The period of motion is simple hormonic motion and the maximum speed of the particle is 0.0031s
(a) Simple harmonic motion is defined as "the motion of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's Law (F=-Kx). The motion experimented by the particle is sinusoidal in time and demonstrates a single resonant frequency".
(b) The equation that describes the simple harmonic motion is given by =
= X = Acos(ωt + θ) [1]
And taking the first and second derivate of the equation (1) we obtain the velocity and acceleration function respectively.
For the velocity:
= V = dx/dt = -Aωsin(ωt + θ) [2]
For the acceleration:
= A = dv/dt = -Aω²cos(ωt + θ) [3]
As we can see in equation [3] the acceleration would be maximum when the cosine term would be -1 and on this case:
= Aω² = 8x10³ m/s²
Since we know the amplitude A=0.002m we can solve for ω like this:
= ω = √ (8000/0.002)
= ω = 2000 rad
And we with this value we can find the period with the following formula;
= T = 2π/ω = 0.0031s
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The complete question:
A 10 g particle undergoes SHM with an amplitude of 2.0 mm and a maximum acceleration of magnitude 8.0 multiplied by 103 m/s2, and an unknown phase constant ?.(a) What is the period of the motion?1 s(b) What is the maximum speed of the particle?
A 1.5 kg object is located at a distance of 6.4 x 10^6 m from the center of a larger object whose mass is 6.0 x 10^24 kg what is the size of the force acting on the smaller object?
Answer:
Approximately 2.4 x 10^-8 N.
Explanation:
The force acting on the smaller object can be calculated using the formula for gravitational force:
F = G * (m1 * m2) / d^2
Where F is the force, G is the gravitational constant (6.674 x 10^-11 N * m^2 / kg^2), m1 is the mass of the smaller object (1.5 kg), m2 is the mass of the larger object (6.0 x 10^24 kg), and d is the distance between the two objects (6.4 x 10^6 m).
Substituting these values into the formula, we get:
F = 6.674 x 10^-11 * (1.5 * 6.0 x 10^24) / (6.4 x 10^6)^2
We can simplify this expression by dividing both sides by 6.0 x 10^24 to get:
F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)
Then we can simplify the right-hand side by performing the calculations in parentheses:
F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)
= 6.674 x 10^-11 * (1.5 / 41.6 x 10^12)
= 6.674 x 10^-11 * 3.6 x 10^-13
Finally, we can multiply both sides by 6.0 x 10^24 to get the value of the force acting on the smaller object:
F = 6.0 x 10^24 * (6.674 x 10^-11 * 3.6 x 10^-13)
= 2.4 x 10^-8 N
Therefore, the size of the force acting on the smaller object is approximately 2.4 x 10^-8 N.
what fraction of the energy density of the universe is dark matter? group of answer choices 71% 5% 1% 24% 99%
Fraction of the energy density of the universe is dark matter is 24% .
It turns out that roughly 68% of the universe is dark energy. Dark matter makes up about 27%.
A mystery, unseen element termed dark matter (25%) and a force that defies gravity called dark energy seem to make up the rest of the cosmos (70 percent). Since the mean energy density of the universe is equal to the critical density (within a 0.5% margin of error), WMAP's discovery that the universe is flat implies. This is comparable to a mass density of just 5.9 protons per cubic meter, or 9.9 x 10-30 g/cm3.
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where tt is measured in days. what is the instantaneous rate of change of the mass of the colony, in grams per day, at the moment the colony reaches a mass of 6 grams?
The instantaneous Bof change of the mass of the colony is t=2.059277.
The immediate charge of exchange is the exchange inside the rate at a specific immediate, and it's miles identical because of the trade inside the spinoff cost at a specific point. For a graph, the immediate fee of trade at a specific point is similar to the tangent line slope. that is, it's miles a curve slope.
Calculation:-
P(t)=2+5tan−1(t2)
=6P(t)=2+5tan−1(t2)=6.
The solution is t=2.059277.
Because the spinoff P′P′ may be interpreted because of the immediate fee of alternate.PP with respect to time, the calculator is used to numerically calculate the by-product of PP at this fee of tt.
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complete question is -
Where tt is measured in days. what is the instantaneous rate of change of the mass of the colony, in grams per day, at the moment the colony reaches a mass of 6 grams?
Two plane mirrors meet at a 113 ∘ angle, (Figure 1).Part A If light rays strike one mirror at 34∘ as shown, at what angle ϕ do they leave the second mirror?
At an angle of 33 degrees, the ray leaves the second mirror.
As per the below-attached figure:
The light beam is reflected at A, incident on the first plane at XA, and then incident on the second plane at XB, where it is again reflected as BY.
The law of reflection is the idea that when light rays strike a smooth surface, the angle of incidence and the angle of reflection are both identical. Additionally, the incident ray, the reflected ray, and the surface normal all reside in the same plane.
From the law of reflection of angle:
angle : BAO = θ = 34 degree
It is also given that,
Angle ABO = φ
Angle AOB = 113 degree
As in a triangle,
The sum of all three angles must be 180 degrees.
So, we can write it as:
∴θ+φ+113=180
φ=180-113-34= 33 degree.
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The required diagram is attached below:
a planet's moon travels in an approximately circular orbit of radius 5.4 107 m with a period of 6 h 7 min. calculate the mass of the planet from this information.
The mass of the planet from this information. 3.56×10²⁶ Kg. A planet's gravitational pull on other bodies determines its weight (or mass).
Every piece of matter in the cosmos is drawn to one another by a gravitational force that is proportionate to its mass, according to Newton's Law of Gravitation. A balance is what you would use to measure mass. A triple beam balance or an electronic balance may be used in the lab to measure mass, but the traditional balance shown below could help you understand what mass is. This is significant because a planet's atmosphere has a direct impact on its climate. The mass of the planet in issue will consequently affect where the "habitable zone" surrounding a star is located.
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5.92 block b, with mass figure p5.92 5.00 kg, rests on block a, with mass 8.00 kg, which in turn is on a horizontal tabletop (fig. p5,92). there is no fric- tion between block a and the tabletop, but the coefficient of static friction between blocks a and b is 0.750. a light string attached to block a passes over b a frictionless, massless pulley, and block c is suspended from the other end of the string. what is the largest mass that block c can have so that blocks a and b still slide together when the system is released from rest?
As a result, it can be concluded that block C must have a mass of at least 39 kg in order for blocks A and B to continue sliding past one another when the system is freed from rest.
A friction is caused by what?Relative motion between two things or materials is resisted by friction, a force. Surface roughness, deformations, and molecule adhesion are the causes of this resistive force.
What three kinds of friction are there?Rolling friction, beginning friction, and sliding friction are the three types of friction that exist between the car's tires and the road, and they are all what allow us to operate cars at all.
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describe how the milky way's light output compares with those of the most luminous galaxies in the blue cloud, based on the information in
The Milky Way is near the top of the luminosity range for blue cloud galaxies. Spiral galaxies usually have a luminosity of a few hundred billion Suns and Milky Way's luminosity is about 1.5 x 10¹⁰, making it near the top of the blue cloud galaxies.
Generally, a galaxy's absolute magnitude (a measure of luminosity) is related to its mass. The relationship can be visualized in a galaxy color-magnitude diagram with three populations:
Red sequence: includes most red galaxies that are usually elliptical shaped. They are red because of a highly far distance, contain many old, red stars, or are really dusty.Green valley: composed of either late-type galaxies (star formation is getting exhausted) or early-type galaxies.Blue cloud: includes most blue galaxies that are usually spiral-shaped.The Milky Way is a spiral galaxy. Spiral galaxies usually produce more stars because the spiral arms generate dense compression areas that provide a good environment for the formation of stars.
Your question seems incomplete, but most likely the completed version is as follows:
The luminosity of our Milky Way galaxy is about 1.5 x 10¹⁰ Lsun. Describe how the Milky Way's light output compares with those of the most luminous galaxies in the blue cloud, based on the information in Figure 1.
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a sample of an unknown material appears to weigh 300n in air and 200n when immersed in alcohol of density 700 kg/m?. what are a) the volume of the piece of material b) the density of the material
The calculated value is 453 g. density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density.
Grams per cubic centimeter are a typical unit of measurement for density.
8.5 g/mL Brass volume, total mass is brass plus wood:
M = 8.5b+100 (grams) (grams).
Volume of wood: 100/0.2 = 500 mL
Brass and wood volumes add up to the total:
V = b+500
Total density equal to water for simple floatation is 1
Total mass equals 1 * V + 500.
Calculate M using [1] above:
b+500 = 8.5b+100
400 = 7.5b
53.33 mL is the brass volume.
Brass should never be measured by volume. 8.5*53.33 = 453 g is the best; make careful to fasten it to the underside of the wood.
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extractor and ejector marks can be found where? group of answer choices inside the barrel of a gun on spent cases fired from certain firearms on a bullet after impacting its target on the firing pin of a gun
A cartridge is removed from the chamber by the extractor mechanism, and is then ejected by the ejector.
Because automatic and semi-automatic weapons (pistols and rifles) have ejectors whereas revolvers do not, the cartridge casings used in those weapons are different from those used in revolvers.A cartridge is removed from the chamber by the extractor mechanism, and is then ejected by the ejector.The mechanism that expels the spent cartridge case from the breech is known as the ejector. Without firing or dismantling a break open shotgun, ejectors can be challenging to spot. The perplexing part about them is that the ejector can be distinguished as one or two in firearms other than double guns.To know more about cartridge
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a wave has a frequency of 57Hz, what is the period
The period of a wave that has a frequency of 57Hz is 0.018s.
How to calculate period?A wave in physics is a moving disturbance in the energy level of a field.
Period refers to length of time and is denoted by T. The period of a wave can be calculated by finding the inverse of the frequency as follows;
T = 1/f
Frequency is the quotient of the number of times n a periodic phenomenon occurs over the time t in which it occurs.
T = 1/57
T = 0.018s
Therefore, 0.018s is the period of the wave.
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what would happen to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled?
Bright fringes occurs to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled.
Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the obstruction or aperture. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise observations of the phenomena in 1660. The wavefront's phase contributions are projected at an infinite number of spots (three are depicted) along length d, leading to a continually changing intensity on the registration plate. The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. As seen in the enclosed figure, the distinctive bending pattern is most obvious when a wave from a coherent source (like a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength. This results from the addition or intensity maxima of various wavefront points (or, alternatively, each wavelet) that follow pathways to the registering surface of varying lengths.
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when the load of scrap metal, initially on the bank, is placed onto the barge, what vertical distance does the water in the lock rise?
Let's imagine we have a 10 tonne barge with 100 tonnes of iron because when the barge is sitting in the lock loaded with iron the buoyancy (upthrust) of the water must balance the weight of the barge.
There will be 110 tonnes of upthrust, or 110,000 kg. Since water has a density of 1 kg/l, the amount of water that the loaded barge will move is also 110,000 kilograms, or 110,000 liters. Now toss the iron into the water. It is currently resting on the mud at the lock's base. The barge will continue to move 10 tons, or 10,000 lb, of water because it is still afloat.
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at what distance (from center to center) must the 4 x 10-6 c charged sphere be placed to keep the 2.30 gram block in equilibrium? the angle of the frictionless incline is 28 degrees.
The distance at which the charged sphere must be placed is 35.38 *10⁻⁹ m.
Fe is the electrostatic force experienced.
The weight mg of the particle can be resolved into two components as
mg sinθ along the inclined plane and mg cosθ perpendicular to the plane.
Applying Newton's second law along incline direction,
∑ F = m* a
Fe - mg sin 28° = 0
Fe = mg sin 28°
1/(4π∈₀) q₁* q₂/x² = mg/2
9* 10⁻⁹ * (4* 10⁻⁶ * 4*10⁻⁶)/x² = (2.3 * 10⁻³* 10)/2
x² * 2.3 * 10⁻² = 18* 16* 10⁻²¹
x² = (18* 16* 10⁻¹⁹)/2.3
x² = [18* 16/ 0.23]* 10⁻¹⁸
x = 35.38 *10⁻⁹ m
Thus, the distance from centre to centre is 35.38 *10⁻⁹ m.
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PLEASE SHOW WORK!
A 700 kg race car makes one lap around a track. It has a velocity of 20 m/s with a centripetal force of 5,600 N. What is the radius of the track?
A speed skater goes around a turn with a 25 m radius. The skater has a velocity of 15 m/s and experiences a centripetal force of 720 N. What is the mass of the skater?
A 900-kg car moving at 5 m/s takes a turn around a circle with a radius of 30 m. Determine the net force acting upon the car.
An 800 kg race car makes one lap around a track. It has a velocity of 40 m/s with a centripetal force of 16,000 N. What is the radius of the track?
Answer:
Question 1. 50 m
Question 2. 80 kg
Question 3. 750 N
Question 4. 80 m
Explanation:
Here are some equations that we might have to use.
[tex]F_{Cnet} =m*a_c\\F_{Cnet} =\frac{m*v^2}{r}\\a_c=\frac{v^2}{r}\\a_c=\frac{F_{Cnet} }{m}\\m=\frac{F_{Cnet} }{a_c}\\m=\frac{F_{Cnet} *r}{v^2} \\r=\frac{m*v^2}{F_{Cnet} }\\r=\frac{v^2}{a_c}[/tex]
Question 1
We are given
[tex]m=700\\v=20\\F_{Cnet}=5600[/tex]
We will use [tex]r=\frac{m*v^2}{F_{Cnet} }[/tex]
[tex]r=\frac{700*20^2}{5600}[/tex]
[tex]r=50[/tex]
Question 2
We are given
[tex]r=25\\v=15\\F_{Cnet} =720[/tex]
We will use [tex]m=\frac{F_{Cnet} *r}{v^2}[/tex]
[tex]m=\frac{720*25}{15^2}[/tex]
[tex]m=80[/tex]
Question 3
We are given
[tex]m=900\\v=5\\r=30[/tex]
We will use [tex]F_{Cnet} =\frac{m*v^2}{r}[/tex]
[tex]F_{Cnet} =\frac{900*5^2}{30}[/tex]
[tex]F_{Cnet} =750[/tex]
Question 4
We are given
[tex]m=800\\v=40\\F_{Cnet}=16000[/tex]
We will use [tex]r=\frac{m*v^2}{F_{Cnet} }[/tex]
[tex]r=\frac{800*40^2}{16000}[/tex]
[tex]r=80[/tex]
Hopefully this helps! A rating/review would be much appreciated! :)
016 (part 1 of 2) 10.0 points
A neutron in a reactor makes an elastic headon collision with the nucleus of an atom initially at rest.
Assume: The mass of the atomic nucleus is
about 11.1 the mass of the neutron.
What fraction of the neutron’s kinetic energy is transferred to the atomic nucleus?
017 (part 2 of 2) 10.0 points
If the initial kinetic energy of the neutron is
4.2 × 10−13 J, find its final kinetic energy.
Answer in units of J.
No Rounding
The fraction of the neutron's kinetic energy transferred to the atomic nucleus is 2.05
If the initial kinetic energy of the neutron is
4.2 × 10−13 J, its final kinetic energy will be 2.50 joules
What is kinetic energy?kinetic energy of an object is described as the energy that it possesses due to its motion which is also the work needed to accelerate a body of a given mass from rest to its stated velocity.
In elastic head-on collision, the energy of the system and total momentum is conserved.
For the neutron,
m - mass
Vi - initial velocity
Vf - final velocity
For the atom ,
M- mass
Mi - initial velocity
Mf - final velocity
Conserved momentum on the head-on collision
mvi = mvf + MVF
vi - vf = MmVf
Vi- vf = 11.1 vf...... (i)
The kinetic energy is
Vi²- vf² = 11.1 v²f.......(ii)
Combining both equations
Vi + Vf = Vf
Solve equation (I) and (III) for Vi
vi = 5.4vf
Now, the fraction of the neutron's kinetic energy transferred to the atomic nucleus,
1/2 mv²f/ 1/2 mv²i = 11.1/ 5.4
If the initial kinetic energy of the neutron is
4.2 × 10−13 J, its final kinetic energy will be 2.50 joules
Hence, we can conclude that the fraction of the neutron's kinetic energy transferred to the atomic nucleus is 2.05
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what if? suppose one of the professors proctored the exam by traveling on spacecraft i and stopped the exam after 88.0 min elapsed on her clock.
The speed of spacecraft relative exam after 88.0 min elapsed on her clock is 73.65 min.
What is speed ?
A direction or speed at which an object's position changes.
What is space craft ?
An object that orbits the Earth, the moon, or another celestial body is referred to as a satellite, whereas a spacecraft is a vehicle or technology designed for travel or operation outside the Earth's atmosphere.
Given speed of space craft perpendicular is v₁= 0.68 c
speed of space craft 2 is V₂= 0.24 c
They travel towards each other .
time elapsed in spacecraft 1 is = 54 mins
SO, speed of space craft ⊥ relative to space craft 2 is
v¹= V₁+V₂/1+V₁ V₂/C²
∴ V¹= (0.68+ 0.24) C/ 1+(0.68* 0.24 ) C²/C² = 0.791 C
∴ Time eclipsed in spacecraft 2 is, t¹ = t/[tex]\sqrt{1-v12/c2}[/tex] = 54/sqrt{1- (0.7911)2}[tex]\sqrt{1- 0.791}[/tex]
= 88.25 min
speed of spacecraft relative to earth is = 0.68c
∴time on earth t¹¹= t/[tex]\sqrt{r-v1/l1}[/tex]
= 54/ [tex]\sqrt{1- (0.08) 2}[/tex] = 73.65 min
Therefore, speed of spacecraft relative exam after 88.0 min elapsed on her clock is 73.65 min.
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a 8.0-m long wire with a mass of 10 g is under tension. a transverse wave for which the frequency is 570 hz, the wavelength is 0.10 m, and the amplitude is 3.7 mm is propagating on the wire. the maximum transverse acceleration of a point on a wire is closest to:______.
The maximum transverse acceleration of a point on a wire is closest to 47,458.2 m/s²
What is the angular speed of the transverse wave?
The angular speed of the transverse wave is calculated as follows;
ω = 2πf
where;
f is the frequency of the waveω = 2πf
ω = 2π ( 570 )
ω = 3,581.4 rad/s
The maximum transverse acceleration of a point on a wire is calculated as follows;
a = ω²A
where;
A is the amplitude of the wave = 3.7 mm = 0.0037 ma = ω²A
a = (3581.4)²(0.0037)
a = 47,458.2 m/s²
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what evidence supports the idea that a collision between two spiral galaxies might lead to the creation of a single elliptical galaxy?
Observables of certain elliptical galaxies with shells of stars surrounding them that are likely developed from stars ripped out of smaller galaxies is the evidence supports the idea that a collision between two spiral galaxies might lead to the creation of a single elliptical galaxy.
That most of the galaxy populations at the centers of dense clusters of galaxies are made up of elliptical galaxies, studies of a few eccentric galaxies with central stars and gas clouds that orbit differently from the galaxy's other stars. Observations of massive, elliptical galaxies that may have developed by consuming other galaxies at the heart of dense clusters. A galaxy is a collection of stars, stellar remains, interstellar gas, dust, and dark matter that are gravitationally bonded together. The name comes from the Greek word galaxias, which means "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies, which contain an average of 100 million stars, range in size from dwarfs, which contain fewer than 100 million stars, to supergiants, which contain 100 trillion stars, all of which orbit the galaxy's center of mass. Only a small percentage of the mass in a normal galaxy is visible in the form of stars and nebulae; the majority of the galaxy's mass is dark matter. Supermassive black holes are a typical component of galaxy centers.
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a proton follows the path shown in (figure 1). its initial speed is v0 = 2.8×106 m/s.
The proton's speed as it passes through point P is 1.66×10⁶ m/s.
The proton's speed at point P can be determined by the equation:
KE = PE + ( mv²/2 )
where,
KE= kinetic energy
PE = potential energy
m = mass of the proton
v = speed of the proton.
Given
Proton's initial speed is v₀ = 2.8×10⁶ m/s
By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:
v = √(2KE/m)
= √(2 ×2.8 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)
= 1.66 × 10⁶ m/s
Therefore, the proton's speed as it passes through point P is 1.66×10⁶ m/s.
Your question is incomplete most probably your full question was
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.8×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.
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if x2 is a binary predictor in y = β0 + β1x1 + β2x2, then which statement is most nearly correct?
The correct statement is 'x₂ will shift the estimated value of y either by 0 units or by β₂ units.'
Given that,
y = β₀ + β₁ x₁ + β₂ x₂
where,
x₂ is the binary predictor
A binary predictor is a categorical random variable in the regression analysis which can take only two values. These variables typically fall into one of two groups, 0 or 1, depending on the variable.
If such binary variables are employed in the study, the regression line's intercept can take two values from two different categories.
Consider, x₂ = 0,1, we get two equations with same slope but different intercepts.
y₀ = β₀ + β₁ x₁ + β₂ (0) = β₀ + β₁ x₁
y₁ = β₀ + β₁ x₁ + β₂ (1) = (β₀ + β₂) + β₁ x₁
The two equations reflect the shift in the regression line by β₂ units relative to basic equation.
The question is incomplete as it does not contain options. They are ' A. x₂ would be a significant predictor if β₂ = 423.72.
B. x₂ will shift the estimated value of Y either by 0 units or by β₂ units.
C. x₂ = 0, x₂ = 1, x₂ = 2 would be appropriate if three categories exist .
D. x₂ = 1 should represent the most desirable condition.'
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a technician is testing a power seat that operates slower than normal. the dome light noticeably dims while operating the power seat motors. the problem is likely .
A slower-than-normal power seat is being tested by a technician. When the power seat motors are running, the dome light noticeably dims. Most likely, the seat mechanism's binding is the issue.
Instead of using manual levers, cranks, or knobs to alter the position or recline of the seat, power seats in automobiles use electric motors. They make it simpler for both the driver to select the ideal driving posture and for the passengers to settle into a comfortable position for the ride. A power seat motors doesn't have a predetermined lifespan. The switch will wear down more quickly the more frequently you change your seat. The scenario is identical to that of power door locks or windows. The switch's contacts deteriorate more quickly the more you use it. The price of an aftermarket seat motor can range from $50 to $340. According to a number of factors, including
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A cart of mass 10 kg is rolling on a level floor at 5 m/s. A 4 kg mass dropped from rest lands in the cart.
what is the momentum of the system before the object drops?
what is the momentum of the system after the object drops?
what is the final speed of the cart and the mass?
The momentum of the system before the object drops is 50 kg m/s.
The momentum of the system after the object drops is 50 kg m/s.
The final speed of the cart and the mass is 3.57 m/s.
We know that, momentum is the product of mass and velocity of the system.
Mathematically,
P = m* v
where,
m is the mass
v is the velocity
Given that,
Mass of the cart m₁ = 10 kg
Velocity of the cart before the object drops v₁ = 5 m/s
Mass of the object dropped m₂ = 4 kg
Velocity of the cart after the object drops v₂ = ?
According to the principle of conservation of linear momentum,
Total momentum of the system before the object drops = total momentum of the system after the object drops
So, mathematically,
m₁* v₁ = (m₁ + m₂)* v₂
10 * 5 = (10 + 4) v₂
14 v₂ = 50
v₂ = 3.57 m/s
Thus, Final speed of the cart = 3.57 m/s
Final mass of the cart = 10 + 4 = 14 kg
The momentum of the system before the object drops = m₁* v₁ = 10* 5 = 50 kg m/s
The momentum of the system after the object drops = (m₁ + m₂)* v₂ = 14* 3.57 = 49.98 ≈ 50 kg m/s
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calculate the work done by the force f⃗ when the sled moves from x=0 to x=8.0m.
The work done by the force when the sled moves from x=0 to x=8 m is -2048 J
Force is a fundamental concept in physics that describes an interaction between two or more objects that results in a change in motion, shape, or energy of one or both of the objects.
Work done = W
Force = F
Distance = x
Area under the curve = A
Here, the distance moved is 8.0 m and the force is given by the graph as a function of x. Thus, we can use the area under the curve to calculate the work done from x = 0 to x = 8.
= W = F X x
= W = F ∫ x (from x = 0 to x = 8.)
= W = - (4/3) X x³
= W = -2048 J
Therefore, the work done by the force F is -2048 J.
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Which of the following is not true of a magnetic disk?
A. It is expensive relative to magnetic tape
B. It provides only sequential access to stored data
C. Users can easily update records by writing over the old data
D. It does not provide an automatic audit trail
E. All of the above are true
A and B are both false.
what fraction of a piece of silicon will be submerged when it floats in mercury?
The fraction of a piece of silicon will be submerged when it floats in mercury is 17%
Density silicon = 2.33 g/cm³,
Density mercury 13.6 g/cm³.
2.33=/13.6 = 0.17 = 17% silicon submerged and 83% above surface of mercury.
With the symbol Si, silicon is an atomic number 14 chemical element. It is a hard, brittle crystalline solid with a blue-grey metallic sheen that is a tetravalent metalloid and semiconductor. Because silicon is abundant in the Earth's crust, natural goods with silicon as their main component have been used for thousands of years.
The most abundant substance found in the crust of the Earth is silicon dioxide (SiO₂).
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a 55-kg lady stands on a bathroom scale inside an elevator. the scale reads 45 kg. what do you know about the motion of the elevator?
A 55-kg lady stands on a bathroom scale inside an elevator. the scale reads 45 kg. Lift is going downward is the motion of the elevator.
An object changing its position with regard to time is referred to as motion. Motion is mathematically characterized in terms of displacement, distance, velocity, acceleration, and speed as well as the observer's frame of reference and the measurement of the change in the body's position with respect to that frame over time. Kinematics is the area of physics that studies how motion is affected by forces, whereas dynamics is the area that studies how motion is affected by forces. An object is said to be at rest, motionless, immobile, stationary, or to have a constant or time-invariant location with respect to its surroundings if it is not changing with respect to a certain frame of reference. Objects, bodies, matter particles, matter fields, radiation, radiation fields, radiation particles, curvature, and space-time are only a few examples of physical systems where motion is applicable. One may also discuss the movement of borders, shapes, and images. The word "motion" often refers to a continual change in the positions or arrangement of a physical system in space. One can discuss the motion of a wave or a quantum particle, for instance, where the configuration is the likelihood that the wave or particle would occupy a particular place.
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to see his full height, a boy that is 1 meter tall needs a mirror that is at least a. 0.33 m tall. b. 0.50 m tall. c. 0.75 m tall. d. 1 m tall. e. depends on how far the mirror is from the boy
A boy who is 1 meter tall requires a mirror that is at least 0.50 m tall in order to see his entire height.
The mirror must be at least half as long as the individual is tall in order for them to see their entire reflection. In order to make it simpler for the person to see themselves in the mirror.
Given that the boy's height (h) = 1 m,
the mirror's height should be h/2 = 1/2 = 0.50 m.
Behind the glass of a mirror, people can see an image of themselves. This image is created when light rays hit the shining surface and reflect or bounce back, creating a "mirror image." Glass can be made into a mirror that reflects light by having a bright metal coating on one side. Mirrors can reflect 95% of the light that hits them, whereas window glass can only reflect 8% of the light that hits it.
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A 600-kg car is moving at 5 m/s then comes to a stop
in 3 seconds. How much average force is necessary?
The average force acting on the car is 1000 N.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given that: A 600-kg car is moving at 5 m/s then comes to a stop in 3 seconds.
Now according to Newton's 2nd law of motion:
Magnitude of force applied on the body = change in momentum/time interval
= I final momentum - initial momentum I/time interval
= I 0 - 600×5 I /3 N
= 10000 N
Hence, average force acting on the car is 1000 N.
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A circular hoop of mass m, radius r, and infinitesimal thickness rolls without slipping down a ramp inclined at an angle θ with the horizontal.
A. What is the acceleration αα of the center of the hoop?
B. What is the minimum coefficient of (static) friction μminμmin needed for the hoop to roll without slipping?
1/2tan(tetha) is the minimal coefficient of static friction required for the hoop to roll without slipping, and 1/2g sin(tetha) is the acceleration of the hoop's centre.
In mechanics, acceleration is the rate at which an object's velocity with respect to time changes. The vector quantity of accelerations (in that they have magnitude and direction). The direction of the net force imposed on an object determines its acceleration in relation to that force. In other words, static friction is the force that maintains an object's resting position.
acceleration A = 1/2g sin where an Ihoop = m*r2 ma = mg sin (o) -Fr ma = mgsin(o) -ma (0)
The least possible static friction coefficient
Alpha = r(mug cos) (tetha)
Mu - a/g cos(tetha) = 1/2 (tan(tetha)
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the direction of induced ? flow through a conductor is determined by the direction of the magnetic field surrounding the conductor and the direction the conductor is traveling through the magnetic field.
To help you recall the direction of magnetic forces, use the right-hand rule. However, we can also modify the magnetic flux by introducing a wire loop into a magnetic field.
A magnetic field is created when current runs through a conductor, right?A magnetic field is created when current travels through a conductor. Individual magnetic fields are created as free electrons flow in one direction.
What three elements govern the induced voltage of a conductor coil?There are three things that can change the voltage's size: how big the magnetic field is. There are more flux lines, hence there are more flux lines for the conductor to cut.
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