Answers
We will have the following:
[tex]\begin{cases}I=r^2m \\ \\ L=I\omega \\ \\ \omega=v/r\end{cases}[/tex]So:
We will find the data we can with the given information:
[tex]\omega_1=\frac{0.3m/s}{0.2m}\Rightarrow\omega=\frac{1.5}{s}[/tex]Also:
[tex]I\omega_1=I\omega_2\Rightarrow\omega_1=\omega_2[/tex]So:
[tex]\frac{1.5}{s}=\frac{v}{0.03m}\Rightarrow v=0.045m/s[/tex]So, the velocity at the bottom of the funnel is 0.045m/s.
Related Questions
A planet has mass M and radius 2R.
a) Derive an expression for the escape speed from the planet.
b) A projectile of mass m is shot directly away from the surface of the planet at ⅓ of the escape
speed from the planet. Derive an expression for the maximum distance from the center of the
planet the projectile reaches, in terms of R. Simplify as far as possible. (Ignore the existence of
all other celestial objects.)
Answers
The escape velocity of the planet is [tex]\sqrt{gR\\}\\[/tex] when mass is M and radius is 2R.
In astronomy and space research, escape velocity refers to the speed at which a body can leave a gravitational field without being further accelerated. It is given be the expression ,[tex]v_{e} = \sqrt{2gR}[/tex]
Where, Ve is the escape velocity, g is gravity , and R is the radius of the earth.
If a planet has mass M and radius 2R then an expression for the escape velocity from the planet can be calculated as,
[tex]v_{e} = \sqrt{(2GM)/R[/tex]
Here, G is the gravitational force of the planet therefore Newton's law of gravitational force can be used as,
g = GM/R²
gR²= GM
Thus, with the help of above equations the escape velocity of the planet can be calculated when mass is M and radius is 2R i.e.
[tex]v_{e} = \sqrt{(2GM)/2R[/tex]
[tex]v_{e} = \sqrt{(2GR)/2R[/tex]
[tex]v_{e} = \sqrt{gR[/tex]
Therefore , the escape velocity of planet is equal to the root of gravity g and radius R .
To know more about escape velocity
https://brainly.com/question/13984830
#SPJ1
If your 1000 kg car ran out of gas and you had to push it into the gas station with a
force of 50 N, what would the acceleration of the car be?
Answers
Answer:
a=0.05m/s²
Explanation:
force=mass × acceleration
f=ma
f=50N
m=1000kg
a=?
50=1000×a
50=1000a
a=50/1000
a=0.05m/s²
please rate as brainliest
What is the average velocity of a car driving down the highway if it’s displacement is 123m west during a time period of 14.0s
Answers
The average velocity of a car driving down the highway if it’s displacement is 123 m west during a time period of 14.0 s is 8.79 m/sec.
What is Velocity?The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity. Unit of velocity is m/sec.
Given in the question a car driving down the highway it’s displacement is 123 m west during a time period of 14.0 s then the average velocity is given as,
Average velocity = displacement / time
= 123/14
= 8.79 m/sec
The average velocity of a car driving down the highway if it’s displacement is 123 m west during a time period of 14.0 s is 8.79 m/sec.
To learn more about velocity refer to the link:
brainly.com/question/18084516
#SPJ1
A bicycle and rider going 15 m/s approach a hill. Their total mass is 66 kg.
(a) What is their kinetic energy?
7425 J
(b) If the rider coasts up the hill without pedaling, how high above its starting level will the bicycle be when it finally rolls to a stop?
Need help with B Please help!!
Answers
a)The kinetic energy is 7425 J.
b) Theight at which the bicycle starts is 1147 m.
For the given problem, we are dealing with kinetic and potential energy, where Kinetic energy is the energy an object has since its movement. On the off chance that we need to accelerate an object, at that point we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed,However when its position is modified from its regular equilibrium position, the bow is able to store energy by virtue of its position. This put-away energy of position is alluded to as potential energy. Potential energy is the stored energy of position had by an object.
Since we were given a mass which is 66 kg and a velocity of 15 m/s
Since the formula of kinetic energy is:
K.E= (1/2)mv², where m is the mass of the object and v is the velocity of the object moving .
= 1/2 (66)(15 m/s)²
=7425 J
For the second part the kinetic energy is converted to the potential energy, so the formula for the potential energy is
P.E = mgh, where m is the mass , g is the acceleration due to gravity and h is the height at which the object.
=7425 J =mgh
=>h= 7425/(mg)
=>h =7425/66*15
=>h =11.47 m
To know more about kinetic energy refer to the link https://brainly.com/question/12669551?referrer=searchResults.
#SPJ1
Please list two materials that are conductors and two materials that are insulators.
Answers
Two materials that are conductors - silver, copper
Two materials that are insulators - rubber, dry wood
Each set of protons and electrons represents a different atom. Place the atoms in order of their overall charge. Order them from most positive to most negative.swap_vert22 protons, 18 electronsswap_vert12 protons, 10 electronsswap_vert17 protons, 10 electrons
Answers
Protons have positive charge
Electrons have negative charge
• 22 protons (+22) + 18 electrons (-18 )
22 - 18 = 4 (positive)
• 12 -10 = 2
• 17 - 10 = 7
• 2 - 1 = 1
From most positive to most negative overall charges.
7 - 4 - 2 - 1
A hollow, spherical shell with mass 2.00 kg rolls without slipping down a 33.0 ∘ slope.
Find the acceleration.
Find the friction force.
Answers
The acceleration of the spherical shell is determined as 6.37 m/s².
The friction force is 12.74 N.
What is the coefficient of friction of the surface?
The coefficient of friction of the surface is calculated as follows;
Fsinθ = μFncosθ
where;
F is the applied force on the spherical shellFn is the weight of the spherical shellmg(sin θ) = (μmg) cosθ
(sin θ) = μ cosθ
μ = sinθ/cos θ
where;
g is acceleration due to gravityθ is angle of inclination of the slopeμ = tan θ
μ = tan(33)
μ = 0.65
The acceleration of the spherical shell is calculated as;
a = μg
a = 0.65 x 9.8 m/s²
a = 6.37 m/s²
The frictional force is calculated as follows;
Ff = μmg
Ff = 0.65 x 2 x 9.8
Ff = 12.74 N
Learn more about friction force here: https://brainly.com/question/24338873
#SPJ1
Explain how a $10.00 compact fluorescent light bulb (15 W) can be an overall money saver compared to an incandescent light bulb (60 W) that costs $0.50.
Answers
Answer:
Explanation:
We would consider the kilowatt hour for both bulbs. It is the energy consumed by an appliance per hour.
Recall, 1 kw = 1000w
15w = 15/1000 = 0.015 kw
60w = 60/1000 = 0.06kw
In 1 hour,
1)
The 15 W bulb would consume 0.015 kw.
For 10 hours per day, the consumption is 0.015 x 10 = 0.15kw
For a month of 30 days, the consumption is 0.15 x 30 = 4.5
Let's assume that the charge per KW is $0.2
Consumption cost per month = 0.2 x 4.5 = $0.9 per month
2)
The 60 W bulb would consume 0.06 kw.
For 10 hours per day, the consumption is 0.06 x 10 = 0.6kw
For a month of 30 days, the consumption is 0.6 x 30 = 18
Let's assume that the charge per KW is $0.2
Consumption cost per month = 0.2 x 18 = $3.6 per month
Thus, the 15W bulb would be an overall money saver as time goes on.
A 1800 kg object moving to the east at 13 m/s, collided with a 200 kg object that was moving to the north at 32 m/s. What was the angle of motion
Answers
. A circular loop of wire of area 10 cm2 carries a current of 25 A. At a particular instant, the loop lies in the xy-plane and is subjected to a magnetic field B=(2.0iˆ+6.0jˆ+8.0kˆ)×10−3T. As viewed from above the xy-plane, the current is circulating clockwise. (a) What is the magnetic dipole moment of the current loop? (b) At this instant, what is the magnetic torque on the loop?
Answers
The magnetic dipole moment of the current loop is 0.025 Am².
The magnetic torque on the loop is 2.5 x 10⁻⁴ Nm.
What is magnetic dipole moment?The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.
Mathematically, magnetic dipole moment is given as;
μ = NIA
where;
N is number of turns of the loopA is the area of the loopI is the current flowing in the loopμ = (1) x (25 A) x (0.001 m²)
μ = 0.025 Am²
The magnetic torque on the loop is calculated as follows;
τ = μB
where;
B is magnetic field strengthB = √(0.002² + 0.006² + 0.008²)
B = 0.01 T
τ = μB
τ = 0.025 Am² x 0.01 T
τ = 2.5 x 10⁻⁴ Nm
Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.
Learn more about magnetic dipole moment here: https://brainly.com/question/13068184
#SPJ1
The diagram shows what happens when a polythene rod is rubbed with a dry cloth. Select the statements that are true
Answers
When a polythene rod is rubbed with a dry cloth, the dry cloth loses electrons, the polythene rod gains electrons and the dry cloth is left with positive charge.
The electrons on the dry cloth's surface move to the polyethene rod when it is brushed against a polythene rod. It is considered to be negatively charged because more electrons have accumulated within the polythene rod as a result of the rod being electron rich and the electrons moving there.
The amount of electrons inside the cloth has dropped, making the cloth electron-deficient. It is referred to as positively charged because of this.
To know more about Charging by Rubbing, visit,
https://brainly.com/question/26375737
#SPJ9
The process of charging a capacitor consists of transferring charge from the plate at lower ____ to the plate at higher one
Answers
The process of charging a capacitor consists of transferring charge from the plate at lower potential to the plate at higher one (higher potential).
What steps are involved in charging a capacitor?When a battery is connected in series with a resistor and capacitor, a large initial current flows when the battery moves charge from one capacitor plate to the other. As the capacitor charges to the battery voltage, the charging current asymptotically decreases until it is zero.
Therefore, a unidirectional flow of electric charge is known as direct current. When the voltage from the power source matches the voltage at the capacitor terminals, the capacitor is fully charged. When the electrical circuit's current stops flowing, the charging phase of the capacitor is complete.
Learn more about capacitor from
https://brainly.com/question/14883923
#SPJ1
A ball is orbits in a circle of radius 10m with a speed 50 m/s. What is its angular velocity?
Answers
The angular velocity of the ball orbiting in circle will be 5 rad/s.
What is angular velocity?Angular velocity describes the rate at which an object rotates.
Given is a ball that orbits in a circle of radius 10m with a speed of 50 m/s.
The relation between the linear and angular velocity of a body is given by-
v = rω
where -
v is the linear velocity
r is the radius
ω is the angular velocity
On substituting the values, we get -
50 = 10 x ω
ω = 50/10
ω = 5 rad/s
Therefore, the angular velocity of the ball orbiting in circle will be
5 rad/s.
To solve more questions on Circular motion, visit the link below-
https://brainly.com/question/14276874
#SPJ1
If the actual release height is 2 h , calculate the normal force exerted by the track at the bottom of the loop.
Answers
The normal force exerted by the track at the bottom of the loop is F = m(v²/h + g).
What is the force exerted at the bottom of the loop?
The normal force at the bottom of a loop, is determined from two opposite forces.
One is reaction to weight and other is from reaction of centripetal force which is due to the curvature of the track.
The normal force exerted at the bottom of a circular loop is calculated as follows;
F = ma + mg
where;
a is the centripetal acceleration of the objectm is mass of the objectg is acceleration due to gravityF = m(v²/r) + mg
where;
v is the velocity of the objectr is the radius of the loopif the release height of the object = 2h
then, the radius of the track = 2h/2 = h
F = m(v²/h) + mg
F = m(v²/h + g)
Thus, the normal force exerted by the track at the bottom of the loop depends on the weight of the object and centripetal force.
Learn more about centripetal force here: https://brainly.com/question/20905151
#SPJ1
. What are the velocities of sound waves in air, helium, and carbon dioxide? Show your data. Which was the fastest? Why do sound waves travel at different speeds in each gas? Explain. Note that the values for helium will be incomplete in these frequency ranges.
Answers
Answer:
Taking into account the table we get that, for n = 2, the velocities of sound waves are
Velocity on air: 267.3 m/s
Velocity on helium: 260 m/s
Velocity of carbon dioxide: 829.3 m/s
The velocity of the sound travels at different speeds in each gas because the velocity depends on the properties of the medium like the density. Since the air, helium, and carbon dioxide have different densities, the sound speed will be different.
A projectile is thrown at an angle 30° from horizontal. Which statement about its vertical component of velocity is true?
Answers
The true statement is the vertical component of the velocity is half of the magnitude of the velocity.
What is vertical component of velocity?
The vertical component of a velocity is the velocity of the object acting along vertical direction.
The vertical component of the velocity acting along the vertical direction is calculated as follows;
Vy = V sinθ
where;
Vy is the vertical component of the velocityθ is the angle of projectionV is the magnitude of the velocitySubstitute the value of the angle of projection and evaluate the vertical component of the velocity.
Vy = V sin(30)
Vy = V(0.5)
Vy = ¹/₂V.
Thus, the vertical component of the velocity is half of the magnitude of the velocity.
Learn more about vertical component of velocity here: https://brainly.com/question/24949996
#SPJ1
The complete question is below
A projectile is thrown at an angle 30° from horizontal. Which statement about its vertical component of velocity is true?
the vertical component of the velocity is half of the magnitude of the velocitythe vertical component of the velocity is one-third of the velocitythe vertical component of the velocity is the same as the magnitude of the velocity.Help I am so confused on what to do with theses steps to get the answer.
Step 1 convert all the dimensions of the box from cm to m
Step 2 calculate the maximum buoyant force if the box was completely submerged. Fb = pfluid V g
Step 3 calculate the Fg of the box Fg = mg
Step 4 Subtract the Fg from the Fb to get the Force of gravity from extra mass
Step 5. Use the Fg from extra mass =mg equation to solve for mass. Using
Answers
The buoyant force if the box was completely submerged is 93.84 N.
The length of the box is 40.8 cm.
The height of the box is 10.4 cm and the depth of the box is 19 cm.
Now we know,
1 m = 100 cm
So,
1 cm = 0.01 m
Therefore,
Length, L = 40.8 cm = 40.8 × 0.01 = 0.408 m
Height, H = 10.4 cm = 10.4 × 0.01 = 0.104 m
Depth, D = 19 cm = 19 × 0.01 = 0.19 m
The density of the fluid is 1187 kg/m³.
ρ = 1187 kg/m³ = 1187 × 10³ g/m³
The mass of the box, m = 2325.4 g
The maximum buoyant force will be:
F = ρgV
Here g = 1 g cc
Therefore,
F = 1187 × 1 × ( 0.408 × 0.104 × 0.19 )
F = 93.846590 N
Learn more about buoyant force here:
brainly.com/question/17009786
#SPJ1
A 7 lb bowling ball accelerates at a rate of 7 m/s2.
Answers
According to the given statement The new acceleration is 21 m/s².
The correct option is D.
What is an acceleration defined as?Any process where the velocity varies is referred to as acceleration. There are only two ways to speed up: changing your speed or changing your direction, or changing both. This happens because velocity entails both a speed and a direction.
Briefing:The initial force is F = mass x acceleration
F = 3.17515 kg x 7 m/s²
F = 22.23 N
When the net force is tripled, the new acceleration will be
3 x F =m x a'
3 x 22.23 = 3.17515 x a'
a' = 21.003 m/s²
The new acceleration is 21 m/s². The correct option is d.
To know more about Acceleration visit:
https://brainly.com/question/12550364
#SPJ13
The complete question is -
A 7 lb bowling ball accelerates at a rate of 7 m/s². If the net force on the bowling ball is tripled, what will be its new acceleration?
a. 2.3 m/s²
b. 7 m/s²
c. 14 m/s²
d. 21 m/s²
What is the magnification of a curved mirror if a 10.0 cm tall object is placed 8.00 cmfrom the mirror and produces an image 12.00 cm in front of the mirror?-0.6671.50-1.500.667
Answers
We will have that the magnification will be given by:
[tex]m=-\frac{v}{u}[/tex]That is:
[tex]\begin{gathered} m=-\frac{8cm}{12cm}\Rightarrow m=-\frac{2}{3} \\ \\ \Rightarrow m\approx-0.667 \end{gathered}[/tex]So, the magnification is approximately -0.667.
You pull a box 23 m horizontally, If the rope tension is 120 N , and if the rope does 2500 J of work on the box, what angle θ does the rope make with the horizontal?
Answers
The angle θ made by the rope with the box is equal to 25.17 degrees.
If the rope is pulled at an angle A and the tension in the rope was T, then the rope will have two components of forces,
One Vertical which is TsinA and one along horizontal which is TcosA,
And we know,
W = F.s.cosα
Where,
F is the force applied,
s is the Displacement along force,
α is the angle between them,
We know, the box is moving forward, so the angle between the vertical component of tension and displacement is 90 degrees, so the vertical component of tension will not do any work, and the angle between displacement and the horizontal component is 0 degrees,
So, the work done by the horizontal component is 0 degrees,
So, we cam write,
W = TcosA.D
where D is the displacement of the box, which is given to be 23m,
T is the tension in the string which is 120N,
W is the work done by the rope on the box which is 25000J,
so, putting all the values,
2500 = 120.cosA.23
cosA = 2500/120x23
cos A = 0.9
So, A is 25.17 degrees.
The angle made by the rope is 25.17 degrees,
To know more about, work done, visit,
https://brainly.com/question/25573309
#SPJ1
A 58 V AC voltage source is connected across a 3.7 H inductor. What is the current through the inductor if the frequency is 63 Hz?
Answers
We will have the following:
First:
[tex]x_l=2\pi(63Hz)(3.7H)\Rightarrow x_l=466.2\pi\Omega[/tex]Then:
[tex]\begin{gathered} I=\frac{58V}{466.2\pi\Omega}\Rightarrow I=0.03960097254...A \\ \\ \Rightarrow I\approx0.04A \end{gathered}[/tex]So, the current is approximately 0.04 A.
Satellite orbits at a distance from earths center of about 6.6 earth radii and takes 24h to go around once. What distance (in meters) does the satellite travel in one day? What is the orbital velocity (in m/s)?
Answers
We know that the radii of the orbit is 6.6 the earth one. To get the distance travel in one day we calculate the circunference of that orbit:
[tex]\begin{gathered} C=(6.6)(6371)(2\pi) \\ C=264,199.14 \end{gathered}[/tex]Therefore the distance travel by the satellite is 264199.14 km per day.
Now, to get the orbital velocity we need to use the equation:
[tex]v=\sqrt[]{\frac{MG}{r}}[/tex]where M is the mass of the object at the center (in this case the earth), G is the gravitational constant and r is the radius of the orbit, then we have:
[tex]\begin{gathered} v=\sqrt[]{\frac{(5.9722\times10^{24})(6.67\times10^{-11})}{(6.6)(6.371\times10^6)}} \\ v=3077.89 \end{gathered}[/tex]Therefore the orbital velocity is 3077.83 m/s.
A football punter accelerates a football from rest to a speed of 13 m/s during the time in which his toe is in contact with the ball (about 0.24 s). If the football has a mass of 0.49 kg, what average force does the punter exert on the ball?_____ N
Answers
Given:
The initial speed of the football is: vi = 0 m/s (as initially, the football is at rest)
The final speed of the football is: vf = 13 m/s
The time for which the football accelerates is: t = 0.24 s
The mass of the football is: m = 0.49 kg
To find:
The force exerted on the ball
Explanation:
The acceleration of the ball can be determined by using the following equation.
[tex]a=\frac{v_f-v_i}{t}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} a=\frac{13\text{ m/s}-0\text{ m/s}}{0.24\text{ s}} \\ \\ a=\frac{13\text{ m/s}}{0.24\text{ s}} \\ \\ a=54.17\text{ m/s}^2 \end{gathered}[/tex]The force exerted by the punter on the ball can be determined by using Newton's second law of motion.
According to Newton's second law of motion,
[tex]F=ma[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} F=0.49\text{ kg}\times54.17\text{ m/s}^2 \\ \\ F=26.54\text{ N} \end{gathered}[/tex]Final answer:
The force exerted by the punter on the ball is 26.54 Newtons (N).
What is thermodynamics Movement of heatMeasure of heatIt’s magic None of them
Answers
To find
What is thermodynamics
Explanation
Thermodynamic study about the transfer of energy to and fro from a system.
Thus thermodynamics is the movement of heat
Conclusion
The correct option is movement of heat
29. [-/10 Points]DETAILSSERCPWA11 4.WA.010.An object of mass 0.77 kg is initially at rest. When a force acts on It for 2.9 ms It acquires a speed of 15.5 m/s. Find the magnitude (In N) of the average force acting on the object during the2.9 ms time interval.
Answers
We have:
m = mass = 0.77 kg
t = time = 2.9 ms = 0.0029 s
vf = final speed = 15.5 m/s
vi= initial speed = 0 m/s
Apply:
• F = m (vf-vi) / t
Replacing:
F = 0.77 (15.5 - 0 )/0.0029
F= 4,155.5 N
10. A punter kicks the ball high enough that it spends 5.2 seconds in the air. How fast was it
going when it left his foot?
Answers
With the use of first equation of motion, the ball will be going with a velocity of - 51 m/s
What is Velocity ?Velocity is the distance travel in a specific direction per time taken. It is a vector quantity and it is measured in m/s
Given that a punter kicks the ball high enough that it spends 5.2 seconds in the air. To know how fast was it, let us assumed that the initial velocity u of the ball is zero. The ball will be moving under the influence of gravity.
To find the velocity, let us use first equation of motion. That is,
v = u - gt
where
Final velocity v = ?Initial velocity u = 0Acceleration due to gravity g = 9.8 m/s²Time t = 5.2 sSubstitute all the parameters into the equation
v = - 9.8 × 5.2
v = - 50.96 m/s
Therefore, the ball will be going as fast as -51 m/s when it left his foot.
Learn more about Velocity here: https://brainly.com/question/24445340
#SPJ1
How do magnification and resolution compare between electron and light microscopes?
Answers
magnification and resolution compare between electron and light microscopes by they produce an photograph of a specimen with the aid of using the usage of a beam of electrons instead of a beam of mild.
Electron microscopes range from mild microscopes in that they produce an photograph of a specimen with the aid of using the usage of a beam of electrons instead of a beam of mild. Electrons have a whole lot a shorter wavelength than seen mild, and this lets in electron microscopes to supply higher-decision photos than popular mild microscopes. Electron microscopes may be used to observe now no longer simply complete cells, however additionally the subcellular systems and cubicles inside them.
For more information about microscope click here:
https://brainly.com/question/507443
For the following questions, refer to the position versus time graph above.a. What is the object's velocity att = 5 s? (2 sig figs)b. What is the object's velocity at t=40s? (2 sig figs)
Answers
We are given a graph of position vs time. We are asked to determine the speed at 5 seconds. To do that we need to determine the slope of the line above the time point of 5 seconds. To determine the slope of the line we will use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]This means that we need to choose two points in the line. We use the graph to determine these points as follows:
The points we have chosen are:
[tex]\begin{gathered} (x_1,y_1)=(0,0)_{} \\ (x_2,y_2)=(10,5) \end{gathered}[/tex]Replacing in the formula for the slope we get:
[tex]m=\frac{5-0}{10-0}[/tex]Solving the operations:
[tex]m=\frac{5}{10}=\frac{1}{2}[/tex]Therefore, the speed at 5 seconds is 0.5 meters per second.
For part B the following points can be taken:
why do surface waves compared to body waves have a high amplitude?
Answers
Calculate the force between charges 4 x 10^-8 C and 1.8 x 10^-6 C if they are 3.5 m apart.
Answers
Explanation
Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.
[tex]F=k\frac{q_1\cdot q_2}{r^2}[/tex]where k is the coulomb constant
[tex]k=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2}[/tex]Step 1
let
[tex]\begin{gathered} q_1=4\cdot10^{-8}C \\ q_2=1.8\cdot10^{-6} \\ r=3.5\text{ m} \\ k=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2} \end{gathered}[/tex]now, replace.
[tex]\begin{gathered} F=k\frac{q_1\cdot q_2}{r^2} \\ F=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2}(\frac{4\cdot10^{-8}C\cdot1.8\cdot10^{-6}}{(3.5m)^2}) \\ F=5.2824\cdot10^{-5}\text{ N} \end{gathered}[/tex]I hope this helps you