8 = 180
2x + 8 = 180
2x = 180 - 8
2x = 172
x = 86 (172/2)
Alyssa's test score = 8 points lower
Shareable points = 172 (180 - 8)
Each received 86 points from the shareable points
Alyssa's test score = 86 points
Jennifer's test score = 94 points
Check:
86 + 94 = 180
94 = 8 points greater than 86
Thus, using an equation, we can conclude that Alyssa scored 86 points on the Alegra test, which is 8 points less than Jennifer's 94 points.
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Which equation below would produce thefollowing graph?A) f(2)=-(2+4)(3-1)(-5)B) f(z) = (2+4)(z-1)(-5)C) f(3) = (2-4)(2+1)(2+5)D) f(3) = -(2-4)(2+1)(2+5)
If we take the first option of the question, we have the following zeros or points passing through the x-axis:
[tex]f(x)=-(x+4)\cdot(x-1)\cdot(x-5)=0[/tex][tex]x+4=0,x-1=0,x-5=0[/tex]We then have:
[tex]x=-4,x=1,x=5[/tex]These points coincide with the ones in the graph.
The expansion of this equation is:
[tex]f(x)=-x^3+2x^2+19x-20_{}[/tex]If we give some points to the equation at points x = -6, x = -3, x = 0, x = 3, x = 6, we have:
f(-6) = 154
f(-3) = -32
f(0) = -20
f(3) = 28
f(6) = -50
And all these values adjust to the proposed graph.
Therefore, the equation for option A would produce the proposed graph.
This is a way to solve this question. We can also make use of the derivatives of the first or of the second-order to find if this equation produces this graph.
Please help (There are two parts to this question you have to graph and then find the slope)
From the given graph,
The line representing the rise and the line representing the run on the given graph can be seen below
To find the slope, m, of a straight line, the formula is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Taking points from the graph
A company claims that each bag of pretzels weighs 11.3 oz. A sample of 37 bags was weighed. The mean weight of these bags was 11.05 oz, with a standard deviation of 1.35 oz Test the hypothesis at a 5% level of significance.A. Reject the null hypothesis. There is enough evidence to oppose the company's claim.B. Fail to reject the null hypothesis. There is enough evidence to oppose the company's claim.C. Fail to reject the null hypothesis. There is not enough evidence to oppose the company's claim.D. Reject the null hypothesis. There is not enough evidence to oppose the company's claim.
Solution
[tex]\begin{gathered} H_0\colon\mu=11.03 \\ \\ H_1\colon\mu=11.05 \\ \\ z=\frac{11.03-11.05}{1.35} \\ \\ Z_{\text{score}}=0.98803>0.05 \end{gathered}[/tex]C. Fail to reject the null hypothesis. There is not enough evidence to oppose the company's claim.
an item is regularly priced at $33. it is now priced at a discount of 85% off the regular price
Answer: The item should now cost $4.95 if that is the question
Step-by-step explanation:
15% of 33 is 4.95 giving you the answer of 4.95 hope this helps
Indicate whether the following statements are True (T) or False (F). 1. The product of two real numbers is always a real number. 2. The quotient of two real numbers is always a real number (provided the denominator is non-zero). 3. The ratio of two real numbers is never zero. 4. The difference of two real numbers is always a real number. 5. The sum of two real numbers is always a real number. 6. The quotient of two real numbers is always a rational number (provided the denominator is non-zero). 7. The difference of two real numbers is always an irrational number.
The required answer is true, false, true, false, true, true, and false for statements 1, 2, 3, 4, 5, 6, and 7 respectively.
The product of two real numbers is always a real number is true.
The quotient of two real numbers is always a real number (provided the denominator is non-zero) is false because when you divide, you get the quotient, and when you divide, you might get decimals.
The ratio of two real numbers is never zero is true.
The difference of two real numbers is always a real number is false because it could be a decimal.
The sum of two real numbers is always a real number is true.
The quotient of two real numbers is always a rational number (provided the denominator is non-zero) is true.
The difference of two real numbers is always an irrational number is false.
Therefore, the required answer is true, false, true, false, true, true, and false for statements 1, 2, 3, 4, 5, 6, and 7 respectively.
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for any numbers x,y [x=0 in(4) and y = 0 in (5)] and any positive integers m,n, the following holds:x^m · x^n=x^m+nProve number 1
Proved
Explanation:
To prove x^m · x^n=x^m+n, let's assign numbers to x, m and n
let x = 2
m = 3, n = 4
x^m · x^n = 2^3 . 2^4
x^m+n = 2^(3+4)
Solve each of the above seperately and comparew the answer:
[tex]\begin{gathered} x^m\times x^n=2^3\times2^4 \\ =\text{ (2}\times2\times2)\times(2\times2\times2\times2) \\ =\text{ 8}\times16 \\ =\text{ }128 \end{gathered}[/tex][tex]\begin{gathered} x^{m+n}=2^{3+4} \\ =2^7\text{ = 2}\times2\times2\times2\times2\times2\times2 \\ =\text{ 128} \end{gathered}[/tex][tex]\begin{gathered} sincex^m\times x^n\text{ = 128} \\ \text{and x}^{m+n}\text{ = 128} \\ \text{Therefore, }x^m\times x^n\text{ = x}^{m+n} \end{gathered}[/tex]This expression x^m · x^n=x^m+n has been proved to be equal
A. Find f(1/2 pie)
B. Find the all values x when f(x)=0. Use a comma to separate each value.
C. Fine the range. Write it in Interval notation.
Answer:
A. [tex]f(\frac{1}{2}\pi)=2[/tex]
B. [tex]x=-2\pi, -\pi, 0, \pi, 2\pi[/tex]
C. [tex][-2, 2][/tex]
Step-by-step explanation:
A:
Since we want to find: [tex]f(\frac{1}{2}\pi)[/tex], all we do is go that that x-value on the function and then go either up or down until we find where the y-value is at that x-value, because [tex]f(\frac{1}{2}\pi)[/tex] is just another way of expressing "the y-value of the function f, at [tex]x=\frac{1}{2}\pi[/tex]
In this case it turns out that the y-value is two, which you can verify by going to that x-value and finding where the y-value is at that point.
So: [tex]f(\frac{1}{2}\pi)=2[/tex]
B.
To find all the x-values such that: [tex]f(x)=0[/tex], we just need to find where the graph crosses the x-axis, also known as an x-intercept. This is because at an x-intercept, the y-value will be equal to zero.
Looking at the graph you can see that these x-intercepts occur at: [tex]x=-2\pi, -\pi, 0, \pi, 2\pi[/tex]
in general you'll notice that all the values are actually separated by a value of pi, so the general formula for a zero in this equation is likely going to be: [tex]x=\pi n\text{ where n is an integer}[/tex], since trigonometric functions are periodic, they repeat.
C.
Looking at the graph you'll notice the value is increasing, then decreasing, then increasing... and so on.
The max value it reaches is two, and the min value it reaches is negative two.
The range of a function is the y-values that the function can output, considering all the possible inputs, or the domain.
In this case no matter the input we can only output values between -2 and 2.
In this interval notation, we use brackets, since the minimum and maximum possible values are included in the range, since the function does output 2 and -2, it doesn't just "approach" it.
So we get a range of: [tex][-2, 2][/tex]
On a map, a museum is located at (15, 17). A library is located at (15, -2). How many units away museum from the libraryA. 2 unitsB. 13 unitsC. 17 unitsD. 19 units
Let's look at the locations of the library and museum in a coordinate plane:
The museum is "17" units above the x-axis.
The library is "2" units below the x-axis.
The total units between the museum and library is 17 + 2 = 19 units
Thus, the distance between the museum and library is 19 units.
Correct Answer:
D
Solve the system algebraically. Make sure that any points you name satisfy both equations.
Write out the two equations given
[tex]\begin{gathered} y=-x^2+5=====(\text{equation 1)} \\ -x+y=3======(\text{equation 2)} \end{gathered}[/tex]Make y the subject of equation 2
[tex]\begin{gathered} -x+y=3 \\ y=3+x====(\text{equation 3)} \end{gathered}[/tex]Since y is equal to y, then equations 1 and 3 are equal
[tex]\begin{gathered} y=-x^2+5 \\ y=3+x \\ y=y \\ -x^2+5=3+x \\ x^2+x+3-5=0 \\ x^2+x-2=0 \end{gathered}[/tex][tex]\begin{gathered} x^2-x+2x-2=0 \\ x(x-1)+2(x-1)=0 \\ (x-1)(x+2)=0 \\ x-1=0,x=1 \\ \text{or} \\ x+2=0,x=-2 \end{gathered}[/tex]Substitute x into equation 3
[tex]\begin{gathered} y=3+x \\ \text{when x=1} \\ y=3+1=4(1,4) \\ \text{when x=-2} \\ y=3+(-2) \\ y=3-2=1(-2,1) \end{gathered}[/tex]Hence, the coordinates of the solution are (1,4) (-2,1)
What is anequation of the line that passes through the points (-4, -1) and(6, -1)?
We are given the following two points
[tex](-4,-1)\text{and }(6,-1)[/tex]We are asked to find the equation of the line that passes through these points.
Recall that the equation of the line in slope-intercept form is given by
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
The slope of the line is given by
[tex]m=\frac{y_2−y_1}{ x_2−x_1}[/tex][tex]\text{where}(x_1,y_1)=(-4,-1)\text{and}(x_2,y_2)=(6,-1)[/tex]Let us substitute the given values into the slope formula
[tex]m=\frac{-1-(-1)}{6-(-4)}=\frac{-1+1}{6+4}=\frac{0}{10}=0[/tex]So, the slope of the equation is 0
The equation of the line becomes
[tex]y=0x+b[/tex]Now let us find the y-intercept (b)
Choose any one point from the given two points
Let choose (-4, -1) and substitute it into the above equation
[tex]\begin{gathered} y=0x+b \\ -1=0(-4)+b \\ -1=0+b \\ b=-1 \end{gathered}[/tex]Therefore, the equation of the line in slope-intercept form is
[tex]y=-1[/tex]Note that this equation has 0 slope that is why mx part becomes 0
If g(x) = 5(x²+1) + 16, what is the value of g(11) ?
Answer:
626
Step-by-step explanation:
11^2= 121
121+1=122
122x5=610
610+16=626
hope this helped
which of the following are point-slope equations of the line going through (-2,-2) and (2,1) check all that apply
The Point-Slope form of the equation of a line is:
[tex]y_{}-y_1=m(x-x_1)_{}[/tex]Where "m" is the slope of the line and this is a point on the line:
[tex](x_1,y_1)[/tex]You can find the slope of a line using this formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, knowing that this line passes through these points:
[tex](-2,-2);\mleft(2,1\mright)[/tex]You can set up that:
[tex]\begin{gathered} y_2=-2 \\ y_1=1 \\ x_2=-2 \\ x_1=2 \end{gathered}[/tex]Substituting values into the formula and evaluating, you get:
[tex]m=\frac{-2-1}{-2-2}=\frac{-3}{-4}=\frac{3}{4}[/tex]Knowing the slope and coordinates of two points on the line, you can set up these two equations for this line:
1. First equation:
[tex]\begin{gathered} y-(-2)=\frac{3}{4}(x-(-2)) \\ \\ y+2=\frac{3}{4}(x+2) \end{gathered}[/tex]2. Second equation:
[tex]y-1=\frac{3}{4}(x-2)[/tex]The answers are: Option A and Option B.
Danielle owes $13.80 for text messaging in the month of March. If her text messaging plan costs $9 forthe first 550 messages and 20¢ for each additional text message, how many text messages did shesend that month?AnswerKeypadKeyboard Shortcutstext messages
Given
Danielle owes $13.80 for text messaging in the month of March.
If her text messaging plan costs $9 for the first 550 messages and 20¢ for each additional text message.
To find the number of text messages did she send that month.
Now,
Let x be the number of text messages she send that month.
Then, from the given data,
[tex]x=550+\frac{13.8-9}{0.20}[/tex]Since 20cents is $0.20.
Then,
[tex]\begin{gathered} x=550+\frac{13.8-9}{20}\times100 \\ =550+\frac{4.8\times100}{20} \\ =550+4.8\times5 \\ =550+24 \\ =574 \end{gathered}[/tex]Hence, the number of text messages send by her is 574.